Cell membranes A. separate the inside of the cell from the exterior..pdf
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Cell membranes A. separate the inside of the cell from the exterior. B. selectively allow certain materials to cross the membrane. C. contain phospholipids and proteins D. are identical across cell types. E. Both A and B. F. Both A and C G. Choices A, B, and C. H. Choices, A, B, and D. All of the choices are correct. Solution Cell Membrane- A. Seperate the inside of the cell from the exterior. B.Selectively allow certain materials to cross the membrane. C.Contain phospholipids and proteins. D.Are identical across cell types E.Both A and B F.Both A and C G. Choices A,B and C H. Choices A,B and D I. All of the choices are correct ANSWER- I. ALL OF THE CHOIUCES ARE CORRECT. (Phospholipids form a thin, flexible, sheet while the proteins float in the phospholipid sheets like iceberg.The phospholipids are arranged in bilayer (hydrophilic head in the intracellular fluid or hydrophobic tail in the extracellular fluid.) (for prokaryotes,membrane contain no carbohydrate and lacks sterols whereas for eukaryotic, the plasma membrane contain carbohydrate and sterol that serve as receptor.).
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BSC1005 Biology General Chapter 6 1 Chapter 6 Cel.docx
BSC1005 Biology General
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Chapter 6: Cell Energy, Transport and Enzymes
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B) in the nucleus.
C) within chloroplasts.
D) outside of cells.
E) within mitochondria.
2) The fluid mosaic model describes the plasma membrane as consisting of
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B) two layers of phospholipids with protein sandwiched between them.
C) a protein bilayer with embedded phospholipids.
D) carbohydrates, proteins, and phospholipids that can drift in the membrane.
E) individual proteins and phospholipids that can drift in a phospholipid bilayer.
3) Membrane phospholipids
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C) makes the cell membrane fluid at room temperature.
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5) A major function of glycoproteins and glycolipids in the cell membrane is to
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D) cholesterol.
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Check all that apply to different sets of genes that are homologous..pdf
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G. exist in different species
******I have already tried: similar biochemical activities, have similar cell function, and exist in
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Solution
Answer
Homologous chromosomes are chromosome pairs, one from each parent that is similar in length,
gene position and centromere location. The position of genes on each homologous chromosome
is the same, however the genes may contain different alleles.
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B. exist in same species.
F. have similar cellular functions like cell division and transport to membranes.
G. Homologous chromosomes may exist in different species. For example, drosophila genes are
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C. the albinism seems to have conferred social advantages.
D. the albinism did not involve vision defects.
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B. medicine
C. pharmaceutical production
D. urban design and layout
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B. provides the basis of adaptation.
C. explains the use of similar genetic systems in all organisms.
D. is a consequence of origin of species.
E. All of the above.
4. Genetics as a discipline can be subdivided into all of the following EXCEPT:
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B. acquisition genetics.
C. molecular genetics.
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5. While modern genetics starts with the experiments of Gregor Mendel in 1866, it wasn\'t
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D. prokaryotes tend to be less complex.
E. None of the above.
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B. come in pairs in eukaryotic cells.
C. come in alternative forms, known as alleles.
D. are encoded by DNA.
E. All of the above.
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B. not inherited directly.
C. not changeable during the life of an organism.
D. A and B.
E. All of the above.
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B. starts with variation.
C. does not require change of DNA.
D. A and B.
E. All of the above.
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B. protein to RNA to DNA.
C. DNA to RNA to protein.
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E. None of the above.
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B. that can affect large regions of chromosomes.
C. that can be passed on to daughter cells.
D. that can change amino acid sequences.
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2). D. urban design and layout
3). D. is a consequence of origin of species.
4). B. acquisition genetics.
5). C. Haldane and others who used populations to connect genetics to evolution.
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public static ArrayList doArrayListSearchSmallest(int numItems) {
System.out.print(\"doArrayListSearchSmallest: \");
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// TODO Write code that adds integers 0 through (numitems - 1)
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long startTime = getTimestamp();
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long endTime = getTimestamp();
long totalTime = endTime - startTime;
System.out.println(totalTime);
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}
Solution
Code that adds integers 0 through (numitems - 1) to the list. I have added a loop for adding
values to the list.
for(int i=0; i doArrayListAdd(int numItems) {
System.out.print(\"doArrayListAdd: \");
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java
Fix in the program below:
handle incomplete data for text file and allow to search multiple items at once
and let it sort duplicate values
and most importantly let it use get and set methods on the Nodes
New Internal Requirements :
For this assignment, you should replace your Database class with another implementation which
uses instances of the Java Collections java.util.LinkedList class to replace your hand-crafted
LinkedList classes. Note the following:
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Database object will contain several LinkedList objects; you will need to organize these lists into
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• You are still required to maintain your lists in sorted order. The pre-built LinkedList methods
do not directly support relative insertion into a linked list; you will need to find ways to
accomplish this with the tools available to you. (There are at least a couple of ways to do this.)
New function to add:
• A new command should be implemented which allows the user to edit a storm from the main
menu. If selected, the program should prompt the user for the year and storm name to be edited.
