Calculate the implied stock price assuming an EBITDA multiple of 11..pdf
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Calculate the implied stock price assuming an EBITDA multiple of 11.2x. (All data in millions) Select one: a. $33.42 b. $41.93 c. $24.14 d. $20.58 e. $21.72Short-term debt:$22.5Shares Outstanding:18.330Convertible debt$0.0Diluted shares outstanding:21.501Long-term debt:$253.5Cash & equivalents:$46.5Total liabilities:$676.8Minority interest:$0.0EBITDA:$60.0Net income:$21.2 Solution EBITDA 60 11.2 672 Enterprise Value 672 Less : Short-Term debt -22.5 Long- term debt -253.5 Add: Cash 46.5 Equity Value 442.5 Diluted shares outstanding 21.501 Implied value of stock 20.58.
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public static ArrayListInteger doArrayListSearchSmallest(int nu.pdf
public static ArrayList doArrayListSearchSmallest(int numItems) {
System.out.print(\"doArrayListSearchSmallest: \");
ArrayList list = new ArrayList<>();
// TODO Write code that adds integers 0 through (numitems - 1)
// to list.
long startTime = getTimestamp();
// TODO Write code that gets the element at the first index from list.
long endTime = getTimestamp();
long totalTime = endTime - startTime;
System.out.println(totalTime);
return list;
}
Solution
Code that adds integers 0 through (numitems - 1) to the list. I have added a loop for adding
values to the list.
for(int i=0; i doArrayListAdd(int numItems) {
System.out.print(\"doArrayListAdd: \");
ArrayList list = new ArrayList<>();
long startTime = getTimestamp();
for(int i=0; i.
Project selection methods and the project portfolio play an importan.pdf
Project selection methods and the project portfolio play an important role for corporate
sustainability and strategic planning. It is important to distinguish between financial and non-
financial models for project selection, since each can yield different results. I need project
selection methods (financial or non-financial) or software applications with links. Also what
would be some of the benefits and/or shortcomings of the particular method
Solution
project selection methods based on financial models are Net present value method, Profitability
Index or Internal rate of return, sensitivity analysis. if you type these methods on the tool bar,
you will get all the related sites and the calculation procedures to implement it.
when it comes to nonfinancial methods, which speaks about sustainability of the firm there are
no pre determined and pre defined methods. the main objective is the climate and environment
should not disturb or pollute with our output. we should produce a product which is eco friendly
and customer friendly..
javaFix in the program belowhandle incomplete data for text fil.pdf
java
Fix in the program below:
handle incomplete data for text file and allow to search multiple items at once
and let it sort duplicate values
and most importantly let it use get and set methods on the Nodes
New Internal Requirements :
For this assignment, you should replace your Database class with another implementation which
uses instances of the Java Collections java.util.LinkedList class to replace your hand-crafted
LinkedList classes. Note the following:
• LinkedList is a generic type; you must instantiate it with concrete class types. Thus, your
Database object will contain several LinkedList objects; you will need to organize these lists into
another instance of LinkedList. (Consider creating a Year object to help with this.)
• You are still required to maintain your lists in sorted order. The pre-built LinkedList methods
do not directly support relative insertion into a linked list; you will need to find ways to
accomplish this with the tools available to you. (There are at least a couple of ways to do this.)
New function to add:
• A new command should be implemented which allows the user to edit a storm from the main
menu. If selected, the program should prompt the user for the year and storm name to be edited.
If a matching storm is found, the corresponding record should be displayed and the user
prompted for new information to be placed in the record. Users may not change the year or storm
name, but may change any of the other information. If no matching storm is found, no action
should be taken. The user should be informed of the outcome in any case.
this is what the txt file the program is reading from looks like:
2000/Alex/0110/0120/0
2001/Bill/0210/0220/0
2002/Chris/0310/0320/0
2003/Devon/0140/0420/0
2004/Eli/0510/0520/1
2005/Fred/0610/0620/2
2006/Gilbert/0710/0820/3
2007/Herbert/0910/0920/4
2008/Kim/1010/1020/5
#######################################Java
Program#######################################################################
###
/*****************************************************************************
***************/
/*This program takes a a file and gives infomation to the user using a LinkedList */
/*****************************************************************************
***************/
import java.io.File;
import java.io.FileNotFoundException;
import java.util.InputMismatchException;
import java.util.Scanner;
//setting variables to string or int
public class Storm {
private int stormYear;
private int stormMag;
private String stormStart;
private String stormEnd;
private String stormName;
/**
* Constructor
* Storing all variables from text file
* @param stormName
* @param stormYear
* @param stormStart
* @param stormEnd
* @param stormMag
*/
public Storm(String stormName, int stormYear, String stormStart, String stormEnd, int
stormMag) {
this.stormName = stormName;
this.stormYear = stormYear;
this.stormStart = stormStart;
this.stormEnd = stormEnd;
this.stormMag = stormMag;
}
/*******************************.
James can row 14 km downstream in a river in 2 hours. He takes 7 hou.pdf
James can row 14 km downstream in a river in 2 hours. He takes 7 hours to go back. Find the
speed of the current and the speed of James in still water.
Solution
d = rt
c = speed of current, r = rowing speed
14 = (r+c)*2 = (r-c)*7
2r+2c=14
7r-7c=14
-------
r+c=7 Eqn 1 div by 2
r-c=2 Eqn 2 div by 7
----- Add equations
2r = 9
r = 4.5 kph
c = 2.5 kph.
In the class we extensively discussed a generic singly linked list i.pdf
In the class we extensively discussed a generic singly linked list implemented as a node class.
Implement a generic node class called DoublyNode in which each node contains an element of
type E and each node is linked not only forward to the next element in the list but also backward
to the previous element in the list. Your implementation should adapt and implement all the
methods of generic Node including the following methods:
Constructor for DoublyNode
addNodeAfter, removeNodeAfter
getData, setData
getForeLink, setForeLink
getBackLink, setBackLink
listCopy
listCopyWithTail
listLength
listPart
listPosition
listSearch
Solution
import java.util.ListIterator;
import java.util.NoSuchElementException;
import java.util.Random;
public class DoublyNode {
private Node head;
private Node tail;
private int size;
public DoublyNode() {
size = 0;
}
private class Node {
E element;
Node getForeNode;
Node getBackNode;
public Node(E element, Node next, Node prev) {
this.element = element;
this.getForeNode = next;
this.getBackNode = prev;
}
}
public int listLength() { return size; }
public boolean isEmpty() { return size == 0; }
public void addFirst(E element) {
Node tmp = new Node(element, head, null);
if(head != null ) {head.getBackNode = tmp;}
head = tmp;
if(tail == null) { tail = tmp;}
size++;
System.out.println(\"adding: \"+element);
}
public void addNodeAfter(E element) {
Node tmp = new Node(element, null, tail);
if(tail != null) {tail.getForeNode = tmp;}
tail = tmp;
if(head == null) { head = tmp;}
size++;
System.out.println(\"adding: \"+element);
}
public void addNodeAfterSpecifiedNode(E element, E tobeAddedAfter) {
Node prevTobeAddedAfter = listSearch(element);
Node afterNode = prevTobeAddedAfter.getForeNode;
Node tmpNode = new Node(element,prevTobeAddedAfter,afterNode);
tmpNode = prevTobeAddedAfter.getForeNode;
afterNode = tmpNode.getForeNode;
}
public void listCopy(){
System.out.println(\"iterating forward..\");
Node tmp = head;
while(tmp != null){
System.out.println(tmp.element);
tmp = tmp.getForeNode;
}
}
public Node listSearch(E item){
System.out.println(\"Searching Item \"+item);
Node tmp = head;
while(tmp != null){
System.out.println(tmp.element);
if(tmp.element == item) {
System.out.println(\"Item found \"+item);
return tmp;
}
tmp = tmp.getForeNode;
}
return null;
}
public void iterateBackward(){
System.out.println(\"iterating backword..\");
Node tmp = tail;
while(tmp != null){
System.out.println(tmp.element);
tmp = tmp.getBackNode;
}
}
public E removeFirst() {
if (size == 0) throw new NoSuchElementException();
Node tmp = head;
head = head.getForeNode;
head.getBackNode = null;
size--;
System.out.println(\"deleted: \"+tmp.element);
return tmp.element;
}
public E removeNodeAfter() {
if (size == 0) throw new NoSuchElementException();
Node tmp = tail;
tail = tail.getBackNode;
tail.getForeNode = null;
size--;
System.out.println(\"deleted: \"+tmp.element);
return tmp.element;
}
}.
