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1.๐โๅ ฅไพตๅคงๅญฆๅ ฅๅญฆ่่ฏไธญๅฟไฟฎๆนๆ็ปฉโๆฅ่ขญ๏ผALEVELๆฟ่ๅคงๆญ็ง๏ผ่ฝปๆพๆๅฎ่่ฏๆ็ปฉ๏ผ ๐ฅไฝ ่ฟๅจไธบๆ ๆณ่ฟๅ ฅๅคงๅญฆๆ็็ณป็ป่็ฆๆผๅ๏ผๆณ็ฅ้ๅฆไฝ้่ฟๆๆฏๆๆฎตๆดๆน...
1.๐โๅ ฅไพตๅคงๅญฆๅ ฅๅญฆ่่ฏไธญๅฟไฟฎๆนๆ็ปฉโๆฅ่ขญ๏ผALEVELๆฟ่ๅคงๆญ็ง๏ผ่ฝปๆพๆๅฎ่่ฏๆ็ปฉ๏ผ ๐ฅไฝ ่ฟๅจไธบๆ ๆณ่ฟๅ ฅๅคงๅญฆๆ็็ณป็ป่็ฆๆผๅ๏ผๆณ็ฅ้ๅฆไฝ้่ฟๆๆฏๆๆฎตๆดๆน...
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Class 12 chapter 7
1.
CHAPTER โ 7 INTEGRALS Basic
Concepts and Formulae : 1.List of Some Standard Integrals : (i) ๐ฅ ๐ ๐๐ฅ = ๐ฅ ๐+1 ๐+1 + ๐ถ (๐ โ 1) (ii) ๐๐ฅ ๐ฅ = ๐๐๐ ๐ฅ + ๐ถ (iii) ๐๐ฅ = ๐ฅ + ๐ถ (iv) ๐๐๐ ๐ฅ ๐๐ฅ = ๐ ๐๐ ๐ฅ + ๐ถ (v) ๐ ๐๐๐ฅ ๐๐ฅ = โ๐๐๐ ๐ฅ + ๐ถ (vi) ๐ ๐๐2 ๐ฅ ๐๐ฅ = ๐ก๐๐ ๐ฅ + ๐ถ (vii) ๐๐๐ ๐๐2 ๐ฅ ๐๐ฅ = โ๐๐๐ก ๐ฅ + ๐ถ (viii) ๐ ๐๐ ๐ฅ ๐ก๐๐ ๐ฅ ๐๐ฅ = ๐ ๐๐ ๐ฅ + ๐ถ (ix) ๐๐๐ ๐๐ ๐ฅ ๐๐๐ก ๐ฅ ๐๐ฅ = โ๐๐๐ ๐๐ ๐ฅ + ๐ถ (x) ๐ ๐ฅ ๐๐ฅ = ๐ ๐ฅ + ๐ถ (xi) ๐ ๐ฅ ๐๐ฅ = ๐ ๐ฅ ๐๐๐ ๐ + ๐ถ (xii) (a) 1 1โ๐ฅ2 ๐๐ฅ = sinโ1 ๐ฅ + ๐ถ (b) ๐๐ฅ ๐2โ๐ฅ2 = sinโ1 ๐ฅ ๐ + ๐ถ (xiii) (a) 1 1+๐ฅ2 ๐๐ฅ = sinโ1 ๐ฅ + ๐ถ (b) 1 ๐2+๐ฅ2 dx = 1 ๐ tanโ1 ๐ฅ ๐ + ๐ถ (xiv) 1 ๐ฅ ๐ฅ2โ1 ๐๐ฅ = secโ1 ๐ฅ + ๐ถ (xv) โ ๐๐ฅ ๐ฅ ๐ฅ2โ1 = cosecโ1 ๐ฅ + ๐ถ (xvi) โ 1 ๐2โ๐ฅ2 ๐๐ฅ = 1 ๐ cotโ1 ๐ฅ ๐ + ๐ถ (xvii) 1 ๐ฅ ๐ฅ2โ๐2 ๐๐ฅ = 1 ๐ secโ1 ๐ฅ ๐ + ๐ถ (xviii) โ 1 ๐ฅ ๐ฅ2โ๐2 ๐๐ฅ = 1 ๐ cosecโ1 ๐ฅ ๐ + ๐ถ 1. More Standard Results : ๐ก๐๐ ๐ฅ ๐๐ฅ = โ๐๐๐ ๐๐๐ ๐ฅ + ๐ถ = ๐๐๐ ๐ ๐๐ ๐ฅ + ๐ถ, provided x is not an odd multiple of ๐ 2 . ๐๐๐ก ๐ฅ ๐๐ฅ = ๐๐๐ ๐ ๐๐ ๐ฅ + ๐ถ. ๐ ๐๐ ๐ฅ ๐๐ฅ = ๐๐๐ ๐ ๐๐ ๐ฅ + ๐ก๐๐ ๐ฅ + ๐ถ = ๐๐๐ ๐ ๐๐ ๐ 4 + ๐ฅ 2 + ๐ถ . ๐๐๐ ๐๐ ๐ฅ ๐๐ฅ = ๐๐๐ ๐๐๐ ๐๐ ๐ฅ โ ๐๐๐ก ๐ฅ + ๐ถ = ๐๐๐ ๐ก๐๐ ๐ฅ 2 + ๐ถ 2. Results of Some Special Integrals : ๐๐ฅ ๐2 + ๐ฅ2 = 1 ๐ tanโ1 ๐ฅ ๐ + ๐ถ ๐๐ฅ ๐ฅ2 โ ๐2 = 1 2๐ log ๐ฅ โ ๐ ๐ฅ + ๐ + ๐ถ ๐๐ฅ ๐2 โ ๐ฅ2 = 1 2๐ log ๐ + ๐ฅ ๐ โ ๐ฅ + ๐ถ 1 ๐2+๐ฅ2 ๐๐ฅ = ๐๐๐ ๐ฅ+ ๐ฅ2+๐2 ๐ + ๐ถ ๐๐ ๐๐๐ ๐ฅ + ๐ฅ2 + ๐2 +C 1 ๐ฅ2โ๐2 ๐๐ฅ = ๐๐๐ ๐ฅ+ ๐ฅ2โ๐2 ๐ + ๐ถ ๐๐ ๐๐๐ ๐ฅ + ๐ฅ2 โ ๐2 +C 1 ๐2 + ๐ฅ2 ๐๐ฅ = sinโ1 ๐ฅ ๐ + ๐ถ
2.
๐2 โ ๐ฅ2
๐๐ฅ = ๐ฅ 2 ๐2 โ ๐ฅ2 + ๐2 2 sinโ1 ๐ฅ ๐ + ๐ถ ๐2 + ๐ฅ2 ๐๐ฅ = ๐ฅ 2 ๐ฅ2 + ๐2 + ๐2 2 ๐๐๐ ๐ฅ + ๐ฅ2 + ๐2 +C ๐ฅ2 โ ๐2 ๐๐ฅ = ๐ฅ 2 ๐ฅ2 โ ๐2 - ๐2 2 ๐๐๐ ๐ฅ + ๐ฅ2 โ ๐2 +C 3. Properties of Definite Integrals : (i) ๐ ๐ฅ ๐๐ฅ = ๐ ๐ง ๐๐ง ๐ ๐ ๐ ๐ (change of variable) (ii) ๐ ๐ฅ ๐๐ฅ = โ ๐ ๐ฅ ๐๐ฅ ๐ ๐ ๐ ๐ (change of limits) (iii) ๐ ๐ฅ ๐๐ฅ = ๐ ๐ฅ ๐๐ฅ + ๐ ๐ฅ ๐๐ฅ ๐ ๐ ๐ ๐ ๐ ๐ where a < c < b (iv) ๐ ๐ ๐ฅ ๐๐ฅ = ๐ ๐ โ ๐ฅ ๐๐ฅ ๐ 