b. is the only source of ATP in red blood cells .pdf
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b. is the only source of ATP in red blood cells Solution b. is the only source of ATP in red blood cells.
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The three environmental changes that would likely change the relativ.pdf
The three environmental changes that would likely change the relative abundances of the
members within a microbial community temperature, oxygen content, water potential etc. There
are also other changes which may influence are light abundance, osmotic conditions, pH,
pressure etc.
Relative abundance refers to percent composition of an organism of particular kind relative to the
sum total of organisms present in the area. Extremphiles are regarded those who can sustain in
extreme environment conditions. For example thermophiles are those which are characterized by
high temperatures 41 - 122 0C. They include mainly prokaryotes like archea . Eukaryotic
organisms are not found above 60 0C. The genetic material of many thermophiles looks that of a
plasmid. Histone llike proteins found in prokaryotes wind DNA into light structures which
resemble nucleosomes and help DNA to retain the double stranded structure even at high
temperatures.
Salts like potassium and magnesium found in thermophilic archea protect the double stranded
DNA from phosphodiester bond degradation.
Solution
The three environmental changes that would likely change the relative abundances of the
members within a microbial community temperature, oxygen content, water potential etc. There
are also other changes which may influence are light abundance, osmotic conditions, pH,
pressure etc.
Relative abundance refers to percent composition of an organism of particular kind relative to the
sum total of organisms present in the area. Extremphiles are regarded those who can sustain in
extreme environment conditions. For example thermophiles are those which are characterized by
high temperatures 41 - 122 0C. They include mainly prokaryotes like archea . Eukaryotic
organisms are not found above 60 0C. The genetic material of many thermophiles looks that of a
plasmid. Histone llike proteins found in prokaryotes wind DNA into light structures which
resemble nucleosomes and help DNA to retain the double stranded structure even at high
temperatures.
Salts like potassium and magnesium found in thermophilic archea protect the double stranded
DNA from phosphodiester bond degradation..
Spanish colonisers spoke and heard different languages than did Dutc.pdf
Spanish colonisers spoke and heard different languages than did Dutch, English and French
colonisers in the North America NORTHEAST(New England). Spanish colonisers brought
Romania Catholicism to the indigenous population. Both protestant, Anglican and Catholic
established presence in the northeast. Spanish came largely to pillage and remove natural wealth.
In the northeast colonists were more motivated by establishing industry and trading with
homelands. Spanish colonisers tended to be dictatorial and northeast colonies tended towards
democracy.
Solution
Spanish colonisers spoke and heard different languages than did Dutch, English and French
colonisers in the North America NORTHEAST(New England). Spanish colonisers brought
Romania Catholicism to the indigenous population. Both protestant, Anglican and Catholic
established presence in the northeast. Spanish came largely to pillage and remove natural wealth.
In the northeast colonists were more motivated by establishing industry and trading with
homelands. Spanish colonisers tended to be dictatorial and northeast colonies tended towards
democracy..
public class Demo{ public static void main(String[] args) throws I.pdf
public class Demo{
public static void main(String[] args) throws IOException {
int temp =0;
int n= 12;
Scanner file1 = new Scanner(new File(\"path to reach yor file\"));
List values = new ArrayList<>();
while (file1.hasNext()) {
temp = file1.next();
values.add(temp);
}
file1.close();
greater(values,n);
}
public void greater(ArrayList a, int n){
for (int x = 0; x < a.length; x++) {
if (x>=n) {
System.out.println(\" \" + x);
}
}
}
}
Solution
public class Demo{
public static void main(String[] args) throws IOException {
int temp =0;
int n= 12;
Scanner file1 = new Scanner(new File(\"path to reach yor file\"));
List values = new ArrayList<>();
while (file1.hasNext()) {
temp = file1.next();
values.add(temp);
}
file1.close();
greater(values,n);
}
public void greater(ArrayList a, int n){
for (int x = 0; x < a.length; x++) {
if (x>=n) {
System.out.println(\" \" + x);
}
}
}
}.
Prime numbers are those which have only two Factors. 1 and the numbe.pdf
Prime numbers are those which have only two Factors. 1 and the number it self. That is to say no
other number can perfectly divide the given prime number. For Example 2,3,5,7,11 .... etc which
are prime numbers ... each of these can only be divisible by either 1 or the number itself. On the
contrary other numbers i.e Composite numbers have more than two factors. Each of the
composite numbers has at least 1 more factor besides 1 and the number itself. For example 4
which has 1,2 and 4 as its factors.
An exponent is the number of times the base is multiplied by itself.
Ex 2^3 (2 cubed or 2 raised to power 3) means 2 X 2 X 2 ( 2 multiplied with itself 3 times which
is 8. The number that is being multiplied repeatedly is called the base or root or radical where as
the number of \'times\' it is multiplied is known as the index or power or exponent.
Difference between a Fraction and a Decimal.
A Decimal is also a fraction with the denominator being either 10 or the exponents of 10. A
fraction on the other hand denotes simply a part of the whole. Decimal fractions is a logical
development of the base 10 place value.
Examples of Fractions - 1/2 (half), 2/3 (two thirds) etc
Decimal Fractions - 0.2 = 2/10, 0.05 = 5/100 etc
Solution
Prime numbers are those which have only two Factors. 1 and the number it self. That is to say no
other number can perfectly divide the given prime number. For Example 2,3,5,7,11 .... etc which
are prime numbers ... each of these can only be divisible by either 1 or the number itself. On the
contrary other numbers i.e Composite numbers have more than two factors. Each of the
composite numbers has at least 1 more factor besides 1 and the number itself. For example 4
which has 1,2 and 4 as its factors.
An exponent is the number of times the base is multiplied by itself.
