2. Complex Numbers
Because the square of any real number can't be negative,
the equation x2 = β1 does not have any real solution.
3. Complex Numbers
Because the square of any real number can't be negative,
the equation x2 = β1 does not have any real solution.
We make up a new number called an imaginary number
οβ1
to be a solution of this equation
4. Complex Numbers
Because the square of any real number can't be negative,
the equation x2 = β1 does not have any real solution.
We make up a new number called an imaginary number
οβ1 β i
to be a solution of this equation and we name it β i β,
5. Complex Numbers
Because the square of any real number can't be negative,
the equation x2 = β1 does not have any real solution.
We make up a new number called an imaginary number
οβ1 β i
to be a solution of this equation and we name it β i β, i.e.
(Β±i)2 = β1
6. Complex Numbers
Using i, the βsolutionsβ of the equations of the form
Because the square of any real number can't be negative,
the equation x2 = β1 does not have any real solution.
We make up a new number called an imaginary number
οβ1 β i
to be a solution of this equation and we name it β i β, i.e.
(Β±i)2 = β1
x2 = βr
7. Complex Numbers
Using i, the βsolutionsβ of the equations of the form
Because the square of any real number can't be negative,
the equation x2 = β1 does not have any real solution.
We make up a new number called an imaginary number
οβ1 β i
to be a solution of this equation and we name it β i β, i.e.
(Β±i)2 = β1
x2 = βr
are x = Β± iοr
8. Complex Numbers
Using i, the βsolutionsβ of the equations of the form
Example A. Solve x2 + 49 = 0 using imaginary numbers.
Because the square of any real number can't be negative,
the equation x2 = β1 does not have any real solution.
We make up a new number called an imaginary number
οβ1 β i
to be a solution of this equation and we name it β i β, i.e.
(Β±i)2 = β1
x2 = βr
are x = Β± iοr
9. Complex Numbers
Using i, the βsolutionsβ of the equations of the form
Example A. Solve x2 + 49 = 0 using imaginary numbers.
Using the square-root method:
x2 + 49 = 0 β x2 = β49
Because the square of any real number can't be negative,
the equation x2 = β1 does not have any real solution.
We make up a new number called an imaginary number
οβ1 β i
to be a solution of this equation and we name it β i β, i.e.
(Β±i)2 = β1
x2 = βr
are x = Β± iοr
10. Complex Numbers
Using i, the βsolutionsβ of the equations of the form
Example A. Solve x2 + 49 = 0 using imaginary numbers.
Using the square-root method:
x2 + 49 = 0 β x2 = β49 so
x = Β±οβ49
Because the square of any real number can't be negative,
the equation x2 = β1 does not have any real solution.
We make up a new number called an imaginary number
οβ1 β i
to be a solution of this equation and we name it β i β, i.e.
(Β±i)2 = β1
x2 = βr
are x = Β± iοr
11. Complex Numbers
Using i, the βsolutionsβ of the equations of the form
Example A. Solve x2 + 49 = 0 using imaginary numbers.
Using the square-root method:
x2 + 49 = 0 β x2 = β49 so
x = Β±οβ49
x = Β±ο49οβ1
x = Β±7i
Because the square of any real number can't be negative,
the equation x2 = β1 does not have any real solution.
We make up a new number called an imaginary number
οβ1 β i
to be a solution of this equation and we name it β i β, i.e.
(Β±i)2 = β1
x2 = βr
are x = Β± iοr
12. A complex number is a number of the form
a + bi
where a and b are real numbers,
Complex Numbers
13. A complex number is a number of the form
a + bi
where a and b are real numbers, a is called the real part
Complex Numbers
14. A complex number is a number of the form
a + bi
where a and b are real numbers, a is called the real part and
bi is called the imaginary part of the complex number.
Complex Numbers
15. A complex number is a number of the form
a + bi
where a and b are real numbers, a is called the real part and
bi is called the imaginary part of the complex number.
Complex Numbers
Example B. 5 β 3i, 6i, β17 are complex numbers.
16. A complex number is a number of the form
a + bi
where a and b are real numbers, a is called the real part and
bi is called the imaginary part of the complex number.
Complex Numbers
Example B. 5 β 3i, 6i, β17 are complex numbers.
The imaginary part of 5 β 3i is β3i.
