4. Uniting Quantaum article.pdf

*Corresponding Author: Paul T E Cusack, Email: St-michael@hotmail.com
RESEARCH ARTICLE
Available Online at
Asian Journal of Mathematical Sciences 2017; 1(3):120-144
www.ajms.in
Uniting Quantum Mechanics & Cosmology
*
Paul T E Cusack1
*1
BScE, DULE, 1641 Sandy Point Rd., Saint John, NB E2K 5E, Canada
Received on: 20/03/2017, Revised on: 09/04/2017, Accepted on: 16/05/2017
ABSTRACT
This paper examines the mathematical physics that allows for the uniting Quantum Mechanics with
Cosmology. Using the Universal Model established in a previous work, Astro-Theology, we build upon
that foundation to use the Golden Mean Parabola to solve Schrodinger’s famous Wave Equation. Several
new Physics equations are established and the Uncertainty Principle is quashed. This solution shows that
the Universe is deterministic. The solution to this problem of an probabilistic universe is overturned.
Keywords: Wave Equation, HermitianOperators, Golden Mean Parabola, Clairnaut, Quanta, Uncertainty
INTRODUCTION
Here is the solution that allows for quantum Mechanics and Cosmology to be unified mathematically.
Energy, Angular Momentum, Schrodinger’s Equation, and Relativity are considered in turn. There is no
uncertainty in the Physical world as the following illustrates.
Consider the Rotational Matrix Ro={cos α -sin α / sin α cos α}
[MATHEMATICS FOR QUANTUM MECHANICS, J D JACKSON, DOVER]]
x'=Ro. *x
x'=∑ α x
Let a=π
v=∂s/∂t=∫π*x ∂x
v=π* x²/2
v=Pis²/2=2.618=∂M/∂t +i
v=∂M/∂t +i
2=v-i
1+1.618=v
1+ ψ=v -ψ=v-1ψ=1/ (√(2π)* ∫ e-t
∂t
(v-1) T Period=e-t
ψ* T=e-t
405=e-t
t=3.7025=1/27=1/c³
t=1/c³
1=(1/(-2c²)
-2=1/c²
c²=1/2
c=i/√2=i/ sin 45°
ψ=1/c²
c^2=1/ψ=(i/√2)^2=-1/2
1/ψ=-1/2

Paul T E Cusack et al. Uniting Quantum Mechanics& Cosmology
121
© 2017, AJMS. All Rights Reserved.
ψ=-2=-∂M/∂t (Degradation of Mass)
i=c* √2 =0.42397~cuz
q=Q cos (2π / T)(x/v-t)
Circ=1.602 cos (2Pi / 253) *(1-t)/ L
2πR=126.2=∂q/∂t=(1-t)/L
1.09801=1-t
t=0.998~1
The Law that governs QM is the charge density.
Vol charge density= lim ∂q/∂Vol
1.602=(2πR)/ 19905
R=2
1.602 (19905)=1/π=freq
A'=1/t
1=A'* t
1=Circ*t
1/t=Circ
E=1/t
C0o=Circ/ Vol
C0 * Vol=Circ
M0=F * d =0.1585 =sin θ* s
0.1585/(4/3)=sin θ
sin θ = 118.9 (118 Chemical Elements)
4.486/ (118.9* 938)=402.11=Re Re/ sin θ = Mp+/M Re=Inertia F / Viscous F=sin (0.1696/)/ sin
(0.2699)=6.383~h =2/Pi h=(∂M/∂t)/ t ∂M/∂t=ht
2=6.36*t
t=Pi
ψ= 1/ √ [2π] ∫ eikx
Continuous Matrix:
Elements = e-(-0.618)(1(1) =1.8552 =106.29°
Ω={cos 106° -sin 106° / sin 106° cos 106°}
={-0.2806 -0.9599 / 0.9599 -0.2806}
=259.794
√259.794=1.618
Operator Ω=π
Operator Ω-1
=1/π
Orthogonal Matrix = cos Ω -sin Ω / sin Ω cos Ω)
Ω* Ω-1
=1=H
n=1 l=0.75 m=4.482
m/l=5.976~6
Or 60 °
√3=Mc²
√3=4.486c²
c^2=259
c=1.618=t
1`/c²=0.113
AJMS,
May-June,
2017,
Vol.
1,
Issue
3

122
CUSACK'S ENERGY EQUATION E=Mt
[from David Bohm]
h²/ (2M)* l(l+1)/ R²=p²/ (2M)
=(6.36)²/ (2(4.482)* (0.75(1.75)/2²
=1.48~p²/ (2(4.482)
c* M=K.E.
p²=0.1326~1334=s
p=365.24 (Earth Year)
So, why is there a Resistance to Mass? Why does Energy repel then attract?
It is so because the angular momentum is caused by the spin. As the radius arm R is lifted, the angular
momentum is increasing until the Rm is overcome. Then the Energy goes into Mass formation,
sin 30 °=x/Rm
R2x
Rm=cuz 2(0.4233)=x
x=0.8466
Sin 60°=x/R
Radius R=x/ 0.866=0.8466/0.866-=0.9769~1.0236
0.9769/0.4233=02.3079
Ln (23.079)=Pi
CUSACKS ANGULAR MOMENTUM EQUATION
Ln (R/rm)=π
m=1
ψ=√[3/(8*π) * sin θ * eiθ
ψ=1/ √[Ft]* F * E
But I=Ft=|E|²
ψ=(1/E )*F* E
ψ=tF E
ψ=IE
I=1.618/ eiθ
i=-0.618
I=3.0017~c
The Impulse is the speed of light.
∫P²=[(l+m)!]/[(l-m!)]* 2/{2l+1)
=1
l=3/4
∫P=0.7353
P=√ 0.7353=0.8575~858
sin θmin=0.015
15% is the efficient multiplier.
For Lagrange Polynomials, (D. Bohm)
l=s
3.4=4/4
16=9
4²=3²
|D|²=c²
=|D|²/c²
=(cos²-sin ²)^2/c²
Let sin θ= cos θ and take the derivative
AJMS,
May-June,
2017,
Vol.
1,
Issue
3