Ex 2^3 (2 cubed or 2 raised to power 3) means 2 X 2 X 2 ( 2 multiplied with itself 3 times which
is 8. The number that is being multiplied repeatedly is called the base or root or radical where as
the number of \'times\' it is multiplied is known as the index or power or exponent.
Difference between a Fraction and a Decimal.
A Decimal is also a fraction with the denominator being either 10 or the exponents of 10. A
fraction on the other hand denotes simply a part of the whole. Decimal fractions is a logical
development of the base 10 place value.
Examples of Fractions - 1/2 (half), 2/3 (two thirds) etc
Decimal Fractions - 0.2 = 2/10, 0.05 = 5/100 etc.
Answer The brains straight (which is also called tentorial sinus.pdf
Answer : The brain\'s straight (which is also called tentorial sinus) sinus permits immediate CSF
drainage from the INFERIOR SAGITTAL SINUS.
Solution
Answer : The brain\'s straight (which is also called tentorial sinus) sinus permits immediate CSF
drainage from the INFERIOR SAGITTAL SINUS..
Microsoft accquiring NokiaMicrosoft had goodwill impairement loss.pdf
Microsoft accquiring Nokia:
Microsoft had goodwill impairement loss of 5.5 Billion Dollars in 2014.
Stakeholders react negatively to impairement as it reuces your net profits.
Acquisition cost is directly proportional to goodwill impairement charges.
Solution
Microsoft accquiring Nokia:
Microsoft had goodwill impairement loss of 5.5 Billion Dollars in 2014.
Stakeholders react negatively to impairement as it reuces your net profits.
Acquisition cost is directly proportional to goodwill impairement charges..
J 1. Accrual BasisA system of accounting in which revenu.pdf
J 1. Accrual Basis
A system of accounting in which revenues are recognized when earned and expenses are
recognized when incurred.
H 2. Cost Principle
Assets are recorded at the cost to acquire them.
E 3. Credit
An entry on the right side of an account.
D 4. Debit
An entry on the left side of an account.
A 5. Generally Accepted Accounting Principles (GAAP)
The various methods, rules, practices, and other procedures that have evolved over time in
response to the need to regulate the preparation of financial statements.
C 6. General Ledger
A book, file, hard drive, or other devices containing all of a company’s accounts.
F 7. Journal
A chronological record of transactions, also known as the book of original entry.
I 8. Liquidity
The ability of a company to pay the debts as they come due.
G 9. Matching Principle
The association of revenue of a period with all of the costs necessary to generate that revenue.
B 10. Materiality
The magnitude of an omission or misstatement in accounting information that will affect the
judgment of someone relying on the information.
Solution
J 1. Accrual Basis
A system of accounting in which revenues are recognized when earned and expenses are
recognized when incurred.
H 2. Cost Principle
Assets are recorded at the cost to acquire them.
E 3. Credit
An entry on the right side of an account.
D 4. Debit
An entry on the left side of an account.
A 5. Generally Accepted Accounting Principles (GAAP)
The various methods, rules, practices, and other procedures that have evolved over time in
response to the need to regulate the preparation of financial statements.
C 6. General Ledger
A book, file, hard drive, or other devices containing all of a company’s accounts.
F 7. Journal
A chronological record of transactions, also known as the book of original entry.
I 8. Liquidity
The ability of a company to pay the debts as they come due.
G 9. Matching Principle
The association of revenue of a period with all of the costs necessary to generate that revenue.
B 10. Materiality
The magnitude of an omission or misstatement in accounting information that will affect the
judgment of someone relying on the information..
Recommended
The three environmental changes that would likely change the relativ.pdf
The three environmental changes that would likely change the relative abundances of the
members within a microbial community temperature, oxygen content, water potential etc. There
are also other changes which may influence are light abundance, osmotic conditions, pH,
pressure etc.
Relative abundance refers to percent composition of an organism of particular kind relative to the
sum total of organisms present in the area. Extremphiles are regarded those who can sustain in
extreme environment conditions. For example thermophiles are those which are characterized by
high temperatures 41 - 122 0C. They include mainly prokaryotes like archea . Eukaryotic
organisms are not found above 60 0C. The genetic material of many thermophiles looks that of a
plasmid. Histone llike proteins found in prokaryotes wind DNA into light structures which
resemble nucleosomes and help DNA to retain the double stranded structure even at high
temperatures.
Salts like potassium and magnesium found in thermophilic archea protect the double stranded
DNA from phosphodiester bond degradation.
Solution
The three environmental changes that would likely change the relative abundances of the
members within a microbial community temperature, oxygen content, water potential etc. There
are also other changes which may influence are light abundance, osmotic conditions, pH,
pressure etc.
Relative abundance refers to percent composition of an organism of particular kind relative to the
sum total of organisms present in the area. Extremphiles are regarded those who can sustain in
extreme environment conditions. For example thermophiles are those which are characterized by
high temperatures 41 - 122 0C. They include mainly prokaryotes like archea . Eukaryotic
organisms are not found above 60 0C. The genetic material of many thermophiles looks that of a
plasmid. Histone llike proteins found in prokaryotes wind DNA into light structures which
resemble nucleosomes and help DNA to retain the double stranded structure even at high
temperatures.
Salts like potassium and magnesium found in thermophilic archea protect the double stranded
DNA from phosphodiester bond degradation..
Spanish colonisers spoke and heard different languages than did Dutc.pdf
Spanish colonisers spoke and heard different languages than did Dutch, English and French
colonisers in the North America NORTHEAST(New England). Spanish colonisers brought
Romania Catholicism to the indigenous population. Both protestant, Anglican and Catholic
established presence in the northeast. Spanish came largely to pillage and remove natural wealth.
In the northeast colonists were more motivated by establishing industry and trading with
homelands. Spanish colonisers tended to be dictatorial and northeast colonies tended towards
democracy.
