on the basis of the above data, list the media in order according to.pdf

•

0 likes•2 views

on the basis of the above data, list the media in order according to their ability to support the growth of the bacteria List the three bacterial species in order of their increasing fastidiosness Why did the most fastidious organism grow poorly in the chemically defined medium? Date Section Observations and Results Optical Density Readings Nutrient Broth Glucose Broth 1. On the basis of the above data, lit the media in order (from best toworst) according to their ability to support the growth of bacteria. 2. List the three bacterialspeciesinorder of their increasing fastidiousness. 3. Why did the most fastidious organismgrow poorly in the chemically defined Lab Re Synthetic Broth Solution The media most able to support bacterial growth in decreasing order are: Yeast extract broth, nutrient broth, inorganic synthetic broth, glucose broth. The bacteria in increasing order of fastidiousness are: E. coli, A. faecalis, S. mitis The most fastidious bacteria grew the slowest as it has a complex nutritional requirement, and as the chemically defined broth has the least variety of nutrients, a fastidious bacteria will take time to digest the few compounds and make the molecules necessary for survival..

Education

Similar to on the basis of the above data, list the media in order according to.pdf

media and its types

Microbiology

Qore probiotic product profile final 8 5-09

Qivana IBO

Understanding Our Microbiome: The Natural Symbiosis

Kumaraguru Veerasamy

Microbiome

TRIDIP BORUAH

2 Tissue culture media.pptx

MabiorJok

Towards Optimal Microbiome: Boosting Your Gut Health

Kumaraguru Veerasamy

Culture media and its types

Crimson College of Technology (Pokhara University)

Food and Microbes History.pptx

DrPriyankaGhoshPaul

Pros And Cons Of Microorganisms

College Papers For Sale State University of New York at New Paltz

Food Microbiology - Chapter 1 & 2

Alia Najiha

Culture media for culturing microorganisms

Md Mohib Rakib

The digestive system contains heavy population of microbes. In the mouth each ml of saliva contains millions of bacteria. The stomach and intestines contain a few organisms because the stomach produces hydrochloric acids and in intestines the food is rapidly moved. The large intestine harbors several microbial populations and each gram feces contains more than 100 billion bacteria. The large intestines mainly contain anaerobic and facultative anaerobic organisms. These bacteria are mainly involved in the enzymatic break down of food especially the polysaccharides and synthesize the vitamins. The health benefits imparted by Probiotic microorganisms are strain specific. No strain will provide all proposed benefits, not even strains of the same species will be effective against defined health conditions. As not all the desirable properties are expressed by all Probiotic micro organisms, numerous strains with lack of pathogenicity are continuously screened and characterized to select those with potential. Tolerance to the extreme gastrointestinal conditions (acid, bile, enzymes, low levels of oxygen), ability to adhere to the gastrointestinal mucosa and competitive exclusion of pathogens have been some criteria for Probiotic selection. Mucous membranes of the body are in direct contact with the outside environment and they are colonized by a large number of different bacteria. Through mucous membranes, the organism is in permanent contact with different antigens. Mucous surfaces are protected by many defense mechanisms that ensure a permanent and effective protection. They include the production of secretory IgA, the production of mucus, cytoprotective peptides; defensins etc Indigenous micro flora markedly affects the structure of the host mucous, its function, and the development of the whole immune system. Protective micro flora prevents pathogens from adhering by competi tion for substrates and places of adhesion, and they simultaneously produce antibacterial substances and stimulate the production of specific antibodies and mucus. The early colonization of the gut with living micro-organisms is important for the development of the gut protection barrier. The number of immune and epithelial cells increases. Probiotics also used in the prevention of H. pylori infection in animal models. The Probiotic strains used in yoghurt BB-12 and La5 (AB-yoghurt) eradicate the colonization of H. pylori. The L. salivarius acts against H. pylori infection in mouse. The gut disorders inflammatory bowel disease – Pouchitis , Crohns disease caused by gut bacteria was prevented using VSL#3 which contains four Lactobacillus species, three Bifidobacterium species and Streptococcus salivarius species, that inhibits colonization of pathogenic bacteria in the gut. Probiotics help in assimilating cholesterol levels. Dairy products containing L. acidophilus reduces cholesterol deposition in the body. Probiotic bacteria can ferment indigestible carbohydrates and produce.

