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CATALYTIC FLUID-SOLID
REACTIONS
SURFACE KINETICS
Langmuir-Hinshelwood kinetics
Why heterogeneous catalysis
 Design of catalytic processes
requires a knowledge reactor
design, operation optimization
and selection.
Heterogeneous
 external mass transfer restrictions
 Surface reactions
 internal mass transfer restrictions
 Different phases
Homogeneous
 none
 none
 none
 Similar phases
Advantages
 Reduced energy requirements
 Easy product-catalyst separation
Heterogeneous catalyst
Major Differences
Basic Properties of catalyst
 A catalyst affects the rate of reaction but emerges from the process unchanged. A
catalyst usually changes a reaction rate by promoting a different molecular path for
a reaction and thereby lowering the activation energy.
Reaction examples
 A small amount of catalyst is often sufficient to bring about a considerable extent of
reaction. (huge surface area)
 The catalyst does not affect the equilibrium state
Steps in Heterogeneous Catalytic Reactions
Step 1: Transport of Reactants to the
Catalyst Surface
Step 2: Transport within the Porous
Catalyst
Step 3: Adsorption of Reactants
It is necessary that at least one of the
reactants attach itself (physical or
chemisorption) to the catalyst surface so
that the reaction proceeds
Step 4: Surface Reaction
Then chemical reaction occurs between adsorbed
species.
Step 5: Desorption of Products
The reverse of Step 3.
Step 6: Diffusion of the Products to the External
Catalyst Surface
This step is essentially the reverse of
Step 2.
Step 7: Transport of Products to the Bulk Fluid
The reverse of Step 1.
1.1 THE RATE EQUATION FOR SURFACE KINETICS
Langmuir Mechanism
• Chemical bonds are formed
• Adsorption sites are
energetically uniform
• Monolayer coverage
• No interaction between
absorbed
• Molecules
• It assumes mass law
describes individual steps
Other adsorption isotherms
Freundlich Adsorption
Isotherm
BET adsorption Isotherm
Langmuir Mechanism
Adsorption
𝐴 + 𝑆 ↔ 𝐴. 𝑆
Rate expression
𝑟𝑎 = 𝑘𝑎𝐶𝐴𝐶𝑠 with rate coefficient ka
𝑟𝑑 = 𝑘𝑑𝐶𝐴.𝑠 with rate coefficient kd
Schematic