If a matching storm is found, the corresponding record should be displayed and the user
prompted for new information to be placed in the record. Users may not change the year or storm
name, but may change any of the other information. If no matching storm is found, no action
should be taken. The user should be informed of the outcome in any case.
this is what the txt file the program is reading from looks like:
2000/Alex/0110/0120/0
2001/Bill/0210/0220/0
2002/Chris/0310/0320/0
2003/Devon/0140/0420/0
2004/Eli/0510/0520/1
2005/Fred/0610/0620/2
2006/Gilbert/0710/0820/3
2007/Herbert/0910/0920/4
2008/Kim/1010/1020/5
#######################################Java
Program#######################################################################
###
/*****************************************************************************
***************/
/*This program takes a a file and gives infomation to the user using a LinkedList */
/*****************************************************************************
***************/
import java.io.File;
import java.io.FileNotFoundException;
import java.util.InputMismatchException;
import java.util.Scanner;
//setting variables to string or int
public class Storm {
private int stormYear;
private int stormMag;
private String stormStart;
private String stormEnd;
private String stormName;
/**
* Constructor
* Storing all variables from text file
* @param stormName
* @param stormYear
* @param stormStart
* @param stormEnd
* @param stormMag
*/
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stormMag) {
this.stormName = stormName;
this.stormYear = stormYear;
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this.stormMag = stormMag;
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/*******************************.
James can row 14 km downstream in a river in 2 hours. He takes 7 hou.pdf
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Solution
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import java.util.ListIterator;
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Node tmp = head;
head = head.getForeNode;
head.getBackNode = null;
size--;
System.out.println(\"deleted: \"+tmp.element);
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public E removeNodeAfter() {
if (size == 0) throw new NoSuchElementException();
Node tmp = tail;
tail = tail.getBackNode;
tail.getForeNode = null;
size--;
System.out.println(\"deleted: \"+tmp.element);
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Solution
Hydrophobic hormones are fat soluble while hydrophilic hormones are water soluble.
Hydrophobic hormones speed and modes of action is slower than the hydrophilic hormones as
they have to cross the cell membrane ,bind to receptors, go to nucleus and then attach to
particular DNA sequence for gene expression to occur while hydrophilic hormones simply attach
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hormones pass through the cell membrane and bind to receptors present inside the cell forming a
hormone receptor complex.This complex then moves to nucleus of the cell and bind to a
particular DNA sequence.This either turns on or turns off the expression of the gene resulting in
production of enzymes that regulate the activity of the cell whereas in case of hydrophilic
hormones the speed and action is faster as they bind directly to receptors (particularly G proteins
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network internally. Complete a risk qualification for this organization and identify the following:
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According to the above corporate network infrastructure, the following risks can be found in
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the user and the network device.
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information or credentials of an authorized administrator as it traverses the network.
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device, they can have the full control or access to view any of this sensitive data.
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traffic on a switched network. The attacker would need to be in the path of the communication
between the network device and the administrator, or the attacker would need to exploit a
vulnerability on another network device in the path. Additionally, the attacker would need some
knowledge of the network device technology in order to capture and view data traversing the
network device after gaining access. The probability of the attacker gaining access once the
credentials have been stolen is further reduced by the use of Access Control Lists (ACLs) on the
network device to limit Telnet connections to certain source IP addresses used by network
administrator’s workstations. Given that the password never expires and is therefore likely not
ever to be changed, the chance of interception and successful exploitation increases over time.
The attack vector with the most the highest probability of success would be from the store
network.
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costing the company over $500,000 directly in the form of fines and lawsuits and also indirectly
when approximately 10% of clients switch their business to a competitor..
Explain Aquinas 5 proofs of God, being sure to identify the Aris.pdf
Explain Aquinas\' 5 proofs of God, being sure to identify the \"Aristotelian\" elements in each
proof.
Solution
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by another, there must thereby exist an Unmoved Mover.)
Part II. The Argument from Efficient Cause. (The sequence of causes which make up this
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Part III. The Argument to Necessary Being. (Since all existent things depend upon other things
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design and order of existent things and natural processes imply that a Great Designer exists.).
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Illegal reference
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Can you explain the movement of ions and ion channel activity during.pdf
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another.
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direction with comparison to outside.. The Potassium ions moves outside of the neuron thus
creating action potential....
Calculate the implied stock price assuming an EBITDA multiple of 11..pdf
Calculate the implied stock price assuming an EBITDA multiple of 11.2x.
(All data in millions)
Select one:
a. $33.42
b. $41.93
c. $24.14
d. $20.58
e. $21.72Short-term debt:$22.5Shares Outstanding:18.330Convertible debt$0.0Diluted shares
outstanding:21.501Long-term debt:$253.5Cash & equivalents:$46.5Total
liabilities:$676.8Minority interest:$0.0EBITDA:$60.0Net income:$21.2
Solution
EBITDA 60 11.2 672 Enterprise Value 672 Less : Short-Term debt -22.5 Long-
term debt -253.5 Add: Cash 46.5 Equity Value 442.5 Diluted shares outstanding 21.501
Implied value of stock 20.58.
Below is the graph of a polynomial function f with real coefficients.pdf
Below is the graph of a polynomial function f with real coefficients. Use the graph to answer the
following questions about f . All local extrema of f are shown in the graph.
Solution
As the graph is + infinity in y , for - infinity in x
and - infinity in y for + infinity in x
it means the degree is odd
that implies
5,7,9.