The digestive system contains heavy population of microbes. In the m.pdf

Rubanjews

Which probiotic for acute diarrheea in children

Awal Dahir.pptx

Lecture 1 (mic204)

Probiotics

Media in microbiology

Musa Khan

B3 revision powerpoint

Hannah Evans

Symptomatic treatment of Dysbacteriosis & Gaseous bowel

Eneutron

Streptocci Research Paper

Sheila Guy

Similar to on the basis of the above data, list the media in order according to.pdf (20)

media and its types

Qore probiotic product profile final 8 5-09

Understanding Our Microbiome: The Natural Symbiosis

Microbiome

2 Tissue culture media.pptx

Towards Optimal Microbiome: Boosting Your Gut Health

Culture media and its types

Food and Microbes History.pptx

Pros And Cons Of Microorganisms

Food Microbiology - Chapter 1 & 2

Culture media for culturing microorganisms

The digestive system contains heavy population of microbes. In the m.pdf

Which probiotic for acute diarrheea in children

Awal Dahir.pptx

Lecture 1 (mic204)

Probiotics

Media in microbiology

B3 revision powerpoint

Symptomatic treatment of Dysbacteriosis & Gaseous bowel

Streptocci Research Paper

More from amitbagga0808

Describe the role of soil microbes in the formation and maintenance of water-stable soil aggregates. Can you identify two mechanisms through which soil microbes contribute to the formation and stabilization of such aggregates? soild science Solution Formation and maintenance ofwater-stable solid aggregates in the soil are important parts of soil formation and tillage. The microorganisms play a very important role in it. The microbes normally reside in the soil as a major part of their life cycle. The microbes residing in the soil perform following function for maintaining soil quality and texture: 1. The microbes survive on soil as a nutrient source. Small microbes such as some bacteria and fungi absorb nutrients from the soil, digest them in their gut and release the excreta rich in polysaccharides and polyuronic acids. These polysaccharides are water-stable and thus help in aggregating small particles of soil and hence bind them. 2. As the microbes gradually complete their life cycle, they die and decay in the soil. As they decay, the bio-molecules and bio-polymers get assimilated in the soil. Since these microbial bio- molecules and bio-polymers are rich in water stable compounds,they agglutinate with minute soil particles to generate water-stable hydrophobic aggregates. Thus, the two mechanisms can be distinguished as described above as: 1. Release of bio-molecules from microbes 2. Decay and assimilation of microbes in soil For example: Zygomyceta (vascular arbuscular mycorrhizal fungi) and some bacteria..

Describe the role of soil microbes in the formation and maintenance .pdf

amitbagga0808

Chapter 9: Problem: P 9-1: The narrative and systems flowchart for the Bridgeport LLC cash receipts system are included in Exhibit 9.5 and Figure 9.11 (pg. 348), respectively. Using Exhibit 9.5 and Figure 9.11, do the following: a. Prepare a control matrix, including explanations of how each recommended control plan helps to accomplish? Or would accomplish in the case of missing plans? Each related control goal. Your choice of recommended control plans should come from Figure 9.4 (pg. 325)/ Exhibit 9.3 (pp. 329? 330) or Figure 9.6 (pg. 334)/Exhibit 9.4 (pg. 338), as appropriate. Be sure to tailor the matrix columns to conform to the specifics of the Bridgeport system. In doing so, assume the following two effectiveness goals only: - Timely deposit of checks? -Compliance with compensating balance agreements with the depository bank? Control Goals of the Bridgeport Cash Receipts Process Control Goals of the Operations Process Control Goals of the Information Process Ensure effectiveness of operations: Ensure efficient employment of resources (people, computers) Ensure security of resources (cash, accounts receivable master data) For the remittance advice inputs (i.e., cash receipts), ensure: For the accounts receivable master data, ensure: Recommended control plans A B IV IC IA UC UA Present Controls P-1: Turnaround documents P-2: Endorse checks immediately P-3: Preformatted screens P-4: Compare input data with master data P-5: Programmed edit checks. P-6: Procedure for rejected inputs P-7: Manual agreement of RA batch totals P-8: Manual agreement of deposit batch totals Missing Controls M-1: Document design M-2: Enter cash receipts in the mailroom (enter data close to original source) M-3: Computer agreement of batch totals Possible effectiveness goals include the following: A – Timely deposit of checks B – Comply with compensating balance agreements with the depository bank IV = input validity IC = input completeness IA = input accuracy UC = update completeness UA = update accuracy Control Goals of the Bridgeport Cash Receipts Process Control Goals of the Operations Process Control Goals of the Information Process Ensure effectiveness of operations: Ensure efficient employment of resources (people, computers) Ensure security of resources (cash, accounts receivable master data) For the remittance advice inputs (i.e., cash receipts), ensure: For the accounts receivable master data, ensure: Recommended control plans A B IV IC IA UC UA Present Controls P-1: Turnaround documents P-2: Endorse checks immediately P-3: Preformatted screens P-4: Compare input data with master data P-5: Programmed edit checks. P-6: Procedure for rejected inputs P-7: Manual agreement of RA batch totals P-8: Manual agreement of deposit batch totals Missing Controls M-1: Document design M-2: Enter cash receipts in the mailroom (enter data close to original source) M-3: Computer agreement of batch totals Possible effectiveness goals include the following: A – Timely deposit.