The catalyst sites are either covered or covered such that:
𝐶𝑇 = 𝐶𝑠 + 𝐶𝐴𝑠
Where: 𝐶𝑠 vacant sites, 𝐶𝐴𝑠 sites occupied by A
At equilibrium adsorption is equal to
desorption
𝑘𝑑𝐶𝐴.𝑠 = 𝑘𝑎𝐶𝐴𝐶𝑠
Eliminating species difficult to measure
𝑘𝑑𝐶𝐴.𝑠 = 𝑘𝑎𝐶𝐴(𝐶𝑇−𝐶𝐴.𝑠)
𝑘𝑑𝐶𝐴.𝑠 = 𝑘𝑎𝐶𝐴𝐶𝑇 − 𝑘𝑎𝐶𝐴𝐶𝐴.𝑠
𝑘𝑑𝐶𝐴.𝑠 + 𝑘𝑎𝐶𝐴𝐶𝐴.𝑠 = 𝑘𝑎𝐶𝐴𝐶𝑇
𝐶𝐴.𝑠 =
𝑘𝑎𝐶𝐴𝐶𝑇
𝑘𝑑 + 𝑘𝑎𝐶𝐴
Divide by kd
𝐶𝐴.𝑠 =
𝐾𝐴𝐶𝐴𝐶𝑇
1 + 𝐾𝐴𝐶𝐴
Where KA = ka/kd
𝜃 =
𝐶𝐴.𝑠
𝐶𝑇
=
𝐾𝐴𝐶𝐴
1 + 𝐾𝐴𝐶𝐴
Langmuir Mechanism- Two species adsorbing same site
Adsorption
𝐴 + 𝑆 ↔ 𝐴. 𝑆
𝐵 + 𝑆 ↔ 𝐵. 𝑆
Rate expression
𝑟𝐶𝐴𝑆 = 𝑘𝑎𝐴𝐶𝐴𝐶𝑠 −𝑘𝑑 𝐶𝐴.𝑠
𝑟𝐵𝑆 = 𝑘𝑎𝐵𝐶𝐵𝐶𝑠 −𝑘𝑑𝐵 𝐶𝐵.𝑠
The catalyst sites are either covered or covered
such that:
𝐶𝑇 = 𝐶𝑠 + 𝐶𝐵𝑠 + 𝐶𝐴𝑠
Where: 𝐶𝑠 vacant sites, 𝐶𝐴𝑠 sites occupied by A
@ equilibrium
𝐾𝐴 =
𝐶𝐴.𝑆
𝐶𝐴𝐶𝑆
=
𝑘𝑎𝐴
𝑘𝑑𝐴
𝐶𝐴.𝑠 = 𝐾𝐴𝐶𝐴𝐶𝑠
𝐶𝐵.𝑠 = 𝐾𝐵𝐶𝐵𝐶𝑠
𝐶𝑇 = 𝐶𝑠 + 𝐾𝐵𝐶𝐵𝐶𝑠 + 𝐾𝐴𝐶𝐴𝐶𝑠
𝐶𝑆 =
𝐶𝑇
1 + 𝐾𝐵𝐶𝐵 + 𝐾𝐴𝐶𝐴
The concentration of absorbed species is given by:
𝐶𝑖.𝑆 =
𝐶𝑇𝐾𝑖𝐶𝑖
1 + 𝐾𝐵𝐶𝐵 + 𝐾𝐴𝐶𝐴
Langmuir Mechanism- if a molecule dissociate upon adsorption
Adsorption
𝐴2 + 2𝑆 ↔ 2𝐴. 𝑆
Rate expression
𝑟𝐶𝐴𝑆 = 𝑘𝑎𝐴𝐶𝐴𝐶𝑠 −𝑘𝑑 𝐶𝐴.𝑠
The catalyst sites are either covered or covered
such that:
𝐶𝑇 = 𝐶𝑠 + 𝐶𝐴𝑠
Where: 𝐶𝑠 vacant sites, 𝐶𝐴𝑠 sites occupied by A
@ equilibrium
𝐾𝐴 =
𝐶𝐴.𝑆
2
𝐶𝐴2
𝐶𝑆
2
𝐶𝐴.𝑠
2
= 𝐾𝐴𝐶𝐴𝐶𝑠
2
𝐶𝑇 = 𝐶𝑠 + 𝐾𝐴𝐶𝐴𝐶𝑠
2
𝐶𝐴.𝑆 =
𝐶𝑇 𝐾𝐴𝐶𝐴2
𝐶𝑠
1 + 𝐾𝐴𝐶𝐴2
Summary
i) Adsorption
ii) Different systems
a) 𝐴 + 𝑆 ↔ 𝐴. 𝑆
b) 𝐴 + 𝑆 ↔ 𝐴. 𝑆
𝐵 + 𝑆 ↔ 𝐵. 𝑆
c) 𝐴2+2𝑆 ↔ 2𝐴. 𝑆
NB: One method of checking whether a model predicts the behavior of experimental
data is to linearize the model equation and then plot the indicated variables against one
another
Exercise
Come up with a Langmuir equation for
dissociative adsorption of carbon monoxide on
platinum.
Surface reactions
 After the reactants have adsorbed onto the surface it is capable of reacting in a
number of ways to form a product: Langmuir-Hinshelwood kinetics
1) Single reaction
𝐴. 𝑆 ↔ 𝑆. 𝐵
 this reaction represents a
isomerization/ decomposition
reaction.
𝑟𝑠𝑟 = 𝑘𝑠𝑟𝐶𝐴.𝑠 −𝑘−𝑠𝑟 𝐶𝑆.𝐵
𝑟𝑠𝑟 = 𝑘𝑠𝑟 𝐶𝐴.𝑠 −
𝐶𝑆.𝐵
𝐾𝑆𝑅
Where; 𝑘𝑠𝑟-surface reaction rate coefficient
𝐾𝑆𝑅-surface reaction equilibrium coefficient
2) Dual sites
𝐴. 𝑆 + 𝑆 ↔ 𝑆. 𝐵 + 𝑆
The adsorbed reactant interacts with
another site (occupied or unoccupied)
to form product.
