D is correct. This is the correct command, and must be entered in Li.pdf

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D is correct. This is the correct command, and must be entered in Line Configuration mode. A, B, and C are incorrect. A and B are incorrect because no telnet is not a valid IOS command. C is incorrect because it is the correct command, but it’s in the wrong configuration mode Solution D is correct. This is the correct command, and must be entered in Line Configuration mode. A, B, and C are incorrect. A and B are incorrect because no telnet is not a valid IOS command. C is incorrect because it is the correct command, but it’s in the wrong configuration mode.

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Given the evidence available at the time (early 1800\'s) nothing was wrong with Dalton\'s theory. It accounted for the variations among elements, their relative masses, the observed conservation of mass, and the observations made by earlier scientists about the proportions of elements found in compounds. Dalton did conjecture that atoms somehow stuck together to make compounds, but he couldn\'t explain how. It was only much later that electrons were discovered, showing that atoms weren\'t indestructible solid objects, and later still that it was shown that atoms had a specific internal structure, the exact nature of which is still under investigation. None of these discoveries invalidate Dalton\'s atomic theory -- they expand and enrich it. Dalton\'s theory did exactly what good scientific theories do -- explain and relate existing evidence, and provide a foundation for further inquiry. Solution Given the evidence available at the time (early 1800\'s) nothing was wrong with Dalton\'s theory. It accounted for the variations among elements, their relative masses, the observed conservation of mass, and the observations made by earlier scientists about the proportions of elements found in compounds. Dalton did conjecture that atoms somehow stuck together to make compounds, but he couldn\'t explain how. It was only much later that electrons were discovered, showing that atoms weren\'t indestructible solid objects, and later still that it was shown that atoms had a specific internal structure, the exact nature of which is still under investigation. None of these discoveries invalidate Dalton\'s atomic theory -- they expand and enrich it. Dalton\'s theory did exactly what good scientific theories do -- explain and relate existing evidence, and provide a foundation for further inquiry..

1. Enzymatic digestion of proteins in to amino acids by pepsin.3. .pdf

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1. Assume that those DNA molecules are same in length as well as in .pdf

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1. Assume that those DNA molecules are same in length as well as in other properities such as supercoiling...etc, in gel after electrophoresis, we can observe one thick band. 2. As DNA is -vely charged molecules due to P- ions, if the electrodes connects in wrong direction, it won\'t enter in to gel. Those molecules sometimes may migrate to buffer chambers. Solution 1. Assume that those DNA molecules are same in length as well as in other properities such as supercoiling...etc, in gel after electrophoresis, we can observe one thick band. 2. As DNA is -vely charged molecules due to P- ions, if the electrodes connects in wrong direction, it won\'t enter in to gel. Those molecules sometimes may migrate to buffer chambers..

Try to save the file using .vbs extension rather than .wsfType thi.pdf

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There are two types of respirationAerobic respiration takes plac.pdf

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There are two types of respiration: Aerobic respiration: takes place in presence of Oxygen to produce ATP. The electron transport chain helps to convert NADH and FADH2 in to ATP. Most of the ATP produced by cellular respiration are made with the help of Oxidative phosphorylation. Anaerobic respiration where electron acceptors are other than oxygen .In anaerobes less oxidizing agents are used such as nitrates where substrate level phosphorylation is used to produce ATP. Based on the above descriptions, the correct answers are: a. Aerobic respiration: Substrate level phosphorylation b. Anaerobic respiration with nitrate used as the terminal electron acceptor: Substrate level phosphorylation c. Embden Meyerhoff pathway for glucose catabolism: Oxidative phosphorylation d. Anaerobic respiration with iron used as the terminal electon acceptor: Substrate level phosphorylation Solution There are two types of respiration: Aerobic respiration: takes place in presence of Oxygen to produce ATP. The electron transport chain helps to convert NADH and FADH2 in to ATP. Most of the ATP produced by cellular respiration are made with the help of Oxidative phosphorylation. Anaerobic respiration where electron acceptors are other than oxygen .In anaerobes less oxidizing agents are used such as nitrates where substrate level phosphorylation is used to produce ATP. Based on the above descriptions, the correct answers are: a. Aerobic respiration: Substrate level phosphorylation b. Anaerobic respiration with nitrate used as the terminal electron acceptor: Substrate level phosphorylation c. Embden Meyerhoff pathway for glucose catabolism: Oxidative phosphorylation d. Anaerobic respiration with iron used as the terminal electon acceptor: Substrate level phosphorylation.

