Organic Name Reactions for the students and aspirants of Chemistry12th.pptx
Moi ii
1. Calculation of Multiplicity of
Infection(moi) - ii
Dr. S. Sivasankara Narayani.,M.Sc.,M.Phil.,Ph.D.,MRSB (UK)
2. A 0.25 mL aliquot of an E. coli culture having a
concentration of 8 x 108 cells/mL is placed into a tube. What
volume of a bacteriophage stock having a concentration of 2
x 109 phage/mL should be added to the cell sample to give
an moi of 0.5?
First, calculate the number of cells in the 0.25 mL aliquot:
0.25mL x 8x108 cells = 2 x 108 cells
mL
3. calculate how many bacteriophage particles are required
for an moi of 0.5 when 2 x 108 cells are used
x phage = 0.5 phage
2x108cells cell
Solve for x:
x = 0.5 Phages (2 x 108 cells) = 1 x 108
phages
cell
4. calculate the volume of the bacteriophage stock that will
contain 1 x 108 phage:
(2 x 109 Phages) X ml = 1 x 108 phages.
ml
x = 1 x 108 phage = 0.05mL
2 x 109 phage/mL
5. Therefore, 0.05 mL of the
phage stock added to the
aliquot of cells will give an
moi of 0.5.
6. Reference
Calculations for molecular biology and Biotechnology – A Guide to mathematics in
the laboratory, Second Edition – Frank. H. Stephenson
21-09-2021
Dr.SS
sivasan91@gmail.com
