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CHAPTER 3
ALKENES & CYCLOALKENES
CHM258
LESSON OUTLINE
1.0 Introduction
✓ General Formula: CnH2n
1.1 Structure and Nomenclature: IUPAC And Common Names
1.2 Methods of Preparation (Alkenes):
✓ Dehydrohalogenation of alkyl halides
✓ Dehalogenation of dihalides
✓ Reduction of alkynes
1.3 Reactions of Alkenes And Cycloalkenes
✓ Addition of symmetric reagents: H2 and X2
✓ Markovnikov and anti-Markovnikov rule.
✓ Addition of unsymmetrical reagents: HX and H2O/H2SO4
✓ Oxidation : Combustion, ozonolysis and diol hydroxylation (KMnO4/H+ cold only)
1.4 Simple Test of Alkenes
1.5 Uses
1.0 INTRODUCTION
ALKENE
Unsaturated
HC
Also known
as olefins
Contain a C=C
bond
Terminal
C=C at the
end
Internal
C=C not at
the end
Cycloalkenes
C=C in a cyclic
structure
sp2
hybridization
Trigonal
planar (120°)
General Formula (CnH2n)
Example
CH2CH2
→ C2H2(2): C2H4
So, CH2CH2 is an alkene which is
ethene
1.1 NOMENCLATURE
Parent chain
→Longest continuous
carbon chain
→ Must include C=C
Numbering
→C=C must at lowest
carbon number
Locate and name
substituents
Arrange
→Alphabetical order
BASIC
ALKENES
ALKENOLS
CIS-
TRANS
ALKENES
1.1 NOMENCLATURE
ALKENES
RULE 1
Find longest continuous carbon chain that must includes a carbon
double bond
Longest Continuous Carbon Chain
RULE 1
Longest carbon chain must contain both atoms of the double bond.
RULE 2
Double bond must at the lowest
carbon number
Numbering
RULE 3
Identify and numbered all the substituent present
Locate and name substituents
RULE 4 Alphabetical order
Have 3 methyl group
at C2, C3 & C5
✓ Use prefix
2,3,5-trimethyl-2-hexene or 2,3,5-trimethylhex-2-ene
COMMON RULES
Compounds with two double bonds;
✓dienes by changing the “-ane” ending of the parent alkane
to the suffix “–adiene”.
Compounds with three double bonds;
✓atrienes, and so forth.
CH2=CH-CH=CH2 CH2=CH-CH=CH-CH=CH2
1,3-butadiene 1,3,5-hexatriene
ALKENOLS
The chain (or ring) is numbered to give the OH group the lower
number.
Double bond and a Hydroxyl group
CIS &TRANS ISOMER
CYCLOALKENES
RULE 1
Find longest continuous carbon chain that must includes a carbon
double bond
Longest Continuous Carbon Chain (must have “=”)
3
5
1
6 4
2
B
r
Double bond: C1 and C2.
If substituent at double
bond,
➢ Substituent : C1
RULE 2
1
3
5
4 2
6
Double bond: C1 and C2.
If have > 1, double bond,
➢ Double Bond :
Lowest Carbon
Number
Numbering
3
5
1
6 4
2
RULE 3
Identify and numbered all the substituent present
Locate and name substituents
3
5
1
6 4
2 ✓ 1-tert-butyl
✓ 3-isopropyl or 3-sec-propyl
✓ 5-methyl
RULE 4
Alphabetical order
3
5
1
6 4
2 ✓ 1-tert-butyl
✓ 3-isopropyl or 3-sec-propyl
✓ 5-methyl
1-tert-butyl-3-isopropyl-5-methylcyclohexa-1,3-dienes
@
1-tert-butyl-5-methyl-3-sec-propylcyclohexa-1,3-dienes
Exercise
2,3,4-tribromo-penta-2,3-diene
2-chlorobutan-2-ene
Cis-6-ethyl-2-methylcyclohexa-1,3-diene
2-bromo-3-chloro-5-iodocyclopenta-1,3-diene
1.2 METHOD OF PREPARATION
(ALKENES)
I) Dehydrohalogenation
of alkyl halides
(-HX)
II) Dehalogenation of
dihalides
(-X2)
III) Reduction of
alkynes
I) DEHYDROHALOGENATION OF
ALKYL HALIDE
Elimination of hydrogen and halogen from an alkyl halides to form alkene
SAYTZEFF RULE
Elimination product that favor formation of an alkene with greatest
number of substituents attached to the C=C group.
