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James K. Wight, Past ACI President, Former Chair of Comm. 318
F.E. Richart, Jr. Collegiate Professor of Civil & Env. Engineering
University of Michigan
ACI 318-19: What’s New for 2019
ACI 318-19: What’s New for 2019
• New Shear Strength Equations;
including size-effect factor
• Higher Rebar Grades
• Updated Development Lengths
• New Effective Stiffness for Deflection
Calculations
• Seismic Design Details – Shear Walls
• Some Updates to Strut & Tie Method
Changes to the Concrete
Design Standard
ACI 318-19
Shear Modifications
Shear equation changes for one-
way and two-way shear
• Size Effect
• Low Flexural Reinforcement Ratio
• Axial load (prestress)
• Results gathered and vetted by ACI Comm. 445
Why one-way shear equations changed
in 318-19
5
Figure: Strength Ratio (Vtest/Vn)
d = 10 in. – λs, size effect factor
,min
v v
A A
≤
Why one-way shear equations changed
in 318-19
6
0.0018 – min. slab ρw
,min
v v
A A
≤
0.015 – ρw effect
Figure: Strength Ratio (Vtest/Vn)
Why one-way shear equations changed
in 318-19
7
d = 10 in. – λs, size effect factor
,min
v v
A A
>
Figure: Strength Ratio (Vtest/Vn)
One-way shear provision:
Modified goals
• Include nonprestressed and prestressed
• Include size effect and axial loading
• Include effect of (ρw)
• Continue to use 2√f’
c
• Reduce multiple empirical equations
• Easy to use
ACI 318-19 New one-way shear equations
Table 22.5.5.1 - Vc for nonprestressed
members
Criteria Vc
Av ≥ Av,min
Either
of:
2𝜆𝜆 𝑓𝑓𝑓𝑐𝑐 +
𝑁𝑁𝑢𝑢
6𝐴𝐴𝑔𝑔
𝑏𝑏𝑤𝑤𝑑𝑑 (a)
8𝜆𝜆 𝜌𝜌𝑤𝑤
⁄
1 3 𝑓𝑓𝑓𝑐𝑐 +
𝑁𝑁𝑢𝑢
6𝐴𝐴𝑔𝑔
𝑏𝑏𝑤𝑤𝑑𝑑 (b)
Av < Av,min 8𝜆𝜆𝑠𝑠𝜆𝜆 𝜌𝜌𝑤𝑤
⁄
1 3
𝑓𝑓𝑓𝑐𝑐 +
𝑁𝑁𝑢𝑢
6𝐴𝐴𝑔𝑔
𝑏𝑏𝑤𝑤𝑑𝑑 (c)
Notes:
1. Axial load, Nu, is positive for compression and negative for tension
2. Vc shall not be taken less than zero.
0
0.5
1
1.5
2
2.5
0.3%
0.4%
0.5%
0.6%
0.7%
0.8%
0.9%
1.0%
1.1%
1.2%
1.3%
1.4%
1.5%
1.6%
1.7%
1.8%
1.9%
2.0%
2.1%
2.2%
2.3%
2.4%
2.5%
Vn
/
sqrt(f’c)
Longitudinal Reinforcement Ratio (As/bd)
ACI 318-19 Shear Equation
8𝜆𝜆 𝜌𝜌𝑤𝑤
⁄
1 3
Effect of ρw
Size Effect: Value for λs?
0
0.2
0.4
0.6
0.8
1
1.2
0 12 24 36 48 60 72 84 96 108 120
λ
s
Depth in inches
2
1.0
1
10
s
d
λ
= ≤
+
Beam discussion
• Where Av,min installed and Nu ≈ 0, Vc≈ (2√f’
c)bwd,
– ACI 318-14 ~ ACI 318-19
• Provisions encourage use of Av,min
9.6.3.1 - Minimum shear
reinforcement
• ACI 318-14
• Av,min required if Vu > 0.5 φVc
• ACI 318-19
• Av,min required if Vu > φλ√f’
c bwd
Example: Foundation Shear Check
• ℓ = 12 ft
• h = 30 in.
