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Subtracting Integers
Find the difference: 14 – (–15)
Rule To subtract in algebra, add the opposite.
15 is the opposite of –15.
14 + 15 = 29
Directions Rewrite each expression as addition. Solve the
new expression.
EXAMPLE
Name Date Period Workbook Activity
Chapter 1, Lesson 5
5
1. –4–(–11) 10. –5–(–5)
2. 9 –(+3) 11. 2 –(+9)
3. –1–13 12. 1 –(+4)
4. –6–(+10) 13. 6 –8
5. 7 –(–10) 14. –8–(–3)
6. 4 –(+4) 15. –3–(+7)
7. 2 –(+8) 16. 8 –(–7)
8. –11–(–1) 17. 10 –(+5)
9. 6 –(+2) 18. 5 –6
Directions Solve these problems. Write an expression and the
answer.
19. Dara’skite is flying 67 feet high. Jill’sisflying
40 feet high. What is the difference between
the heights of these two kites?
20. A helicopter hovers 60 m above the ocean’s
surface. A submarine is resting 30 m
underwater, directly below the helicopter.
What is the difference between the positions of
these twoobjects?
Algebra©AGS Publishing. Permission is granted to reproduce for classroom use only
Multiplying Integers
Notice the possible combinations for multiplying positive and negative integers.
positive (positive) = positive
positive (negative) = negative
negative (positive) = negative
negative (negative) = positive
4(4) = 16
4(–4) = –16
–4(4) = –16
–4(–4) = 16
Multiplying any integer, positive or negative, by 0 gives 0 as the product.
Directions Tell whether the product is positive, negative, or
zero.
Directions Find each product. Write the
answer.
EXAMPLE
Name Date Period Workbook Activity
Chapter 1, Lesson 6
6
Algebra©AGS Publishing. Permission is granted to reproduce for classroom use only
1. (4)(–7) 6. (5)(–3) 11. (–3)(–9)
2. (–6)(3) 7. (–15)(–1) 12. (4)(6)
3. (–7)(0) 8. (0)(14) 13. (11)(–2)
4. (–9)(–9) 9. (–5)(7) 14. (2)(9)
5. (2)(–11) 10. (–8)(–2) 15. (–6)(4)
16. (2)(9) 25. (–11)(–2)
17. (–5)(9) 26. (–4)(8)
18. (3)(–9) 27. (–10)(–8)
19. (–10)(2) 28. (5)(–5)
20. (–9)(–7) 29. (–1)(–1)
21. (–5)(10) 30. (7)(10)
22. (12)(2)
23. (–32)(0)
24. (6)(–4)
Name Date Period Workbook Activity
Chapter 1, Lesson 6
7
Integers
Algebra©AGS Publishing. Permission is granted to reproduce for classroom use only
Data from a climbing expedition is shown in this table.
During the climb, some climbers began at base camp and climbed to the summit.
Other climbers also began at base camp but did not reach the summit—these climbers
moved back and forth between camps carrying supplies and other necessities.
Directions The movements of various climbers in the expedition are
shown below. Find the number of feet climbed by each climber.
1. Climber A: Base Camp to Camp 1 to Base Camp
2. Climber C: Base Camp to Camp 5 to Base Camp
3. Climber F: Base Camp to Camp 3 to Base Camp
4. Climber B: Base Camp to Camp 2 to Base Camp
5. Climber H: Base Camp to Camp 6 to Base Camp
6. Climber E: Base Camp to Summit to Base Camp
7. Climber G: Base Camp to Camp 4 to Base Camp
8. Climber D: Base Camp to Camp 5 to Camp 3
to Camp 4 to Base Camp
9. Climber I: Base Camp to Camp 2 to Camp 1
to Camp 6 to Base Camp
10. How many feet above base camp is the summit?
Elevationin Feet
(Comparedto SeaLevel)
BaseCamp –384
Camp 1 +5,027
Camp 2 +7,511
Camp 3 +8,860
Camp 4 +10,103
Camp 5 +10,856
Camp 6 +11,349
Summit +12,015
Dividing Positive and Negative Integers
Notice the possible combinations for dividing positive and negative integers.
positive ÷ positive = positive
positive ÷ negative = negative
negative ÷ positive = negative
negative ÷ negative = positive
6 ÷ 2 = 3
6 ÷ –2 = –3
–6 ÷ 2 = –3
–6 ÷ –2 = 3
Dividing 0 by any integer, positive or negative, produces 0 as the quotient.