How do hydrophobic and hydrophilic hormones differ in their speeds a.pdf
How do hydrophobic and hydrophilic hormones differ in their speeds and modes of action?
Solution
Hydrophobic hormones are fat soluble while hydrophilic hormones are water soluble.
Hydrophobic hormones speed and modes of action is slower than the hydrophilic hormones as
they have to cross the cell membrane ,bind to receptors, go to nucleus and then attach to
particular DNA sequence for gene expression to occur while hydrophilic hormones simply attach
to receptors on cell surface and trigger a chemical recation. Mode of action: Hydrophobic
hormones pass through the cell membrane and bind to receptors present inside the cell forming a
hormone receptor complex.This complex then moves to nucleus of the cell and bind to a
particular DNA sequence.This either turns on or turns off the expression of the gene resulting in
production of enzymes that regulate the activity of the cell whereas in case of hydrophilic
hormones the speed and action is faster as they bind directly to receptors (particularly G proteins
)that are expressed on the cell surface and initiate a signaling event involving second messenger,
such as cyclic adenosine monophosphate (cAMP). The second messengers then function to
amplify the hormone signal to a greater extent thereby resulting in efficinet and faster response.
Overall the speed and mode of action of hydrophilic hormones is faster than hydrophilic
hormones..
Given below is an issue that you have identified as an issue in a ret.pdf
Given below is an issue that you have identified as an issue in a retail company: Assume the
organization is a typical retailer with a corporate network installation. Store networks are
connected to the backend servers via the POS machines. Network administrators use Telnet to
access the network and network passwords never expire. Administrators should only access the
network internally. Complete a risk qualification for this organization and identify the following:
Vulnerability: Threats (threat actor and activity): Severity: Likelihood: Sensitivity:
Solution
According to the above corporate network infrastructure, the following risks can be found in
terms of security & Risk Management:
Vulnerability: As authentication credentials and all the commands are sent to the network device
in cleartext format, it could allow for eavesdropping or manipulation of data in transit between
the user and the network device.
Threat: It\'s a kind of internal abuse.A savvy insider could interpret and steal sensitive
information or credentials of an authorized administrator as it traverses the network.
Severity: Payment card information traverses these n/w devices between the point of sale system
(in the stores) and back-end servers (corporate data centers). If they can get access to the n/w
device, they can have the full control or access to view any of this sensitive data.
Likelihood: Although it is possible to view any data in a Telnet session, it is not trivial to sniff
traffic on a switched network. The attacker would need to be in the path of the communication
between the network device and the administrator, or the attacker would need to exploit a
vulnerability on another network device in the path. Additionally, the attacker would need some
knowledge of the network device technology in order to capture and view data traversing the
network device after gaining access. The probability of the attacker gaining access once the
credentials have been stolen is further reduced by the use of Access Control Lists (ACLs) on the
network device to limit Telnet connections to certain source IP addresses used by network
administrator’s workstations. Given that the password never expires and is therefore likely not
ever to be changed, the chance of interception and successful exploitation increases over time.
The attack vector with the most the highest probability of success would be from the store
network.
Sensitivity: A breach of this sort would require the organization to publicly report the incident,
costing the company over $500,000 directly in the form of fines and lawsuits and also indirectly
when approximately 10% of clients switch their business to a competitor..
Explain Aquinas 5 proofs of God, being sure to identify the Aris.pdf
Explain Aquinas\' 5 proofs of God, being sure to identify the \"Aristotelian\" elements in each
proof.
Solution
Part I. The Argument from Motion. (Thomas argues that since everything that moves is moved
by another, there must thereby exist an Unmoved Mover.)
Part II. The Argument from Efficient Cause. (The sequence of causes which make up this
universe must have a First Cause.)
Part III. The Argument to Necessary Being. (Since all existent things depend upon other things
for their existence, there must exist at least one thing that is not dependent and so is a Necessary
Being.)
Part IV. The Argument from Gradation. (Since all existent things can be compared to such
qualities as degrees of goodness, there must exist something that is an Absolutely Good Being.)
Part V. The Argument from Design. (Also named “The Teleological Argument”— The intricate
design and order of existent things and natural processes imply that a Great Designer exists.).
Recommended
public static ArrayListInteger doArrayListSearchSmallest(int nu.pdf
public static ArrayList doArrayListSearchSmallest(int numItems) {
System.out.print(\"doArrayListSearchSmallest: \");
ArrayList list = new ArrayList<>();
// TODO Write code that adds integers 0 through (numitems - 1)
// to list.
long startTime = getTimestamp();
// TODO Write code that gets the element at the first index from list.
long endTime = getTimestamp();
long totalTime = endTime - startTime;
System.out.println(totalTime);
return list;
}
Solution
Code that adds integers 0 through (numitems - 1) to the list. I have added a loop for adding
values to the list.
for(int i=0; i doArrayListAdd(int numItems) {
System.out.print(\"doArrayListAdd: \");
ArrayList list = new ArrayList<>();
long startTime = getTimestamp();
for(int i=0; i.
Project selection methods and the project portfolio play an importan.pdf
Project selection methods and the project portfolio play an important role for corporate
sustainability and strategic planning. It is important to distinguish between financial and non-
financial models for project selection, since each can yield different results. I need project
selection methods (financial or non-financial) or software applications with links. Also what
would be some of the benefits and/or shortcomings of the particular method
Solution
project selection methods based on financial models are Net present value method, Profitability
Index or Internal rate of return, sensitivity analysis. if you type these methods on the tool bar,
you will get all the related sites and the calculation procedures to implement it.
when it comes to nonfinancial methods, which speaks about sustainability of the firm there are
no pre determined and pre defined methods. the main objective is the climate and environment
should not disturb or pollute with our output. we should produce a product which is eco friendly
and customer friendly..
javaFix in the program belowhandle incomplete data for text fil.pdf
java
Fix in the program below:
handle incomplete data for text file and allow to search multiple items at once
and let it sort duplicate values
and most importantly let it use get and set methods on the Nodes
New Internal Requirements :
For this assignment, you should replace your Database class with another implementation which
uses instances of the Java Collections java.util.LinkedList class to replace your hand-crafted
LinkedList classes. Note the following:
• LinkedList is a generic type; you must instantiate it with concrete class types. Thus, your
Database object will contain several LinkedList objects; you will need to organize these lists into
another instance of LinkedList. (Consider creating a Year object to help with this.)
• You are still required to maintain your lists in sorted order. The pre-built LinkedList methods
do not directly support relative insertion into a linked list; you will need to find ways to
accomplish this with the tools available to you. (There are at least a couple of ways to do this.)
New function to add:
• A new command should be implemented which allows the user to edit a storm from the main
menu. If selected, the program should prompt the user for the year and storm name to be edited.
If a matching storm is found, the corresponding record should be displayed and the user
prompted for new information to be placed in the record. Users may not change the year or storm
name, but may change any of the other information. If no matching storm is found, no action
should be taken. The user should be informed of the outcome in any case.
this is what the txt file the program is reading from looks like:
2000/Alex/0110/0120/0
2001/Bill/0210/0220/0
2002/Chris/0310/0320/0
2003/Devon/0140/0420/0
2004/Eli/0510/0520/1
2005/Fred/0610/0620/2
2006/Gilbert/0710/0820/3
2007/Herbert/0910/0920/4
2008/Kim/1010/1020/5
#######################################Java
Program#######################################################################
###
/*****************************************************************************
***************/
/*This program takes a a file and gives infomation to the user using a LinkedList */
/*****************************************************************************
***************/
import java.io.File;
import java.io.FileNotFoundException;
import java.util.InputMismatchException;
import java.util.Scanner;
//setting variables to string or int
public class Storm {
private int stormYear;
private int stormMag;
private String stormStart;
private String stormEnd;
private String stormName;
/**
* Constructor
* Storing all variables from text file
* @param stormName
* @param stormYear
* @param stormStart
* @param stormEnd
* @param stormMag
*/
public Storm(String stormName, int stormYear, String stormStart, String stormEnd, int
stormMag) {
this.stormName = stormName;
this.stormYear = stormYear;
this.stormStart = stormStart;
this.stormEnd = stormEnd;
this.stormMag = stormMag;
}
/*******************************.