𝑟𝑠𝑟 = 𝑘𝑠𝑟 𝐶𝐴.𝑠𝐶𝑆 −
𝐶𝑆.𝐵𝐶𝑆
𝐾𝑆𝑅
Surface reactions
Another types of dual-sites mechanism is the reaction between two adsorbed
species
2) Dual sites (ii)
𝐴. 𝑆 + 𝐵. 𝑆 ↔ 𝑆. 𝐶 + 𝑆. 𝐷
Two species adsorbed on the same
type of sites
𝑟𝑠𝑟 = 𝑘𝑠𝑟 𝐶𝐴.𝑠𝐶𝐵.𝑆 −
𝐶𝑆.𝐶𝐶𝑆.𝐷
𝐾𝑆𝑅
3) Dual sites (iii)
𝐴. 𝑆 + 𝐵. 𝑆` ↔ 𝑆. 𝐶` + 𝑆. 𝐷
Two species adsorbed on different
type of sites
𝑟𝑠𝑟 = 𝑘𝑠𝑟 𝐶𝐴.𝑠𝐶𝐵.𝑆` −
𝐶𝑆`.𝐶𝐶𝑆.𝐷
𝐾𝑆𝑅
1.1 THE RATE EQUATION FOR SURFACE KINETICS
Eley-Rideal Mechanism
• Is for a reaction between an
absorbed molecule and a
molecule in the gas phase
𝐴. 𝑆 + 𝐵. (𝑔) ↔ 𝑆. 𝐶
Rate Law:
𝑟𝑠𝑟 = 𝑘𝑠𝑟 𝐶𝐴.𝑠𝑃𝐵 −
𝐶𝑆.𝐶
𝐾𝑆𝑅
Desorption
After the catalytic reactions the products subsequently have to desorb into the gas
phase
C. 𝑆 ↔ 𝑆 + 𝐶(𝑔)
Desorption rate:
𝑟𝐷𝑐 = 𝑘𝐷𝑐 𝐶𝐶.𝑠 −
𝐶𝑆𝑃𝐶
𝐾𝐷𝑐
Note that rate of desorption of C is opposite the rate of a adsorption of C
𝑟𝐷𝑐 = 𝑘𝐴𝐷𝑐
In addition the desorption equilibrium constant KDC is just the reciprocal of the
adsorption equilibrium constant.
𝑟𝐷𝑐 = 𝑘𝐷𝑐 𝐶𝐶.𝑠 − 𝐾𝐴𝑐𝐶𝑆𝑃𝐶
The Rate-limiting step
 At steady state the rates of each of the three
reaction steps in series (adsorption, surface
reaction and desorption) are equal.
 Usually one of the steps is rate limiting, the
process of coming with the rate is as follows:
i) Rates are written for individual steps assuming
they are reversible
ii) A rate limiting step is postulated and steps that
are not rate limiting are used to eliminate all
coverage-dependent terms
Adsorption controlling
C 𝑔 + 𝑆 𝑠 ↔ 𝑆. 𝐶(𝑠) adsorption
𝑟𝐴𝐷 = 𝑘𝐴𝐷 𝑃𝐶𝐶𝑠 −
𝐶𝐶𝐶.𝑆
𝐾𝐴𝐷
C. 𝑆 ↔ 𝐵. 𝑆 + 𝑃 surface reaction
𝑟𝑆 = 𝑘𝑆 𝐶𝐶.𝑆 −
𝑃𝑃𝐶𝐵.𝑆
𝐾𝑠
B. 𝑆 ↔ 𝑆 + 𝐵 desorption
𝑟𝐷 = 𝑘𝐷 𝐶𝐵.𝑆 −
𝑃𝐵𝐶𝑆
𝐾𝐷𝐵
But KDB is the reciprocal of KADB
𝑟𝐷 = 𝑘𝐷 𝐶𝐵.𝑆 − 𝐾𝐴𝐷𝐵𝑃𝐵𝐶𝑆
Assuming steady state
𝑟`𝑐 = 𝑟𝐴𝐷 = 𝑟𝑆 = 𝑟𝐷𝐷
If adsorption is controlling: kAD<<< Ks ,Kd
𝑟`𝑐 = 𝑟𝐴𝐷 = 𝑘𝐴𝐷 𝑃𝐶𝐶𝑠 −
𝐶𝐶𝐶.𝑆
𝐾𝐴𝐷
Since CS and CC.S can not be measured they need
to be replaced.Based on ealier assumption rs/ks &
rD/kD ̴ 0 while rAD/kAD is relative large.