• d~25.5 in.
• f’
c = 4000 psi
• 13-No. 8 bars
• b = 12 ft
• Av = 0 in.2
• As = 10.27 in.2
• Analysis Vu= 231 kip
3
ft
–
0
in.
Example: Foundation Shear Check
• ACI 318-14
'
2
(0.75)(2)(1) 4000 (144 .)(25.5 .)
348 kip 231 kip OK
c c
c
c
V f bd
V psi in in
V
φ φ λ
φ
φ
=
=
= > ∴
Example: Foundation Shear Check
• ACI 318-19
• Av ≤ Av,min
• Per ACI 318-19 (13.2.6.2), neglect size effect
for:
– One-way shallow foundations
– Two-way isolated footings
– Two-way combined and mat foundations
1
'
3
8 ( )
c w c
V f bd
φ φ λ ρ
=
Example: Foundation Shear Check
• ACI 318-19
( )
1
'
3
2
1
3
8 ( )
10.27 in.
0.0028
(144 in.)(25.5 in.)
(0.75)(8)(1) 0.0028 4000 (144 .)(25.5 .)
196 kip 231 kip NG
c w c
w
c
c
V f bd
V psi in in
V
φ φ λ ρ
ρ
φ
φ
=
=
=
= < ∴
Example: Foundation Shear Check
• ACI 318-19
• Add 6 in. thickness
( )
1
'
3
2
1
3
8 ( )
10.27 in.
0.0023
(144 in.)(31.5 in.)
(0.75)(8)(1) 0.0023 4000 psi(144 in.)(31.5 in.)
226 kip > 191 kip OK
c w c
w
c
c
V f bd
V
V
φ φ λ ρ
ρ
φ
φ
=
=
=
∴
Why two-way shear provisions changed in
318-19
• First Equation developed in 1963 for slabs with
t < 5 in. and ρ > 1%
• Two issues similar to one-way shear
• Size effect
• Low ρ
vc
Least of (a), (b),
and (c):
(a)
(b)
(c)
'
4 c
f
λ
'
4
2 c
f
 
+ λ
 
β
 
'
2 s
c
o
d
f
b
 
α
+ λ
 
 
bo
Vc = vc(bod)
Two-way shear: size effect
• Table 22.6.5.2—vc for two-way members without
shear reinforcement
vc
Least of (a), (b),
and (c):
(a)
(b)
(c)
'
4 c
s f
λ λ
'
4
2 c
s f
 
+ λ
 
β
λ
 
'
2 s
s
c
o
d
f
b
 
α
λ
+ λ

 
2
1
1
10
s
d
λ
= ≤
+
Two-way shear: Effect of low ρ
• Only vert. load, cracking ~2 𝒇𝒇𝒄𝒄
′
; punching 4 𝒇𝒇𝒄𝒄
′
• Aggregate interlock contributes to shear strength
• Low ρ  local bar yielding, crack width increase,
allows sliding along shear crack
• Punching loads < 4 𝒇𝒇𝒄𝒄
′
Source: Performance and design of
punching –shear reinforcing system, Ruiz et
al, fib 2010
New two-way slab reinforcement limits
• Need As,min ≥ 0.0018Ag
• If on the critical section
• Then
,min
5 uv slab o
s
s y
v b b
A
f
≥
φα
'
2
uv s c
v f
> φ λ λ
h
1.5h
Slab edge
bslab
h
1.5h
bslab
1.5h
Slab edge
Table 8.4.2.2.3
h
h
1.5 h
1.5 h
1.5 h
bslab bslab
Definition of bslab
Slab Edge
Changes to the Concrete
Design Standard
ACI 318-19
Development Length
Development Length
• Straight Deformed Bars and Deformed Wires in
Tension
• Simple modification to 318-14
• Accounts for Grade 80 and 100
• Standard Hooks and Headed Deformed Bars
• Substantial changes from 318-14
Straight Development Length of
Deformed Bars in Tension
ftest = reinforcement stress at the time of failure
fcalc = calculated stress: ACI 318-14
Unconfined
Straight Development Length of
Deformed Bars in Tension
• Modification in
simplified
provisions of Table
25.4.2.3
• Ψg : new
modification factor
based on grade of
reinforcement:
• Grade 80, 1.15
• Grade 100, 1.30
Straight Development Length of
Deformed Bars in Tension
• Modification in general development length
equation 25.4.2.4(a)
• Provision 25.4.2.2
Ktr ≥ 0.5db for fy ≥ 80,000 psi , if longitudinal bar
spacing < 6 in.
