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Journal of Physics Special Topics
A4 7 Supermassive (Interstellar) Black Hole
C. Sullivan, J. Sallabank, A. Foden, A. Higgins
Department of Physics and Astronomy, University of Leicester. Leicester, LE1 7RH.
Nov 12, 2014.
Abstract
This paper considers the plausibility of an event from the 2014 film Interstellar. It states that
an hour on a planet orbiting a supermassive back hole is equivalent to 7 years passing on Earth.
Calculations made state that the planet is inside the minimum orbit for a planet around a black
hole and would thus fall with a ballistic trajectory into the centre. However, a static system
was assumed, so with an optically spinning black hole the planet may be in a stable orbit. A
spacecraft orbiting at a distance unaffected by time dilation is also considered and found to be
largely implausible.
Introduction
Interstellar follows astronauts travelling to potentially habitable planets in a new system brought con-
veniently close to Earth via a wormhole located near Saturn. One such planet known as Miller’s Planet
orbits a supermassive black hole and as such is affected by gravitational time dilation. When the astro-
nauts spend an hour on the surface of the planet, 7 years elapse not only on Earth but on their mothership
which is staying outside the effect of the gravitational potential well.
Other important factors when determining the plausibility of the system are the location of the min-
imum stable orbit and the Schwarzschild radius, also known as the event horizon, within which nothing,
not even light, can escape. Figure 1 illustrates the system. We are not considering the repercussions of
the planet orbiting at relativistic velocities, only the time dilation due to the gravity of the black hole.
Fig. 1: The structure of the gravity well around the
black hole. Distances not to scale
When does 1 hour equal 7 years?
The equation for gravitational time dilation for a
circular orbit is given by [1];
T =
To
1 − 3
2
rs
r
, (1)
where To is the observed time, T is the time
observed from far away (i.e. Earth), rs is the
Schwarzschild radius and r is the orbital radius.
Using the definition of the Schwarzschild radius
[2],
rs =
2GM
c2
, (2)
we can rearrange eqn.1 to find the orbital radius
for a given time dilation,
r =
3
2
2GM
c2(1 − (To
T )2)
. (3)
G=6.67×10−11
m3
kg−1
s−2
is the gravitational
constant, c=3×108
ms−1
is the speed of light and
M is the mass of the black hole stated by the film
producers to be 100 million M where the mass of
the sun (M ) is 1.99×1030
kg [3]. For To=1 hour
and T=24×365×7 hours, the orbital distance is calculated to be 4.42×1011
m (2.95Au). Using eqn.2 the
Schwarzschild radius for this supermassive black hole is found to be 2.95×1011
m (1.96Au). For a structure
100 million times the mass of the sun, 1Au from the planet to the event horizon is a tiny distance.
1
Supermassive (Interstellar) Black Hole, Nov 12, 2014.
What counts as a safe distance away?
The mothership stationed outside the effect of gravitational time dilation is next considered. A small
amount of time dilation is taken to be the amount experienced by astronauts on the ISS. This can be
found by putting the orbital distance of the ISS (∼400km) [4] and the Earth’s mass (5.97×1024
kg) into
eqn.1 (including rs from eqn.2). This gives a 17ns per second time difference with Earth. Using this to set
T=1+(1.7×10−9
)s and To=1s eqn.3 can be used to find an extremely safe orbital radius from the black
hole. This is found to be 1.3×1019
m which is 86.8 million Au from the centre! For a more achievable safe
distance the time is set to run twice as fast (T=2To) giving an achievable safe distance of 5.90×1011
m
(3.93Au).
The time it would take to travel from the planet to these safe distances can be found from hints in
the film. It is stated that it takes the astronauts 2 years to travel from Earth to Saturn. We can use
this to find a rough estimate for the speeds at which they can travel. For the highest possible speed and
therefore the most optimistic travel times it is assumed that Saturn is at its furthest distance from Earth
(1.7 billion km) [5][Note: At this distance Saturn would be directly behind the Sun so the path could not
be direct]. Converting 2 years into 6.31×107
s the average speed is approximately 27.0kms−1
. The time
to travel from the planet at an orbital distance of 2.95Au to the extremely safe distance (86.8 million
Au) is therefore 15 million years! For the achievable safe distance (3.93Au) it would take 63 days. This
makes the ability to quickly visit the surface with minimal time change on return to the ship apparently
impossible within the technology of the film.
