can you upload another pic, it is visible .pdf

More from annamalassociates

(a). (i) NH4Cl + H2O == NH4 OH + HCl Since in water it produces strong acid HCl which willdissociates completely to produce H+ ions.So, it is acidic innature (ii) ZnSO4 + 2H2O == Zn(OH)2 + H2 SO4 Since in water it produces strong acid H2SO4 which willdissociates completely to produce H+ ions.So, it is acidic innature (iii)Na2CO3 + 2H2O == 2NaOH + H2CO3 Since in water it produces strong base NaOH which willdissociates completely to produce OH- ions.So, it is basic innature (b). Concentration C = 0.10 M pH = 11.5 Solution (a). (i) NH4Cl + H2O == NH4 OH + HCl Since in water it produces strong acid HCl which willdissociates completely to produce H+ ions.So, it is acidic innature (ii) ZnSO4 + 2H2O == Zn(OH)2 + H2 SO4 Since in water it produces strong acid H2SO4 which willdissociates completely to produce H+ ions.So, it is acidic innature (iii)Na2CO3 + 2H2O == 2NaOH + H2CO3 Since in water it produces strong base NaOH which willdissociates completely to produce OH- ions.So, it is basic innature (b). Concentration C = 0.10 M pH = 11.5.

(a). (i) NH4Cl + H2O == NH4 OH + HClSince in water it produces str.pdf

annamalassociates

The elements in period 6 are those starting with Cs and going across. Given that the metal reacts vigorously with water, it must be either from groups 1 or 2 (alkali metals and alkali earth metals). If you\'ve seen the reaction (or heard about it) between sodium and water (hydrogen is produced rapidly and enough heat is given off that it explodes!), you\'ve seen this sort of reaction. Since the salt has 2 OH groups, it must form a stable +2 ion. This means it comes from group 2. If the compound was MOH, then it would have been from group 1. Now that we know it is in the 6th period (row) and 2nd group (column), we can identify the element as barium (Ba). Also, we know that its outermost electrons occupy the 6s orbital (because it is in the 6th period), so we can fill up orbitals now: Ba: 1s2, 2s2, 2p6, 3s2, 3p6, 4s2, 3d10, 4p6, 5s2, 4d10, 5p6, 6s2. The ordering is slightly different because higher values of n lead to d orbitals of very high energy, thus, for example, it is preferred to fill the 4s orbital before the 3 d orbital, and the 5p and 6s before considering the 4 f orbitals. The reaction that occurs is: Ba(s) + 2H2O(l) -------> Ba(OH)2(aq) + H2(g) Solution The elements in period 6 are those starting with Cs and going across. Given that the metal reacts vigorously with water, it must be either from groups 1 or 2 (alkali metals and alkali earth metals). If you\'ve seen the reaction (or heard about it) between sodium and water (hydrogen is produced rapidly and enough heat is given off that it explodes!), you\'ve seen this sort of reaction. Since the salt has 2 OH groups, it must form a stable +2 ion. This means it comes from group 2. If the compound was MOH, then it would have been from group 1. Now that we know it is in the 6th period (row) and 2nd group (column), we can identify the element as barium (Ba). Also, we know that its outermost electrons occupy the 6s orbital (because it is in the 6th period), so we can fill up orbitals now: Ba: 1s2, 2s2, 2p6, 3s2, 3p6, 4s2, 3d10, 4p6, 5s2, 4d10, 5p6, 6s2. The ordering is slightly different because higher values of n lead to d orbitals of very high energy, thus, for example, it is preferred to fill the 4s orbital before the 3 d orbital, and the 5p and 6s before considering the 4 f orbitals. The reaction that occurs is: Ba(s) + 2H2O(l) -------> Ba(OH)2(aq) + H2(g).

The elements in period 6 are those starting with Cs and going acr.pdf

annamalassociates

You can find the confidence interval (CI) for a population proportion to show the statistical probability that a characteristic is likely to occur within the population. When a characteristic being measured is categorical Solution You can find the confidence interval (CI) for a population proportion to show the statistical probability that a characteristic is likely to occur within the population. When a characteristic being measured is categorical.