123
cos²θ- -sin ²θ)/ 2c
2cos² θ/c=0.5614 =1/17.8=1/F=E
1/E=t=57.29°=1 rad
L/h=√[l*(l+1)]
(87/6.36)²=l²-l
l²-l-0.18712=0
l=[1+ √ 0.251)]/2
CUSACK'S TOTAL ANGULAR MOMENTUM QUANTUM NUMBER FORMULA
l={E+ √T]/ Gc l=Mass Gap/ E''
Mass Gap=l*0.75=1.5
sin theta min=1/ √[l+1]
theta =49.1 degrees=0.857 rads=E min
∂ψ/∂θ=cot θ=1/√3 * 0.857 =1.1132 =1/c²
c=2.997 TRUE
∂ψ/∂t=l * cot φ
2t-1=cot 60° =2t-1=1/√3
t=12679=ρ
t=1/ρ
K.E.=1/ρ
t²-t-1=E
(1/0.12679)²-(1/0.12679)-1=1.644~1/6
E=Mc²
1.644=M (9) M=1852
=n/p+
Vol=4/3πR^3
Vol'=4/3π 3R²/2 =251=T Period
Angular Momentum=Ω²R
(1/c²)^2 (1)
=1.2277
P=Mv²
1.2277=M * (0.8415)²
1.73=√3
K.E.=1/2 M Ω²* x²
=1/2(4.482)(1/c²)(0.8415²) =176.3~1 rad
Ln 1.763=1.7355=√3=E
Ln (K.E.)=E K.E.=t
TIME is K.E.
For a cycle and a half N=1.5
2πN=942.48
p2/p1=402.47/2.1722=1852
p2=M2v
n/ H+=1.0086554/1.00819=1853
2.1729=1.0086554 v
v=2.1107
2.1107/sin 1=250.8=T Period
TRANSMITIVITY
The Transitivity =c=2.9979
AJMS,
May-June,
2017,
Vol.
1,
Issue
3

124
T=|A|²/|D|²=12/4=3
I derived the following formula for the speed of light:
Tr.=1/ [1+ (1/4) sin (υ/10)]
Or
T=1/[1+1(0.25)F]
So the mass of a Neutron and Electron is:
c* freq
=2.9979* 1/π=941.8
sin (n *π x/ L)
(π* √ 2)/ (8.7)=51.07~0.5199=Mass of e
940.8/0.4233=222.2
2221.2/4.482=1/0.2018 =`1/ Dampened cosine curve.
2.018-0.4233=1.59~1.6=1/6
The Eigen function of the K.E.=p²(2M) is given by
ψ=sin (n*π* x/ L)
Since the critical operator is π
sin π=0
So, n*π *x/L=c=2.9979
n=116.9=116
n *π * x / L=116*π* x/ 8.7
x=01.333=4/3=s
This simple equation gives the mass and space from the Eigen function of the Clairnaut Equation.
t²-t-1=E
π²-π-1=5.729=1 rad
E=h v =6.36* (0.8415) =5.35
E=Mc² =(4.482)(2.9979)^2 =402.8 =Re
402.8=h/(λ/υ) λ/υ=6.36/402.8=1578=Moment
λ/ υ=λ=027=1578 λ=04263~cuz
P=h/λ=6.36/λ
And P=Mv=4648=6.36/ λ]
λ=0.1368
0863
3.1658
5.3519/402.8=0.133
1-0.133=0.866=sin 60°
The Speed of Light is minimized when sin 60°=0.866
The constant of motion is, of course, the speed of light c
E=Mc² =(4.482)(3)² =0.403=Re =Inertial F/ Viscous F =1089
∫ I=∫ft=sin t* t²/2
2178=sin θ * t²
1/t=196 Or ∞
For Hermitian Operator cH=c=3
(E+t)/ [h * H]
=π/3
2/[6.36*3]=π/3
∂²E/∂t²/[h*c)=Pi/3
G/c(1/h)=π/3
6.67/6/37=π/3
h*Ω=G=∂²E/∂t²
HAMILITONIAN OPERATOR
The Hermitian Operator for the universe =1. The Anti-Hermitian Operator =√(-1)=0.618
AJMS,
May-June,
2017,
Vol.
1,
Issue
3

125
H/ H*=1.618=ψ
Emin/ t=--1.2533/05=2506=T Period
α=Ω²* R =(1²2 =2 =G=E=∂²E/∂t²
α-G=0
α=G
Once you have G, all the other variables precipitate. alpha is caused by the spin of the universe. The spin
is caused by the Force = sin theta. The force is caused by the charge Co. The co is the result of the Area
of a circle = to the circumference. That is y=y' where the continuous meets the discrete.
I=Ft
∫I=cuz=F* ∫t
cuz=sin t* t^2/2
t=1
∫I=Pi-e ∫ I=(t-E)
E=0576=1/√3=cot 60°
T=∂q/∂t
∫T=q =I=Ft
T²/2=q
T=√(2q)
T=250.6
q=π=Ω
From QM:
√(2π)=1/t * e-t
E²=√(2π)
E=0.1583~01585=Moment.
So the Impulse is the Moment=1-sin 1
IMPULSE
I=Ft=T Period
8/3(t=2506)
t=6.68~G
t=G
K.E.=1/Mv² v=a
K.E.=1/2 (4.482)(2506)² =0.0947
T=a=1/√ (2π) * e-t
/ sin 60°=1/ √ [2PΩ*i]* π
π=Ω
Vector Space
(E+t)/ O=6.36=h=Planck's Constant
Angular Momentum
K.E.=1/2M Ω² x²
0.947=1/2(4.482)(1)(x²)
x=0.4233=cuz
For a circle:
Circ=A'
2πR=PiR²
R²/R=2
R=2=∂²E/∂t²
AJMS,
May-June,
2017,
Vol.
1,
Issue
3