Solution
Spanish colonisers spoke and heard different languages than did Dutch, English and French
colonisers in the North America NORTHEAST(New England). Spanish colonisers brought
Romania Catholicism to the indigenous population. Both protestant, Anglican and Catholic
established presence in the northeast. Spanish came largely to pillage and remove natural wealth.
In the northeast colonists were more motivated by establishing industry and trading with
homelands. Spanish colonisers tended to be dictatorial and northeast colonies tended towards
democracy..
public class Demo{ public static void main(String[] args) throws I.pdf
public class Demo{
public static void main(String[] args) throws IOException {
int temp =0;
int n= 12;
Scanner file1 = new Scanner(new File(\"path to reach yor file\"));
List values = new ArrayList<>();
while (file1.hasNext()) {
temp = file1.next();
values.add(temp);
}
file1.close();
greater(values,n);
}
public void greater(ArrayList a, int n){
for (int x = 0; x < a.length; x++) {
if (x>=n) {
System.out.println(\" \" + x);
}
}
}
}
Solution
public class Demo{
public static void main(String[] args) throws IOException {
int temp =0;
int n= 12;
Scanner file1 = new Scanner(new File(\"path to reach yor file\"));
List values = new ArrayList<>();
while (file1.hasNext()) {
temp = file1.next();
values.add(temp);
}
file1.close();
greater(values,n);
}
public void greater(ArrayList a, int n){
for (int x = 0; x < a.length; x++) {
if (x>=n) {
System.out.println(\" \" + x);
}
}
}
}.
Prime numbers are those which have only two Factors. 1 and the numbe.pdf
Prime numbers are those which have only two Factors. 1 and the number it self. That is to say no
other number can perfectly divide the given prime number. For Example 2,3,5,7,11 .... etc which
are prime numbers ... each of these can only be divisible by either 1 or the number itself. On the
contrary other numbers i.e Composite numbers have more than two factors. Each of the
composite numbers has at least 1 more factor besides 1 and the number itself. For example 4
which has 1,2 and 4 as its factors.
An exponent is the number of times the base is multiplied by itself.
Ex 2^3 (2 cubed or 2 raised to power 3) means 2 X 2 X 2 ( 2 multiplied with itself 3 times which
is 8. The number that is being multiplied repeatedly is called the base or root or radical where as
the number of \'times\' it is multiplied is known as the index or power or exponent.
Difference between a Fraction and a Decimal.
A Decimal is also a fraction with the denominator being either 10 or the exponents of 10. A
fraction on the other hand denotes simply a part of the whole. Decimal fractions is a logical
development of the base 10 place value.
Examples of Fractions - 1/2 (half), 2/3 (two thirds) etc
Decimal Fractions - 0.2 = 2/10, 0.05 = 5/100 etc
Solution
Prime numbers are those which have only two Factors. 1 and the number it self. That is to say no
other number can perfectly divide the given prime number. For Example 2,3,5,7,11 .... etc which
are prime numbers ... each of these can only be divisible by either 1 or the number itself. On the
contrary other numbers i.e Composite numbers have more than two factors. Each of the
composite numbers has at least 1 more factor besides 1 and the number itself. For example 4
which has 1,2 and 4 as its factors.
An exponent is the number of times the base is multiplied by itself.
Ex 2^3 (2 cubed or 2 raised to power 3) means 2 X 2 X 2 ( 2 multiplied with itself 3 times which
is 8. The number that is being multiplied repeatedly is called the base or root or radical where as
the number of \'times\' it is multiplied is known as the index or power or exponent.
Difference between a Fraction and a Decimal.
A Decimal is also a fraction with the denominator being either 10 or the exponents of 10. A
fraction on the other hand denotes simply a part of the whole. Decimal fractions is a logical
development of the base 10 place value.
Examples of Fractions - 1/2 (half), 2/3 (two thirds) etc
Decimal Fractions - 0.2 = 2/10, 0.05 = 5/100 etc.
Answer The brains straight (which is also called tentorial sinus.pdf
Answer : The brain\'s straight (which is also called tentorial sinus) sinus permits immediate CSF
drainage from the INFERIOR SAGITTAL SINUS.
Solution
Answer : The brain\'s straight (which is also called tentorial sinus) sinus permits immediate CSF
drainage from the INFERIOR SAGITTAL SINUS..
Microsoft accquiring NokiaMicrosoft had goodwill impairement loss.pdf
Microsoft accquiring Nokia:
Microsoft had goodwill impairement loss of 5.5 Billion Dollars in 2014.
Stakeholders react negatively to impairement as it reuces your net profits.
Acquisition cost is directly proportional to goodwill impairement charges.
Solution
Microsoft accquiring Nokia:
Microsoft had goodwill impairement loss of 5.5 Billion Dollars in 2014.
Stakeholders react negatively to impairement as it reuces your net profits.
Acquisition cost is directly proportional to goodwill impairement charges..
J 1. Accrual BasisA system of accounting in which revenu.pdf
J 1. Accrual Basis
A system of accounting in which revenues are recognized when earned and expenses are
recognized when incurred.
H 2. Cost Principle
Assets are recorded at the cost to acquire them.
E 3. Credit
An entry on the right side of an account.
D 4. Debit
An entry on the left side of an account.
A 5. Generally Accepted Accounting Principles (GAAP)
The various methods, rules, practices, and other procedures that have evolved over time in
response to the need to regulate the preparation of financial statements.
C 6. General Ledger
A book, file, hard drive, or other devices containing all of a company’s accounts.
F 7. Journal
A chronological record of transactions, also known as the book of original entry.
I 8. Liquidity
The ability of a company to pay the debts as they come due.
G 9. Matching Principle
The association of revenue of a period with all of the costs necessary to generate that revenue.
B 10. Materiality
The magnitude of an omission or misstatement in accounting information that will affect the
judgment of someone relying on the information.