0 ๐ 0 (b) ๐ ๐ฅ ๐๐ฅ = ๐ ๐ + ๐ โ ๐ฅ ๐๐ฅ ๐ ๐ ๐ ๐ (v) (a) ๐ ๐ฅ ๐๐ฅ = 2 ๐ ๐ฅ ๐๐ฅ, ๐ 0 2๐ ๐ if f (2a โ x) = f(x) (b) ๐ ๐ฅ ๐๐ฅ = 0 2๐ ๐ , if f (2a โ x) = - f(x) 1 Mark Questions 1. Integrate the following w.r.t.x. (i) 1 ๐ฅ3 ๐๐ฅ. (ii) 1 ๐ฅ dx. (iii) ๐ ๐๐2 ๐ฅ ๐๐๐ ๐๐2 ๐ฅ ๐๐ฅ. (iv) ๐ก๐๐2 ๐ฅ ๐๐ฅ (v) ๐๐๐ก2 ๐ฅ ๐๐ฅ (vi) ๐๐ฅ ๐ ๐๐2 ๐ฅ ๐๐๐ 2 ๐ฅ . (vii) 2 ๐๐๐ ๐ฅ 3๐ ๐๐2 ๐ฅ ๐๐ฅ. (viii) 2 ๐ก๐๐ ๐ฅ โ 3 ๐๐๐ก ๐ฅ 2 ๐๐ฅ. (ix) ๐ฅ3 ๐ ๐๐ ๐ฅ4 ๐๐ฅ (x) ๐ ๐๐ 2 ๐๐๐ ๐ฅ ๐ฅ dx (xi) ๐ฅ ๐ ๐ฅ2 dx (xii) 1+๐๐๐๐ฅ 2 ๐ฅ dx (xiii) ๐ฅ2 1+๐ฅ3 dx (xiv) ๐ฅ+๐๐๐ 6๐ฅ 3๐ฅ2+ ๐ ๐๐ 6๐ฅ dx (xv) 2๐ฅ + 4 ๐ฅ2 + 4๐ฅ + 3 dx (xvi) 1+๐ ๐๐2๐ฅ ๐ฅ+๐ ๐๐2 ๐ฅ dx (xvii) 1+๐ก๐๐๐ฅ ๐ฅ+๐๐๐ ๐ ๐๐๐ฅ dx (xviii) ๐๐ฅ ๐ฅ+ ๐ฅ (xix) ๐๐ฅ 4๐ฅ2โ9 (xx) ๐ฅ3 1+๐ฅ8 dx (xxi) ๐ฅ2+4๐ฅ ๐ฅ3+6๐ฅ2+5 dx (xxii) ๐ ๐๐ 2 ๐ฅ 3+๐ก๐๐ ๐ฅ dx 2. Evaluate the following integrals : (๐) ๐ ๐๐7 ๐ฅ ๐ 2 โ ๐ 2 dx (ii) ๐ ๐๐ ๐ฅ ๐ฅ dx (iii) ๐ ๐๐2 (7 โ 4๐ฅ) ๐๐ฅ
3.
(iv) ๐ฅ ๐โ1+๐ ๐ฅโ1 ๐ฅ
๐+๐ ๐ฅ dx (v) ๐๐๐ 3+5๐๐๐ ๐ฅ 3+5 ๐ ๐๐ ๐ฅ ๐ 2 0 dx (vi) ๐๐๐ 5 ๐ฅ ๐๐ฅ ๐ 0 (vii) ๐๐ฅ 1+๐ฅ2 1 0 (viii) 2๐ฅ 5๐ฅ2+1 1 0 dx (ix) ๐ฅ ๐ฅ 1 โ2 dx (x) ๐3 ๐๐๐ ๐ฅ ๐ฅ41 0 dx (xi) ๐ฅ 1.5 0 dx (xii) ๐ฅ ๐ฅ 2 0 dx (xiii) 1 1+๐ ๐ฅ dx (xiv) ๐ ๐๐2 ๐ฅ ๐ 2 0 dx (xv) ๐ฅ ๐ฅ2+1 