The triangle DEF -- TRIANGLE HIG is a glide reflection.Reflection.pdf

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The triangle DEF --> TRIANGLE HIG is a glide reflection. Reflection line: Each point of a reflected image is the same distance from the line of reflection as the corresponding point of the original figure. In other words, the line of reflection lies directly in the middle between the figure and its image -- it is the perpendicular bisector of the segment joining any point to its image. The reflection line = IG Translation rule: The translation rule is shift. Shifts A shift is a rigid translation in that it does not change the shape or size of the graph of the function. All that a shift will do is change the location of the graph. A vertical shift adds/subtracts a constant to/from every y-coordinate while leaving the x-coordinate unchanged. A horizontal shift adds/subtracts a constant to/from every x-coordinate while leaving the y- coordinate unchanged. Vertical and horizontal shifts can be combined into one expression. Shifts are added/subtracted to the x or f(x) components. If the constant is grouped with the x, then it is a horizontal shift, otherwise it is a vertical shift. center and angle of rotation: Glide translation rule:and reflection line: When a translation (a slide or glide) and a reflection are performed one after the other, a transformation called a glide reflection is produced. In a glide reflection, the line of reflection is parallel to the direction of the translation. It does not matter whether you glide first and then reflect, or reflect first and then glide. This transformation is commutative. When two or more transformations are combined to form a new transformation, the result is called a composition of transformations. Since translations and reflections are both isometries, a glide reflection is also an isometry. Solution The triangle DEF --> TRIANGLE HIG is a glide reflection. Reflection line: Each point of a reflected image is the same distance from the line of reflection as the corresponding point of the original figure. In other words, the line of reflection lies directly in the middle between the figure and its image -- it is the perpendicular bisector of the segment joining any point to its image. The reflection line = IG Translation rule: The translation rule is shift. Shifts A shift is a rigid translation in that it does not change the shape or size of the graph of the function. All that a shift will do is change the location of the graph. A vertical shift adds/subtracts a constant to/from every y-coordinate while leaving the x-coordinate unchanged. A horizontal shift adds/subtracts a constant to/from every x-coordinate while leaving the y- coordinate unchanged. Vertical and horizontal shifts can be combined into one expression. Shifts are added/subtracted to the x or f(x) components. If the constant is grouped with the x, then it is a horizontal shift, otherwise it is a vertical shift. center and angle of rotation: Glide translation rule:and reflection line: When a translation (a slide or glide) and a reflectio.

