The document evaluates two expressions:
1) u(w(2)), where u(x)=x^2+3x+2 and w(x)=1/(x-1). It finds that u(w(2))=6.
2) w(u(-3)), where u(-3)=2. It then finds that w(u(-3))=1.
The document discusses parabolas and their equations in real world contexts. It shows the steps to derive the equation of a parabola from its vertex: Y=1(X-2)^2+2. By expanding and simplifying this equation, the final equation is found to be Y=X^2-4X+6. This final equation is then compared to the actual equation derived from the parabola: Y=-0.083(x)^2+0.442(X)+1.544, showing their similarities.
This document provides a summary of key algebra concepts including:
1) Basic properties of arithmetic operations, exponents, radicals, inequalities, absolute value, and logarithms.
2) Formulas and methods for factoring, solving equations, completing the square, and using the quadratic formula.
3) Definitions and graphs of common functions like linear, quadratic, parabolic, circular, elliptic, and hyperbolic functions.
4) Examples of common algebraic errors and how to avoid or correct them.
The document discusses the chain rule for taking derivatives of composite functions. It explains that the chain rule allows you to break down composite functions into their constituent parts. The chain rule states that the derivative of the outside function is the derivative of the inside function multiplied by the derivative of the inside with respect to the outside. The document provides an example of using the chain rule to take the derivative of a polynomial function composed of simpler functions. It also notes that the general power rule can be used to take derivatives when the outside function is a power and the inside is a differentiable function.
The document provides a step-by-step guide for finding the vertex of parabolic functions by completing the square. It gives two examples, finding that the vertex of f(x)=x^2 -4x+3 is (2,-1) and the vertex of f(x)=-2x^2 -2x+1 is (-1/2,-1). Completing the square involves factoring the quadratic term and rearranging constants to put the function in vertex form f(x)=a(x-h)^2 + k, where (h,k) gives the vertex coordinates.
The document discusses the chain rule, which is used to find the derivative of composite functions. It provides examples of applying the chain rule to functions of the form f(g(x)) by taking the derivative of the outside function with respect to the inside function, and multiplying by the derivative of the inside function with respect to x. The chain rule can be used repeatedly when a function is composed of multiple nested functions. Derivative formulas themselves incorporate the chain rule. The chain rule is essential for finding derivatives and is the most common mistake made by students on tests.
The same function can have different functional expressions in different ranges. Finding maximum/minimum values in these cases becomes very interesting
This document explains the chain rule for differentiating composite functions. The chain rule states that if y = u(x), where u is expressed in terms of x, then dy/dx = (dy/du) * (du/dx). The document provides examples of applying the chain rule to differentiate functions like y = (3x + 2)^4 and y = 1/(x^2 + 1).
The document contains examples of differentiation formulas and their applications:
1) It provides the formula for differentiating y=u/v with respect to x and works through an example.
2) It differentiates y=x^2 - 5/2x^2 with respect to x using the formula.
3) Additional examples include differentiating trigonometric, exponential, and other functions with respect to x.
The document discusses parabolas and their equations in real world contexts. It shows the steps to derive the equation of a parabola from its vertex: Y=1(X-2)^2+2. By expanding and simplifying this equation, the final equation is found to be Y=X^2-4X+6. This final equation is then compared to the actual equation derived from the parabola: Y=-0.083(x)^2+0.442(X)+1.544, showing their similarities.
This document provides a summary of key algebra concepts including:
1) Basic properties of arithmetic operations, exponents, radicals, inequalities, absolute value, and logarithms.
2) Formulas and methods for factoring, solving equations, completing the square, and using the quadratic formula.
3) Definitions and graphs of common functions like linear, quadratic, parabolic, circular, elliptic, and hyperbolic functions.
4) Examples of common algebraic errors and how to avoid or correct them.
The document discusses the chain rule for taking derivatives of composite functions. It explains that the chain rule allows you to break down composite functions into their constituent parts. The chain rule states that the derivative of the outside function is the derivative of the inside function multiplied by the derivative of the inside with respect to the outside. The document provides an example of using the chain rule to take the derivative of a polynomial function composed of simpler functions. It also notes that the general power rule can be used to take derivatives when the outside function is a power and the inside is a differentiable function.