17. A complex number is a number of the form
a + bi
where a and b are real numbers, a is called the real part and
bi is called the imaginary part of the complex number.
Complex Numbers
Example B. 5 β 3i, 6i, β17 are complex numbers.
The imaginary part of 5 β 3i is β3i. The real part of 6i is 0.
18. A complex number is a number of the form
a + bi
where a and b are real numbers, a is called the real part and
bi is called the imaginary part of the complex number.
Complex Numbers
Example B. 5 β 3i, 6i, β17 are complex numbers.
The imaginary part of 5 β 3i is β3i. The real part of 6i is 0.
Any real number a is also complex because a = a + 0i
hence β17 = β17 + 0i.
19. A complex number is a number of the form
a + bi
where a and b are real numbers, a is called the real part and
bi is called the imaginary part of the complex number
Example B. 5 β 3i, 6i, β17 are complex numbers.
The imaginary part of 5 β 3i is β3i. The real part of 6i is 0.
Any real number a is also complex because a = a + 0i
hence β17 = β17 + 0i.
Complex Numbers
(Addition and subtraction of complex numbers)
Treat the "i" as a variable when adding or subtracting complex
numbers.
20. A complex number is a number of the form
a + bi
where a and b are real numbers, a is called the real part and
bi is called the imaginary part of the complex number
Complex Numbers
(Addition and subtraction of complex numbers)
Treat the "i" as a variable when adding or subtracting complex
numbers.
Example C.
(7 + 4i) + (5 β 3i)
Example B. 5 β 3i, 6i, β17 are complex numbers.
The imaginary part of 5 β 3i is β3i. The real part of 6i is 0.
Any real number a is also complex because a = a + 0i
hence β17 = β17 + 0i.
21. A complex number is a number of the form
a + bi
where a and b are real numbers, a is called the real part and
bi is called the imaginary part of the complex number
Complex Numbers
(Addition and subtraction of complex numbers)
Treat the "i" as a variable when adding or subtracting complex
numbers.
Example C.
(7 + 4i) + (5 β 3i) = 7 + 4i + 5 β 3i
Example B. 5 β 3i, 6i, β17 are complex numbers.
The imaginary part of 5 β 3i is β3i. The real part of 6i is 0.
Any real number a is also complex because a = a + 0i
hence β17 = β17 + 0i.
22. A complex number is a number of the form
a + bi
where a and b are real numbers, a is called the real part and
bi is called the imaginary part of the complex number
Complex Numbers
(Addition and subtraction of complex numbers)
Treat the "i" as a variable when adding or subtracting complex
numbers.
Example C.
(7 + 4i) + (5 β 3i) = 7 + 4i + 5 β 3i = 12 + i
Example B. 5 β 3i, 6i, β17 are complex numbers.
The imaginary part of 5 β 3i is β3i. The real part of 6i is 0.
Any real number a is also complex because a = a + 0i
hence β17 = β17 + 0i.
23. A complex number is a number of the form
a + bi
where a and b are real numbers, a is called the real part and
bi is called the imaginary part of the complex number
Complex Numbers
(Addition and subtraction of complex numbers)
Treat the "i" as a variable when adding or subtracting complex
numbers.
Example C.
(7 + 4i) + (5 β 3i) = 7 + 4i + 5 β 3i = 12 + i
(7 + 4i) β (5 β 3i)
Example B. 5 β 3i, 6i, β17 are complex numbers.
The imaginary part of 5 β 3i is β3i. The real part of 6i is 0.
Any real number a is also complex because a = a + 0i
hence β17 = β17 + 0i.
24. A complex number is a number of the form
a + bi
where a and b are real numbers, a is called the real part and
bi is called the imaginary part of the complex number
Complex Numbers
(Addition and subtraction of complex numbers)
Treat the "i" as a variable when adding or subtracting complex
numbers.
Example C.
(7 + 4i) + (5 β 3i) = 7 + 4i + 5 β 3i = 12 + i
(7 + 4i) β (5 β 3i) = 7 + 4i β 5 + 3i
Example B. 5 β 3i, 6i, β17 are complex numbers.
The imaginary part of 5 β 3i is β3i. The real part of 6i is 0.
Any real number a is also complex because a = a + 0i
hence β17 = β17 + 0i.
