“БІЛІМ-Инновация”
Халықаралық қоғамдық қоры
PHYSICS CHAPTER 5.8
4-term Week 2-3 2019-2020
Buoyant force
Textbook page
82
CHAPTER 5.8 Buoyant force
PHYSICS 4-term Week 2-3 2019-2020 2
You will be able to:
• 7.3.1.12 – to explain the nature of buoyant forces in liquids and
gases;
• 7.3.1.13 – to apply Archimedes' principle in solving problems
PHYSICS 4-term Week 2-3 2019-2020 3
TERMS:
• UPTHRUST
• BUOYANCY
• DENSITY
• FLOAT
• SINK
• MERCURY
• IMMERSE
- жоғары итеру / выталкивающая сила
- жүзгіштік / плавучесть
- тығыздық / плотность
- сұйықтықтың бетінде қалу / плавать на
поверхности жидкости
- бату/ тонуть
- сынап / ртуть
- батыру / погрузить
CHAPTER 5.8 Buoyant force
PHYSICS 4-term Week 2-3 2019-2020 4
CHAPTER 5.8 Buoyant force
PHYSICS 4-term Week 2-3 2019-2020 5
CHAPTER 5.8 Buoyant force
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CHAPTER 5.8 Buoyant force
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CHAPTER 5.8 Buoyant force
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CHAPTER 5.8 Buoyant force
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CHAPTER 5.8 Buoyant force
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CHAPTER 5.8 Buoyant force
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CHAPTER 5.8 Buoyant force
Archimedes' Principle
PHYSICS 4-term Week 2-3 2019-2020 12
CHAPTER 5.8 Buoyant force
PHYSICS 4-term Week 2-3 2019-2020 13
CHAPTER 5.8 Buoyant force
From Archimedes’s Principle :
Buoyant Force = Weight of fluid displaced
= mg
= ρVg (note : ρ = m )
V
Thus FB = ρ g V
Where ……
FB = Buoyant Force or Upthrust (N, Newtons)
ρ = Density of fluid (kg/m3)
V = Volume of fluid displaced or (m3)
the volume of the object that immersed in the fluid.
PHYSICS 4-term Week 2-3 2019-2020 14
CHAPTER 5.8 Buoyant force
At what depth is the buoyant
force acting on the brick at its
greatest?
PHYSICS 4-term Week 2-3 2019-2020 15
CHAPTER 5.8 Buoyant force
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CHAPTER 5.8 Buoyant force
Floating objects
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CHAPTER 5.8 Buoyant force
lighter object heavier object too heavy
The weight of displaced
water is less than the
weight of the object
PHYSICS 4-term Week 2-3 2019-2020 18
CHAPTER 5.8 Buoyant force
PHYSICS 4-term Week 2-3 2019-2020 19
CHAPTER 5.8 Buoyant force
Hot air balloon
1. rises upwards
(Upthrust > Weight of hot air (helium gas) + weight of airship fabric
+ weight of gondola + weight of passengers.)( balloon expand)
2..descends
(Upthrust < Weight of hot air (helium gas) + weight of airship
fabric + weight of gondola + weight of passengers.)(balloon shrinks)
3. stationary
(Upthrust = Weight of hot air (helium gas) + weight of airship fabric
+ weight of gondola + weight of passengers.)( balloon size uncanged)
Buoyant force and Floatation in gases
PHYSICS 4-term Week 2-3 2019-2020 20
CHAPTER 5.8 Buoyant force
Buoyant force = weight ⇒ the object floats and stationary
Buoyant force > weight ⇒ the object moves up
Buoyant force < weight ⇒ the object moves down
Buoyant force and Floatation in liquids
PHYSICS 4-term Week 2-3 2019-2020 21
CHAPTER 5.8 Buoyant force
PHYSICS 4-term Week 2-3 2019-2020 22
CHAPTER 5.8 Buoyant force
Given:
Dimensions of change of the displaced water: a=2 m, b=3 m, c=0,12 m
Density of water = 1000 kg/m
The barge with horse floats
Find the weight of horse?
3
PHYSICS 4-term Week 2-3 2019-2020 23
CHAPTER 5.8 Buoyant force
Solution :
Weight of horse = Buoyant force
Given:
Dimensions of change of the displaced water: a=2 m, b=3 m, c=0,12 m
Density of water = 1000 kg/m
The barge with horse floats
Find the weight of horse?
