1. Transformers are rated in Kilovolt-Amps (KVA) at a specified frequency and voltage, not in Watts, as the load power factor is unknown.
2. Efficiency is the ratio of output power to input power, expressed as a percentage. Some power is lost overcoming iron losses like eddy currents and hysteresis, and copper losses from resistance in the windings.
3. Copper losses vary with the square of the load current and can be measured using a short circuit test, while iron losses are fixed and measured using an open circuit test.
12. PF
S
Power
V1 = 230 V V2 = 32 V
S = 20 kVA
η = 90% PF = 0.85
(a) Power output of transformer
0.85
100
P
P = 85 W
Problem
13. In
Out
η
V1 = 230 V V2 = 32 V
S = 20 kVA
η = 90% PF = 0.85
(b) Power input
P = 94.4 W
η
Out
In
0.9
W
85
In
Problem
14. Losses
Out
In
V1 = 230 V V2 = 32 V
S = 20 kVA
η = 90% PF = 0.85
(c) Losses
P = 9.4W
Losses
85
94.4
Problem
15. Transformer Losses
Copper Losses (Cu)
•Varies with load current
•Produces HEAT
•Created by resistance of windings
•Short circuit test supplies copper losses
16. Short Circuit Test
Copper Losses (Cu)
Secondary
Short Circuited
Limited
Supply
Voltage
≈ 5-10 %
Wattmeter indicates Copper Losses (Cu)
17. Short Circuit Test
100
0.5
loss
Copper
2
Copper Losses (Cu)
•Finds Cooper losses at full load
•Copper losses vary with the square of the load
Full load Cu loss = 100 W
Transformer loaded at 50%
PCu = 25 W
100
0.25
loss
Copper
19. Transformer Losses
Iron Losses (Fe)
•Fixed
•Always present
•Related to transformers construction
Eddy Currents
Reduced by laminations
Produces HEAT
Hysteresis
Reduced by using special
steels in laminations
20. Open Circuit Test
Finds Iron Losses (Fe)
Full Supply
Voltage
Secondary
Open Circuit
Wattmeter indicates Iron Losses (Fe)