Pythagoras!
c =a +b
                             2           2             2



                                           c
                   a



                                       b
c must be the hypotenuse - the longest side in a right angle triangle (opposite the
right angle), and a and b are the two shorter sides
c2 = a2 + b2
8 cm                x2 = 82 + 5.22
                x   x2 = 64 + 27.04
                    x2 = 91.04
                    x = √91.04
                    x = 9.541488354
       5.2 cm       x = 9.5 to 1 d.p.
x              3 cm   x = 5 cm

           4 cm


                      x
5 cm                                x = 13 cm

                  12 cm

               5 cm
6 cm
                      x = 7.8 cm (1 dp)
           x
c2 = a2 + b2
                152 = 112 + x2
15 cm           225 = 121 + x2
        11 cm
                x2 = 225 – 121
                x2 = 104
                x = √104
                x = 10.19803903
    x
                x = 10.2 to 1 d.p.
11m
xm
                        x = 6.3 m (1 dp)

              9m


                       23.8 cm
11 cm                                x = 21.1 cm (1 dp)

                      x cm


                      3.4 cm
     7.1 cm
                             x = 7.9 cm (1 dp)
               x cm
15 miles
H
                   B


                   6.4 miles




               L
15 miles
                   H
                                                                B


                                                                6.4 miles




                                                            L
Total distance travelled = 21.4 + 16.4 = 37.7 miles
12 ft
            9.5 ft


        L
12 ft
                        9.5 ft


                    L


L = 7.3ft
Exam Question
Exam Question




                230
Exam Question




            13.7

FCA GCSE Pythagoras

  • 1.
  • 2.
    c =a +b 2 2 2 c a b c must be the hypotenuse - the longest side in a right angle triangle (opposite the right angle), and a and b are the two shorter sides
  • 3.
    c2 = a2+ b2 8 cm x2 = 82 + 5.22 x x2 = 64 + 27.04 x2 = 91.04 x = √91.04 x = 9.541488354 5.2 cm x = 9.5 to 1 d.p.
  • 4.
    x 3 cm x = 5 cm 4 cm x 5 cm x = 13 cm 12 cm 5 cm 6 cm x = 7.8 cm (1 dp) x
  • 5.
    c2 = a2+ b2 152 = 112 + x2 15 cm 225 = 121 + x2 11 cm x2 = 225 – 121 x2 = 104 x = √104 x = 10.19803903 x x = 10.2 to 1 d.p.
  • 6.
    11m xm x = 6.3 m (1 dp) 9m 23.8 cm 11 cm x = 21.1 cm (1 dp) x cm 3.4 cm 7.1 cm x = 7.9 cm (1 dp) x cm
  • 7.
    15 miles H B 6.4 miles L
  • 8.
    15 miles H B 6.4 miles L Total distance travelled = 21.4 + 16.4 = 37.7 miles
  • 9.
    12 ft 9.5 ft L
  • 10.
    12 ft 9.5 ft L L = 7.3ft
  • 11.
  • 12.
  • 13.