1 | 4
Lesson Plan for Grade 7 Mathematics
I. TOPIC: Solving First Degree Equations in One Variable Algebraically
II. Learning Objectives
At the end of the lesson, the students must have:
a. solved first degree equations in one variable by algebraic procedure using the properties of equality.
III. Learning Contents
A. Mathematical Concepts
 Properties of Equality
B. References
Mirabona, I. (2013). Interactive mathematics 7. Manila: Innovative Educational Materials, Inc., pp.
154-158
C. Instructional Materials
Chalk, Blackboard, Manila Paper, Cartolina, Marker, Visual Aids
D. Value Foci
Accuracy, Cooperation, Objectivity, Perseverance
E. Strategies/Techniques
Discussion Method, Oral Questioning, Constructivism, Cooperative Learning
IV. Learning Activities
A. Preliminaries
Teacher’s Activity Students’ Activity
a. Prayer
May I request everyone to stand for a prayer?
Good morning class!
Please take your seat.
b. Checking of Attendance
(Stands up and pray)
Good morning Maám!
Thank you, Maám.
B. Developmental Activities
Teacher’s Activity Students’ Activity
a. Activity
Now, we are going to have an activity. Please
answer the following on your ½ sheet of pad paper
cut crosswise. Do this with a partner. I will give you
6 minutes to answer.
What is the value of 𝑥 in the following equations?
1. 𝑥 + 4 = 12
2. 7𝑥 = 28
3. 6𝑥 − 5 = 31
4. 5𝑥 − 7 = 𝑥 + 9
5. 3(2𝑥 − 4) = 42
a. How did you arrive at your answer?
b. Did you use the properties of equality to solve
for 𝑥? How?
2 | 4
c. Substitute the value of 𝑥 to check your answer.
Do the values of 𝑥 make the mathematical
sentences true?
Time’s up class! Please look at the board now.
b. Analysis
How was the activity?
Now, let’s start with item letter a. How did you
arrive at your answer?
Yes, ___.
Very good, ___.
Was it easy?
That’s it. Our lesson for today is about solving
first degree equations in one variable. This time,
we’ll solve it algebraically. That means we are
going to solve for the easy way of finding 𝑥 or
any unknown variable.
What about in item letter b?
Yes, ___.
Very good, ___. What about in item letter c?
Yes, ___.
Very good, ___.
Now, let’s have item number 1. What property
can we use to 𝑥 + 4 = 12 when we add a number
to both sides?
Very good. What should we add to both sides of
the equation to have 𝑥 only on one side?
Who wants to try adding it here?
Yes, ___.
Very good, ___. Now, what is the next step?
Yes, ___.
Very good, ___. Then we’ll use parenthesis to
group the like terms:
𝑥 + [4 + (−4)] = 12 + (−4).
What property did I use?
Very good. Now what is 4 + (−4)?
What property did we use?
What about 12 + (−4)?
Very good. what is 𝑥 + 0?
Challenging, Maám.
(Raising hands)
We used the trial and error method, Maám.
No, Maám. It’s time-consuming.
(Raising hands)
Yes, Maám. We studied the examples and how
the properties of equality are used.
(Raising hands)
Yes, Maám. We got them right.
Addition Property of Equality, Maám.
−4, Maám.
(Raising hands)
𝑥 + 4 + (−4) = 12 + (−4)
(Raising hands)
Combine like terms, Maám.
Associative property of addition, Maám.
0, Maám.
Additive inverse, Maám.
8, Maám.
𝑥, Maám.
Additive Identity, Maám.
3 | 4
What property did you use?
Very good. Now you have the value of 𝑥 which is
8. How would you know 8 is the really the value
of 𝑥?
Very good. How?
Very good again. Who wants to check the
answer?
Yes, ___.
Very good, ___. We also do it like this:
𝑥 + 4 = 12
8 + 4 = 12
12 = 12
Remember class, this is how we solve for the
value of 𝑥 algebraically. Can you follow?
Now, try solving for the value of 𝑥 algebraically
on the other items. I will give you 5 minutes.
Now, who wants to try solving the rest of the
items algebraically and explain here at the front?
Yes, ___, ___, ___ and ___.
Did you also get the correct answers?
Now, who wants to check them?
Yes, ___, ___, ___ and ___.
Very good class. Do you have any questions?
We’ll check the answer, Maám.
By substitution, Maám.
(Raising hands)
8 + 4 = 12
Yes, Maám.
(Raising hands)
7𝑥 = 28 Given
1
7
∙ 7𝑥 =
1
7
∙ 28 Mutliplication Property of Equality
(
1
7
∙ 7) 𝑥 = 4 Associative
Property(Multiplication)
1 ∙ 𝑥 = 4 Multiplicative Inverse
𝑥 = 4 Multiplicative Identity
6𝑥 − 5 = 31 Given
6𝑥 − 5 + 5 = 31 + 5 Addition Prop. of Equality
6𝑥 = 36 Simplify
6𝑥
6
=
36
6
Mult. Prop. of Equality
𝑥 = 6 Simplify
5𝑥 − 7 = 𝑥 + 9 Given
5𝑥 − 𝑥 − 7 + 7 = 𝑥 − 𝑥 + 9 + 7 A.P.E.