Solution
J 1. Accrual Basis
A system of accounting in which revenues are recognized when earned and expenses are
recognized when incurred.
H 2. Cost Principle
Assets are recorded at the cost to acquire them.
E 3. Credit
An entry on the right side of an account.
D 4. Debit
An entry on the left side of an account.
A 5. Generally Accepted Accounting Principles (GAAP)
The various methods, rules, practices, and other procedures that have evolved over time in
response to the need to regulate the preparation of financial statements.
C 6. General Ledger
A book, file, hard drive, or other devices containing all of a company’s accounts.
F 7. Journal
A chronological record of transactions, also known as the book of original entry.
I 8. Liquidity
The ability of a company to pay the debts as they come due.
G 9. Matching Principle
The association of revenue of a period with all of the costs necessary to generate that revenue.
B 10. Materiality
The magnitude of an omission or misstatement in accounting information that will affect the
judgment of someone relying on the information..
(a). (i) NH4Cl + H2O == NH4 OH + HClSince in water it produces str.pdf
(a). (i) NH4Cl + H2O == NH4 OH + HCl
Since in water it produces strong acid HCl which willdissociates completely to produce H+
ions.So, it is acidic innature
(ii) ZnSO4 + 2H2O == Zn(OH)2 + H2 SO4
Since in water it produces strong acid H2SO4 which willdissociates completely to produce H+
ions.So, it is acidic innature
(iii)Na2CO3 + 2H2O == 2NaOH + H2CO3
Since in water it produces strong base NaOH which willdissociates completely to produce OH-
ions.So, it is basic innature
(b). Concentration C = 0.10 M
pH = 11.5
Solution
(a). (i) NH4Cl + H2O == NH4 OH + HCl
Since in water it produces strong acid HCl which willdissociates completely to produce H+
ions.So, it is acidic innature
(ii) ZnSO4 + 2H2O == Zn(OH)2 + H2 SO4
Since in water it produces strong acid H2SO4 which willdissociates completely to produce H+
ions.So, it is acidic innature
(iii)Na2CO3 + 2H2O == 2NaOH + H2CO3
Since in water it produces strong base NaOH which willdissociates completely to produce OH-
ions.So, it is basic innature
(b). Concentration C = 0.10 M
pH = 11.5.
The elements in period 6 are those starting with Cs and going acr.pdf
The elements in period 6 are those starting with Cs and going across. Given that the metal reacts
vigorously with water, it must be either from groups 1 or 2 (alkali metals and alkali earth
metals). If you\'ve seen the reaction (or heard about it) between sodium and water (hydrogen is
produced rapidly and enough heat is given off that it explodes!), you\'ve seen this sort of
reaction.
Since the salt has 2 OH groups, it must form a stable +2 ion. This means it comes from group 2.
If the compound was MOH, then it would have been from group 1.
Now that we know it is in the 6th period (row) and 2nd group (column), we can identify the
element as barium (Ba). Also, we know that its outermost electrons occupy the 6s orbital
(because it is in the 6th period), so we can fill up orbitals now:
Ba: 1s2, 2s2, 2p6, 3s2, 3p6, 4s2, 3d10, 4p6, 5s2, 4d10, 5p6, 6s2.
The ordering is slightly different because higher values of n lead to d orbitals of very high
energy, thus, for example, it is preferred to fill the 4s orbital before the 3 d orbital, and the 5p and
6s before considering the 4 f orbitals.
The reaction that occurs is:
Ba(s) + 2H2O(l) -------> Ba(OH)2(aq) + H2(g)
Solution
The elements in period 6 are those starting with Cs and going across. Given that the metal reacts
vigorously with water, it must be either from groups 1 or 2 (alkali metals and alkali earth
metals). If you\'ve seen the reaction (or heard about it) between sodium and water (hydrogen is
produced rapidly and enough heat is given off that it explodes!), you\'ve seen this sort of
reaction.
Since the salt has 2 OH groups, it must form a stable +2 ion. This means it comes from group 2.
If the compound was MOH, then it would have been from group 1.
Now that we know it is in the 6th period (row) and 2nd group (column), we can identify the
element as barium (Ba). Also, we know that its outermost electrons occupy the 6s orbital
(because it is in the 6th period), so we can fill up orbitals now:
Ba: 1s2, 2s2, 2p6, 3s2, 3p6, 4s2, 3d10, 4p6, 5s2, 4d10, 5p6, 6s2.
The ordering is slightly different because higher values of n lead to d orbitals of very high
energy, thus, for example, it is preferred to fill the 4s orbital before the 3 d orbital, and the 5p and
6s before considering the 4 f orbitals.
The reaction that occurs is:
Ba(s) + 2H2O(l) -------> Ba(OH)2(aq) + H2(g).
You can find the confidence interval (CI) for a population prop.pdf
You can find the confidence interval (CI) for a population proportion to show the statistical
probability that a characteristic is likely to occur within the population.
When a characteristic being measured is categorical
Solution
You can find the confidence interval (CI) for a population proportion to show the statistical
probability that a characteristic is likely to occur within the population.
When a characteristic being measured is categorical.
