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2.1 LINEAR MOTION
Physical
Quantity
Definition, Quantity, Symbol and unit
Distance, l
Distance is the total path length traveled from one
location to another.
Quantity: scalar SI unit: meter (m)
Displacement,
l
(a)The distance in a specified direction.
(b)the distance between two locations measured along
the shortest path connecting them in a specific
direction.
(c)The distance of its final position from its initial
position in a specified direction.
Quantity: vector SI unit: meter (m)
Speed,v
Speed is the rate of change of distance
Speed = Distance traveled
Time taken
Quantity: scalar SI unit: m s-1
Velocity, v
Velocity is the rate of change of displacement.
Velocity = Displacement
Time taken
Direction of velocity is the direction of displacement
Quantity : Vector SI unit: m s-1
Average
speed
v = Total distant traveled, s
Total time taken , t
Average
velocity
v = Displacement, s
Time taken, t
Example: A car moves at
an average speed /
velocity of 20 ms-1
On average, the car moves
a distance / displacement
of 20 m in 1 second for the
whole journey.
Uniform
speed
Speed that remains the same in magnitude regardless of
its direction.
Uniform
velocity
Velocity that remains the same in magnitude and
direction.
An object has
a non-uniform
velocity if:
(a)the direction of motion changes or the motion is
not linear.
(b)The magnitude of its velocity changes.
Acceleration,
a
t
u
v
a
−
=
unit : ms-2
acceleration
is positive
When the velocity of an object changes, the object is
said to be accelerating.
Acceleration is defined as the rate of change of
velocity.
Acceleration = Change in velocity
Time taken
= final velocity, v – initial velocity, u
Time taken, t
• The velocity of an object increases from an initial
velocity, u, to a higher final velocity, v
Deceleration
acceleration
is negative.
The rate of decrease in speed in a specified direction.
The velocity of an object decreases from an initial
velocity, u, to a lower final velocity, v.
Zero
acceleration
An object moving at a constants velocity, that is, the
magnitude and direction of its velocity remain
unchanged – is not accelerating
Constant
acceleration
Velocity increases at a uniform rate.
When a car moves at a constant or uniform acceleration
of 5 ms-2
, its velocity increases by 5 ms-1
for every
second that the car is in motion.
2
3
1. Constant = uniform
2. increasing velocity = acceleration
3. decreasing velocity = deceleration
4. zero velocity = object at stationary / at rest
5. negative velocity = object moves at opposite
direction
6. zero acceleration = constant velocity
7. negative acceleration = deceleration
Comparisons between distance
and displacement.
Distance Displacement
Total path length
traveled from
one location to
another
The distance
between two
locations
measured along
the shortest path
connecting them
in specific
direction
Scalar quantity Vector quantity
It has magnitude
but no direction
It has both
magnitude and
direction
SI unit meter SI unit : meter
Comparisons between speed and
velocity
Speed Velocity
The rate of change
of distance
The rate of change
of displacement
Scalar quantity Vector quantity
It has magnitude
but no direction
It has both
magnitude and
direction
SI unit : m s-1
SI unit : m s-1
Fill in the blanks:
1. A steady speed of 10 m/s = A distance of .. ……….is traveled
every ………..
2. A steady velocity of -10 m/s = A …………. Of 10 m is traveled every
………..to the left.
3. A steady acceleration of 4 ms-2
= Speed goes up by 4 m/s every
……….
4. A steady deceleration of 4 ms-2
= speed goes ……….. by 4 m/s
every ……….
5. A steady velocity of 10 m/s = ……………………………………………
…………………………………………………………………………………
Example 1
Every day Rahim walks from his
house to the junction which is 1.5
km from his house. Then he turns
back and stops at warung Pak Din
which is 0.5 km from his house.
(a)What is Rahim’s displacement
from his house
• when he reaches the junction.
• When he is at warung Pak
Din.
(b)After breakfast, Rahim walks
back to his house. When he
reaches home,
(i) what is the total distance
traveled by Rahim?
(ii) what is Rahim’s total
displacement from his
house?
Example 2
Every morning Amirul walks to
Ahmad’s house which is situated
80 m to the east of Amirul’s house.
They then walk towards their
school which is 60 m to the south
of Ahmad’s house.
(a)What is the distance traveled
by Amirul and his
displacement from his
house?
(b)If the total time taken by
Amirul to travel from his
house to Ahmad’s house and
then to school is 15 minutes,
what is his speed and
velocity?
Example 3
Syafiq running in a race covers 60 m in 12 s.
(a) What is his speed in m/s
(b) If he takes 40 s to complete the race, what is his distance covered?
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5
Example 4
An aeroplane flys towards the
north with a velocity 300 km/hr in
one hour. Then, the plane
moves to the east with the
velocity 400 km / hr in one hour.
(a)What is the average speed
of the plane?
(b)What is the average
velocity of the plane?
(c)What is the difference
between average speed and
average velocity of the
plane?
Example 5
The speedometer reading for a
car traveling north shows 80
km/hr. Another car traveling at
80 km/hr towards south. Is the
speed of both cars same? Is the
velocity of both cars same?
A ticker timer
¾ Use: 12 V a.c power supply
¾ 1 tick = time interval between two dots.
¾ The time taken to make 50 ticks on the ticker tape is 1 second.
Hence, the time interval between 2 consecutive dots is 1/50 = 0.02 s.
¾ 1 tick = 0.02 s
Relating displacement, velocity, acceleration and time using ticker tape.
FORMULA
VELOCITY Time, t = 10 dots x 0.02 s
= 0.2 s
displacement, s = x cm
velocity = s = x cm
t 0.2 s
ACCELERATION
elapse time, t = (5 – 1) x 0.2 s = 0.8 s
or t = (50 – 10) ticks x 0.02 s = 0.8 s
Initial velocity,
u = x1
0.2
final velocity,
v = x2
0.2
acceleration,
a = v – u
t
TICKER TAPE AND
CHARTS
TYPE OF MOTION
Constant velocity
– slow moving
Constant velocity
– fast moving
¾ Distance between the dots
increases uniformly
¾ the velocity is of the object is
increasing uniformly
¾ The object is moving at a
uniform / constant
acceleration.
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¾ Distance between the dots
decrease uniformly
¾ The velocity of the object is
decreasing uniformly
¾ The object is experiencing
uniform / constant
deceleration
Example 6
The diagram above shows a ticker tape
chart for a moving trolley. The frequency
of the ticker-timer used is 50 Hz. Each
section has 10 dots-spacing.
(a) What is the time between two dots.
(b) What is the time for one strips.
(c) What is the initial velocity
(d) What is the final velocity.
(e) What is the time interval to change
from initial velocity to final velocity?
(f) What is the acceleration of the
object.
THE EQUATIONS OF MOTION
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u = initial velocity
v = final velocity
t = time taken
s = displacement
a = constant accleration
2.2 MOTION GRAPHS
DISPLACEMENT – TIME
GRAPH
Velocity is obtained from the gradient of
the graph.
A – B : gradient of the graph is +ve and
constant ∴ velocity is constant.
B – C : gradient of the graph = 0 ∴ the
velocity = 0, object at rest.
C – D : gradient of the graph –ve and
constant. The velocity is negative and
object moves in the opposite direction.
Area below
graph
Distance / displacement
Positive
gradient
Constant Acceleration
(A – B)
Negative
gradient
Constant Deceleration
(C – D)
VELOCITY-TIME GRAPH
Zero
gradient
Constant velocity / zero
acceleration
(B – C)
GRAPH s versus t v versus t a versus t
Zero
velocity
Negative
velocity
Constant
velocity
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GRAPH s versus t v versus t a versus t
Constant
acceleration
Constant
deceleration
Example 6
Contoh 11
Based on the s – t graph above:
(a) Calculate the velocity at
(i) AB (ii) BC (iii) CD
(b) Describe the motion of the object at:
(i) AB (ii) BC (iii) CD
(c)Find:
(i) total distance
(ii) total displacement
(d) Calculate
(i) the average speed
(ii) the average velocity of the
moving particle.
Example 7
(a) Calculate the acceleration at:
(i) JK (ii) KL (iii) LM
(b) Describe the motion of the object at:
(i) JK (ii) KL (iii) LM
Calculate the total displacement.
(c) Calculate the average velocity.
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2.3 INERTIA
Inertia The inertia of an object is the tendency of the
object to remain at rest or, if moving, to continue
its motion.
Newton’s first law Every object continues in its state of rest or of
uniform motion unless it is acted upon by an
external force.
Relation between
inertia and mass
The larger the mass, the larger the inertia
SITUATIONS INVOLVING INERTIA
SITUATION EXPLAINATION
When the cardboard is pulled away quickly, the
coin drops straight into the glass.
The inertia of the coin maintains its state at rest.
The coin falls into the glass due to gravity.
Chili sauce in the bottle can be easily poured out if
the bottle is moved down fast with a sudden stop.
The sauce inside the bottle moves together with
the bottle. When the bottle stops suddenly, the
sauce continue in its state of motion due to the
effect of its inertia.
