2. LESSON OUTLINE
1.0 Introduction
✓ General Formula: CnH2n
1.1 Structure and Nomenclature: IUPAC And Common Names
1.2 Methods of Preparation (Alkenes):
✓ Dehydrohalogenation of alkyl halides
✓ Dehalogenation of dihalides
✓ Reduction of alkynes
1.3 Reactions of Alkenes And Cycloalkenes
✓ Addition of symmetric reagents: H2 and X2
✓ Markovnikov and anti-Markovnikov rule.
✓ Addition of unsymmetrical reagents: HX and H2O/H2SO4
✓ Oxidation : Combustion, ozonolysis and diol hydroxylation (KMnO4/H+ cold only)
1.4 Simple Test of Alkenes
1.5 Uses
3. 1.0 INTRODUCTION
ALKENE
Unsaturated
HC
Also known
as olefins
Contain a C=C
bond
Terminal
C=C at the
end
Internal
C=C not at
the end
Cycloalkenes
C=C in a cyclic
structure
sp2
hybridization
Trigonal
planar (120°)
General Formula (CnH2n)
Example
CH2CH2
→ C2H2(2): C2H4
So, CH2CH2 is an alkene which is
ethene
4. 1.1 NOMENCLATURE
Parent chain
→Longest continuous
carbon chain
→ Must include C=C
Numbering
→C=C must at lowest
carbon number
Locate and name
substituents
Arrange
→Alphabetical order
10. RULE 3
Identify and numbered all the substituent present
Locate and name substituents
11. RULE 4 Alphabetical order
Have 3 methyl group
at C2, C3 & C5
✓ Use prefix
2,3,5-trimethyl-2-hexene or 2,3,5-trimethylhex-2-ene
12. COMMON RULES
Compounds with two double bonds;
✓dienes by changing the “-ane” ending of the parent alkane
to the suffix “–adiene”.
Compounds with three double bonds;
✓atrienes, and so forth.
CH2=CH-CH=CH2 CH2=CH-CH=CH-CH=CH2
1,3-butadiene 1,3,5-hexatriene
13. ALKENOLS
The chain (or ring) is numbered to give the OH group the lower
number.
Double bond and a Hydroxyl group
16. RULE 1
Find longest continuous carbon chain that must includes a carbon
double bond
Longest Continuous Carbon Chain (must have “=”)
3
5
1
6 4
2
B
r
17. Double bond: C1 and C2.
If substituent at double
bond,
➢ Substituent : C1
RULE 2
1
3
5
4 2
6
Double bond: C1 and C2.
If have > 1, double bond,
➢ Double Bond :
Lowest Carbon
Number
Numbering
3
5
1
6 4
2
18. RULE 3
Identify and numbered all the substituent present
Locate and name substituents
3
5
1
6 4
2 ✓ 1-tert-butyl
✓ 3-isopropyl or 3-sec-propyl
✓ 5-methyl
23. SAYTZEFF RULE
Elimination product that favor formation of an alkene with greatest
number of substituents attached to the C=C group.
CH3CH-CH-CH2
Br
H H
KOH CH3CH=CH-CH3 CH3CH2CH=CH2
alcohol
reflux
2-bromobutane
2-butene
(major product)
1-butene
29. ADDITION REACTION
• A reaction in which an unsaturated molecule becomes saturated by
the addition of a molecule across a multiple bond (C=C in alkenes,
-C≡C- in alkynes, C=O in aldehydes and ketones)
• Characteristics:
✓the π bond of the double bond is broken and two single bonds
are formed
✓only one product is obtained at the end of the reaction
✓the product obtained is a saturated organic compound
32. I) HYDROGENATION
Hydrogen in the present of catalyst (Pt, Ni or Pd) will be
added to double bond to form an alkanes
Ni, Pt or Pd
Addition of hydrogen to a double bond
33. II) HALOGENATION
Addition of halogen (X2) to a double bond
✓ Alkenes react with halogens at room temperature and in dark.
✓ Halogens is usually dissolved in an inert solvent such as
dichloromethane (CH2Cl2) and tetrachloromethane (CCl4).
37. MARKOVNIKOV RULES
H atom will be added to the double bond that has
more hydrogen attached to it.
The more electropositive atom of the reagent will be added to the carbon that
has more H atoms.
47. I) COMBUSTION
Alkenes burn with a more sooty flame than alkanes
1. The double bond means there is less hydrogen to combine
with oxygen.
2. Some carbon will not be oxidized and will produce carbon in the
form of soot.
3. Hence, alkenes are not used a fuels
Reaction with oxygen (O2) to produce carbon dioxide ( CO2) and water (H2O)
C2H4 + 3O2 → 2CO2 + 2H2O
48. II) OZONOLYSIS
C C
R
R
R'
H
O3 C
O O
C
O R'
H
R
R
(CH3)2S
C O
R
R
C
O
R'
H
ozonide ketone aldehyde
or H2O, Zn/H+
Reaction with ozone (O3) to produce ketone and/or aldehyde
Reagent
✓O3, (CH3)2S or H2O, Zinc/ H+ or Zinc dust
50. III) HYDROXYLATION
Reagent
✓cold, dilute, alkaline potassium permanganate (KMnO4)
✓known as Baeyer’s reagent
Reaction with cold, dilute KMnO4, -OH to produce a diol
52. 1.4 SIMPLE TEST FOR ALKENES
BAEYER’S TEST
Cold, dilute, alkaline
KMnO4
BROMINE TEST
Bromine in inert solution
53. BAEYER’S TEST
• Test : Baeyer’s test
• Reagent and : Cold, dilute, KMnO4 solution, H+ or OH-
condition
• Observation : i) Alkane : Purple color of KMnO4 remain unchanged
: ii) Alkene : Purple color of KMnO4 decolorized and formation of
brown precipitate of manganese (IV) oxide, MnO2
C C C C
OH OH
MnO2
KMnO4 (aq), OH-
cold, dilute
a diol / glycol brown precipitate
54. BROMINE TEST
• Test : Bromine test
• Reagent and : Bromine in inert solvent (CCl4 or CH2Cl2) condition
• Observation : i) Alkane : Brown/ yellow color of bromine remain unchanged
: ii) Alkene : Brown/ yellow color of bromine decolorized
55. 1.5 USES
• Ethylene and propylene are the largest-volume industrial organic chemicals.
• Used to synthesis a wide variety of useful compounds.