Chapter 9Problem P 9-1The narrative and systems flowchart for.pdf

amitbagga0808

Compare and contrast the thick and thin filaments. Solution There are two different types of filaments that extend along the muscle tissues in cylindrical shapes. Together these two filaments are known as myofibrils. Thick Filaments: 1. Myosin(a large family of motor protein ) are found to be present in these thick filaments in a bipolar fashion 2. These filaments can be found in one of the bands of sarcomere (skeletal muscle tissue) called A-Band (anisotropic band named after its property to be directionally dependent unlike isotropy ) 3. These filaments are divided/separated by an M-Line which is made up of myomesin protein Thin Filaments 1.Unlike thick filaments, thin filaments are made up of 3 types of proteins (actin, tropomyosin, and troponin) while troponin and tropomyosin are engaged is muscle contraction, actin is engaged in cell shape and cell adhesion. 2. Thin filaments are present in both A-Band and I-Band (While A-Band is anisotropic due to its quality of being directionally dependent, I-Band is isotropic band being directionally independent 3. It is divided by a different proteinaceous non-contractile line called Z-Line.

Compare and contrast the thick and thin filaments.SolutionTher.pdf

amitbagga0808

Anatomy can be studied in many ways. Regional anatomy is the study of particular areas of the body, such as the head or leg. Most undergraduate college courses in anatomy and physiology (and the format of this lab manual) involve systemic anatomy he study of organ systems, such as the skeletal system and nervous system. Although organ systems are studied separately, it is important to realize the intimate connections between the systems. If the heart fails to pump blood as part of the circulatory system, then the lungs do not receive blood for oxygenation and the intestines do not transfer nutrients to the blood as fuel. The brain and other organs are no longer capable of functioning, and the result is death. From a clinical standpoint, the failure of one system has impacts on many other organ systems. There are 11 organ systems that have functions unique to them. A brief overview of these systems is presented in the following paragraphs. Reproductive the gonads (testes and ovaries) contain the sex-producing cells of the body, and the accessory organs, such as the uterus, vagina, penis, and seminal vesicles, play a part in the transport of the sex cells and the development of the fetus. Urinary the kidneys serve as filters of the body, and the urinary bladder is a storage organ. The Solution The procedure to study the reproductive system of human is follow regional anatomy process and; to view and study all organs seperately. The male reproductive system consists of series of oragans. The major organs are testes and scrotal sac which help in the production and storage of spermatozoa. There are various glands such as seminal vesicle, prostate and vas deferens; they are responsible for ejaculation of fluids. The final category are useful during copulation; these are penis, urethra, and cowper\'s gland. The female reproductive system consists of the following organs; the vaginal area, the uterus and the ovaries. The female reproductive system recieves the male sex cells (sperms) through the vaginal area and is transported to the fallopian tube where they meet the female sex cell (ovum). This event leads to fertilization of the ovum and initiation of development of the fetus..