Body moves forward when the car stops suddenly
The passengers were in a state of motion when the
car was moving. When the car stopped suddenly,
the inertia in the passengers made them maintain
their state of motion. Thus when the car stop, the
passengers moved forward.
A boy runs away from a cow in a zig zag motion.
The cow has a large inertia making it difficult to
change direction.
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• The head of hammer is secured tightly to its
handle by knocking one end of the handle, held
vertically, on a hard surface.
• This causes the hammer head to continue on its
downward motion when the handle has been
stopped, so that the top end of the handle is
slotted deeper into the hammer head.
• The drop of water on a wet umbrella will fall
when the boy rotates the umbrella.
• This is because the drop of water on the surface
of the umbrella moves simultaneously as the
umbrella is rotated.
• When the umbrella stops rotating, the inertia of
the drop of water will continue to maintain its
motion.
Ways to reduce
the negative
effects of inertia
1. Safety in a car:
(a)Safety belt secure the driver to their seats.
When the car stops suddenly, the seat belt
provides the external force that prevents the
driver from being thrown forward.
(b)Headrest to prevent injuries to the neck
during rear-end collisions. The inertia of the
head tends to keep in its state of rest when
the body is moved suddenly.
(c)An air bag is fitted inside the steering wheel.
It provides a cushion to prevent the driver
from hitting the steering wheel or dashboard
during a collision.
2. Furniture carried by a lorry normally are tied up
together by string. When the lorry starts to
move suddenly, the furniture are more difficult
to fall off due to their inertia because their
combined mass has increased.
Relationship
between mass
and inertia
• Two empty buckets which are hung with rope
from a the ceiling.
• One bucket is filled with sand while the other
bucket is empty.
• Then, both pails are pushed.
• It is found that the empty bucket is easier to
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push compared to the bucket with sand.
• The bucket filled with sand offers more
resistance to movement.
• When both buckets are oscillating and an
attempt is made to stop them, the bucket filled
with sand offers more resistance to the hand
(more difficult to bring to a standstill once it has
started moving)
• This shows that the heavier bucket offers a
greater resistance to change from its state of
rest or from its state of motion.
• An object with a larger mass has a larger inertia.
2.4 MOMENTUM
Definition Momentum = Mass x velocity = mv
SI unit: kg ms-1
Principle of
Conservation of
Momentum
In the absence of an external force, the total
momentum of a system remains unchanged.
Elastic Collision Inelastic collision
ƒ Both objects move
independently at their
respective velocities after the
collision.
ƒ Momentum is conserved.
ƒ Kinetic energy is conserved.
ƒ Total energy is conserved.
ƒ The two objects combine and
move together with a
common velocity after the
collision.
ƒ Momentum is conserved.
ƒ Kinetic energy is not
conserved.
ƒ Total energy is conserved.
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13
Total Momentum Before = total
momentum After
m1u1 + m2u2 = m1v1 + m2v2
Total Momentum Before = Total
Momentum After
m1u1 + m2u2 = (m1 + m2) v
Explosion
Before explosion both object stick
together and at rest. After collision,
both object move at opposite direction.
Total Momentum
before collision
Is zero
Total Momentum
after collision :
m1v1 + m2v2
From the law of conservation of
momentum:
Total Momentum = Total Momentum
Before collision after collision
0 = m1v1 + m2v2
m1v1 = - m2v2
-ve sign means opposite direction
EXAMPLES OF EXPLOSION (Principle Of Conservation Of Momentum)
¾ When a rifle is fired, the bullet of mass m,
moves with a high velocity, v. This creates
a momentum in the forward direction.
¾ From the principle of conservation of
momentum, an equal but opposite
momentum is produced to recoil the riffle
backward.
Application in the jet engine:
A high-speed hot gases are ejected from the
back with high momentum.
This produces an equal and opposite
momentum to propel the jet plane forward.
The launching of rocket
¾ Mixture of hydrogen and oxygen fuels burn
explosively in the combustion chamber.
Jets of hot gases are expelled at very high
speed through the exhaust.
¾ These high speed hot gases produce a large
amount of momentum downward.
¾ By conservation of momentum, an equal but
opposite momentum is produced and acted
on the rocket, propelling the rocket
upwards.
In a swamp area, a fan boat is used.
¾ The fan produces a high speed movement of
air backward. This produces a large
momentum backward.
¾ By conservation of momentum, an equal but
opposite momentum is produced and acted
on the boat. So the boat will move forward.
A squid propels by expelling water at high
velocity. Water enters through a large opening
and exits through a small tube. The water is
forced out at a high speed backward.
Total Mom. before= Total Mom. after
0 =Mom water + Mom squid
0 = mwvw + msvs
-mwvw = msvs
The magnitude of the momentum of water and
squid are equal but opposite direction.
This causes the squid to jet forward.
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Example
Car A of mass 1000 kg moving at
20 ms-1
collides with a car B of mass
1200 kg moving at 10 m s-1
in same
direction. If the car B is shunted
forwards at 15 m s-1
by the impact,
what is the velocity, v, of the car A
immediately after the crash?
Example
Before collision After collision
MA = 4 kg MB = 2 kg
UA = 10 m/s to the left
UB = 8 m/s to the right
VB = 4 m/s to the left.
Calculate the value of VA .
Example
A truck of mass 1200 kg moving at
30 m/s collides with a car of mass
1000 kg which is traveling in the
opposite direction at 20 m/s. After
the collision, the two vehicles move
together. What is the velocity of
both vehicles immediately after
collision?
Example
A man fires a pistol which has a
mass of 1.5 kg. If the mass of the
bullet is 10 g and it reaches a
velocity of 300 m/s after shooting,
what is the recoil velocity of the
pistol?
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2.5 FORCE
Example:
Balanced Force
When the forces acting on
an object are balanced, they
cancel each other out.
The net force is zero.
Effect :
the object at is at rest [
velocity = 0]
or moves at constant
velocity [ a = 0]
Weight, W = Lift, U Thrust, F = drag, G
When the forces acting on an object are not
balanced, there must be a net force acting
on it.
The net force is known as the unbalanced
force or the resultant force.
Unbalanced Force/
Resultant Force
Effect : Can cause a body to
- change it state at rest (an object will
accelerate
- change it state of motion (a moving
object will decelerate or change its
direction)
Force, Mass & Acceleration
The acceleration produced by a force on an object
is directly proportional to the magnitude of the net
force applied and is inversely proportional to the
mass of the object. The direction of the
acceleration is the same as that of the net force.
Newton’s Second
Law of Motion
When a net force, F, acts
on a mass, m it causes
an acceleration, a.
Force = Mass x Acceleration
F = ma
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Relationship
between a & F
a α F
The acceleration, a, is directly
proportional to the applied force, F.
Relationship
between a and
m
m
a
1
∝
The acceleration of an object is
inversely proportional to the mass,
Experiment to Find The Relationship between Force, Mass & Acceleration
Relationship
between
a & F a & m
Situation
Both men are pushing the
same mass but man A
puts greater effort. So he
moves faster.
Both men exerted the same
strength. But man B moves
faster than man A.
Inference The acceleration
produced by an object
depends on the net force
applied to it.
The acceleration produced
by an object depends on
the mass
Hypothesis The acceleration of the
object increases when
the force applied
increases
The acceleration of the
object decreases when the
mass of the object
increases
Variables:
Manipulated :
Responding :
Constant :
Force
Acceleration
Mass
Mass
Acceleration
Force
Apparatus
and Material
Ticker tape and elastic cords, ticker timer, trolleys,
power supply and friction compensated runway and
meter ruler.
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An elastic cord is hooked
over the trolley. The
elastic cord is stretched
until the end of the
trolley. The trolley is
pulled down the runway
with the elastic cord
being kept stretched by
the same amount of force
An elastic cord is hooked
over a trolley. The elastic
cord is stretched until the
end of the trolley. The
trolley is pulled down the
runway with the elastic
cord being kept stretched
by the same amount of
force
Determine the
acceleration by analyzing
the ticker tape.
Acceleration
t
u
v
a
−
=
Determine the acceleration
by analyzing the ticker
tape.
Acceleration
t
u
v
a
−
=
Procedure :
- Controlling
manipulated
variables.
- Controlling
responding
variables.
- Repeating
experiment.
Repeat the experiment by
using two , three, four
and five elastic cords
Repeat the experiment by
using two, three, four and
five trolleys.
Recording
data
Analysing
data
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1. What force is required to move a
2 kg object with an acceleration
of 3 m s-2
, if
(a) the object is on a smooth
surface?
(b) The object is on a surface where
the average force of friction
acting on the object is 2 N?
2. Ali applies a force of 50 N to
move a 10 kg table at a constant
velocity. What is the frictional
force acting on the table?
3. A car of mass 1200 kg traveling
at 20 m/s is brought to rest over a
distance of 30 m. Find
(a) the average deceleration,
(b) the average braking force.
4. Which of the following systems
will produce maximum
acceleration?