James can row 14 km downstream in a river in 2 hours. He takes 7 hou.pdf
James can row 14 km downstream in a river in 2 hours. He takes 7 hours to go back. Find the
speed of the current and the speed of James in still water.
Solution
d = rt
c = speed of current, r = rowing speed
14 = (r+c)*2 = (r-c)*7
2r+2c=14
7r-7c=14
-------
r+c=7 Eqn 1 div by 2
r-c=2 Eqn 2 div by 7
----- Add equations
2r = 9
r = 4.5 kph
c = 2.5 kph.
In the class we extensively discussed a generic singly linked list i.pdf
In the class we extensively discussed a generic singly linked list implemented as a node class.
Implement a generic node class called DoublyNode in which each node contains an element of
type E and each node is linked not only forward to the next element in the list but also backward
to the previous element in the list. Your implementation should adapt and implement all the
methods of generic Node including the following methods:
Constructor for DoublyNode
addNodeAfter, removeNodeAfter
getData, setData
getForeLink, setForeLink
getBackLink, setBackLink
listCopy
listCopyWithTail
listLength
listPart
listPosition
listSearch
Solution
import java.util.ListIterator;
import java.util.NoSuchElementException;
import java.util.Random;
public class DoublyNode {
private Node head;
private Node tail;
private int size;
public DoublyNode() {
size = 0;
}
private class Node {
E element;
Node getForeNode;
Node getBackNode;
public Node(E element, Node next, Node prev) {
this.element = element;
this.getForeNode = next;
this.getBackNode = prev;
}
}
public int listLength() { return size; }
public boolean isEmpty() { return size == 0; }
public void addFirst(E element) {
Node tmp = new Node(element, head, null);
if(head != null ) {head.getBackNode = tmp;}
head = tmp;
if(tail == null) { tail = tmp;}
size++;
System.out.println(\"adding: \"+element);
}
public void addNodeAfter(E element) {
Node tmp = new Node(element, null, tail);
if(tail != null) {tail.getForeNode = tmp;}
tail = tmp;
if(head == null) { head = tmp;}
size++;
System.out.println(\"adding: \"+element);
}
public void addNodeAfterSpecifiedNode(E element, E tobeAddedAfter) {
Node prevTobeAddedAfter = listSearch(element);
Node afterNode = prevTobeAddedAfter.getForeNode;
Node tmpNode = new Node(element,prevTobeAddedAfter,afterNode);
tmpNode = prevTobeAddedAfter.getForeNode;
afterNode = tmpNode.getForeNode;
}
public void listCopy(){
System.out.println(\"iterating forward..\");
Node tmp = head;
while(tmp != null){
System.out.println(tmp.element);
tmp = tmp.getForeNode;
}
}
public Node listSearch(E item){
System.out.println(\"Searching Item \"+item);
Node tmp = head;
while(tmp != null){
System.out.println(tmp.element);
if(tmp.element == item) {
System.out.println(\"Item found \"+item);
return tmp;
}
tmp = tmp.getForeNode;
}
return null;
}
public void iterateBackward(){
System.out.println(\"iterating backword..\");
Node tmp = tail;
while(tmp != null){
System.out.println(tmp.element);
tmp = tmp.getBackNode;
}
}
public E removeFirst() {
if (size == 0) throw new NoSuchElementException();
Node tmp = head;
head = head.getForeNode;
head.getBackNode = null;
size--;
System.out.println(\"deleted: \"+tmp.element);
return tmp.element;
}
public E removeNodeAfter() {
if (size == 0) throw new NoSuchElementException();
Node tmp = tail;
tail = tail.getBackNode;
tail.getForeNode = null;
size--;
System.out.println(\"deleted: \"+tmp.element);
return tmp.element;
}
}.
How do hydrophobic and hydrophilic hormones differ in their speeds a.pdf
How do hydrophobic and hydrophilic hormones differ in their speeds and modes of action?
Solution
Hydrophobic hormones are fat soluble while hydrophilic hormones are water soluble.
Hydrophobic hormones speed and modes of action is slower than the hydrophilic hormones as
they have to cross the cell membrane ,bind to receptors, go to nucleus and then attach to
particular DNA sequence for gene expression to occur while hydrophilic hormones simply attach
to receptors on cell surface and trigger a chemical recation. Mode of action: Hydrophobic
hormones pass through the cell membrane and bind to receptors present inside the cell forming a
hormone receptor complex.This complex then moves to nucleus of the cell and bind to a
particular DNA sequence.This either turns on or turns off the expression of the gene resulting in
production of enzymes that regulate the activity of the cell whereas in case of hydrophilic
hormones the speed and action is faster as they bind directly to receptors (particularly G proteins
)that are expressed on the cell surface and initiate a signaling event involving second messenger,
such as cyclic adenosine monophosphate (cAMP). The second messengers then function to
amplify the hormone signal to a greater extent thereby resulting in efficinet and faster response.
Overall the speed and mode of action of hydrophilic hormones is faster than hydrophilic
hormones..
Given below is an issue that you have identified as an issue in a ret.pdf
Given below is an issue that you have identified as an issue in a retail company: Assume the
organization is a typical retailer with a corporate network installation. Store networks are
connected to the backend servers via the POS machines. Network administrators use Telnet to
access the network and network passwords never expire. Administrators should only access the
network internally. Complete a risk qualification for this organization and identify the following:
Vulnerability: Threats (threat actor and activity): Severity: Likelihood: Sensitivity:
Solution
According to the above corporate network infrastructure, the following risks can be found in
terms of security & Risk Management:
Vulnerability: As authentication credentials and all the commands are sent to the network device
in cleartext format, it could allow for eavesdropping or manipulation of data in transit between
the user and the network device.
Threat: It\'s a kind of internal abuse.A savvy insider could interpret and steal sensitive
information or credentials of an authorized administrator as it traverses the network.
Severity: Payment card information traverses these n/w devices between the point of sale system
(in the stores) and back-end servers (corporate data centers). If they can get access to the n/w
device, they can have the full control or access to view any of this sensitive data.
Likelihood: Although it is possible to view any data in a Telnet session, it is not trivial to sniff
traffic on a switched network. The attacker would need to be in the path of the communication
between the network device and the administrator, or the attacker would need to exploit a
vulnerability on another network device in the path. Additionally, the attacker would need some
knowledge of the network device technology in order to capture and view data traversing the
network device after gaining access. The probability of the attacker gaining access once the
credentials have been stolen is further reduced by the use of Access Control Lists (ACLs) on the
network device to limit Telnet connections to certain source IP addresses used by network
administrator’s workstations. Given that the password never expires and is therefore likely not
ever to be changed, the chance of interception and successful exploitation increases over time.
The attack vector with the most the highest probability of success would be from the store
network.
Sensitivity: A breach of this sort would require the organization to publicly report the incident,
costing the company over $500,000 directly in the form of fines and lawsuits and also indirectly
when approximately 10% of clients switch their business to a competitor..
Explain Aquinas 5 proofs of God, being sure to identify the Aris.pdf
Explain Aquinas\' 5 proofs of God, being sure to identify the \"Aristotelian\" elements in each
proof.
Solution
Part I. The Argument from Motion. (Thomas argues that since everything that moves is moved
by another, there must thereby exist an Unmoved Mover.)
Part II. The Argument from Efficient Cause. (The sequence of causes which make up this
universe must have a First Cause.)
Part III. The Argument to Necessary Being. (Since all existent things depend upon other things
for their existence, there must exist at least one thing that is not dependent and so is a Necessary
Being.)
Part IV. The Argument from Gradation. (Since all existent things can be compared to such
qualities as degrees of goodness, there must exist something that is an Absolutely Good Being.)
Part V. The Argument from Design. (Also named “The Teleological Argument”— The intricate
design and order of existent things and natural processes imply that a Great Designer exists.).
Exercise 7. Show that if C(0) (the punctured plane) and U C are conf.pdf
Exercise 7. Show that if C/(0) (the punctured plane) and U C are conformally equivalent, then
C/U has no interior, i.e. the complement of U contains no open sets.
Solution
Let P be the punctured plane and U be conformally equivalent.
Then the complements P\' (of P) and U\'( of U) will be topologically equivalent.
But P\' ={0} is a singleton...has no interior points..(hence contains no open sets)
So the same it true of U\'.
Hence the result.
Consider the following segment table What are the physical addresse.pdf
Consider the following segment table: What are the physical addresses for the following virtual
addresses? 4.44 1.22 Briefly compare segmentation to paging.