Are higher than average sea surface temperatures associated with a g.pdf
Are higher than average sea surface temperatures associated with a greater than average number
of hurricanes each year? In a 2010 study, the average global sea surface temperature anomaly
was recorded, along with the number of Atlantic hurricanes above or below the average for that
year. The response variable is:
Solution
Variables of interest in an experiment (those that are measured or observed) are called response
or dependent variable
The response variable is: average number of hurricanes each year.
A table of values of an increasing function F is shown. Use the table.pdf
A table of values of an increasing function F is shown. Use the table to find to find lower and
upper estimates for integral^30 _10 (x) dx.
Solution
function is increasing
x =4
lower estimate =x[f(10)+f(14)+f(18)+f(22)+f(26)]
lower estimate =4*[-12-6-2+1+3]
lower estimate =-64
============================
upper estimate =x[f(14)+f(18)+f(22)+f(26)+f(30)]
upper estimate =4*[-6-2+1+3+8]
upper estimate =16.
A polygenic trait is determined by a single gene with many different.pdf
A polygenic trait is determined by a single gene with many different alleles.
true or false
Solution
False -some traits are controlled by more than one pair of genes this is refered to as continuous or
polygeneic trait.
This means each dominant allele is adds to the expression of next dominant allele..
More Related Content
Similar to Cell membranes A. separate the inside of the cell from the exterior..pdf
BSC1005 Biology General Chapter 6 1 Chapter 6 Cel.docx
BSC1005 Biology General
Chapter 6
1
Chapter 6: Cell Energy, Transport and Enzymes
1) Many of the enzymes that control a deep-sea firefly squid's ability to produce light energy from chemical energy are located
A) in membranes.
B) in the nucleus.
C) within chloroplasts.
D) outside of cells.
E) within mitochondria.
2) The fluid mosaic model describes the plasma membrane as consisting of
A) a phospholipid bilayer with embedded carbohydrates.
B) two layers of phospholipids with protein sandwiched between them.
C) a protein bilayer with embedded phospholipids.
D) carbohydrates, proteins, and phospholipids that can drift in the membrane.
E) individual proteins and phospholipids that can drift in a phospholipid bilayer.
3) Membrane phospholipids
A) have hydrophobic heads that face the center of the membrane and are shielded from water.
B) have hydrophilic tails that face outward and are exposed to water.
C) often have "kinks" in their tails caused by the presence of a double bond between carbons.
D) remain fluid because they are tightly packed against one another.
E) form impermeable layers for cells.
4) The cholesterol associated with animal cell membranes
A) is attached to membrane proteins and extends into the watery environment surrounding the cell.
B) helps to stabilize the cell membrane at body temperature.
C) makes the cell membrane fluid at room temperature.
D) is an abnormality resulting from a diet high in cholesterol.
E) helps solidify the membranes when the room temperature is below freezing.
5) A major function of glycoproteins and glycolipids in the cell membrane is to
A) glue cells together to form tissues.
B) allow the cells of an embryo to sort themselves into tissues and organs.
C) attach the cell membrane to the cytoskeleton.
D) help the cell resist swelling.
E) help the cell retain its shape.
6) When physicians perform an organ transplant, they choose a donor whose tissues match those of the recipient as closely as
possible. Which of the following cell components are being matched?
A) plasma membrane phospholipids
B) plasma membrane proteins
C) cell-surface carbohydrates
D) plasma membrane cholesterols
E) cytoskeletal elements
7) Most of the functions of a cell membrane are performed by
A) glycolipids.
B) proteins.
C) phospholipids.
D) cholesterol.
E) nucleotides.
BSC1005 Biology General
Chapter 6
2
9) Relaying a message from a membrane receptor to a molecule that performs a specific function within a cell is called
A) signal transduction.
B) inhibition.
C) competition.
D) self-recognition.
E) selective permeability.
10) Plasma membranes are selectively permeable. This means that
A) anything can pass into or out of a cell as long as the membrane is intact and the cell is healthy.
B) the plasma membrane allows some substances to enter or leave a cell more easily than others.
C) glucose cannot ...
Check all that apply to different sets of genes that are homologous..pdf
Check all that apply to different sets of genes that are homologous.
A.have similar biochemical activities (ex. bind to DNA, synthesize polypeptides)
B.exist in the same species
C. exist in the same individual
D.have different cellular functions (ex. cell division, transport to membranes)
E.have different biochemical activities (ex. bind to DNA, synthesize polypeptides)
F. have similar cellular functions (ex. cell division, transport to membranes)
G. exist in different species
******I have already tried: similar biochemical activities, have similar cell function, and exist in
different species I got half credit for this so i must be missing something.
Solution
Answer
Homologous chromosomes are chromosome pairs, one from each parent that is similar in length,
gene position and centromere location. The position of genes on each homologous chromosome
is the same, however the genes may contain different alleles.
A. have similar biochemical activities.
B. exist in same species.
F. have similar cellular functions like cell division and transport to membranes.
G. Homologous chromosomes may exist in different species. For example, drosophila genes are
homologous with genes of human beings.
So the answer would be A, B, F, and G..