ℓ𝑑𝑑 =
3
40
𝑓𝑓𝑦𝑦
𝜆𝜆 𝑓𝑓𝑐𝑐
′
𝜓𝜓𝑡𝑡𝜓𝜓𝑒𝑒𝜓𝜓𝑠𝑠𝝍𝝍𝒈𝒈
𝑐𝑐𝑏𝑏 + 𝐾𝐾𝑡𝑡𝑡𝑡
𝑑𝑑𝑏𝑏
𝑑𝑑𝑏𝑏
Modification factors
λ : Lightweight
ψt : Casting position
ψe : Epoxy
ψs : Size
ψg : Reinforcement grade
40 tr
tr
A
K
s n
=
⋅
Development Length
• Deformed Bars and Deformed Wires in Tension
• Standard Hooks in Tension
• Headed Deformed Bars in Tension
Development Length of Std.
Hooks in Tension
• Failure Modes
• Mostly, front and side failures
• Dominant front failure (pullout and blowout)
• Blowouts were more sudden in nature
Front Pullout Front Blowout Side splitting Tail kickout
Side blowout
Development Length of Standard
Hooks in Tension
fsu = stress at anchorage failure for the hooked bar
fs,ACI = stress predicted by the ACI development length equation
Confined Test Results
Unconfined Test Results
Development Length of Standard
Hooks in Tension
- 25.4.3.1—Development length of standard hooks in
tension is the greater of (a) through (c):
(a)
(b) 8db
(c) 6 in
- Modification factors
𝝍𝝍𝒓𝒓 : Confining reinforcement (redefined)
𝝍𝝍𝒐𝒐 : Location (new)
𝝍𝝍𝒄𝒄 : Concrete strength (new)
𝑓𝑓𝑦𝑦𝜓𝜓𝑒𝑒𝝍𝝍𝒓𝒓𝝍𝝍𝒐𝒐𝝍𝝍𝒄𝒄
55𝜆𝜆 𝑓𝑓𝑐𝑐
′
𝑑𝑑𝑏𝑏
𝟏𝟏.𝟓𝟓
ACI 318- 14
ℓ𝑑𝑑𝑑 =
𝑓𝑓𝑦𝑦𝜓𝜓𝑒𝑒𝝍𝝍𝒄𝒄𝝍𝝍𝒓𝒓
50𝜆𝜆 𝑓𝑓𝑐𝑐
′
𝑑𝑑𝑏𝑏
Development Length of Standard Hooks
in Tension
Modification
factor
Condition Value of
factor
318-14
Confining
reinforcement,
ψr
For 90-degree hooks of No. 11 and smaller
bars
(1) enclosed along ℓdh within ties or stirrups
perpendicular to ℓdh at s ≤ 3db, or
(2) enclosed along the bar extension
beyond hook including the bend within ties
or stirrups perpendicular to ℓext at s ≤ 3db
0.8
Other 1.0
318-19
Confining
reinforcement,
ψr
For No.11 and smaller bars with
Ath ≥ 0.4Ahs or s ≥ 6db
1.0
Other 1.6
Table 25.4.3.2: Modification factors for development of hooked bars in
tension
Development Length of Standard
Hooks in Tension
• (1) Confining reinforcement
placed parallel to the bar
(Typical in beam-column joint)
• Two or more ties or stirrups
parallel to ℓdh enclosing the
hooks
• Evenly distributed with a
center-to-center spacing ≤
8db
• within 15db of the centerline
of the straight portion of the
hooked bars
Fig. R25.4.3.3a
Development Length of Standard
Hooks in Tension
• (2) Confining reinforcement
placed perpendicular to the
bar
• Two or more ties or stirrups
perpendicular to ℓdh enclosing
the hooks
• Evenly distributed with a
center-to-center spacing ≤ 8db
Fig. R25.4.3.3b
Development Length of Std. Hooks in
Tension
Modification
factor
Condition Value of
factor
318-14
Cover
ψc
For No. 11 bar and smaller hooks with side
cover (normal to plane of hook) ≥ 2-1/2 in.