Solution
a) Physical address for 4,44:
2200+44 = 2244
Physical address for 1,22:
Illegal reference
b) Paging and segmentation are different in the following ways:
1) A page is a contiguous range of memory addresses which is mapped to physical memory
whereas a segment is an independent address space.
2) A has only one linear address space whereas a segment has many address spaces.
3) A page is a physical unit whereas a segment is a logical unit..
Can you explain the movement of ions and ion channel activity during.pdf
Can you explain the movement of ions and ion channel activity during the resting and action
potential?
Solution
Action potential is the potential due to the which the impulse is passed from one neuron to
another.
Resting stage - in resting stage the inside has higher concentration of Potassium ions ie (-ve)
sign,wheareas the outside it has high concentration of Sodium ions ie (+ve) ions..!! The
membrane is slightly permeable to Sodium ions to transport the Sodium outside maintaining the
concentration outside and inside..
Action potential - during this this the membrane becomes much more permeable to Sodium ions
which allows the huge of Sodium inside the neuron in a short time making the charge opposite
direction with comparison to outside.. The Potassium ions moves outside of the neuron thus
creating action potential....
Below is the graph of a polynomial function f with real coefficients.pdf
Below is the graph of a polynomial function f with real coefficients. Use the graph to answer the
following questions about f . All local extrema of f are shown in the graph.
Solution
As the graph is + infinity in y , for - infinity in x
and - infinity in y for + infinity in x
it means the degree is odd
that implies
5,7,9.
Are higher than average sea surface temperatures associated with a g.pdf
Are higher than average sea surface temperatures associated with a greater than average number
of hurricanes each year? In a 2010 study, the average global sea surface temperature anomaly
was recorded, along with the number of Atlantic hurricanes above or below the average for that
year. The response variable is:
Solution
Variables of interest in an experiment (those that are measured or observed) are called response
or dependent variable
The response variable is: average number of hurricanes each year.
A table of values of an increasing function F is shown. Use the table.pdf
A table of values of an increasing function F is shown. Use the table to find to find lower and
upper estimates for integral^30 _10 (x) dx.
Solution
function is increasing
x =4
lower estimate =x[f(10)+f(14)+f(18)+f(22)+f(26)]
lower estimate =4*[-12-6-2+1+3]
lower estimate =-64
============================
upper estimate =x[f(14)+f(18)+f(22)+f(26)+f(30)]
upper estimate =4*[-6-2+1+3+8]
upper estimate =16.
A polygenic trait is determined by a single gene with many different.pdf
A polygenic trait is determined by a single gene with many different alleles.
true or false
Solution
False -some traits are controlled by more than one pair of genes this is refered to as continuous or
polygeneic trait.
This means each dominant allele is adds to the expression of next dominant allele..
4. Phil is conducting a seed germination experiment. He places 3 gro.pdf
4. Phil is conducting a seed germination experiment. He places 3 groups of lettuce seeds in a 34º
Celsius
incubator with adequate moisture. One set of seeds is placed in a dark area with no light source.
A second set
is placed under artificial light and third set of seeds is placed in direct sunlight. This experiment
is intended to
test Phil\'s hypothesis that light is necessary for lettuce seed germination.
Based on the experimental design, which group was the control?
A. Moisture
B. Seeds in the dark
C. Type of light
D. Temperature
E. Germination rate
Solution
In this study seeds in the dark is control group. The control group does not receive any treatment
by the researchers in an experiment and this control group is used for the comparison with other
test group. In this experiment seeds in the dark is not receiving any treatment as it is placed in a
dark area with no light source. Hence seeds in the dark is control group in this experiment..
21. What is the relationship between the maximum size of aggregates a.pdf
21. What is the relationship between the maximum size of aggregates and concrete strengths for
the same water-cement ratio 22. Certain harmful materias in aggregates, such as such as some
shales, will cause popouts. What are the mechanisms of the popouts? 23. What are the minerals
that are considered low shrinkage aggregates? 24. List three negative effects of organic
impurities in concrete
Solution
21) Relationship between maximum size of aggregates and concrete compreesive strength:
Compressive strength of concrete depends on the aggreagte strength not necessarily on the
aggragate size. However, with an increase in size of the aggreagte to the maximum the
consumption of water-cement ratio decreases, thereby the density of concrete increases. With
increase in density, the compressive strength increases.
The surface texture of aggregate can either be smooth or rough. A smooth surface can improve
the workability, yet a rougher surface generates a stronger bond between the paste and the
agggregates creating a higher strength. Angular and elongated aggregates have higher surface to
volume ratio, better bond characteristics but require more cement paste to produce a workable
mixture. So for the same water-cement ratio, smooth aggregates are preferred to produce higher
compressive strength.
22) Mechanisms of popouts:
Shales have been found to be montmorillonitic. Popouts could be attributed to the pressures
generated by the absorption of water by the monmorillonite.
The reaction between cement alkalis and the reactive shale particles form an alkali-silica gel at
the surface of the reacted particle. The quantity of gel produced from a single reactive particle,
and the rate at which it forms, will be the greatest if the particles are exposed to high-alkali
concentrations. Once formed, the alkali silica gel absorbs water and start to swell. The swollen
gel occupies the available pore space in the concrete creating pressures, which often causes
popouts.
23) Minerals that are considered low shrinkage aggregates:
Metakalinite: It is a highly reactive material which is formed as a result of roasting of natural
kaolinite at temperatures of 700oC to 900oC.
Zeolite: The source of zeolite formation is due to settlement of volcanic ash and then reaction
with lake salts.
Fly ash: It is a by-product obtained during combustion of coal in thermal power plants.
Silica fumes: It is a by-product of the production of elemental silicon or alloys containing silicon,
also known as condensed silica fume or microsilica.
Slag: Blast furnace slag is a by product of extraction of iron ore. Amongst the mineral
admixtures, slag possesses the highest specific gravity( around 2.8 to 3.0).
Rice hush ash: It is a highly reactive pozzolan obtained by controlled calcination of rice husks.
24) Negative effects of organic impurities:
- Organic impurities derived from decaying vegetation delay the setting time and hardening of
concrete.
- Silt, clay and dust may form a coating on the a.
Which of the following are organizer molecules in the avian PMZ is a.pdf
Which of the following are organizer molecules in the avian PMZ? is a multiple answer
question. pick all that fit. Chordin Cerebrus Frzb Goosecoid Noggin Follistatin Veg T Vg1
Nodal Sonic hedgehog
Solution
1) Cordin
2) Goosecoid
3) VegT
4) Vg1
These are the avian organizer molecules.
In summary, there is evidence for an active Wnt/Beta catenin pathway within the vegetal region
of the chick embryo, which is radially distributed around the epiblast. In contrast, the
Tbx6L/cVg1/CMIX system is restricted to the posterior vegetal region of the embryo. The
activities of the two pathways overlap spatially in the posterior marginal zone(PMZ), which thus
becomes a focal structure of early avian development..
What are the five stages of team development Describe each stage an.pdf
What are the five stages of team development? Describe each stage and how that might appear in
a healthcare setting.
Solution
What are the five stages of team development? Describe each stage and how that might appear in
a healthcare setting.
Answer :
Team Development :
Improvement of the efficiency of work team, by developing objective & function amplification
and interpersonal processes.
Following are the stages of Team development.
Step 1: Forming : Team Formation as per the skills
Step 2: Storming : Discussions on views , thoughts , ideas of each team member
Step 3: Norming : To decide the work & to take a decision
Step 4: Performing : Here actual work starts
Step 5: Adjourning :This is the end step of a project , where team leader ensure about the
completeness of a project.
--------------------------------------------------------------------------------------------------------------------
--------------------------------------------------
Application
Team Development in Health care sector :
5 to 6 years back the issues of Swine Flue disease in India was very hot.This diseases was arising
in rainy seasons , because of the Wet & moisture atmosphere.At that moment there were no
vaccinations available. At that moment this diseases was attacking to so many people.
For that disease the famous institute in India , Syram Institute Pvt.Ltd (SIPL), this institute had
developed the Vaccination on this Swine Flu disease.
For preparing this vaccinations they gone through following stages of team development.
Step 1: Forming :
SIPL found a team from well background medical history .All were professional executive.They
were very much aware about the swine Flu diseases.
Step 2: Storming :
After forming a team , each & every individuals prospectus is being taken into account.
