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Combinational Logic
By
Dr. Heman Pathak
Associate Professor
Dept. of Comp. Sc.
Kanya Gurukul Dehradun
Combinational Logic
Combinational Logic
Design Procedure
The Problem is Stated
The number of available input variables and required output variables is determined.
The input and output variables are assigned letter symbols.
The truth table that defines the required relationship between inputs and outputs is derived.
The simplified Boolean function for each output variable is obtained.
The logic diagram is drawn.
Adders
Half Adder
X Y S C
0 0 0 0
0 1 1 0
1 0 1 0
1 1 0 1
S’ = X’Y’ + XY C’ = X’ + Y’
S = (X’Y’ + XY)’ C = (X’ + Y’)’
S = (X + Y)(X’ + Y’) C = XY
Design a circuit for Half-Adder
Inputs -2 Outputs - 2
Inputs – x & y Outputs – S & C
Half Adder
Half Adder
Half Adder
S = (X’Y’ + XY)’
S = (X’Y’ + C)
Half Adder
Half Adder
Full Adder
Design a circuit for Full-Adder
Inputs -3 Outputs - 2
Inputs – x,y & z Outputs – S & C
Full Adder
Full Adder
Full Adder
Full Adder
LET A = X  Y = X’Y +XY’
X  Y  Z = A  Z
= A’Z + AZ’
= (X’Y+XY’)’ Z+ (X’Y+XY’)Z’
= (X +Y’)(X’+Y)Z + X’YZ’ + XY’Z’
= (XX’+XY+X’Y’+YY’)Z + X’YZ’+XY’Z’
= XYZ + X’Y’Z + X’YZ’ + XY’Z’
= m1 + m2 + m4 + m7
S = X  Y  Z
Full Adder
C = x’yz + xy’z + xyz’ + xyz
= z(x’y + xy’) + xy(z’ + z)
= z(x  y) + xy
Full Adder
C = x’yz + xy’z + xyz’ + xyz
= z(x’y + xy’) + xy(z’ + z)
= z(x  y) + xy
Half Subtrator
Design a circuit for Half Subtrator
Inputs -2 Outputs - 2
Inputs – x & y Outputs – D & B
Half Subtrator
Full Subtrator
Design a circuit for Full Subtrator
Inputs -3 Outputs - 2
Inputs – x & y Outputs – D & B
Full Subtrator
Full Subtrator
Full Subtrator
Full Subtrator
Binary Parallel Adder
Binary Parallel Adder
Subtraction by 2’s Complement
Subtraction by 2’s Complement
Subtraction by 2’s Complement
M = 4+16+64=84
N = 4+64 = 68
M-N = 16
N-M = -16
Subtraction by 2’s Complement
Subtraction by 2’s Complement
• A – B = A + (B’+1)
= A + B’ + (C0 = 1)
1
Binary Parallel Subtractor
S B F
0 0 0
0 1 1
1 0 1
1 1 0
F = S’B + SB’
Binary Parallel Adder/Subtractor
Carry Propagation
35
Boolean functions
Pi = Ai ⊕ Bi steady state value
Gi = AiBi steady state value
Output sum and carry
Si = Pi ⊕ Ci
Ci+1 = Gi + PiCi
Gi : carry generate Pi : carry propagate
36
• Delay time of n-bit CLAA = XOR + (AND + OR) + XOR
Binary Parallel Adder
Binary Coded Decimal (BCD)
BCD is a class of binary encodings of decimal numbers
where each digit is represented by a four bits.
Decimal
Digit
BCD/
Binary
Decimal
Digit
Binary BCD
0 0000 10 1010 0001 0000
1 0001 11 1011 0001 0001
2 0010 15 1111 0001 0101
3 0011 16 10000 0001 0110
4 0100 17 10001 0001 0111
5 0101 18 10010 0001 1000
6 0110 19 10011 0001 1001
7 0111 20 10100 0010 0000
8 1000 29 11101 0010 1001
9 1001 64 1000000 0110 0100
Binary Coded Decimal (BCD)
Design a Decimal Adder
Input - 9 Output - 5
Input – A,B,Cin Output – Z,Cout
Decimal Adder
• When the binary sum is greater than 1001, we obtain
a non-valid BCD representation.
• The addition of binary 6(0110) to the binary sum
converts it to the correct BCD representation and also
produces an output carry as required.