FYBSc Course-I Semester-I MCQ : Levels of organization sudeshrathod
FYBSc Course-I Semester-I MCQ : Levels of organization sudeshrathodDr. Sudesh D. Rathod, B N Bandodkar College of Science
The document contains 51 multiple choice questions related to taxonomy and classification of various organisms. The questions cover topics like kingdoms, phyla, classes, characteristics and distinguishing features of taxa ranging from protozoans to arthropods. Each question is followed by four answer options, with the correct answer indicated by an asterisk. The questions assess understanding of key concepts in organism diversity, phylogeny and evolutionary relationships.1. The case of albinism among the Hopi Indians of Black M.pdf
1. The case of albinism among the Hopi Indians of Black Mesa is different from other
cases of albinism because of all of the following EXCEPT:
A. the incidence is much higher among the Hopis.
B. the albinism seems to have provided a reproductive advantage.
C. the albinism seems to have conferred social advantages.
D. the albinism did not involve vision defects.
E. Actually, all of the above are accurate.
2. Genetics has NOT played a key role in which of the following areas?
A. agriculture
B. medicine
C. pharmaceutical production
D. urban design and layout
E. Actually, it has played a key role in all of these areas.
3. Genetic variation in populations:
A. demonstrates descent from a common ancestor.
B. provides the basis of adaptation.
C. explains the use of similar genetic systems in all organisms.
D. is a consequence of origin of species.
E. All of the above.
4. Genetics as a discipline can be subdivided into all of the following EXCEPT:
A. transmission genetics.
B. acquisition genetics.
C. molecular genetics.
D. population genetics.
E. Actually, all of these are found in the discipline.
5. While modern genetics starts with the experiments of Gregor Mendel in 1866, it wasn\'t
until the start of the 20th century that those studies became well known, in several areas, NOT
including:
A. Sutton, who proposed that genes were on chromosomes.
B. Morgan, who identified fruit fly mutations.
C. Haldane and others who used populations to connect genetics to evolution.
D. Watson and Crick\'s determination of the structure of DNA.
E. Actually, Mendel\'s work was critical in each of these areas.
6. Prokaryotes and eukaryotes differ in that:
A. prokaryotes have a nucleus.
B. they decode DNA to different amino acids.
C. prokaryotes tend to be larger.
D. prokaryotes tend to be less complex.
E. None of the above.
7. Genes:
A. are carried on chromosomes.
B. come in pairs in eukaryotic cells.
C. come in alternative forms, known as alleles.
D. are encoded by DNA.
E. All of the above.
8. Phenotypes are:
A. measurable traits of an organism.
B. not inherited directly.
C. not changeable during the life of an organism.
D. A and B.
E. All of the above.
9. Evolution:
A. is genetic change.
B. starts with variation.
C. does not require change of DNA.
D. A and B.
E. All of the above.
10. The flow of information is as follows:
A. protein to DNA to RNA.
B. protein to RNA to DNA.
C. DNA to RNA to protein.
D. RNA to protein to DNA.
E. None of the above.
11. Mutations are changes of DNA:
A. that can affect a single gene.
B. that can affect large regions of chromosomes.
C. that can be passed on to daughter cells.
D. that can change amino acid sequences.
E. All of the above.
Solution
1). C. the albinism seems to have conferred social advantages.
2). D. urban design and layout
3). D. is a consequence of origin of species.
4). B. acquisition genetics.
5). C. Haldane and others who used populations to connect genetics to evolution.
6). E. None of the above.
7). A. are carried on ch.
Test bank-for-human-physiology- chapter 3
This document contains a test bank of multiple choice questions about human physiology and cell biology. The questions cover topics like cellular compartments, organelles, membranes, tissues, and protein secretion. They assess comprehension of concepts like compartmentalization of the body, selective permeability of membranes, functions of organelles like mitochondria and the endoplasmic reticulum, and intracellular transport pathways.
Biology and you chapter 1
The document provides an overview of key biology concepts such as the basic properties of life, cellular structure and function, metabolism, heredity, evolution, and ecology. It also discusses how biology can help address issues like population growth, feeding the world, and fighting diseases. The scientific process is outlined as a way for biologists to investigate biological questions and phenomena.
Similar to Cell membranes A. separate the inside of the cell from the exterior..pdf (6)
BSC1005 Biology General Chapter 6 1 Chapter 6 Cel.docx
BSC1005 Biology General Chapter 6 1 Chapter 6 Cel.docx
Check all that apply to different sets of genes that are homologous..pdf
Check all that apply to different sets of genes that are homologous..pdf
FYBSc Course-I Semester-I MCQ : Levels of organization sudeshrathod
FYBSc Course-I Semester-I MCQ : Levels of organization sudeshrathod
1. The case of albinism among the Hopi Indians of Black M.pdf
1. The case of albinism among the Hopi Indians of Black M.pdf
More from birajdar2
public static ArrayListInteger doArrayListSearchSmallest(int nu.pdf
public static ArrayList doArrayListSearchSmallest(int numItems) {
System.out.print(\"doArrayListSearchSmallest: \");
ArrayList list = new ArrayList<>();
// TODO Write code that adds integers 0 through (numitems - 1)
// to list.
long startTime = getTimestamp();
// TODO Write code that gets the element at the first index from list.
long endTime = getTimestamp();
long totalTime = endTime - startTime;
System.out.println(totalTime);
return list;
}
Solution
Code that adds integers 0 through (numitems - 1) to the list. I have added a loop for adding
values to the list.
for(int i=0; i doArrayListAdd(int numItems) {
System.out.print(\"doArrayListAdd: \");
ArrayList list = new ArrayList<>();
long startTime = getTimestamp();
for(int i=0; i.
