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Germany
Population
  By Evan Franz
Information used.
Making a prediction with a line.



This is done by taking two points and drawing a line
through them. We take the corresponding years and
 population and put them into the linear equation.
It will look somewhat like this.




1850 is referred to as year 0
  because it is the year we
        started with.
                       The points i used for this are year 100(1950) and
                        year 150(2000). These are used as the X values
                             with the populations as the Y values.
y1-y2
          = Slope                                       y-y1=m(x-x1)
    x1-x2

          68377000-82797400
                            =288408=Slope
               100-150
                   y-68377000=288408(x-100)
                 y-68377000=288408x-28840800
                 +68377000         +68377000
                      y=288408x+39536200
We then plug in the year that we want to predict the population. 2061=211

                     y=288408(211)+39536200
                          y=100390288

Predicted population of Germany in 2061~100,390,288
Making a prediction with a Quadratic

We need to chose 3 points for this prediction. we will plug
these points into the equation ax^2+bx+c and use them to
                find the values of a b and c.
  We also need to write the populations in a much more
   manageable way. We write them in scientific notation,
             moving the decimal over 7 places.
x1,y1    0,3.5       3.5=a(0)^2+b(0)+c              3.5=a(0)^2+b(0)+c
  x2,y2   100,6.8   6.8=a(100)^2+b(100)+c                 3.5=0+0+c
  x3,y3   110,7.2   7.2=a(110)^2+b(110)+c                    3.5=c

   6.8=a(100)^2+b(100)+3.5
   7.2=a(110)^2+b(110)+3.5                      3.7=12100a+110(.033-100a)
                              3.3=10000a+100b
                                                 3.7=12100a+3.63-11000a
                                     100
      3.3=10000a+100b                                   .07=1100a
      3.7=12100a+110b            .033-100a=b               1100
   3.3=10000(.00006)+100b        a=.00006 b=.027
         3.3=.6+100b
           2.7=100b         Our Equation.           y=.00006x^2+.027x+3.5
              100
Now we plug in the year we want to predict (211) once again as the x value.


   y=.00006(211)^2+.027(211)+3.5             Predicted population:
        y=.2.67126+5.697+3.5                     118,682,600
Exponential/Logarithmic
68=ab^100
 y=ab^x                               y=population, x=years
                      83=ab^150

a=68/b^100   a=83/b^150      68=a(1.00399)^100
                                   68=a1.48984
      68      83              1.48984 1.48984
    b^100 = b^150                a=45.64249
   68b^150=83b^100
    b^100 b^100           Now we use these 2 points
      68b^50=83             in the origanal equation
        68   68           y=(45.64249)(1.00399)^211
     b^50=1.22059
       b=1.00399
                          y=(45.64249)(2.31686)
                               y=105.74748
             Predicted Population:
                 105,747,480

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Germany population keynote

  • 3. Making a prediction with a line. This is done by taking two points and drawing a line through them. We take the corresponding years and population and put them into the linear equation.
  • 4. It will look somewhat like this. 1850 is referred to as year 0 because it is the year we started with. The points i used for this are year 100(1950) and year 150(2000). These are used as the X values with the populations as the Y values.
  • 5. y1-y2 = Slope y-y1=m(x-x1) x1-x2 68377000-82797400 =288408=Slope 100-150 y-68377000=288408(x-100) y-68377000=288408x-28840800 +68377000 +68377000 y=288408x+39536200 We then plug in the year that we want to predict the population. 2061=211 y=288408(211)+39536200 y=100390288 Predicted population of Germany in 2061~100,390,288
  • 6. Making a prediction with a Quadratic We need to chose 3 points for this prediction. we will plug these points into the equation ax^2+bx+c and use them to find the values of a b and c. We also need to write the populations in a much more manageable way. We write them in scientific notation, moving the decimal over 7 places.
  • 7.
  • 8. x1,y1 0,3.5 3.5=a(0)^2+b(0)+c 3.5=a(0)^2+b(0)+c x2,y2 100,6.8 6.8=a(100)^2+b(100)+c 3.5=0+0+c x3,y3 110,7.2 7.2=a(110)^2+b(110)+c 3.5=c 6.8=a(100)^2+b(100)+3.5 7.2=a(110)^2+b(110)+3.5 3.7=12100a+110(.033-100a) 3.3=10000a+100b 3.7=12100a+3.63-11000a 100 3.3=10000a+100b .07=1100a 3.7=12100a+110b .033-100a=b 1100 3.3=10000(.00006)+100b a=.00006 b=.027 3.3=.6+100b 2.7=100b Our Equation. y=.00006x^2+.027x+3.5 100 Now we plug in the year we want to predict (211) once again as the x value. y=.00006(211)^2+.027(211)+3.5 Predicted population: y=.2.67126+5.697+3.5 118,682,600
  • 10. 68=ab^100 y=ab^x y=population, x=years 83=ab^150 a=68/b^100 a=83/b^150 68=a(1.00399)^100 68=a1.48984 68 83 1.48984 1.48984 b^100 = b^150 a=45.64249 68b^150=83b^100 b^100 b^100 Now we use these 2 points 68b^50=83 in the origanal equation 68 68 y=(45.64249)(1.00399)^211 b^50=1.22059 b=1.00399 y=(45.64249)(2.31686) y=105.74748 Predicted Population: 105,747,480

Editor's Notes

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