Step1 pH change during the addition of 0.1 mol o.pdf
Step:1 pH change during the addition of 0.1 mol of Hcl to the 0.1 M NaH2PO4 In
aqueous solutions - H2PO4^- (aq) + H3O^+ (l) <--------> H3PO4 (aq) + H2O (l) 0.1 0.1 0 - 0.1 -
0.1 +0.1 0 0 0.1 Hence we get completely acidic solution finally - H3PO4 (aq) + H2O (l) ---------
> H3O^+ (aQ) + H2PO4^- (aQ) I(M) 0.1 0 0 C -x +x +x Eq 0.1-x x x Ka1 = 7.3*10^-5 =
[H3O^+][H2PO4^-] / [H3PO4] = x^2 / (0.1-x) by solving , we get - x = 0.00266 M Thus pH =-
log[H^+] = - log (0.00266) = 2.57 step:2 When we add base to the solution - the reaction occurs
as H2PO4^- (aq) + OH^- (aq) <-----> HPO4^-2 (aq) + H2O (l) but here H2PO4^- is completely
reacted and forms its conjugate base Hence- HPO4^-2 (aq) + H2O (l) <-----> H3O^+ (aq) +
PO4^-3 (aq) I(M) 0.1 0 0 0 C - x +x +x Eq 0.1-x x x Kb = Kw/Ka3 = 10^-14 /(4.8*10^-13) =
x^2 /(0.1-x) by solving - we get - x = 0.0363 Therefore [OH^-] = 0.0363 M Thus pOH = -
log[OH^-] = - log (0.0363) = 1.44 pH = 14 -1.44 = 12.55
Solution
Step:1 pH change during the addition of 0.1 mol of Hcl to the 0.1 M NaH2PO4 In
aqueous solutions - H2PO4^- (aq) + H3O^+ (l) <--------> H3PO4 (aq) + H2O (l) 0.1 0.1 0 - 0.1 -
0.1 +0.1 0 0 0.1 Hence we get completely acidic solution finally - H3PO4 (aq) + H2O (l) ---------
> H3O^+ (aQ) + H2PO4^- (aQ) I(M) 0.1 0 0 C -x +x +x Eq 0.1-x x x Ka1 = 7.3*10^-5 =
[H3O^+][H2PO4^-] / [H3PO4] = x^2 / (0.1-x) by solving , we get - x = 0.00266 M Thus pH =-
log[H^+] = - log (0.00266) = 2.57 step:2 When we add base to the solution - the reaction occurs
as H2PO4^- (aq) + OH^- (aq) <-----> HPO4^-2 (aq) + H2O (l) but here H2PO4^- is completely
reacted and forms its conjugate base Hence- HPO4^-2 (aq) + H2O (l) <-----> H3O^+ (aq) +
PO4^-3 (aq) I(M) 0.1 0 0 0 C - x +x +x Eq 0.1-x x x Kb = Kw/Ka3 = 10^-14 /(4.8*10^-13) =
x^2 /(0.1-x) by solving - we get - x = 0.0363 Therefore [OH^-] = 0.0363 M Thus pOH = -
log[OH^-] = - log (0.0363) = 1.44 pH = 14 -1.44 = 12.55.
SF4 is most likely to be a covalent compound beca.pdf
SF4 is most likely to be a covalent compound because the electronegativity
difference between S and F is not large enough to form a ionic bond.
Solution
SF4 is most likely to be a covalent compound because the electronegativity
difference between S and F is not large enough to form a ionic bond..
please post the clear qsn..... i ll help u in ans.pdf
please post the clear qsn..... i ll help u in answering..... thank u...
Solution
please post the clear qsn..... i ll help u in answering..... thank u....
linear shape non- polar since there are 2 simila.pdf
linear shape non- polar since there are 2 similar Carbon - Oxygen double bonds
Soluble in water CO2 + H20 = H2CO3
Solution
linear shape non- polar since there are 2 similar Carbon - Oxygen double bonds
Soluble in water CO2 + H20 = H2CO3.
B. Transcription of the viral genome for future translation (correct.pdf
B. Transcription of the viral genome for future translation (correct answer).
Explanation: Hepatitis B virus (HBV) is a good example of dsDNA virus having gaps. It
replicates via reverse transcription using a RNA intermediate. First of all, the virus enters
nucleus of the host cell. In the nucleus, the gapped genome is filled with ccc DNA. This serves
as template for production of host mRNA and sub-genomic RNA (transcription).
This RNA further converts into DNA by the enzyme reverse transcriptase.
Solution
B. Transcription of the viral genome for future translation (correct answer).
Explanation: Hepatitis B virus (HBV) is a good example of dsDNA virus having gaps. It
replicates via reverse transcription using a RNA intermediate. First of all, the virus enters
nucleus of the host cell. In the nucleus, the gapped genome is filled with ccc DNA. This serves
as template for production of host mRNA and sub-genomic RNA (transcription).
This RNA further converts into DNA by the enzyme reverse transcriptase..
e) HBr is a weak electrolyte. .pdf
e) HBr is a weak electrolyte.
Solution
e) HBr is a weak electrolyte..
C. An endothermic reaction is always nonspontaneo.pdf
C. An endothermic reaction is always nonspontaneous.
Solution
C. An endothermic reaction is always nonspontaneous..
can you upload another pic, it is visible .pdf
can you upload another pic, it is visible
Solution
can you upload another pic, it is visible.
Future Value= Present value(1+interest Rate per year)10But the fut.pdf
Future Value= Present value(1+interest Rate per year)10
But the future value we have to take for 6 years so 10 years-6 years= 4 years
$20000=PV(1.1)(10-6)
PV= $20000/1.4641= $13660 Ans
Solution
Future Value= Present value(1+interest Rate per year)10
But the future value we have to take for 6 years so 10 years-6 years= 4 years
$20000=PV(1.1)(10-6)
PV= $20000/1.4641= $13660 Ans.
a) the system into the surroundings c) is endothe.pdf
a) the system into the surroundings c) is endothemic C) Heat is a product of the
reaction
Solution
a) the system into the surroundings c) is endothemic C) Heat is a product of the
reaction.
Code Division Multiple Access (CDMA) could be a digital cellular tec.pdf
Code Division Multiple Access (CDMA) could be a digital cellular technology used for mobile
communication. CDMA is that the base on that access strategies like cdmaOne, CDMA-2000,
and WCDMA area unit designed. CDMA cellular systems area unit deemed superior to FDMA
and TDMA, that is why CDMA plays a essential role in building economical, robust, and secure
radio communication systems.