The document provides a step-by-step guide for finding the vertex of parabolic functions by completing the square. It gives two examples, finding that the vertex of f(x)=x^2 -4x+3 is (2,-1) and the vertex of f(x)=-2x^2 -2x+1 is (-1/2,-1). Completing the square involves factoring the quadratic term and rearranging constants to put the function in vertex form f(x)=a(x-h)^2 + k, where (h,k) gives the vertex coordinates.
The document discusses the chain rule, which is used to find the derivative of composite functions. It provides examples of applying the chain rule to functions of the form f(g(x)) by taking the derivative of the outside function with respect to the inside function, and multiplying by the derivative of the inside function with respect to x. The chain rule can be used repeatedly when a function is composed of multiple nested functions. Derivative formulas themselves incorporate the chain rule. The chain rule is essential for finding derivatives and is the most common mistake made by students on tests.
The same function can have different functional expressions in different ranges. Finding maximum/minimum values in these cases becomes very interesting
This document explains the chain rule for differentiating composite functions. The chain rule states that if y = u(x), where u is expressed in terms of x, then dy/dx = (dy/du) * (du/dx). The document provides examples of applying the chain rule to differentiate functions like y = (3x + 2)^4 and y = 1/(x^2 + 1).
The document contains examples of differentiation formulas and their applications:
1) It provides the formula for differentiating y=u/v with respect to x and works through an example.
2) It differentiates y=x^2 - 5/2x^2 with respect to x using the formula.
3) Additional examples include differentiating trigonometric, exponential, and other functions with respect to x.
This document provides steps to differentiate composite functions using the product rule formula. It gives examples of differentiating expressions like x(x^2 + 3x), (x^3 + 3x)(x^2 + 6), and (2x-5)(3x^2 + 6). It explains letting u and v represent the terms being multiplied and applying the formula du/dx * v + u * dv/dx.
Multiple Choice Questions of Successive Differentiation (Calculus) for B.Sc. 1st Semester (Panjab University ) Mathematics students.There are 2o questions with answer keys.
The document discusses the chain rule and how to use it to find derivatives of more complex equations. It provides examples of using the chain rule to take derivatives of functions involving exponents, trigonometric functions, radicals, and combinations of these. Key steps include identifying the inner and outer functions, taking the derivative of the inner function, and plugging into the chain rule formula. The document also contrasts using the chain rule method versus the inside-outside method for some problems.
The document discusses the chain rule and how to use it to differentiate and integrate composite functions. The chain rule states that if h(x) = g(f(x)), then h'(x) = g'(f(x))f'(x). It provides examples of applying the chain rule to differentiate functions like sin(x2 - 4) and integrate functions like ∫(3x2 + 4)3 dx. It also discusses how to integrate functions of the form f'(x)g(f(x)) by recognizing them as derivatives of composite functions.
The document shows the step-by-step working of simplifying the algebraic expression (5/4) (x^2 + y) - 1/4(x^2 + y) - (x^2 + y). It first uses the distributive property and combines like terms to get the solution of 0. It then notes that a faster approach is to treat the term (x^2 + y) as a single variable w, resulting in a simpler expression that also equals 0. The answer is D.
This document contains the marking scheme for the Mathematics exam of class 12 from the year 2017-18. It lists 12 questions from Section A, 7 questions from Section B, and 4 questions from Section C along with the marks assigned to each question. For most questions, the full solution is provided with marks assigned based on the steps shown. The marking scheme provides the question numbers, expected answers, and total marks to evaluate student responses on the Mathematics exam.
1) The document explains the chain rule for differentiating composite functions.
2) It provides examples of applying the chain rule to functions of the form f(g(x)) where f and g are different functions.
3) The key steps are to let the inner function g(x) equal a variable u, take the derivative of the outer function f(u) with respect to u, and multiply it by the derivative of the inner function g(x) with respect to x.
This document presents the solution to quadruple Fourier series equations involving heat polynomials. Quadruple series equations are useful for solving four-part boundary value problems in fields like electrostatics and elasticity. The document considers two sets of quadruple series equations, the first kind and second kind, involving heat polynomials of the first and second kind. The solutions are obtained by reducing the problems to simultaneous Fredholm integral equations of the second kind. The specific equations considered and the steps to solve them using operator theory are presented.
Engineering Mathematics - Total derivatives, chain rule and derivative of imp...Jayanshu Gundaniya
This document discusses the total derivative and methods for finding derivatives of functions with multiple variables.
The total derivative expresses the total differential of a function u with respect to time t as the sum of the partial derivatives of u with respect to each variable x1, x2,...xn, multiplied by the rate of change of that variable with respect to time.