25. A complex number is a number of the form
a + bi
where a and b are real numbers, a is called the real part and
bi is called the imaginary part of the complex number
Complex Numbers
(Addition and subtraction of complex numbers)
Treat the "i" as a variable when adding or subtracting complex
numbers.
Example C.
(7 + 4i) + (5 β 3i) = 7 + 4i + 5 β 3i = 12 + i
(7 + 4i) β (5 β 3i) = 7 + 4i β 5 + 3i = 2 + 7i
Example B. 5 β 3i, 6i, β17 are complex numbers.
The imaginary part of 5 β 3i is β3i. The real part of 6i is 0.
Any real number a is also complex because a = a + 0i
hence β17 = β17 + 0i.
27. (Multiplication of complex numbers)
To multiply complex numbers, use FOIL, then set i2 to be (-1)
and simplify the result.
Complex Numbers
28. (Multiplication of complex numbers)
To multiply complex numbers, use FOIL, then set i2 to be (-1)
and simplify the result.
Complex Numbers
Example D. (4 β 3i)(2 + 7i)
29. (Multiplication of complex numbers)
To multiply complex numbers, use FOIL, then set i2 to be (-1)
and simplify the result.
Complex Numbers
Example D. (4 β 3i)(2 + 7i) FOIL
= 8 β 6i + 28i β 21i2
30. (Multiplication of complex numbers)
To multiply complex numbers, use FOIL, then set i2 to be (-1)
and simplify the result.
Complex Numbers
Example D. (4 β 3i)(2 + 7i) FOIL
= 8 β 6i + 28i β 21i2 set i2 = (-1)
= 8 β 6i + 28i + 21
31. (Multiplication of complex numbers)
To multiply complex numbers, use FOIL, then set i2 to be (-1)
and simplify the result.
Complex Numbers
Example D. (4 β 3i)(2 + 7i) FOIL
= 8 β 6i + 28i β 21i2 set i2 = (-1)
= 8 β 6i + 28i + 21
= 29 + 22i
32. (Multiplication of complex numbers)
To multiply complex numbers, use FOIL, then set i2 to be (-1)
and simplify the result.
Complex Numbers
Example D. (4 β 3i)(2 + 7i) FOIL
= 8 β 6i + 28i β 21i2 set i2 = (-1)
= 8 β 6i + 28i + 21
= 29 + 22i
The conjugate of (a + bi) is (a β bi) and viceβversa.
33. (Multiplication of complex numbers)
To multiply complex numbers, use FOIL, then set i2 to be (-1)
and simplify the result.
Complex Numbers
Example D. (4 β 3i)(2 + 7i) FOIL
= 8 β 6i + 28i β 21i2 set i2 = (-1)
= 8 β 6i + 28i + 21
= 29 + 22i
The conjugate of (a + bi) is (a β bi) and viceβversa.
The most important complex number multiplication formula is
the product of a pair of conjugate numbers.
34. (Multiplication of complex numbers)
To multiply complex numbers, use FOIL, then set i2 to be (-1)
and simplify the result.
Complex Numbers
Example D. (4 β 3i)(2 + 7i) FOIL
= 8 β 6i + 28i β 21i2 set i2 = (-1)
= 8 β 6i + 28i + 21
= 29 + 22i
(Conjugate Multiplication)
The conjugate of (a + bi) is (a β bi) and viceβversa.
The most important complex number multiplication formula is
the product of a pair of conjugate numbers.
35. (Multiplication of complex numbers)
To multiply complex numbers, use FOIL, then set i2 to be (-1)
and simplify the result.
Complex Numbers
Example D. (4 β 3i)(2 + 7i) FOIL
= 8 β 6i + 28i β 21i2 set i2 = (-1)
= 8 β 6i + 28i + 21
= 29 + 22i
(Conjugate Multiplication) The nonzero conjugate product is
(a + bi)(a β bi) = a2 + b2 which is always positive.
The conjugate of (a + bi) is (a β bi) and viceβversa.
The most important complex number multiplication formula is
the product of a pair of conjugate numbers.
36. (Multiplication of complex numbers)
To multiply complex numbers, use FOIL, then set i2 to be (-1)
and simplify the result.
Complex Numbers
Example D. (4 β 3i)(2 + 7i) FOIL
= 8 β 6i + 28i β 21i2 set i2 = (-1)
= 8 β 6i + 28i + 21
= 29 + 22i
Example E.
