Muriel recently stopped taking her medication resulting in flulike s.pdf

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Muriel recently stopped taking her medication resulting in flulike symptoms. She was most likely taking a(n): A. atypical second-generation antidepressant. B. SSRI. C. MAOI. D. tricyclic antidepressant. Solution 1. The above all 4 drugs belong to antidepressant drugs. 2. Atypical second-generation antidepressants are antipsychotic drugs. These drugs have less side effects. 3. The remaining three SSRI, MAOI and Tricyclic antidepressant are antidepressant mostly used in panic disorder or social phobia. 4. MAOI is used as last line treatment when SSRI and Tricyclic antidepressant have failed. 5. Side effects of tricyclic antidepressant causes symptoms like flu such as dry mounth, dry nose, blurry vision, and increasing body temperature. 6. So she was most likely taking tricyclic antidepressant..

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Note the structures through which light passes to reach the retina. Write these structures in order. Solution The order of light passage from outside till to retina: Initially light enters cornea & sclera layers ---> pupil ---> circular Iris that surrounds pupil using pupillary sphincter muscle --> light enters lens---> retinal layers ---> rods & cones Explanation: Neural layer is the inner layer; it is in contact with the vitreous humour. The neural layer contains three distinct populations of cells namely, From the outer (pigmented epithelial layer) to the inner (towards the vitreous humour), these cells are arranged in the order of, photoreceptors, bipolar cells, ganglion cells. Photoreceptor cells (rods and cones) are communicated with the nerve cells called bipolar cells. These bipolar cells synapse with the ganglion cells, which transmit the impulses to the brain via axons in the optic nerve. Retina is the innermost nervous coat of eyeball, and it contains some special photo receptor structures called “rods and cones.” These rods and cones receive the light and send impulses to the optic nerve. The inner nuclear layer of the retina contains oval shaped bipolar cells. The dendrites of bipolar cells synapse with the photoreceptor cells, and axons of bipolar cells synapse with the ganglionic cells. Ganglion cells are multipolar cells present in the ganglion cell layer of retina; their axons are present in the inner surface of the retina, forming the optic nerve. The dendrites of ganglion cells synapse with the axons of bipolar cells. These ganglion cells transmit the impulses to the brain via axons in the optic nerve..

Note the structures through which light passes to reach the retina. W.pdf

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managerial reporting systems areStandardizedRigidFlexible.pdf

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Lot X_1, ..., X_n be independent and identically distributed continuo.pdf

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Let Y follows a Poisson distribution with mean lambda: that is, Y approx equal Poisson(lambda). Show that E(Y) = lambda. Hint: you may use one of the following two methods Method 1: use exponential series e^x = 1 + x + x^2/2! + x^3/3! + .,.. Method 2: Use the 2nd property of a valid pmf that summation y p(y) = 1 Solution P(x; ?) = (e-?) (?x) / x! xP(x) = x (e-?) (?x) / x! = (e-?) (?x) / (x-1)!= (e-?) (?) (?x-1) / (x-1)! Mean = sum of all xP(X) = (e-?) (?) e?? = ? Thus mean of Poisson distribution is its parameter. Or E(Y) = Lemda.

Let Y follows a Poisson distribution with mean lambda that is, Y app.pdf

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In humans, the HOXD homeotic gene cluster plays a critical role in limb development. In one large family, 16 of 36 members expressed one of two dominantly inherited malformations of the feet known as rocker bottom foot (CVT) or claw foot (CMT). One individual had one foot with CVT and the other with CMT. Genomic analysis identified a single missense mutation in the HOXD10 gene, resulting in a single amino acid substitution in the homeodomain of the encoded transcription factor. This region is crucial for making contact and binding to the target genes controlled by this protein. All family members with the foot malformations were heterzygotes; all unaffected members were homozygous for the normal allele. 1) Given that affected heterozygotes carry one normal allele of the HOX10D gene, how mught a dominant mutation in a gene encoding a transcription factor lead to a developmental malformation? 2) How can two clinically different phenotypes result from the same mutation? 3) What might we learn about the control of developmental processes from an understanding of how this mutation works? Solution 1) If the wild type allele is dominant, it would not allow the expression of the dominant mutation. If the wild type allele is recessive, it would allow the expression of the dominant mutation. Here, the heterozygotes possess wild type allele that is recessive and hence cannot prevent the expression of the mutation. Homozygotes possess wild type allele that is dominant and hence can prevent the mutation expression. 2) If the recessive alleles present at a given locus are different from each other in having two mutations at different loci, then two different phenotypes result from a single mutation. Here, one allele represents a dominant mutation and the other is a recessive allele of normal type. Often two unrelated allele inheritance might result in the two different phenotypes, one due to a classic mutation and other due to a rare and a new mutation. 3) If a weak or recessive allele exists along with a dominant mutation at the same locus, the dominant mutation might have negative impact on the normal wild type recessive allele as well during the inheritance. This impact will show a lot of difference in the expression of the gene and in turn in the control of the developmental processes..