Project selection methods and the project portfolio play an importan.pdf
Project selection methods and the project portfolio play an important role for corporate
sustainability and strategic planning. It is important to distinguish between financial and non-
financial models for project selection, since each can yield different results. I need project
selection methods (financial or non-financial) or software applications with links. Also what
would be some of the benefits and/or shortcomings of the particular method
Solution
project selection methods based on financial models are Net present value method, Profitability
Index or Internal rate of return, sensitivity analysis. if you type these methods on the tool bar,
you will get all the related sites and the calculation procedures to implement it.
when it comes to nonfinancial methods, which speaks about sustainability of the firm there are
no pre determined and pre defined methods. the main objective is the climate and environment
should not disturb or pollute with our output. we should produce a product which is eco friendly
and customer friendly..
javaFix in the program belowhandle incomplete data for text fil.pdf
java
Fix in the program below:
handle incomplete data for text file and allow to search multiple items at once
and let it sort duplicate values
and most importantly let it use get and set methods on the Nodes
New Internal Requirements :
For this assignment, you should replace your Database class with another implementation which
uses instances of the Java Collections java.util.LinkedList class to replace your hand-crafted
LinkedList classes. Note the following:
• LinkedList is a generic type; you must instantiate it with concrete class types. Thus, your
Database object will contain several LinkedList objects; you will need to organize these lists into
another instance of LinkedList. (Consider creating a Year object to help with this.)
• You are still required to maintain your lists in sorted order. The pre-built LinkedList methods
do not directly support relative insertion into a linked list; you will need to find ways to
accomplish this with the tools available to you. (There are at least a couple of ways to do this.)
New function to add:
• A new command should be implemented which allows the user to edit a storm from the main
menu. If selected, the program should prompt the user for the year and storm name to be edited.
If a matching storm is found, the corresponding record should be displayed and the user
prompted for new information to be placed in the record. Users may not change the year or storm
name, but may change any of the other information. If no matching storm is found, no action
should be taken. The user should be informed of the outcome in any case.
this is what the txt file the program is reading from looks like:
2000/Alex/0110/0120/0
2001/Bill/0210/0220/0
2002/Chris/0310/0320/0
2003/Devon/0140/0420/0
2004/Eli/0510/0520/1
2005/Fred/0610/0620/2
2006/Gilbert/0710/0820/3
2007/Herbert/0910/0920/4
2008/Kim/1010/1020/5
#######################################Java
Program#######################################################################
###
/*****************************************************************************
***************/
/*This program takes a a file and gives infomation to the user using a LinkedList */
/*****************************************************************************
***************/
import java.io.File;
import java.io.FileNotFoundException;
import java.util.InputMismatchException;
import java.util.Scanner;
//setting variables to string or int
public class Storm {
private int stormYear;
private int stormMag;
private String stormStart;
private String stormEnd;
private String stormName;
/**
* Constructor
* Storing all variables from text file
* @param stormName
* @param stormYear
* @param stormStart
* @param stormEnd
* @param stormMag
*/
public Storm(String stormName, int stormYear, String stormStart, String stormEnd, int
stormMag) {
this.stormName = stormName;
this.stormYear = stormYear;
this.stormStart = stormStart;
this.stormEnd = stormEnd;
this.stormMag = stormMag;
}
/*******************************.
James can row 14 km downstream in a river in 2 hours. He takes 7 hou.pdf
James can row 14 km downstream in a river in 2 hours. He takes 7 hours to go back. Find the
speed of the current and the speed of James in still water.
Solution
d = rt
c = speed of current, r = rowing speed
14 = (r+c)*2 = (r-c)*7
2r+2c=14
7r-7c=14
-------
r+c=7 Eqn 1 div by 2
r-c=2 Eqn 2 div by 7
----- Add equations
2r = 9
r = 4.5 kph
c = 2.5 kph.
In the class we extensively discussed a generic singly linked list i.pdf
In the class we extensively discussed a generic singly linked list implemented as a node class.
Implement a generic node class called DoublyNode in which each node contains an element of
type E and each node is linked not only forward to the next element in the list but also backward
to the previous element in the list. Your implementation should adapt and implement all the
methods of generic Node including the following methods:
Constructor for DoublyNode
addNodeAfter, removeNodeAfter
getData, setData
getForeLink, setForeLink
getBackLink, setBackLink
listCopy
listCopyWithTail
listLength
listPart
listPosition
listSearch
Solution
import java.util.ListIterator;
import java.util.NoSuchElementException;
import java.util.Random;
public class DoublyNode {
private Node head;
private Node tail;
private int size;
public DoublyNode() {
size = 0;
}
private class Node {
E element;
Node getForeNode;
Node getBackNode;
public Node(E element, Node next, Node prev) {
this.element = element;
this.getForeNode = next;
this.getBackNode = prev;
}
}
public int listLength() { return size; }
public boolean isEmpty() { return size == 0; }
public void addFirst(E element) {
Node tmp = new Node(element, head, null);
if(head != null ) {head.getBackNode = tmp;}
head = tmp;
if(tail == null) { tail = tmp;}
size++;
System.out.println(\"adding: \"+element);
}
public void addNodeAfter(E element) {
Node tmp = new Node(element, null, tail);
if(tail != null) {tail.getForeNode = tmp;}
tail = tmp;
if(head == null) { head = tmp;}
size++;
System.out.println(\"adding: \"+element);
}
public void addNodeAfterSpecifiedNode(E element, E tobeAddedAfter) {
Node prevTobeAddedAfter = listSearch(element);
Node afterNode = prevTobeAddedAfter.getForeNode;
Node tmpNode = new Node(element,prevTobeAddedAfter,afterNode);
tmpNode = prevTobeAddedAfter.getForeNode;
afterNode = tmpNode.getForeNode;
}
public void listCopy(){
System.out.println(\"iterating forward..\");
Node tmp = head;
while(tmp != null){
System.out.println(tmp.element);
tmp = tmp.getForeNode;
}
}
public Node listSearch(E item){
System.out.println(\"Searching Item \"+item);
Node tmp = head;
while(tmp != null){
System.out.println(tmp.element);
if(tmp.element == item) {
System.out.println(\"Item found \"+item);
return tmp;
}
tmp = tmp.getForeNode;
}
return null;
}
public void iterateBackward(){
System.out.println(\"iterating backword..\");
Node tmp = tail;
while(tmp != null){
System.out.println(tmp.element);
tmp = tmp.getBackNode;
}
}
public E removeFirst() {
if (size == 0) throw new NoSuchElementException();
Node tmp = head;
head = head.getForeNode;
head.getBackNode = null;
size--;
System.out.println(\"deleted: \"+tmp.element);
return tmp.element;
}
public E removeNodeAfter() {
if (size == 0) throw new NoSuchElementException();
Node tmp = tail;
tail = tail.getBackNode;
tail.getForeNode = null;
size--;
System.out.println(\"deleted: \"+tmp.element);
return tmp.element;
}
}.