126
∂R/∂t=R/t=0.4233
∂³E/∂t³=C1=0.4223
∫ℂ=∫ r=R^2/2=(0.4233)³/2=2.71= e
The more the universe spins, the more it wants to spin because of the opposite charges caused by the
spinning. When the Rm is overcome, the Energy is stored iin the Mass of the Universe. Spin causes a
charge; charge causes a spin.
V=iR
emf=V=4/3 * 0.4233
=0.5644
1/√π
emf * G=1/sqrt Pi * 6.66=118.12 Chemical Elements in the Periodic table.
The density=ρ=0.1267
If the current density =0.12676, that is equal to the Period T =freq=1/π
So a wave is Energy in motion. We know E=t²-t-1
Therefore ∂E/∂t=2t-1
∂²E/∂t²=2
Since v=a
∂E/∂t=d^2E/dt^2=2t-1=2
y=y'
2t=3
t=3/2=1.5 (Mass Gap)
E=1/t=0666=G
Clairnaut
And,
(15)²-1.5-1=1/4
E/t=1/4/1.5=1.667=1/6
ρ=M/Vol
T* 1/π=ρ
M *1/π=M/Vol
Vol=π
(E+t)/ π=M
(E+_t)=M * Vol
4.482* π=14.08
0.858
Ln (0.858)=-0.1532=1/G
And that is our universe.
Say that the smallest entity is a string is the same mistake to say that an electron is a particle. A sting is
not a physical entity, I theorize, but a wave. It is simply Energy or vibrations. Everything in the universe
is Energy. It’s all there is. Now I await someone to invent a phasor that can interrupt a human beings
wave energy so as to destroy him or her.
The frequency of the Human Mind = 1.π as we well know by now.
T* 1/Pi=ρ
The Human Mind is tuned to the universe.
s=v=a
s/v=v/a=s/v
s/v [=} m* s/m=s=t
F=Ma is proportional to a=ψ=1/ √[2π]* ∫e-t∂
t
a=1/ sqrt [2π] * e-t
/ sin θ
Let t=1, θ = 1 rad=60°
a=1/√[2Pi]* π
a=250.6~251==Period T
This is how QM is solved in relation to Cosmology.
AJMS,
May-June,
2017,
Vol.
1,
Issue
3

127
[2*2π]/[(4+ t) *Ω}=1=E
E/(2* (E+t))=1/4
t²-t-1=E
(1/4)²-1/4-1=118.75=Elements in the Periodic Table.
An electron "particle" is an interference between the Super force F=sin and the Schrodinger Wave
Equation
ψ=sin t+ 1/ sqrt [2π] * ∫e-t
k ∂k
8/3+ 1.618=sin t + 1/ √[2Pi]* e-t
k²/2
0.4285=sin t +2 e-t
k²
0.8475 = Ln (sin t)+ 0.6931 t* k²'
x-Ln x=0.6391 * t * 1.4657
0.8845=0.6931t³
127.6=t^3=ρ
F+t=ρ
F*s=t*s=M/Vol
W+ t/s=rho
E+ 3/4=0.1276 * 2
1.75(2)=M
M=1.5 (Mass Gap)
{QUANTUM THEORY, DAVID BOHM] states that if there were an indivisible[continuous], probability
[bell curve], wave-particle duality {1.618], system in the universe, then that system could be used to
make measurements on other systems. [WE CAN DO THAT MATHEMATICALLY]
The Bell Curve is a Fourier Integral:
f(x|μ, σ)=1/ [σ * √2π]* e-t
where t=(x-x )²/ (2σ)
Since the Wave Equation has this form and its solution is 1618, then:
ψ=1/ √(2π) * e-t
t=0.618 =(x-x )²/( 2σ)
Let σ=1
1.236=1/81=(x-x /σ)²=(x-x )²
S.D.=√ [(x-x )²/ N]
For 100%, k *σ=1-1/k²
k³-k²-1=0
roots
k1=1.46557
k2=0.023279+0.79255*i
k3=0.23279-0.79255 *i
S.D.=1/c²/ √N
N=√ 3=eigen vector
And,
Mt=E
0618*(1/81)=0.868
h/v²=c²
ΔP=2hv/c [D Bohm]
ΔP=2(h/c)(v/c)
∂M/∂t (v2-v1)=2(h/v)(v/c)
v2-v1=hv/c²
v2-0.8415=0.178
v2=6.635=1/1.5=1/ Mass Gap
v2=1/M
v2=0.223
AJMS,
May-June,
2017,
Vol.
1,
Issue
3

128
0.223-0.8415=0.618
=√(-1)
=t
CUSACK'S TIME- MASS-VELOCITY EQUATION
t=v2-1/M
Mt=P-1
2=P-1
P=3=c
P=Mv=3
M=1, v=a
CUSACK'S MOMENTUM EQUATION P=1-Mt
F*s=Work
W=sin 60° * 4/3=1.1547=1/sin 60°
F*s=W sin 60°=1/sin 60°
sin θ=1/sin ² θ=4/3
s=1/sin² 60°=1/√2=sin 45°=cos 45°
F=P
Ma=Mv
a=v=s/M
E=1/t
QUANTA
Time is continuous. Energy is a quanta. The universe exists where the tie (fraction =continuous) meets
the Energy (multiple=quanta.),or y=y'
So God is a creator and He is eternal. He creates Energy by putting a torque on it to produce time. Energy
is defined as the ability to do Work. Work is done against a Force. So God creates Energy by doing Work
against a force. Energy, time and space are interrelated by the cross product. The space s follows the sine
wave. So force and space are equal. Its the tension between the time and eternity that create space. Force
is a living entity. Revelation tells us that there are 4 living creatures. they are four columns carrying a
force. The resistance to carrying a load in Mass (P.E.)m is R m=π-e
P.E.=Mc²=Mgh
c²=gh
9=0.1585h
h=0.567
1--0.567=0.0433
1/K.E.=23.095=eπ
K.E.=1/eπ
=0.318=freq
1/2 Mv²=sin 60°
2* freq/v²=M=P.E.
h/v²=c² when M=1
Rm/C0=0.4233/1.602=0.2642
0.2642)³/2=08467
1-0.8467=0.1533
1/0.1533=-0.652=G=Ln 1.618/π
When Energy is squeezed, Gravity is the result when the Resistance to Mass is overcome.
THIS LINKS COSMOLOGY AND QM.
Interesting that if an experimenter intercepts a sine wave at the crest, the value is 1. If he intercepts it at
the x-axis, the value is 0. Probabilities range from 0 to 1.
AJMS,
May-June,
2017,
Vol.
1,
Issue
3