Directions Tell whether the quotient is positive, negative, or
zero.
Directions Find and write each
quotient.
EXAMPLE
Name Date Period Workbook Activity
Chapter 1, Lesson 7
8
Algebra©AGS Publishing. Permission is granted to reproduce for classroom use only
1. 16 ÷ –4 9. –27÷ 3
2. –63÷ –9 10. 0 ÷ –4
3. –10÷ 2 11. –81÷ –9
4. 33 ÷11 12. 19 ÷ –1
5. –12÷ 4 13. 56 ÷ 8
6. 100 ÷10 14. 500 ÷ 5
7. 36 ÷ –9 15. 32 ÷ –8
8. 15 ÷ –5
16. 36 ÷12 24. –50÷ 10
17. 21 ÷ –7 25. 27 ÷–9
18. 18 ÷ –3 26. –14÷ 2
19. –35÷ 7 27. 0 ÷16
20. –24÷ 2 28. –72÷ –9
21. –16÷ –8 29. –1÷ –1
22. 45 ÷ –9 30. 9 ÷3
23. –200÷–200
Simplifying Expressions—One Variable
Simplify 2n + 2 + 4n.
1. Look for like terms. 2n and 4n are like terms, because they have the same variable, n.
2. Combine the terms: 2n + 4n = 6n
3. Rewrite the whole expression: 6n + 2
Now you are finished, because 6n cannot combine with 2.
Directions In each expression, underline the like
terms.
Directions Simplify each
expression.
EXAMPLE
Name Date Period Workbook Activity
Chapter 1, Lesson 8
9
Algebra©AGS Publishing. Permission is granted to reproduce for classroom use only
1. 3k –8 + 2k
2. p+ 12 + p
3. 100 + 4w+ 4w
4. 5m –3 + 2m
5. 7x + 5x –12
6. –2+ 11c + c
4
7. ——+2m + 3m7
8. 2y –(–3y)+ 7
9. 4x –13 + 5x
10. 8r + (–3r)
11. 3b + b 21. 2y + (–2y)+ 5
12. 11y + 2y + y 22. –5+ 6n –4n
13. 7j + 3j –2j 23. 2x + 11x –13
14. 2k –17 + k 24. –h+ 7h
15. 11x + x –14 25. –11–(–3k)+ k
16. 22 + 2d + 8d 26. 7d –d + 40
17. 9g+ (–2g)+ 4 27. 8 + 3m –(–m)
18. 14h –3 –2h 28. 3w + (–5w)
19. 2m + (–8m) 29. 2 + 5x –2x
20. 3 + 4k –3k 30. 8g+ (–5g)–6
Name Date Period Workbook Activity
Chapter 1, Lesson 9
10
Simplifying Expressions—Several Variables
Simplify 2j + 4 + j – 1 + 3k.
1. Scan for variables. The expression has two: j and k.
2j + j = 3j
3k (no combining required)
2. Combine j terms:
3. Combine k terms:
4. Combine integers: 4 + (–1) = +3
5. Rewrite the whole expression: 3j + 3k + 3
Now you are finished, because you cannot combine unlike terms.
Directions Check the column or columns to show which kinds of
terms each expressionincludes.
Directions Combine like terms. Simplify each expression.