How do hydrophobic and hydrophilic hormones differ in their speeds a.pdf
How do hydrophobic and hydrophilic hormones differ in their speeds and modes of action?
Solution
Hydrophobic hormones are fat soluble while hydrophilic hormones are water soluble.
Hydrophobic hormones speed and modes of action is slower than the hydrophilic hormones as
they have to cross the cell membrane ,bind to receptors, go to nucleus and then attach to
particular DNA sequence for gene expression to occur while hydrophilic hormones simply attach
to receptors on cell surface and trigger a chemical recation. Mode of action: Hydrophobic
hormones pass through the cell membrane and bind to receptors present inside the cell forming a
hormone receptor complex.This complex then moves to nucleus of the cell and bind to a
particular DNA sequence.This either turns on or turns off the expression of the gene resulting in
production of enzymes that regulate the activity of the cell whereas in case of hydrophilic
hormones the speed and action is faster as they bind directly to receptors (particularly G proteins
)that are expressed on the cell surface and initiate a signaling event involving second messenger,
such as cyclic adenosine monophosphate (cAMP). The second messengers then function to
amplify the hormone signal to a greater extent thereby resulting in efficinet and faster response.
Overall the speed and mode of action of hydrophilic hormones is faster than hydrophilic
hormones..
Given below is an issue that you have identified as an issue in a ret.pdf
Given below is an issue that you have identified as an issue in a retail company: Assume the
organization is a typical retailer with a corporate network installation. Store networks are
connected to the backend servers via the POS machines. Network administrators use Telnet to
access the network and network passwords never expire. Administrators should only access the
network internally. Complete a risk qualification for this organization and identify the following:
Vulnerability: Threats (threat actor and activity): Severity: Likelihood: Sensitivity:
Solution
According to the above corporate network infrastructure, the following risks can be found in
terms of security & Risk Management:
Vulnerability: As authentication credentials and all the commands are sent to the network device
in cleartext format, it could allow for eavesdropping or manipulation of data in transit between
the user and the network device.
Threat: It\'s a kind of internal abuse.A savvy insider could interpret and steal sensitive
information or credentials of an authorized administrator as it traverses the network.
Severity: Payment card information traverses these n/w devices between the point of sale system
(in the stores) and back-end servers (corporate data centers). If they can get access to the n/w
device, they can have the full control or access to view any of this sensitive data.
Likelihood: Although it is possible to view any data in a Telnet session, it is not trivial to sniff
traffic on a switched network. The attacker would need to be in the path of the communication
between the network device and the administrator, or the attacker would need to exploit a
vulnerability on another network device in the path. Additionally, the attacker would need some
knowledge of the network device technology in order to capture and view data traversing the
network device after gaining access. The probability of the attacker gaining access once the
credentials have been stolen is further reduced by the use of Access Control Lists (ACLs) on the
network device to limit Telnet connections to certain source IP addresses used by network
administrator’s workstations. Given that the password never expires and is therefore likely not
ever to be changed, the chance of interception and successful exploitation increases over time.
The attack vector with the most the highest probability of success would be from the store
network.
Sensitivity: A breach of this sort would require the organization to publicly report the incident,
costing the company over $500,000 directly in the form of fines and lawsuits and also indirectly
when approximately 10% of clients switch their business to a competitor..
Explain Aquinas 5 proofs of God, being sure to identify the Aris.pdf
Explain Aquinas\' 5 proofs of God, being sure to identify the \"Aristotelian\" elements in each
proof.
Solution
Part I. The Argument from Motion. (Thomas argues that since everything that moves is moved
by another, there must thereby exist an Unmoved Mover.)
Part II. The Argument from Efficient Cause. (The sequence of causes which make up this
universe must have a First Cause.)
Part III. The Argument to Necessary Being. (Since all existent things depend upon other things
for their existence, there must exist at least one thing that is not dependent and so is a Necessary
Being.)