2.6 IMPULSE AND IMPULSIVE FORCE
Impulse The change of momentum
mv - mu
Unit : kgms-1
or Ns
Impulsive
Force
The rate of change of momentum in a
collision or explosion
Unit = N
m = mass
u = initial
velocity
v = final
velocity
t = time
Longer period of time →Impulsive
force decrease
Effect of
time
Impulsive force
is inversely
proportional to
time of contact
Shorter period of time →Impulsive
force increase
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Situations for Reducing Impulsive Force in Sports
Situations Explanation
Thick mattress with soft surfaces are used in
events such as high jump so that the time
interval of impact on landing is extended, thus
reducing the impulsive force. This can prevent
injuries to the participants.
Goal keepers will wear gloves to increase the
collision time. This will reduce the impulsive
force.
A high jumper will bend his legs upon landing.
This is to increase the time of impact in order to
reduce the impulsive force acting on his legs.
This will reduce the chance of getting serious
injury.
A baseball player must catch the ball in the
direction of the motion of the ball. Moving his
hand backwards when catching the ball
prolongs the time for the momentum to change
so as to reduce the impulsive force.
Situation of Increasing Impulsive Force
Situations Explanation
A karate expert can break a thick wooden slab
with his bare hand that moves at a very fast
speed. The short impact time results in a large
impulsive force on the wooden slab.
A massive hammer head moving at a fast
speed is brought to rest upon hitting the nail.
The large change in momentum within a short
time interval produces a large impulsive force
which drives the nail into the wood.
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A football must have enough air pressure in it
so the contact time is short. The impulsive
force acted on the ball will be bigger and the
ball will move faster and further.
Pestle and mortar are made of stone. When a
pestle is used to pound chilies the hard
surfaces of both the pestle and mortar cause
the pestle to be stopped in a very short time. A
large impulsive force is resulted and thus
causes these spices to be crushed easily.
Example 1
A 60 kg resident jumps from the first
floor of a burning house. His
velocity just before landing on the
ground is 6 ms-1
.
(a) Calculate the impulse when his
legs hit the ground.
(b) What is the impulsive force on
the resident’s legs if he bends
upon landing and takes 0.5 s to
stop?
(c) What is the impulsive force on
the resident’s legs if he does not
bend and stops in 0.05 s?
(d) What is the advantage of bending
his legs upon landing?
Example 2
Rooney kicks a ball with a force of
1500 N. The time of contact of his
boot with the ball is 0.01 s. What is
the impulse delivered to the ball? If
the mass of the ball is 0.5 kg, what is
the velocity of the ball?
21
2.7 SAFETY VEHICLE
Component Function
Headrest To reduce the inertia effect of the driver’s head.
Air bag Absorbing impact by increasing the amount of time the
driver’s head to come to the steering. So that the
impulsive force can be reduce
Windscreen The protect the driver
Crumple
zone
Can be compressed during accident. So it can increase
the amount of time the car takes to come to a complete
stop. So it can reduce the impulsive force.
Front
bumper
Absorb the shock from the accident. Made from steel,
aluminium, plastic or rubber.
ABS Enables drivers to quickly stop the car without causing
the brakes to lock.
Side impact
bar
Can be compressed during accident. So it can increase
the amount of time the car takes to come to a complete
stop. So it can reduce the impulsive force.
Seat belt To reduce the inertia effect by avoiding the driver from
thrown forward.
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2.8 GRAVITY
Gravitational
Force
Objects fall because they are pulled towards the Earth
by the force of gravity.
This force is known as the pull of gravity or the earth’s
gravitational force.
The earth’s gravitational force tends to pull everything
towards its centre.
Free fall ¾ An object is falling freely when it is falling under the
force of gravity only.
¾ A piece of paper does not fall freely because its fall is
affected by air resistance.
¾ An object falls freely only in vacuum. The absence of
air means there is no air resistance to oppose the
motion of the object.
¾ In vacuum, both light and heavy objects fall freely.
They fall with the same acceleration ie. The
acceleration due to gravity, g.
Acceleration
due to
gravity, g
¾ Objects dropped under the influence of the pull of
gravity with constant acceleration.
¾ This acceleration is known as the gravitational
acceleration, g.
¾ The standard value of the gravitational acceleration,
g is 9.81 m s-2
. The value of g is often taken to be 10
m s-2
for simplicity.
¾ The magnitude of the acceleration due to gravity
depends on the strength of the gravitational field.
Gravitational
field
The gravitational field is the region around the earth in
which an object experiences a force towards the centre
of the earth. This force is the gravitational attraction
between the object and the earth.
The gravitational field strength is defined as the
gravitational force which acts on a mass of 1 kilogram.
m
F
g = Its unit is N kg-1
.
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Gravitational field strength, g = 10 N kg-1
Acceleration due to gravity, g = 10 m s-2
The approximate value of g can therefore be written
either as 10 m s-2
or as 10 N kg-1
.
Weight The gravitational force acting on the object.
Weight = mass x gravitational acceleration
W = mg SI unit : Newton, N and it is a vector quantity
Comparison
between
weight &
mass
Mass Weight
The mass of an object is
the amount of matter in
the object
The weight of an object is
the force of gravity acting
on the object.
Constant everywhere Varies with the magnitude
of gravitational field
strength, g of the location
A scalar quantity A vector quantity
A base quantity A derived quantity
SI unit: kg SI unit : Newton, N
The
difference
between a
fall in air and
a free fall in
a vacuum of
a coin and a
feather.
Both the
coin and the
feather are
released
simulta-
neously from
the same
height.
At vacuum state:
There is no air resistance.
The coin and the feather
will fall freely.
Only gravitational force
acted on the objects.
Both will fall at the same
time.
At normal state:
Both coin and feather will
fall because of gravitational
force.
Air resistance effected by
the surface area of a fallen
object.
The feather that has large
area will have more air
resistance.
The coin will fall at first.
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Two steel
spheres are
falling under
gravity. The
two spheres
are dropped
at the same
time from
the same
height.
(a)The two sphere are
falling with an
acceleration.
The distance between
two successive images
of the sphere increases
showing that the two
spheres are falling with
increasing velocity;
falling with an
acceleration.
(b)The two spheres are
falling down with the
same acceleration
The two spheres are at
the same level at all
times. Thus, a heavy
object and a light object
fall with the same
gravitational
acceleration.
Gravitational
acceleration is
independent of mass.
Motion graph for free fall object
Free fall object Object thrown upward Object thrown upward
and fall
Example 1
A coconut takes 2.0 s to fall to the
ground. What is
(a) its speed when it strikes the
ground
(b) the height of the coconut tree.
25
2.9 FORCES IN EQUILIBRIUM
Forces in
Equilibrium
When an object is in equilibrium, the resultant force acting
on it is zero.
The object will either be
1. at rest
2. move with constant velocity.
Newton’s
3rd
Law
Examples( Label the forces acted on the objects)
Resultant
Force
A single force that represents the combined effect of two of
more forces in magnitude and direction.
Addition of Forces
Resultant force, F = ____ + ____
Resultant force, F = ____ + ____
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Two forces acting at a point at an angle [Parallelogram method]
STEP 1 : Using ruler and protractor,
draw the two forces F1 and F2 from a
point.
STEP 2
Complete the parallelogram
STEP 3
Draw the diagonal of the
parallelogram. The diagonal
represent the resultant force, F in
magnitude and direction.
scale: 1 cm = ……
Resolution of
Forces
A force F can be resolved into components
which are perpendicular to each other:
(a) horizontal component , FX
(b) vertical component, FY
Fx = F cos θ
Fy = F sin θ
Inclined Plane
Component of weight parallel to the plane
= mg sin θ
Component of weight normal to the plane
= mg cos θ
27
find the resultant force
(d) (e)
Lift
Stationary Lift Lift accelerate upward Lift accelerate
downward
Resultant Force = Resultant Force = Resultant Force =
The reading of
weighing scale =
The reading of
weighing scale =
The reading of
weighing scale =
28
Pulley
1. Find the
resultant force, F
2. Find the
moving mass,m
3. Find the
acceleration,a
4. Find string
tension, T
29
2.10 WORK, ENERGY, POWER & EFFICIENCY
Work Work done is the product of an applied force
and the displacement of an object in the
direction of the applied force
W = Fs W = work, F = force s = displacement
The SI unit of work is the
joule, J 1 joule of work is done when a force of 1 N
moves an object 1 m in the direction of the
force
Calculation of Work
30
The displacement, s of the object is in the
direction of the force, F
The displacement , s of the
object is not in the
direction of the force, F
W = Fs
W = F s
W = (F cos θ) s
Example 1
A boy pushing his bicycle
with a force of 25 N
through a distance of 3 m.
Calculate the work done
by the boy.
Example 2
A girl is lifting up a 3 kg
flower pot steadily to a
height of 0.4 m.
What is the work done by
the girl?
Example 3
A man is pulling a crate of fish
along the floor with a force of
40 N through a distance of 6 m.
What is the work done in
pulling the crate?
s F
No work is done when:
The object is stationary
A student carrying his bag
while waiting at the bus
stop
The direction of motion of
the object is perpendicular
to that of the applied force.