Minimum stable orbit
Fabian et al. (2000) discusses the limits for the minimum stable orbit around black holes. It is referred
to as the radius of marginal stability (rms), within which matter would follow a ballistic trajectory
into the centre of the black hole. For a static black hole rms=6rs. For the black hole considered here
rms=1.77×1012
m (11.8Au) using rs from eqn.2. This is much further out than Miller’s Planet at 2.95Au,
therefore the planet could not exist in its orbit for a static black hole. Fabian et al. also discuss how a
spinning black hole effects the minimum orbit. For prograde orbits and an optimally spinning black hole
rms=1.235rs [7]. This gives a minimum orbit of 3.64×1011
m (2.43Au). Miller’s Planet would therefore
be in an acceptable orbit for a maximally spinning black hole.
Conclusion
Interstellar is very accurate for a Hollywood film, going so far as to consult with physicist Kip Thorne
[3] to improve the realism of the film. However, no film is flawless, and what has been shown here is that
some elements still require a suspension of disbelief.
Although a rotating black hole may legitimize the portrayal of Miller’s Planet, the affects of time
dilation while travelling to and from the planet do not hold up under close scrutiny. This is due to the 63
day travel time to reach a distance with relatively small time dilation. The elapsed time depicted in the
film on the astronauts’ return to the mothership should therefore be significantly greater. This said, it is
still felt that the film should be applauded for showing a respect to science not often seen in cinemas.
References
[1] http://en.wikipedia.org/wiki/Gravitational_time_dilation Accessed on 12/11/2014
[2] http://hyperphysics.phy-astr.gsu.edu/hbase/astro/blkhol.html Accessed on 12/11/2014
[3] http://www.space.com/27692-science-of-interstellar-infographic.html Accessed on 12/11/2014.
[4] http://www.esa.int/Our_Activities/Human_Spaceflight/International_Space_Station/ISS_
International_Space_Station Accessed on 12/11/2014
[5] http://www.space.com/18477-how-far-away-is-saturn.html Accessed on 12/11/2014
[6] http://ned.ipac.caltech.edu/level5/Fabian4/Fab4.html Accessed on 12/11/2014
[7] A.C. Fabian, K. Iwasawa, C.S. Reynolds, A.J. Young, Broad iron lines in Active Galactic Nuclei PASP, vol
112 (2000)
2

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  • 1. Journal of Physics Special Topics A4 7 Supermassive (Interstellar) Black Hole C. Sullivan, J. Sallabank, A. Foden, A. Higgins Department of Physics and Astronomy, University of Leicester. Leicester, LE1 7RH. Nov 12, 2014. Abstract This paper considers the plausibility of an event from the 2014 film Interstellar. It states that an hour on a planet orbiting a supermassive back hole is equivalent to 7 years passing on Earth. Calculations made state that the planet is inside the minimum orbit for a planet around a black hole and would thus fall with a ballistic trajectory into the centre. However, a static system was assumed, so with an optically spinning black hole the planet may be in a stable orbit. A spacecraft orbiting at a distance unaffected by time dilation is also considered and found to be largely implausible. Introduction Interstellar follows astronauts travelling to potentially habitable planets in a new system brought con- veniently close to Earth via a wormhole located near Saturn. One such planet known as Miller’s Planet orbits a supermassive black hole and as such is affected by gravitational time dilation. When the astro- nauts spend an hour on the surface of the planet, 7 years elapse not only on Earth but on their mothership which is staying outside the effect of the gravitational potential well. Other important factors when determining the plausibility of the system are the location of the min- imum stable orbit and the Schwarzschild radius, also known as the event horizon, within which nothing, not even light, can escape. Figure 1 illustrates the system. We are not considering the repercussions of the planet orbiting at relativistic velocities, only the time dilation due to the gravity of the black hole. Fig. 1: The structure of the gravity well around the black hole. Distances not to scale When does 1 hour equal 7 years? The equation for gravitational time dilation for a circular orbit is given by [1]; T = To 1 − 3 2 rs r , (1) where To is the observed time, T is the time observed from far away (i.e. Earth), rs is the Schwarzschild radius and r is the orbital radius. Using the definition of the Schwarzschild radius [2], rs = 2GM c2 , (2) we can rearrange eqn.1 to find the orbital radius for a given time dilation, r = 3 2 2GM c2(1 − (To T )2) . (3) G=6.67×10−11 m3 kg−1 s−2 is the gravitational constant, c=3×108 ms−1 is the speed of light and M is the mass of the black hole stated by the film producers to be 100 million M where the mass of the sun (M ) is 1.99×1030 kg [3]. For To=1 hour and T=24×365×7 hours, the orbital distance is calculated to be 4.42×1011 m (2.95Au). Using eqn.2 the Schwarzschild radius for this supermassive black hole is found to be 2.95×1011 m (1.96Au). For a structure 100 million times the mass of the sun, 1Au from the planet to the event horizon is a tiny distance. 1