CH3CH-CH-CH2
Br
H H
KOH CH3CH=CH-CH3 CH3CH2CH=CH2
alcohol
reflux
2-bromobutane
2-butene
(major product)
1-butene
EXAMPLE
BACK
II) DEHALOGENATION OF
DIHALIDES
Elimination of two vicinal halide from an alkyl dihalides to form alkene
BACK
III) REDUCTION OF ALKYNES
i. Alkynes to cis-alkenes
ii. Alkynes to trans-alkenes
EXAMPLE
BACK
1.3 REACTION OF ALKENES
ADDITION
I) Hydrogenation
II) Halogenation
III) Hydration
IV) Hydrohalogenation
OXIDATION
I) Combustion
II) Ozonolysis
III) Hydroxylation
ADDITION REACTION
• A reaction in which an unsaturated molecule becomes saturated by
the addition of a molecule across a multiple bond (C=C in alkenes,
-C≡C- in alkynes, C=O in aldehydes and ketones)
• Characteristics:
✓the π bond of the double bond is broken and two single bonds
are formed
✓only one product is obtained at the end of the reaction
✓the product obtained is a saturated organic compound
ADDITION REACTION
SYMMETRICAL
REAGENT
I) HYDROGENATION II) HALOGENATION
UNSYMMETRICAL
REAGENT
III) HYDRO-
HALOGENATION
IV) HYDRATION
Addition Of
Symmetrical
Reagent
I) HYDROGENATION
Hydrogen in the present of catalyst (Pt, Ni or Pd) will be
added to double bond to form an alkanes
Ni, Pt or Pd
Addition of hydrogen to a double bond
II) HALOGENATION
Addition of halogen (X2) to a double bond
✓ Alkenes react with halogens at room temperature and in dark.
✓ Halogens is usually dissolved in an inert solvent such as
dichloromethane (CH2Cl2) and tetrachloromethane (CCl4).
EXAMPLES
Addition of
Unsymmetrical
Reagent
STABILITY OF CARBOCATION
The greater the number of alkyl groups on
the carbon atom, the greater its stability
MARKOVNIKOV RULES
H atom will be added to the double bond that has
more hydrogen attached to it.
The more electropositive atom of the reagent will be added to the carbon that
has more H atoms.
III) HYDRATION
Reagent : H2SO4 or H3PO4 , 300°C
Addition of water (H2O) to a double bond.
EXAMPLES
IV) HYDROHALOGENATION
Addition of hydrogen halides (HX) to a double bond
EXAMPLES
ANTI-MARKOVNIKOV RULES
Addition of hydrogen bromide (HBr) to a double bond with
presence of peroxide or H2O2 or ROOR.
SUMMARY
CYCLOALKENES
H2, Pt
X2, CCl4
X2, H2O H-X
H2O,
H2SO4 H Br, ROOR
X
H
H
Br
OH
H
OH
X
X
X
H
H
EXAMPLES
OXIDATION REACTION
COMBUSTION OZONOLYSIS
HYDROXYLATION
(reactions that form carbon-oxygen bonds)
I) COMBUSTION
Alkenes burn with a more sooty flame than alkanes
1. The double bond means there is less hydrogen to combine
with oxygen.
2. Some carbon will not be oxidized and will produce carbon in the
form of soot.