and for 90-degree hook with cover on bar
extension beyond hook ≥ 2 in.
0.7
Other 1.0
318-19
Location, ψo
For No.11 and smaller diameter hooked bars
(1) Terminating inside column core w/ side
cover normal to plane of hook ≥ 2.5 in., or
(2) with side cover normal to plane of hook ≥
6db
1.0
Other 1.25
Table 25.4.3.2: Modification factors for development of hooked bars in
tension
Development Length of Std. Hooks in
Tension
Modification
factor
Condition Value of factor
Concrete
strength, ψc
For f’c < 6000 psi f’c/15,000 +0.6
For f’c ≥ 6000 psi 1.0
Changes to the Concrete
Design Standard
ACI 318-19
Deflection Equations
Concerns about deflection
calculations
• Service level deflections based on Branson’s
equation underpredicted deflections for ρ below ≈
0.8%
• Reports of excessive slab deflections (Kopczynski,
Stivaros)
• High-strength reinforcement may result in lower
reinforcement ratios
𝑰𝑰𝒆𝒆 =
𝑴𝑴𝒄𝒄𝒄𝒄
𝑴𝑴𝒂𝒂
𝟑𝟑
𝑰𝑰𝒈𝒈 + 𝟏𝟏 −
𝑴𝑴𝒄𝒄𝒄𝒄
𝑴𝑴𝒂𝒂
𝟑𝟑
𝑰𝑰𝒄𝒄𝒄𝒄
Ie should be the average of flexibilities
• Branson
• Bischoff
Branson combines stiffnesses. Bischoff combines flexibilities.
Comparison of Branson’s and
Bischoff’s Ie
𝐼𝐼𝑒𝑒 =
𝑀𝑀𝑐𝑐𝑐𝑐
𝑀𝑀𝑎𝑎
3
𝐼𝐼𝑔𝑔 + 1 −
𝑀𝑀𝑐𝑐𝑐𝑐
𝑀𝑀𝑎𝑎
3
𝐼𝐼𝑐𝑐𝑐𝑐 ≤ 𝐼𝐼𝑔𝑔
1
𝐼𝐼𝑒𝑒
=
𝑀𝑀𝑐𝑐𝑐𝑐
𝑀𝑀𝑎𝑎
2 1
𝐼𝐼𝑔𝑔
+ 1 −
𝑀𝑀𝑐𝑐𝑐𝑐
𝑀𝑀𝑎𝑎
2 1
𝐼𝐼𝑐𝑐𝑐𝑐
≤
1
𝐼𝐼𝑔𝑔
𝐼𝐼𝑒𝑒 =
𝑀𝑀𝑐𝑐𝑐𝑐
𝑀𝑀𝑎𝑎
3
𝐼𝐼𝑔𝑔 + 1 −
𝑀𝑀𝑐𝑐𝑐𝑐
𝑀𝑀𝑎𝑎
3
𝐼𝐼𝑐𝑐𝑐𝑐 ≤ 𝐼𝐼𝑔𝑔
𝐼𝐼𝑒𝑒 =
𝑀𝑀𝑐𝑐𝑐𝑐
𝑀𝑀𝑎𝑎
3
𝐼𝐼𝑔𝑔 + 1 −
𝑀𝑀𝑐𝑐𝑐𝑐
𝑀𝑀𝑎𝑎
3
𝐼𝐼𝑐𝑐𝑐𝑐 ≤ 𝐼𝐼𝑔𝑔
1
𝐼𝐼𝑒𝑒
=
𝑀𝑀𝑐𝑐𝑐𝑐
𝑀𝑀𝑎𝑎
2 1
𝐼𝐼𝑔𝑔
+ 1 −
𝑀𝑀𝑐𝑐𝑐𝑐
𝑀𝑀𝑎𝑎
2 1
𝐼𝐼𝑐𝑐𝑐𝑐
≤
1
𝐼𝐼𝑔𝑔
Lightly reinforced
Midspan deflection
Midspan
moment
Experimental
Branson’s Eq.
