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Home ▶︎ Electrical Engineering ▶︎ Engr17-2016F-Tatro ▶︎ Exams and Quizzes ▶︎
Exam 2 - Section 1 - Chapters 4, 5 and 6
Started on Wednesday, 2 November 2016, 11:55 AM
State Finished
Completed on Wednesday, 2 November 2016, 12:55 PM
Time taken 59 mins 42 secs
Grade 82.50 out of 100.00
Question 1
Partially correct
Mark 7.50 out of
15.00
Q1d
a) Find the voltage across the 7.5A current source.
V = -122 Volts
b) Find the voltage across the 25 Ω (Ohm) resistor.
V = -10 Volts
Numeric Answer
V = 216V
V = -10V
Partially correct
Marks for this submission: 7.50/15.00.
7.5A
25Ω
7.5A
25Ω
Question 2
Correct
Mark 15.00 out of
15.00
Q2j
Given:
v = 21 Volts v = 28 Volts
R = 10 Ω (Ohms) R = 40 Ω (Ohms) R = 80 Ω (Ohms)
Find the currents i and i .
i = 63.6 mA (milli Amp)
i = -190.9 mA (milli Amp)
Numeric Answer
i = 63.636 mA
i = -190.909 mA
Correct
Marks for this submission: 15.00/15.00.
1 2
1 2 3
a b
a
b
a
b
Question 3
Correct
Mark 10.00 out of
10.00
Q3f
Given: I = 10 A R = 10 Ω (Ohms) R = 40 Ω (Ohms)
Perform a source transformation and find the voltage transform equivalent.
this circuit.
V = 80 V
R = 8 Ω (Ohm)
Numeric Answer
V = 80 V
R = 8 Ω (Ohm)
Correct
Marks for this submission: 10.00/10.00.
s 1 2
transform
transform
transform
transform
Question 4
Correct
Mark 15.00 out of
15.00
Q4b
Given:
V = 10 Volts I = 3 Amps
R = 20 Ω (Ohm) R = 20 Ω (Ohm) R = 10 Ω (Ohm)
a) Find the Thévenin equivalent voltage V .
V = 35 Volts
b) Find the Thévenin equivalent resistance R .
R = 20 Ω (Ohms)
Numeric Answer
a) V = 35.0 Volts
b) R = 20.0 Ω (Ohms)
Correct
Marks for this submission: 15.00/15.00.
a b
1 2 3
Th
Th
Th
Th
Th
Th
Question 5
Correct
Mark 15.00 out of
15.00
Q5b
Find the Norton equivalent circuit with respect to terminals ab.
I = 6 A
R = 10 Ω (Ohm)
Numeric Answer
I = = 6 A
R = 10 Ω (Ohm)
Correct
Marks for this submission: 15.00/15.00.
N
Th
N
Th
Question 6
Correct
Mark 10.00 out of
10.00
Q6j
Given:
V = 40 Volts R = 140 Ω (Ohm) R = 84 Ω (Ohm)
a) Find the value of R that results in maximum power being transferred to R .
R = 52.5 Ω (Ohms)
b) Find the maximum power that can be delivered to R .
P = 1.07 Watts
Numeric Answer
a) R = 52.50 Ω (Ohms)
b) P = 1.071 Watts
Correct
Marks for this submission: 10.00/10.00.
s 1 2
L L
L,max power
L
RL,max power
L,max power
RL,max power
Question 7
Not answered
Mark 0.00 out of
5.00
Q7j
Assume that the operational amplifier is ideal.
The opamp has two power inputs (not shown) of +V = +15V and –V = -15V.
Given: V = 10 Volts V = 10 Volts
R = 2 kΩ (kilo Ohm) R = 3 kΩ (kilo Ohm) R = 1.5 kΩ (kilo Ohm)
Determine the voltage v .
v = Volts
Numeric Answer
v = -12.5 Volts
cc cc
1 2
1 2 3
out
out
out
Question 8
Incorrect
Mark 0.00 out of
5.00
Q8c
Assume that the operational amplifier is ideal.
The opamp has two power inputs +V = +15V and –V = -15V.
Given: V = -3.0 Volts R = 47 kΩ (kilo Ohm) R = 270 kΩ
(kilo Ohm)
Determine the voltage V .
V = -17.23 Volts
Numeric Answer
v = 15.0 Volts
Incorrect
Marks for this submission: 0.00/5.00.
cc cc
S 1 2
out
out
out
Question 9
Correct
Mark 5.00 out of
5.00
Q9e
Given:
C = 10 µF (micro F) C = 6 µF (micro F) C = 4 µF (micro F)
Find the equivalent capacitance C .
C = 5 µF (micro F)
Numeric Answer
C = 5.0 µF (micro F)
Correct
Marks for this submission: 5.00/5.00.
1 2 3
Eq
Eq
Eq
Question 10
Correct
Mark 5.00 out of
5.00
Q10h
Given:
L = 1 mH (milli H) L = 4 mH (milli H) L = 7 mH (milli H)
Find the equivalent inductance L .
L = 3.55 } mH (milli H)
Numeric Answer
L = 3.5455 mH
Correct
Marks for this submission: 5.00/5.00.