Part IV. The Argument from Gradation. (Since all existent things can be compared to such
qualities as degrees of goodness, there must exist something that is an Absolutely Good Being.)
Part V. The Argument from Design. (Also named “The Teleological Argument”— The intricate
design and order of existent things and natural processes imply that a Great Designer exists.).
Exercise 7. Show that if C(0) (the punctured plane) and U C are conf.pdf
Exercise 7. Show that if C/(0) (the punctured plane) and U C are conformally equivalent, then
C/U has no interior, i.e. the complement of U contains no open sets.
Solution
Let P be the punctured plane and U be conformally equivalent.
Then the complements P\' (of P) and U\'( of U) will be topologically equivalent.
But P\' ={0} is a singleton...has no interior points..(hence contains no open sets)
So the same it true of U\'.
Hence the result.
Consider the following segment table What are the physical addresse.pdf
Consider the following segment table: What are the physical addresses for the following virtual
addresses? 4.44 1.22 Briefly compare segmentation to paging.
Solution
a) Physical address for 4,44:
2200+44 = 2244
Physical address for 1,22:
Illegal reference
b) Paging and segmentation are different in the following ways:
1) A page is a contiguous range of memory addresses which is mapped to physical memory
whereas a segment is an independent address space.
2) A has only one linear address space whereas a segment has many address spaces.
3) A page is a physical unit whereas a segment is a logical unit..
Can you explain the movement of ions and ion channel activity during.pdf
Can you explain the movement of ions and ion channel activity during the resting and action
potential?
Solution
Action potential is the potential due to the which the impulse is passed from one neuron to
another.
Resting stage - in resting stage the inside has higher concentration of Potassium ions ie (-ve)
sign,wheareas the outside it has high concentration of Sodium ions ie (+ve) ions..!! The
membrane is slightly permeable to Sodium ions to transport the Sodium outside maintaining the
concentration outside and inside..
Action potential - during this this the membrane becomes much more permeable to Sodium ions
which allows the huge of Sodium inside the neuron in a short time making the charge opposite
direction with comparison to outside.. The Potassium ions moves outside of the neuron thus
creating action potential....
Calculate the implied stock price assuming an EBITDA multiple of 11..pdf
Calculate the implied stock price assuming an EBITDA multiple of 11.2x.
(All data in millions)
Select one:
a. $33.42
b. $41.93
c. $24.14
d. $20.58
e. $21.72Short-term debt:$22.5Shares Outstanding:18.330Convertible debt$0.0Diluted shares
outstanding:21.501Long-term debt:$253.5Cash & equivalents:$46.5Total
liabilities:$676.8Minority interest:$0.0EBITDA:$60.0Net income:$21.2
Solution
EBITDA 60 11.2 672 Enterprise Value 672 Less : Short-Term debt -22.5 Long-
term debt -253.5 Add: Cash 46.5 Equity Value 442.5 Diluted shares outstanding 21.501
Implied value of stock 20.58.
Below is the graph of a polynomial function f with real coefficients.pdf
Below is the graph of a polynomial function f with real coefficients. Use the graph to answer the
following questions about f . All local extrema of f are shown in the graph.
Solution
As the graph is + infinity in y , for - infinity in x
and - infinity in y for + infinity in x
it means the degree is odd
that implies
5,7,9.
Are higher than average sea surface temperatures associated with a g.pdf
Are higher than average sea surface temperatures associated with a greater than average number
of hurricanes each year? In a 2010 study, the average global sea surface temperature anomaly
was recorded, along with the number of Atlantic hurricanes above or below the average for that
year. The response variable is:
Solution
Variables of interest in an experiment (those that are measured or observed) are called response
or dependent variable
The response variable is: average number of hurricanes each year.
A table of values of an increasing function F is shown. Use the table.pdf
A table of values of an increasing function F is shown. Use the table to find to find lower and
upper estimates for integral^30 _10 (x) dx.
Solution
function is increasing
x =4
lower estimate =x[f(10)+f(14)+f(18)+f(22)+f(26)]
lower estimate =4*[-12-6-2+1+3]
lower estimate =-64
============================
upper estimate =x[f(14)+f(18)+f(22)+f(26)+f(30)]
upper estimate =4*[-6-2+1+3+8]
upper estimate =16.
A polygenic trait is determined by a single gene with many different.pdf
A polygenic trait is determined by a single gene with many different alleles.
true or false
Solution
False -some traits are controlled by more than one pair of genes this is refered to as continuous or
polygeneic trait.
This means each dominant allele is adds to the expression of next dominant allele..
4. Phil is conducting a seed germination experiment. He places 3 gro.pdf
4. Phil is conducting a seed germination experiment. He places 3 groups of lettuce seeds in a 34º
Celsius
incubator with adequate moisture. One set of seeds is placed in a dark area with no light source.
A second set
is placed under artificial light and third set of seeds is placed in direct sunlight. This experiment
is intended to
test Phil\'s hypothesis that light is necessary for lettuce seed germination.
Based on the experimental design, which group was the control?
A. Moisture
B. Seeds in the dark
C. Type of light
D. Temperature
E. Germination rate
Solution
In this study seeds in the dark is control group. The control group does not receive any treatment
by the researchers in an experiment and this control group is used for the comparison with other
test group. In this experiment seeds in the dark is not receiving any treatment as it is placed in a
dark area with no light source. Hence seeds in the dark is control group in this experiment..