Anatomy can be studied in many ways. Regional anatomy is the study of.pdf

amitbagga0808

A red blood cell enters the right atrium from the superior vena cava. In order, list ALL the structures it passes through to reach the right coronary artery. Be sure to include ALL the chambers of the heart, and the valves of the heart that it passes through. A red blood cell enters the celiac trunk from the aorta. In order, list ALL the structures it passes through to reach the right carotid artery. Be sure to include ALL the chambers of the heart, and the valves of the heart that it passes through. Solution Q.No 1 Heart contains four chambers, two atria and a couple of ventricles. The blood that is definitely returned to the right atrium is deoxygenated and s passed into the right ventricle to be pumped through the pulmonary artery to the lungs for reoxygenation and elimination of carbon dioxide. The left atrium receives newly oxygenated blood through the lungs with the pulmonary veins, that may be passed throughout the strong left ventricle to be pumped through the aorta to the various organs of one\'s body. Superior Vena Cava The superior vena cava is one of these two main veins bringing de-oxygenated blood from the entire body to heart. Veins through the head and upper body feed into the superior vena cava, which empties into the right atrium of the heart. Inferior Vena Cava The inferior vena cava is one of these two main veins bringing de-oxygenated blood from the entire body to heart. Veins through the legs reducing torso feed into the inferior vena cava, which empties into the right atrium of the heart. Aorta The aorta is the main single circulatory around the body. It is around the diameter from your thumb. This vessel carries oxygen-rich blood from the left ventricle to different parts of one\'s body. Pulmonary Artery The pulmonary artery is the vessel transporting de-oxygenated blood from the right ventricle to the lungs. Perhaps the most common misconception is all arteries carry oxygen-rich blood. It really is appropriate to classify arteries as vessels carrying blood away from the heart. Pulmonary Vein The pulmonary vein is the vessel transporting oxygen-rich blood through the lungs to the left atrium. Perhaps the most common misconception is all veins carry de-oxygenated blood. It really is appropriate to classify veins as vessels carrying blood to heart. Papillary Muscles The papillary muscles attach to the reduced percentage of the interior wall of one\'s ventricles. They connect with the chordae tendineae, which attach to the tricuspid valve in the right ventricle and the mitral valve around the left ventricle. The contraction of the papillary muscles closes these valves. When the papillary muscles relax, the valves open. Chordae Tendineae The chordae tendineae are tendons linking the papillary muscles to the tricuspid valve in the right ventricle and the mitral valve around the left ventricle. As the papillary muscles contract and relax, the chordae tendineae transmit the resulting increase and reduce in tension to respecti.

A red blood cell enters the right atrium from the superior vena cava..pdf

amitbagga0808

You have been hired by Planet Poachers to write a Java console application that reads, converts, sorts, and writes planet data. Create text file PlanetDataEnglish.txt, paste the following data into it, and place the file in your project folder. PlanetDataEnglish.txt Planet Escape Velocity (miles/s) Mean Temperature (F) Number of Moons Mercury 2.7 333 0 Venus 6.4 867 0 Earth 7.0 59 1 Mars 3.1 -85 2 Jupiter 37.0 -166 67 Saturn 22.1 -220 62 Uranus 13.2 -320 27 Neptune 14.6 -330 13 Pluto 0.7 -375 5 Create the following methods: Column Purpose readTextFile To read the data from file PlanetDataEnglish.txt into four parallel arrays: planets, escapes, means, and moons. printArrays To print the unsorted, converted, and sorted data using the appropriate column headers. convertArrays To convert the escape velocities from miles/s to km/s, and to convert the mean temperatures from Fahrenheit to Celsius. bubbleSortArray To sort the data by planet name in ascending order. Note that when values are swapped in one array, the same values must be swapped in the other arrays. writeTextFile To write the data to file PlanetDataMetric.txt in the same layout as the input file. Sample Output on .txt file PlanetDataMetric.txt Planet Escape Velocity (miles/s) Mean Temperature (F) Number of Moons Earth 11.3 15 1 Jupiter 59.5 -110 67 … Solution Following will be program for the planet as requested //Inclusion of the lib files Import Java.util.scanner; import java.io.Filewriter; import java.io.PrintWriter; Import java.io.FileNotFoundException; import java.util.InputMismatchException; import java.io.IOException; import java.io.File; Public class Planets // Main method is followed { public static void main(String[] args) // main mehtod { // variables are declared scanner keyboard = new Scanner(System.in); // here the keyboard will be connected Scanner fileIn = null; //file variable are declared String fileInName = \"PlanetSourceData.txt\";// File name variable is declared int i=0; int j=0; int k =0; int Usednumber = 10; String [] Plantets = new String[20]; int [] diameters = new int[15]; double [] leng = newdouble [12]; try { fileIn = new Scanner(new FileInputStream(fileInName)); //Scanning of the text file is done } Catch(FileNotFoundException e) \\\\catching of the exception { System.out.printIn(\"Error:File \'\" +fileInName+ \"\' not found.\"); //gives the error message that file is not found System.exit(-1); } System.out.println(\"This is templelate from Java keyboard entry\"); // To read the input file this loop is formed while(fieIn.hasNextLine()) { Planets[i] = fileIn.next(); diameters[j] = fileIn.nextInt(); lengths[k] = fileIn.nextDouble(); System.out.Printf(\"%-10 %8s %8s %n\" , \"Planets\", \"Diameter(miles)\",\" Hours of the planest(Length of the planet:); System.out.printf(\"%-10s %8d %8.1f 5n \", planets[i], diameters[j] , lenths [k]); } PrintArray(diameters, numberUsed); bubbleSortArray(diameters,numberUsed); //finding the miles(escape velocity) printArray(dua.