A Simple Analogy
Let’s take an easy analogy to grasp the thought of CDMA. Assume we\'ve a couple of students
gathered in a very room WHO would really like to speak to every alternative at the same time.
Nothing would be sonic if everybody starts speaking at constant time. Either they need to
alternate to talk or use totally different languages to speak.
The second choice is kind of just like CDMA students speaking constant language will perceive
one another, whereas alternative languages area unit perceived as noise and rejected. Similarly,
in radio CDMA, every cluster of users is given a shared code. several codes occupy constant
channel, however solely those users related to a selected code will communicate.
Salient options of CDMA
CDMA, that is predicated on the unfold spectrum technique has following salient options
In CDMA, each channel uses the total accessible spectrum.
Individual conversations area unit encoded with a pseudo-random digital sequence so transmitted
employing a wide frequency vary.
CDMA systematically provides higher capability for voice and knowledge communications,
permitting a lot of subscribers to attach at any given time.
CDMA is that the common platform on that 3G technologies area unit designed. For 3G, CDMA
uses 1x EV-DO and EV-DV.
Third Generation Standards
CDMA2000 uses Frequency Division Duplexing-Multicarrier (FDD-MC) mode. Here,
multicarrier implies N × one.25 Mc channels overlaid on N existing IS-95 carriers or deployed
on unoccupied spectrum. CDMA2000 includes
1x — uses a spreading rate of one.2288 Mcps.
3x — uses a spreading rate of three × one.2288 Mcps or three.6864 Mcps.
1xEV-DO (1x Evolution – knowledge Optimized) — uses a spreading rate of one.2288 Mcps,
optimized for the info.
WCDMA/FDD-DS — band CDMA (WCDMA) Frequency Division Duplexing-Direct Sequence
spreading (FDD-DS) mode. This encompasses a single five Mc channel. WCDMA uses one
carrier per channel and employs a spreading rate of three.84 Mcps.
CDMA Development cluster (CDG)
The CDMA Development cluster (CDG), supported in Dec 1993, is a world pool of firms. It
works along to steer the expansion and evolution of advanced wireless telecommunication
systems.
CDG is comprised of service suppliers, infrastructure makers, device vendors, equipment
vendors, application developers, and content suppliers. Its members put together outline the
technical needs for the event of complementary systems CDMA2000 and 4G. Further, the ability
with alternative rising wireless technologies area unit meant to extend the provision of wireless
merchandise and services to customers and .
can you provide a pictureSolutioncan you provide a picture.pdf
can you provide a picture?
Solution
can you provide a picture?.
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(a). (i) NH4Cl + H2O == NH4 OH + HClSince in water it produces str.pdf
(a). (i) NH4Cl + H2O == NH4 OH + HCl
Since in water it produces strong acid HCl which willdissociates completely to produce H+
ions.So, it is acidic innature
(ii) ZnSO4 + 2H2O == Zn(OH)2 + H2 SO4
Since in water it produces strong acid H2SO4 which willdissociates completely to produce H+
ions.So, it is acidic innature
(iii)Na2CO3 + 2H2O == 2NaOH + H2CO3
Since in water it produces strong base NaOH which willdissociates completely to produce OH-
ions.So, it is basic innature
(b). Concentration C = 0.10 M
pH = 11.5
Solution
(a). (i) NH4Cl + H2O == NH4 OH + HCl
Since in water it produces strong acid HCl which willdissociates completely to produce H+
ions.So, it is acidic innature
(ii) ZnSO4 + 2H2O == Zn(OH)2 + H2 SO4
Since in water it produces strong acid H2SO4 which willdissociates completely to produce H+
ions.So, it is acidic innature
(iii)Na2CO3 + 2H2O == 2NaOH + H2CO3
Since in water it produces strong base NaOH which willdissociates completely to produce OH-
ions.So, it is basic innature
(b). Concentration C = 0.10 M
pH = 11.5.
The elements in period 6 are those starting with Cs and going acr.pdf
The elements in period 6 are those starting with Cs and going across. Given that the metal reacts
vigorously with water, it must be either from groups 1 or 2 (alkali metals and alkali earth
metals). If you\'ve seen the reaction (or heard about it) between sodium and water (hydrogen is
produced rapidly and enough heat is given off that it explodes!), you\'ve seen this sort of
reaction.
Since the salt has 2 OH groups, it must form a stable +2 ion. This means it comes from group 2.
If the compound was MOH, then it would have been from group 1.
Now that we know it is in the 6th period (row) and 2nd group (column), we can identify the
element as barium (Ba). Also, we know that its outermost electrons occupy the 6s orbital
(because it is in the 6th period), so we can fill up orbitals now:
Ba: 1s2, 2s2, 2p6, 3s2, 3p6, 4s2, 3d10, 4p6, 5s2, 4d10, 5p6, 6s2.
The ordering is slightly different because higher values of n lead to d orbitals of very high
energy, thus, for example, it is preferred to fill the 4s orbital before the 3 d orbital, and the 5p and
6s before considering the 4 f orbitals.
The reaction that occurs is:
Ba(s) + 2H2O(l) -------> Ba(OH)2(aq) + H2(g)
Solution
The elements in period 6 are those starting with Cs and going across. Given that the metal reacts
vigorously with water, it must be either from groups 1 or 2 (alkali metals and alkali earth
metals). If you\'ve seen the reaction (or heard about it) between sodium and water (hydrogen is
produced rapidly and enough heat is given off that it explodes!), you\'ve seen this sort of
reaction.
Since the salt has 2 OH groups, it must form a stable +2 ion. This means it comes from group 2.
If the compound was MOH, then it would have been from group 1.