The process of making a chip begins with sand. Sand contains 25 sil.pdf

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The process of making a chip begins with sand. Sand contains 25% silicon by mass. Sand especially Quartz contains high percentage of Silicon dioxide which is the basic ingredient of semiconductor manufacturing. Silicon is purified in multiple stages to obtain the quality called Electronic Grade Silicon in the form of Ingots. Ingots are big mono crystals. Mono crystal Silicon Ingots have highly pure silicon of purity 99.99%. The Ingots are cut into individual silicon discs or slices called wafers. These wafers are polished untile mirror smooth surfaces are obtained. A photo resis layer is applied by rotating the wafers. Wafers are rotated for an even finish. The photo resist finish is exposed to ultra violet light which triggers a chemical reaction which transforms the photo resist to a soluble . UV light exposure is for creating various circuit patterns on the wafer. Solvents are used to clean out the Photo resist to reveal the patterns. made using UV light. Unwanted material is removed by etching. Ion implantation is done by bombarding the various chemical impurities called Ions. Ions are implanted by shooting them onto the surface with a very high speed of over 3 x 10^5 km/h. The wafers are put into a copper sulphate solution . As a result the copper ions are deposited onto the transistor through a process called electroplating. The copper ions settle as a thin layer of copper and the excess material is polished off. Multiple metal layers are created to interconnect. the architecture and design is dependent on the functionality of the transistor or part in which the chip has to work. Functionality tests are done to evaluate the response of every single chip. Wafers are cut into pieces. Furthermore , the defaulty pieces are discarded off. Groups of pieces are arranged to cater for the respective functionality. Hence , the procedure for sand to chip Solution The process of making a chip begins with sand. Sand contains 25% silicon by mass. Sand especially Quartz contains high percentage of Silicon dioxide which is the basic ingredient of semiconductor manufacturing. Silicon is purified in multiple stages to obtain the quality called Electronic Grade Silicon in the form of Ingots. Ingots are big mono crystals. Mono crystal Silicon Ingots have highly pure silicon of purity 99.99%. The Ingots are cut into individual silicon discs or slices called wafers. These wafers are polished untile mirror smooth surfaces are obtained. A photo resis layer is applied by rotating the wafers. Wafers are rotated for an even finish. The photo resist finish is exposed to ultra violet light which triggers a chemical reaction which transforms the photo resist to a soluble . UV light exposure is for creating various circuit patterns on the wafer. Solvents are used to clean out the Photo resist to reveal the patterns. made using UV light. Unwanted material is removed by etching. Ion implantation is done by bombarding the various chemical impurities called Ions. Ions ar.

The Permian Period was the ultimate period of the Paleozoic Era whic.pdf

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The Permian Period was the ultimate period of the Paleozoic Era which lasted from 299 million to 251 million years ago.It preceded the Triassic Period. The evolutionary innovations of seed and pollen are as follows. The giant swamp forests began to dry out totally. The mossy plants that depended on spores for reproduction were being replaced by the the gymnosperms which were the first seed-bearing plants. They are vascular plants, that transport water internally. They have exposed seeds that develop on the scales of cones and are fertilized when pollen sifts down and lands directly on the seed. Today’s conifers are gymnosperms, as are the short palm like cycads. Solution The Permian Period was the ultimate period of the Paleozoic Era which lasted from 299 million to 251 million years ago.It preceded the Triassic Period. The evolutionary innovations of seed and pollen are as follows. The giant swamp forests began to dry out totally. The mossy plants that depended on spores for reproduction were being replaced by the the gymnosperms which were the first seed-bearing plants. They are vascular plants, that transport water internally. They have exposed seeds that develop on the scales of cones and are fertilized when pollen sifts down and lands directly on the seed. Today’s conifers are gymnosperms, as are the short palm like cycads..

RNs role in kidney transplant recipient in the immediate post-operative period; RN\'s role in organ transplantation to assess, plan, implement, practice evidence based approach to evaluate care interventions in the care of the transplant patient . To analyse the biological, psychological and sociological effects of transplantation on the patient. Post-transplant nursing care for the patient begins in the post-anesthesia care unit. The first 24 hours after transplantation represent a critical period, marked by hemodynamic and respiratory instability, and there is a great risk of developing complications, mainly of graft rejection. The nurse treating the patient in the early post-transplant period needs specialized knowledge to reduce the problems, prevent or anticipate and intervene immediately to maximize the result of long-term graft and provide quality care throughout the hospitalization period. The behavior of diuresis is the most important element in the monitoring of renal functions, since it causes therapeutic behaviors such as hydration, medication and even surgery for urologic complications. The urinary catheter placement provides accurate measurement of urine output and determines the presence of hemorrhage and blood clot, acute graft rejection, and vascular thrombosis, and is a predictor of the development of transplantation. The urinary catheter is removed after proper healing of the anastomosis of the ureter into the bladder, when continued monitoring of urine volume is required. During the hospitalization of the patient, daily blood tests must be done, with the most relevant results including levels of serum creatinine, polymerase chain reaction (PCR), white cell count, and levels of immunosuppressive drugs. These parameters determine that the kidney function is effective and show the first signs of a possible rejection or infection, and whether the drug levels are within the therapeutic range required for the maintenance of immunosuppression or induction, maintenance and treatment of rejection. The nurse should moniter the patient\'s hemodynamic status and fluid volume to avoid post- transplant complications while maintaining central venous pressure at 10 mmHg and systolic blood pressure above 120 mmHg. Urine output is replaced on an hourly milliliter-for-milliliter basis and should be recorded hourly. RNs role in kidney transplant donor in the immediate post-operative period Donors face the possibility of post-operative complications such as bleeding, wound infection, fever, etc. Most of the post-operative complications are generally short-term and can be addressed with quality medical care. Closely monitor the renal function to assess for impairment and monitor the hematocrit to asses for bleeding . Donors experience more pain than recipient. Donor who had an open surgical approach may experience more pain than when a laproscopic approach used. Donors who had open approach will be usually discharged from hospital in 4 or 5 day.