Dissolution , Analysis on thoughts , ideas were done for successful execution.
Step 3: Norming :
In this step this has been decided to produce vaccinations as a medicine for this diseases.
Vaccinations is being designed , tested ,achieved results .Finally hand over for mass productions.
Step 4: Performing :
In this stage millions of vaccinations are produced and made available time to time for patients
within time.
Step 5: Adjourning :
They completed this project successfully & made available this project to market in next year.At
the same time they are maintaining the changes in vaccinations time to time..
What kinds of molecules can be used as metabolic fuel to produce ATP.pdf
What kinds of molecules can be used as metabolic fuel to produce ATP?
A) Amino acids, fatty acids, and CO2
B) Water, sugars, and amino acids
C) Sugars, amino acids, and fatty acids
Solution
C) Sugar, Amino acid and fatty acids
CO2 and water molecule can not synthesise ATP. Sugars, amino acids, and fatty acids are
mediator in TCA cycle to synthesise ATP..
1. Choose the best answer for each statmentquestion.a.) Which sta.pdf
1. Choose the best answer for each statment/question.
a.) Which statement describes the difference between the normal neuron protein PrPC and the
pathogenic version PrPSc
In a persistent infection, the host cell is continually releasing new viral particles slowly. In a
latent infection, there are periods of time where the virus is not replicating and creating new viral
particles.
b.) One hypothesis that has been proposed to explain the development of viruses suggests that
viruses were beneficial because they allowed for rapid gene transfer, especially in prokaryotic
cells, and therefore increased genetic diversity. If most bacteriophages were temperate, then this
could have increased horizontal gene transfer between prokaryotic cells and potentially could
have increased fitness. With respect to this hypothesis, why would it matter whether the
bacteriophages were temperate or virulent?
Temperate phages don\'t immediately kill their hosts.
c.) One hypothesis that has been proposed to explain the development of viruses suggests that
viruses were beneficial because they allowed for rapid gene transfer, especially in prokaryotic
cells, and therefore increased genetic diversity. Why is this hypothesis stronger with respect to
prokaryotic cells than if large, complex eukaryotic organisms had been involved?
In eukaryotic organisms with sexual reproduction, great genetic diversity can be accomplished
through crossing over and independent assortment in meiosis.
d.) Why do some bacteriophages, like X174, using rolling circle replication instead of the
bidirectional replication?Persistent infections always lead to cell lysis, while latent infections
never lead to cell lysis.In a latent infection, the host cell is continually releasing new viral
particles slowly. In a persistent infection, there are periods of time where the virus is not
replicating and creating new viral particles.Persistent infections can cause transformation of the
host cell, which can lead to the development of cancer. Latent infections do not cause
transformation.
In a persistent infection, the host cell is continually releasing new viral particles slowly. In a
latent infection, there are periods of time where the virus is not replicating and creating new
viral particles.
b.) One hypothesis that has been proposed to explain the development of viruses suggests that
viruses were beneficial because they allowed for rapid gene transfer, especially in prokaryotic
cells, and therefore increased genetic diversity. If most bacteriophages were temperate, then this
could have increased horizontal gene transfer between prokaryotic cells and potentially could
have increased fitness. With respect to this hypothesis, why would it matter whether the
bacteriophages were temperate or virulent?Temperate phages are capable of lysogeny and their
genetic material can be integrated into the host genome, causing damage rather than increasing
fitness.Virulent phages are capable of lysogeny and their genetic.
1) What does the nonbranching proposal say about split-brain patient.pdf
1) What does the nonbranching proposal say about split-brain patients? Are there two people
present in the body? If so, is either identical with the person who occupied the body before the
operation?
Solution
As far as awareness hypothesis there is a contention that says that the patient has two continuous
flows. One half of the globe contending with the other with regards to taking care of an object(s).
Inside an ordinary subject contending continuous flows is nothing strange, yet the distinction is
by all accounts that the SB understanding can\'t synchronize the two contending streams into a
bound together state. In the matter of whether this outcomes in a split identity I don\'t generally
know.
Yes. In right gave patients, the left-mind stays associated with beon and will show the greater
part of the subject\'s unique attributes. (Switched in left gave patients.) from the beginning, the
correct cerebrum will show no identity since it is recently curious to see what happens, as some
time recently..
What are the levels of biodiversity. And how are they valuable Drag.pdf
What are the levels of biodiversity. And how are they valuable? Drag the labels onto the
concept map to review the ecological value and practical benefits of biodiversity. First fill in the
pink targets using the pink labels. Then complete the rest of the concept map using the blue
labels.
Solution
a. Ecosystem diversity
b. Species diversity
c. Genetic diversity
d . Ecosystem services: Ecosystem diversity provides Ecosystem services including water
purification.
e. Community interactions: these community interactions lead to emergence of keystone species.
f. genes with practical uses
g. New medicines
h.Species survival.
Two students were debating how to classify superscalar operation ver.pdf
Two students were debating how to classify superscalar operation versus the use of VLIW
instructions. The debate was over which of these is an organizational feature and which is an
architectural feature. Indicate which point of view you would support and explain why.
Solution
A superscalar processor is a CPU that implements a form of parallelism calledinstruction-level
parallelism within a single processor. It therefore allows for morethroughput (the number of
instructions that can be executed in a unit of time) than would otherwise be possible at a
givenclock rate. A superscalar processor can execute more than one instruction during a clock
cycle by simultaneously dispatching multiple instructions to different execution units on the
processor. Each execution unit is not a separate processor (or a core if the processor is a multi-
core processor), but an execution resource within a single CPU such as an arithmetic logic unit.
In Flynn\'s taxonomy, a single-core superscalar processor is classified as anSISD processor
(Single Instruction stream, Single Data stream), though many superscalar processors support
short vector operations and so could be classified as SIMD (Single Instruction stream, Multiple
Data streams). A multi-core superscalar processor is classified as an MIMD processor (Multiple
Instruction streams, Multiple Data streams).
While a superscalar CPU is typically alsopipelined, pipelining and superscalar execution are
considered different performance enhancement techniques. The former executes multiple
instructions in the same execution unit in parallel by dividing the execution unit into different
phases, whereas the latter executes multiple instructions in parallel by using multiple execution
units.
The superscalar technique is traditionally associated with several identifying characteristics
(within a given CPU):
Instructions are issued from a sequential instruction stream
The CPU dynamically checks for data dependencies between instructions at run time (versus
software checking at compile time)
The CPU can execute multiple instructions per clock cycle.
Throughout the semester, we have been working on command line applic.pdf
Throughout the semester, we have been working on command line applications. While the
command line can be a powerful form of interacting with the computer, most modern
applications have a graphical user interface, or GUI. This program will give you some initial
experience making GUI applications with Swing.
1. Write an original GUI application in Java using Swing. The program can be a simple game, or
an application that demonstrates some of the capabilities of Swing, for example.
2. The application must do something non-trivial that is controlled by GUI components such as
buttons, text boxes, drop-down boxes, etc. For example, it might draw different things, or change
colors, based on button presses.
3. The GUI elements should be layed out reasonably using layout managers.
4. At least one element in your GUI program besides the title bar must include your name.
Suggestions
Get the skeleton of your GUI working first. First get the buttons drawing properly, then go on to
listen to and respond to events.
Initially, hook up the event listeners so that they print something to the console when a button is
pressed. That way you can know that your code is getting events.
If your program will draw shapes, make a subclass of JPanel called \"DrawPanel\" or something
like that to draw the objects and your name. Override the \"paintComponent\" method of this
class.
Solution
import javax.swing.*; import java.awt.*; class gui{ public static void main(String args[]){
//Creating the Frame JFrame frame = new JFrame(\"Chat Frame\");
frame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE); frame.setSize(400,400);
//Creating the MenuBar and adding components JMenuBar mb = new JMenuBar(); JMenu m1 =
new JMenu(\"FILE\"); JMenu m2 = new JMenu(\"Help\"); mb.add(m1); mb.add(m2);
JMenuItem m11 = new JMenuItem(\"Open\"); JMenuItem m22 =new JMenuItem(\"Save as\");
m1.add(m11); m1.add(m22); //Creating the panel at bottom and adding components JPanel panel
= new JPanel(); // the panel is not visible in output JLabel label = new JLabel(\"Enter Text\");
JTextField tf = new JTextField(10);// accepts upto 10 characters JButton send = new
JButton(\"Send\"); JButton reset = new JButton(\"Reset\"); panel.add(label);// Components
Added using Flow Layout panel.add(tf); panel.add(send); panel.add(reset); // Text Area at the
Center JTextArea ta = new JTextArea(); //Adding Components to the frame.
frame.getContentPane().add(BorderLayout.SOUTH,panel);
frame.getContentPane().add(BorderLayout.NORTH,mb);
frame.getContentPane().add(BorderLayout.CENTER,ta); frame.setVisible(true); } }.
the formula to compute the spending multiplier isSolutionS.pdf
the formula to compute the spending multiplier is:
Solution
Spending multiplier= Change in equilibrium real GDP/ initial change in autonomous spending.