𝑟𝑆 = 𝑘𝑆 𝐶𝐶.𝑆 −
𝑃𝑃𝐶𝐵.𝑆
𝐾𝑠
surface reaction
0 = 𝐶𝐶.𝑆 −
𝑃𝑃𝐶𝐵.𝑆
𝐾𝑠
Adsorption controlling
𝐶𝐶.𝑆 =
𝑃𝑃𝐶𝐵.𝑆
𝐾𝑠
𝑟𝐷 = 𝑘𝐷 𝐶𝐵.𝑆 − 𝐾𝐴𝐷𝐵𝑃𝐵𝐶𝑆 desorption
0 = 𝐶𝐵.𝑆 − 𝐾𝐴𝐷𝐵𝑃𝐵𝐶𝑆
𝐶𝐵.𝑆 = 𝐾𝐴𝐷𝐵𝑃𝐵𝐶𝑆
Therefore CC.S is equal
𝐶𝐶.𝑆 =
𝑃𝑃𝐾𝐴𝐷𝐵𝑃𝐵𝐶𝑆
𝐾𝑠
𝑟𝐴𝐷 = 𝑘𝐴𝐷 𝑃𝐶𝐶𝑠 −
𝑃𝑃𝐾𝐴𝐷𝐵𝑃𝐵𝐶𝑆
𝐾𝑠
𝐾𝐴𝐷
𝑟𝐴𝐷 = 𝑘𝐴𝐷 𝑃𝐶 −
𝑃𝐵𝑃𝑃
𝐾𝑃
𝐶𝑆
@ equilibrium
rAD approaches zero, 𝐾𝑃=
𝑃𝐵𝑒 𝑃𝑃𝑒
𝑃𝐶𝑒
=
𝐾𝐴𝐷 𝐾𝑆
𝐾𝐵
Equilibrium constant can be expressed Gibbs
energy
𝐶𝑇 = 𝐶𝑠 + 𝐶𝐶.𝑠 + 𝐶𝐵.𝑠
𝐶𝑇 = 𝐶𝑠 +
𝑃𝑃𝐾𝐴𝐷𝐵𝑃𝐵𝐶𝑆
𝐾𝑠
+𝐾𝐴𝐷𝐵𝑃𝐵𝐶𝑆
Solve for Cs
𝐶𝑠 =
𝐶𝑇
1 +
𝐾𝐴𝐷𝐵𝑃𝐵𝑃𝑃
𝐾𝑠
+ 𝐾𝐴𝐷𝐵𝑃𝐵
Initial rate of reaction is:
𝑟𝐴𝐷 =
𝑘𝐴𝐷 𝑃𝐶 −
𝑃𝐵𝑃𝑃
𝐾𝑃
𝐶𝑇
1 +
𝐾𝐴𝐷𝐵𝑃𝐵𝑃𝑃
𝐾𝑠
+ 𝐾𝐴𝐷𝐵𝑃𝐵
Surface reaction;Desorption
controlling
Surface reaction
𝑟𝑆 =
𝑘𝑠𝐾𝑐 𝑃𝐶 −
𝑃𝐵𝑃𝑃
𝐾𝑃
𝐶𝑇
1 + 𝐾𝐴𝐷𝐵𝑃𝐵 + 𝐾𝐶𝑃𝐶
Desorption
𝑟𝐷 =
𝑘𝐷𝐾𝑆𝐾𝑐 𝑃𝐶 −
𝑃𝐵𝑃𝑃
𝐾𝑃
𝐶𝑇
𝑃𝑃 + 𝐾𝐶𝑃𝐶𝐾𝑆 + 𝐾𝐶𝑃𝑃𝑃𝐶
Prove these rate equations
Rate Law analysis
Dependence on the product if products are
adsorbed to the surface, they do appear as a
denominator on the rate equation
𝑟 =
1 + 𝐾𝐶𝑃𝐶 + ⋯
Dependence on reactant and leveling off : this
normal suggest an expression as shown below
𝑟 =
𝑃𝑐
1 + 𝐾𝐶𝑃𝐶 + ⋯
References
1. Calvin H. Bartholomew and Robert J. Farrauto,
“Fundamentals of industrial catalytic processes”
JOHN WILEY & SONS, INC., 2 nd edition, 2006.
2. Octave Levenspiel., Chemical Reaction
Engineering, 3rd Edition, John Wiley & Sons,New
York, 1999
3. J. R Richardson and D. G Peacock., Chemical
Engineering volume 3, 3 rd Edition, Pergamon ,
1994
4. H. Scott Fogler, Essentials of Chemical Reaction
Engineering, Pearson Education International, 2010

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2._CATALYTIC_FLUID-SOLID_REACTIONS (1).pdf

  • 2. Why heterogeneous catalysis  Design of catalytic processes requires a knowledge reactor design, operation optimization and selection.