4 2 dx (xvi) ๐ฅ(1 โ ๐ฅ)2 ๐๐ฅ 1 0 (xvii) 1โ๐ก๐๐ ๐ฅ 1+๐ก๐๐ ๐ฅ dx (xviii) ๐๐ฅ ๐ฅ2+1 โ 0 dx (xix) ๐ ๐๐4 ๐ฅ ๐ก๐๐ ๐ฅ ๐๐ฅ (xx) ๐ฅ 2 โ1 dx (xxi) ๐ ๐ฅ 4โ๐2๐ฅ dx (xxii) ๐๐๐ ๐ก๐๐ ๐ฅ ๐๐ฅ ๐ 2 0 (xxiii) ๐ ๐๐75 ๐ฅ + ๐ฅ125๐ โ๐ dx (xxiv) ๐ ๐๐ 2๐ฅ ๐๐ฅ ๐ 2 0 (xv) ๐๐๐ ๐ฅ ๐ ๐๐ ๐ฅ ๐๐๐ ๐ ๐๐ ๐ฅ dx (xvi) ๐ ๐ฅ ๐ ๐ฅ dx (xvii) 1โ๐๐๐ก ๐ฅ ๐ฅ+ ๐๐๐ ๐๐๐ ๐๐ ๐ฅ dx (xviii) ๐๐ฅ 9โ๐ฅ2 3 0 (xix) ๐ ๐ฅ 1+๐2๐ฅ 1 0 dx 4 Marks Questions. 3. Evaluate the following: (i) ๐ฅ2+1 ๐ฅ+1 2 dx (ii) ๐๐ฅ 1+๐ก๐๐ ๐ฅ (iii) ๐๐ฅ 1+๐๐๐ก ๐ฅ (iv) ๐ ๐๐4 ๐ฅ ๐๐ฅ (v) ๐๐๐ 4 ๐ฅ ๐๐ฅ (vi) ๐๐๐ 2๐ฅ ๐๐๐ ๐ฅ +๐ ๐๐ ๐ฅ 2 dx (vii) ๐๐๐ 5 ๐ฅ ๐ ๐๐ ๐ฅ dx (viii) ๐ก๐๐ ๐ฅ ๐ ๐๐ ๐ฅ ๐๐๐ ๐ฅ dx (ix) ๐๐ฅ ๐ ๐๐3 ๐ฅ ๐ ๐๐ (๐ฅ+๐ผ) dx (x) ๐ ๐๐ ๐ฅ ๐ ๐๐ (๐ฅ+๐) dx (xi) ๐๐๐ 2๐ฅโ๐๐๐ ๐ผ ๐๐๐ ๐ฅโ๐๐๐ ๐ผ dx (xii) ๐๐ฅ ๐๐๐ ๐ฅโ๐ ๐๐๐ (๐ฅโ๐) (xiii) ๐๐๐ 2๐ฅ ๐๐๐ 4๐ฅ ๐๐๐ 6๐ฅ ๐๐ฅ (xiv) ๐ ๐๐ 2๐ฅ ๐2 ๐ ๐๐2 ๐ฅ+๐2 ๐๐๐ 2 ๐ฅ dx (xv) ๐ฅ+2 2๐ฅ2+6๐ฅ+5 dx (xvi) ๐๐ฅ 7โ6๐ฅโ๐ฅ2 (xvii) 5๐ฅ+3 ๐ฅ2+4๐ฅ+10) dx
4.
(xviii) ๐ ๐๐( ๐ฅโ ๐ผ ๐ ๐๐
(๐ฅ+ ๐ผ) dx (xix) ๐ฅ ๐ฅ4โ๐ฅ2+1 dx (xx) 2๐ฅ 1โ๐ฅ2โ๐ฅ4 dx (xxi) ๐ ๐ฅ 5โ4๐ ๐ฅ โ๐2๐ฅ dx (xxii) ๐๐๐ ๐ฅ ๐ ๐๐2 ๐ฅโ2 ๐ ๐๐ ๐ฅโ3 dx (xxiii) ๐ฅ 1โ๐ฅ2+๐ฅ4 dx (xxiv) 2๐ฅโ1 ๐ฅโ1 ๐ฅ+2 ๐ฅโ3) dx (xxv) 3๐ฅโ2 ๐ฅ+1 2(๐ฅ+3) dx (xxvi) ๐ ๐๐ ๐ฅ 1โ๐๐๐ ๐ฅ 2โ๐๐๐ ๐ฅ dx (xxvii) ๐ฅ ๐ฅ2+1 (๐ฅ+1) dx (xxviii) ๐๐ฅ ๐ฅ ๐ฅ5+1 dx (xxix) ๐ก๐๐ ๐ฅ ๐๐ฅ (xxx) 2๐ฅ ๐ฅ2+1 (๐ฅ2+3) dx (xxxi) ๐ฅ2 1+๐ฅ3 (2+๐ฅ3) dx (xxxii) ๐๐ฅ ๐ฅ[6 ๐๐๐ ๐ฅ 2+7 ๐๐๐ ๐ฅ+2 dx 4. Integrate the following: (i) ๐ฅ2+1 ๐ฅ4+1 dx (ii) ๐๐ฅ 1+๐ฅ+๐ฅ2+๐ฅ3 dx (iii) ๐ฅ ๐๐๐ 1 + ๐ฅ ๐๐ฅ (iv) ๐ฅ tanโ1 ๐๐ฅ(v) sinโ1 ๐ฅ 2 dx (vi) ๐ ๐๐3 ๐ฅ ๐๐ฅ (vii) ๐ ๐ฅ ๐๐๐ ๐ฅ ๐๐ฅ (viii) sin โ1 ๐ฅ ๐ฅ2 dx (ix) ๐ ๐ฅ [tanโ1 ๐ฅ + 1 1+๐ฅ2]dx (x) ๐ฅ ๐ฅ+1 2 ๐ ๐ฅ ๐๐ฅ (xi) 1 ๐๐๐ ๐ฅ โ 1 ๐๐๐ ๐ฅ 2 dx (xii) ๐ ๐ฅ 1 ๐ฅ โ 1 ๐ฅ2 dx (xiii) ๐ฅ2+1 ๐ฅ+1 2 ๐ ๐ฅ dx (xiv) ๐๐๐ ๐๐๐ ๐ฅ + 1 ๐๐๐ ๐ฅ dx (xv) ๐ ๐ฅ 1 ๐ฅ2 โ 1 ๐ฅ3 dx (xvi) ๐ ๐ฅ 1+๐ ๐๐๐ฅ ๐๐๐ ๐ฅ ๐๐๐ 2 ๐ฅ dx (xvii) 1โ ๐ฅ 1+ ๐ฅ dx (xviii) 2+๐ ๐๐ 2๐ฅ 1+๐๐๐ 2๐ฅ ๐ ๐ฅ dx (xix) ๐ ๐๐8 ๐ฅโ๐๐๐ 8 ๐ฅ 1โ2 ๐ ๐๐2 ๐ฅ ๐๐๐ 2 ๐ฅ dx (xx) sin โ1 ๐ฅโcos โ1 ๐ฅ sin โ1 ๐ฅ+cos โ1 ๐ฅ dx (xxi) ๐ ๐๐ ๐ฅ+๐๐๐ ๐ฅ ๐ ๐๐ ๐ฅ ๐๐๐ ๐ฅ ๐๐ฅ (xxii) ๐๐ฅ ๐ ๐๐ ๐ฅ (5โ4 ๐๐๐ ๐ฅ) (xxiii) ๐ฅ ๐ฅ3โ1 ๐๐ฅ (xxiv) ๐ฅ sinโ1 ๐ฅ ๐๐ฅ (xxv) ๐ฅ2 tanโ1 ๐ฅ ๐๐ฅ (xxvi) 1โ๐ฅ 1+๐ฅ dx (xxvii) 1โ๐ฅ2 ๐ฅ(1โ2๐ฅ) dx 4. Evaluate the following integrals : (i) ๐ ๐๐ ๐ฅ ๐ ๐๐ ๐ฅ+๐๐๐ ๐ฅ ๐ 2 0 ๐๐ฅ (ii) ๐ ๐๐ ๐ฅ ๐ ๐๐ ๐ฅ+ ๐๐๐ ๐ฅ ๐ 2 0 ๐๐ฅ (iii) ๐ฅ ๐ ๐๐ ๐ฅ 1+ ๐๐๐ 2 ๐ฅ ๐ 2 0 ๐๐ฅ
5.