This multiplier shows how much economy\'s output can rise with an increase in spending.
This change in spending could be change in consumption, investment,govt spending and net
exports.
Formula for spending multiplier= 1/(1-MPC) or 1/MPS; where MPC is maginal propensity to
consume..
The figure illustrates an interaction between a(n) CTL and its tar.pdf
The figure illustrates an interaction between a(n) CTL and its target cell. antigen presenting
cell and a plasma cell. antigen presenting cell and a B lymphocyte. antigen presenting cell and a
T lymphocyte. NK cell and its target cell.
Solution
TCR (T-cell receptor) and MHC|| are complex to present APC( antigen presenting cell)
CD4 CD8 are xo stimulatory signals for activation of T-cell
So answer is Interaction between antigen presenting cell and T-lymphocytes.
The implementation for Mergesort given in Section 7.4 takes an array .pdf
The implementation for Mergesort given in Section 7.4 takes an array as input and soils that
array. At the beginning of Section 7.4 there is a simple pseudocode implementation for sorting a
linked list using Mergesort. Implement both a linked list-based version of Mergesort and the
array-based version of Mergesort, and compare and analyze their running times.
Solution
program
import java.io.BufferedReader;
import java.io.InputStreamReader;
import java.util.ArrayList;
import java.util.Iterator;
public class Merge
{
public static int[] merge(int [] list)
{
if (list.length <= 1)
{
return list;
}
int[] first = new int[list.length / 2];
int[] second = new int[list.length - first.length];
System.arraycopy(list, 0, first, 0, first.length);
System.arraycopy(list, first.length, second, 0, second.length);
merge(first);
merge(second);
mergesort(first, second, list);
return list;
}
private static void mergesort(int[] first, int[] second, int [] result) {
int iFirst = 0;
int iSecond = 0;
int j = 0;
while (iFirst < first.length && iSecond < second.length)
{
if (first[iFirst] < second[iSecond])
{
result[j] = first[iFirst];
iFirst++;
} else
{
result[j] = second[iSecond];
iSecond++;
}
j++;
}
System.arraycopy(first, iFirst, result, j, first.length - iFirst);
System.arraycopy(second, iSecond, result, j, second.length - iSecond);
}
public static void main(String args[]) throws Exception
{
String list=\"\";
int i=0,n=0;
Merge s= new Merge();
ArrayList arrlist=new ArrayList();
System.out.println(\" \");
System.out.println(\" \");
System.out.println(\"Please enter the list of elements,one element per line\");
System.out.println(\" write \'STOP\' when list is completed \");
BufferedReader bf=new BufferedReader(new InputStreamReader(System.in));
while(!(list=bf.readLine()).equalsIgnoreCase(\"stop\"))
{
int intelement=Integer.parseInt(list);
arrlist.add(intelement);
}
int elementlist[] = new int[arrlist.size()];
Iterator iter = arrlist.iterator();
for (int j=0;iter.hasNext();j++) {
elementlist[j] = iter.next();
}
elementlist=merge(elementlist);
System.out.println(\" \");
System.out.println(\" \");
System.out.println(\" \");
System.out.println(\"Values after Merge Sort : \");
for (int j=0;j.
How libraries can support authors with open access requirements for UKRI fund...
How libraries can support authors with open access requirements for UKRI funded books
Wednesday 22 May 2024, 14:00-15:00.
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Exercise 7. Show that if C(0) (the punctured plane) and U C are conf.pdf
Exercise 7. Show that if C/(0) (the punctured plane) and U C are conformally equivalent, then
C/U has no interior, i.e. the complement of U contains no open sets.
Solution
Let P be the punctured plane and U be conformally equivalent.
Then the complements P\' (of P) and U\'( of U) will be topologically equivalent.
But P\' ={0} is a singleton...has no interior points..(hence contains no open sets)
So the same it true of U\'.
Hence the result.
Consider the following segment table What are the physical addresse.pdf
Consider the following segment table: What are the physical addresses for the following virtual
addresses? 4.44 1.22 Briefly compare segmentation to paging.
Solution
a) Physical address for 4,44:
2200+44 = 2244
Physical address for 1,22:
Illegal reference
b) Paging and segmentation are different in the following ways:
1) A page is a contiguous range of memory addresses which is mapped to physical memory
whereas a segment is an independent address space.
2) A has only one linear address space whereas a segment has many address spaces.
3) A page is a physical unit whereas a segment is a logical unit..
Can you explain the movement of ions and ion channel activity during.pdf
Can you explain the movement of ions and ion channel activity during the resting and action
potential?
Solution
Action potential is the potential due to the which the impulse is passed from one neuron to
another.
Resting stage - in resting stage the inside has higher concentration of Potassium ions ie (-ve)
sign,wheareas the outside it has high concentration of Sodium ions ie (+ve) ions..!! The
membrane is slightly permeable to Sodium ions to transport the Sodium outside maintaining the
concentration outside and inside..
Action potential - during this this the membrane becomes much more permeable to Sodium ions
which allows the huge of Sodium inside the neuron in a short time making the charge opposite
direction with comparison to outside.. The Potassium ions moves outside of the neuron thus
creating action potential....
Below is the graph of a polynomial function f with real coefficients.pdf
Below is the graph of a polynomial function f with real coefficients. Use the graph to answer the
following questions about f . All local extrema of f are shown in the graph.
Solution
As the graph is + infinity in y , for - infinity in x
and - infinity in y for + infinity in x
it means the degree is odd
that implies
5,7,9.
Are higher than average sea surface temperatures associated with a g.pdf
Are higher than average sea surface temperatures associated with a greater than average number
of hurricanes each year? In a 2010 study, the average global sea surface temperature anomaly
was recorded, along with the number of Atlantic hurricanes above or below the average for that
year. The response variable is:
Solution
Variables of interest in an experiment (those that are measured or observed) are called response
or dependent variable
The response variable is: average number of hurricanes each year.
A table of values of an increasing function F is shown. Use the table.pdf
A table of values of an increasing function F is shown. Use the table to find to find lower and
upper estimates for integral^30 _10 (x) dx.
Solution
function is increasing
x =4
lower estimate =x[f(10)+f(14)+f(18)+f(22)+f(26)]
lower estimate =4*[-12-6-2+1+3]
lower estimate =-64
============================
upper estimate =x[f(14)+f(18)+f(22)+f(26)+f(30)]
upper estimate =4*[-6-2+1+3+8]
upper estimate =16.
A polygenic trait is determined by a single gene with many different.pdf
A polygenic trait is determined by a single gene with many different alleles.
true or false
Solution
False -some traits are controlled by more than one pair of genes this is refered to as continuous or
polygeneic trait.
This means each dominant allele is adds to the expression of next dominant allele..
4. Phil is conducting a seed germination experiment. He places 3 gro.pdf
4. Phil is conducting a seed germination experiment. He places 3 groups of lettuce seeds in a 34º
Celsius
incubator with adequate moisture. One set of seeds is placed in a dark area with no light source.
A second set
is placed under artificial light and third set of seeds is placed in direct sunlight. This experiment
is intended to
test Phil\'s hypothesis that light is necessary for lettuce seed germination.
Based on the experimental design, which group was the control?
A. Moisture
B. Seeds in the dark
C. Type of light
D. Temperature
E. Germination rate
Solution
In this study seeds in the dark is control group. The control group does not receive any treatment
by the researchers in an experiment and this control group is used for the comparison with other
test group. In this experiment seeds in the dark is not receiving any treatment as it is placed in a
dark area with no light source. Hence seeds in the dark is control group in this experiment..
