The document is a mathematics module in Malay on the topic of length for students taking the UPSR examination. It contains objective and subjective questions testing concepts such as converting between units of length (mm, cm, m, km), adding and subtracting lengths, multiplying and dividing lengths, and solving word problems involving lengths. The questions range in difficulty from basic conversions to multi-step word problems.

1. Modul Bestari Matematik UPSR
JPNS 2011
UNIT 7
LENGTH
Objective Questions
1. Convert 5 800 mm to cm.
Tukarkan 5 800 mm kepada cm.
A 0.58
B 5.8
C 58
D 580
2. 8 m 72 cm + 6 m 19 cm =
A 2 m 53 cm
B 14 m 91 cm
C 22 m 24 cm
D 24 m 91 cm
3. 2160 cm – 98 cm =
A 76. 4 cm
B 118 cm
C 2 062 cm
D 2 602 cm
4. The length of a pencil box is 25 cm. What is the total length of 6 similar pencil boxes,
in m?
Panjang sebuah kotak pensel ialah 25 cm. Berapakah jumlah panjang 6 buah kotak
pensel yang sama, dalam m?
A 0.15
B 1.5
C 15
D 150
5. cm + 21 cm = 5 021 cm
A 5
B 50
C 500
D 5 000
6. 0.75 m – m = 0.56 m
A 0.11
B 0.19
C 0.21
Unit 7 Length Page 189

2. Modul Bestari Matematik UPSR
JPNS 2011
D 0.29
7. The total length of 9 similar pencils is 144 cm. What is the length of a pencil, in cm?
Jumlah panjang 9 batang pensel yang sama ialah 144 cm. Berapakah panjang sebatang
pensel, dalam cm?
A 14
B 16
C 17
D 18
8. Subtract 69 m from 91 m.
Tolakkan 69 m daripada 91 m.
A 160 m
B 156 m
C 100 m
D 22 m
9. 4.3 cm × 1 000 =
A 43 cm
B 430 cm
C 4 300 cm
D 43 000 cm
10. 100.8 cm ÷ 6 =
A 1.68 cm
B 16.8 cm
C 168 cm
D 1680 cm
11. A rope measuring 96 m is cut into 8 equal parts. What is the length of each part?
Seutas tali yang berukuran 96 m telah dipotong kepada 8 bahagian yang sama panjang.
Berapakah panjang satu bahagian tali itu?
A 11 m
B 12 m
C 13 m
D 14 m
12. 7 m 98 cm – 5 m 89 cm =
A 22 m 99 cm
B 21 m 91 cm
C 12 m 19 cm
D 2 m 9 cm
13. Calculate 4 m 8 cm ÷ 4 =
Hitungkan 4 m 8 cm ÷ 4 =
A 1 m 2 cm
B 4 m 4 cm
C 8 m 12 cm
D 16 m 32 cm
Unit 7 Length Page 190

3. Modul Bestari Matematik UPSR
JPNS 2011
14. Find the difference between 8 cm 14 mm and 2 cm 8 mm
Cari perbezaan antara 8 cm 14 mm dan 2 cm 8 mm
A 22 cm 99 mm
B 20 cm 19 mm
C 10 cm 22 mm
D 6 cm 6 mm
15. Find the product of 1.25 m and 6
Cari hasil darab 1.25 m dan 6.
A 70.5 m
B 7.5 m
C 7.05 m
D 7.005 m
16. Convert 3.25 km to m
Tukarkan 3.25 km kepada m
A 325 m
B 3 250 m
C 32 500 m
D 325 000 m
17. 9 km 700 m – 7 km 650 m =
A 20 km 500 m
B 16 km 150 m
C 16 km 15 m
D 2 km 50 m
18. 0.39 km × 100 =
A 39 m
B 390 m
C 3 900 m
D 39 000 m
19. 950 m ÷ 10 =
A 0.95 km
B 0.095 km
C 0.0095 km
D 0.00095 km
20. 120.5 km – 75 m =
A 45.5 km
B 120.425 km
C 455 km
D 120 425 km
Unit 7 Length Page 191