6. 3k –2k + 12 + 5r
7. 2c+ 3b + 8b + c
8. 5k + 3 + 2j –2 –k
9. 7 + 4p –6 + 2m –2p
10. –4n+ 4 –(–2d)+ n –5
11. 18 + (–4x)+ 1 –3x + 8y
12. 2w + (–11)+ 18y + 2w –11
13. 6h –12 –9h + 8k + (–3k)
14. 3 –3m –3m –8p –3p
15. 14x –7 + 3y –7x –7x
EXAMPLE
Expression xterms yterms Integers
1. 3x + 2x + 3 + 6y
2. 3y –14
3. x + 2y –10 + 3y
4. 72 –68
5. x –8
Algebra©AGS Publishing. Permission is granted to reproduce for classroom use only

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COLLEGE ALGEBRA - MIDTERM

  • 1. Subtracting Integers Find the difference: 14 – (–15) Rule To subtract in algebra, add the opposite. 15 is the opposite of –15. 14 + 15 = 29 Directions Rewrite each expression as addition. Solve the new expression. EXAMPLE Name Date Period Workbook Activity Chapter 1, Lesson 5 5 1. –4–(–11) 10. –5–(–5) 2. 9 –(+3) 11. 2 –(+9) 3. –1–13 12. 1 –(+4) 4. –6–(+10) 13. 6 –8 5. 7 –(–10) 14. –8–(–3) 6. 4 –(+4) 15. –3–(+7) 7. 2 –(+8) 16. 8 –(–7) 8. –11–(–1) 17. 10 –(+5) 9. 6 –(+2) 18. 5 –6 Directions Solve these problems. Write an expression and the answer. 19. Dara’skite is flying 67 feet high. Jill’sisflying 40 feet high. What is the difference between the heights of these two kites? 20. A helicopter hovers 60 m above the ocean’s surface. A submarine is resting 30 m underwater, directly below the helicopter. What is the difference between the positions of these twoobjects? Algebra©AGS Publishing. Permission is granted to reproduce for classroom use only
  • 2. Multiplying Integers Notice the possible combinations for multiplying positive and negative integers. positive (positive) = positive positive (negative) = negative negative (positive) = negative negative (negative) = positive 4(4) = 16 4(–4) = –16 –4(4) = –16 –4(–4) = 16 Multiplying any integer, positive or negative, by 0 gives 0 as the product. Directions Tell whether the product is positive, negative, or zero. Directions Find each product. Write the answer. EXAMPLE Name Date Period Workbook Activity Chapter 1, Lesson 6 6 Algebra©AGS Publishing. Permission is granted to reproduce for classroom use only 1. (4)(–7) 6. (5)(–3) 11. (–3)(–9) 2. (–6)(3) 7. (–15)(–1) 12. (4)(6) 3. (–7)(0) 8. (0)(14) 13. (11)(–2) 4. (–9)(–9) 9. (–5)(7) 14. (2)(9) 5. (2)(–11) 10. (–8)(–2) 15. (–6)(4) 16. (2)(9) 25. (–11)(–2) 17. (–5)(9) 26. (–4)(8) 18. (3)(–9) 27. (–10)(–8) 19. (–10)(2) 28. (5)(–5) 20. (–9)(–7) 29. (–1)(–1) 21. (–5)(10) 30. (7)(10) 22. (12)(2) 23. (–32)(0) 24. (6)(–4)
  • 3. Name Date Period Workbook Activity Chapter 1, Lesson 6 7 Integers Algebra©AGS Publishing. Permission is granted to reproduce for classroom use only Data from a climbing expedition is shown in this table. During the climb, some climbers began at base camp and climbed to the summit. Other climbers also began at base camp but did not reach the summit—these climbers moved back and forth between camps carrying supplies and other necessities. Directions The movements of various climbers in the expedition are shown below. Find the number of feet climbed by each climber. 1. Climber A: Base Camp to Camp 1 to Base Camp 2. Climber C: Base Camp to Camp 5 to Base Camp 3. Climber F: Base Camp to Camp 3 to Base Camp 4. Climber B: Base Camp to Camp 2 to Base Camp 5. Climber H: Base Camp to Camp 6 to Base Camp 6. Climber E: Base Camp to Summit to Base Camp 7. Climber G: Base Camp to Camp 4 to Base Camp 8. Climber D: Base Camp to Camp 5 to Camp 3 to Camp 4 to Base Camp 9. Climber I: Base Camp to Camp 2 to Camp 1 to Camp 6 to Base Camp 10. How many feet above base camp is the summit? Elevationin Feet (Comparedto SeaLevel) BaseCamp –384 Camp 1 +5,027 Camp 2 +7,511 Camp 3 +8,860 Camp 4 +10,103 Camp 5 +10,856 Camp 6 +11,349 Summit +12,015