A waiter is carrying a tray
of food and walking
No force is applied on the
object in the direction of
displacement (the object
moves because of its
own inertia)
A satellite orbiting in
space. There is no
friction in space. No
force is acting in the
direction of movement of
the satellite.
Concept Definition Formula & Unit
Power The rate at which work is
done, or the amount of work
done per second.
t
W
P =
p = power, W = work /
energy t = time
Energy ¾ Energy is the capacity to do work.
¾ An object that can do work has energy
¾ Work is done because a force is applied and the
objects move. This is accompanied by the transfer
of energy from one object to another object.
¾ Therefore, when work is done, energy is transferred
from one object to another.
¾ The work done is equal to the amount of energy
transferred.
Potential
Energy Gravitational potential energy
is the energy of an object due
to its higher position in the
gravitational field.
m = mass
h = height
g = gravitational
acceleration
E = mgh
Kinetic
Energy
Kinetic energy is the energy of
an object due to its motion.
m = mass
v = velocity
E = ½ mv2
31
Principle of
Conservation
of Energy
Energy can be changed from one form to another, but
it cannot be created or destroyed.
The energy can be transformed from one form to
another, total energy in a system is constant.
Total energy before = total energy after
Example 4
A worker is pulling a wooden block of
weight,W,with a force of P along a
fritionless plank at height of h. The
distance traveled by the block is x.
Calculate the work done by the worker to
pull the block.
Example 5
A student of mass m is climbing up a
flight of stairs which has the height of h.
He takes t seconds..
32
What is the power of the student?
Example 6
A stone is thrown upward with initial
velocity of 20 ms
-1
. What is the maximum
height which can be reached by the
stone?
Example 7
A boll is released from point A of height
0.8 m so that it can roll along a curve
frictionless track. What is the velocity of
the ball when it reaches point B?
Example 8 Example 9
A trolley is released from rest at point X
along a frictionless track. What is the
velocity of the trolley at point Y?
A ball moves upwards along a frictionless
track of height 1.5 m with a velocity of
6 ms
-1
. What is its velocity at point B?
Example 10
A boy of mass 20 kg sits at the top of a
concrete slide of height 2.5 m. When he
slides down the slope, he does work to
overcome friction of 140 J. What is his
velocity at the end of the slope?
33
2.12 ELASTICITY
Elasticity A property of matter that enables an object to
return to its original size and shape when the
force that was acting on it is removed.
No external force is applied.
Molecules are at their equilibrium separation.
Intermolecular force is equal zero.
Compressing a solid causes its molecules to be
displaced closer to each other.
Repulsive intermolecular force acts to push the
molecules back to their original positions.
Stretching a solid causes its molecules to be
displaced away from each other.
Attractive intermolecular force acts to pull back
the molecules to their original positions.
Stretching a wire by an
external force:
¾ Its molecules are slightly displaced away from
one another.
¾ Strong attractive forces act between the
molecules to oppose the stretching
When the external force is removed:
¾ The attractive intermolecular forces bring the
molecules back to their equilibrium separation.
¾ The wire returns to its original position
34
Hooke’s Law The extension of a spring is directly proportional
to the applied force provided the elastic limit is
not exceeded.
F = kx
F= force on the spring
x = extension
k = force constant of the spring
Force extension graph Based on the graph:
Relationship between F & x :
F is directly proportional to x
The gradient of the graph represent = force
constant of the spring, k
Area under the graph equal to the work done to
extent the spring:
= elastic potential energy = ½ Fx = ½ kx2
The elastic limit of a
spring
The maximum force that can be applied to a
spring such that the spring will be able to be
restored to its original length when the force is
removed.
If a force stretches a spring beyond its elastic
limit, the spring cannot return to its original l
even though the force no longer acts on it.
ength
The Hooke’s law is not obeyed anymore.
Force constant of the
spring, k
The force required to produce one unit of
extension of the spring.
x
F
k = unit N m-1
or N cm-1
or N mm-1
k is a measurement of the stiffness of the spring
¾ The spring with a larger force constant is
harder to extend and is said to be more stiff.
¾ A spring with a smaller force constant is easier
to extend and is said to be less stiff or softer.
35
Factors that effect elasticity
Factor Change in factor How does it affects the
elasticity
Shorter spring Less elastic
Length
Longer spring More elastic
Smaller diameter More elastic
Diameter of spring
wire Larger diameter Less elastic
Smaller diameter Less elastic
Diameter spring
Larger diameter More elastic
Type of material Springs made of different materials
Elasticity changes according to the type of
material
Arrangement of the spring
In series
The same load is applied to each
spring.
Tension in each spring = W
Extension of each spring = x
Total extension = 2x
If n springs are used:
The total extension = nx
In parallel
The load is shared equally among the
springs.
Tension in each spring =
2
W
Extension of each spring =
2
x
If n springs are used:
The total extension =
n
x
Example 1
The original length of
each spring is 10 cm.
With a load of 10 g, the
extension of each
spring is 2 cm.
What is the length of the
spring system for (a),
(b) and (c)?
36
37
38
SECTION A
QUESTION 1
Figure 1.1 shows a car moving along a straight line but hilly road.
Figure 1.1
Figure 1.2 shows how the velocity of the car
varies with time as it travels from A to E. The car
travels at 60 kmh-1
from A to B for two minutes.
Figure 1.2
(a) Describe the acceleration of the car as it
travels from A to E.
…………………………………………………
…………………………….
2
m
(b) Compare the resultant force as it travels
along AB and CD.
…………………………………………………
……………………………
1
m
(c) Give a reason to your answer in (b)
…………………………………………………
…………………………
1
m
(d) Calculate the distance AB
2
m
(e) The velocity of a car increases if the
force exerted on the accelerator of a car
increases. Explain why the velocity of the
car increases from D to E although the
force on the accelerator of the car is the
same as a long C to D.
…………………………………………………
2
m
39
……………………………
…………………………………………………
…………………………...
QUESTION 2 (SPM 1999)
40
A bus traveled from Kota
Lumpur at 9:00 pm. The cap
passenger in the bus is 40
mass of the bus with the ca
and the average frictional fo
bus tire and the road for the jo
The bus moves at average sp
Kota Bharu before stopover a
at 12:00 mid night on the s
hour later the bus continue
Kuala Lumpur with average
The bus arrived at 6:00 am on
(a) Put in a table all the phys
involved in the informatio
two groups.
(b) Calculate the total distanc
the bus.
(c) Sketch a distance-time gr
the motion of the bus.
(d)
(i)
(ii)
What is the value of the tr
the bus when it moves at
speed?
………………………………
……………………………
Give a reason for the ans
………………………………
……………………………
(e) Why is it necessary to ha
capacity limit for the safe
the bus?
………………………………
……………………………
………………………………
……………………………
QUESTION 3 ( SPM 2000)
Figure 2
Figure 2 shows a car of mass 1 000kg moving a
straight but hilly road. QRST and TU is the part
of the hill that have constant slope where the
slope of QRST is higher that the slope of TU. The
frictional force that acts along QRSTU is 2 000N.
The velocity if the car at P is
80kmh-1
and takes 3 minutes to move from point
P to Q. The motion of the car along
PQRSTU represent by a velocity-time graph in
Figure 3.
41
(a) Classify the physical quantity into two groups.
2m
(b) From the graph in Figure 3, explain the acceleration of the car from
point P to S.
…………………………………………………………………………………………
………………………………………………………………………………………… 2m
(c) (i) Compare the resultant force of the car when the move along PQ and
ST.
……………………………………………………………………………………..
(ii) State a reason for your answer in c(i)
……………………………………………………………………………………...
1m
1m
(d) Calculate the distance form point P to Q
2m
QUESTION 4 (SPM 2002)
Figure 3(i)
Figure 3(ii)
Figure 3(i) shows a sky diver start to make a jump from an aircraft at a
certain height. Figure 3(ii) shows a velocity-time graph for the skydiver at
position S, T, U, V and W from the earth surface.
(a) (i) At which point the parachute start to open?
……………………………………………………………………………………
(ii) Give a reason for your answer in (a)(i)
……………………………………………………………………………………
1m
1m
(b) Calculate the acceleration of the diver at ST.
2m
(c) Sketch an acceleration-time graph for the motion of the skydiver at
point S, T, U, V and W at the space below.
3m
(d) Suggest one way that can the skydiver apply to reduce injuries on his
leg during landing. Explain your answer.
………………………………………………………………………………………...
……………………………………………………………………………………….. 2m
QUESTION 5 (SPM 1988)
Figure 4(i)
42
Figure 4(i) show a gun fires a bullet of mass 5g to an object.
(a) (i) What happen to the gun during the shot?
…………………………………………………………………………………..
(ii) Explain your answer in (a)(i)
…………………………………………………………………………………...
1m
1m
(b) The bullet shot the object of mass 0.495kg.
(i) If the bullet speed is 400ms-1
, what is the momentum of the
bullet?