You can find the confidence interval (CI) for a population prop.pdf

annamalassociates

a. 0.31Solution a. 0.31.pdf

annamalassociates

two molecules .pdf

annamalassociates

Step:1 pH change during the addition of 0.1 mol of Hcl to the 0.1 M NaH2PO4 In aqueous solutions - H2PO4^- (aq) + H3O^+ (l) <--------> H3PO4 (aq) + H2O (l) 0.1 0.1 0 - 0.1 - 0.1 +0.1 0 0 0.1 Hence we get completely acidic solution finally - H3PO4 (aq) + H2O (l) --------- > H3O^+ (aQ) + H2PO4^- (aQ) I(M) 0.1 0 0 C -x +x +x Eq 0.1-x x x Ka1 = 7.3*10^-5 = [H3O^+][H2PO4^-] / [H3PO4] = x^2 / (0.1-x) by solving , we get - x = 0.00266 M Thus pH =- log[H^+] = - log (0.00266) = 2.57 step:2 When we add base to the solution - the reaction occurs as H2PO4^- (aq) + OH^- (aq) <-----> HPO4^-2 (aq) + H2O (l) but here H2PO4^- is completely reacted and forms its conjugate base Hence- HPO4^-2 (aq) + H2O (l) <-----> H3O^+ (aq) + PO4^-3 (aq) I(M) 0.1 0 0 0 C - x +x +x Eq 0.1-x x x Kb = Kw/Ka3 = 10^-14 /(4.8*10^-13) = x^2 /(0.1-x) by solving - we get - x = 0.0363 Therefore [OH^-] = 0.0363 M Thus pOH = - log[OH^-] = - log (0.0363) = 1.44 pH = 14 -1.44 = 12.55 Solution Step:1 pH change during the addition of 0.1 mol of Hcl to the 0.1 M NaH2PO4 In aqueous solutions - H2PO4^- (aq) + H3O^+ (l) <--------> H3PO4 (aq) + H2O (l) 0.1 0.1 0 - 0.1 - 0.1 +0.1 0 0 0.1 Hence we get completely acidic solution finally - H3PO4 (aq) + H2O (l) --------- > H3O^+ (aQ) + H2PO4^- (aQ) I(M) 0.1 0 0 C -x +x +x Eq 0.1-x x x Ka1 = 7.3*10^-5 = [H3O^+][H2PO4^-] / [H3PO4] = x^2 / (0.1-x) by solving , we get - x = 0.00266 M Thus pH =- log[H^+] = - log (0.00266) = 2.57 step:2 When we add base to the solution - the reaction occurs as H2PO4^- (aq) + OH^- (aq) <-----> HPO4^-2 (aq) + H2O (l) but here H2PO4^- is completely reacted and forms its conjugate base Hence- HPO4^-2 (aq) + H2O (l) <-----> H3O^+ (aq) + PO4^-3 (aq) I(M) 0.1 0 0 0 C - x +x +x Eq 0.1-x x x Kb = Kw/Ka3 = 10^-14 /(4.8*10^-13) = x^2 /(0.1-x) by solving - we get - x = 0.0363 Therefore [OH^-] = 0.0363 M Thus pOH = - log[OH^-] = - log (0.0363) = 1.44 pH = 14 -1.44 = 12.55.