  • 2. Supermassive (Interstellar) Black Hole, Nov 12, 2014. What counts as a safe distance away? The mothership stationed outside the effect of gravitational time dilation is next considered. A small amount of time dilation is taken to be the amount experienced by astronauts on the ISS. This can be found by putting the orbital distance of the ISS (∼400km) [4] and the Earth’s mass (5.97×1024 kg) into eqn.1 (including rs from eqn.2). This gives a 17ns per second time difference with Earth. Using this to set T=1+(1.7×10−9 )s and To=1s eqn.3 can be used to find an extremely safe orbital radius from the black hole. This is found to be 1.3×1019 m which is 86.8 million Au from the centre! For a more achievable safe distance the time is set to run twice as fast (T=2To) giving an achievable safe distance of 5.90×1011 m (3.93Au). The time it would take to travel from the planet to these safe distances can be found from hints in the film. It is stated that it takes the astronauts 2 years to travel from Earth to Saturn. We can use this to find a rough estimate for the speeds at which they can travel. For the highest possible speed and therefore the most optimistic travel times it is assumed that Saturn is at its furthest distance from Earth (1.7 billion km) [5][Note: At this distance Saturn would be directly behind the Sun so the path could not be direct]. Converting 2 years into 6.31×107 s the average speed is approximately 27.0kms−1 . The time to travel from the planet at an orbital distance of 2.95Au to the extremely safe distance (86.8 million Au) is therefore 15 million years! For the achievable safe distance (3.93Au) it would take 63 days. This makes the ability to quickly visit the surface with minimal time change on return to the ship apparently impossible within the technology of the film. Minimum stable orbit Fabian et al. (2000) discusses the limits for the minimum stable orbit around black holes. It is referred to as the radius of marginal stability (rms), within which matter would follow a ballistic trajectory into the centre of the black hole. For a static black hole rms=6rs. For the black hole considered here rms=1.77×1012 m (11.8Au) using rs from eqn.2. This is much further out than Miller’s Planet at 2.95Au, therefore the planet could not exist in its orbit for a static black hole. Fabian et al. also discuss how a spinning black hole effects the minimum orbit. For prograde orbits and an optimally spinning black hole rms=1.235rs [7]. This gives a minimum orbit of 3.64×1011 m (2.43Au). Miller’s Planet would therefore be in an acceptable orbit for a maximally spinning black hole. Conclusion Interstellar is very accurate for a Hollywood film, going so far as to consult with physicist Kip Thorne [3] to improve the realism of the film. However, no film is flawless, and what has been shown here is that some elements still require a suspension of disbelief. Although a rotating black hole may legitimize the portrayal of Miller’s Planet, the affects of time dilation while travelling to and from the planet do not hold up under close scrutiny. This is due to the 63 day travel time to reach a distance with relatively small time dilation. The elapsed time depicted in the film on the astronauts’ return to the mothership should therefore be significantly greater. This said, it is still felt that the film should be applauded for showing a respect to science not often seen in cinemas. References [1] http://en.wikipedia.org/wiki/Gravitational_time_dilation Accessed on 12/11/2014 [2] http://hyperphysics.phy-astr.gsu.edu/hbase/astro/blkhol.html Accessed on 12/11/2014 [3] http://www.space.com/27692-science-of-interstellar-infographic.html Accessed on 12/11/2014. [4] http://www.esa.int/Our_Activities/Human_Spaceflight/International_Space_Station/ISS_ International_Space_Station Accessed on 12/11/2014 [5] http://www.space.com/18477-how-far-away-is-saturn.html Accessed on 12/11/2014 [6] http://ned.ipac.caltech.edu/level5/Fabian4/Fab4.html Accessed on 12/11/2014 [7] A.C. Fabian, K. Iwasawa, C.S. Reynolds, A.J. Young, Broad iron lines in Active Galactic Nuclei PASP, vol 112 (2000) 2