129
If we consider that the universe is filled with ether, and light must travel around it, where the
experimenter encounters the wave results in a Probability.
t²-t-1=E
Derivative:
2t-1=E'
Derivative:
2=E''=2=G
At first glance, I'd say light is a wave. It is a source of Energy that slips through the ether. Because only a
certain wavelength fits through the sphere packed kalonite, it it appears that is is quarantined. Reality is
continuous. Now Mass appears to break down in discrete quanta. However, it is really continuous for the
same reason as above. The Mass we perceive is discrete but it is really continuous.
∂²E/∂t²-E=0
G=E
Integral M=M2
/2
M²/2=c4
M² / c4
=2
M/c²=√ 2
c²/M=1/√ 2=sin 45°=cos 45°
qa1/qa2=1/√ 2
qa1=1=E=t
qa2=√2=√E²+ t²)
E/√(E²+t²)=t
sqrt (E²+t²)=1
E²+t^2==±1
(1)²+ (1)²=±1
2=1
∂M/∂t=E
∫∂M/∂t=M=∫E
M=E²/2
E²=M*2
E=√M * √2
E=2
sin t, cos t, Ln x, ex
, and Y are all continuous functions. But, the golden mean is discrete. They all meet at
1. 1 is discrete. the universe therefore exists where the continuous meets the discrete. Or,
y=y'
Or
CUSACK'S EQUATION
s=v=a
P=Mv =(9.109)(1.008) =924
H=p^2/ (2M)+ 1/2 M omega^2 x^2
1=(924)²/ [2* 9.109)+ 1/2 (9.109) (1)²(1)²
Ω=x=c
s=v=c
Ω²* x²=c4
=81
As the 7 levels of the fraction 1/81=0.012345679 are exhausted, no more atoms con be sustained by
fundamental forces. This is why there are 118 elements.
H=P.E. +K.E. 1=p²/ (2M)+1/2 M Ω² x²
Ω=1, x=L=1
AJMS,
May-June,
2017,
Vol.
1,
Issue
3

130
1=p²/(2(9.109))+ 1/2 (9.109)(1)1
(1)²
p=9.05=c²
E=Mc²
So, when the Momentum of light is c², the e- is dislodged. The force that is holding the electron on the
aton is c²=p²
E=Mc²=Mp²
p²/2M=E/M
p²E
E=0.868
p=2(0.868)=√3=Eigen Vector=2(sin 60°)=e-t
sin 60°
From the same Biblical verse:
10/5/30=1.0530
3.125 (Babylonian π)/ 1.0530=2.967~c
p²/ (2M)+v=E
v=6.68~~G
(0.1440+0.1385+0.1320)/2.9917=0.1385
0.8615 168
F=4.475/168=2.667=8/3=Force
sin-1
(0.26637)=0.1544 0.8455 57.72°
1.0075 rads= Hydrogen Mass = 1.007825
That the ratio of the circumference to the diameter of a circle is constant (namely, pi) has been recognized
for as long as we have written records. A ratio of 3:1 appears in the following biblical verse: And he
made a molten sea, ten cubits from the one brim to the other: it was round all about, and his height was
five cubits: and a line of thirty cubits did compass it about. (I Kings 7, 23; II Chronicles 4, 2.) The ancient
Babylonians generally calculated the area of a circle by taking 3 times the square of its radius ( =3), but
one Old Babylonian tablet (from ca. 1900-1680 BCE) indicates a value of 3.125 for π.
A cubit, or the length of one's forearm, according to the Biblical measurements, is 44 cm or 13.41 inches.
{CHRISTIAN COMMUNITY BIBLE] 10 cubits= 4.4~4.482=Mass 5 cubits=1385 (1/13.85=7.22
Kings) 13.85 OR 86.16 (1/86.2=116 elements in the Periodic Table of the Elements)
5 x 44=220 1/220=455
(455+4.4)/2=4.475~4.486 =Mass
4.55+4.4=c² =Speed of Light squared 30 cubits=1320 1320/3.281=402.3=Reynolds’s Number
13.20-100=868=sin 60 °= Force=Energy
So, E=Mc²
E=4.475* 8.95=4.00=(2(E+t)=2(1+1)=4 Vector Space E=0.868 =sin 60.2° (Energy and Time Vectors,
Babylonian Sexigesimal System) c=
√ (4.55+4.4)=21.9917=c =Speed of Light
4/2.9917=1.337~4/3=Space Energy: (0.1440+0.1385+0.1320)/2.9917=0.1385 0.8615 168
F=4.475/168=2.667=8/3=Super force sin-1
(0.26637)=0.1544 0.8455 57.72 ° 1.0075 rads= Hydrogen
Mass = 1.007825 Chronicles 2:42 1/ 2.42=0.4132 0.4132-3.125 (Babylonian π)=2.7118=Base e From
the same Biblical verse:
10/5/30=1.0530
3.125 (Babylonian π)/ 1.0530=2.967~c
p²/ (2M) +v=E v=6.68~G=Gravitational Constant
The 11 Dimensions of the universe are from the Interest formula (1+i)N
So the Ancients knew how to
calculate, Energy, Time, Space, Mass, Speed of Light, Gravitational Constant, Hamiltonian Kinetic and
Potential Energy, Universal Dimensions, Vector Spaces, and "Einstein's" Equation, Pi, Base e. From
these results the Gravitational Constant and all the other universal physical constants.
[QUANTUM THEORY, DAVID BOHM, DOVER]
P.E.Mc² 1.79/c²=2=∂M/∂t
n²=2M/ Planck² *(E-v)* c²/Ω²
AJMS,
May-June,
2017,
Vol.
1,
Issue
3