4𝑥 = 16
4𝑥
4
=
16
4
M.P.E.
𝑥 = 4
3(2𝑥 − 4) = 42 Given
6𝑥 − 12 = 42 D.P.M.A.
6𝑥 − 12 + 12 = 42 + 12 A.P.E.
6𝑥 = 54
6𝑥
6
=
54
6
M.P.E.
𝑥 = 9
Yes, Maám.
(Raising hands)
(Checks their answers correctly)
None, Maám.
C. Abstraction
Teacher’s Activity Students’ Activity
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How do we solve for the value of 𝑥 algebraically?
What do we use in solving?
Very good. how would you know that you solved
the correct value of 𝑥?
Very good again.
Questions?
Is our lesson easy?
Properties of equality, Maám.
By substituting the value of 𝑥 to the given
equation.
None, Maám.
Yes, Maám.
D. Application
Teacher’s Activity Students’ Activity
If none, let us have practice exercises I have
posted on the board. You can work with your
seatmates and discuss. I will give you 5 minutes.
Solve the following equations and check the
solutions.
1. 𝑥 − 8 = 47
2. 𝑥 − 42 = −115
3. 𝑚 + 1.8 = 17
4. 𝑛 − 3/8 = 11/20
5. 𝑥 + 42 = 12
Are you all done? Who can answer them on the
board?
Let’s have ___, ___, ___, ___, ___, ___ and ___.
Are their answers correct? Did you also get the
correct answers?
Very good. Now are you ready for a quiz?
Please get a whole sheet of pad paper.
1. 𝑥 = 55
2. 𝑥 = −73
3. 𝑥 = 15.2
4. 𝑥 = 37/40
5. 𝑥 = −30
(Raising hands)
Yes, Maám.
Yes, Maám.
E. Evaluation
Solve for the value of each variable in set of real numbers.
1. 5𝑦 = 85
2. −9𝑥 = 333
3. 1.2𝑑 = −18
4. 1.5 = −6𝑥
5. −
4
7
𝑟 =
2
9
6.
4+𝑥
5
=
3
20
7.
𝑥
3
+
𝑥
6
= 12
8. 𝑥 + ( 𝑥 + 2) + ( 𝑥 + 4) = 66
9. 4( 𝑚 − 3) − ( 𝑚 − 3) = 21
10. 5(2𝑛 − 3) = 4(𝑛 + 3)
F. Assignment
1. Exercises Letter C page 160 and 164

Algebraically

  • 1.
    1 | 4 LessonPlan for Grade 7 Mathematics I. TOPIC: Solving First Degree Equations in One Variable Algebraically II. Learning Objectives At the end of the lesson, the students must have: a. solved first degree equations in one variable by algebraic procedure using the properties of equality. III. Learning Contents A. Mathematical Concepts  Properties of Equality B. References Mirabona, I. (2013). Interactive mathematics 7. Manila: Innovative Educational Materials, Inc., pp. 154-158 C. Instructional Materials Chalk, Blackboard, Manila Paper, Cartolina, Marker, Visual Aids D. Value Foci Accuracy, Cooperation, Objectivity, Perseverance E. Strategies/Techniques Discussion Method, Oral Questioning, Constructivism, Cooperative Learning IV. Learning Activities A. Preliminaries Teacher’s Activity Students’ Activity a. Prayer May I request everyone to stand for a prayer? Good morning class! Please take your seat. b. Checking of Attendance (Stands up and pray) Good morning Maám! Thank you, Maám. B. Developmental Activities Teacher’s Activity Students’ Activity a. Activity Now, we are going to have an activity. Please answer the following on your ½ sheet of pad paper cut crosswise. Do this with a partner. I will give you 6 minutes to answer. What is the value of 𝑥 in the following equations? 1. 𝑥 + 4 = 12 2. 7𝑥 = 28 3. 6𝑥 − 5 = 31 4. 5𝑥 − 7 = 𝑥 + 9 5. 3(2𝑥 − 4) = 42 a. How did you arrive at your answer? b. Did you use the properties of equality to solve for 𝑥? How?
  • 2.
