Concreto Armado. Diseño y Análisis de Sección Te

1. β1 = 0,85 f'c = 250 fy = 4200
ρt = 0,01613988
ρselecc = 0,01
Rn = 37,83696
Mu = 32000
𝜙 = 0,9
b*d^2= 93970,4341
b= 65 cm
d= 38,0223485
Se asume d = 38,5 cm
rd = 6,5 cm
h = d+rd = 45 cm
SE COMPRUEBA SI TRABAJA COMO RECTANGULAR O COMO Te
As = ρ*b*d = 25,025 cm2
a = 7,60941176 cm
c= 8,95224913 cm
hf = 6 cm
Trabaja como Te
bw = 25 cm
Asf = 12,1428571 cm2
Mnf= 18105 kgf-m
Mnw = 17450,5556
aw = 9,772 cm

2. Mnw(2) = 17450,2879
Tanteo con aw
c= 11,4964706 cm
Asw = 12,3606062 cm2
As = 24,5034634 cm2
As min= 3,20833333 cm
As > As min ok
REVISIÓN Asb = 5,07 db = 2,54
y1= 6,223 cm A1 15,21
y2 = 8,763 cm A2= 10,14
rd = 7,239 cm
CÁLCULO DE d
d = 37,761 cm ACERO COLOCADO = 25,34 cm2
a = 7,70519457 cm
c= 8,95224913 cm C > hf
51000 kgf

3. 12,1428571 cm2
17728,11 kgf-m
13,1971429 cm2
10,4335059 cm
18038,6253 kgf-m
35766,7353 kgf-m
As min= 3,14675 cm
As > As min ok

4. ab/d = 0,51
aw / d = 0,27630375 fs = fy
dt = 38,777 cm
actl/dt = 0,31875
aw / dt = 0,26906429
Control por tracción
32190,0617
Cumple