C = K + Z8Z4 + Z8Z2
Decimal Adder
Decimal Adder
Magnitude Comparator
46
Magnitude Comparator
47
Magnitude Comparator
48
A B X
0 0 1
0 1 0
1 0 0
1 1 1
X = A’B’ + AB
X = A’B’ + AB = A XNOR B
X = (A XOR B)’
= (A’B + AB’)’
= (A’B)’. (AB’)’
= (A + B’).(A’ + B)
= AA’ + AB + A’B’ + BB’
= AB + A’B’
Magnitude Comparator
49
Magnitude Comparator
50
Magnitude Comparator
51
We inspect the relative magnitudes of
pairs of MSB. If equal, we compare
the next lower significant pair of
digits until a pair of unequal digits is
reached.
If the corresponding digit of A is 1
and that of B is 0, we conclude that
A>B.
(A>B)=A3B’3+x3A2B’2+x3x2A1B’1+x3x2x1A0B’0
(A<B)=A’3B3+x3A’2B2+x3x2A’1B1+x3x2x1A’0B0
Decoders
• The decoder is called n-to-m-line decoder, where
m≤2n
.
• the decoder is also used in conjunction with other
code converters such as a BCD-to-seven_segment
decoder.
• 3-to-8 line decoder: For each possible input
combination, there are seven outputs that are equal
to 0 and only one that is equal to 1.
52
Decoders
53
A B Q0 Q1 Q2 Q3
0 0 1 0 0 0
0 1 0 1 0 0
1 0 0 0 1 0
1 1 0 0 0 1
No. of Inputs = n
No. of Possible Combinations = 2n
No. of Outputs ≤ 2n
Decoders (3 X 8)
54
No. of Inputs = 3
No. of Possible Combinations = 23
No. of Outputs = 8
Decoders (3 X 8)
55
Decoders (BCD-to-Decimal)
56
Decoders (BCD-to-Decimal)
57
w x y z D0 D1 D2 D3 D4 D5 D6 D7 D8 D9
Decoders (BCD-to-Decimal)
58
w x y z D0 D1 D2 D3 D4 D5 D6 D7 D8 D9
1 0 1 0 X X X X X X X X X X
1 0 1 1 X X X X X X X X X X
1 1 0 0 X X X X X X X X X X
1 1 0 1 X X X X X X X X X X
1 1 1 0 X X X X X X X X X X
1 1 1 1 X X X X X X X X X X
Decoders (BCD-to-Decimal)
59
YZ 00 01 11 10
00 1 0 0 0
01 0 0 0 0
11 X X X X
10 0 0 X X
WX
Decoders (BCD-to-Decimal)
60
61
Decoders (BCD-to-Decimal)
62
Decoders (3 X 8)
63
Decoders
Decoders
Decoders
Decoder with Enable input
A B Q0 Q1 Q2 Q3
0 0 1 0 0 0
0 1 0 1 0 0
1 0 0 0 1 0
1 1 0 0 0 1
E A B Q0 Q1 Q2 Q3
0 X X 0 0 0 0
1 0 0 1 0 0 0
1 0 1 0 1 0 0
1 1 0 0 0 1 0
1 1 1 0 0 0 1
Decoder with Enable input
Decoder with Enable input
X’/E A/Y B/Z Q0 Q1 Q2 Q3
0 X X 0 0 0 0
1 0 0 1 0 0 0
1 0 1 0 1 0 0
1 1 0 0 0 1 0
1 1 1 0 0 0 1
X/E A/Y B/Z Q4 Q5 Q6 Q7
0 X X 0 0 0 0
1 0 0 1 0 0 0
1 0 1 0 1 0 0
1 1 0 0 0 1 0
1 1 1 0 0 0 1
X Y Z Q0 Q1 Q2 Q3 Q4 Q5 Q6 Q7
0 0 0 1 0 0 0 0 0 0 0
0 0 1 0 1 0 0 0 0 0 0
0 1 0 0 0 1 0 0 0 0 0
0 1 1 0 0 0 1 0 0 0 0
1 0 0 0 0 0 0 1 0 0 0
1 0 1 0 0 0 0 0 1 0 0
1 1 0 0 0 0 0 0 0 1 0
1 1 1 0 0 0 0 0 0 0 1
Decoder with Enable input
X
Y
Z
Decoder with Enable input
Decoder using NAND Gates
E A B D0 D1 D2 D3
1 X X 1 1 1 1
0 0 0 0 1 1 1
0 0 1 1 0 1 1
0 1 0 1 1 0 1
0 1 1 1 1 1 0
Decoder using NAND Gates

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