Corporate form of business is where an entity is owned by a small .pdf

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Corporate form of business is where an entity is owned by a small or large group of people ,called owners /shareholders ,each of whose liability is limited by shares--subject to laws of the state in which it operates. It has access to finance through issue of shares in the public It is a separate legal entity ,distinct from its shareholders.So, unlike ,sole-proprietorships& partnerships, the shareholders are not personally liable,if the business goes into liquidation. But,the primary disadvantage of this type of business form is double taxation of earnings & dividends of the company. ie. Any distribution of profits to shareholders ,is only from after- tax(corporate tax rate) income of the company. But they are also taxed at the personal level,on receipt of dividends,at the hands of the shareholders.So, the shareholder is subject to double taxation . So, ANSWER: b) double taxation Solution Corporate form of business is where an entity is owned by a small or large group of people ,called owners /shareholders ,each of whose liability is limited by shares--subject to laws of the state in which it operates. It has access to finance through issue of shares in the public It is a separate legal entity ,distinct from its shareholders.So, unlike ,sole-proprietorships& partnerships, the shareholders are not personally liable,if the business goes into liquidation. But,the primary disadvantage of this type of business form is double taxation of earnings & dividends of the company. ie. Any distribution of profits to shareholders ,is only from after- tax(corporate tax rate) income of the company. But they are also taxed at the personal level,on receipt of dividends,at the hands of the shareholders.So, the shareholder is subject to double taxation . So, ANSWER: b) double taxation.

Well first thing to remember is that C,N,S, and P.pdf

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Well first thing to remember is that C,N,S, and P are more often the central atom because they are more likely to bond with more atoms than O,F,H, and Cl. If it wants to bond with more atoms naturally, it will be at the center more often. (If a C always wants 4 atoms attached to it, it will usually get 4 atoms to attach to it, making it the center). Well choice a. can be thrown out because its saying that C,N,S, and P cannot hybridize atomic orbitals (which is already wrong) to allow as many bonds as allowed (meaning that because they can\'t hybridize, they cant hold as many bonds). This is an argument against why they are not central atoms. Choice d. can be thrown out too as well because O,F,H, and Cl are less metalic than the others, yet they do not take as many electrons (because the more electrons an atom shares, the more bonds it makes). If this was true, O,F,H, and Cl would act more as central atoms. This is also a negative argument. Left is B and C. C states that more metallic nonmetals have more desire for electrons, meaning C,N,S, and P want more electrons. This seems true, but then why does B usually only become BF3, meaning they do not want more electrons. B is true because it says that O,F,H, and Cl are less likely to share electrons with more than 2 atoms. It doesn\'t say why, just that it is less likely to. This is true because the sharing electrons with an atom = forming a bond with an atom. So if they don\'t want to share electrons with more than 2, it means they don\'t want to naturally form bonds with more than 2 atoms, which is absolutely true. Compared to C,N,S, and P who are more likely to share electrons with more than 2 atoms and bonding with more atoms meaning they are more often bonded to several atoms aka being the center. Solution Well first thing to remember is that C,N,S, and P are more often the central atom because they are more likely to bond with more atoms than O,F,H, and Cl. If it wants to bond with more atoms naturally, it will be at the center more often. (If a C always wants 4 atoms attached to it, it will usually get 4 atoms to attach to it, making it the center). Well choice a. can be thrown out because its saying that C,N,S, and P cannot hybridize atomic orbitals (which is already wrong) to allow as many bonds as allowed (meaning that because they can\'t hybridize, they cant hold as many bonds). This is an argument against why they are not central atoms. Choice d. can be thrown out too as well because O,F,H, and Cl are less metalic than the others, yet they do not take as many electrons (because the more electrons an atom shares, the more bonds it makes). If this was true, O,F,H, and Cl would act more as central atoms. This is also a negative argument. Left is B and C. C states that more metallic nonmetals have more desire for electrons, meaning C,N,S, and P want more electrons. This seems true, but then why does B usually only become BF3, meaning they do not want more electrons. B is true because it s.