    2 | 4 c.Substitute the value of 𝑥 to check your answer. Do the values of 𝑥 make the mathematical sentences true? Time’s up class! Please look at the board now. b. Analysis How was the activity? Now, let’s start with item letter a. How did you arrive at your answer? Yes, ___. Very good, ___. Was it easy? That’s it. Our lesson for today is about solving first degree equations in one variable. This time, we’ll solve it algebraically. That means we are going to solve for the easy way of finding 𝑥 or any unknown variable. What about in item letter b? Yes, ___. Very good, ___. What about in item letter c? Yes, ___. Very good, ___. Now, let’s have item number 1. What property can we use to 𝑥 + 4 = 12 when we add a number to both sides? Very good. What should we add to both sides of the equation to have 𝑥 only on one side? Who wants to try adding it here? Yes, ___. Very good, ___. Now, what is the next step? Yes, ___. Very good, ___. Then we’ll use parenthesis to group the like terms: 𝑥 + [4 + (−4)] = 12 + (−4). What property did I use? Very good. Now what is 4 + (−4)? What property did we use? What about 12 + (−4)? Very good. what is 𝑥 + 0? Challenging, Maám. (Raising hands) We used the trial and error method, Maám. No, Maám. It’s time-consuming. (Raising hands) Yes, Maám. We studied the examples and how the properties of equality are used. (Raising hands) Yes, Maám. We got them right. Addition Property of Equality, Maám. −4, Maám. (Raising hands) 𝑥 + 4 + (−4) = 12 + (−4) (Raising hands) Combine like terms, Maám. Associative property of addition, Maám. 0, Maám. Additive inverse, Maám. 8, Maám. 𝑥, Maám. Additive Identity, Maám.
  • 3.
    3 | 4 Whatproperty did you use? Very good. Now you have the value of 𝑥 which is 8. How would you know 8 is the really the value of 𝑥? Very good. How? Very good again. Who wants to check the answer? Yes, ___. Very good, ___. We also do it like this: 𝑥 + 4 = 12 8 + 4 = 12 12 = 12 Remember class, this is how we solve for the value of 𝑥 algebraically. Can you follow? Now, try solving for the value of 𝑥 algebraically on the other items. I will give you 5 minutes. Now, who wants to try solving the rest of the items algebraically and explain here at the front? Yes, ___, ___, ___ and ___. Did you also get the correct answers? Now, who wants to check them? Yes, ___, ___, ___ and ___. Very good class. Do you have any questions? We’ll check the answer, Maám. By substitution, Maám. (Raising hands) 8 + 4 = 12 Yes, Maám. (Raising hands) 7𝑥 = 28 Given 1 7 ∙ 7𝑥 = 1 7 ∙ 28 Mutliplication Property of Equality ( 1 7 ∙ 7) 𝑥 = 4 Associative Property(Multiplication) 1 ∙ 𝑥 = 4 Multiplicative Inverse 𝑥 = 4 Multiplicative Identity 6𝑥 − 5 = 31 Given 6𝑥 − 5 + 5 = 31 + 5 Addition Prop. of Equality 6𝑥 = 36 Simplify 6𝑥 6 = 36 6 Mult. Prop. of Equality 𝑥 = 6 Simplify 5𝑥 − 7 = 𝑥 + 9 Given 5𝑥 − 𝑥 − 7 + 7 = 𝑥 − 𝑥 + 9 + 7 A.P.E. 4𝑥 = 16 4𝑥 4 = 16 4 M.P.E. 𝑥 = 4 3(2𝑥 − 4) = 42 Given 6𝑥 − 12 = 42 D.P.M.A. 6𝑥 − 12 + 12 = 42 + 12 A.P.E. 6𝑥 = 54 6𝑥 6 = 54 6 M.P.E. 𝑥 = 9 Yes, Maám. (Raising hands) (Checks their answers correctly) None, Maám. C. Abstraction Teacher’s Activity Students’ Activity
  • 4.
    4 | 4 Howdo we solve for the value of 𝑥 algebraically? What do we use in solving? Very good. how would you know that you solved the correct value of 𝑥? Very good again. Questions? Is our lesson easy? Properties of equality, Maám. By substituting the value of 𝑥 to the given equation. None, Maám. Yes, Maám. D. Application Teacher’s Activity Students’ Activity If none, let us have practice exercises I have posted on the board. You can work with your seatmates and discuss. I will give you 5 minutes. Solve the following equations and check the solutions. 1. 𝑥 − 8 = 47 2. 𝑥 − 42 = −115 3. 𝑚 + 1.8 = 17 4. 𝑛 − 3/8 = 11/20 5. 𝑥 + 42 = 12 Are you all done? Who can answer them on the board? Let’s have ___, ___, ___, ___, ___, ___ and ___. Are their answers correct? Did you also get the correct answers? Very good. Now are you ready for a quiz? Please get a whole sheet of pad paper. 1. 𝑥 = 55 2. 𝑥 = −73 3. 𝑥 = 15.2 4. 𝑥 = 37/40 5. 𝑥 = −30 (Raising hands) Yes, Maám. Yes, Maám. E. Evaluation Solve for the value of each variable in set of real numbers. 1. 5𝑦 = 85 2. −9𝑥 = 333 3. 1.2𝑑 = −18 4. 1.5 = −6𝑥 5. − 4 7 𝑟 = 2 9 6. 4+𝑥 5 = 3 20 7. 𝑥 3 + 𝑥 6 = 12 8. 𝑥 + ( 𝑥 + 2) + ( 𝑥 + 4) = 66 9. 4( 𝑚 − 3) − ( 𝑚 − 3) = 21 10. 5(2𝑛 − 3) = 4(𝑛 + 3) F. Assignment 1. Exercises Letter C page 160 and 164