3. Hence, alkenes are not used a fuels
Reaction with oxygen (O2) to produce carbon dioxide ( CO2) and water (H2O)
C2H4 + 3O2 → 2CO2 + 2H2O
II) OZONOLYSIS
C C
R
R
R'
H
O3 C
O O
C
O R'
H
R
R
(CH3)2S
C O
R
R
C
O
R'
H
ozonide ketone aldehyde
or H2O, Zn/H+
Reaction with ozone (O3) to produce ketone and/or aldehyde
Reagent
✓O3, (CH3)2S or H2O, Zinc/ H+ or Zinc dust
EXAMPLE
III) HYDROXYLATION
Reagent
✓cold, dilute, alkaline potassium permanganate (KMnO4)
✓known as Baeyer’s reagent
Reaction with cold, dilute KMnO4, -OH to produce a diol
EXAMPLES
CH CH2
CH3
CH2 CH2 CH2 CH2
OH OH
CH2
OH
CH
CH3
OH
MnO2
MnO2
KMnO4 (aq), OH-
cold, dilute
ethene
1,2-ethanediol
KMnO4 (aq), OH-
cold, dilute
propene
1,2-propanediol
1.4 SIMPLE TEST FOR ALKENES
BAEYER’S TEST
Cold, dilute, alkaline
KMnO4
BROMINE TEST
Bromine in inert solution
BAEYER’S TEST
• Test : Baeyer’s test
• Reagent and : Cold, dilute, KMnO4 solution, H+ or OH-
condition
• Observation : i) Alkane : Purple color of KMnO4 remain unchanged
: ii) Alkene : Purple color of KMnO4 decolorized and formation of
brown precipitate of manganese (IV) oxide, MnO2
C C C C
OH OH
MnO2
KMnO4 (aq), OH-
cold, dilute
a diol / glycol brown precipitate
BROMINE TEST
• Test : Bromine test
• Reagent and : Bromine in inert solvent (CCl4 or CH2Cl2) condition
• Observation : i) Alkane : Brown/ yellow color of bromine remain unchanged
: ii) Alkene : Brown/ yellow color of bromine decolorized
1.5 USES
• Ethylene and propylene are the largest-volume industrial organic chemicals.
• Used to synthesis a wide variety of useful compounds.
POLYETHENE (PE)
POLYVINYL CHLORIDE (PVC)
1. Clothing :
✓ Waterproof : coats,
shoes, jackets,
aprons and bags
2. Insulator for electric
wire
3. Pipe
4. Composite for
accessories or housing
portable electronics
THE
END

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CHAPTER 3 CHM 258 - Introduction to Organic Chemistry. Alkenes and cycloalkenes

  • 1. CHAPTER 3 ALKENES & CYCLOALKENES CHM258
  • 2. LESSON OUTLINE 1.0 Introduction ✓ General Formula: CnH2n 1.1 Structure and Nomenclature: IUPAC And Common Names 1.2 Methods of Preparation (Alkenes): ✓ Dehydrohalogenation of alkyl halides ✓ Dehalogenation of dihalides ✓ Reduction of alkynes 1.3 Reactions of Alkenes And Cycloalkenes ✓ Addition of symmetric reagents: H2 and X2 ✓ Markovnikov and anti-Markovnikov rule. ✓ Addition of unsymmetrical reagents: HX and H2O/H2SO4 ✓ Oxidation : Combustion, ozonolysis and diol hydroxylation (KMnO4/H+ cold only) 1.4 Simple Test of Alkenes 1.5 Uses
  • 3. 1.0 INTRODUCTION ALKENE Unsaturated HC Also known as olefins Contain a C=C bond Terminal C=C at the end Internal C=C not at the end Cycloalkenes C=C in a cyclic structure sp2 hybridization Trigonal planar (120°) General Formula (CnH2n) Example CH2CH2 → C2H2(2): C2H4 So, CH2CH2 is an alkene which is ethene
  • 4. 1.1 NOMENCLATURE Parent chain →Longest continuous carbon chain → Must include C=C Numbering →C=C must at lowest carbon number Locate and name substituents Arrange →Alphabetical order
  • 7. RULE 1 Find longest continuous carbon chain that must includes a carbon double bond Longest Continuous Carbon Chain
  • 8. RULE 1 Longest carbon chain must contain both atoms of the double bond.