1 2 3
Eq
Eq
Eq

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Electrical Engineering

  • 1. Home ▶︎ Electrical Engineering ▶︎ Engr17-2016F-Tatro ▶︎ Exams and Quizzes ▶︎ Exam 2 - Section 1 - Chapters 4, 5 and 6 Started on Wednesday, 2 November 2016, 11:55 AM State Finished Completed on Wednesday, 2 November 2016, 12:55 PM Time taken 59 mins 42 secs Grade 82.50 out of 100.00
  • 2. Question 1 Partially correct Mark 7.50 out of 15.00 Q1d a) Find the voltage across the 7.5A current source. V = -122 Volts b) Find the voltage across the 25 Ω (Ohm) resistor. V = -10 Volts Numeric Answer V = 216V V = -10V Partially correct Marks for this submission: 7.50/15.00. 7.5A 25Ω 7.5A 25Ω
  • 3. Question 2 Correct Mark 15.00 out of 15.00 Q2j Given: v = 21 Volts v = 28 Volts R = 10 Ω (Ohms) R = 40 Ω (Ohms) R = 80 Ω (Ohms) Find the currents i and i . i = 63.6 mA (milli Amp) i = -190.9 mA (milli Amp) Numeric Answer i = 63.636 mA i = -190.909 mA Correct Marks for this submission: 15.00/15.00. 1 2 1 2 3 a b a b a b
  • 4. Question 3 Correct Mark 10.00 out of 10.00 Q3f Given: I = 10 A R = 10 Ω (Ohms) R = 40 Ω (Ohms) Perform a source transformation and find the voltage transform equivalent. this circuit. V = 80 V R = 8 Ω (Ohm) Numeric Answer V = 80 V R = 8 Ω (Ohm) Correct Marks for this submission: 10.00/10.00. s 1 2 transform transform transform transform
  • 5. Question 4 Correct Mark 15.00 out of 15.00 Q4b Given: V = 10 Volts I = 3 Amps R = 20 Ω (Ohm) R = 20 Ω (Ohm) R = 10 Ω (Ohm) a) Find the Thévenin equivalent voltage V . V = 35 Volts b) Find the Thévenin equivalent resistance R . R = 20 Ω (Ohms) Numeric Answer a) V = 35.0 Volts b) R = 20.0 Ω (Ohms) Correct Marks for this submission: 15.00/15.00. a b 1 2 3 Th Th Th Th Th Th
  • 6. Question 5 Correct Mark 15.00 out of 15.00 Q5b Find the Norton equivalent circuit with respect to terminals ab. I = 6 A R = 10 Ω (Ohm) Numeric Answer I = = 6 A R = 10 Ω (Ohm) Correct Marks for this submission: 15.00/15.00. N Th N Th
  • 7. Question 6 Correct Mark 10.00 out of 10.00 Q6j Given: V = 40 Volts R = 140 Ω (Ohm) R = 84 Ω (Ohm) a) Find the value of R that results in maximum power being transferred to R . R = 52.5 Ω (Ohms) b) Find the maximum power that can be delivered to R . P = 1.07 Watts Numeric Answer a) R = 52.50 Ω (Ohms) b) P = 1.071 Watts Correct Marks for this submission: 10.00/10.00. s 1 2 L L L,max power L RL,max power L,max power RL,max power
  • 8. Question 7 Not answered Mark 0.00 out of 5.00 Q7j Assume that the operational amplifier is ideal. The opamp has two power inputs (not shown) of +V = +15V and –V = -15V. Given: V = 10 Volts V = 10 Volts R = 2 kΩ (kilo Ohm) R = 3 kΩ (kilo Ohm) R = 1.5 kΩ (kilo Ohm) Determine the voltage v . v = Volts Numeric Answer v = -12.5 Volts cc cc 1 2 1 2 3 out out out
  • 9. Question 8 Incorrect Mark 0.00 out of 5.00 Q8c Assume that the operational amplifier is ideal. The opamp has two power inputs +V = +15V and –V = -15V. Given: V = -3.0 Volts R = 47 kΩ (kilo Ohm) R = 270 kΩ (kilo Ohm) Determine the voltage V . V = -17.23 Volts Numeric Answer v = 15.0 Volts Incorrect Marks for this submission: 0.00/5.00. cc cc S 1 2 out out out
  • 10. Question 9 Correct Mark 5.00 out of 5.00 Q9e Given: C = 10 µF (micro F) C = 6 µF (micro F) C = 4 µF (micro F) Find the equivalent capacitance C . C = 5 µF (micro F) Numeric Answer C = 5.0 µF (micro F) Correct Marks for this submission: 5.00/5.00. 1 2 3 Eq Eq Eq
  • 11. Question 10 Correct Mark 5.00 out of 5.00 Q10h Given: L = 1 mH (milli H) L = 4 mH (milli H) L = 7 mH (milli H) Find the equivalent inductance L . L = 3.55 } mH (milli H) Numeric Answer L = 3.5455 mH Correct Marks for this submission: 5.00/5.00. 1 2 3 Eq Eq Eq