Step1 pH change during the addition of 0.1 mol o.pdf

annamalassociates

SF4 is most likely to be a covalent compound beca.pdf

annamalassociates

please post the clear qsn..... i ll help u in ans.pdf

annamalassociates

one Solution one .pdf

annamalassociates

linear shape non- polar since there are 2 simila.pdf

annamalassociates

B. Transcription of the viral genome for future translation (correct answer). Explanation: Hepatitis B virus (HBV) is a good example of dsDNA virus having gaps. It replicates via reverse transcription using a RNA intermediate. First of all, the virus enters nucleus of the host cell. In the nucleus, the gapped genome is filled with ccc DNA. This serves as template for production of host mRNA and sub-genomic RNA (transcription). This RNA further converts into DNA by the enzyme reverse transcriptase. Solution B. Transcription of the viral genome for future translation (correct answer). Explanation: Hepatitis B virus (HBV) is a good example of dsDNA virus having gaps. It replicates via reverse transcription using a RNA intermediate. First of all, the virus enters nucleus of the host cell. In the nucleus, the gapped genome is filled with ccc DNA. This serves as template for production of host mRNA and sub-genomic RNA (transcription). This RNA further converts into DNA by the enzyme reverse transcriptase..

B. Transcription of the viral genome for future translation (correct.pdf

annamalassociates

answer(A)Solutionanswer(A).pdf

annamalassociates

e) HBr is a weak electrolyte. .pdf

annamalassociates

C. An endothermic reaction is always nonspontaneo.pdf

annamalassociates

b. is the only source of ATP in red blood cells .pdf

annamalassociates

Future Value= Present value(1+interest Rate per year)10But the fut.pdf

annamalassociates

a) the system into the surroundings c) is endothe.pdf

annamalassociates

Code Division Multiple Access (CDMA) could be a digital cellular technology used for mobile communication. CDMA is that the base on that access strategies like cdmaOne, CDMA-2000, and WCDMA area unit designed. CDMA cellular systems area unit deemed superior to FDMA and TDMA, that is why CDMA plays a essential role in building economical, robust, and secure radio communication systems. A Simple Analogy Let’s take an easy analogy to grasp the thought of CDMA. Assume we\'ve a couple of students gathered in a very room WHO would really like to speak to every alternative at the same time. Nothing would be sonic if everybody starts speaking at constant time. Either they need to alternate to talk or use totally different languages to speak. The second choice is kind of just like CDMA students speaking constant language will perceive one another, whereas alternative languages area unit perceived as noise and rejected. Similarly, in radio CDMA, every cluster of users is given a shared code. several codes occupy constant channel, however solely those users related to a selected code will communicate. Salient options of CDMA CDMA, that is predicated on the unfold spectrum technique has following salient options In CDMA, each channel uses the total accessible spectrum. Individual conversations area unit encoded with a pseudo-random digital sequence so transmitted employing a wide frequency vary. CDMA systematically provides higher capability for voice and knowledge communications, permitting a lot of subscribers to attach at any given time. CDMA is that the common platform on that 3G technologies area unit designed. For 3G, CDMA uses 1x EV-DO and EV-DV. Third Generation Standards CDMA2000 uses Frequency Division Duplexing-Multicarrier (FDD-MC) mode. Here, multicarrier implies N × one.25 Mc channels overlaid on N existing IS-95 carriers or deployed on unoccupied spectrum. CDMA2000 includes 1x — uses a spreading rate of one.2288 Mcps. 3x — uses a spreading rate of three × one.2288 Mcps or three.6864 Mcps. 1xEV-DO (1x Evolution – knowledge Optimized) — uses a spreading rate of one.2288 Mcps, optimized for the info. WCDMA/FDD-DS — band CDMA (WCDMA) Frequency Division Duplexing-Direct Sequence spreading (FDD-DS) mode. This encompasses a single five Mc channel. WCDMA uses one carrier per channel and employs a spreading rate of three.84 Mcps. CDMA Development cluster (CDG) The CDMA Development cluster (CDG), supported in Dec 1993, is a world pool of firms. It works along to steer the expansion and evolution of advanced wireless telecommunication systems. CDG is comprised of service suppliers, infrastructure makers, device vendors, equipment vendors, application developers, and content suppliers. Its members put together outline the technical needs for the event of complementary systems CDMA2000 and 4G. Further, the ability with alternative rising wireless technologies area unit meant to extend the provision of wireless merchandise and services to customers and .