4. Modul Bestari Matematik UPSR
JPNS 2011
21. 1.25 km × 6 =
A 0.75 m
B 7.50 m
C 750 m
D 7 500 m
22. Find the difference between 0.9 km and 475 m.
Cari beza antara 0.9 km dan 475 m
A 385 m
B 425 m
C 474.1 m
D 852.5 m
23. 1 957 m × 12 =
A 23.484 km
B 234.84 km
C 2 348.4 km
D 23 484 km
24. 6 km 125 m + = 8 km 425 m
What must be written into the box above?
Apakah yang perlu diisi dalam petak di atas?
A 1 km 700 m
B 2 km 300 m
C 14 km 300 m
D 14 km 550 km
25. 1.75 km ÷ 10 =
A 0.175 m
B 1.75 m
C 17.5 m
D 175 m
26. Mosque School
Masjid Sekolah John’s house
7.25 km
Rumah John
825 m
Diagarm 1
Rajah 1
Diagram 1 shows a road map. Find the distance, in km, from the mosque to John’s house
passing through the school.
Rajah 1 menunjukkan peta jalan. Cari jarak, dalam km, dari masjid ke rumah John
melalui sekolah
A 8.075 km
B 8.25 km
C 7.25 km
Unit 7 Length Page 192

5. Modul Bestari Matematik UPSR
JPNS 2011
D 6.425 km
27. A plot of land of 1 500 m long is divided equally into 12 parts. Find the length, in km, of
each part.
Sebidang tanah yang panjangnya 1 500 m dibahagikan kepada 12 bahagian yang sama
besar. Cari panjang, dalam km setiap bahagian.
A 0.125
B 1.5
C 15
D 125
28.
P 6 519 m Q R
Diagram 2
Rajah 2
In Diagram 2, PQ is 4 250 m longer than QR. Calculate the length of QR, in km.
Dalam Rajah 2. PQ adalah 4 250 m lebih panjang daripada QR. Kira panjang QR,
dalam km.
A 107.69
B 22.69
C 10.769
D 2.269
29. 0.035 km of rope is cut into 5 parts of the same length. Find the length of each part, in m.
Seutas tali yang panjangnya 0.035 km telah dipotong kepada 5 bahagian yang sama
panjang. Cari panjang setiap bahagian tali itu, dalam m.
A 70
B 7
C 0.7
D 0.07
30. Add 2.8 km and 412 m. Give the answer in m.
Tambahkan 2.8 km dan 412 m. Berikan jawapan dalam m.
A 4 148
B 3 212
C 414.8
D 3.212
Unit 7 Length Page 193

6. Modul Bestari Matematik UPSR
JPNS 2011
UNIT 7
LENGTH
Subjective Questions
1. 1 cm = __________ mm
2. 1 m = ______________cm
3. 28 cm = _____________ mm
4. 20 m = ______________cm
5. 7.4 m = ___________ cm
6. 14 mm = ___________ cm
7. 807 cm = ___________ mm
8. 3 m 51 cm + 7 m 64 cm = _________ m _________ cm
9. 85 m 33 cm – 49 m 90 cm = _________ m ________ cm
10. Convert the height of the glass below in mm.
Tukarkan tinggi gelas di bawah kepada mm.
12 cm
Unit 7 Length Page 194

7. Modul Bestari Matematik UPSR
JPNS 2011
11. The length of the nail below is __________ cm.
Panjang paku di bawah ialah ______ cm
12. 52 mm = ___________ cm
13. 5 cm + 20 cm = ______________ cm
14. 60 m – 20 m = ____________ m
15. 5. 4 cm x 100 = _______________ cm
16. 25 mm ÷ 5 = _____________ mm
17. Amy walks to the cake house from her house through the bookshop. How far does she
walk altogether, in m?
Amy berjalan ke kedai kek dari rumahnya melalui kedai buku. Berapa jauhkah dia
berjalan, dalam m?
350 m 670 m
Amy’s house Bookshop Cake house
Rumah Amy Kedai buku Kedai kek
Unit 7 Length Page 195

8. Modul Bestari Matematik UPSR
JPNS 2011
18. What is the length of AB, in m?
Apakah jarak AB, dalam m? 550 m
A B C
1 020 m
19. 5 006 m = ___________ km
20. 0.051 km = __________ m
21. 7.64 km + 0.04 km = ____________ m
22. 481 m + 865 m = ______________ km
23. 7.18 km – 1.03 km = _____________ m
24. 6 032 m – 1 153 m = _____________ km
25. 0. 003 km  2 = ____________ km
Unit 7 Length Page 196