You have been hired by Planet Poachers to write a Java console appli.pdf

amitbagga0808

An organism that has a normal diploid autosome set with an XXY sex c.pdf

amitbagga0808

Which level of Orange Book protection is considered mandatory protection and is the first level in which labels are required? A. B3 B. C2 C. B1 D. A1 Solution C. The Orange Book rates systems as one of four categories. Category A is verified protection, B is mandatory protection, C is discretionary protection, and D is minimal protection. B1 is the first level in which labels are required. Therefore, answers A, B, and D are incorrect.

Which level of Orange Book protection is considered mandatory protec.pdf

amitbagga0808

Why is it an advantage for the epiglottis to fit over the trachea? Solution Epiglottis is a leaf like , yellow, elastic cartilage forming anterior wall of the laryngeal inlet. The epiglottis is located on the trachea that is closed during the swallowing of meals which prevents the aspiration of food , water and other sunstances into the Lungs. Aspiration of food into Lungs leads to obstruction of trachea is called as choking, and also leads to fibrosis of lung leads to death of the patient. Hence the epiglottis is fitted in the trachea..

Why is it an advantage for the epiglottis to fit over the trachea.pdf

amitbagga0808

//This is Function Class public abstract class Function { /** * Calculates the value f(x) of the function at x * @param x The x-value at which the function will be evaluated * @return a double, the value of the function at x */ public abstract double fnValue(double x); /** * Translates f(x) to the display coordinate system. Note that Java graphics * places (0,0) in the upper left, and (xmax, ymax) in the lower right of the * display. A buffer of 5 pixels is kept at top and bottom. * @param x the value at which f(x) will be evaluated * @param d the height in pixels of the display * @param minY the minimum f(x) to be displayed, over the extent of the x\'s * @param maxY the maximum f(x) to be displayed, over the extent of the x\'s * @return the value of f(x) translated to the display coordinate system */ public double fnValueToPlot(double x, double d, double minY, double maxY) { double y = fnValue(x); double yDraw = (d+5)-((y-minY)*(d/(maxY-minY))); return yDraw; } /** * Determines the display value where y=0 * @param height Height of the Canvas * @param minY th=0e minimum height of the function within the chosen extents * @param maxY the maximum height of the function within the chosen extents * @return the value of y to display corresponding to y */ public double originToPlot(double height, double minY, double maxY) { double yDraw = (height+5)-((0-minY)*(height/(maxY-minY))); return yDraw; } } //This is GraphManager Class public class GraphManager implements GraphManagerInterface { private double xLeft, xRight; private double yTop = Integer.MIN_VALUE; private double yBottom = Integer.MAX_VALUE; private int functionChoice=-999; Function function1, function2, function3, function4, function5, function6; /** * Constructor instantiates the functions specified. */ GraphManager() { function1 = new Function1(); function2 = new Function2(); function3 = new Function3(); } /** * getFnValue calculates the value of the function requested by the user, at a specific x value. * @param fnNum the choice of which function to evaluate * @param x the value at which to evaluate the function * @return the value of f(x) */ public double getFnValue (int fnNum, double x) { switch(fnNum) { case 1: return function1.fnValue(x); case 2: return function2.fnValue(x); case 3: return function3.fnValue(x); default: return 0; } } /** * Sets the function choice * @param choice an integer indexing the function desired */ public void setFunctionChoice(int choice) { functionChoice = choice; } /** * Gets the function index previously selected by the user * @return an index 1-4 corresponding to a function */ public int getFunctionChoice() { return functionChoice; } /** * Gets the actual function instance * @param choice the index of the function desired * @return an instance of a sub-class of the Function class */ public Function getFunction(int choice) { switch(choice) { case 1: return function1; case 2: return function2; case 3: return function3; default: return null; } } /** * Sets.

