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7. A statistics professor receives an average of five e-mail messages per day from students.
Assume the number of messages approximates a Poisson distribution. What is The probability
that on a randomly selected day she will have two messages? A. 0.0014 B. 0.0842 C. 0.4200 D.
0.0067
Solution
Given X~Poisson(mean=5)
P(X=x)=(5^x)*exp(-5)/x!
So the probability is
P(X=2) = (5^2)*exp(-5)/2= 0.08422434
Answer: B

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  • 1. 7. A statistics professor receives an average of five e-mail messages per day from students. Assume the number of messages approximates a Poisson distribution. What is The probability that on a randomly selected day she will have two messages? A. 0.0014 B. 0.0842 C. 0.4200 D. 0.0067 Solution Given X~Poisson(mean=5) P(X=x)=(5^x)*exp(-5)/x! So the probability is P(X=2) = (5^2)*exp(-5)/2= 0.08422434 Answer: B