They both have dipole-dipole interactions, interm.pdf

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They both have dipole-dipole interactions, intermolecular hydrogen bonding, and vander wals force. However, water has two lone pairs that can do hydrogen bonding whereas ammonia has only 1 lone pair. Solution They both have dipole-dipole interactions, intermolecular hydrogen bonding, and vander wals force. However, water has two lone pairs that can do hydrogen bonding whereas ammonia has only 1 lone pair..

The violin is a string instrument, usually with f.pdf

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The violin is a string instrument, usually with four strings tuned in perfect fifths. It is the smallest, highest-pitched member of the violin family of string instruments, which also includes the viola and cello. The violin is sometimes informally called a fiddle, regardless of the type of music played on it. The word violin comes from the Medieval Latin word vitula, meaning stringed instrument;this word is also believed to be the source of the Germanic \"fiddle\".The violin, while it has ancient origins, acquired most of its modern characteristics in 16th-century Italy, with some further modifications occurring in the 18th and 19th centuries. Violinists and collectors particularly prize the instruments made by the Gasparo da Sal Solution The violin is a string instrument, usually with four strings tuned in perfect fifths. It is the smallest, highest-pitched member of the violin family of string instruments, which also includes the viola and cello. The violin is sometimes informally called a fiddle, regardless of the type of music played on it. The word violin comes from the Medieval Latin word vitula, meaning stringed instrument;this word is also believed to be the source of the Germanic \"fiddle\".The violin, while it has ancient origins, acquired most of its modern characteristics in 16th-century Italy, with some further modifications occurring in the 18th and 19th centuries. Violinists and collectors particularly prize the instruments made by the Gasparo da Sal.

the element is phosphorus (P) Solution .pdf

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Step1 False ; An elemental sample consists of one.pdf

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solution or homogeneous mixture Solution .pdf

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PV ^ n = constant using pv = N R T we get P ^ .pdf

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PV ^ n = constant using pv = N* R * T we get P ^ 1-n * T ^ n = contant T1= 150 T1= 293 P2= 600 T2 = 393 k P1/P2 = (T2/T1 ) ^ n/1-n 1/4 = ( 1.34)^ n/1-n taking log on both side log( 1/4) = n/1-n * ( log (1.34) n/1-n =-4.736 n= 1.267 Solution PV ^ n = constant using pv = N* R * T we get P ^ 1-n * T ^ n = contant T1= 150 T1= 293 P2= 600 T2 = 393 k P1/P2 = (T2/T1 ) ^ n/1-n 1/4 = ( 1.34)^ n/1-n taking log on both side log( 1/4) = n/1-n * ( log (1.34) n/1-n =-4.736 n= 1.267.

methyl-m-nitrobenzoate is more polar than methyl .pdf

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methyl-m-nitrobenzoate is more polar than methyl benzoate. There is a large separation of charge in the nitro group (between the nitrogen and oxygens). This leads to a higher level of polarity, and the compound containing the nitro is more polar. Hope this helps! Solution methyl-m-nitrobenzoate is more polar than methyl benzoate. There is a large separation of charge in the nitro group (between the nitrogen and oxygens). This leads to a higher level of polarity, and the compound containing the nitro is more polar. Hope this helps!.