This is Function Class public abstract class Function { .pdf

amitbagga0808

What factors are likely to be involved in setting the limit to how long an animal migration can be? In other words, could you predict an animals1 longest possible migration given measures of physiological performance, morphology etc...? If yes, what would those be? Solution Migration is a typical conduct of eukayotic animals.Migration is refinement of complex connection between inside components, for example, genetics,physiology and conduct and outer variables weather,habitat condition, sustenance accessibility, predation geology. Migration is the development of individuals starting with one area then onto the next and broadly connected with change of perpetual place of habitation. Reasons of Migration are between local and intraregional differences at full scale level and generally absence of business openings coming about low expectation for everyday comforts conditions among various financial gatherings at smaller scale level. There are three segments of populace change. They are mortality, richness and migration. There are two sorts of movement: interior migration and worldwide movement. Inner migration is the development of individuals from one place to other place in a given nation. Universal migration is the development of individuals starting with one nation then onto the next so as to take up work of set up living arrangement or to increment in expectation for everyday comforts. The vital elements which rouse individuals to move can be ordered into five classifications. They are financial components, statistic variables, socio-social elements, political elements and incidental elements. (i) Economic Factors Most of the reviews show that migration is basically roused by financial elements. In creating nations, low agrarian wage, horticultural unemployment and underemployment are viewed as essential elements pushing the vagrants towards created zone with more prominent openings for work. Accordingly, all reviews agree that the vast majority of transients have moved looking for better monetary open doors. The essential financial variables which inspire migration might be further named \'Push Factors\' and \'Force Factors\'. The push components are variables that force a man, because of various reasons, to leave that place and go to some other place. The regular push components are low efficiency, unemployment and underdevelopment, poor monetary conditions, absence of chances for headway, fatigue of normal assets and characteristic cataclysms. Presentation of capital serious techniques for generation into farming part, and automation of specific procedures diminish work necessity in rustic regions. The non-accessibility of option wellsprings of wage in country region is additionally essential component for movement. The Pull Factors will be components which draw in the transients to a zone. Open doors for better business, higher wages, offices, better working conditions and appealing pleasantries are draw components of a range. (ii) Demo.

What factors are likely to be involved in setting the limit to how lo.pdf

amitbagga0808

What is alternative splicing? What is the difference between mRNA splicing and editing? Solution Alternative splicing is a process by which exons or portions of exons or noncoding regions within a pre-mRNA transcript are differentially joined or skipped, resulting in multiple protein isoforms being encoded by a single gene RNA splicing is a process that removes introns and joins exons in a primary transcript. Where as RNA editing is any process, other than splicing, that results in a change in the sequence of a RNA transcript such that it differs from the sequence of the DNA template.

What is alternative splicing What is the difference between mRNA sp.pdf

amitbagga0808

What are histones and their role in regulating transcription. What is histone methylation and histone acetylation and how do these effect transcription. How are genes subdivided? What are histones and their role in regulating transcription. What is histone methylation and histone acetylation and how do these effect transcription. How are genes subdivided? What is histone methylation and histone acetylation and how do these effect transcription. How are genes subdivided? Solution Histones are alkaline proteins which are found inside the nucleus of eukaryotic cells that condense and structure the DNA into units called nucleosomes.They function as spools for the thread like DNA to wrap around and play a role in gene regulation. 2 types of histones Core histones (H2A, H2B, H3and H4) and linker his tones ( H1 and H5). Histone methylation (lysine methylation) can either activate or repress gene expression depending on both the location of the modified lysine and which his tone is the target. For example, if this occurs in histone H3 at lysine 4, it is linked to gene activation and if it occurs at lysine 9 it is a marker for gene silencing. His tone acetylation removes the negative charge from lysine so it can no longer bind to the DNA phosphate backbone. This weakens the interaction between histones and DNA, resulting in a more relaxed DNA structure which is more available for DNA transcription. Histone acetyl transferase (HAT) complexes are recruited by transcription activator proteins, while the repressor proteins recruit his tone deacetylase (HDAC) complexes. These add and remove acetylations respectively..

What are histones and their role in regulating transcription. .pdf

amitbagga0808

What are the cellular differences between fungi and protists? Solution 1.Fungi live in aerobic environment to survive, whereas protists live in an anaerobic environment. 2. protists are single-celled, however fungi are multi-celled. 3.The protista kingdom consists of members which are autotrophic and heterotrophic. The autotrophs are able to make their own food even as heterotrophs depend on others for food. Fungi can not be considered autotrophic or heterotrophic, although they extra closely relate to the heterotrophs. Members of the fungi are saprophytes I.e. consume dead or composing material..