Now that we know it is in the 6th period (row) and 2nd group (column), we can identify the
element as barium (Ba). Also, we know that its outermost electrons occupy the 6s orbital
(because it is in the 6th period), so we can fill up orbitals now:
Ba: 1s2, 2s2, 2p6, 3s2, 3p6, 4s2, 3d10, 4p6, 5s2, 4d10, 5p6, 6s2.
The ordering is slightly different because higher values of n lead to d orbitals of very high
energy, thus, for example, it is preferred to fill the 4s orbital before the 3 d orbital, and the 5p and
6s before considering the 4 f orbitals.
The reaction that occurs is:
Ba(s) + 2H2O(l) -------> Ba(OH)2(aq) + H2(g).
You can find the confidence interval (CI) for a population prop.pdf
You can find the confidence interval (CI) for a population proportion to show the statistical
probability that a characteristic is likely to occur within the population.
When a characteristic being measured is categorical
Solution
You can find the confidence interval (CI) for a population proportion to show the statistical
probability that a characteristic is likely to occur within the population.
When a characteristic being measured is categorical.
Step1 pH change during the addition of 0.1 mol o.pdf
Step:1 pH change during the addition of 0.1 mol of Hcl to the 0.1 M NaH2PO4 In
aqueous solutions - H2PO4^- (aq) + H3O^+ (l) <--------> H3PO4 (aq) + H2O (l) 0.1 0.1 0 - 0.1 -
0.1 +0.1 0 0 0.1 Hence we get completely acidic solution finally - H3PO4 (aq) + H2O (l) ---------
> H3O^+ (aQ) + H2PO4^- (aQ) I(M) 0.1 0 0 C -x +x +x Eq 0.1-x x x Ka1 = 7.3*10^-5 =
[H3O^+][H2PO4^-] / [H3PO4] = x^2 / (0.1-x) by solving , we get - x = 0.00266 M Thus pH =-
log[H^+] = - log (0.00266) = 2.57 step:2 When we add base to the solution - the reaction occurs
as H2PO4^- (aq) + OH^- (aq) <-----> HPO4^-2 (aq) + H2O (l) but here H2PO4^- is completely
reacted and forms its conjugate base Hence- HPO4^-2 (aq) + H2O (l) <-----> H3O^+ (aq) +
PO4^-3 (aq) I(M) 0.1 0 0 0 C - x +x +x Eq 0.1-x x x Kb = Kw/Ka3 = 10^-14 /(4.8*10^-13) =
x^2 /(0.1-x) by solving - we get - x = 0.0363 Therefore [OH^-] = 0.0363 M Thus pOH = -
log[OH^-] = - log (0.0363) = 1.44 pH = 14 -1.44 = 12.55
Solution
Step:1 pH change during the addition of 0.1 mol of Hcl to the 0.1 M NaH2PO4 In
aqueous solutions - H2PO4^- (aq) + H3O^+ (l) <--------> H3PO4 (aq) + H2O (l) 0.1 0.1 0 - 0.1 -
0.1 +0.1 0 0 0.1 Hence we get completely acidic solution finally - H3PO4 (aq) + H2O (l) ---------
> H3O^+ (aQ) + H2PO4^- (aQ) I(M) 0.1 0 0 C -x +x +x Eq 0.1-x x x Ka1 = 7.3*10^-5 =
[H3O^+][H2PO4^-] / [H3PO4] = x^2 / (0.1-x) by solving , we get - x = 0.00266 M Thus pH =-
log[H^+] = - log (0.00266) = 2.57 step:2 When we add base to the solution - the reaction occurs
as H2PO4^- (aq) + OH^- (aq) <-----> HPO4^-2 (aq) + H2O (l) but here H2PO4^- is completely
reacted and forms its conjugate base Hence- HPO4^-2 (aq) + H2O (l) <-----> H3O^+ (aq) +
PO4^-3 (aq) I(M) 0.1 0 0 0 C - x +x +x Eq 0.1-x x x Kb = Kw/Ka3 = 10^-14 /(4.8*10^-13) =
x^2 /(0.1-x) by solving - we get - x = 0.0363 Therefore [OH^-] = 0.0363 M Thus pOH = -
log[OH^-] = - log (0.0363) = 1.44 pH = 14 -1.44 = 12.55.
SF4 is most likely to be a covalent compound beca.pdf
SF4 is most likely to be a covalent compound because the electronegativity
difference between S and F is not large enough to form a ionic bond.
Solution
SF4 is most likely to be a covalent compound because the electronegativity
difference between S and F is not large enough to form a ionic bond..
please post the clear qsn..... i ll help u in ans.pdf
please post the clear qsn..... i ll help u in answering..... thank u...
Solution
please post the clear qsn..... i ll help u in answering..... thank u....
linear shape non- polar since there are 2 simila.pdf
linear shape non- polar since there are 2 similar Carbon - Oxygen double bonds
Soluble in water CO2 + H20 = H2CO3
Solution
linear shape non- polar since there are 2 similar Carbon - Oxygen double bonds
Soluble in water CO2 + H20 = H2CO3.
B. Transcription of the viral genome for future translation (correct.pdf
B. Transcription of the viral genome for future translation (correct answer).
Explanation: Hepatitis B virus (HBV) is a good example of dsDNA virus having gaps. It
replicates via reverse transcription using a RNA intermediate. First of all, the virus enters
nucleus of the host cell. In the nucleus, the gapped genome is filled with ccc DNA. This serves
as template for production of host mRNA and sub-genomic RNA (transcription).
This RNA further converts into DNA by the enzyme reverse transcriptase.
Solution
B. Transcription of the viral genome for future translation (correct answer).
Explanation: Hepatitis B virus (HBV) is a good example of dsDNA virus having gaps. It
replicates via reverse transcription using a RNA intermediate. First of all, the virus enters
nucleus of the host cell. In the nucleus, the gapped genome is filled with ccc DNA. This serves
as template for production of host mRNA and sub-genomic RNA (transcription).
