Exercise in Torsion of Shaft (in Japanese) 軸のねじり問題Kazuhiro Suga
Text book for the mechanics of materials
Exercise in Torsion of Shaft
・Statically indeterminate problem
・Corn Like Shaft
・Power Transmission Shaft
note: Your feedback is welcome!
軸のねじり問題
・ねじりの不静定問題
・径の変化する軸
・伝動軸の設計
Exercise in Torsion of Shaft (in Japanese) 軸のねじり問題Kazuhiro Suga
Text book for the mechanics of materials
Exercise in Torsion of Shaft
・Statically indeterminate problem
・Corn Like Shaft
・Power Transmission Shaft
note: Your feedback is welcome!
軸のねじり問題
・ねじりの不静定問題
・径の変化する軸
・伝動軸の設計
A continuación se muestran las reglas para derivar funciones algebraicas, trigonométricas y trascendentales. Esto comprende las reglas principales, existen otras más que no se incluyen en este formato.
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formulas calculo integral y diferencial
1. Formulario de Cálculo Diferencial e Integral Jesús Rubí M.
Formulario de ( a + b ) ⋅ ( a 2 − ab + b2 ) = a3 + b3 θ sen cos tg ctg sec csc
Gráfica 4. Las funciones trigonométricas inversas
arcctg x , arcsec x , arccsc x : sen α + sen β
1 1
= 2sen (α + β ) ⋅ cos (α − β )
( a + b ) ⋅ ( a3 − a 2 b + ab2 − b3 ) = a 4 − b4 0 0 ∞ ∞ 0 2 2
Cálculo Diferencial
1 1
1 1
30 12 3 2 3 2 sen α − sen β = 2 sen (α − β ) ⋅ cos (α + β )
4
3 2 1 3
( a + b ) ⋅ ( a 4 − a3b + a 2 b2 − ab3 + b4 ) = a5 + b5
e Integral VER.4.3 45 1 2 1 2 1 1 2 2 3
2 2
( a + b ) ⋅ ( a5 − a 4 b + a3b2 − a 2 b3 + ab4 − b5 ) = a 6 − b6
1 1
60 3 2 12 3 1 3 2 2 3 cos α + cos β = 2 cos (α + β ) ⋅ cos (α − β )
Jesús Rubí Miranda (jesusrubim@yahoo.com) 2 2 2
90 1 0 ∞ 0 ∞ 1
http://mx.geocities.com/estadisticapapers/ ⎛ n ⎞ cos α − cos β
1 1
= −2sen (α + β ) ⋅ sen (α − β )
( a + b ) ⋅ ⎜ ∑ ( −1) a n− k b k −1 ⎟ = a n + b n ∀ n ∈
k +1
impar ⎡ π π⎤ 1
http://mx.geocities.com/dicalculus/ ⎝ k =1 ⎠ y = ∠ sen x y ∈ ⎢− , ⎥ 2 2
⎣ 2 2⎦
sen (α ± β )
0
VALOR ABSOLUTO ⎛ n
⎞
( a + b ) ⋅ ⎜ ∑ ( −1) y ∈ [ 0, π ]
k +1
a n − k b k −1 ⎟ = a n − b n ∀ n ∈ par y = ∠ cos x tg α ± tg β =
⎧a si a ≥ 0 ⎝ k =1 ⎠
-1
cos α ⋅ cos β
a =⎨
arc ctg x
π π arc sec x
⎩− a si a < 0 y = ∠ tg x y∈ − arc csc x
SUMAS Y PRODUCTOS , 1
⎡sen (α − β ) + sen (α + β ) ⎤
-2
2 2 -5 0 5
sen α ⋅ cos β =
a = −a n
2⎣ ⎦
a1 + a2 + + an = ∑ ak 1 IDENTIDADES TRIGONOMÉTRICAS
a ≤ a y −a≤ a y = ∠ ctg x = ∠ tg y ∈ 0, π 1