(4 β 3i)(4 + 3i)
The conjugate of (a + bi) is (a β bi) and viceβversa.
The most important complex number multiplication formula is
the product of a pair of conjugate numbers.
(Conjugate Multiplication) The nonzero conjugate product is
(a + bi)(a β bi) = a2 + b2 which is always positive.
37. (Multiplication of complex numbers)
To multiply complex numbers, use FOIL, then set i2 to be (-1)
and simplify the result.
Complex Numbers
Example D. (4 β 3i)(2 + 7i) FOIL
= 8 β 6i + 28i β 21i2 set i2 = (-1)
= 8 β 6i + 28i + 21
= 29 + 22i
Example E.
(4 β 3i)(4 + 3i) = 42 + 32 = 25
The conjugate of (a + bi) is (a β bi) and viceβversa.
The most important complex number multiplication formula is
the product of a pair of conjugate numbers.
(Conjugate Multiplication) The nonzero conjugate product is
(a + bi)(a β bi) = a2 + b2 which is always positive.
38. (Multiplication of complex numbers)
To multiply complex numbers, use FOIL, then set i2 to be (-1)
and simplify the result.
Complex Numbers
Example D. (4 β 3i)(2 + 7i) FOIL
= 8 β 6i + 28i β 21i2 set i2 = (-1)
= 8 β 6i + 28i + 21
= 29 + 22i
Example E.
(4 β 3i)(4 + 3i) = 42 + 32 = 25
(ο5 β 7i)(ο5 + 7i)
The conjugate of (a + bi) is (a β bi) and viceβversa.
The most important complex number multiplication formula is
the product of a pair of conjugate numbers.
(Conjugate Multiplication) The nonzero conjugate product is
(a + bi)(a β bi) = a2 + b2 which is always positive.
39. (Multiplication of complex numbers)
To multiply complex numbers, use FOIL, then set i2 to be (-1)
and simplify the result.
Complex Numbers
Example D. (4 β 3i)(2 + 7i) FOIL
= 8 β 6i + 28i β 21i2 set i2 = (-1)
= 8 β 6i + 28i + 21
= 29 + 22i
Example E.
(4 β 3i)(4 + 3i) = 42 + 32 = 25
(ο5 β 7i)(ο5 + 7i) = (ο5)2 + 72
The conjugate of (a + bi) is (a β bi) and viceβversa.
The most important complex number multiplication formula is
the product of a pair of conjugate numbers.
(Conjugate Multiplication) The nonzero conjugate product is
(a + bi)(a β bi) = a2 + b2 which is always positive.
40. (Multiplication of complex numbers)
To multiply complex numbers, use FOIL, then set i2 to be (-1)
and simplify the result.
Complex Numbers
Example D. (4 β 3i)(2 + 7i) FOIL
= 8 β 6i + 28i β 21i2 set i2 = (-1)
= 8 β 6i + 28i + 21
= 29 + 22i
Example E.
(4 β 3i)(4 + 3i) = 42 + 32 = 25
(ο5 β 7i)(ο5 + 7i) = (ο5)2 + 72 = 54
The conjugate of (a + bi) is (a β bi) and viceβversa.
The most important complex number multiplication formula is
the product of a pair of conjugate numbers.
(Conjugate Multiplication) The nonzero conjugate product is
(a + bi)(a β bi) = a2 + b2 which is always positive.
42. Complex Numbers
(Division of Complex Numbers)
To divide complex numbers, we write the division as a fraction,
then multiply the top and the bottom of the fraction by the
conjugate of the denominator.
43. Complex Numbers
(Division of Complex Numbers)
To divide complex numbers, we write the division as a fraction,
then multiply the top and the bottom of the fraction by the
conjugate of the denominator.
3 β 2i
4 + 3i
Example F. Simplify
44. Complex Numbers
(Division of Complex Numbers)
To divide complex numbers, we write the division as a fraction,
then multiply the top and the bottom of the fraction by the
conjugate of the denominator.
3 β 2i
4 + 3i
Example F. Simplify
Multiply the conjugate of the denominator (4 β 3i) to the top
and the bottom.