  • 3. Heterogeneous  external mass transfer restrictions  Surface reactions  internal mass transfer restrictions  Different phases Homogeneous  none  none  none  Similar phases Advantages  Reduced energy requirements  Easy product-catalyst separation Heterogeneous catalyst Major Differences
  • 4. Basic Properties of catalyst  A catalyst affects the rate of reaction but emerges from the process unchanged. A catalyst usually changes a reaction rate by promoting a different molecular path for a reaction and thereby lowering the activation energy. Reaction examples  A small amount of catalyst is often sufficient to bring about a considerable extent of reaction. (huge surface area)  The catalyst does not affect the equilibrium state
  • 5. Steps in Heterogeneous Catalytic Reactions Step 1: Transport of Reactants to the Catalyst Surface Step 2: Transport within the Porous Catalyst Step 3: Adsorption of Reactants It is necessary that at least one of the reactants attach itself (physical or chemisorption) to the catalyst surface so that the reaction proceeds Step 4: Surface Reaction Then chemical reaction occurs between adsorbed species. Step 5: Desorption of Products The reverse of Step 3. Step 6: Diffusion of the Products to the External Catalyst Surface This step is essentially the reverse of Step 2. Step 7: Transport of Products to the Bulk Fluid The reverse of Step 1.
  • 6. 1.1 THE RATE EQUATION FOR SURFACE KINETICS Langmuir Mechanism • Chemical bonds are formed • Adsorption sites are energetically uniform • Monolayer coverage • No interaction between absorbed • Molecules • It assumes mass law describes individual steps Other adsorption isotherms Freundlich Adsorption Isotherm BET adsorption Isotherm