9. Modul Bestari Matematik UPSR
JPNS 2011
26. Diagram 26 shows a road map.
Rajah 26 menunjukkan sebuah peta jalan.
Y
8 km 17 km
X Z
Diagram 26
Rajah 26
What is the distance from X to Z through Y, in km?
Apakah jarak dari X ke Z melalui Y, dalam km?
27. Diagram 27 shows the location of houses A, B, C.
Rajah 27 menunjukkan lokasi rumah A, B, C.
C
A
881 km
602 km
B
Diagram 27
Rajah 27
Find the difference in the distance from house A to house B and the distance from house
B to house C, in km.
Cari perbezaan jarak dari rumah A ke rumah B dan jarak rumah B ke rumah C, dalam
km.
28. 567 m = ___________ km
29. 0.640 km = __________ m
Unit 7 Length Page 197

10. Modul Bestari Matematik UPSR
JPNS 2011
30. 30 km + 4 km = ____________ m
31. 866 m + 200 m = ______________ km
32. 8.80 km – 2.30 km = _____________ m
33. 7489 m – 298 m = _____________ km
34. 388 m  6 = ____________ m
35. 0.400 km ÷ 4 = _____________ km
36. Diagram 36 shows the positions of three houses P, Q and R along a street.
Rajah 36 menunjukkan kedudukan tiga buah rumah P, Q dan R sepanjang sebatang
jalan.
3.27 km
P 1.93 km Q R
Diagram 36
Unit 7 Length Page 198

11. Modul Bestari Matematik UPSR
JPNS 2011
Rajah 36
Calculate the distance, in km, between Q and R?
Hitungkan jarak, dalam km, antara Q dan R
37. Diagram 37 shows the location of houses T, U and V.
Rajah 37 menunjukkan lokasi rumah T, U dan V.
V
T
6661 km
321 km
U
Diagram 37
Rajah 37
Find the total distance, in km, from house T to house U and the distance from house U
to house V.
Cari jumlah jarak, dalam km, antara rumah T ke rumah U dan rumah U ke rumah V.
38. Calculate 3.27 km – 216 m. Give your answer in m.
Hitungkan 3.27 km – 216 m. Berikan jawapan anda dalam m.
39. 7.26 km ÷ 3 =
Express your answer in m.
Tukarkan jawapan anda dalam m.
40. 18.03 km – 386 m =
Give your answer in km.
Berikan jawapan anda dalam km.
Unit 7 Length Page 199

12. Modul Bestari Matematik UPSR
JPNS 2011
41. The distance from P to Q is 7 times the distance from Q to R. The distance from Q to R
is 9.465 km. What is the distance from P to Q?
Jarak dari P ke Q ialah 7 kaloi jarak dari Q ke R. Jarak dari Q ke R ialah 9.465 km.
Berapakah jarak dari P ke Q?
42. Mr Wong stays in Lok Kawi. He works in Inanam. He has to pass Putatan before
reaching Inanam. The distance from Lok Kawi to Putatan is 7.8 km, while the distance
from Putatan to Inanam is 20 km 750 m. How far is Mr Wong’s house from his office?
En. Wong tinggal di Lok Kawi. Dia bekerja di Inanam. Dia perlu melalui Putatan
sebelum sampai ke Inanam. Jarak dari Lok Kawi ke Putatan ialah 7.8 km, sementara
jarak dari Putatan ke Inanam ialah 20 km 750 m. Berapa jauhkah pejabat En.Wong dari
rumahnya?
43. The perimeter of a basketball court is 127.5 m. Ranjit ran 9 rounds around the basketball
court. How many kilometres did he run? Give your answer in three decimal places.
Perimeter sebuah gelanggang bola keranjang ialah 127.5 m. Ranjit lari 9 pusingan
mengelilingi gelanggang itu. Berapa kilometer Ranjit telah lari. Berikan jawapan anda
dalam tiga tempat perpuluhan.
44. In a map, 2 cm represents 2.5 km. What distance does 7 cm on the map represents?
Dalam sebuah peta, 2 cm mewakili 2.5 km. Apakah jarak yang diwakili oleh 7 cm di atas
peta itu?
45. The length of a roll wire is 0.015 km. Fuad cuts it into three parts. The length of the first
4
part is 3 m while the second part measures 6.04 m. Find the length, in m, of the third
5
part.
Panjang segulung dawai ialah 0.015 km. Fuad potong dawai itu kepada tiga bahagian.
4
Panjang bahagian pertama ialah 3 m manakala bahagian kedua berukuran 6.04 m.
5
Cari panjang, dalam m, bahagian ketiga.
Unit 7 Length Page 200