(3 β 2i)
(4 + 3i)
45. Complex Numbers
(Division of Complex Numbers)
To divide complex numbers, we write the division as a fraction,
then multiply the top and the bottom of the fraction by the
conjugate of the denominator.
3 β 2i
4 + 3i
Example F. Simplify
Multiply the conjugate of the denominator (4 β 3i) to the top
and the bottom.
(3 β 2i)
(4 + 3i)
=
(4 β 3i)
(4 β 3i)
*
46. Complex Numbers
(Division of Complex Numbers)
To divide complex numbers, we write the division as a fraction,
then multiply the top and the bottom of the fraction by the
conjugate of the denominator.
3 β 2i
4 + 3i
Example F. Simplify
Multiply the conjugate of the denominator (4 β 3i) to the top
and the bottom.
(3 β 2i)
(4 + 3i)
=
(4 β 3i)
(4 β 3i)
* 42 + 32
47. Complex Numbers
(Division of Complex Numbers)
To divide complex numbers, we write the division as a fraction,
then multiply the top and the bottom of the fraction by the
conjugate of the denominator.
3 β 2i
Example F. Simplify
Multiply the conjugate of the denominator (4 β 3i) to the top
and the bottom.
(3 β 2i)
(4 + 3i)
=
(4 β 3i)
(4 β 3i)
* 42 + 32 =
25
4 + 3i
48. Complex Numbers
(Division of Complex Numbers)
To divide complex numbers, we write the division as a fraction,
then multiply the top and the bottom of the fraction by the
conjugate of the denominator.
3 β 2i
4 + 3i
Example F. Simplify
Multiply the conjugate of the denominator (4 β 3i) to the top
and the bottom.
(3 β 2i)
(4 + 3i)
=
(4 β 3i)
(4 β 3i)
* 42 + 32 =
25
12 β 8i β 9i + 6i2
49. Complex Numbers
(Division of Complex Numbers)
To divide complex numbers, we write the division as a fraction,
then multiply the top and the bottom of the fraction by the
conjugate of the denominator.
3 β 2i
4 + 3i
Example F. Simplify
Multiply the conjugate of the denominator (4 β 3i) to the top
and the bottom.
(3 β 2i)
(4 + 3i)
=
(4 β 3i)
(4 β 3i)
* 42 + 32 =
25
12 β 8i β 9i + 6i2
β6
50. Complex Numbers
(Division of Complex Numbers)
To divide complex numbers, we write the division as a fraction,
then multiply the top and the bottom of the fraction by the
conjugate of the denominator.
3 β 2i
4 + 3i
Example F. Simplify
Multiply the conjugate of the denominator (4 β 3i) to the top
and the bottom.
(3 β 2i)
(4 + 3i)
=
(4 β 3i)
(4 β 3i)
* 42 + 32 =
25
12 β 8i β 9i + 6i2
β6
6 β 17i
=
25
6
25
17i
β
51. Complex Numbers
(Division of Complex Numbers)
To divide complex numbers, we write the division as a fraction,
then multiply the top and the bottom of the fraction by the
conjugate of the denominator.
3 β 2i
4 + 3i
Example F. Simplify
Multiply the conjugate of the denominator (4 β 3i) to the top
and the bottom.
(3 β 2i)
(4 + 3i)
=
(4 β 3i)
(4 β 3i)
* 42 + 32 =
25
12 β 8i β 9i + 6i2
β6
6 β 17i
=
25
6
25
17i
β
Using the quadratic formula, we can solve all 2nd degree
equations and obtain their complex number solutions.
52. Complex Numbers
(Division of Complex Numbers)
To divide complex numbers, we write the division as a fraction,
then multiply the top and the bottom of the fraction by the
conjugate of the denominator.
3 β 2i
4 + 3i
Example F. Simplify
Multiply the conjugate of the denominator (4 β 3i) to the top
and the bottom.
(3 β 2i)
(4 + 3i)
=
(4 β 3i)
(4 β 3i)
* 42 + 32 =
25
12 β 8i β 9i + 6i2
β6
6 β 17i
=
25
6
25
17i
β
Example G. Solve 2x2 β 2x + 3 = 0 and simplify the answers.
Using the quadratic formula, we can solve all 2nd degree
equations and obtain their complex number solutions.
53. Complex Numbers
(Division of Complex Numbers)
To divide complex numbers, we write the division as a fraction,
then multiply the top and the bottom of the fraction by the
conjugate of the denominator.