  • 7. Langmuir Mechanism Adsorption 𝐴 + 𝑆 ↔ 𝐴. 𝑆 Rate expression 𝑟𝑎 = 𝑘𝑎𝐶𝐴𝐶𝑠 with rate coefficient ka 𝑟𝑑 = 𝑘𝑑𝐶𝐴.𝑠 with rate coefficient kd Schematic The catalyst sites are either covered or covered such that: 𝐶𝑇 = 𝐶𝑠 + 𝐶𝐴𝑠 Where: 𝐶𝑠 vacant sites, 𝐶𝐴𝑠 sites occupied by A At equilibrium adsorption is equal to desorption 𝑘𝑑𝐶𝐴.𝑠 = 𝑘𝑎𝐶𝐴𝐶𝑠 Eliminating species difficult to measure 𝑘𝑑𝐶𝐴.𝑠 = 𝑘𝑎𝐶𝐴(𝐶𝑇−𝐶𝐴.𝑠) 𝑘𝑑𝐶𝐴.𝑠 = 𝑘𝑎𝐶𝐴𝐶𝑇 − 𝑘𝑎𝐶𝐴𝐶𝐴.𝑠 𝑘𝑑𝐶𝐴.𝑠 + 𝑘𝑎𝐶𝐴𝐶𝐴.𝑠 = 𝑘𝑎𝐶𝐴𝐶𝑇 𝐶𝐴.𝑠 = 𝑘𝑎𝐶𝐴𝐶𝑇 𝑘𝑑 + 𝑘𝑎𝐶𝐴 Divide by kd 𝐶𝐴.𝑠 = 𝐾𝐴𝐶𝐴𝐶𝑇 1 + 𝐾𝐴𝐶𝐴 Where KA = ka/kd 𝜃 = 𝐶𝐴.𝑠 𝐶𝑇 = 𝐾𝐴𝐶𝐴 1 + 𝐾𝐴𝐶𝐴
  • 8. Langmuir Mechanism- Two species adsorbing same site Adsorption 𝐴 + 𝑆 ↔ 𝐴. 𝑆 𝐵 + 𝑆 ↔ 𝐵. 𝑆 Rate expression 𝑟𝐶𝐴𝑆 = 𝑘𝑎𝐴𝐶𝐴𝐶𝑠 −𝑘𝑑 𝐶𝐴.𝑠 𝑟𝐵𝑆 = 𝑘𝑎𝐵𝐶𝐵𝐶𝑠 −𝑘𝑑𝐵 𝐶𝐵.𝑠 The catalyst sites are either covered or covered such that: 𝐶𝑇 = 𝐶𝑠 + 𝐶𝐵𝑠 + 𝐶𝐴𝑠 Where: 𝐶𝑠 vacant sites, 𝐶𝐴𝑠 sites occupied by A @ equilibrium 𝐾𝐴 = 𝐶𝐴.𝑆 𝐶𝐴𝐶𝑆 = 𝑘𝑎𝐴 𝑘𝑑𝐴 𝐶𝐴.𝑠 = 𝐾𝐴𝐶𝐴𝐶𝑠 𝐶𝐵.𝑠 = 𝐾𝐵𝐶𝐵𝐶𝑠 𝐶𝑇 = 𝐶𝑠 + 𝐾𝐵𝐶𝐵𝐶𝑠 + 𝐾𝐴𝐶𝐴𝐶𝑠 𝐶𝑆 = 𝐶𝑇 1 + 𝐾𝐵𝐶𝐵 + 𝐾𝐴𝐶𝐴 The concentration of absorbed species is given by: 𝐶𝑖.𝑆 = 𝐶𝑇𝐾𝑖𝐶𝑖 1 + 𝐾𝐵𝐶𝐵 + 𝐾𝐴𝐶𝐴
  • 9. Langmuir Mechanism- if a molecule dissociate upon adsorption Adsorption 𝐴2 + 2𝑆 ↔ 2𝐴. 𝑆 Rate expression 𝑟𝐶𝐴𝑆 = 𝑘𝑎𝐴𝐶𝐴𝐶𝑠 −𝑘𝑑 𝐶𝐴.𝑠 The catalyst sites are either covered or covered such that: 𝐶𝑇 = 𝐶𝑠 + 𝐶𝐴𝑠 Where: 𝐶𝑠 vacant sites, 𝐶𝐴𝑠 sites occupied by A @ equilibrium 𝐾𝐴 = 𝐶𝐴.𝑆 2 𝐶𝐴2 𝐶𝑆 2 𝐶𝐴.𝑠 2 = 𝐾𝐴𝐶𝐴𝐶𝑠 2 𝐶𝑇 = 𝐶𝑠 + 𝐾𝐴𝐶𝐴𝐶𝑠 2 𝐶𝐴.𝑆 = 𝐶𝑇 𝐾𝐴𝐶𝐴2 𝐶𝑠 1 + 𝐾𝐴𝐶𝐴2
  • 10. Summary i) Adsorption ii) Different systems a) 𝐴 + 𝑆 ↔ 𝐴. 𝑆 b) 𝐴 + 𝑆 ↔ 𝐴. 𝑆 𝐵 + 𝑆 ↔ 𝐵. 𝑆 c) 𝐴2+2𝑆 ↔ 2𝐴. 𝑆 NB: One method of checking whether a model predicts the behavior of experimental data is to linearize the model equation and then plot the indicated variables against one another
  • 11. Exercise Come up with a Langmuir equation for dissociative adsorption of carbon monoxide on platinum.