Bischoff’s Eq.
• Table 24.2.3.5 ~ Inverse of Bischoff Eqn.
• 2/3 factor added to account for:
• restraint that reduces effective cracking moment
• reduced concrete tensile strength during construction
• Prestressed concrete maintains use of Branson’s Eq.
and 1.0 Ma.
Effective Moment of Inertia
𝑀𝑀𝑎𝑎 > ⁄
2 3 𝑀𝑀𝑐𝑐𝑐𝑐, 𝐼𝐼𝑒𝑒 =
𝐼𝐼𝑐𝑐𝑐𝑐
1 −
⁄
2 3 𝑀𝑀𝑐𝑐𝑐𝑐
𝑀𝑀𝑎𝑎
2
1 −
𝐼𝐼𝑐𝑐𝑐𝑐
𝐼𝐼𝑔𝑔
𝑀𝑀𝑎𝑎 ≤ ⁄
2 3 𝑀𝑀𝑐𝑐𝑐𝑐, 𝐼𝐼𝑒𝑒 = 𝐼𝐼𝑔𝑔
𝑀𝑀𝑎𝑎 > ⁄
2 3 𝑀𝑀𝑐𝑐𝑐𝑐, 𝐼𝐼𝑒𝑒 =
𝐼𝐼𝑐𝑐𝑐𝑐
1 −
⁄
2 3 𝑀𝑀𝑐𝑐𝑐𝑐
𝑀𝑀𝑎𝑎
2
1 −
𝐼𝐼𝑐𝑐𝑐𝑐
𝐼𝐼𝑔𝑔
𝑀𝑀𝑎𝑎 ≤ ⁄
2 3 𝑀𝑀𝑐𝑐𝑐𝑐, 𝐼𝐼𝑒𝑒 = 𝐼𝐼𝑔𝑔
Changes to the Concrete
Design Standard
ACI 318-19
Special Structural
Walls
18.10.2.4—Longitudinal
reinforcement ratio at ends of walls
hw/ℓw ≥ 2.0
• Failures in Chile and New
Zealand
• 1 or 2 large cracks
• Minor secondary cracks
18.10.2.4—Longitudinal
reinforcement ratio at ends of walls
New edge reinforcement ratio
• Well distributed cracks
• Flexure yielding over longer
length
'
6 c
y
f
f
ρ =
18.10.2.4—Longitudinal
reinforcement ratio at ends of walls
18.10.6.4(f)—Special Boundary
Elements Longitudinal bars
supported by a seismic
hook or corner of a hoop
0.025 w
b c
≥ 
Changes to the Concrete
Design Standard
ACI 318-19
Strut-and-Tie Method
23.10 Curved-bar Nodes
Nodal zones are
generally too small to
allow development
Dapped-end T-beam
23.10 Curved-bar Nodes
Two issues that need to
be addressed:
1. Slipping of bar
2. Concrete crushing
Circumferential stress
Radial stress
T1
T2
23.10 Curved-bar Nodes
≥
ts y
b '
s c
A f
r
b f
2
C-T-T
T
T
C
C
but not less than half bend
diameter of Table 25.3
θ < 180 degree bend
23.10 Curved-bar Nodes
23.10.6 The curved bar must
have sufficient to develop
difference in force
ℓcb > ℓd(1 – tan θc)
In terms of rb
2 (1 tan )
2
d c b
b
d
r
− θ
> −
π

James Wight - ACI Building Code-01-54.pdf

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James Wight - ACI Building Code-01-54.pdf

  • 1. James K. Wight, Past ACI President, Former Chair of Comm. 318 F.E. Richart, Jr. Collegiate Professor of Civil & Env. Engineering University of Michigan ACI 318-19: What’s New for 2019