131
=2(4.482)/(6.36)² (1-0.8415)(3)²/1² =0.316 m²=π n=√π
h=1+√π
n=1+n=M*i M=252.79=Period T
From Snell's Law
sin t/1/ sin t2=n2/n1
Let n1=1
sin t2=sqrt π
t2=34.2°=0.597 rads ~0.6
T/t=252.79/0.596=0.4234~cuz
υ=(E1-E2)/h
But
h=M*i =(4.482)(0.618) =2.7699
υ=0.27
υ(h)=(0.27)(2.799)=74787~0.75=3/4=1/s
E1-E2=1-0.75=252.13=Period T
υ=T/h
CUSACK'S- FREQUENCY EQUATION
h=T/υ-=M*i
Ω ψ char.=ℂ ψ X Characteristic
π/3==60°=1=E
Normalized
H=1/ √ (∂x)
=1/ √ (s)=1/sqrt (4/3)
=√ 3/2=0.866
H=sin 60° =E
E=F=sin 60°
ρ=0.1272=M/Vol
∂ρ/∂t=[∂M/∂t]/[∂Vol/∂t]
Vol=4/3PiR³
∂Vol/∂t=(ds/∂t)(∂t/∂t)(3R³/2)
=0.8415*1*3/2*2^2 =0.8415 * 6
=0.505
Now ∂ρ/∂t=t
∂ρ=t ∂t ∂ρ=1
∂M/∂Vol=1
M=1/0.505=P.E=1/2 M Ω² * x² =1/2(4.482)(1/√π)^2 (0.8415) =P.E=Mc²
H=K.E. +P,.E.
E=Mc²
-QM
h=1+√π
LORENTZ-RELATIVITY
L=√[1+v²/c²]
h=(v²/c²)^2
=PLANCK h/c4
=h/M=i
L=√ [1+i]
=0.1272=ρ
ASTROTHEOLOGY-CUSACK'S UNIVERSE
Set
ψ= t²-t-1
ψ'=2t-1
AJMS,
May-June,
2017,
Vol.
1,
Issue
3

132
ψ''=2=E
i=0.618
i * h = -h²(2M) * ψ''
i=-h/M
0.618(4.482)=-h
h=2.77=1+π
=1+t=E
h=E
∇²* ψ= ∂²/dx² ψ +∂²/∂y²ψ+∂²/∂y²ψ
1/π=c
E=π c
E=Mc²
E(Mc) c
M=Pi/3=60°
For a right triangle with leg t=1, and leg E=√3
t²+c=E² 1+ √3=E
E=2.73
E=1+ t
2=1+1 true
Now, 1/t=1/π=c=v
1/t=E=c=v
E=v=0.8415
E=sin 1=e-t
t=√3=1.726=tan 60°
Continuing,
p²(2M)+ v=E
v=1/t
p²/(2M)=1
p²=M
M²v²=2M
(4.482)v²=2
v=6.68~G
M²G²=2M
MG=2
MG²=E
E=2.967~c
E=Mc²
c=Mc²
1=Mc
M=1/3
M²G²=4.94
1/M²G²=2.02~Y Dampened cosine curve
SCHRODINGER'S EQUATION
-h²/ (2M) L² ψ + v(r)* ψ=E* ψ
-6.36²/ (2*4.482) (1/π) (1.618)+v(r)(1.618)=(1)(1.618)
0.1436+v(r)=1
v(r)=0.8564 58.9°
[QUANTUM PHYSICS FOR BEGINNERS, JASON STEPHENSON]
H=K.E.+ P.E.=E=1
AJMS,
May-June,
2017,
Vol.
1,
Issue
3

133
H=L²/ (2I) 1=L²(2(0.1585))
L=1/√π=Ω
H=p²/ (2M)+1/2 M *Ω² x²
1=p²/ (2(4.482)+1/2(4.482)(1/√π)^2(0.8415)²
1=p²/ (2(4.482))+5.05
-4=p²/ (2(4.482))
p5.988~6
p=Mv
6=4.3482v
v=0.1336~4/3=s
ψ²=Intensity
(1+0.618)²= 1²+ (√(-1))= 0=Intensity
E=0, t=π for the sin wave.
y=y' takes something that is continuous ()sin t) and makes it discrete (point) . The Spiritual world is
continuous; the material world is discrete. Sunday, 13 March 2016
So the perceptible material universe exists where the complimentary variables are equal, or v=L
L=s and v=ds/dt
s=s'
s=v=a
If QM had been correct, human beings wouldn't be free. We would be ties to the laws of physics entirely
and have no capacity to escape. When the derivative is equal to the function, we humans become free as
the chain is broken.
How do we relate E and P and v and L
E=e-t
P=Mv
v=L
P/M = (sin t)v
P/M=M (a)v=Mc²=E
E=e-t
=W/s=F* (d/t)=(sin t)* v
E and v are related. So E and P, and v and L are related. That's the end of uncertainty.
P=h/λ
P=6.36/ 3
=2.12
I=P*t=2.12* π=6.66=G
G is the Impulse or change in Force. It is a dampening force,
Y=e-t
cos θ
G= e-t
cos π
G=e-t
6.67=e-t
t=0.405
1/t=2.4646
2.4647=(π/2)²
2.4646)²-2.4646-1=E
E=e-t
= 2.6207
0.9634~1=t
CONTINUOUS EXPERIENCE OF THE UNIVERSE OCCURS AT
t=π
F=sin θ= 1
θ=π=t
θ/ freq=π/ (1/π)=π²=Ω²
AJMS,
May-June,
2017,
Vol.
1,
Issue
3

134
RMS (Root Mean Square)=-√(π/2)=-1.2533
=Emin of the Energy Parabola when Jesus entered time.
IMPULSE
I=Ft
I=(sin t)t
P=∂I/∂t=cos t(1)
P=cos t
F=sin t
E=e^(-t)
W/t=E=F*d/t=e-t
(sin t)d/t)=e-t
(sin t)v=e-t
F*(P/M)=E
P=Mv
P/M=v
Ma=P/M=E
Pa=E
M * v* a=E
v=a
E=Mc²
t²-t-1=E
2t-1=E'
2=E''=∂M/∫t
E'=∫M
E=M²/2
But,
E=Mc²
Mc²=1/2 M²
G=2=M/c²
2/3=M/9
M=6
C=A'
2πR=πR²
R=2=G
R=M/c
(2)(3)=M=6
This is what the Ancients knew - the circle and the parabola.
∂x =P/M * ∂t
eπ=Mv/ M * π
eπ
/ π=Mv/M=0.1376
P=Mv
=2(0.1376) =275=11/4=M ({2(E+t)}
c=Mc^2
1=Mc
M=1/3
M^2G^2=4.94
1/M^2G^2=2.02~Y Dampened cosine curve
SCHRODINGER'S EQUATION
-h^2/ (2M) L^2 W.EQ. + v(r)* W.EQ. =E* W.EQ
-6.36^2/ (2*4.482) (1/Pi) (1.618)+v(r)(1.618)=(1)(1.618)
AJMS,
May-June,
2017,
Vol.
1,
Issue
3