  • 12. Surface reactions  After the reactants have adsorbed onto the surface it is capable of reacting in a number of ways to form a product: Langmuir-Hinshelwood kinetics 1) Single reaction 𝐴. 𝑆 ↔ 𝑆. 𝐵  this reaction represents a isomerization/ decomposition reaction. 𝑟𝑠𝑟 = 𝑘𝑠𝑟𝐶𝐴.𝑠 −𝑘−𝑠𝑟 𝐶𝑆.𝐵 𝑟𝑠𝑟 = 𝑘𝑠𝑟 𝐶𝐴.𝑠 − 𝐶𝑆.𝐵 𝐾𝑆𝑅 Where; 𝑘𝑠𝑟-surface reaction rate coefficient 𝐾𝑆𝑅-surface reaction equilibrium coefficient 2) Dual sites 𝐴. 𝑆 + 𝑆 ↔ 𝑆. 𝐵 + 𝑆 The adsorbed reactant interacts with another site (occupied or unoccupied) to form product. 𝑟𝑠𝑟 = 𝑘𝑠𝑟 𝐶𝐴.𝑠𝐶𝑆 − 𝐶𝑆.𝐵𝐶𝑆 𝐾𝑆𝑅
  • 13. Surface reactions Another types of dual-sites mechanism is the reaction between two adsorbed species 2) Dual sites (ii) 𝐴. 𝑆 + 𝐵. 𝑆 ↔ 𝑆. 𝐶 + 𝑆. 𝐷 Two species adsorbed on the same type of sites 𝑟𝑠𝑟 = 𝑘𝑠𝑟 𝐶𝐴.𝑠𝐶𝐵.𝑆 − 𝐶𝑆.𝐶𝐶𝑆.𝐷 𝐾𝑆𝑅 3) Dual sites (iii) 𝐴. 𝑆 + 𝐵. 𝑆` ↔ 𝑆. 𝐶` + 𝑆. 𝐷 Two species adsorbed on different type of sites 𝑟𝑠𝑟 = 𝑘𝑠𝑟 𝐶𝐴.𝑠𝐶𝐵.𝑆` − 𝐶𝑆`.𝐶𝐶𝑆.𝐷 𝐾𝑆𝑅
  • 14. 1.1 THE RATE EQUATION FOR SURFACE KINETICS Eley-Rideal Mechanism • Is for a reaction between an absorbed molecule and a molecule in the gas phase 𝐴. 𝑆 + 𝐵. (𝑔) ↔ 𝑆. 𝐶 Rate Law: 𝑟𝑠𝑟 = 𝑘𝑠𝑟 𝐶𝐴.𝑠𝑃𝐵 − 𝐶𝑆.𝐶 𝐾𝑆𝑅
  • 15. Desorption After the catalytic reactions the products subsequently have to desorb into the gas phase C. 𝑆 ↔ 𝑆 + 𝐶(𝑔) Desorption rate: 𝑟𝐷𝑐 = 𝑘𝐷𝑐 𝐶𝐶.𝑠 − 𝐶𝑆𝑃𝐶 𝐾𝐷𝑐 Note that rate of desorption of C is opposite the rate of a adsorption of C 𝑟𝐷𝑐 = 𝑘𝐴𝐷𝑐 In addition the desorption equilibrium constant KDC is just the reciprocal of the adsorption equilibrium constant. 𝑟𝐷𝑐 = 𝑘𝐷𝑐 𝐶𝐶.𝑠 − 𝐾𝐴𝑐𝐶𝑆𝑃𝐶
  • 16. The Rate-limiting step  At steady state the rates of each of the three reaction steps in series (adsorption, surface reaction and desorption) are equal.  Usually one of the steps is rate limiting, the process of coming with the rate is as follows: i) Rates are written for individual steps assuming they are reversible ii) A rate limiting step is postulated and steps that are not rate limiting are used to eliminate all coverage-dependent terms