21. What is the relationship between the maximum size of aggregates a.pdf
21. What is the relationship between the maximum size of aggregates and concrete strengths for
the same water-cement ratio 22. Certain harmful materias in aggregates, such as such as some
shales, will cause popouts. What are the mechanisms of the popouts? 23. What are the minerals
that are considered low shrinkage aggregates? 24. List three negative effects of organic
impurities in concrete
Solution
21) Relationship between maximum size of aggregates and concrete compreesive strength:
Compressive strength of concrete depends on the aggreagte strength not necessarily on the
aggragate size. However, with an increase in size of the aggreagte to the maximum the
consumption of water-cement ratio decreases, thereby the density of concrete increases. With
increase in density, the compressive strength increases.
The surface texture of aggregate can either be smooth or rough. A smooth surface can improve
the workability, yet a rougher surface generates a stronger bond between the paste and the
agggregates creating a higher strength. Angular and elongated aggregates have higher surface to
volume ratio, better bond characteristics but require more cement paste to produce a workable
mixture. So for the same water-cement ratio, smooth aggregates are preferred to produce higher
compressive strength.
22) Mechanisms of popouts:
Shales have been found to be montmorillonitic. Popouts could be attributed to the pressures
generated by the absorption of water by the monmorillonite.
The reaction between cement alkalis and the reactive shale particles form an alkali-silica gel at
the surface of the reacted particle. The quantity of gel produced from a single reactive particle,
and the rate at which it forms, will be the greatest if the particles are exposed to high-alkali
concentrations. Once formed, the alkali silica gel absorbs water and start to swell. The swollen
gel occupies the available pore space in the concrete creating pressures, which often causes
popouts.
23) Minerals that are considered low shrinkage aggregates:
Metakalinite: It is a highly reactive material which is formed as a result of roasting of natural
kaolinite at temperatures of 700oC to 900oC.
Zeolite: The source of zeolite formation is due to settlement of volcanic ash and then reaction
with lake salts.
Fly ash: It is a by-product obtained during combustion of coal in thermal power plants.
Silica fumes: It is a by-product of the production of elemental silicon or alloys containing silicon,
also known as condensed silica fume or microsilica.
Slag: Blast furnace slag is a by product of extraction of iron ore. Amongst the mineral
admixtures, slag possesses the highest specific gravity( around 2.8 to 3.0).
Rice hush ash: It is a highly reactive pozzolan obtained by controlled calcination of rice husks.
24) Negative effects of organic impurities:
- Organic impurities derived from decaying vegetation delay the setting time and hardening of
concrete.
- Silt, clay and dust may form a coating on the a.
Which of the following are organizer molecules in the avian PMZ is a.pdf
Which of the following are organizer molecules in the avian PMZ? is a multiple answer
question. pick all that fit. Chordin Cerebrus Frzb Goosecoid Noggin Follistatin Veg T Vg1
Nodal Sonic hedgehog
Solution
1) Cordin
2) Goosecoid
3) VegT
4) Vg1
These are the avian organizer molecules.
In summary, there is evidence for an active Wnt/Beta catenin pathway within the vegetal region
of the chick embryo, which is radially distributed around the epiblast. In contrast, the
Tbx6L/cVg1/CMIX system is restricted to the posterior vegetal region of the embryo. The
activities of the two pathways overlap spatially in the posterior marginal zone(PMZ), which thus
becomes a focal structure of early avian development..
What are the five stages of team development Describe each stage an.pdf
What are the five stages of team development? Describe each stage and how that might appear in
a healthcare setting.
Solution
What are the five stages of team development? Describe each stage and how that might appear in
a healthcare setting.
Answer :
Team Development :
Improvement of the efficiency of work team, by developing objective & function amplification
and interpersonal processes.
Following are the stages of Team development.
Step 1: Forming : Team Formation as per the skills
Step 2: Storming : Discussions on views , thoughts , ideas of each team member
Step 3: Norming : To decide the work & to take a decision
Step 4: Performing : Here actual work starts
Step 5: Adjourning :This is the end step of a project , where team leader ensure about the
completeness of a project.
--------------------------------------------------------------------------------------------------------------------
--------------------------------------------------
Application
Team Development in Health care sector :
5 to 6 years back the issues of Swine Flue disease in India was very hot.This diseases was arising
in rainy seasons , because of the Wet & moisture atmosphere.At that moment there were no
vaccinations available. At that moment this diseases was attacking to so many people.
For that disease the famous institute in India , Syram Institute Pvt.Ltd (SIPL), this institute had
developed the Vaccination on this Swine Flu disease.
For preparing this vaccinations they gone through following stages of team development.
Step 1: Forming :
SIPL found a team from well background medical history .All were professional executive.They
were very much aware about the swine Flu diseases.
Step 2: Storming :
After forming a team , each & every individuals prospectus is being taken into account.
Dissolution , Analysis on thoughts , ideas were done for successful execution.
Step 3: Norming :
In this step this has been decided to produce vaccinations as a medicine for this diseases.
Vaccinations is being designed , tested ,achieved results .Finally hand over for mass productions.
Step 4: Performing :
In this stage millions of vaccinations are produced and made available time to time for patients
within time.
Step 5: Adjourning :
They completed this project successfully & made available this project to market in next year.At
the same time they are maintaining the changes in vaccinations time to time..
What kinds of molecules can be used as metabolic fuel to produce ATP.pdf
What kinds of molecules can be used as metabolic fuel to produce ATP?
A) Amino acids, fatty acids, and CO2
B) Water, sugars, and amino acids
C) Sugars, amino acids, and fatty acids
Solution
C) Sugar, Amino acid and fatty acids
CO2 and water molecule can not synthesise ATP. Sugars, amino acids, and fatty acids are
mediator in TCA cycle to synthesise ATP..
1. Choose the best answer for each statmentquestion.a.) Which sta.pdf
1. Choose the best answer for each statment/question.
a.) Which statement describes the difference between the normal neuron protein PrPC and the
pathogenic version PrPSc
In a persistent infection, the host cell is continually releasing new viral particles slowly. In a
latent infection, there are periods of time where the virus is not replicating and creating new viral
particles.
b.) One hypothesis that has been proposed to explain the development of viruses suggests that
viruses were beneficial because they allowed for rapid gene transfer, especially in prokaryotic
cells, and therefore increased genetic diversity. If most bacteriophages were temperate, then this
could have increased horizontal gene transfer between prokaryotic cells and potentially could
have increased fitness. With respect to this hypothesis, why would it matter whether the
bacteriophages were temperate or virulent?
Temperate phages don\'t immediately kill their hosts.
c.) One hypothesis that has been proposed to explain the development of viruses suggests that
viruses were beneficial because they allowed for rapid gene transfer, especially in prokaryotic
cells, and therefore increased genetic diversity. Why is this hypothesis stronger with respect to
prokaryotic cells than if large, complex eukaryotic organisms had been involved?
In eukaryotic organisms with sexual reproduction, great genetic diversity can be accomplished
through crossing over and independent assortment in meiosis.
d.) Why do some bacteriophages, like X174, using rolling circle replication instead of the
bidirectional replication?Persistent infections always lead to cell lysis, while latent infections
never lead to cell lysis.In a latent infection, the host cell is continually releasing new viral
particles slowly. In a persistent infection, there are periods of time where the virus is not
replicating and creating new viral particles.Persistent infections can cause transformation of the
host cell, which can lead to the development of cancer. Latent infections do not cause
transformation.
In a persistent infection, the host cell is continually releasing new viral particles slowly. In a
latent infection, there are periods of time where the virus is not replicating and creating new
viral particles.
b.) One hypothesis that has been proposed to explain the development of viruses suggests that
viruses were beneficial because they allowed for rapid gene transfer, especially in prokaryotic
cells, and therefore increased genetic diversity. If most bacteriophages were temperate, then this
could have increased horizontal gene transfer between prokaryotic cells and potentially could
have increased fitness. With respect to this hypothesis, why would it matter whether the
bacteriophages were temperate or virulent?Temperate phages are capable of lysogeny and their
genetic material can be integrated into the host genome, causing damage rather than increasing
fitness.Virulent phages are capable of lysogeny and their genetic.
1) What does the nonbranching proposal say about split-brain patient.pdf
1) What does the nonbranching proposal say about split-brain patients? Are there two people
present in the body? If so, is either identical with the person who occupied the body before the
operation?
Solution
As far as awareness hypothesis there is a contention that says that the patient has two continuous
flows. One half of the globe contending with the other with regards to taking care of an object(s).