135
0.1436+v(r)=1
v(r)=0.8564 58.9 degrees
CUSACK'S MOMENTUM EQUATION
P=N / [2(E+t)] (1+i)N
=2P(E+t) N(1+i)=Ln (2P*2)
1+i=Ln (4P)/N=0.126P
1+i=rho *P
1+i=M/ Vol* M *v
(1+i)/ M²=v/ Vol
Vol=4(0.8415)/ (1+cuz)
4/3Pi R³=23.649
R=17.8 kN
∂x/∂t=∂E/∂t
∂t=1/ freq=1/ 31.8 Hz=π
v=∂E/π=eπ
/ π=0.1376
1/v=0.862 59.59°
t²-t-1=E
2t-1=∂E/∂t
2=∂E²/∂t²=G
M=1/81=0.012345679
The Mass crests over between 7 and 9
∑E n=0==> 7 {0+1+2+3+4+5+6+7}/ 8=28/8=3.5
∫ E=E²/2
E²/2> ∂E²/∂t²
E²/∂t²=2=G
Clairnaut:
∂E²/∂t²-E=0
G-E=0
G=E
There is no uncertainty in the laws of nature. Experimenters just have no figured out how to measure
these effects yet.
e-t
=Rm + Ln E Money Supply=M.S.= 7=10/√2
7.07=(t-E)+ Ln E
8.07E=Ln E
E=0.868
If L=v (Position=Velocity)
∫L=∫v
M.S=L
∫L=L
M.S.=L=v
M.S.=sin θ = F=Ma=P=Mv
F=8/3=2.667
M.S./ I.M=sin θ * M
8.3=sin θ M²
8/3=0.8415 M²
M=3.16~π
I. M=π²=1.7802
π²/11521=1.7802/115=1.548~1.5 Mass Gap
=1/G
Since it takes money to make money, the more money one accumulates, the more one has to invest and
make more money. It is the same with Mass or matter. Gravity works the same for money as it does for
Matter.
AJMS,
May-June,
2017,
Vol.
1,
Issue
3

136
t²-t-1=E=e^(-t)
2Ln t-Ln t-0=-t
Ln t=-t
1/t=1
t=1
1/2 *E*t*s=1/2 (0.868)(1)(4/3)=1/√3
WAVE EQUATION
U+ iV=1+ (1)(0.618)=1.618
1.618=1/ √(2* π)* ek
k=14.001
Now,
(1+ et
)=1.73
et
=0.73
Ln (0.15t)=Ln 0.73
15t=3.14
t=2.098 =2.15
Ln (t)* Ln 2.15=3.069=c
Ln t=t
y=y'
MISTAKEN UNCERTAINTY PRINCIPLE
Pr(x)=1/sin θ
P(x)'=1/ [2sin²θ]
=1[2(0.8415)^2 =0.706~1/√2=sin 45° =cos 45°=Momentum =Force
0.706 say 7.06
M=1/81=0.01234567
1/1+1/1+....1/1
7(1/1)=7
M=0+ dM1
/∂t+∂M2
/∂t+.....∂M7
/∂t
=2(7)=14
ψ=1/√[2π]∫ek
∂ k
ek
=1.4001 say 1.4
M=Ln 1.618
G=π/Ln 1.618 =π/ M G=π/M No Uncertainty
G=π/(1/81) =251=Period T 1/ T=Re
WAVE EQUATION
ψ=ME=(80.8)(2)=1.616~1.618
E=Mc²
P.E.=M^2c²
F=ME F'=∂M/∂t * ∂E/∂t
y''=∂M²/∂t² * ∂E²/∂t²
(2)(∂M/∂t)(G)
4G=4* (2/3)=8/3=2.667=F
F=G M1M2/R²
M1M2/R²=∂M/∂t
Integrate
[M²/2* M]/R²=M
M²/2=R²
M²=2R²
M²=2
M=√2
M=√ 2
AJMS,
May-June,
2017,
Vol.
1,
Issue
3

137
M'=21.5
/ (1.5)
M''=2√2/3.75
=1.5=Mass Gap
Light
ψ[=]J/kg=m/s=s/t
c=s³/t
Light is Energy that acts on Mass that radiates in three dimensions.
The smallest particle that can be detected has a limit. It is:
1/d^2=1
d=√1=+/- 1
Since s must be positive, d=+1
For a circle, R=d/2=1/2
Energy is give by
t²-t-1=E
(1/2)²-(1/2)-1=-1.2533 (This is the Energy that Jesus enters creation at t=1/2)
Derivative:
2t-1=0 (Minimum)
2=1/2
So, R=1/2, t=1/2 s=t, E=1/t=1/s=1/ (1/2)=2
t²-t-1=2 t=1.5248,- 0.5248
Since t must be positive,
t=0.1998~0.2
1- 0.15248=0.8475
57.94°
Large Scale:
1/ (22* 2.9979)=0.1516
0.8484
58 °
The Human Mind is at the center of the Cosmic and Quantum Worlds. We can perceive it all.
FOURIER INTEGRAL
{QUANTUM THEORY DAVID BOHM]
The Fourier Integral is the dampened cosine curve already introduced.
The pulse of the universe is like a heartbeat, one dampened cosine curve after another.
Y=e-t
cos θ
Y'=et
sin θ
y=y'
cos θ = sin θ
ψ=1/ √ 2 / √π* ∫ ek
∂k
=1/√π * cos 45° ek
=1/ √π* Y
1/sqrt π * cos 45°= 0.3991~4
4=∑(E+ t) (Vector Space)
THIS UNITES COSMOLOGY WITH QUANTUM MECHANICS.
So, we've unified Cosmology with Quantum Mechanics and Electromagnetism. That is the Grand Unified
Theory.
t=-0.618+1618 =2.2236
t²-t=0.1236
t(t-1)=1/81 t=1/81, 0.01236
t=1/81=M
F=sin t=sin (1/81)=1/√2=sin 45°=cos 45°
AJMS,
May-June,
2017,
Vol.
1,
Issue
3