The chain rule is used to take derivatives of composite functions, where the output of one function is an input to another. The derivative is expressed as the product of the partial derivatives of each nested function.
Derivatives can also be taken for implicit functions, where not all variables can be solved for explicitly. The derivative of one variable with respect to another in an
International Journal of Computational Engineering Research(IJCER) is an intentional online Journal in English monthly publishing journal. This Journal publish original research work that contributes significantly to further the scientific knowledge in engineering and Technology.
This document presents several theorems that establish upper bounds on the coefficients of functions belonging to new subclasses of analytic functions defined using subordination. Theorem 2.1 establishes upper bounds of |a2| and |a3| for functions in the subclass P(β) of a new class of analytic functions. Theorem 3.1 generalizes these results by providing sharper bounds for functions in a broader subclass Q(α,β) in terms of the parameters α and β. The bounds established in Theorems 2.1 and 3.1 are shown to be sharp. The document also discusses some special cases and provides extremal functions that attain the established bounds.
1. The chain rule describes how to take the derivative of a function composed of other functions. It states that if z = f(x, y) and x and y are functions of t, then the derivative of z with respect to t is the sum of the partial derivatives multiplied by the derivatives of x and y with respect to t.
2. The chain rule is applied to find the derivative of two example functions, w = xy and w = xy + z, with respect to t along given paths for x, y, and z in terms of t.
3. The chain rule is generalized to the case of a function u of n variables, where each variable is a function of m other variables
The document provides 12 examples of solving problems involving surds and indices. It covers laws of indices, definitions and laws of surds, and examples of simplifying expressions with surds and indices, evaluating expressions, and determining relative sizes of surds. The examples progress from basic operations to more complex multi-step problems.
The document evaluates two expressions:
1) u(w(2)), where u(x)=x^2+3x+2 and w(x)=1/(x-1). It finds that u(w(2))=6.
2) w(u(-3)), where u(-3)=2. It then finds that w(u(-3))=1.
This document discusses the business and products of Alliance In Motion Global Inc. (AIM Global), a company that produces herbal supplements and food products. Some key points:
- AIM Global has been in business for over 45 years and is publicly traded on the NASDAQ and NYSE. It has over 700 product lines that are approved by regulatory bodies.
- The company emphasizes research and development, conducting clinical studies and using direct processing of plants from its own plantations.
- AIM Global measures the antioxidant levels in its products using the ORAC scale and produces supplements with high levels of antioxidants and other beneficial compounds.
- The document describes several of AIM Global's supplement products and provides
The document describes trends in CD and total revenue from 1990 to 2008. CD sales followed a quadratic function, peaking at 5000 in 1999 and declining to 0 by 2005. Ticket sales followed a linear function, declining from 1.5 to 0 from 1999 to 2005. Total revenue was modeled as a composite function of CD and ticket sales multiplied by 1.04 to the power of t, representing a 4% annual increase. When graphed from 1990 to 2008, total revenue increased until peaking around $24,000 from 2000 to 2001 before declining.
The document evaluates two expressions:
1) u(w(2)), where u(x)=x^2+3x+2 and w(x)=1/(x-1). It finds that u(w(2))=6.
2) w(u(-3)), where u(-3)=2. It then finds that w(u(-3))=1.
This document discusses Alliance In Motion Global Inc., a company that produces herbal supplements and food products. Some key points:
- The company has been in business for 45 years and is traded on the NASDAQ and NYSE. It has over 700 product lines that are FDA, Halal, and Kosher approved.
- The company emphasizes research and development, conducting clinical studies with over 200 medical doctors and herbalists. It uses a direct processing method from plantation to careful harvest.
- The document discusses antioxidants and free radicals, and how the company's products contain high levels of antioxidants to help combat free radical damage in the body.
This document provides steps to differentiate composite functions using the product rule formula. It gives examples of differentiating expressions like x(x^2 + 3x), (x^3 + 3x)(x^2 + 6), and (2x-5)(3x^2 + 6). It explains letting u and v represent the terms being multiplied and applying the formula du/dx * v + u * dv/dx.
Multiple Choice Questions of Successive Differentiation (Calculus) for B.Sc. 1st Semester (Panjab University ) Mathematics students.There are 2o questions with answer keys.