(ii) What is speed of the object after the bullet obscured into the
object after
the gunshot?
2m
2m
(c) The object and the bullet that obscured in the object aloft at a
maximum height of H, as shown in Figure 4(ii).
Figure 4(ii)
(i) What is the value of kinetic energy of the object together with
the bullet
inside the object? 2m
43
44
(ii) Calculate maximum height, H achieved by the object?
(iii) In real situation it is possible to achieved maximum height, H.
Why?
……………………………………………………………………………………
……………………………………………………………………………………
2m
1m
QUESTION 6 (SPM 1994)
Figure 5 shows a man standing on a stationary boat. He then jumps out of
the boat onto the jetty. The boat moves a way from the jetty as he jumps.
Figure 5
(a) State the physics principle that is involved in the movement of the boat
as the man jumps onto the jetty.
………………………………………………………………………………………… 1m
(b) Explain why the boat moves away from the jetty when the man jumps.
………………………………………………………………………………………… 1m
(c) The mass of the man is 50 kg and he jumps at a velocity 2ms-1
. The
mass of the boat is 20kg. Calculate the velocity of the boat as the man
jumps.
2m
(d) Name one application of the physics principle stated in (a) in an
exploration of outer space.
………………………………………………………………………………………… m
45

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2 - Forces and Motion.pdf

  • 1. 1 2.1 LINEAR MOTION Physical Quantity Definition, Quantity, Symbol and unit Distance, l Distance is the total path length traveled from one location to another. Quantity: scalar SI unit: meter (m) Displacement, l (a)The distance in a specified direction. (b)the distance between two locations measured along the shortest path connecting them in a specific direction. (c)The distance of its final position from its initial position in a specified direction. Quantity: vector SI unit: meter (m) Speed,v Speed is the rate of change of distance Speed = Distance traveled Time taken Quantity: scalar SI unit: m s-1 Velocity, v Velocity is the rate of change of displacement. Velocity = Displacement Time taken Direction of velocity is the direction of displacement Quantity : Vector SI unit: m s-1 Average speed v = Total distant traveled, s Total time taken , t Average velocity v = Displacement, s Time taken, t Example: A car moves at an average speed / velocity of 20 ms-1 On average, the car moves a distance / displacement of 20 m in 1 second for the whole journey.
  • 2. Uniform speed Speed that remains the same in magnitude regardless of its direction. Uniform velocity Velocity that remains the same in magnitude and direction. An object has a non-uniform velocity if: (a)the direction of motion changes or the motion is not linear. (b)The magnitude of its velocity changes. Acceleration, a t u v a − = unit : ms-2 acceleration is positive When the velocity of an object changes, the object is said to be accelerating. Acceleration is defined as the rate of change of velocity. Acceleration = Change in velocity Time taken = final velocity, v – initial velocity, u Time taken, t • The velocity of an object increases from an initial velocity, u, to a higher final velocity, v Deceleration acceleration is negative. The rate of decrease in speed in a specified direction. The velocity of an object decreases from an initial velocity, u, to a lower final velocity, v. Zero acceleration An object moving at a constants velocity, that is, the magnitude and direction of its velocity remain unchanged – is not accelerating Constant acceleration Velocity increases at a uniform rate. When a car moves at a constant or uniform acceleration of 5 ms-2 , its velocity increases by 5 ms-1 for every second that the car is in motion. 2
  • 3. 3 1. Constant = uniform 2. increasing velocity = acceleration 3. decreasing velocity = deceleration 4. zero velocity = object at stationary / at rest 5. negative velocity = object moves at opposite direction 6. zero acceleration = constant velocity 7. negative acceleration = deceleration Comparisons between distance and displacement. Distance Displacement Total path length traveled from one location to another The distance between two locations measured along the shortest path connecting them in specific direction Scalar quantity Vector quantity It has magnitude but no direction It has both magnitude and direction SI unit meter SI unit : meter Comparisons between speed and velocity Speed Velocity The rate of change of distance The rate of change of displacement Scalar quantity Vector quantity It has magnitude but no direction It has both magnitude and direction SI unit : m s-1 SI unit : m s-1 Fill in the blanks: 1. A steady speed of 10 m/s = A distance of .. ……….is traveled every ……….. 2. A steady velocity of -10 m/s = A …………. Of 10 m is traveled every ………..to the left. 3. A steady acceleration of 4 ms-2 = Speed goes up by 4 m/s every ………. 4. A steady deceleration of 4 ms-2 = speed goes ……….. by 4 m/s every ………. 5. A steady velocity of 10 m/s = …………………………………………… …………………………………………………………………………………
  • 4. Example 1 Every day Rahim walks from his house to the junction which is 1.5 km from his house. Then he turns back and stops at warung Pak Din which is 0.5 km from his house. (a)What is Rahim’s displacement from his house • when he reaches the junction. • When he is at warung Pak Din. (b)After breakfast, Rahim walks back to his house. When he reaches home, (i) what is the total distance traveled by Rahim? (ii) what is Rahim’s total displacement from his house? Example 2 Every morning Amirul walks to Ahmad’s house which is situated 80 m to the east of Amirul’s house. They then walk towards their school which is 60 m to the south of Ahmad’s house. (a)What is the distance traveled by Amirul and his displacement from his house? (b)If the total time taken by Amirul to travel from his house to Ahmad’s house and then to school is 15 minutes, what is his speed and velocity? Example 3 Syafiq running in a race covers 60 m in 12 s. (a) What is his speed in m/s (b) If he takes 40 s to complete the race, what is his distance covered? 4
  • 5. 5 Example 4 An aeroplane flys towards the north with a velocity 300 km/hr in one hour. Then, the plane moves to the east with the velocity 400 km / hr in one hour. (a)What is the average speed of the plane? (b)What is the average velocity of the plane? (c)What is the difference between average speed and average velocity of the plane? Example 5 The speedometer reading for a car traveling north shows 80 km/hr. Another car traveling at 80 km/hr towards south. Is the speed of both cars same? Is the velocity of both cars same? A ticker timer ¾ Use: 12 V a.c power supply ¾ 1 tick = time interval between two dots. ¾ The time taken to make 50 ticks on the ticker tape is 1 second. Hence, the time interval between 2 consecutive dots is 1/50 = 0.02 s. ¾ 1 tick = 0.02 s
  • 6. Relating displacement, velocity, acceleration and time using ticker tape. FORMULA VELOCITY Time, t = 10 dots x 0.02 s = 0.2 s displacement, s = x cm velocity = s = x cm t 0.2 s ACCELERATION elapse time, t = (5 – 1) x 0.2 s = 0.8 s or t = (50 – 10) ticks x 0.02 s = 0.8 s Initial velocity, u = x1 0.2 final velocity, v = x2 0.2 acceleration, a = v – u t TICKER TAPE AND CHARTS TYPE OF MOTION Constant velocity – slow moving Constant velocity – fast moving ¾ Distance between the dots increases uniformly ¾ the velocity is of the object is increasing uniformly ¾ The object is moving at a uniform / constant acceleration. 6
  • 7. ¾ Distance between the dots decrease uniformly ¾ The velocity of the object is decreasing uniformly ¾ The object is experiencing uniform / constant deceleration Example 6 The diagram above shows a ticker tape chart for a moving trolley. The frequency of the ticker-timer used is 50 Hz. Each section has 10 dots-spacing. (a) What is the time between two dots. (b) What is the time for one strips. (c) What is the initial velocity (d) What is the final velocity. (e) What is the time interval to change from initial velocity to final velocity? (f) What is the acceleration of the object. THE EQUATIONS OF MOTION 7 u = initial velocity v = final velocity t = time taken s = displacement a = constant accleration
  • 8. 2.2 MOTION GRAPHS DISPLACEMENT – TIME GRAPH Velocity is obtained from the gradient of the graph. A – B : gradient of the graph is +ve and constant ∴ velocity is constant. B – C : gradient of the graph = 0 ∴ the velocity = 0, object at rest. C – D : gradient of the graph –ve and constant. The velocity is negative and object moves in the opposite direction. Area below graph Distance / displacement Positive gradient Constant Acceleration (A – B) Negative gradient Constant Deceleration (C – D) VELOCITY-TIME GRAPH Zero gradient Constant velocity / zero acceleration (B – C) GRAPH s versus t v versus t a versus t Zero velocity Negative velocity Constant velocity 8
  • 9. GRAPH s versus t v versus t a versus t Constant acceleration Constant deceleration Example 6 Contoh 11 Based on the s – t graph above: (a) Calculate the velocity at (i) AB (ii) BC (iii) CD (b) Describe the motion of the object at: (i) AB (ii) BC (iii) CD (c)Find: (i) total distance (ii) total displacement (d) Calculate (i) the average speed (ii) the average velocity of the moving particle. Example 7 (a) Calculate the acceleration at: (i) JK (ii) KL (iii) LM (b) Describe the motion of the object at: (i) JK (ii) KL (iii) LM Calculate the total displacement. (c) Calculate the average velocity. 9
  • 10. 2.3 INERTIA Inertia The inertia of an object is the tendency of the object to remain at rest or, if moving, to continue its motion. Newton’s first law Every object continues in its state of rest or of uniform motion unless it is acted upon by an external force. Relation between inertia and mass The larger the mass, the larger the inertia SITUATIONS INVOLVING INERTIA SITUATION EXPLAINATION When the cardboard is pulled away quickly, the coin drops straight into the glass. The inertia of the coin maintains its state at rest. The coin falls into the glass due to gravity. Chili sauce in the bottle can be easily poured out if the bottle is moved down fast with a sudden stop. The sauce inside the bottle moves together with the bottle. When the bottle stops suddenly, the sauce continue in its state of motion due to the effect of its inertia. Body moves forward when the car stops suddenly The passengers were in a state of motion when the car was moving. When the car stopped suddenly, the inertia in the passengers made them maintain their state of motion. Thus when the car stop, the passengers moved forward. A boy runs away from a cow in a zig zag motion. The cow has a large inertia making it difficult to change direction. 10