3 β 2i
4 + 3i
Example F. Simplify
Multiply the conjugate of the denominator (4 β 3i) to the top
and the bottom.
(3 β 2i)
(4 + 3i)
=
(4 β 3i)
(4 β 3i)
* 42 + 32 =
25
12 β 8i β 9i + 6i2
β6
6 β 17i
=
25
6
25
17i
β
Example G. Solve 2x2 β 2x + 3 = 0 and simplify the answers.
To find b2 β 4ac first: a = 2, b = β2, c = 3,
Using the quadratic formula, we can solve all 2nd degree
equations and obtain their complex number solutions.
54. Complex Numbers
(Division of Complex Numbers)
To divide complex numbers, we write the division as a fraction,
then multiply the top and the bottom of the fraction by the
conjugate of the denominator.
3 β 2i
4 + 3i
Example F. Simplify
Multiply the conjugate of the denominator (4 β 3i) to the top
and the bottom.
(3 β 2i)
(4 + 3i)
=
(4 β 3i)
(4 β 3i)
* 42 + 32 =
25
12 β 8i β 9i + 6i2
β6
6 β 17i
=
25
6
25
17i
β
Example G. Solve 2x2 β 2x + 3 = 0 and simplify the answers.
To find b2 β 4ac first: a = 2, b = β2, c = 3, so b2 β 4ac = β20.
Using the quadratic formula, we can solve all 2nd degree
equations and obtain their complex number solutions.
55. Complex Numbers
(Division of Complex Numbers)
To divide complex numbers, we write the division as a fraction,
then multiply the top and the bottom of the fraction by the
conjugate of the denominator.
3 β 2i
4 + 3i
Example F. Simplify
Multiply the conjugate of the denominator (4 β 3i) to the top
and the bottom.
(3 β 2i)
(4 + 3i)
=
(4 β 3i)
(4 β 3i)
* 42 + 32 =
25
12 β 8i β 9i + 6i2
β6
6 β 17i
=
25
6
25
17i
β
Example G. Solve 2x2 β 2x + 3 = 0 and simplify the answers.
To find b2 β 4ac first: a = 2, b = β2, c = 3, so b2 β 4ac = β20.
x =
2 Β± οβ20
4
Using the quadratic formula, we can solve all 2nd degree
equations and obtain their complex number solutions.
Hence
56. Complex Numbers
(Division of Complex Numbers)
To divide complex numbers, we write the division as a fraction,
then multiply the top and the bottom of the fraction by the
conjugate of the denominator.
3 β 2i
4 + 3i
Example F. Simplify
Multiply the conjugate of the denominator (4 β 3i) to the top
and the bottom.
(3 β 2i)
(4 + 3i)
=
(4 β 3i)
(4 β 3i)
* 42 + 32 =
25
12 β 8i β 9i + 6i2
β6
6 β 17i
=
25
6
25
17i
β
Example G. Solve 2x2 β 2x + 3 = 0 and simplify the answers.
To find b2 β 4ac first: a = 2, b = β2, c = 3, so b2 β 4ac = β20.
x =
2 Β± οβ20
4 =
2 Β± 2οβ5
4
Using the quadratic formula, we can solve all 2nd degree
equations and obtain their complex number solutions.
Hence
57. Complex Numbers
(Division of Complex Numbers)
To divide complex numbers, we write the division as a fraction,
then multiply the top and the bottom of the fraction by the
conjugate of the denominator.
3 β 2i
4 + 3i
Example F. Simplify
Multiply the conjugate of the denominator (4 β 3i) to the top
and the bottom.
(3 β 2i)
(4 + 3i)
=
(4 β 3i)
(4 β 3i)
* 42 + 32 =
25
12 β 8i β 9i + 6i2
β6
6 β 17i
=
25
6
25
17i
β
Example G. Solve 2x2 β 2x + 3 = 0 and simplify the answers.
To find b2 β 4ac first: a = 2, b = β2, c = 3, so b2 β 4ac = β20.
x =
2 Β± οβ20
4 =
2 Β± 2οβ5
4 =
2(1 Β± iο5)
4 =
1 Β± iο5
2
Using the quadratic formula, we can solve all 2nd degree
equations and obtain their complex number solutions.