The document discusses the chain rule and how to use it to find derivatives of more complex equations. It provides examples of using the chain rule to take derivatives of functions involving exponents, trigonometric functions, radicals, and combinations of these. Key steps include identifying the inner and outer functions, taking the derivative of the inner function, and plugging into the chain rule formula. The document also contrasts using the chain rule method versus the inside-outside method for some problems.
The document discusses the chain rule and how to use it to differentiate and integrate composite functions. The chain rule states that if h(x) = g(f(x)), then h'(x) = g'(f(x))f'(x). It provides examples of applying the chain rule to differentiate functions like sin(x2 - 4) and integrate functions like ∫(3x2 + 4)3 dx. It also discusses how to integrate functions of the form f'(x)g(f(x)) by recognizing them as derivatives of composite functions.
The document shows the step-by-step working of simplifying the algebraic expression (5/4) (x^2 + y) - 1/4(x^2 + y) - (x^2 + y). It first uses the distributive property and combines like terms to get the solution of 0. It then notes that a faster approach is to treat the term (x^2 + y) as a single variable w, resulting in a simpler expression that also equals 0. The answer is D.
This document contains the marking scheme for the Mathematics exam of class 12 from the year 2017-18. It lists 12 questions from Section A, 7 questions from Section B, and 4 questions from Section C along with the marks assigned to each question. For most questions, the full solution is provided with marks assigned based on the steps shown. The marking scheme provides the question numbers, expected answers, and total marks to evaluate student responses on the Mathematics exam.
1) The document explains the chain rule for differentiating composite functions.
2) It provides examples of applying the chain rule to functions of the form f(g(x)) where f and g are different functions.
3) The key steps are to let the inner function g(x) equal a variable u, take the derivative of the outer function f(u) with respect to u, and multiply it by the derivative of the inner function g(x) with respect to x.
This document presents the solution to quadruple Fourier series equations involving heat polynomials. Quadruple series equations are useful for solving four-part boundary value problems in fields like electrostatics and elasticity. The document considers two sets of quadruple series equations, the first kind and second kind, involving heat polynomials of the first and second kind. The solutions are obtained by reducing the problems to simultaneous Fredholm integral equations of the second kind. The specific equations considered and the steps to solve them using operator theory are presented.
Engineering Mathematics - Total derivatives, chain rule and derivative of imp...Jayanshu Gundaniya
This document discusses the total derivative and methods for finding derivatives of functions with multiple variables.
The total derivative expresses the total differential of a function u with respect to time t as the sum of the partial derivatives of u with respect to each variable x1, x2,...xn, multiplied by the rate of change of that variable with respect to time.
The chain rule is used to take derivatives of composite functions, where the output of one function is an input to another. The derivative is expressed as the product of the partial derivatives of each nested function.
Derivatives can also be taken for implicit functions, where not all variables can be solved for explicitly. The derivative of one variable with respect to another in an
International Journal of Computational Engineering Research(IJCER) is an intentional online Journal in English monthly publishing journal. This Journal publish original research work that contributes significantly to further the scientific knowledge in engineering and Technology.
This document presents several theorems that establish upper bounds on the coefficients of functions belonging to new subclasses of analytic functions defined using subordination. Theorem 2.1 establishes upper bounds of |a2| and |a3| for functions in the subclass P(β) of a new class of analytic functions. Theorem 3.1 generalizes these results by providing sharper bounds for functions in a broader subclass Q(α,β) in terms of the parameters α and β. The bounds established in Theorems 2.1 and 3.1 are shown to be sharp. The document also discusses some special cases and provides extremal functions that attain the established bounds.
1. The chain rule describes how to take the derivative of a function composed of other functions. It states that if z = f(x, y) and x and y are functions of t, then the derivative of z with respect to t is the sum of the partial derivatives multiplied by the derivatives of x and y with respect to t.
2. The chain rule is applied to find the derivative of two example functions, w = xy and w = xy + z, with respect to t along given paths for x, y, and z in terms of t.
3. The chain rule is generalized to the case of a function u of n variables, where each variable is a function of m other variables
The document provides 12 examples of solving problems involving surds and indices. It covers laws of indices, definitions and laws of surds, and examples of simplifying expressions with surds and indices, evaluating expressions, and determining relative sizes of surds. The examples progress from basic operations to more complex multi-step problems.
The document evaluates two expressions:
1) u(w(2)), where u(x)=x^2+3x+2 and w(x)=1/(x-1). It finds that u(w(2))=6.
2) w(u(-3)), where u(-3)=2. It then finds that w(u(-3))=1.