k =1
x sen α ⋅ sen β = ⎡cos (α − β ) − cos (α + β ) ⎤
sen θ + cos2 θ = 1 2⎣ ⎦
2
n
a ≥0y a =0 ⇔ a=0
∑ c = nc y = ∠ sec x = ∠ cos
1
y ∈ [ 0, π ] 1 + ctg 2 θ = csc2 θ 1
k =1 cos α ⋅ cos β = ⎡cos (α − β ) + cos (α + β ) ⎤
2⎣ ⎦
n n x
ab = a b ó ∏a = ∏ ak n n
⎡ π π⎤ tg 2 θ + 1 = sec2 θ
∑ ca = c ∑ ak 1
k
k =1 k =1 k y = ∠ csc x = ∠ sen y ∈ ⎢− , ⎥ tg α + tg β
n n k =1 k =1 x ⎣ 2 2⎦ sen ( −θ ) = − sen θ tg α ⋅ tg β =
a+b ≤ a + b ó ∑a ≤ ∑ ak n n n ctg α + ctg β
k =1
k
k =1 ∑(a
k =1
k + bk ) = ∑ ak + ∑ bk
k =1 k =1
Gráfica 1. Las funciones trigonométricas: sen x , cos ( −θ ) = cosθ FUNCIONES HIPERBÓLICAS
cos x , tg x :
EXPONENTES n tg ( −θ ) = − tg θ e x − e− x
a p ⋅ a q = a p+q ∑(a − ak −1 ) = an − a0 senh x =
sen (θ + 2π ) = sen θ
k 2
k =1
2
ap 1.5
e x + e− x
= a p−q n
n cos (θ + 2π ) = cosθ cosh x =
aq ∑ ⎡ a + ( k − 1) d ⎤ = 2 ⎡ 2a + ( n − 1) d ⎤
⎣ ⎦ ⎣ ⎦
1
2
k =1 tg (θ + 2π ) = tg θ
( a p ) = a pq senh x e x − e − x
q 0.5
n tgh x = =
(a + l )
= 0 sen (θ + π ) = − sen θ cosh x e x + e − x
(a ⋅ b) = ap ⋅bp
p
2 -0.5
cos (θ + π ) = − cosθ 1 e x + e− x
n
1 − r n a − rl ctgh x = =
⎛a⎞ ap
p
∑ ar k −1
=a = -1
tg (θ + π ) = tg θ tgh x e x − e − x
⎜ ⎟ = p k =1 1− r 1− r
⎝b⎠
sen x
b -1.5
1 2
sen (θ + nπ ) = ( −1) sen θ sech x = =
cos x n
( n + n)
n
1 2
∑k =
tg x
a p/q
= a
q p -2
-8 -6 -4 -2 0 2 4 6 8 cosh x e x + e − x
2
k =1
cos (θ + nπ ) = ( −1) cos θ
n
1 2
LOGARITMOS csch x = =
∑ k 2 = 6 ( 2n3 + 3n2 + n )
n
1 Gráfica 2. Las funciones trigonométricas csc x ,
log a N = x ⇒ a x = N tg (θ + nπ ) = tg θ senh x e x − e − x
k =1 sec x , ctg x :
log a MN = log a M + log a N senh : →
sen ( nπ ) = 0
∑ k 3 = 4 ( n 4 + 2n3 + n 2 )
n
1
M
2.5
cosh : → [1, ∞
= log a M − log a N cos ( nπ ) = ( −1)
n
log a k =1 2
N tgh : → −1,1
∑ k 4 = 30 ( 6n5 + 15n4 + 10n3 − n )
n
1
tg ( nπ ) = 0
1.5
log a N r = r log a N 1
ctgh : − {0} → −∞ , −1 ∪ 1, ∞
k =1
⎛ 2n + 1 ⎞
+ ( 2n − 1) = n 2 π ⎟ = ( −1) → 0,1]
0.5 n
log b N ln N 1+ 3 + 5 + sen ⎜
log a N = = sech :
⎝ 2 ⎠
0
log b a ln a n
− {0} → − {0}
n! = ∏ k
-0.5
csch :
log10 N = log N y log e N = ln N ⎛ 2n + 1 ⎞
k =1
-1
cos ⎜ π⎟=0
ALGUNOS PRODUCTOS -1.5 ⎝ 2 ⎠ Gráfica 5. Las funciones hiperbólicas senh x ,
⎛n⎞ n! csc x
a ⋅ ( c + d ) = ac + ad ⎜ ⎟= , k≤n -2 sec x
⎛ 2n + 1 ⎞ cosh x , tgh x :
⎝ k ⎠ ( n − k )!k !