Inside an ordinary subject contending continuous flows is nothing strange, yet the distinction is
by all accounts that the SB understanding can\'t synchronize the two contending streams into a
bound together state. In the matter of whether this outcomes in a split identity I don\'t generally
know.
Yes. In right gave patients, the left-mind stays associated with beon and will show the greater
part of the subject\'s unique attributes. (Switched in left gave patients.) from the beginning, the
correct cerebrum will show no identity since it is recently curious to see what happens, as some
time recently..
What are the levels of biodiversity. And how are they valuable Drag.pdf
What are the levels of biodiversity. And how are they valuable? Drag the labels onto the
concept map to review the ecological value and practical benefits of biodiversity. First fill in the
pink targets using the pink labels. Then complete the rest of the concept map using the blue
labels.
Solution
a. Ecosystem diversity
b. Species diversity
c. Genetic diversity
d . Ecosystem services: Ecosystem diversity provides Ecosystem services including water
purification.
e. Community interactions: these community interactions lead to emergence of keystone species.
f. genes with practical uses
g. New medicines
h.Species survival.
Two students were debating how to classify superscalar operation ver.pdf
Two students were debating how to classify superscalar operation versus the use of VLIW
instructions. The debate was over which of these is an organizational feature and which is an
architectural feature. Indicate which point of view you would support and explain why.
Solution
A superscalar processor is a CPU that implements a form of parallelism calledinstruction-level
parallelism within a single processor. It therefore allows for morethroughput (the number of
instructions that can be executed in a unit of time) than would otherwise be possible at a
givenclock rate. A superscalar processor can execute more than one instruction during a clock
cycle by simultaneously dispatching multiple instructions to different execution units on the
processor. Each execution unit is not a separate processor (or a core if the processor is a multi-
core processor), but an execution resource within a single CPU such as an arithmetic logic unit.
In Flynn\'s taxonomy, a single-core superscalar processor is classified as anSISD processor
(Single Instruction stream, Single Data stream), though many superscalar processors support
short vector operations and so could be classified as SIMD (Single Instruction stream, Multiple
Data streams). A multi-core superscalar processor is classified as an MIMD processor (Multiple
Instruction streams, Multiple Data streams).
While a superscalar CPU is typically alsopipelined, pipelining and superscalar execution are
considered different performance enhancement techniques. The former executes multiple
instructions in the same execution unit in parallel by dividing the execution unit into different
phases, whereas the latter executes multiple instructions in parallel by using multiple execution
units.
The superscalar technique is traditionally associated with several identifying characteristics
(within a given CPU):
Instructions are issued from a sequential instruction stream
The CPU dynamically checks for data dependencies between instructions at run time (versus
software checking at compile time)
The CPU can execute multiple instructions per clock cycle.
Throughout the semester, we have been working on command line applic.pdf
Throughout the semester, we have been working on command line applications. While the
command line can be a powerful form of interacting with the computer, most modern
applications have a graphical user interface, or GUI. This program will give you some initial
experience making GUI applications with Swing.
1. Write an original GUI application in Java using Swing. The program can be a simple game, or
an application that demonstrates some of the capabilities of Swing, for example.
2. The application must do something non-trivial that is controlled by GUI components such as
buttons, text boxes, drop-down boxes, etc. For example, it might draw different things, or change
colors, based on button presses.
3. The GUI elements should be layed out reasonably using layout managers.
4. At least one element in your GUI program besides the title bar must include your name.
Suggestions
Get the skeleton of your GUI working first. First get the buttons drawing properly, then go on to
listen to and respond to events.
Initially, hook up the event listeners so that they print something to the console when a button is
pressed. That way you can know that your code is getting events.
If your program will draw shapes, make a subclass of JPanel called \"DrawPanel\" or something
like that to draw the objects and your name. Override the \"paintComponent\" method of this
class.
Solution
import javax.swing.*; import java.awt.*; class gui{ public static void main(String args[]){
//Creating the Frame JFrame frame = new JFrame(\"Chat Frame\");
frame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE); frame.setSize(400,400);
//Creating the MenuBar and adding components JMenuBar mb = new JMenuBar(); JMenu m1 =
new JMenu(\"FILE\"); JMenu m2 = new JMenu(\"Help\"); mb.add(m1); mb.add(m2);
JMenuItem m11 = new JMenuItem(\"Open\"); JMenuItem m22 =new JMenuItem(\"Save as\");
m1.add(m11); m1.add(m22); //Creating the panel at bottom and adding components JPanel panel
= new JPanel(); // the panel is not visible in output JLabel label = new JLabel(\"Enter Text\");
JTextField tf = new JTextField(10);// accepts upto 10 characters JButton send = new
JButton(\"Send\"); JButton reset = new JButton(\"Reset\"); panel.add(label);// Components
Added using Flow Layout panel.add(tf); panel.add(send); panel.add(reset); // Text Area at the
Center JTextArea ta = new JTextArea(); //Adding Components to the frame.
frame.getContentPane().add(BorderLayout.SOUTH,panel);
frame.getContentPane().add(BorderLayout.NORTH,mb);
frame.getContentPane().add(BorderLayout.CENTER,ta); frame.setVisible(true); } }.
the formula to compute the spending multiplier isSolutionS.pdf
the formula to compute the spending multiplier is:
Solution
Spending multiplier= Change in equilibrium real GDP/ initial change in autonomous spending.
This multiplier shows how much economy\'s output can rise with an increase in spending.
This change in spending could be change in consumption, investment,govt spending and net
exports.
Formula for spending multiplier= 1/(1-MPC) or 1/MPS; where MPC is maginal propensity to
consume..
The figure illustrates an interaction between a(n) CTL and its tar.pdf
The figure illustrates an interaction between a(n) CTL and its target cell. antigen presenting
cell and a plasma cell. antigen presenting cell and a B lymphocyte. antigen presenting cell and a
T lymphocyte. NK cell and its target cell.
Solution
TCR (T-cell receptor) and MHC|| are complex to present APC( antigen presenting cell)
CD4 CD8 are xo stimulatory signals for activation of T-cell
So answer is Interaction between antigen presenting cell and T-lymphocytes.
The implementation for Mergesort given in Section 7.4 takes an array .pdf
The implementation for Mergesort given in Section 7.4 takes an array as input and soils that
array. At the beginning of Section 7.4 there is a simple pseudocode implementation for sorting a
linked list using Mergesort. Implement both a linked list-based version of Mergesort and the
array-based version of Mergesort, and compare and analyze their running times.
Solution
program
import java.io.BufferedReader;
import java.io.InputStreamReader;
import java.util.ArrayList;
import java.util.Iterator;
public class Merge
{
public static int[] merge(int [] list)
{
if (list.length <= 1)
{
return list;
}
int[] first = new int[list.length / 2];
int[] second = new int[list.length - first.length];
System.arraycopy(list, 0, first, 0, first.length);
System.arraycopy(list, first.length, second, 0, second.length);
merge(first);
merge(second);
mergesort(first, second, list);
return list;
}
private static void mergesort(int[] first, int[] second, int [] result) {
int iFirst = 0;
int iSecond = 0;
int j = 0;
while (iFirst < first.length && iSecond < second.length)
{
if (first[iFirst] < second[iSecond])
{
result[j] = first[iFirst];
iFirst++;
} else
{
result[j] = second[iSecond];
iSecond++;
}
j++;
}
System.arraycopy(first, iFirst, result, j, first.length - iFirst);
System.arraycopy(second, iSecond, result, j, second.length - iSecond);
}
public static void main(String args[]) throws Exception
{
String list=\"\";
int i=0,n=0;
Merge s= new Merge();
ArrayList arrlist=new ArrayList();
System.out.println(\" \");
System.out.println(\" \");
System.out.println(\"Please enter the list of elements,one element per line\");
System.out.println(\" write \'STOP\' when list is completed \");
BufferedReader bf=new BufferedReader(new InputStreamReader(System.in));
while(!(list=bf.readLine()).equalsIgnoreCase(\"stop\"))
{
int intelement=Integer.parseInt(list);
arrlist.add(intelement);
}
int elementlist[] = new int[arrlist.size()];
Iterator iter = arrlist.iterator();
for (int j=0;iter.hasNext();j++) {
elementlist[j] = iter.next();
}
elementlist=merge(elementlist);
System.out.println(\" \");
System.out.println(\" \");
System.out.println(\" \");
System.out.println(\"Values after Merge Sort : \");
for (int j=0;j.
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