Code Division Multiple Access (CDMA) could be a digital cellular tec.pdf

annamalassociates

can you provide a pictureSolutioncan you provide a picture.pdf

annamalassociates

C13H22SolutionC13H22.pdf

annamalassociates

More from annamalassociates (20)

(a). (i) NH4Cl + H2O == NH4 OH + HClSince in water it produces str.pdf

The elements in period 6 are those starting with Cs and going acr.pdf

You can find the confidence interval (CI) for a population prop.pdf

a. 0.31Solution a. 0.31.pdf

two molecules .pdf

Step1 pH change during the addition of 0.1 mol o.pdf

SF4 is most likely to be a covalent compound beca.pdf

please post the clear qsn..... i ll help u in ans.pdf

one Solution one .pdf

linear shape non- polar since there are 2 simila.pdf

B. Transcription of the viral genome for future translation (correct.pdf

answer(A)Solutionanswer(A).pdf

e) HBr is a weak electrolyte. .pdf

C. An endothermic reaction is always nonspontaneo.pdf

b. is the only source of ATP in red blood cells .pdf

Future Value= Present value(1+interest Rate per year)10But the fut.pdf

a) the system into the surroundings c) is endothe.pdf

Code Division Multiple Access (CDMA) could be a digital cellular tec.pdf

can you provide a pictureSolutioncan you provide a picture.pdf

C13H22SolutionC13H22.pdf

Recently uploaded

INU_CAPSTONEDESIGN_비밀번호486_업로드용 발표자료.pdf

bu07226

Additional Benefits for Employee Website.pdf

joachimlavalley1

Basic phrases for greeting and assisting costumers

PedroFerreira53928

Jose-Rizal-and-Philippine-Nationalism-National-Symbol-2.pptx

ricssacare

We all have good and bad thoughts from time to time and situation to situation. We are bombarded daily with spiraling thoughts(both negative and positive) creating all-consuming feel , making us difficult to manage with associated suffering. Good thoughts are like our Mob Signal (Positive thought) amidst noise(negative thought) in the atmosphere. Negative thoughts like noise outweigh positive thoughts. These thoughts often create unwanted confusion, trouble, stress and frustration in our mind as well as chaos in our physical world. Negative thoughts are also known as “distorted thinking”.

How to Break the cycle of negative Thoughts

Col Mukteshwar Prasad

[GDSC YCCE] Build with AI Online Presentation

GDSCYCCE

NCERT Solutions Power Sharing Class 10 Notes pdf

Vivekanand Anglo Vedic Academy

🌲🦁 Forest and wildlife resources are the lifelines of our planet, nurturing biodiversity, maintaining ecological balance, and supporting countless life forms. 🌍 Understanding their significance is key to preserving our natural heritage sustainably. 🌿 Join me as we delve into the types, importance, threats, and conservation measures of these vital resources in our class 10 journey! 📚 Let's protect and cherish our forests and wildlife for generations to come. 🌳🐾 For more information, visit-www.vavaclasses.com

Forest and Wildlife Resources Class 10 Free Study Material PDF

Vivekanand Anglo Vedic Academy

Operations Management - Book1.p - Dr. Abdulfatah A. Salem

Arab Academy for Science, Technology and Maritime Transport

Ethnobotany and Ethnopharmacology ......

Ashokrao Mane college of Pharmacy Peth-Vadgaon

2024_Student Session 2_ Set Plan Preparation.pptx

mansk2

B.ed spl. HI pdusu exam paper-2023-24.pdf

Special education needs

Basic Civil Engineering Notes of Chapter-6, Topic- Ecosystem, Biodiversity Green house effect & Hydrological cycle Types of Ecosystem (1) Natural Ecosystem (2) Artificial Ecosystem component of ecosystem Biotic Components Abiotic Components Producers Consumers Decomposers Functions of Ecosystem Types of Biodiversity Genetic Biodiversity Species Biodiversity Ecological Biodiversity Importance of Biodiversity Hydrological Cycle Green House Effect

Basic Civil Engineering Notes of Chapter-6, Topic- Ecosystem, Biodiversity G...