  • 11. • The head of hammer is secured tightly to its handle by knocking one end of the handle, held vertically, on a hard surface. • This causes the hammer head to continue on its downward motion when the handle has been stopped, so that the top end of the handle is slotted deeper into the hammer head. • The drop of water on a wet umbrella will fall when the boy rotates the umbrella. • This is because the drop of water on the surface of the umbrella moves simultaneously as the umbrella is rotated. • When the umbrella stops rotating, the inertia of the drop of water will continue to maintain its motion. Ways to reduce the negative effects of inertia 1. Safety in a car: (a)Safety belt secure the driver to their seats. When the car stops suddenly, the seat belt provides the external force that prevents the driver from being thrown forward. (b)Headrest to prevent injuries to the neck during rear-end collisions. The inertia of the head tends to keep in its state of rest when the body is moved suddenly. (c)An air bag is fitted inside the steering wheel. It provides a cushion to prevent the driver from hitting the steering wheel or dashboard during a collision. 2. Furniture carried by a lorry normally are tied up together by string. When the lorry starts to move suddenly, the furniture are more difficult to fall off due to their inertia because their combined mass has increased. Relationship between mass and inertia • Two empty buckets which are hung with rope from a the ceiling. • One bucket is filled with sand while the other bucket is empty. • Then, both pails are pushed. • It is found that the empty bucket is easier to 11
  • 12. push compared to the bucket with sand. • The bucket filled with sand offers more resistance to movement. • When both buckets are oscillating and an attempt is made to stop them, the bucket filled with sand offers more resistance to the hand (more difficult to bring to a standstill once it has started moving) • This shows that the heavier bucket offers a greater resistance to change from its state of rest or from its state of motion. • An object with a larger mass has a larger inertia. 2.4 MOMENTUM Definition Momentum = Mass x velocity = mv SI unit: kg ms-1 Principle of Conservation of Momentum In the absence of an external force, the total momentum of a system remains unchanged. Elastic Collision Inelastic collision ƒ Both objects move independently at their respective velocities after the collision. ƒ Momentum is conserved. ƒ Kinetic energy is conserved. ƒ Total energy is conserved. ƒ The two objects combine and move together with a common velocity after the collision. ƒ Momentum is conserved. ƒ Kinetic energy is not conserved. ƒ Total energy is conserved. 12
  • 13. 13 Total Momentum Before = total momentum After m1u1 + m2u2 = m1v1 + m2v2 Total Momentum Before = Total Momentum After m1u1 + m2u2 = (m1 + m2) v Explosion Before explosion both object stick together and at rest. After collision, both object move at opposite direction. Total Momentum before collision Is zero Total Momentum after collision : m1v1 + m2v2 From the law of conservation of momentum: Total Momentum = Total Momentum Before collision after collision 0 = m1v1 + m2v2 m1v1 = - m2v2 -ve sign means opposite direction EXAMPLES OF EXPLOSION (Principle Of Conservation Of Momentum) ¾ When a rifle is fired, the bullet of mass m, moves with a high velocity, v. This creates a momentum in the forward direction. ¾ From the principle of conservation of momentum, an equal but opposite momentum is produced to recoil the riffle backward. Application in the jet engine: A high-speed hot gases are ejected from the back with high momentum. This produces an equal and opposite momentum to propel the jet plane forward.
  • 14. The launching of rocket ¾ Mixture of hydrogen and oxygen fuels burn explosively in the combustion chamber. Jets of hot gases are expelled at very high speed through the exhaust. ¾ These high speed hot gases produce a large amount of momentum downward. ¾ By conservation of momentum, an equal but opposite momentum is produced and acted on the rocket, propelling the rocket upwards. In a swamp area, a fan boat is used. ¾ The fan produces a high speed movement of air backward. This produces a large momentum backward. ¾ By conservation of momentum, an equal but opposite momentum is produced and acted on the boat. So the boat will move forward. A squid propels by expelling water at high velocity. Water enters through a large opening and exits through a small tube. The water is forced out at a high speed backward. Total Mom. before= Total Mom. after 0 =Mom water + Mom squid 0 = mwvw + msvs -mwvw = msvs The magnitude of the momentum of water and squid are equal but opposite direction. This causes the squid to jet forward. 14
  • 15. Example Car A of mass 1000 kg moving at 20 ms-1 collides with a car B of mass 1200 kg moving at 10 m s-1 in same direction. If the car B is shunted forwards at 15 m s-1 by the impact, what is the velocity, v, of the car A immediately after the crash? Example Before collision After collision MA = 4 kg MB = 2 kg UA = 10 m/s to the left UB = 8 m/s to the right VB = 4 m/s to the left. Calculate the value of VA . Example A truck of mass 1200 kg moving at 30 m/s collides with a car of mass 1000 kg which is traveling in the opposite direction at 20 m/s. After the collision, the two vehicles move together. What is the velocity of both vehicles immediately after collision? Example A man fires a pistol which has a mass of 1.5 kg. If the mass of the bullet is 10 g and it reaches a velocity of 300 m/s after shooting, what is the recoil velocity of the pistol? 15
  • 16. 2.5 FORCE Example: Balanced Force When the forces acting on an object are balanced, they cancel each other out. The net force is zero. Effect : the object at is at rest [ velocity = 0] or moves at constant velocity [ a = 0] Weight, W = Lift, U Thrust, F = drag, G When the forces acting on an object are not balanced, there must be a net force acting on it. The net force is known as the unbalanced force or the resultant force. Unbalanced Force/ Resultant Force Effect : Can cause a body to - change it state at rest (an object will accelerate - change it state of motion (a moving object will decelerate or change its direction) Force, Mass & Acceleration The acceleration produced by a force on an object is directly proportional to the magnitude of the net force applied and is inversely proportional to the mass of the object. The direction of the acceleration is the same as that of the net force. Newton’s Second Law of Motion When a net force, F, acts on a mass, m it causes an acceleration, a. Force = Mass x Acceleration F = ma 16
  • 17. Relationship between a & F a α F The acceleration, a, is directly proportional to the applied force, F. Relationship between a and m m a 1 ∝ The acceleration of an object is inversely proportional to the mass, Experiment to Find The Relationship between Force, Mass & Acceleration Relationship between a & F a & m Situation Both men are pushing the same mass but man A puts greater effort. So he moves faster. Both men exerted the same strength. But man B moves faster than man A. Inference The acceleration produced by an object depends on the net force applied to it. The acceleration produced by an object depends on the mass Hypothesis The acceleration of the object increases when the force applied increases The acceleration of the object decreases when the mass of the object increases Variables: Manipulated : Responding : Constant : Force Acceleration Mass Mass Acceleration Force Apparatus and Material Ticker tape and elastic cords, ticker timer, trolleys, power supply and friction compensated runway and meter ruler. 17
  • 18. An elastic cord is hooked over the trolley. The elastic cord is stretched until the end of the trolley. The trolley is pulled down the runway with the elastic cord being kept stretched by the same amount of force An elastic cord is hooked over a trolley. The elastic cord is stretched until the end of the trolley. The trolley is pulled down the runway with the elastic cord being kept stretched by the same amount of force Determine the acceleration by analyzing the ticker tape. Acceleration t u v a − = Determine the acceleration by analyzing the ticker tape. Acceleration t u v a − = Procedure : - Controlling manipulated variables. - Controlling responding variables. - Repeating experiment. Repeat the experiment by using two , three, four and five elastic cords Repeat the experiment by using two, three, four and five trolleys. Recording data Analysing data 18
  • 19. 1. What force is required to move a 2 kg object with an acceleration of 3 m s-2 , if (a) the object is on a smooth surface? (b) The object is on a surface where the average force of friction acting on the object is 2 N? 2. Ali applies a force of 50 N to move a 10 kg table at a constant velocity. What is the frictional force acting on the table? 3. A car of mass 1200 kg traveling at 20 m/s is brought to rest over a distance of 30 m. Find (a) the average deceleration, (b) the average braking force. 4. Which of the following systems will produce maximum acceleration? 2.6 IMPULSE AND IMPULSIVE FORCE Impulse The change of momentum mv - mu Unit : kgms-1 or Ns Impulsive Force The rate of change of momentum in a collision or explosion Unit = N m = mass u = initial velocity v = final velocity t = time Longer period of time →Impulsive force decrease Effect of time Impulsive force is inversely proportional to time of contact Shorter period of time →Impulsive force increase 19