21. What is the relationship between the maximum size of aggregates a.pdf
21. What is the relationship between the maximum size of aggregates and concrete strengths for
the same water-cement ratio 22. Certain harmful materias in aggregates, such as such as some
shales, will cause popouts. What are the mechanisms of the popouts? 23. What are the minerals
that are considered low shrinkage aggregates? 24. List three negative effects of organic
impurities in concrete
Solution
21) Relationship between maximum size of aggregates and concrete compreesive strength:
Compressive strength of concrete depends on the aggreagte strength not necessarily on the
aggragate size. However, with an increase in size of the aggreagte to the maximum the
consumption of water-cement ratio decreases, thereby the density of concrete increases. With
increase in density, the compressive strength increases.
The surface texture of aggregate can either be smooth or rough. A smooth surface can improve
the workability, yet a rougher surface generates a stronger bond between the paste and the
agggregates creating a higher strength. Angular and elongated aggregates have higher surface to
volume ratio, better bond characteristics but require more cement paste to produce a workable
mixture. So for the same water-cement ratio, smooth aggregates are preferred to produce higher
compressive strength.
22) Mechanisms of popouts:
Shales have been found to be montmorillonitic. Popouts could be attributed to the pressures
generated by the absorption of water by the monmorillonite.
The reaction between cement alkalis and the reactive shale particles form an alkali-silica gel at
the surface of the reacted particle. The quantity of gel produced from a single reactive particle,
and the rate at which it forms, will be the greatest if the particles are exposed to high-alkali
concentrations. Once formed, the alkali silica gel absorbs water and start to swell. The swollen
gel occupies the available pore space in the concrete creating pressures, which often causes
popouts.
23) Minerals that are considered low shrinkage aggregates:
Metakalinite: It is a highly reactive material which is formed as a result of roasting of natural
kaolinite at temperatures of 700oC to 900oC.
Zeolite: The source of zeolite formation is due to settlement of volcanic ash and then reaction
with lake salts.
Fly ash: It is a by-product obtained during combustion of coal in thermal power plants.
Silica fumes: It is a by-product of the production of elemental silicon or alloys containing silicon,
also known as condensed silica fume or microsilica.
Slag: Blast furnace slag is a by product of extraction of iron ore. Amongst the mineral
admixtures, slag possesses the highest specific gravity( around 2.8 to 3.0).
Rice hush ash: It is a highly reactive pozzolan obtained by controlled calcination of rice husks.
24) Negative effects of organic impurities:
- Organic impurities derived from decaying vegetation delay the setting time and hardening of
concrete.
- Silt, clay and dust may form a coating on the a.
Which of the following are organizer molecules in the avian PMZ is a.pdf
Which of the following are organizer molecules in the avian PMZ? is a multiple answer
question. pick all that fit. Chordin Cerebrus Frzb Goosecoid Noggin Follistatin Veg T Vg1
Nodal Sonic hedgehog
Solution
1) Cordin
2) Goosecoid
3) VegT
4) Vg1
These are the avian organizer molecules.
In summary, there is evidence for an active Wnt/Beta catenin pathway within the vegetal region
of the chick embryo, which is radially distributed around the epiblast. In contrast, the
Tbx6L/cVg1/CMIX system is restricted to the posterior vegetal region of the embryo. The
activities of the two pathways overlap spatially in the posterior marginal zone(PMZ), which thus
becomes a focal structure of early avian development..
What are the five stages of team development Describe each stage an.pdf
What are the five stages of team development? Describe each stage and how that might appear in
a healthcare setting.
Solution
What are the five stages of team development? Describe each stage and how that might appear in
a healthcare setting.
Answer :
Team Development :
Improvement of the efficiency of work team, by developing objective & function amplification
and interpersonal processes.
Following are the stages of Team development.
Step 1: Forming : Team Formation as per the skills
Step 2: Storming : Discussions on views , thoughts , ideas of each team member
Step 3: Norming : To decide the work & to take a decision
Step 4: Performing : Here actual work starts
Step 5: Adjourning :This is the end step of a project , where team leader ensure about the
completeness of a project.
--------------------------------------------------------------------------------------------------------------------
--------------------------------------------------
Application
Team Development in Health care sector :
5 to 6 years back the issues of Swine Flue disease in India was very hot.This diseases was arising
in rainy seasons , because of the Wet & moisture atmosphere.At that moment there were no
vaccinations available. At that moment this diseases was attacking to so many people.
For that disease the famous institute in India , Syram Institute Pvt.Ltd (SIPL), this institute had
developed the Vaccination on this Swine Flu disease.
For preparing this vaccinations they gone through following stages of team development.
Step 1: Forming :
SIPL found a team from well background medical history .All were professional executive.They
were very much aware about the swine Flu diseases.
Step 2: Storming :
After forming a team , each & every individuals prospectus is being taken into account.
Dissolution , Analysis on thoughts , ideas were done for successful execution.
Step 3: Norming :
In this step this has been decided to produce vaccinations as a medicine for this diseases.
Vaccinations is being designed , tested ,achieved results .Finally hand over for mass productions.
Step 4: Performing :
In this stage millions of vaccinations are produced and made available time to time for patients
within time.
Step 5: Adjourning :
They completed this project successfully & made available this project to market in next year.At
the same time they are maintaining the changes in vaccinations time to time..
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