3
PHYSICS 4-term Week 2-3 2019-2020 24
CHAPTER 5.8 Buoyant force
Solution :
Weight of horse = Buoyant force
Weight of horse = ρ g V = ρ g (abc)=1000*10*(2*3*0,12)=7200 N
Given:
Dimensions of change of the displaced water: a=2 m, b=3 m, c=0,12 m
Density of water = 1000 kg/m
The barge with horse floats
Find the weight of horse?
3
PHYSICS 4-term Week 2-3 2019-2020 25
CHAPTER 5.8 Buoyant force
Solution :
Weight of horse = Buoyant force
Weight of horse = ρ g V = ρ g (abc)=1000*10*(2*3*0,12)=7200 N
Result: Weight of horse = 7200 N or 720 kg
Given:
Dimensions of change of the displaced water: a=2 m, b=3 m, c=0,12 m
Density of water = 1000 kg/m
The barge with horse floats
Find the weight of horse?
3
PHYSICS 4-term Week 2-3 2019-2020 26
CHAPTER 5.8 Buoyant force
PHYSICS 4-term Week 2-3 2019-2020 27
CHAPTER 5.8 Buoyant force
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CHAPTER 5.8 Buoyant force
Plimsoll line of the ship
PHYSICS 4-term Week 2-3 2019-2020 29
CHAPTER 5.8 Buoyant force
Plimsoll line of the ship
PHYSICS 4-term Week 2-3 2019-2020
- Physics 7 grade, Астана кітап
- https://science.howstuffworks.com/transport/engines-
equipment/submarine1.htm
- https://en.wikipedia.org/wiki/Buoyancy
- https://www.bbc.co.uk/bitesize/guides/z9ykmsg/revision/4
Resources
CHAPTER 5.8 Buoyant force
Archimedes' principle.pptx

Archimedes' principle.pptx

  • 1.
    “БІЛІМ-Инновация” Халықаралық қоғамдық қоры PHYSICSCHAPTER 5.8 4-term Week 2-3 2019-2020 Buoyant force Textbook page 82
  • 2.
    CHAPTER 5.8 Buoyantforce PHYSICS 4-term Week 2-3 2019-2020 2 You will be able to: • 7.3.1.12 – to explain the nature of buoyant forces in liquids and gases; • 7.3.1.13 – to apply Archimedes' principle in solving problems
  • 3.
    PHYSICS 4-term Week2-3 2019-2020 3 TERMS: • UPTHRUST • BUOYANCY • DENSITY • FLOAT • SINK • MERCURY • IMMERSE - жоғары итеру / выталкивающая сила - жүзгіштік / плавучесть - тығыздық / плотность - сұйықтықтың бетінде қалу / плавать на поверхности жидкости - бату/ тонуть - сынап / ртуть - батыру / погрузить CHAPTER 5.8 Buoyant force
  • 4.
    PHYSICS 4-term Week2-3 2019-2020 4 CHAPTER 5.8 Buoyant force
  • 5.
    PHYSICS 4-term Week2-3 2019-2020 5 CHAPTER 5.8 Buoyant force
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    PHYSICS 4-term Week2-3 2019-2020 6 CHAPTER 5.8 Buoyant force
  • 7.
    PHYSICS 4-term Week2-3 2019-2020 7 CHAPTER 5.8 Buoyant force
  • 8.
    PHYSICS 4-term Week2-3 2019-2020 8 CHAPTER 5.8 Buoyant force
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    PHYSICS 4-term Week2-3 2019-2020 9 CHAPTER 5.8 Buoyant force
  • 10.
    PHYSICS 4-term Week2-3 2019-2020 10 CHAPTER 5.8 Buoyant force
  • 11.
    PHYSICS 4-term Week2-3 2019-2020 11 CHAPTER 5.8 Buoyant force Archimedes' Principle
  • 12.
    PHYSICS 4-term Week2-3 2019-2020 12 CHAPTER 5.8 Buoyant force
  • 13.
    PHYSICS 4-term Week2-3 2019-2020 13 CHAPTER 5.8 Buoyant force From Archimedes’s Principle : Buoyant Force = Weight of fluid displaced = mg = ρVg (note : ρ = m ) V Thus FB = ρ g V Where …… FB = Buoyant Force or Upthrust (N, Newtons) ρ = Density of fluid (kg/m3) V = Volume of fluid displaced or (m3) the volume of the object that immersed in the fluid.