L(f(t)) = 6s^4 - 2s^3 .pdf

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It was a 19th century geologist who first recogni.pdf

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It was a 19th century geologist who first recognized periodicity in the physical properties of the elements. Alexandre Beguyer de Chancourtois (1820-1886), professor of geology at the School of Mines in Paris, published in 1862 a list of all the known elements. The list was constructed as a helical graph wrapped around a cylinder--elements with similar properties occupied positions on the same vertical line of cylinder (the list also included some ions and compounds). Using geological terms and published without the diagram, de Chancourtois ideas were completely ignored until the work of Mendeleev. it is used to distinguish elements by their properties Solution It was a 19th century geologist who first recognized periodicity in the physical properties of the elements. Alexandre Beguyer de Chancourtois (1820-1886), professor of geology at the School of Mines in Paris, published in 1862 a list of all the known elements. The list was constructed as a helical graph wrapped around a cylinder--elements with similar properties occupied positions on the same vertical line of cylinder (the list also included some ions and compounds). Using geological terms and published without the diagram, de Chancourtois ideas were completely ignored until the work of Mendeleev. it is used to distinguish elements by their properties.

here the solution is 0.015 M HCl so we have HCl -.pdf

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H2SO4 + 2 NaOH = Na2SO4 + 2 H2O moles of NaOH = .pdf

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D) H2SO4, heat followed by H2, Pt .pdf

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CCl4 4. molecular CaBr2 3. ionic RbF 3. ionic .pdf

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b.HCN Only two atoms bind to C. And there are no.pdf

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NO3-(aq) + 2H+(aq) + e- --- NO2(g) + H2O(l) Ered = +0.80 VCu(s) -.pdf

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internet protocol stack contains 5 layersi)application layerii)t.pdf

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internet protocol stack contains 5 layers i)application layer ii)transport layer iii)network layer iv)link layer v)physical layer a) Route selection is done in network layer b)Provide user services such as e-mail and file transfer is done in application layer c) Mechanical and electrical interface is done in physical layer Solution internet protocol stack contains 5 layers i)application layer ii)transport layer iii)network layer iv)link layer v)physical layer a) Route selection is done in network layer b)Provide user services such as e-mail and file transfer is done in application layer c) Mechanical and electrical interface is done in physical layer.

in water, HC2H3O2 does not ionize since it is a weak acid CsOH, ho.pdf

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in water, HC2H3O2 does not ionize since it is a weak acid CsOH, however, dissociates. Molecular: HC2H3O2(aq) + CsOH(aq) --> CsC2H3O2(aq) + H2O(l) Ionic: HC2H3O2(aq) + Cs+(aq) + OH-(aq) --> Cs+(aq) + C2H3O2-(aq) + H2O(l) Net Ionic: HC2H3O2(aq) + OH-(aq) --> C2H3O2-(aq) + H2O(l) Molecular fomula is where all compound are written as you would see them in reagent bottles. Ionic equation is where all compounds that dissociate in water are written as ions if in aqueous environment Net ionic equation is same as ionic equation, but species identical on both sides of equation (spectator ions) are not written. Hope it helps :D Solution in water, HC2H3O2 does not ionize since it is a weak acid CsOH, however, dissociates. Molecular: HC2H3O2(aq) + CsOH(aq) --> CsC2H3O2(aq) + H2O(l) Ionic: HC2H3O2(aq) + Cs+(aq) + OH-(aq) --> Cs+(aq) + C2H3O2-(aq) + H2O(l) Net Ionic: HC2H3O2(aq) + OH-(aq) --> C2H3O2-(aq) + H2O(l) Molecular fomula is where all compound are written as you would see them in reagent bottles. Ionic equation is where all compounds that dissociate in water are written as ions if in aqueous environment Net ionic equation is same as ionic equation, but species identical on both sides of equation (spectator ions) are not written. Hope it helps :D.

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