This document discusses the business and products of Alliance In Motion Global Inc. (AIM Global), a company that produces herbal supplements and food products. Some key points:
- AIM Global has been in business for over 45 years and is publicly traded on the NASDAQ and NYSE. It has over 700 product lines that are approved by regulatory bodies.
- The company emphasizes research and development, conducting clinical studies and using direct processing of plants from its own plantations.
- AIM Global measures the antioxidant levels in its products using the ORAC scale and produces supplements with high levels of antioxidants and other beneficial compounds.
- The document describes several of AIM Global's supplement products and provides
The document describes trends in CD and total revenue from 1990 to 2008. CD sales followed a quadratic function, peaking at 5000 in 1999 and declining to 0 by 2005. Ticket sales followed a linear function, declining from 1.5 to 0 from 1999 to 2005. Total revenue was modeled as a composite function of CD and ticket sales multiplied by 1.04 to the power of t, representing a 4% annual increase. When graphed from 1990 to 2008, total revenue increased until peaking around $24,000 from 2000 to 2001 before declining.
The document evaluates two expressions:
1) u(w(2)), where u(x)=x^2+3x+2 and w(x)=1/(x-1). It finds that u(w(2))=6.
2) w(u(-3)), where u(-3)=2. It then finds that w(u(-3))=1.
This document discusses Alliance In Motion Global Inc., a company that produces herbal supplements and food products. Some key points:
- The company has been in business for 45 years and is traded on the NASDAQ and NYSE. It has over 700 product lines that are FDA, Halal, and Kosher approved.
- The company emphasizes research and development, conducting clinical studies with over 200 medical doctors and herbalists. It uses a direct processing method from plantation to careful harvest.
- The document discusses antioxidants and free radicals, and how the company's products contain high levels of antioxidants to help combat free radical damage in the body.
This document discusses the business and products of Alliance In Motion Global Inc. (AIM Global), a supplements and herbal products company. It details AIM Global's history, awards, manufacturing processes, product lines including supplements, coffee products and chocolate products. It also outlines AIM Global's compensation plan which includes retail profits, direct referral bonuses, sales matching bonuses, unilevel bonuses, and other incentives for distributors.
The document describes trends in CD and total revenue from 1990 to 2008. CD sales followed a quadratic function, peaking at 5000 in 1999 and declining to 0 by 2005. Ticket sales followed a linear function, declining from 1.5 to 0 from 1999 to 2005. Total revenue was modeled as a composite function of CD and ticket sales multiplied by 1.04 to the power of t, representing an annual 4% increase. When graphed from 1990 to 2008, total revenue initially increased then declined after peaking at around $24,000 from 2000 to 2001.
The document provides an overview of Carrollco Marketing, a marketing and branding firm with 20 years of experience and over 200 customers. It discusses Carrollco's approach of developing strategic marketing plans through research, messaging, and funnel management. Testimonials from satisfied clients praise Carrollco's success in helping companies expand into new markets, launch new products, and generate publicity and revenue. The document demonstrates Carrollco's services through examples of website design, white papers, and case studies produced for logistics and transportation clients.
The document discusses a staging event at the Elizabeth Gregory Home in Seattle, WA. Volunteers from the International Association of Home Staging Professionals staged several transitional housing units to make them feel more warm, welcoming and personalized for residents. Staging improvements included dressing beds as daybeds, adding seating options, storage solutions and decor items. The event helped improve the living situations for homeless women staying at the transitional housing facility.
The document evaluates two expressions:
1) u(w(2)), where u(x)=x^2+3x+2 and w(x)=1/(x-1). It finds that u(w(2))=6.
2) w(u(-3)), where u(-3)=2. It then finds that w(u(-3))=1.
The document discusses Section 12 of the Indian Contract Act regarding a person being considered of sound mind for the purpose of contracting. It states that a person is of sound mind if they are capable of understanding a contract and forming a rational judgment on how it affects their interests. It provides special cases - a person usually unsound but occasionally sound can contract when sound, and vice versa for a usually sound person when occasionally unsound. An illustration is given of a patient in an asylum who can contract during intervals of soundness.
Icici & custoner service report07 chapter 4Priyanka Gupta
This document provides a history of ICICI Bank from its founding in 1955 as the Industrial Credit and Investment Corporation of India through 2009. It discusses the bank's establishment, expansion both within India and internationally through acquisitions and new branches/subsidiaries, products/services offered, and key developments and milestones over the years. The document is organized by sections covering the bank's history, current scenario, products/services, and a detailed chronological journey through major events.