This RNA further converts into DNA by the enzyme reverse transcriptase..
e) HBr is a weak electrolyte. .pdf
e) HBr is a weak electrolyte.
Solution
e) HBr is a weak electrolyte..
C. An endothermic reaction is always nonspontaneo.pdf
C. An endothermic reaction is always nonspontaneous.
Solution
C. An endothermic reaction is always nonspontaneous..
can you upload another pic, it is visible .pdf
can you upload another pic, it is visible
Solution
can you upload another pic, it is visible.
Future Value= Present value(1+interest Rate per year)10But the fut.pdf
Future Value= Present value(1+interest Rate per year)10
But the future value we have to take for 6 years so 10 years-6 years= 4 years
$20000=PV(1.1)(10-6)
PV= $20000/1.4641= $13660 Ans
Solution
Future Value= Present value(1+interest Rate per year)10
But the future value we have to take for 6 years so 10 years-6 years= 4 years
$20000=PV(1.1)(10-6)
PV= $20000/1.4641= $13660 Ans.
a) the system into the surroundings c) is endothe.pdf
a) the system into the surroundings c) is endothemic C) Heat is a product of the
reaction
Solution
a) the system into the surroundings c) is endothemic C) Heat is a product of the
reaction.
Code Division Multiple Access (CDMA) could be a digital cellular tec.pdf
Code Division Multiple Access (CDMA) could be a digital cellular technology used for mobile
communication. CDMA is that the base on that access strategies like cdmaOne, CDMA-2000,
and WCDMA area unit designed. CDMA cellular systems area unit deemed superior to FDMA
and TDMA, that is why CDMA plays a essential role in building economical, robust, and secure
radio communication systems.
A Simple Analogy
Let’s take an easy analogy to grasp the thought of CDMA. Assume we\'ve a couple of students
gathered in a very room WHO would really like to speak to every alternative at the same time.
Nothing would be sonic if everybody starts speaking at constant time. Either they need to
alternate to talk or use totally different languages to speak.
The second choice is kind of just like CDMA students speaking constant language will perceive
one another, whereas alternative languages area unit perceived as noise and rejected. Similarly,
in radio CDMA, every cluster of users is given a shared code. several codes occupy constant
channel, however solely those users related to a selected code will communicate.
Salient options of CDMA
CDMA, that is predicated on the unfold spectrum technique has following salient options
In CDMA, each channel uses the total accessible spectrum.
Individual conversations area unit encoded with a pseudo-random digital sequence so transmitted
employing a wide frequency vary.
CDMA systematically provides higher capability for voice and knowledge communications,
permitting a lot of subscribers to attach at any given time.
CDMA is that the common platform on that 3G technologies area unit designed. For 3G, CDMA
uses 1x EV-DO and EV-DV.
Third Generation Standards
CDMA2000 uses Frequency Division Duplexing-Multicarrier (FDD-MC) mode. Here,
multicarrier implies N × one.25 Mc channels overlaid on N existing IS-95 carriers or deployed
on unoccupied spectrum. CDMA2000 includes
1x — uses a spreading rate of one.2288 Mcps.
3x — uses a spreading rate of three × one.2288 Mcps or three.6864 Mcps.
1xEV-DO (1x Evolution – knowledge Optimized) — uses a spreading rate of one.2288 Mcps,
optimized for the info.
WCDMA/FDD-DS — band CDMA (WCDMA) Frequency Division Duplexing-Direct Sequence
spreading (FDD-DS) mode. This encompasses a single five Mc channel. WCDMA uses one
carrier per channel and employs a spreading rate of three.84 Mcps.
CDMA Development cluster (CDG)
The CDMA Development cluster (CDG), supported in Dec 1993, is a world pool of firms. It
works along to steer the expansion and evolution of advanced wireless telecommunication
systems.
CDG is comprised of service suppliers, infrastructure makers, device vendors, equipment
vendors, application developers, and content suppliers. Its members put together outline the
technical needs for the event of complementary systems CDMA2000 and 4G. Further, the ability
with alternative rising wireless technologies area unit meant to extend the provision of wireless
merchandise and services to customers and .
can you provide a pictureSolutioncan you provide a picture.pdf
can you provide a picture?
Solution
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(a). (i) NH4Cl + H2O == NH4 OH + HClSince in water it produces str.pdf
(a). (i) NH4Cl + H2O == NH4 OH + HClSince in water it produces str.pdf
The elements in period 6 are those starting with Cs and going acr.pdf
The elements in period 6 are those starting with Cs and going acr.pdf
You can find the confidence interval (CI) for a population prop.pdf
You can find the confidence interval (CI) for a population prop.pdf
Step1 pH change during the addition of 0.1 mol o.pdf
Step1 pH change during the addition of 0.1 mol o.pdf
SF4 is most likely to be a covalent compound beca.pdf
SF4 is most likely to be a covalent compound beca.pdf
please post the clear qsn..... i ll help u in ans.pdf
please post the clear qsn..... i ll help u in ans.pdf
linear shape non- polar since there are 2 simila.pdf
linear shape non- polar since there are 2 simila.pdf
B. Transcription of the viral genome for future translation (correct.pdf
B. Transcription of the viral genome for future translation (correct.pdf
C. An endothermic reaction is always nonspontaneo.pdf
C. An endothermic reaction is always nonspontaneo.pdf
Future Value= Present value(1+interest Rate per year)10But the fut.pdf
Future Value= Present value(1+interest Rate per year)10But the fut.pdf
a) the system into the surroundings c) is endothe.pdf
a) the system into the surroundings c) is endothe.pdf
Code Division Multiple Access (CDMA) could be a digital cellular tec.pdf
Code Division Multiple Access (CDMA) could be a digital cellular tec.pdf
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