This document presents calculations using the matrix stiffness method to model the dynamic response of the universe. The author uses equations from structural engineering to model the universe under a compressive "Superforce" and calculate physical constants. Key equations include F=-ks, where F is force, k is stiffness, and s is deflection. The author concludes that the matrix stiffness method can accurately model how the universe is constructed.

1. *Corresponding Author: Paul T E Cusack, Email: St-michael@hotmail.com
RESEARCH ARTICLE
Available Online at www.ajms.in
Asian Journal of Mathematical Sciences 2017; 1(6):215-220
Universal Matrix (Stiffness) Method
*Paul T E Cusack
*BScE, DULE, 1641 Sandy Point Rd., Saint John, NB, E2K 5E8 Canada
Received on: 15/09/2017, Revised on: 20/10/2017, Accepted on: 20/11/2017
ABSTRACT
Here are some calculations on the dynamic response of the universe to the Superforce based on the matrix
stiffness method. We see that by using these methods, various physical parameters can be explained by
using these well tested methods.
Keywords: Stiffness method; matrix method; Astrotheology; Aerodynamic pressure
INTRODUCTION
Here we provide some interesting calculation based on the Matrix Stiffness Method, well know in
Structural engineering for determining the effect that forces have on a structure. The universe is under a
compressive force. There is no vacuum. Thus, we can see physical constants such as stiffness and mass
drop out in the calculations. Laursen provides an interesting equation for calculation of the moment on a
structure. This is used here to calculate the Superforce by yet another method. Also, the dummy or
virtual load is used to determine the monatomic gas constant. We begin with the classic stiffness
equation.
F=-ks
F/k=s
(1+1+1+1)/0.4233)=s=944.9=δ
s-Mp+
-G0+dm/dt
=944.8-938+6.52+0.20
=0.8
=1/1.25
=1/E
=t
Et=EM
For matrices, the special case where AB=BA is unusual.
A=[I]11
B=[k]11
=0.7818
B=(0.4233)11
=0.7819=1/ρ
F-ks where F is a vector
F=(1+1+1+1)=4
F/k=-s=-4/(0.4233) k11
=944.96 (0.7818)
=738.8
=938-200
F/k= -s=Mp+
-V
Where V=shear=dM/dt

2. Paul T E Cusack et al. Universal Matrix (Stiffness) Method
© 2017, AJMS. All Rights Reserved. 216
F/k=|M|
Where M=mass
ρ=|M|/F
127.9=|M|/ 2.66
|M|=2.939~c
The det M=c
c=F/k
kc=F
F=-ks
c=-s=δ
The speed of light is the deflection.
F=ks
=|k||M|
But, we know,
F/k=|M|
F=F/|M| |M|
F=F
F=ks=(0.4233)(2.9979)=126.9=ρ -1
ρ=F+1
= 0.2668+1
=1.2688
=ρ
Figure 1: Laursen [1]
Figure 2: Laursen, [1]
Laursen derives this equation below that can be used to calculate the Superforce as a Moment.