  • 9. RULE 2 Double bond must at the lowest carbon number Numbering
  • 10. RULE 3 Identify and numbered all the substituent present Locate and name substituents
  • 11. RULE 4 Alphabetical order Have 3 methyl group at C2, C3 & C5 ✓ Use prefix 2,3,5-trimethyl-2-hexene or 2,3,5-trimethylhex-2-ene
  • 12. COMMON RULES Compounds with two double bonds; ✓dienes by changing the “-ane” ending of the parent alkane to the suffix “–adiene”. Compounds with three double bonds; ✓atrienes, and so forth. CH2=CH-CH=CH2 CH2=CH-CH=CH-CH=CH2 1,3-butadiene 1,3,5-hexatriene
  • 13. ALKENOLS The chain (or ring) is numbered to give the OH group the lower number. Double bond and a Hydroxyl group
  • 16. RULE 1 Find longest continuous carbon chain that must includes a carbon double bond Longest Continuous Carbon Chain (must have “=”) 3 5 1 6 4 2 B r
  • 17. Double bond: C1 and C2. If substituent at double bond, ➢ Substituent : C1 RULE 2 1 3 5 4 2 6 Double bond: C1 and C2. If have > 1, double bond, ➢ Double Bond : Lowest Carbon Number Numbering 3 5 1 6 4 2
  • 18. RULE 3 Identify and numbered all the substituent present Locate and name substituents 3 5 1 6 4 2 ✓ 1-tert-butyl ✓ 3-isopropyl or 3-sec-propyl ✓ 5-methyl
  • 19. RULE 4 Alphabetical order 3 5 1 6 4 2 ✓ 1-tert-butyl ✓ 3-isopropyl or 3-sec-propyl ✓ 5-methyl 1-tert-butyl-3-isopropyl-5-methylcyclohexa-1,3-dienes @ 1-tert-butyl-5-methyl-3-sec-propylcyclohexa-1,3-dienes
  • 21. 1.2 METHOD OF PREPARATION (ALKENES) I) Dehydrohalogenation of alkyl halides (-HX) II) Dehalogenation of dihalides (-X2) III) Reduction of alkynes
  • 22. I) DEHYDROHALOGENATION OF ALKYL HALIDE Elimination of hydrogen and halogen from an alkyl halides to form alkene
  • 23. SAYTZEFF RULE Elimination product that favor formation of an alkene with greatest number of substituents attached to the C=C group. CH3CH-CH-CH2 Br H H KOH CH3CH=CH-CH3 CH3CH2CH=CH2 alcohol reflux 2-bromobutane 2-butene (major product) 1-butene
  • 25. II) DEHALOGENATION OF DIHALIDES Elimination of two vicinal halide from an alkyl dihalides to form alkene BACK
  • 26. III) REDUCTION OF ALKYNES i. Alkynes to cis-alkenes ii. Alkynes to trans-alkenes
  • 28. 1.3 REACTION OF ALKENES ADDITION I) Hydrogenation II) Halogenation III) Hydration IV) Hydrohalogenation OXIDATION I) Combustion II) Ozonolysis III) Hydroxylation
  • 29. ADDITION REACTION • A reaction in which an unsaturated molecule becomes saturated by the addition of a molecule across a multiple bond (C=C in alkenes, -C≡C- in alkynes, C=O in aldehydes and ketones) • Characteristics: ✓the π bond of the double bond is broken and two single bonds are formed ✓only one product is obtained at the end of the reaction ✓the product obtained is a saturated organic compound
  • 30. ADDITION REACTION SYMMETRICAL REAGENT I) HYDROGENATION II) HALOGENATION UNSYMMETRICAL REAGENT III) HYDRO- HALOGENATION IV) HYDRATION
  • 32. I) HYDROGENATION Hydrogen in the present of catalyst (Pt, Ni or Pd) will be added to double bond to form an alkanes Ni, Pt or Pd Addition of hydrogen to a double bond
  • 33. II) HALOGENATION Addition of halogen (X2) to a double bond ✓ Alkenes react with halogens at room temperature and in dark. ✓ Halogens is usually dissolved in an inert solvent such as dichloromethane (CH2Cl2) and tetrachloromethane (CCl4).