13. Modul Bestari Matematik UPSR
JPNS 2011
46. After cutting 20 pieces of ribbons, each measuring 4.2 m, Husniza has 88.5 m of ribbon
left. Find the length, in m, of the original piece of ribbon.
Selepas memotong 20 helai reben, yang berukuran 4.2 m setiap satu, Reben Husniza
masih tinggal 88.5 m. Cari panjang asal reben itu, dalam m.
1
47. Mr Goon drove for 3 km before he stopped for a rest. Then he drove another 5 km
2
900 m to reach his house. What is the total distance, in km, covered by Mr Goon?
1
En. Goon memandu sejauh 3 km sebelum dia berhenti untuk rehat. Kemudian, dia
2
memandu 5 km 900 m untuk sampai ke rumahnya. Berapakah jumlah jarak, dalam km,
yang dilalui oleh En. Goon?
48. The length of a roll wire is 216 m. Find the length, in km, of 8 similar rolls of copper
wire.
Panjang segulung dawai ialah 216 m. Cari panjang, dalam km, 8 gulung dawai yang
sama panjang.
49. Azlan jogged 5 km a day. If he jogs 5 days with the same distance, how far did he jog, in
m, in five days?
Azlan berjoging 5 km sehari. Jika dia berjoging selama 5 hari dengan jarak yang sama,
berapa jauhkah dia berjoging, dalam m, dalam 5 hari.
50. Amir has a rope which measures 7.26 m long. He cuts the rope into 3 equal parts. Find
the length, in cm, of each rope.
Amir ada seutas tali yang berukuran 7.26 m panjang. Dia potong tali itu kepada 3
bahagian yang sama panjang. Cari panjang, dalam cm, setiap tali itu.
Unit 7 Length Page 201

14. Modul Bestari Matematik UPSR
JPNS 2011
UNIT 7
LENGTH
Sample Answers
21. 7.64 km + 0.04 km = ____________ m
7.64 km 7.68km × 1000 = 7680 m
+ 0.04 km
7.68 km
48. The length of a roll wire is 216 m. Find the length, in km, of 8 similar rolls of copper
wire.
Panjang segulung dawai ialah 216 m. Cari panjang, dalam km, 8 gulung dawai yang
sama panjang.
216 m 1728m ÷ 1000 = 1.728 km
× 8
1728 m
Unit 7 Length Page 202

15. Modul Bestari Matematik UPSR
JPNS 2011
UNIT 7
LENGTH
Answers for Objective Questions
1 D 11 B 21 D
2 B 12 D 22 B
3 C 13 A 23 A
4 B 14 D 24 B
5 D 15 B 25 D
6 B 16 B 26 A
7 B 17 D 27 A
8 D 18 D 28 D
9 C 19 B 29 B
10 B 20 B 30 B
UNIT 7 PETUNJUK:
P – Pengetahuan
LENGTH K – Kaedah
N – Nilai
Answers for Subjective Questions
Questions Sub Total
Suggested Answers Remarks
No. Marks Marks
1 10 P1 1
2 100 P1 1
28 cm × 10 K1
3 2
280 mm N1
20 m × 100 K1
4 2
2 000 cm N1
7.4 m × 100 K1
5 2
740 cm N1
6 K1 2
14 mm ÷ 10 N1
1.4 cm
Unit 7 Length Page 203

16. Modul Bestari Matematik UPSR
JPNS 2011
Questions Sub Total
Suggested Answers Remarks
No. Marks Marks
807 cm × 10 K1
7 2
8 070 mm N1
1
3 m 5 1 cm K1
8 2
+ 7 m 6 4 cm N1
1 1 m 1 5 cm
8 5 m 3 3 cm
- 4 9 m 9 0 cm
K1
9 3 5 m 4 3 cm 2
N1
12 cm × 10 K1
10 2
120 mm N1
11 5.4 P1 1
52 mm ÷ 10 K1
12 2
5.2 cm N1
5
+ 2 0
K1
13 2 5 2
N1
6 0 m
- 2 0 m
4 0 m
K1
14 2
N1
K1
15 5.4 cm × 100 2
N1
540 cm
Unit 7 Length Page 204