  • 2. ACI 318-19: What’s New for 2019 • New Shear Strength Equations; including size-effect factor • Higher Rebar Grades • Updated Development Lengths • New Effective Stiffness for Deflection Calculations • Seismic Design Details – Shear Walls • Some Updates to Strut & Tie Method
  • 3. Changes to the Concrete Design Standard ACI 318-19 Shear Modifications
  • 4. Shear equation changes for one- way and two-way shear • Size Effect • Low Flexural Reinforcement Ratio • Axial load (prestress) • Results gathered and vetted by ACI Comm. 445
  • 5. Why one-way shear equations changed in 318-19 5 Figure: Strength Ratio (Vtest/Vn) d = 10 in. – λs, size effect factor ,min v v A A ≤
  • 6. Why one-way shear equations changed in 318-19 6 0.0018 – min. slab ρw ,min v v A A ≤ 0.015 – ρw effect Figure: Strength Ratio (Vtest/Vn)
  • 7. Why one-way shear equations changed in 318-19 7 d = 10 in. – λs, size effect factor ,min v v A A > Figure: Strength Ratio (Vtest/Vn)
  • 8. One-way shear provision: Modified goals • Include nonprestressed and prestressed • Include size effect and axial loading • Include effect of (ρw) • Continue to use 2√f’ c • Reduce multiple empirical equations • Easy to use
  • 9. ACI 318-19 New one-way shear equations Table 22.5.5.1 - Vc for nonprestressed members Criteria Vc Av ≥ Av,min Either of: 2𝜆𝜆 𝑓𝑓𝑓𝑐𝑐 + 𝑁𝑁𝑢𝑢 6𝐴𝐴𝑔𝑔 𝑏𝑏𝑤𝑤𝑑𝑑 (a) 8𝜆𝜆 𝜌𝜌𝑤𝑤 ⁄ 1 3 𝑓𝑓𝑓𝑐𝑐 + 𝑁𝑁𝑢𝑢 6𝐴𝐴𝑔𝑔 𝑏𝑏𝑤𝑤𝑑𝑑 (b) Av < Av,min 8𝜆𝜆𝑠𝑠𝜆𝜆 𝜌𝜌𝑤𝑤 ⁄ 1 3 𝑓𝑓𝑓𝑐𝑐 + 𝑁𝑁𝑢𝑢 6𝐴𝐴𝑔𝑔 𝑏𝑏𝑤𝑤𝑑𝑑 (c) Notes: 1. Axial load, Nu, is positive for compression and negative for tension 2. Vc shall not be taken less than zero.
  • 11. Size Effect: Value for λs? 0 0.2 0.4 0.6 0.8 1 1.2 0 12 24 36 48 60 72 84 96 108 120 λ s Depth in inches 2 1.0 1 10 s d λ = ≤ +
  • 12. Beam discussion • Where Av,min installed and Nu ≈ 0, Vc≈ (2√f’ c)bwd, – ACI 318-14 ~ ACI 318-19 • Provisions encourage use of Av,min
  • 13. 9.6.3.1 - Minimum shear reinforcement • ACI 318-14 • Av,min required if Vu > 0.5 φVc • ACI 318-19 • Av,min required if Vu > φλ√f’ c bwd
  • 14. Example: Foundation Shear Check • ℓ = 12 ft • h = 30 in. • d~25.5 in. • f’ c = 4000 psi • 13-No. 8 bars • b = 12 ft • Av = 0 in.2 • As = 10.27 in.2 • Analysis Vu= 231 kip 3 ft – 0 in.