What are the cellular differences between fungi and protistsSol.pdf

amitbagga0808

Program In C You are required to write an interactive C program that prompts the user for commands, accepts commands from the keyboard (stdin) and executes those commands. When a command requires output, it must be written to stdout. The program must continue to accept and process commands until the user types the end command ourput, it must be writen to stdout. The program must continue to accept and proces.commands The program deals with linked lists. Each node of such a list contains a string of length at most 10, a positive integer (i.e., an integer value 2 1) and a pointer to the next node of the list. For any node, the string and the integer stored in that node will be referred to as the symbol and count for that node respectively. At all times, the list must satisfy the following two important properties. 1. The symbols appearing in the list are all distinct; that is, no two nodes have the same symbol. 2. When the list is scanned from left to right, the counts must be in non-increasing order. An example of such a linked list is shown below. Search 4 Maxval4 begin/ Loop head Solution /**********************************************/ /****** NAMES ******************** COMMANDS ***/ /* Insert Command : ins str */ /* Delete Command : del str */ /* Forced Delete Command : fde val */ /* Print Statistics Command : pst */ /* Print List Command : prl */ /* Print using Count Range Command: pcr v1 v2 */ /* Print Prefix Command : ppr str */ /* Print Suffix Command : psu str */ /* End Command : end */ /***********************************************/ #include #include #include #define CSIZE 4 #define SSIZE 11 /* Struct for each node in the linked list */ struct node { int count; char symbol[SSIZE]; struct node *next; }; struct node *head; /* Prototypes for the functions */ void insert(char *); void delete(char *); void forced_delete(int value); void print_stats(); void print_list(); void print_count(int, int); void print_prefix(char pre[]); void print_suffix(char suf[]); void sort_list(); /**************** ** Main Method ** ****************/ int main(void) { int count; char symbol[SSIZE]; char cmd[CSIZE]; int v1; int v2; /* Enter commands */ printf(\"Command? \"); fflush(stdout); scanf(\"%s\", cmd); /* Check for command*/ while(strcmp(cmd,\"end\") != 0) { /* check which function to use */ if(strcmp(cmd,\"ins\") == 0) { scanf(\"%s\", symbol); insert(symbol); } if(strcmp(cmd,\"del\") == 0) { scanf(\"%s\", symbol); delete(symbol); } else if(strcmp(cmd,\"fde\")==0){scanf(\"%d\",&count); forced_delete(count); } if(strcmp(cmd,\"pst\") == 0) { print_stats();} if(strcmp(cmd,\"prl\") == 0) { print_list(); } if(strcmp(cmd,\"pcr\") == 0) { scanf(\"%d %d\",&v1,&v2); print_count(v1,v2); } if(strcmp(cmd,\"ppr\") == 0) { scanf(\"%s\", symbol); print_prefix(symbol);} if(strcmp(cmd,\"psu\") == 0) { scanf(\"%s\", symbol); print_suffix(symbol);} printf(\"Command? \"); fflush(stdout); scanf(\"%s\", cmd); }// End of While Loop return 0; }// End of main method /*********.

Program In C You are required to write an interactive C program that.pdf

amitbagga0808

Prove that is L is regular and h is a homomorphism, then h(L) is regular. Prove that is L is regular and h is a homomorphism, then h(L) is regular. Prove that is L is regular and h is a homomorphism, then h(L) is regular. Solution If L is a regular language, and h is a homomorphism on its alphabet, then h(L) = {h(w) | w is in L} is also a regular language. Proof : Let E be a regular expression for L. Apply h to each symbol in E. Language of resulting RE is h(L). Let h(0) = ab; h(1) = .Let L be the language of regular expression 01* +10*. Then h(L) is the language of regular expression ab* +(ab)*. which can be simplified * = , so ab*=ab is the identitiy under concetenation . so E=E=E for any RE E Thus ab*+(ab)* =ab +(ab)* =ab+(ab)* Finall , L(ab) is contained in L(ab)* so RE for h(L) is (ab)* so h(L) is regular.

Prove that is L is regular and h is a homomorphism, then h(L) is.pdf

amitbagga0808

Not sure how to do this case analysis please help me do it! 1.Are the regions similar? 2.What would be a good forecasting method to use? 3.Are there more advanced methods that might be considered? Here is the data https://docs.google.com/spreadsheets/d/1LYZHLx9f0Av9FJ6NLfULMU61cZPV3voqrVzbJNfV jKk/edit?usp=sharing Solution Most people view the world as consisting of a large number of alternatives. Futures research evolved as a way of examining the alternative futures and identifying the most probable. Forecasting is designed to help decision making and planning in the present. Forecasts empower people because their use implies that we can modify variables now to alter (or be prepared for) the future. A prediction is an invitation to introduce change into a system. There are several assumptions about forecasting: 1. There is no way to state what the future will be with complete certainty. Regardless of the methods that we use there will always be an element of uncertainty until the forecast horizon has come to pass. 2. There will always be blind spots in forecasts. We cannot, for example, forecast completely new technologies for which there are no existing paradigms. 3. Providing forecasts to policy-makers will help them formulate social policy. The new social policy, in turn, will affect the future, thus changing the accuracy of the forecast. Many scholars have proposed a variety of ways to categorize forecasting methodologies. The following classification is a modification of the schema developed by Gordon over two decades ago: Genius forecasting - This method is based on a combination of intuition, insight, and luck. Psychics and crystal ball readers are the most extreme case of genius forecasting. Their forecasts are based exclusively on intuition. Science fiction writers have sometimes described new technologies with uncanny accuracy. There are many examples where men and women have been remarkable successful at predicting the future. There are also many examples of wrong forecasts. The weakness in genius forecasting is that its impossible to recognize a good forecast until the forecast has come to pass. Some psychic individuals are capable of producing consistently accurate forecasts. Mainstream science generally ignores this fact because the implications are simply to difficult to accept. Our current understanding of reality is not adequate to explain this phenomena. Trend extrapolation - These methods examine trends and cycles in historical data, and then use mathematical techniques to extrapolate to the future. The assumption of all these techniques is that the forces responsible for creating the past, will continue to operate in the future. This is often a valid assumption when forecasting short term horizons, but it falls short when creating medium and long term forecasts. The further out we attempt to forecast, the less certain we become of the forecast. The stability of the environment is the key factor in determining whether tren.