Hence
59. The powers of i go in a cycle as shown below:
i
-1 = i2
Powers of i
60. The powers of i go in a cycle as shown below:
i
-1 = i2
-i = i3
Powers of i
61. The powers of i go in a cycle as shown below:
i
-1 = i2
-i = i3
1 = i4
Powers of i
62. The powers of i go in a cycle as shown below:
i = i5
-1 = i2
-i = i3
1 = i4
Powers of i
63. Complex Numbers
Exercise D. Divide by rationalizing the denominators.
2 + 3i
i
24.
3 β 4i
i
25.
3 β 4i
i
26.
1 + i
1 β i
27. 2 β i
3 β i
28. 3 β 2i
2 + i
29.
2 + 3i
2 β 3i
30.
3 β 4i
3 β 2i
31.
3 β 4i
2 + 5i
32.
33. Is there a difference between β4i and 2i?
64. The powers of i go in a cycle as shown below:
i = i5
-1 = i2 = i6 ..
-i = i3
1 = i4
Powers of i
65. The powers of i go in a cycle as shown below:
i = i5
-1 = i2 = i6 ..
-i = i3 = i7 ..
1 = i4
Powers of i
66. The powers of i go in a cycle as shown below:
i = i5
-1 = i2 = i6 ..
-i = i3 = i7 ..
1 = i4 = i8 ..
Powers of i
67. The powers of i go in a cycle as shown below:
i = i5 = i9 ..
-1 = i2 = i6 ..
-i = i3 = i7 ..
1 = i4 = i8 ..
Powers of i
68. The powers of i go in a cycle as shown below:
i = i5 = i9 ..
-1 = i2 = i6 ..
-i = i3 = i7 ..
1 = i4 = i8 ..
Example H. Simplify i59
Powers of i
69. The powers of i go in a cycle as shown below:
i = i5 = i9 ..
-1 = i2 = i6 ..
-i = i3 = i7 ..
1 = i4 = i8 ..
Example H. Simplify i59
59 = 4*14 + 3,
Powers of i
70. The powers of i go in a cycle as shown below:
i = i5 = i9 ..
-1 = i2 = i6 ..
-i = i3 = i7 ..
1 = i4 = i8 ..
Example H. Simplify i59
59 = 4*14 + 3,
hence i59 = i4*14+3
Powers of i
71. The powers of i go in a cycle as shown below:
i = i5 = i9 ..
-1 = i2 = i6 ..
-i = i3 = i7 ..
1 = i4 = i8 ..
Example H. Simplify i59
59 = 4*14 + 3,
hence i59 = i4*14+3 = i4*14+3
Powers of i
72. The powers of i go in a cycle as shown below:
i = i5 = i9 ..
-1 = i2 = i6 ..
-i = i3 = i7 ..
1 = i4 = i8 ..
Example H. Simplify i59
59 = 4*14 + 3,
hence i59 = i4*14+3 = i4*14+3 = (i4)14 i3
Powers of i
73. The powers of i go in a cycle as shown below:
i = i5 = i9 ..
-1 = i2 = i6 ..
-i = i3 = i7 ..
1 = i4 = i8 ..
Example H. Simplify i59
59 = 4*14 + 3,
hence i59 = i4*14+3 = i4*14+3 = (i4)14 i3 = 114 i3
Powers of i
74. The powers of i go in a cycle as shown below:
i = i5 = i9 ..
-1 = i2 = i6 ..
-i = i3 = i7 ..
1 = i4 = i8 ..
Example H. Simplify i59
59 = 4*14 + 3,
hence i59 = i4*14+3 = i4*14+3 = (i4)14 i3 = 114 i3 = i3 = -i
Powers of i
75. Quadratic Formula and Complex Numbers
and
From example G, the solutions of 2x2 β 2x + 3 = 0 are
x =
1 + iο5
2
x = 1 β iο5
2
because b2 β 4ac = β20 < 0.
76. Quadratic Formula and Complex Numbers
and
From example G, the solutions of 2x2 β 2x + 3 = 0 are
x =
1 + iο5
2
x = 1 β iο5
2
because b2 β 4ac = β20 < 0.
Therefore we have a complex conjugate pair as solutions.