  • 15. Example: Foundation Shear Check • ACI 318-14 ' 2 (0.75)(2)(1) 4000 (144 .)(25.5 .) 348 kip 231 kip OK c c c c V f bd V psi in in V φ φ λ φ φ = = = > ∴
  • 16. Example: Foundation Shear Check • ACI 318-19 • Av ≤ Av,min • Per ACI 318-19 (13.2.6.2), neglect size effect for: – One-way shallow foundations – Two-way isolated footings – Two-way combined and mat foundations 1 ' 3 8 ( ) c w c V f bd φ φ λ ρ =
  • 17. Example: Foundation Shear Check • ACI 318-19 ( ) 1 ' 3 2 1 3 8 ( ) 10.27 in. 0.0028 (144 in.)(25.5 in.) (0.75)(8)(1) 0.0028 4000 (144 .)(25.5 .) 196 kip 231 kip NG c w c w c c V f bd V psi in in V φ φ λ ρ ρ φ φ = = = = < ∴
  • 18. Example: Foundation Shear Check • ACI 318-19 • Add 6 in. thickness ( ) 1 ' 3 2 1 3 8 ( ) 10.27 in. 0.0023 (144 in.)(31.5 in.) (0.75)(8)(1) 0.0023 4000 psi(144 in.)(31.5 in.) 226 kip > 191 kip OK c w c w c c V f bd V V φ φ λ ρ ρ φ φ = = = ∴
  • 19. Why two-way shear provisions changed in 318-19 • First Equation developed in 1963 for slabs with t < 5 in. and ρ > 1% • Two issues similar to one-way shear • Size effect • Low ρ vc Least of (a), (b), and (c): (a) (b) (c) ' 4 c f λ ' 4 2 c f   + λ   β   ' 2 s c o d f b   α + λ     bo Vc = vc(bod)
  • 20. Two-way shear: size effect • Table 22.6.5.2—vc for two-way members without shear reinforcement vc Least of (a), (b), and (c): (a) (b) (c) ' 4 c s f λ λ ' 4 2 c s f   + λ   β λ   ' 2 s s c o d f b   α λ + λ    2 1 1 10 s d λ = ≤ +
  • 21. Two-way shear: Effect of low ρ • Only vert. load, cracking ~2 𝒇𝒇𝒄𝒄 ′ ; punching 4 𝒇𝒇𝒄𝒄 ′ • Aggregate interlock contributes to shear strength • Low ρ  local bar yielding, crack width increase, allows sliding along shear crack • Punching loads < 4 𝒇𝒇𝒄𝒄 ′ Source: Performance and design of punching –shear reinforcing system, Ruiz et al, fib 2010
  • 22. New two-way slab reinforcement limits • Need As,min ≥ 0.0018Ag • If on the critical section • Then ,min 5 uv slab o s s y v b b A f ≥ φα ' 2 uv s c v f > φ λ λ
  • 23. h 1.5h Slab edge bslab h 1.5h bslab 1.5h Slab edge Table 8.4.2.2.3 h h 1.5 h 1.5 h 1.5 h bslab bslab Definition of bslab Slab Edge
  • 24. Changes to the Concrete Design Standard ACI 318-19 Development Length
  • 25. Development Length • Straight Deformed Bars and Deformed Wires in Tension • Simple modification to 318-14 • Accounts for Grade 80 and 100 • Standard Hooks and Headed Deformed Bars • Substantial changes from 318-14
  • 26. Straight Development Length of Deformed Bars in Tension ftest = reinforcement stress at the time of failure fcalc = calculated stress: ACI 318-14 Unconfined