  • 36. STABILITY OF CARBOCATION The greater the number of alkyl groups on the carbon atom, the greater its stability
  • 37. MARKOVNIKOV RULES H atom will be added to the double bond that has more hydrogen attached to it. The more electropositive atom of the reagent will be added to the carbon that has more H atoms.
  • 38. III) HYDRATION Reagent : H2SO4 or H3PO4 , 300°C Addition of water (H2O) to a double bond.
  • 40. IV) HYDROHALOGENATION Addition of hydrogen halides (HX) to a double bond
  • 42. ANTI-MARKOVNIKOV RULES Addition of hydrogen bromide (HBr) to a double bond with presence of peroxide or H2O2 or ROOR.
  • 45. H2, Pt X2, CCl4 X2, H2O H-X H2O, H2SO4 H Br, ROOR X H H Br OH H OH X X X H H EXAMPLES
  • 47. I) COMBUSTION Alkenes burn with a more sooty flame than alkanes 1. The double bond means there is less hydrogen to combine with oxygen. 2. Some carbon will not be oxidized and will produce carbon in the form of soot. 3. Hence, alkenes are not used a fuels Reaction with oxygen (O2) to produce carbon dioxide ( CO2) and water (H2O) C2H4 + 3O2 → 2CO2 + 2H2O
  • 48. II) OZONOLYSIS C C R R R' H O3 C O O C O R' H R R (CH3)2S C O R R C O R' H ozonide ketone aldehyde or H2O, Zn/H+ Reaction with ozone (O3) to produce ketone and/or aldehyde Reagent ✓O3, (CH3)2S or H2O, Zinc/ H+ or Zinc dust
  • 50. III) HYDROXYLATION Reagent ✓cold, dilute, alkaline potassium permanganate (KMnO4) ✓known as Baeyer’s reagent Reaction with cold, dilute KMnO4, -OH to produce a diol
  • 51. EXAMPLES CH CH2 CH3 CH2 CH2 CH2 CH2 OH OH CH2 OH CH CH3 OH MnO2 MnO2 KMnO4 (aq), OH- cold, dilute ethene 1,2-ethanediol KMnO4 (aq), OH- cold, dilute propene 1,2-propanediol
  • 52. 1.4 SIMPLE TEST FOR ALKENES BAEYER’S TEST Cold, dilute, alkaline KMnO4 BROMINE TEST Bromine in inert solution
  • 53. BAEYER’S TEST • Test : Baeyer’s test • Reagent and : Cold, dilute, KMnO4 solution, H+ or OH- condition • Observation : i) Alkane : Purple color of KMnO4 remain unchanged : ii) Alkene : Purple color of KMnO4 decolorized and formation of brown precipitate of manganese (IV) oxide, MnO2 C C C C OH OH MnO2 KMnO4 (aq), OH- cold, dilute a diol / glycol brown precipitate
  • 54. BROMINE TEST • Test : Bromine test • Reagent and : Bromine in inert solvent (CCl4 or CH2Cl2) condition • Observation : i) Alkane : Brown/ yellow color of bromine remain unchanged : ii) Alkene : Brown/ yellow color of bromine decolorized
  • 55. 1.5 USES • Ethylene and propylene are the largest-volume industrial organic chemicals. • Used to synthesis a wide variety of useful compounds.
  • 57. POLYVINYL CHLORIDE (PVC) 1. Clothing : ✓ Waterproof : coats, shoes, jackets, aprons and bags 2. Insulator for electric wire 3. Pipe 4. Composite for accessories or housing portable electronics