Denish Jangid

Danh sách HSG Bộ môn cấp trường - Cấp THPT.pdf

QucHHunhnh

Matatag-Curriculum and the 21st Century Skills Presentation.pptx

JenilouCasareno

GIÁO ÁN DẠY THÊM (KẾ HOẠCH BÀI BUỔI 2) - TIẾNG ANH 8 GLOBAL SUCCESS (2 CỘT) N...

Nguyen Thanh Tu Collection

aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa

siemaillard

Title: Maximizing Industrial Training Benefits: A Comprehensive Guide Introduction:- Welcome to our comprehensive guide on industrial training and its myriad benefits. Learn how to optimize your industrial training experience for maximum growth and skill development. Understanding Industrial Training:- Definition: Industrial training refers to a structured program that integrates academic knowledge with practical application in a professional setting. Importance: It bridges the gap between theoretical learning and real-world industry practices. Key Components of Industrial Training:- Practical Experience: Hands-on learning in a real workplace environment. Mentorship: Guidance from experienced professionals in the field. Skill Development: Enhancement of technical, interpersonal, and problem-solving skills. Benefits of Industrial Training Enhanced Skill Set: Gain practical skills relevant to your field of study or career path. Industry Exposure: Acquire firsthand knowledge of industry practices and trends. Networking Opportunities: Connect with professionals and build valuable contacts for future endeavors. Career Advancement: Increase employability and stand out in the job market with relevant experience. Personal Growth: Develop confidence, adaptability, and problem-solving abilities. Resume Enhancement: Strengthen your resume with valuable practical experience. Potential Job Offers: Impress employers and increase your chances of securing job offers post-training. Insight into Work Culture: Understand workplace dynamics and organizational structures. Professional Guidance: Receive mentorship and guidance from seasoned professionals. Test-Drive Careers: Explore different career paths and industries to make informed decisions about your future. Case Studies Highlight successful industrial training experiences and their impact on participants' careers. Showcase testimonials from trainees and employers on the benefits of industrial training. Slide 8: Conclusion Industrial training offers invaluable opportunities for skill development, career advancement, and personal growth. By implementing the strategies outlined in this guide, you can maximize the benefits of your industrial training experience. Embrace every opportunity to learn, grow, and excel in your chosen field. SEO Ranking Tags:- Industrial Training AKTU report AKTU Industrial Training Report

Industrial Training Report- AKTU Industrial Training Report

Avinash Rai

aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa

siemaillard

How to Split Bills in the Odoo 17 POS Module

Celine George

Recently uploaded (20)

INU_CAPSTONEDESIGN_비밀번호486_업로드용 발표자료.pdf

Additional Benefits for Employee Website.pdf

Basic phrases for greeting and assisting costumers

Jose-Rizal-and-Philippine-Nationalism-National-Symbol-2.pptx

How to Break the cycle of negative Thoughts

[GDSC YCCE] Build with AI Online Presentation

NCERT Solutions Power Sharing Class 10 Notes pdf

Forest and Wildlife Resources Class 10 Free Study Material PDF

Operations Management - Book1.p - Dr. Abdulfatah A. Salem

Ethnobotany and Ethnopharmacology ......

2024_Student Session 2_ Set Plan Preparation.pptx

B.ed spl. HI pdusu exam paper-2023-24.pdf

Basic Civil Engineering Notes of Chapter-6, Topic- Ecosystem, Biodiversity G...

Danh sách HSG Bộ môn cấp trường - Cấp THPT.pdf

Matatag-Curriculum and the 21st Century Skills Presentation.pptx

GIÁO ÁN DẠY THÊM (KẾ HOẠCH BÀI BUỔI 2) - TIẾNG ANH 8 GLOBAL SUCCESS (2 CỘT) N...

aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa

Industrial Training Report- AKTU Industrial Training Report

aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa

How to Split Bills in the Odoo 17 POS Module

can you upload another pic, it is visible .pdf

Recommended

Recommended

More Related Content

More from annamalassociates

More from annamalassociates (20)

Recently uploaded

Recently uploaded (20)

can you upload another pic, it is visible .pdf