Not sure how to do this case analysis please help me do it!1.Are t.pdf

amitbagga0808

In each of the following situations, data are obtained by conducting a research study. Classify each Experimental or Correlational. Research Study A researcher is interested in whether listening to different types of music or no music while taking a test affects test scores. Students are randomly assigned to one of three groups: The first group takes a test without listening to an iPod, the second group takes the same test while listening to classical music on an iPod, and the third group takes the test while listening to rock music on an iPod. The researcher compares the test scores across the three groups. A psychologist is interested in gender and cognition. She collects data on a large sample of siblings, recording their gender, birth order, and IQ. A professor of ophthalmology is interested in developmental precursors of vision disorders. He collects data from a sample of teenagers on right-eye vision, left-eye vision, and whether the bedroom light was kept off or on as they slept during the night as babies. Solution 1) Experimental ( There is intervention- types of music) 2) correlational ( There is No intervention, only collection of data) 3) correlational ( There is No intervention, only collection of data).

In each of the following situations, data are obtained by conducting .pdf

amitbagga0808

i need a summary book report on thw Iwo by richard wheeler Solution As part of my ongoing research on a historical novel I want to write set in the 1930s and 40s, I bought this book on the Battle of Iwo Jima. My father was there as a radioman and gunner on a landing craft, and I had known some basic information about the battle, but this book did a good job of filling in the gaps. Further, Wheeler does a thorough job of including the visceral details that add both incredible realism and admiration for those who experienced this battle. A wounded veteran of Iwo Jima himself, Wheeler did comprehensive interviewing as part of the background research for this book. He also interviewed Japanese survivors and got access to letters written by notable Japanese soldiers such as General Tadamichi Kuribayashi, the architect of the defenses on Iwo and commander of forces there. Having the Japanese perspective added greatly to the telling of the story. This is not fiction; this was a nonfiction retelling of the story. There was substantial detail in the recounting of many individual incidents. The only downside of the story was that it was encyclopedic in approach. Whether it was the chosen approach of the author or his writing style, the story never got personal. Perhaps if it had gotten too personal, the numerous anecdotes would have suffered somehow. Unfortunately, I found the writing stiff and formal, more like a textbook than narrative. The information and individual incidents were extensive, visceral and incredible. Wheeler writes in one place of a Marine who suffered injuries from five artillery shells, one after the other, but remarkable survived them, albeit with major injuries. He also goes into detail as to which units were involved in which assaults and who took the most damage, include Easy Company’s assault on Mount Surabachi and the famous hoisting of American colors on that mountain..

i need a summary book report on thw Iwoby richard wheelerSolut.pdf

amitbagga0808

18 Alicia climbs into the passenger side of her boyfriend Bo\'s car. In an attempt to impress Alicia, Bo speeds away from the curb as Alicia\'s head presses against the headrest. What allows Alicia to sense this linear acceleration? A When thrust backward, the medulla sends signals to the cortex. B When thrust backward, the cerebellum sends signals to the cortex. C Hair cells in the cochlea bend with the forward motion. D Hair cells in the vestibular system bend with the forward motion. Solution 18. Option D. Hair cells in the vestibular system bend in the forward motion. Vestibular system (otolithic organs) makes us aware of the balance, acceleration. 23. Option C.think the apple and the potato are the same. Smell and taste receptors work together to give a sense of the taste of the food. 25. Option B. safe Infants are hard wired to know that sweet taste is deliciuos and nutritious and bitter means poison..

18 Alicia climbs into the passenger side of her boyfriend Bos car. .pdf

amitbagga0808

More from amitbagga0808 (20)