In humans, the HOXD homeotic gene cluster plays a critical role in l.pdf

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I am sorry but my major does not cover programming in depth (ICT) and we are expected to know advanced java programming. I am looking for help. I have purchased a book from Oracle but I will not be up to speed this semester. Please Help me!!! 1. Write an app called viewer that will have a Label at the top saying \"My Viewer\" (or something like that) 2. Will have JButtons at the bottom that will do Next, Previous, and Quit 3. Have the whole middle be a JLabel in which you will display Images stored in a directory. 4. The directory can be named Resource. 5. When you run the program (java viewer) it will read all the names in the Resource Directory. Then, when you click Next or Previous it will display an Image. 6. Note: you will need to find a java method that exists for reading a whole directory of filenames. You can store all those names in a String Array when run the program. 7. You will use a counter or index that is an int an when you click Next it will increment the counter until it reach some maximum value and then you will set it to 0. Previous will decrement the counter until it goes negative and then it will set the counter to the Maximum index ( which is how many filenames you have in the Image names array) 8. Submit the program viewer.java I should be able to use it with my own Resource directory Solution Compilation process javac Viewer.java Run java Viewer Click on next or previous a file chooser will be opened and you can select your file The Code is in four file. // File Dg.java import java.io.File; public class Dg { public File nextFile(File file) { File f[] = new File[5000]; f = file.getParentFile().listFiles(new ImageFileFilter()); int max = f.length; max = max - 1; // System.out.println(file); for (int i = 0; i < f.length; i++) { if (f[i].equals(file)) { if (i + 1 > max) { return f[0]; } else { return f[i + 1]; } } else { // System.out.println(0); // return file; } } return file; } public File priFile(File file) { File f[] = new File[5000]; f = file.getParentFile().listFiles(new ImageFileFilter()); int min = 0; // System.out.println(file); for (int i = 0; i < f.length; i++) { if (f[i].equals(file)) { min = i - 1; if (min < 0) { return f[f.length-1]; } else { return f[min]; } } else { // System.out.println(0); // return file; } } return file; } } /// Image.java import java.awt.Graphics; import java.awt.Graphics2D; import java.awt.geom.AffineTransform; import java.awt.image.BufferedImage; import java.io.File; import java.io.IOException; import javax.imageio.ImageIO; import javax.swing.JPanel; import java.awt.Color; import javax.swing.JLabel; import java.awt.Font; public class Image extends JPanel { /** * */ private static final long serialVersionUID = 1L; public BufferedImage img = null; /** * Create the panel. */ @SuppressWarnings(\"static-access\") public Image() { setBackground(new Color(255, 255, 255)); setLayout(null); try { Viewer ocr = new Viewer(); img = ImageIO.read(ocr.file); JLabel lblNewLabel = new JLabel(Viewer.f.

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explain why blockage or removal of the lymphatic vessels can result in significant edema Solution LYMPH: Lymph is the second largest circulatory system in human body.It is made up of lymphatic vessels or capillaries. FUNCTION OF LYMPHATIC VESSELS: The main function of lymphatic vessels or lymphatic capillaries is pick up the fluid that leaks in to the tissues from the blood stream and return into the circulatory system.it absorbs the lymphatic fluid from the tissues. The blockage ir removal of the lymphatic vessels leads to the significant edema. EDEMA: Edema means swellimg of a perticular body part due to the accumulation of fluid.or inflamation of a body part.other wise it can happens due to the injury of a body part. The obstruction of the lymphatic capillaries or lymphatic vessels leads to its disfunction..so that the absorption of accumulatic lymphatic fluid from the tissues does not takes place in the body.. this leads to the edema..This may occurs at a perticular region of the body or somtimes entire body can be affected..

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Alice Agent is an employee of Patti Principal. She negligently runs a stop sign in the course of her employment and injures Bart Bikerider. Can Bart sue Patti for his damages from Alice’s Negligence? Why or why not? Solution Yes Bart can sue Patti for his damages because the employer is responsible for actions of employees during the course of their employment. The doctrine is called respondeat superior..

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at log kHz Solution You can have several problems: 1) if you are working with transistors sure you\'re not saturating. 2) if diodes are sure they are doing the right contact or try another. 3) Make sure your input source this good. 4) for me the most certain is that you are using an active elemnto and this is in court and why that image, check input sources, the currents that these manipulated are optimal for circuit elements you use or application you\'re doing..