77. Quadratic Formula and Complex Numbers
and
From example G, the solutions of 2x2 β 2x + 3 = 0 are
x =
1 + iο5
2
x = 1 β iο5
2
In general, for ax2 + bx + c = 0 with a, b, and c real numbers,
and b2 β 4ac < 0,
because b2 β 4ac = β20 < 0.
Therefore we have a complex conjugate pair as solutions.
78. Quadratic Formula and Complex Numbers
x =
βb +οb2 β 4ac
2a
x =
βb βοb2 β 4ac
2a
and
From example G, the solutions of 2x2 β 2x + 3 = 0 are
x =
1 + iο5
2
x = 1 β iο5
2
and
In general, for ax2 + bx + c = 0 with a, b, and c real numbers,
and b2 β 4ac < 0, then its two roots:
because b2 β 4ac = β20 < 0.
are of the form A + Bi and A β Bi, a conjugate pair.
Therefore we have a complex conjugate pair as solutions.
79. Quadratic Formula and Complex Numbers
x =
βb +οb2 β 4ac
2a
x =
βb βοb2 β 4ac
2a
and
If a, b, and c are real numbers, then the complex roots* for
ax2 + bx + c = 0
are a complex conjugates pair. ( * if b2 β 4ac < 0).
From example G, the solutions of 2x2 β 2x + 3 = 0 are
x =
1 + iο5
2
x = 1 β iο5
2
and
In general, for ax2 + bx + c = 0 with a, b, and c real numbers,
and b2 β 4ac < 0, then its two roots:
because b2 β 4ac = β20 < 0.
are of the form A + Bi and A β Bi, a conjugate pair.
Therefore we have a complex conjugate pair as solutions.
80. Quadratic Formula and Complex Numbers
x =
βb +οb2 β 4ac
2a
x =
βb βοb2 β 4ac
2a
and
If a, b, and c are real numbers, then the complex roots* for
ax2 + bx + c = 0
are a complex conjugates pair. ( * if b2 β 4ac < 0).
From example G, the solutions of 2x2 β 2x + 3 = 0 are
x =
1 + iο5
2
For example, if x = i is a solution of #x2 + # x + # = 0,
then automatically x = β i is the other root (# real numbers.)
x = 1 β iο5
2
and
In general, for ax2 + bx + c = 0 with a, b, and c real numbers,
and b2 β 4ac < 0, then its two roots:
because b2 β 4ac = β20 < 0.
are of the form A + Bi and A β Bi, a conjugate pair.
Therefore we have a complex conjugate pair as solutions.
81. Complex Numbers
In what sense are the complex numbers, numbers?
Real numbers are physically measurable quantities (or the
lack of such quantities in the case of the negative numbers).
Theoretically, we can forever improve upon the construction of
a stick with length exactly ο2. But how do we make a stick of
length 3i, or a cookie that weighs 3i oz? Well, we canβt.
Imaginary numbers and complex numbers in general are not
physically measurable in the traditional sense. Only the real
numbers, which are a part of the complex numbers, are
tangible in the traditional sense.
Complex numbers are directional measurements.
They keep track of measurements and directions,
i.e. how much and in what direction (hence the twoβ
component form of the complex numbers).
Google the terms βcomplex numbers, 2D vectorsβ for further
information.
83. Complex Numbers
Exercise D. Divide by rationalizing the denominators.
2 + 3i
i
24.
3 β 4i
i
25.
3 + 4i
i
26.
1 + i
1 β i
27. 2 β i
3 β i
28. 3 β 2i
2 + i
29.
2 + 3i
2 β 3i
30.
3 β 4i
3 β 2i
31.
3 β 4i
2 + 5i
32.
Simplify
33. i92
38. Find a and b if (a + bi) 2 = i.
34. i β25 36. i 205
37. i β102
39. Is there a difference between β4i and 2i?
84. Complex Numbers
(Answers to odd problems) Exercise A.
1. 5 3. 7 + (2 β β5) i
Exercise B.
9. 10 11. 25
Exercise C.
17. 11 β 3i 19. β 25i
5. β5 β i 7. β1/4 + 5/3 i
13. 54 15. 72
21. β 2i 23. 21 + 20i
Exercise D.
β 4 β 3i
25. 27.
33. 1
i 29.
1
5
(4 β 7i) 31.
1
13
(17 β 6i)
37. β 1 39. There is no difference