  • 20. Situations for Reducing Impulsive Force in Sports Situations Explanation Thick mattress with soft surfaces are used in events such as high jump so that the time interval of impact on landing is extended, thus reducing the impulsive force. This can prevent injuries to the participants. Goal keepers will wear gloves to increase the collision time. This will reduce the impulsive force. A high jumper will bend his legs upon landing. This is to increase the time of impact in order to reduce the impulsive force acting on his legs. This will reduce the chance of getting serious injury. A baseball player must catch the ball in the direction of the motion of the ball. Moving his hand backwards when catching the ball prolongs the time for the momentum to change so as to reduce the impulsive force. Situation of Increasing Impulsive Force Situations Explanation A karate expert can break a thick wooden slab with his bare hand that moves at a very fast speed. The short impact time results in a large impulsive force on the wooden slab. A massive hammer head moving at a fast speed is brought to rest upon hitting the nail. The large change in momentum within a short time interval produces a large impulsive force which drives the nail into the wood. 20
  • 21. A football must have enough air pressure in it so the contact time is short. The impulsive force acted on the ball will be bigger and the ball will move faster and further. Pestle and mortar are made of stone. When a pestle is used to pound chilies the hard surfaces of both the pestle and mortar cause the pestle to be stopped in a very short time. A large impulsive force is resulted and thus causes these spices to be crushed easily. Example 1 A 60 kg resident jumps from the first floor of a burning house. His velocity just before landing on the ground is 6 ms-1 . (a) Calculate the impulse when his legs hit the ground. (b) What is the impulsive force on the resident’s legs if he bends upon landing and takes 0.5 s to stop? (c) What is the impulsive force on the resident’s legs if he does not bend and stops in 0.05 s? (d) What is the advantage of bending his legs upon landing? Example 2 Rooney kicks a ball with a force of 1500 N. The time of contact of his boot with the ball is 0.01 s. What is the impulse delivered to the ball? If the mass of the ball is 0.5 kg, what is the velocity of the ball? 21
  • 22. 2.7 SAFETY VEHICLE Component Function Headrest To reduce the inertia effect of the driver’s head. Air bag Absorbing impact by increasing the amount of time the driver’s head to come to the steering. So that the impulsive force can be reduce Windscreen The protect the driver Crumple zone Can be compressed during accident. So it can increase the amount of time the car takes to come to a complete stop. So it can reduce the impulsive force. Front bumper Absorb the shock from the accident. Made from steel, aluminium, plastic or rubber. ABS Enables drivers to quickly stop the car without causing the brakes to lock. Side impact bar Can be compressed during accident. So it can increase the amount of time the car takes to come to a complete stop. So it can reduce the impulsive force. Seat belt To reduce the inertia effect by avoiding the driver from thrown forward. 22
  • 23. 2.8 GRAVITY Gravitational Force Objects fall because they are pulled towards the Earth by the force of gravity. This force is known as the pull of gravity or the earth’s gravitational force. The earth’s gravitational force tends to pull everything towards its centre. Free fall ¾ An object is falling freely when it is falling under the force of gravity only. ¾ A piece of paper does not fall freely because its fall is affected by air resistance. ¾ An object falls freely only in vacuum. The absence of air means there is no air resistance to oppose the motion of the object. ¾ In vacuum, both light and heavy objects fall freely. They fall with the same acceleration ie. The acceleration due to gravity, g. Acceleration due to gravity, g ¾ Objects dropped under the influence of the pull of gravity with constant acceleration. ¾ This acceleration is known as the gravitational acceleration, g. ¾ The standard value of the gravitational acceleration, g is 9.81 m s-2 . The value of g is often taken to be 10 m s-2 for simplicity. ¾ The magnitude of the acceleration due to gravity depends on the strength of the gravitational field. Gravitational field The gravitational field is the region around the earth in which an object experiences a force towards the centre of the earth. This force is the gravitational attraction between the object and the earth. The gravitational field strength is defined as the gravitational force which acts on a mass of 1 kilogram. m F g = Its unit is N kg-1 . 23
  • 24. Gravitational field strength, g = 10 N kg-1 Acceleration due to gravity, g = 10 m s-2 The approximate value of g can therefore be written either as 10 m s-2 or as 10 N kg-1 . Weight The gravitational force acting on the object. Weight = mass x gravitational acceleration W = mg SI unit : Newton, N and it is a vector quantity Comparison between weight & mass Mass Weight The mass of an object is the amount of matter in the object The weight of an object is the force of gravity acting on the object. Constant everywhere Varies with the magnitude of gravitational field strength, g of the location A scalar quantity A vector quantity A base quantity A derived quantity SI unit: kg SI unit : Newton, N The difference between a fall in air and a free fall in a vacuum of a coin and a feather. Both the coin and the feather are released simulta- neously from the same height. At vacuum state: There is no air resistance. The coin and the feather will fall freely. Only gravitational force acted on the objects. Both will fall at the same time. At normal state: Both coin and feather will fall because of gravitational force. Air resistance effected by the surface area of a fallen object. The feather that has large area will have more air resistance. The coin will fall at first. 24
  • 25. Two steel spheres are falling under gravity. The two spheres are dropped at the same time from the same height. (a)The two sphere are falling with an acceleration. The distance between two successive images of the sphere increases showing that the two spheres are falling with increasing velocity; falling with an acceleration. (b)The two spheres are falling down with the same acceleration The two spheres are at the same level at all times. Thus, a heavy object and a light object fall with the same gravitational acceleration. Gravitational acceleration is independent of mass. Motion graph for free fall object Free fall object Object thrown upward Object thrown upward and fall Example 1 A coconut takes 2.0 s to fall to the ground. What is (a) its speed when it strikes the ground (b) the height of the coconut tree. 25
  • 26. 2.9 FORCES IN EQUILIBRIUM Forces in Equilibrium When an object is in equilibrium, the resultant force acting on it is zero. The object will either be 1. at rest 2. move with constant velocity. Newton’s 3rd Law Examples( Label the forces acted on the objects) Resultant Force A single force that represents the combined effect of two of more forces in magnitude and direction. Addition of Forces Resultant force, F = ____ + ____ Resultant force, F = ____ + ____ 26
  • 27. Two forces acting at a point at an angle [Parallelogram method] STEP 1 : Using ruler and protractor, draw the two forces F1 and F2 from a point. STEP 2 Complete the parallelogram STEP 3 Draw the diagonal of the parallelogram. The diagonal represent the resultant force, F in magnitude and direction. scale: 1 cm = …… Resolution of Forces A force F can be resolved into components which are perpendicular to each other: (a) horizontal component , FX (b) vertical component, FY Fx = F cos θ Fy = F sin θ Inclined Plane Component of weight parallel to the plane = mg sin θ Component of weight normal to the plane = mg cos θ 27
  • 28. find the resultant force (d) (e) Lift Stationary Lift Lift accelerate upward Lift accelerate downward Resultant Force = Resultant Force = Resultant Force = The reading of weighing scale = The reading of weighing scale = The reading of weighing scale = 28
  • 29. Pulley 1. Find the resultant force, F 2. Find the moving mass,m 3. Find the acceleration,a 4. Find string tension, T 29
  • 30. 2.10 WORK, ENERGY, POWER & EFFICIENCY Work Work done is the product of an applied force and the displacement of an object in the direction of the applied force W = Fs W = work, F = force s = displacement The SI unit of work is the joule, J 1 joule of work is done when a force of 1 N moves an object 1 m in the direction of the force Calculation of Work 30 The displacement, s of the object is in the direction of the force, F The displacement , s of the object is not in the direction of the force, F W = Fs W = F s W = (F cos θ) s Example 1 A boy pushing his bicycle with a force of 25 N through a distance of 3 m. Calculate the work done by the boy. Example 2 A girl is lifting up a 3 kg flower pot steadily to a height of 0.4 m. What is the work done by the girl? Example 3 A man is pulling a crate of fish along the floor with a force of 40 N through a distance of 6 m. What is the work done in pulling the crate? s F
  • 31. No work is done when: The object is stationary A student carrying his bag while waiting at the bus stop The direction of motion of the object is perpendicular to that of the applied force. A waiter is carrying a tray of food and walking No force is applied on the object in the direction of displacement (the object moves because of its own inertia) A satellite orbiting in space. There is no friction in space. No force is acting in the direction of movement of the satellite. Concept Definition Formula & Unit Power The rate at which work is done, or the amount of work done per second. t W P = p = power, W = work / energy t = time Energy ¾ Energy is the capacity to do work. ¾ An object that can do work has energy ¾ Work is done because a force is applied and the objects move. This is accompanied by the transfer of energy from one object to another object. ¾ Therefore, when work is done, energy is transferred from one object to another. ¾ The work done is equal to the amount of energy transferred. Potential Energy Gravitational potential energy is the energy of an object due to its higher position in the gravitational field. m = mass h = height g = gravitational acceleration E = mgh Kinetic Energy Kinetic energy is the energy of an object due to its motion. m = mass v = velocity E = ½ mv2 31