TEST BANK For Community and Public Health Nursing: Evidence for Practice, 3rd...Donc Test
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Rasamanikya is a excellent preparation in the field of Rasashastra, it is used in various Kushtha Roga, Shwasa, Vicharchika, Bhagandara, Vatarakta, and Phiranga Roga. In this article Preparation& Comparative analytical profile for both Formulationon i.e Rasamanikya prepared by Kushmanda swarasa & Churnodhaka Shodita Haratala. The study aims to provide insights into the comparative efficacy and analytical aspects of these formulations for enhanced therapeutic outcomes.
Does Over-Masturbation Contribute to Chronic Prostatitis.pptxwalterHu5
In some case, your chronic prostatitis may be related to over-masturbation. Generally, natural medicine Diuretic and Anti-inflammatory Pill can help mee get a cure.
Our backs are like superheroes, holding us up and helping us move around. But sometimes, even superheroes can get hurt. That’s where slip discs come in.
Cell Therapy Expansion and Challenges in Autoimmune DiseaseHealth Advances
There is increasing confidence that cell therapies will soon play a role in the treatment of autoimmune disorders, but the extent of this impact remains to be seen. Early readouts on autologous CAR-Ts in lupus are encouraging, but manufacturing and cost limitations are likely to restrict access to highly refractory patients. Allogeneic CAR-Ts have the potential to broaden access to earlier lines of treatment due to their inherent cost benefits, however they will need to demonstrate comparable or improved efficacy to established modalities.
In addition to infrastructure and capacity constraints, CAR-Ts face a very different risk-benefit dynamic in autoimmune compared to oncology, highlighting the need for tolerable therapies with low adverse event risk. CAR-NK and Treg-based therapies are also being developed in certain autoimmune disorders and may demonstrate favorable safety profiles. Several novel non-cell therapies such as bispecific antibodies, nanobodies, and RNAi drugs, may also offer future alternative competitive solutions with variable value propositions.
Widespread adoption of cell therapies will not only require strong efficacy and safety data, but also adapted pricing and access strategies. At oncology-based price points, CAR-Ts are unlikely to achieve broad market access in autoimmune disorders, with eligible patient populations that are potentially orders of magnitude greater than the number of currently addressable cancer patients. Developers have made strides towards reducing cell therapy COGS while improving manufacturing efficiency, but payors will inevitably restrict access until more sustainable pricing is achieved.
Despite these headwinds, industry leaders and investors remain confident that cell therapies are poised to address significant unmet need in patients suffering from autoimmune disorders. However, the extent of this impact on the treatment landscape remains to be seen, as the industry rapidly approaches an inflection point.
- Video recording of this lecture in English language: https://youtu.be/kqbnxVAZs-0
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Dive into an in-depth exploration of the histological structure of female reproductive system with this comprehensive lecture. Presented by Dr. Ayesha Irfan, Assistant Professor of Anatomy, this presentation covers the Gross anatomy and functional histology of the female reproductive organs. Ideal for students, educators, and anyone interested in medical science, this lecture provides clear explanations, detailed diagrams, and valuable insights into female reproductive system. Enhance your knowledge and understanding of this essential aspect of human biology.
1. Example 2 Let u(x)=x²+3x+2 and w(x)=1 x-1 a) Evaluate u(w(2)) b) Evaluate w(u(-3)) Method 1: Find u(w(x)) the sub into equation a) u(x) =x²+3x+2 u(w(x))=(1/(x-1))²+3(1/(x-1))+2 u(w(2))=(1/(2-1)²+3(1/(2-1))+2 =1²+3(1)+2 =6
2. Let u(x)=x²+3x+2 and w(x)=1 x-1 a) Evaluate u(w(2)) b) Evaluate w(u(-3)) Method 2: Find w(2) then sub into equation a) w(x)=1/(x-1) w(2)=1/(2-1) =1 u(w(2))=u(1) =1/(2-1) =6
3. Let u(x)=x²+3x+2 and w(x)=1 x-1 a) Evaluate u(w(2)) b) Evaluate w(u(-3)) Find u(-3) then sub into w(x) and evaluate b) u(x)=x²+3x+2 u(-3)=(-3)²+3(-3)+2 =2 w(u(-3))=w(2) =1/(2-1) =1