  • 14.
    PHYSICS 4-term Week2-3 2019-2020 14 CHAPTER 5.8 Buoyant force At what depth is the buoyant force acting on the brick at its greatest?
  • 15.
    PHYSICS 4-term Week2-3 2019-2020 15 CHAPTER 5.8 Buoyant force
  • 16.
    PHYSICS 4-term Week2-3 2019-2020 16 CHAPTER 5.8 Buoyant force Floating objects
  • 17.
    PHYSICS 4-term Week2-3 2019-2020 17 CHAPTER 5.8 Buoyant force lighter object heavier object too heavy The weight of displaced water is less than the weight of the object
  • 18.
    PHYSICS 4-term Week2-3 2019-2020 18 CHAPTER 5.8 Buoyant force
  • 19.
    PHYSICS 4-term Week2-3 2019-2020 19 CHAPTER 5.8 Buoyant force Hot air balloon 1. rises upwards (Upthrust > Weight of hot air (helium gas) + weight of airship fabric + weight of gondola + weight of passengers.)( balloon expand) 2..descends (Upthrust < Weight of hot air (helium gas) + weight of airship fabric + weight of gondola + weight of passengers.)(balloon shrinks) 3. stationary (Upthrust = Weight of hot air (helium gas) + weight of airship fabric + weight of gondola + weight of passengers.)( balloon size uncanged) Buoyant force and Floatation in gases
  • 20.
    PHYSICS 4-term Week2-3 2019-2020 20 CHAPTER 5.8 Buoyant force Buoyant force = weight ⇒ the object floats and stationary Buoyant force > weight ⇒ the object moves up Buoyant force < weight ⇒ the object moves down Buoyant force and Floatation in liquids
  • 21.
    PHYSICS 4-term Week2-3 2019-2020 21 CHAPTER 5.8 Buoyant force
  • 22.
    PHYSICS 4-term Week2-3 2019-2020 22 CHAPTER 5.8 Buoyant force Given: Dimensions of change of the displaced water: a=2 m, b=3 m, c=0,12 m Density of water = 1000 kg/m The barge with horse floats Find the weight of horse? 3
  • 23.
    PHYSICS 4-term Week2-3 2019-2020 23 CHAPTER 5.8 Buoyant force Solution : Weight of horse = Buoyant force Given: Dimensions of change of the displaced water: a=2 m, b=3 m, c=0,12 m Density of water = 1000 kg/m The barge with horse floats Find the weight of horse? 3
  • 24.
    PHYSICS 4-term Week2-3 2019-2020 24 CHAPTER 5.8 Buoyant force Solution : Weight of horse = Buoyant force Weight of horse = ρ g V = ρ g (abc)=1000*10*(2*3*0,12)=7200 N Given: Dimensions of change of the displaced water: a=2 m, b=3 m, c=0,12 m Density of water = 1000 kg/m The barge with horse floats Find the weight of horse? 3
  • 25.
    PHYSICS 4-term Week2-3 2019-2020 25 CHAPTER 5.8 Buoyant force Solution : Weight of horse = Buoyant force Weight of horse = ρ g V = ρ g (abc)=1000*10*(2*3*0,12)=7200 N Result: Weight of horse = 7200 N or 720 kg Given: Dimensions of change of the displaced water: a=2 m, b=3 m, c=0,12 m Density of water = 1000 kg/m The barge with horse floats Find the weight of horse? 3
  • 26.
    PHYSICS 4-term Week2-3 2019-2020 26 CHAPTER 5.8 Buoyant force
  • 27.
    PHYSICS 4-term Week2-3 2019-2020 27 CHAPTER 5.8 Buoyant force
  • 28.
    PHYSICS 4-term Week2-3 2019-2020 28 CHAPTER 5.8 Buoyant force Plimsoll line of the ship
  • 29.
    PHYSICS 4-term Week2-3 2019-2020 29 CHAPTER 5.8 Buoyant force Plimsoll line of the ship
  • 30.
    PHYSICS 4-term Week2-3 2019-2020 - Physics 7 grade, Астана кітап - https://science.howstuffworks.com/transport/engines- equipment/submarine1.htm - https://en.wikipedia.org/wiki/Buoyancy - https://www.bbc.co.uk/bitesize/guides/z9ykmsg/revision/4 Resources CHAPTER 5.8 Buoyant force