M=EI/(L)4
[4L3
θi
+2L³ θj
] [1, Laursen] pg 40
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3. Paul T E Cusack et al. Universal Matrix (Stiffness) Method
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=(0.4233)(1/202)/(1/2)4
[4(1/2)³(1)+(2)(1/2)³(1)]
=0.2688
=F
M=F ×d
M=F (1)
M=F
Now,
k=EI/L[ 4 2 / 2 4 ]
Taking the det [4 2 / 2 4]
=16-4
=12
k=(0.4233)(1/202)/(1/2) (12)
=503=1/k=f=1998
Dampened Cosine
Y=e1
cos [(2π)(1)]
=1988
For the Dummy load:
F=-ks
=1=k(1)
1=|k||M|
1=kc
F=1→ c=s
Operators
E=1/t
Et=1
1/π (π)=1=F
freq.=E=F ×d×t
-1/π=F dt
-1/π=-(1)(dt)
F=1=-dt²
-dt²-Et +1=0
d=1, E=1
-dt²+Et+1=0
Golden mean
t²-t-1=0
-E+F-F=0
-E=0
This is the value of the ln function at t=1, dE/dt=1
F=-ks
1/k × F=s
fF=s
σ=Eε
σ/E=ΔL/L
1/k (P/A)=ΔL/L
(1/k ×P) /A=ΔL/L
s/A=ΔL/L
A=L
A=1/2
√A=1/√2 =sin 45°=cos 45°
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4. Paul T E Cusack et al. Universal Matrix (Stiffness) Method
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Now
δ=PL/AE
1=(1)(1/2)/[1/√2)(0.4233)
=0.167
=γ
Momatomic Gas
d=AD
d=A(1)
F/k=A(1)
0.2668/0.4233=A
A=63.03
F × d=W=δd k A D
=(1)(0.4233)*F/k) (1)
F ×d =F
F=F
F/k=A=63.03=2/π
F=2.695~8/3=cc
Ln F=c Ln c
273=c
1=√3=c
t+E=c
δ+E=c
Y=E=c-δ
et
xcos (2πt)=c-δ
ds/dt+ s=Y’
v+s=EF
Aerodynamic Pressure
q=1/2 ρ v²
=1/2(1/k) v²
=1/2 f(sin θ)²
=(118.12)(sin 1)²
=0.5959
=1/1.67
=1/γ
γ=1.67 for a monatomic gas
Q=[A][k] where Q is the load, and A is the transformation Matrix [1]
F=(4.482)(0.4233)
F=1+c²
F=t+E/M
F=t+ Re
F=t+[I.F. /V.F.]
F=t[ × V.F. +I.F.] / V.F.
V.F.² =t F +P
F²-tF-Mv=0
Golden mean
F²-(1)F-(118)(0.8415)=0
F²-F-1=0
Finally, the physical constants summed:
M=4.482=118(0.4233)
Re=0.402
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5. Paul T E Cusack et al. Universal Matrix (Stiffness) Method
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freq.=0.318
k=0.4233
G=6.52
T=1/t=0.251
s=0.1334
∑=6.66=G
dM/dt=V=2
F=Ma=(118(0.8415)=1
P=mv=(118.2)(0.8415)=1
t=1 rad
E=1
∑=12.66=ρ
N=12
∑=23.67=Ln π
Q=AD
Where Q is the member loads;
A is the Transformation metric for the universe; and
D is the external deflection.
F=-ks
ΣQ= [12.66]=-[0.4233][c]
c=2.99079
Identity Matrix
Identity matrix =I=[1 0 00/ 0 1 0/ 0 0 1....]
1/UI=I
1/t=E
t=I=E
t=1/E=E
E²=1
E=√1=±1
Now consider the negaitveIdnetity Matrix.
1/-I=-I
1/-t=-E
-t=-I=-E
-t=1/-E=-E
E²=1 same as above!
E=√1=±1
The simplest equation that describes the universe and everythin in it is:
E²=1
1/t²=1
t²=1
E²=t²=1
There is only one, positive universe.
K.E. =q=1/2 ρv²
=1/2 M/Vol. v²
=1/2 M/Vol. × 1/ M²
q=1/[2 V1.333)(118.8)
=31.8 Hz
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6. Paul T E Cusack et al. Universal Matrix (Stiffness) Method
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=freq. of the human mind.
The only signal there is in the universe is q. The human mind is tuned to that frequentcy./
dE/dt=dt/dt=1
dE/dt=t=1
E=t²/2
E=1/2, t=1
E=cos t
E=cos 1=0.5403 April 3, 2005
The date the Idol of The Oppressor (The Great Abomination) was installed at the local Cathedral, Divine
Mercy Sunday, 2005.
Period T=1/freq.
T=1/[1/π]
=πIn harmonic analysis, Tmin⇒ m=0
The Characteristic Equation for the Universe is:
t²-t-1=0
Derivative
2t-1=0
t=1/2
T=π=1/t
Operator =π
π × 1/t=1/2
t=2π = 1 cycle
Between April 3, 2005 - January 6, 2018 (1.618) = 4660 days
=12 years 9 months 2 days =12.7=127.6=ρ
ρ=1/k=1/cuz=2.362
Ln 23.62~π
Convergence.
CONCLUSION
We see that the Matrix Stiffness is applicable and useful for calculating the way our universe really is
constructed.
REFERENCE
1. Laursen, H. I., Matrix Method of Structural Analysis. McGraw hill., 1966
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