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Why do you think it is usually preferable to start with the side containing the more complicated expression when establishing a trigonometric identity? Solution 1. Human brains are accustomed to simplify complicated things rather than complicating a simpler one. 2. A simpler/simplest conclusion of a complicated problem in trigonometric identities is only a handful;mere 2 or 3. But if I want to complicate a simpler side, outcomes are numerous. For eg: prove cosx*tanx =sinx Now I know that if I want to simplify LHS, I will try to convert it is terms of Sin or Cos (which we consider simple in the world of trigonometry) So cosx*(sinx/cosx)= cosx which is RHS. But if I want to complicate sinx ,I can write it as 1/cscx or 1-cos^2x or (1-cos2x)/2 . . . . And the list goes on! So, by and large, it is customary simplify complicated things rather than the other way. Hope it clarifies your doubt!.

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Why is the mucus thicker than normal in CF patients? A good answer will include a description of how osmosis is affected by CF. Solution Mucus is a substance that coats our Epithelial surface.It keeps surfaces lubricated and helps prevent disease by trapping potential invaders.Invading microbes can become trapped in the mucus.The epithelial cells are lined with cilia that are constantly beating and moving mucus with trapped bacteria up and out of the respiratory tract.Mucus is amixture of predominantly water and glycproteins.The mucins are produced by goblet cell that are interspersed among the respiratory epithelial cell.The composition,water content and volume of mucus are controlled by the secretion and absorption of ions and water across the respiratory epithelium.The salt imbalance resulting from a disfuctional chloride channel could through osmosis lead to the thick mucus characterstic of cystic fibrosis mutation could lead to disease.cystic fibrosis is a thick that lines both the airways and the intestinal tract of affected individual.In the respiratory tract this thick mucus is not removed by the cillia that usually beat and push mucus up into the throat.This thick mucus builds up in the airways and bacteria trapped in the mucus are not removed.Thus bacterial respiratory infections are extremely common and dangerous in CF individuals..

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what kind of accessory protein would you classify IRS1 and 2 as? Docking protein Adaptor protein? Transcription factor? SH2 domain protein Solution Docking protein - The robosomes are of two types based on their occurence in the cell. Free ribosomes and membrane bound (on ER surface). Ever wondered why and how they are of two types? Yes!! Some specific proteins which are found on the surface of certain specific ribosomal particles making them \"dock\" (stick) on to the ER surface are called docking proteins. Adapter protein - An adapter protein is one which assists in signal transduction across membranes. They aid receptor mechanisms in the cells. Transcription factor - The process of copying cell DNA codons in to an mRNA strand in called transcription. This is assisted by certain types of protein called Transcription factors. SH2 domain - These are specific proteins that mediate and fecilitate protein-protein inteactions in the cell. SH2 domain (a structurally special part within a protein molecule) is found within Src oncoprotein (cancer protein) which makes the Src oncoprotein attach to other protein containing phosphorylated tyrosin residues. **IRS1 and IRS2 proteins are classified as adapter proteins.**.

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What is the main difference between prokaryotic and eukaryotic ribosomes? Prokaryotic ribosomes synthesize RNA whereas eukaryotic ribosomes synthesize proteins Eukaryotic ribosomes are composed of RNA and protons whereas prokaryote ribosomes are Solution None of the above The main difference is that Prokaryotic ribosomes(70S) having two subunits- 30S and 50S and Eukaryotic ribosomes(80S) also having two subunits- 40S and 60S Both are composed of RNA & proteins. 70S having 60% RNA & 40% proteins while 80S having 40%RNA & 60% proteins..

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what is the cardinality of a sample space? Solution A sample space is a collection of all possible outcomes of a random experiment. A random variable is a function defined on a sample space. We shall consider several examples shortly. Later on we shall introduce probability functions on the sample spaces. A sample space may be finite or infinite. Infinite sample spaces may be discrete or continuous.

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What is computer information systems in three paragraphs. Solution A computer information system be a system collected of people and computer that process or interpret information. The word is also from time to time used in more limited senses to refer to only the software used to sprint a automated database or to refer to only a computer system. A computer(based) information system, or CBIS, uses computers to gather, procedure, store, examine and allocate information for a specific reason, such as gathering a trade objective. The main mechanism of a CBIS comprise hardware, software, data, events and public. A computer(based) information system be basically an IS using computer knowledge to take out some or all of its intended tasks. The basic mechanism of computer based information system are:- · Hardware these are the plans like the check, processor, printer and keyboard, all of which work jointly to accept, procedure, show information and in sequence. · Software are the program that let the hardware to procedure the data. · Databases are the meeting of connected files or tables contain related data. · Networks are a between system that allow diverse computer to hand out resources. · Procedures are the instructions for combine the mechanism above to development in sequence and produce the ideal output..

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