ctg x
tg ⎜ π⎟=∞
⎝ 2 ⎠
-2.5
( a + b) ⋅ ( a − b) = a − b
-8 -6 -4 -2 0 2 4 6 8
2 2
5
n
⎛n⎞
( x + y ) = ∑ ⎜ ⎟ xn−k y k π⎞
n
Gráfica 3. Las funciones trigonométricas inversas ⎛
( a + b ) ⋅ ( a + b ) = ( a + b ) = a 2 + 2ab + b2
4
sen θ = cos ⎜θ − ⎟
2
k =0 ⎝ k ⎠ arcsen x , arccos x , arctg x : ⎝ 2⎠ 3
( a − b ) ⋅ ( a − b ) = ( a − b ) = a 2 − 2ab + b 2
2 2
( x1 + x2 + + xk )
n
=∑
n!
x1n1 ⋅ x2 2 ⎛ π⎞
cosθ = sen ⎜θ + ⎟
n nk
x 4
( x + b ) ⋅ ( x + d ) = x 2 + ( b + d ) x + bd
1
k
n1 !n2 ! nk !
3
⎝ 2⎠ 0
( ax + b ) ⋅ ( cx + d ) = acx 2 + ( ad + bc ) x + bd CONSTANTES sen (α ± β ) = sen α cos β ± cos α sen β -1
( a + b ) ⋅ ( c + d ) = ac + ad + bc + bd π = 3.14159265359… 2
cos (α ± β ) = cos α cos β ∓ sen α sen β
-2
se nh x
e = 2.71828182846…
-3 co sh x
( a + b ) = a3 + 3a 2b + 3ab2 + b3 tg α ± tg β
3 1 tgh x
tg (α ± β ) =
-4
-5 0 5
TRIGONOMETRÍA
1 ∓ tg α tg β
( a − b ) = a3 − 3a 2b + 3ab2 − b3
3 0
CO 1 FUNCIONES HIPERBÓLICAS INV
sen θ = cscθ = sen 2θ = 2sen θ cosθ
( a + b + c ) = a 2 + b2 + c 2 + 2ab + 2ac + 2bc
2 HIP
CA
sen θ
1
-1
arc sen x
arc cos x
arc tg x cos 2θ = cos 2 θ − sen 2 θ (
senh −1 x = ln x + x 2 + 1 , ∀x ∈ )
cosθ = secθ =
( a − b ) ⋅ ( a + ab + b ) = a − b ( )
-2
2 tg θ
2 2 3 3
cosθ
-3 -2 -1 0 1 2 3
HIP tg 2θ = cosh −1 x = ln x ± x 2 − 1 , x ≥ 1
sen θ CO 1 − tg 2 θ
( a − b ) ⋅ ( a3 + a 2 b + ab2 + b3 ) = a 4 − b4 tg θ = = ctg θ =
1
1 ⎛1+ x ⎞
cosθ CA tg θ 1 tgh −1 x = ln ⎜ ⎟, x < 1
( a − b ) ⋅ ( a 4 + a3b + a 2 b2 + ab3 + b 4 ) = a5 − b5 sen 2 θ = (1 − cos 2θ ) 2 ⎝ 1− x ⎠
2
⎛ ⎞ π radianes=180 1 ⎛ x +1 ⎞
ctgh −1 x = ln ⎜
n
1
( a − b ) ⋅ ⎜ ∑ a n − k b k −1 ⎟ = a n − b n ∀n ∈ cos 2 θ = (1 + cos 2θ ) ⎟, x > 1
2 ⎝ x −1 ⎠
⎝ k =1 ⎠ 2
1 − cos 2θ ⎛ 1 ± 1 − x2 ⎞
HIP tg 2 θ = sech −1 x = ln ⎜ ⎟, 0 < x ≤ 1
CO 1 + cos 2θ ⎜ x ⎟
⎝ ⎠
θ ⎛1 x2 + 1 ⎞
csch −1 x = ln ⎜ + ⎟, x ≠ 0
CA ⎜x x ⎟
⎝ ⎠