17. Modul Bestari Matematik UPSR
JPNS 2011
K1
16 25 mm ÷ 5 2
N1
5 mm
1
3 5 0 m
+ 6 7 0 m
1 0 2 0 m K1
17 2
N1
Questions Sub Total
Suggested Answers Remarks
No. Marks Marks
0 9 12
1 0 2 0 m
- 5 5 0 m
4 7 0 m K1
18 2
N1
K1
19 5.006 km 2
N1
K1
20 51 m 2
N1
7 . 6 4 k m
+ 0 . 0 4 k m K1
21 7 . 6 8 k m 2
N1
7.68 km × 1 000
7 680 m
1
0 . 4 8 1 k m K1
22 + 0 . 8 6 5 k m 2
N1
1 . 3 4 6 k m
7 . 1 8 0 k m
- 1 . 0 3 0 k m K1
23 6 . 1 5 0 k m K1 3
N1
6.150 km × 1 000
6 150 m
Unit 7 Length Page 205

18. Modul Bestari Matematik UPSR
JPNS 2011
5 9 12 12
6 0 3 2 m
- 1 1 5 3 m K1
24 4 8 7 9 m K1 3
N1
4 879 m ÷ 1 000
4.879 km
K1
25 0.003 km × 2 2
N1
0.006 km
K1
26 8 km + 17 km 2
N1
25 km
Questions Sub Total
Suggested Answers Remarks
No. Marks Marks
K1
27 881 km – 602 km 2
N1
279 km
P1
28 1
0.567 km
P1
29 1
640 m
30 km + 4 km K1
30 2
34 km × 1 000 N1
34 000 m
866 m + 200 m K1
31 2
1 066 m ÷ 1 000 N1
1.066 km
8.80 km – 2.30 km K1
32 2
6.50 km × 1 000 N1
6 500 m
7 489 m – 298 m K1
33
7 191 m ÷ 1 000 N1
7.191 km
K1
34 388 m × 6 2
N1
2 328 m
K1
35 0.400 km ÷ 4 2
N1
0.100 km
K1
36 3.27 km – 1.93 km 2
N1
1.34 km
Unit 7 Length Page 206

19. Modul Bestari Matematik UPSR
JPNS 2011
K1
37 321 km + 6 661 km 2
N1
6 982 km
3.27 km – 216 m K1
38 2
3 270 m – 216 m N1
3 054 m
7.26 km ÷ 3 K1
39 2
7 260 m ÷ 3 N1
2 420 m
K1
40 18.03 km – 0.386 km 2
N1
17.644 km
Questions Sub Total
Suggested Answers Remarks
No. Marks Marks
9.465 km × 7 K1
41 2
66.255 km N1
7.8 km + 20 km 750 m K1
42 7.8 km + 20.75 km 2
N1
28.55 km
9 × 127.5 m K1
43 1 147.5 m ÷ 1 000 K1 3
1.1475 km N1
1.148 km (three decimal places)
1 cm on the map represents;
2.5 km ÷ 2 K1
1.25 km
44 3
7 cm represents;
7 × 1.25 km K1
8.75 km N1
0.015 km = 15 m
4 K1
45 3 m = 3.80 m 3
5
15 m – 3.80 m – 6.04 m K1
5.16 m N1
20 × 4.2 m K1
46 84.0 m + 88.5 m K1 3
172.5 m N1
47 3
1 K1
3 km + 5 km 900 m
2
3.5 km + 5.9 km K1
Unit 7 Length Page 207

20. Modul Bestari Matematik UPSR
JPNS 2011
9.4 km N1
8 × 216 m = 1 728 m K1
48 K1 3
1 728 m ÷ 1 000
1.728 km N1
5 km × 5 = 25 km K1
49 25 km × 1 000 K1 3
25 000 m N1
7.26 m ÷ 3 = 2.42 m K1
50 2.42 m × 100 K1 3
242 cm N1
Unit 7 Length Page 208