(iv) ๐๐ฅ 1+ ๐ก๐๐ ๐ฅ ๐ 3 ๐ 6 (v)
๐ฅ + 2 5 โ5 ๐๐ฅ (vi) ๐๐๐ 1 + ๐ก๐๐ ๐ฅ ๐๐ฅ ๐ 4 0 (vii) (2 ๐๐๐ ๐ ๐๐ ๐ฅ โ ๐๐๐ ๐ ๐ 2๐ฅ)๐๐ฅ ๐ 2 0 (viii) ๐ ๐๐2 ๐ฅ ๐๐ฅ ๐ 4 โ ๐ 4 (ix) ๐ ๐ฅ 1+ ๐ก๐๐ 3 ๐ฅ ๐ 2 0 (x) ๐ฅ 1+๐ ๐๐ ๐ฅ ๐ 0 ๐๐ฅ (xi) ๐ ๐๐ ๐ฅโ๐๐๐ ๐ฅ 1+๐ ๐๐ ๐ฅ ๐๐๐ ๐ฅ ๐ 2 0 ๐๐ฅ (xii) ๐ฅ ๐ฅ+ ๐โ๐ฅ ๐ 0 dx (xiii) ๐ฅ โ 1 4 0 ๐๐ฅ (xiv) ๐ ๐๐ ๐ฅ+๐๐๐ ๐ฅ ๐ ๐๐ 2 ๐ฅ ๐ 3 ๐ 6 dx (xv) ๐ฅ 1+๐๐๐ 2 ๐ฅ ๐ 0 ๐๐ฅ (xvi) ๐ฅ ๐ก๐๐ ๐ฅ ๐ ๐๐ ๐ฅ ๐๐๐ ๐๐ ๐ฅ ๐ 0 ๐๐ฅ (xvii) ๐ ๐๐ ๐ฅ ๐ 4 โ ๐ 4 ๐๐ฅ (xviii) ๐ฅ ๐ก๐๐ ๐ฅ ๐ ๐๐ ๐ฅ+๐ก๐๐ ๐ฅ ๐ 0 ๐๐ฅ (xix) ๐ฅ ๐๐๐ ๐ ๐ฅ 1 โ1 ๐๐ฅ (xx) ๐ ๐ฅ ๐ ๐๐ 4๐ฅโ4 1โ๐๐๐ 4๐ฅ ๐๐ฅ 6 Marks Questions : 5. Using properties of definite, evaluate. (i) ๐ฅ ๐๐ฅ 4โ๐๐๐ 2 ๐ฅ ๐ 0 (ii) ๐ ๐๐๐ ๐ฅ ๐ ๐๐๐ ๐ฅ +๐โ๐๐๐ ๐ฅ ๐ 0 dx (iii) ๐ฅ ๐๐ฅ ๐2 ๐๐๐ 2 ๐ฅ+ ๐2 ๐ ๐๐2 ๐ฅ ๐ 0 (iv) ๐ ๐๐ ๐ฅ+๐๐๐ ๐ฅ 9+16 ๐ ๐๐ 2๐ฅ ๐ 4 0 ๐๐ฅ (v) ๐๐๐ ๐ ๐๐ ๐ฅ ๐๐ฅ ๐ 2 0 (vi) sinโ1 2๐ฅ 1+๐ฅ2 1 0 dx (vii) ๐ ๐ฅ 3+2 ๐ ๐๐ ๐ฅ+๐๐๐ ๐ฅ ๐ 2 0 (viii) Show that ๐ก๐๐ ๐ฅ + ๐๐๐ก ๐ฅ ๐๐ฅ = 2 ๐ ๐ 2 0 (ix) sinโ1 ๐ฅ ๐+๐ฅ ๐ 0 (x) ๐ ๐๐ 2 ๐ฅ ๐ ๐๐ ๐ฅ+๐๐๐ ๐ฅ ๐ 2 0 dx (xi) ๐ฅ + ๐ฅ + 2 + ๐ฅ + 5 0 โ5 dx (xii) ๐๐๐ ๐ฅ 1โ๐ฅ 1 0 dx (xiii) ๐ก๐๐ ๐ฅ ๐ 4 0 ๐๐ฅ 6. Evaluate as the limit of sums : (i) 2๐ฅ2 โ 5 ๐๐ฅ 3 0 (ii) ๐ฅ2 + 5๐ฅ ๐๐ฅ 3 1 (iii) ๐ฅ2 + ๐ฅ + 1 ๐๐ฅ 2 0 (v) 3๐ฅ2 + 2๐ฅ ๐๐ฅ 3 1 (vi) ๐ฅ2 ๐ฅ ๐ ๐๐ ๐ฅ+๐๐๐ ๐ฅ 2 dx
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