  • 4. Dividing Positive and Negative Integers Notice the possible combinations for dividing positive and negative integers. positive ÷ positive = positive positive ÷ negative = negative negative ÷ positive = negative negative ÷ negative = positive 6 ÷ 2 = 3 6 ÷ –2 = –3 –6 ÷ 2 = –3 –6 ÷ –2 = 3 Dividing 0 by any integer, positive or negative, produces 0 as the quotient. Directions Tell whether the quotient is positive, negative, or zero. Directions Find and write each quotient. EXAMPLE Name Date Period Workbook Activity Chapter 1, Lesson 7 8 Algebra©AGS Publishing. Permission is granted to reproduce for classroom use only 1. 16 ÷ –4 9. –27÷ 3 2. –63÷ –9 10. 0 ÷ –4 3. –10÷ 2 11. –81÷ –9 4. 33 ÷11 12. 19 ÷ –1 5. –12÷ 4 13. 56 ÷ 8 6. 100 ÷10 14. 500 ÷ 5 7. 36 ÷ –9 15. 32 ÷ –8 8. 15 ÷ –5 16. 36 ÷12 24. –50÷ 10 17. 21 ÷ –7 25. 27 ÷–9 18. 18 ÷ –3 26. –14÷ 2 19. –35÷ 7 27. 0 ÷16 20. –24÷ 2 28. –72÷ –9 21. –16÷ –8 29. –1÷ –1 22. 45 ÷ –9 30. 9 ÷3 23. –200÷–200
  • 5. Simplifying Expressions—One Variable Simplify 2n + 2 + 4n. 1. Look for like terms. 2n and 4n are like terms, because they have the same variable, n. 2. Combine the terms: 2n + 4n = 6n 3. Rewrite the whole expression: 6n + 2 Now you are finished, because 6n cannot combine with 2. Directions In each expression, underline the like terms. Directions Simplify each expression. EXAMPLE Name Date Period Workbook Activity Chapter 1, Lesson 8 9 Algebra©AGS Publishing. Permission is granted to reproduce for classroom use only 1. 3k –8 + 2k 2. p+ 12 + p 3. 100 + 4w+ 4w 4. 5m –3 + 2m 5. 7x + 5x –12 6. –2+ 11c + c 4 7. ——+2m + 3m7 8. 2y –(–3y)+ 7 9. 4x –13 + 5x 10. 8r + (–3r) 11. 3b + b 21. 2y + (–2y)+ 5 12. 11y + 2y + y 22. –5+ 6n –4n 13. 7j + 3j –2j 23. 2x + 11x –13 14. 2k –17 + k 24. –h+ 7h 15. 11x + x –14 25. –11–(–3k)+ k 16. 22 + 2d + 8d 26. 7d –d + 40 17. 9g+ (–2g)+ 4 27. 8 + 3m –(–m) 18. 14h –3 –2h 28. 3w + (–5w) 19. 2m + (–8m) 29. 2 + 5x –2x 20. 3 + 4k –3k 30. 8g+ (–5g)–6
  • 6. Name Date Period Workbook Activity Chapter 1, Lesson 9 10 Simplifying Expressions—Several Variables Simplify 2j + 4 + j – 1 + 3k. 1. Scan for variables. The expression has two: j and k. 2j + j = 3j 3k (no combining required) 2. Combine j terms: 3. Combine k terms: 4. Combine integers: 4 + (–1) = +3 5. Rewrite the whole expression: 3j + 3k + 3 Now you are finished, because you cannot combine unlike terms. Directions Check the column or columns to show which kinds of terms each expressionincludes. Directions Combine like terms. Simplify each expression. 6. 3k –2k + 12 + 5r 7. 2c+ 3b + 8b + c 8. 5k + 3 + 2j –2 –k 9. 7 + 4p –6 + 2m –2p 10. –4n+ 4 –(–2d)+ n –5 11. 18 + (–4x)+ 1 –3x + 8y 12. 2w + (–11)+ 18y + 2w –11 13. 6h –12 –9h + 8k + (–3k) 14. 3 –3m –3m –8p –3p 15. 14x –7 + 3y –7x –7x EXAMPLE Expression xterms yterms Integers 1. 3x + 2x + 3 + 6y 2. 3y –14 3. x + 2y –10 + 3y 4. 72 –68 5. x –8 Algebra©AGS Publishing. Permission is granted to reproduce for classroom use only