November 26, 2010
66. A + B gives AB Elementary step
A + A gives C
C + B gives BC
Overall 2A + B gives C + BC
72. a) A + B + C gives D
b) X and Y
c) step 1 is bimolecular rate = k[A][B]
step 2 is bimolecular rate = k[X][C]
step 3 is unimolecular rate = k[Y]
d) yes
e) yes it's possible
November 26, 2010
73. a. ClO- + I- gives Cl- + IO-
b.H2O, OH-, HIO, HClO
c. step 1 is bimolecular rate = k[ClO-][H2O]
step 2 is bimolecular rate = k[ I-][HClO]
step 3 is bimolecular rate = k[OH-][HIO]
d. slow step rate law is rate =k[ I-][HClO] this is not
consistent with the proposed rate law. The HClO is an
intermediate and should be replaced. From step 1, leaving out
water, [HClO] = [ClO-]/[OH-]. Replacing [HClO] in the slow step
rate law gives:
rate = k[I-][ClO-]/[OH-]. This is not the observed rate law.

Ch.16 kinetics problems

  • 1.
    November 26, 2010 66.A + B gives AB Elementary step A + A gives C C + B gives BC Overall 2A + B gives C + BC 72. a) A + B + C gives D b) X and Y c) step 1 is bimolecular rate = k[A][B] step 2 is bimolecular rate = k[X][C] step 3 is unimolecular rate = k[Y] d) yes e) yes it's possible
  • 2.
    November 26, 2010 73.a. ClO- + I- gives Cl- + IO- b.H2O, OH-, HIO, HClO c. step 1 is bimolecular rate = k[ClO-][H2O] step 2 is bimolecular rate = k[ I-][HClO] step 3 is bimolecular rate = k[OH-][HIO] d. slow step rate law is rate =k[ I-][HClO] this is not consistent with the proposed rate law. The HClO is an intermediate and should be replaced. From step 1, leaving out water, [HClO] = [ClO-]/[OH-]. Replacing [HClO] in the slow step rate law gives: rate = k[I-][ClO-]/[OH-]. This is not the observed rate law.