138
As F cycles, a charge like phenomenon dissipates on the Energy parabola (Characteristic Equation or
Eigen Equation) . This is why we sense quantum mechanics.
G=π/ Ln 1.618
G *Ln 1.618=π
eG
* 1.618=eπ
1/.618=eπ
/eG
=eπ-G
x=1/(x-1)
x=t
eπ-G
=1/t-1
E=1/t
e(π-G-e)
-eπ-G
=1
Taking Ln of both sides,
π-G-t-π+G=0
-t=0
t=0
1/t E=∞
t=0, E=∞ Heaven
Quantum Packages are released at every cycle of Pi. Human Perception is freq=1/π=31.8 Hz
When the continuous charge is built up drop by drop over this time, a quantum is released. This is when
the Energy of sin + cos is maximum, or its slope is 0. ∂E/∂t=0, t=1
The universe is really continuous is the Spiritual World. Humans however have evolve to sense only the
E max. Why?
Q=sin θ t=1. E=1
∫∂Q/∂t=∫π
Q=πQ
π=Q/Q=1
=quanta
Quanta=n*1
F=sin θ
∂F/∂t=cos θ
θ=π/4=1/ ρ
t=1/ρ=E E=ρ=0.127
1602/1273=79.5~80
1/81=0.01234567
The Mass crests over at the quanta. That is what humans perceive. The world outside the human mind is
continuous.
As F cycles, a charge like phenomenon dissipates on the Energy parabola (Characteristic Equation or
Eigen Equation) . This is why we sense quantum mechanics.
G=π/ Ln 1.618
G *Ln 1.618=π
eG
* 1.618=eπ
1/.618=eπ
/eG
=eπ-G
x=1/(x-1)
x=t
eπ-G
=1/t-1
E=1/t
e(π-G-e)
-eπ-G
=1
Taking Ln of both sides,
π-G-t-π+G=0
-t=0
t=0
1/t E=∞
AJMS,
May-June,
2017,
Vol.
1,
Issue
3

139
t=0, E=∞ Heaven
Quantum Packages are released at every cycle of Pi.
Human Perception is freq=1/π=31.8 Hz
When the continuous charge is built up drop by drop over this time, a quantum is released. This is when
the Energy of sin + cos is maximum, or its slope is 0. ∂E/∂t=0, t=1
The universe is really continuous is the Spiritual World. Humans however have evolve to sense only the
E max. Why?
Q=sin θ t=1. E=1
∫∂Q/∂t=∫π
Q=πQ
π=Q/Q=1
=quanta
Quanta=n*1
F=sin θ
∂F/∂t=cos θ
θ=π/4=1/ ρ
t=1/ρ=E E=ρ=0.127
1602/1273=79.5~80
1/81=0.01234567
The Mass crests over at the quanta. That is what humans perceive. The world outside the human mind is
continuous.
Electromagnetism
Jr²=cosγ
Ω=∫∫ S cos γ/r² ∂a=∫∫S J ∂a
J²/2=cos γ *1/r²
J² * r^2/2=cos γ
The Orb is 44 cm diameter. So
[(4/3)² * (44/2)²]/2=cos γ
γ=Pi/2
23.704/2=cos γ
118.52=cos γ
γ=83.2°=1.452 rads
An/A=cos θ
<E,t>=|An| I
I=current=1.334
s=|An| (4/3)
An=1
-sin θ= -a=An=1/ cos θ
sin θ(cos θ)=-1
sin θ =-(1/cos θ)
-cos θ=-1/2x²
-cosθ=1/ 2x²
-2cos ³θ (t)=1
cos³ θ =1/2
cos t=0.7937
t=37.467 ° = 6539 rads =π/ Ln 1.618=G
t=G
Now s=|E||t|cos θ
<E,t>=s=cos θ M=<E,t>
An/A=<E,t>=M
AJMS,
May-June,
2017,
Vol.
1,
Issue
3

140
An / A=cos θ An=A cos γ n
An=A<E,t>
1/An=cos θ
1/An=4/3
A=3/4 Spherical
z=r*cos θ
z=cos θ=r An
r=An
[QUANTUM THEORY, DAVID BOHM, DOVER]
For R=2
k=2Pi/ λ=2π/π=2 =R
R=sin θ=2 θ114.6°
sin 114.6 =0.9093 =c²
R=sin (c²)=cuz
Circumference=2πR=2Pi (cuz)=2.66=F
Classical, (Newton), Relativity (Einstein) and Quantum (Dirac) Theories are essentially correct, but
lacked the glue to hold them together. Cusack's Universe holds them together in one theory.
F=1-sin θ =Moment
F-1=F 2F=1
F=1/2
t²-t-1=E
E=-1.25
For a 30°-60°-90° triangle,
sin θ= √(3/2)
θ=60°
∂E/∂t=0 @t=0.5
t²-t-1=0
t=0.5
F/t=1/2/1/2=1
∂F/∂t=cos t
cos t= 1/2
t=60°
Since the charge on an electron isa quanta,
1/0.4233=23.624
Ln 23.624=3.162~π
1/3.162=3.162
G=Ln 1.618/π
π=Ln 1.618/ G
Ln (π)=Ln [Ln 1.618/ G]=262.91=ℂ =Re'
So this unifies Gravity, Quantum Mechanics and the Coulomb.
HEISENBERG'S UNCERTAINITY
[THE STRANGEST MAN, THJE HIDDEN LIFE OF PAUL DIRAC, MYSTIC OF THE ATOM]
Of course, we know by now that we can know both position and velocity of a particle at the same time. It
is found from the Reynold's Number.
Re=Inertia F/ Viscous F
Re=v*L / υ
Taking the derivative,
υ* Re=∂v/∂t * ∂L/∂t
υ Re'=a* v
AJMS,
May-June,
2017,
Vol.
1,
Issue
3