  • 32. Principle of Conservation of Energy Energy can be changed from one form to another, but it cannot be created or destroyed. The energy can be transformed from one form to another, total energy in a system is constant. Total energy before = total energy after Example 4 A worker is pulling a wooden block of weight,W,with a force of P along a fritionless plank at height of h. The distance traveled by the block is x. Calculate the work done by the worker to pull the block. Example 5 A student of mass m is climbing up a flight of stairs which has the height of h. He takes t seconds.. 32 What is the power of the student? Example 6 A stone is thrown upward with initial velocity of 20 ms -1 . What is the maximum height which can be reached by the stone? Example 7 A boll is released from point A of height 0.8 m so that it can roll along a curve frictionless track. What is the velocity of the ball when it reaches point B? Example 8 Example 9
  • 33. A trolley is released from rest at point X along a frictionless track. What is the velocity of the trolley at point Y? A ball moves upwards along a frictionless track of height 1.5 m with a velocity of 6 ms -1 . What is its velocity at point B? Example 10 A boy of mass 20 kg sits at the top of a concrete slide of height 2.5 m. When he slides down the slope, he does work to overcome friction of 140 J. What is his velocity at the end of the slope? 33
  • 34. 2.12 ELASTICITY Elasticity A property of matter that enables an object to return to its original size and shape when the force that was acting on it is removed. No external force is applied. Molecules are at their equilibrium separation. Intermolecular force is equal zero. Compressing a solid causes its molecules to be displaced closer to each other. Repulsive intermolecular force acts to push the molecules back to their original positions. Stretching a solid causes its molecules to be displaced away from each other. Attractive intermolecular force acts to pull back the molecules to their original positions. Stretching a wire by an external force: ¾ Its molecules are slightly displaced away from one another. ¾ Strong attractive forces act between the molecules to oppose the stretching When the external force is removed: ¾ The attractive intermolecular forces bring the molecules back to their equilibrium separation. ¾ The wire returns to its original position 34
  • 35. Hooke’s Law The extension of a spring is directly proportional to the applied force provided the elastic limit is not exceeded. F = kx F= force on the spring x = extension k = force constant of the spring Force extension graph Based on the graph: Relationship between F & x : F is directly proportional to x The gradient of the graph represent = force constant of the spring, k Area under the graph equal to the work done to extent the spring: = elastic potential energy = ½ Fx = ½ kx2 The elastic limit of a spring The maximum force that can be applied to a spring such that the spring will be able to be restored to its original length when the force is removed. If a force stretches a spring beyond its elastic limit, the spring cannot return to its original l even though the force no longer acts on it. ength The Hooke’s law is not obeyed anymore. Force constant of the spring, k The force required to produce one unit of extension of the spring. x F k = unit N m-1 or N cm-1 or N mm-1 k is a measurement of the stiffness of the spring ¾ The spring with a larger force constant is harder to extend and is said to be more stiff. ¾ A spring with a smaller force constant is easier to extend and is said to be less stiff or softer. 35
  • 36. Factors that effect elasticity Factor Change in factor How does it affects the elasticity Shorter spring Less elastic Length Longer spring More elastic Smaller diameter More elastic Diameter of spring wire Larger diameter Less elastic Smaller diameter Less elastic Diameter spring Larger diameter More elastic Type of material Springs made of different materials Elasticity changes according to the type of material Arrangement of the spring In series The same load is applied to each spring. Tension in each spring = W Extension of each spring = x Total extension = 2x If n springs are used: The total extension = nx In parallel The load is shared equally among the springs. Tension in each spring = 2 W Extension of each spring = 2 x If n springs are used: The total extension = n x Example 1 The original length of each spring is 10 cm. With a load of 10 g, the extension of each spring is 2 cm. What is the length of the spring system for (a), (b) and (c)? 36
  • 37. 37
  • 38. 38 SECTION A QUESTION 1 Figure 1.1 shows a car moving along a straight line but hilly road. Figure 1.1 Figure 1.2 shows how the velocity of the car varies with time as it travels from A to E. The car travels at 60 kmh-1 from A to B for two minutes. Figure 1.2 (a) Describe the acceleration of the car as it travels from A to E. ………………………………………………… ……………………………. 2 m (b) Compare the resultant force as it travels along AB and CD. ………………………………………………… …………………………… 1 m (c) Give a reason to your answer in (b) ………………………………………………… ………………………… 1 m (d) Calculate the distance AB 2 m (e) The velocity of a car increases if the force exerted on the accelerator of a car increases. Explain why the velocity of the car increases from D to E although the force on the accelerator of the car is the same as a long C to D. ………………………………………………… 2 m
  • 40. 40 A bus traveled from Kota Lumpur at 9:00 pm. The cap passenger in the bus is 40 mass of the bus with the ca and the average frictional fo bus tire and the road for the jo The bus moves at average sp Kota Bharu before stopover a at 12:00 mid night on the s hour later the bus continue Kuala Lumpur with average The bus arrived at 6:00 am on (a) Put in a table all the phys involved in the informatio two groups. (b) Calculate the total distanc the bus. (c) Sketch a distance-time gr the motion of the bus. (d) (i) (ii) What is the value of the tr the bus when it moves at speed? ……………………………… …………………………… Give a reason for the ans ……………………………… …………………………… (e) Why is it necessary to ha capacity limit for the safe the bus? ……………………………… …………………………… ……………………………… …………………………… QUESTION 3 ( SPM 2000) Figure 2 Figure 2 shows a car of mass 1 000kg moving a straight but hilly road. QRST and TU is the part of the hill that have constant slope where the slope of QRST is higher that the slope of TU. The frictional force that acts along QRSTU is 2 000N. The velocity if the car at P is 80kmh-1 and takes 3 minutes to move from point P to Q. The motion of the car along PQRSTU represent by a velocity-time graph in Figure 3.
  • 41. 41 (a) Classify the physical quantity into two groups. 2m (b) From the graph in Figure 3, explain the acceleration of the car from point P to S. ………………………………………………………………………………………… ………………………………………………………………………………………… 2m (c) (i) Compare the resultant force of the car when the move along PQ and ST. …………………………………………………………………………………….. (ii) State a reason for your answer in c(i) ……………………………………………………………………………………... 1m 1m (d) Calculate the distance form point P to Q 2m QUESTION 4 (SPM 2002) Figure 3(i) Figure 3(ii) Figure 3(i) shows a sky diver start to make a jump from an aircraft at a certain height. Figure 3(ii) shows a velocity-time graph for the skydiver at position S, T, U, V and W from the earth surface. (a) (i) At which point the parachute start to open? …………………………………………………………………………………… (ii) Give a reason for your answer in (a)(i) …………………………………………………………………………………… 1m 1m (b) Calculate the acceleration of the diver at ST.
  • 42. 2m (c) Sketch an acceleration-time graph for the motion of the skydiver at point S, T, U, V and W at the space below. 3m (d) Suggest one way that can the skydiver apply to reduce injuries on his leg during landing. Explain your answer. ………………………………………………………………………………………... ……………………………………………………………………………………….. 2m QUESTION 5 (SPM 1988) Figure 4(i) 42
  • 43. Figure 4(i) show a gun fires a bullet of mass 5g to an object. (a) (i) What happen to the gun during the shot? ………………………………………………………………………………….. (ii) Explain your answer in (a)(i) …………………………………………………………………………………... 1m 1m (b) The bullet shot the object of mass 0.495kg. (i) If the bullet speed is 400ms-1 , what is the momentum of the bullet? (ii) What is speed of the object after the bullet obscured into the object after the gunshot? 2m 2m (c) The object and the bullet that obscured in the object aloft at a maximum height of H, as shown in Figure 4(ii). Figure 4(ii) (i) What is the value of kinetic energy of the object together with the bullet inside the object? 2m 43
  • 44. 44 (ii) Calculate maximum height, H achieved by the object? (iii) In real situation it is possible to achieved maximum height, H. Why? …………………………………………………………………………………… …………………………………………………………………………………… 2m 1m QUESTION 6 (SPM 1994) Figure 5 shows a man standing on a stationary boat. He then jumps out of the boat onto the jetty. The boat moves a way from the jetty as he jumps. Figure 5 (a) State the physics principle that is involved in the movement of the boat as the man jumps onto the jetty. ………………………………………………………………………………………… 1m (b) Explain why the boat moves away from the jetty when the man jumps. ………………………………………………………………………………………… 1m (c) The mass of the man is 50 kg and he jumps at a velocity 2ms-1 . The mass of the boat is 20kg. Calculate the velocity of the boat as the man jumps. 2m (d) Name one application of the physics principle stated in (a) in an exploration of outer space. ………………………………………………………………………………………… m
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