  • 17. Adsorption controlling C 𝑔 + 𝑆 𝑠 ↔ 𝑆. 𝐶(𝑠) adsorption 𝑟𝐴𝐷 = 𝑘𝐴𝐷 𝑃𝐶𝐶𝑠 − 𝐶𝐶𝐶.𝑆 𝐾𝐴𝐷 C. 𝑆 ↔ 𝐵. 𝑆 + 𝑃 surface reaction 𝑟𝑆 = 𝑘𝑆 𝐶𝐶.𝑆 − 𝑃𝑃𝐶𝐵.𝑆 𝐾𝑠 B. 𝑆 ↔ 𝑆 + 𝐵 desorption 𝑟𝐷 = 𝑘𝐷 𝐶𝐵.𝑆 − 𝑃𝐵𝐶𝑆 𝐾𝐷𝐵 But KDB is the reciprocal of KADB 𝑟𝐷 = 𝑘𝐷 𝐶𝐵.𝑆 − 𝐾𝐴𝐷𝐵𝑃𝐵𝐶𝑆 Assuming steady state 𝑟`𝑐 = 𝑟𝐴𝐷 = 𝑟𝑆 = 𝑟𝐷𝐷 If adsorption is controlling: kAD<<< Ks ,Kd 𝑟`𝑐 = 𝑟𝐴𝐷 = 𝑘𝐴𝐷 𝑃𝐶𝐶𝑠 − 𝐶𝐶𝐶.𝑆 𝐾𝐴𝐷 Since CS and CC.S can not be measured they need to be replaced.Based on ealier assumption rs/ks & rD/kD ̴ 0 while rAD/kAD is relative large. 𝑟𝑆 = 𝑘𝑆 𝐶𝐶.𝑆 − 𝑃𝑃𝐶𝐵.𝑆 𝐾𝑠 surface reaction 0 = 𝐶𝐶.𝑆 − 𝑃𝑃𝐶𝐵.𝑆 𝐾𝑠
  • 18. Adsorption controlling 𝐶𝐶.𝑆 = 𝑃𝑃𝐶𝐵.𝑆 𝐾𝑠 𝑟𝐷 = 𝑘𝐷 𝐶𝐵.𝑆 − 𝐾𝐴𝐷𝐵𝑃𝐵𝐶𝑆 desorption 0 = 𝐶𝐵.𝑆 − 𝐾𝐴𝐷𝐵𝑃𝐵𝐶𝑆 𝐶𝐵.𝑆 = 𝐾𝐴𝐷𝐵𝑃𝐵𝐶𝑆 Therefore CC.S is equal 𝐶𝐶.𝑆 = 𝑃𝑃𝐾𝐴𝐷𝐵𝑃𝐵𝐶𝑆 𝐾𝑠 𝑟𝐴𝐷 = 𝑘𝐴𝐷 𝑃𝐶𝐶𝑠 − 𝑃𝑃𝐾𝐴𝐷𝐵𝑃𝐵𝐶𝑆 𝐾𝑠 𝐾𝐴𝐷 𝑟𝐴𝐷 = 𝑘𝐴𝐷 𝑃𝐶 − 𝑃𝐵𝑃𝑃 𝐾𝑃 𝐶𝑆 @ equilibrium rAD approaches zero, 𝐾𝑃= 𝑃𝐵𝑒 𝑃𝑃𝑒 𝑃𝐶𝑒 = 𝐾𝐴𝐷 𝐾𝑆 𝐾𝐵 Equilibrium constant can be expressed Gibbs energy 𝐶𝑇 = 𝐶𝑠 + 𝐶𝐶.𝑠 + 𝐶𝐵.𝑠 𝐶𝑇 = 𝐶𝑠 + 𝑃𝑃𝐾𝐴𝐷𝐵𝑃𝐵𝐶𝑆 𝐾𝑠 +𝐾𝐴𝐷𝐵𝑃𝐵𝐶𝑆 Solve for Cs 𝐶𝑠 = 𝐶𝑇 1 + 𝐾𝐴𝐷𝐵𝑃𝐵𝑃𝑃 𝐾𝑠 + 𝐾𝐴𝐷𝐵𝑃𝐵 Initial rate of reaction is: 𝑟𝐴𝐷 = 𝑘𝐴𝐷 𝑃𝐶 − 𝑃𝐵𝑃𝑃 𝐾𝑃 𝐶𝑇 1 + 𝐾𝐴𝐷𝐵𝑃𝐵𝑃𝑃 𝐾𝑠 + 𝐾𝐴𝐷𝐵𝑃𝐵
  • 19. Surface reaction;Desorption controlling Surface reaction 𝑟𝑆 = 𝑘𝑠𝐾𝑐 𝑃𝐶 − 𝑃𝐵𝑃𝑃 𝐾𝑃 𝐶𝑇 1 + 𝐾𝐴𝐷𝐵𝑃𝐵 + 𝐾𝐶𝑃𝐶 Desorption 𝑟𝐷 = 𝑘𝐷𝐾𝑆𝐾𝑐 𝑃𝐶 − 𝑃𝐵𝑃𝑃 𝐾𝑃 𝐶𝑇 𝑃𝑃 + 𝐾𝐶𝑃𝐶𝐾𝑆 + 𝐾𝐶𝑃𝑃𝑃𝐶 Prove these rate equations
  • 20. Rate Law analysis Dependence on the product if products are adsorbed to the surface, they do appear as a denominator on the rate equation 𝑟 = 1 + 𝐾𝐶𝑃𝐶 + ⋯ Dependence on reactant and leveling off : this normal suggest an expression as shown below 𝑟 = 𝑃𝑐 1 + 𝐾𝐶𝑃𝐶 + ⋯
  • 21. References 1. Calvin H. Bartholomew and Robert J. Farrauto, “Fundamentals of industrial catalytic processes” JOHN WILEY & SONS, INC., 2 nd edition, 2006. 2. Octave Levenspiel., Chemical Reaction Engineering, 3rd Edition, John Wiley & Sons,New York, 1999 3. J. R Richardson and D. G Peacock., Chemical Engineering volume 3, 3 rd Edition, Pergamon , 1994 4. H. Scott Fogler, Essentials of Chemical Reaction Engineering, Pearson Education International, 2010