141
C!=a* v/ υ
C1=2.6227
Going back up,
υ* Re=∂v/∂t * ∂L/∂t
0.27(262)=a* ∂L/∂t
Integrating
∫0.27(262)∂t=v* L
0.27* 2.62*1=v* L
v=velocity, L= position
So
v=0,708/L
L=0.708/v
0.708~1/√2=sin 45°
CUSACK'S CERTAINTY EQUATION v=sin 45°/L
[PRINCIPLE OF QUANTUM MECHANICS, 2 ED., R SHANKAR]
Dot Product = Cross Product
sin θ = cos θ θ=45°
det A=[cos , sin
-sin , cos ]
=1
cos²+ sin²=1
θ= 45°
Dot Product = <f,g>=∫f(x)(g(x)Δ , Δ= L/[n+1]
From above,
=-2x/ (x-1) * ∞/ (∞ +1)
<f,g>=sin θ-=F,
cos θ=c
Delta= ∞/ [∞+1]=~1
<f,g>=sin θ* M=F * Mass
F Δ=FM=1/ sqrt 2
M=4.486
M√2= 1/F=E
4.486 * √2=6.3
F=1/6.3=0.1576
1-F=0.8424
t=sin-1
(0.8424)=1.0017 rads ~1
sin-1
(1-F)=t
1-F=sin t
1²-sin²=cos²
cos²θ =c²
Now,
Mp+= 936.26+0.201=938.27
cos θ=sin θ * M
c=FM
c²=F(Mc²)
c²/F=Mc²=E
E/c²+ c²/F=Mp+
(FE +x)/(c²X)=Mp+
E+1/c^2=Mp+
E+1=Mc²
E+E=Mc²
2E=Mc²
2 * 4.482 c²*x
x=00,4016~402=Re
AJMS,
May-June,
2017,
Vol.
1,
Issue
3

142
This shows that the Golden Mean is related to the Quantum Masses and the Reynolds's Number.
√2*1.618=2.2882
=π *c10
=2.8797
1.618(1/11)
=1.1042=1/c²=1/3.00943
This is how the Golden Mean parabola relates to the Mass of a proton and an electron.
c10
= {2.974/3}10
=0.9166
π=3.14159
π-0.9166=2.8797
1/2.8797=0.944~Mp+
0.944/0.93827=1.0061
1/1.0061=9939/{998.62+0.0005448}=0.9999=∞/ {∞ +1} ~1
ENERGY IS A VECTOR.
IT HAS A PURPOSE.
Time travel is possible at ∂E/∂t=1 or -1
We know,
x²+y²+R²
Let x=-y
2x²=1
x=1/ √2
This is the 45°-45°-90° triangle. sin 45° =1/√2
1/√2=E/√2=E/[e²+t²]=R²
E=R²[E²+t²]
R²E²-E+t²=0
This is the golden mean equation:
R²x=(x-1)/x
R² x²-x-1=0
Let R=1
x²-x-1=0
x=-0.618, 1.618 Ex²+Mx+c=0
Bessel Cylinder
∂/∂z² +1/z ∂/∂z+ (1-υ²/z²)[Z(x]=0
Let x=t=1
E²+1/81x+Lo]Z(1)=0
1+1/81+7.28=0 t+M+ s [e-t
)=a=28.5 9.5140
943 = M p+
951.4-943=0.84
57.14° = 1 rad
2A=√3
A=√(3/2)
F'=√(3/2)
θ= 30°
F=sin 30°=1/2
F'=-cos 30° =0.866 =sin 60
F(K) = 1/1! F' K1
=π
F(K)=1/2! F²' K²=Pi²
F(K)=1/3! F²' K³=π²
.......
1F'+1/2F''+ 1/3F'''....
F'=e
AJMS,
May-June,
2017,
Vol.
1,
Issue
3

143
e+e/2+e/3+......
e(harmonic series)
Y=E(1/x)
y'=ex²/2
F(π)=e/(2x²)
2x²=e/Pi
x=0.865=0.866=sin 60°
π+π²+π³...=e[1/1+1/2+1/3....]
[[MATHEMATICS FOR QUANTUM MECHANICS, J D JACKSON]
e(aK)
[f(x)]=f(x+a)
a=1.618
K=π
Ln [e1.618
+Ln π]* f(x)=f(x+1.618)
4.132* (f(x)=f(x+1.618)=x^2-x+1-1.618
4.132*(f(x)-1.618=0
f(x)=1.618/4.132=1/2554=1/T=t
OPERATOR
F (K) =∑1/n! * ∂1F (z)/∂t1 z=0 Kn
F (K) =∂F/∂t
y=y'
K=π
∫(Δ(x-a)=1
Δ=0.6 rads
-0.618<a<1.618
∫(x-a)=1.0.6
(x-a)² / 2=0.1666
(x-a)²-3.333=0
x²+1/81x+c=0
So,
Et²+Mt+c=0
E=Mc² E=1/t
c=cos t
Solving for four roots
t=1.562, 0.326
or
t=3.5264, 0.2028=Y
t cos t +1/t +1-cos t=0
t=61.9° L0=7.28=sin(sin 1))
Lo is the length of the sin curve from -2π - 1 rad.
1/x * cos x +1/x +1=23.61
Ln 23.61=π
CONCLUSION
So, we've unified Cosmology with Quantum Mechanics and Electromagnetism. That is the Grand Unified
Theory finished.
REFERENCES
1. BOHM, D. QUANTUM THEORY, , Dover, New York., 1951.
2. Cusack, P., REINMANN HYPOTHESIS, Journal of Physical Mathematics, OMI 2January 2016
3. Farmelo, G. THE STRANGEST MAN, THJE HIDDEN LIFE OF PAUL DIRAC, MYSTIC OF
THE ATOM, Basic Books., 2009
4. Grogan, P, CHRISTIAN COMMUNITY BIBLE, Claretian Publishing, Philippines. 1999.
AJMS,
May-June,
2017,
Vol.
1,
Issue
3

144
5. Jackson, J. D., MATHEMATICS FOR QUANTUM MECHANICS Dover,. W. A. Benjamin,
New York, 1962 edition.
6. Ronjansky, V.,ELECTROMAGNETYIC FIELDS AND WAVES, Dover., New York., 1970
7. Shankar, R., PRINCIPLE OF QUANTUM MECHANICS, 2 ED., Springer Science Business
Media, 1994.
8. Stephenson, J. QUANTUM PHYSICS FOR BEGINNERS, USA, 2015.
AJMS,
May-June,
2017,
Vol.
1,
Issue
3

4. Uniting Quantaum article.pdf

Recommended

Recommended

More Related Content

Similar to 4. Uniting Quantaum article.pdf

Similar to 4. Uniting Quantaum article.pdf (20)

More from BRNSS Publication Hub

More from BRNSS Publication Hub (20)

Recently uploaded

Recently uploaded (20)

4. Uniting Quantaum article.pdf