  • 27. Straight Development Length of Deformed Bars in Tension • Modification in simplified provisions of Table 25.4.2.3 • Ψg : new modification factor based on grade of reinforcement: • Grade 80, 1.15 • Grade 100, 1.30
  • 28. Straight Development Length of Deformed Bars in Tension • Modification in general development length equation 25.4.2.4(a) • Provision 25.4.2.2 Ktr ≥ 0.5db for fy ≥ 80,000 psi , if longitudinal bar spacing < 6 in. ℓ𝑑𝑑 = 3 40 𝑓𝑓𝑦𝑦 𝜆𝜆 𝑓𝑓𝑐𝑐 ′ 𝜓𝜓𝑡𝑡𝜓𝜓𝑒𝑒𝜓𝜓𝑠𝑠𝝍𝝍𝒈𝒈 𝑐𝑐𝑏𝑏 + 𝐾𝐾𝑡𝑡𝑡𝑡 𝑑𝑑𝑏𝑏 𝑑𝑑𝑏𝑏 Modification factors λ : Lightweight ψt : Casting position ψe : Epoxy ψs : Size ψg : Reinforcement grade 40 tr tr A K s n = ⋅
  • 29. Development Length • Deformed Bars and Deformed Wires in Tension • Standard Hooks in Tension • Headed Deformed Bars in Tension
  • 30. Development Length of Std. Hooks in Tension • Failure Modes • Mostly, front and side failures • Dominant front failure (pullout and blowout) • Blowouts were more sudden in nature Front Pullout Front Blowout Side splitting Tail kickout Side blowout
  • 31. Development Length of Standard Hooks in Tension fsu = stress at anchorage failure for the hooked bar fs,ACI = stress predicted by the ACI development length equation Confined Test Results Unconfined Test Results
  • 32. Development Length of Standard Hooks in Tension - 25.4.3.1—Development length of standard hooks in tension is the greater of (a) through (c): (a) (b) 8db (c) 6 in - Modification factors 𝝍𝝍𝒓𝒓 : Confining reinforcement (redefined) 𝝍𝝍𝒐𝒐 : Location (new) 𝝍𝝍𝒄𝒄 : Concrete strength (new) 𝑓𝑓𝑦𝑦𝜓𝜓𝑒𝑒𝝍𝝍𝒓𝒓𝝍𝝍𝒐𝒐𝝍𝝍𝒄𝒄 55𝜆𝜆 𝑓𝑓𝑐𝑐 ′ 𝑑𝑑𝑏𝑏 𝟏𝟏.𝟓𝟓 ACI 318- 14 ℓ𝑑𝑑𝑑 = 𝑓𝑓𝑦𝑦𝜓𝜓𝑒𝑒𝝍𝝍𝒄𝒄𝝍𝝍𝒓𝒓 50𝜆𝜆 𝑓𝑓𝑐𝑐 ′ 𝑑𝑑𝑏𝑏
  • 33. Development Length of Standard Hooks in Tension Modification factor Condition Value of factor 318-14 Confining reinforcement, ψr For 90-degree hooks of No. 11 and smaller bars (1) enclosed along ℓdh within ties or stirrups perpendicular to ℓdh at s ≤ 3db, or (2) enclosed along the bar extension beyond hook including the bend within ties or stirrups perpendicular to ℓext at s ≤ 3db 0.8 Other 1.0 318-19 Confining reinforcement, ψr For No.11 and smaller bars with Ath ≥ 0.4Ahs or s ≥ 6db 1.0 Other 1.6 Table 25.4.3.2: Modification factors for development of hooked bars in tension
  • 34. Development Length of Standard Hooks in Tension • (1) Confining reinforcement placed parallel to the bar (Typical in beam-column joint) • Two or more ties or stirrups parallel to ℓdh enclosing the hooks • Evenly distributed with a center-to-center spacing ≤ 8db • within 15db of the centerline of the straight portion of the hooked bars Fig. R25.4.3.3a
  • 35. Development Length of Standard Hooks in Tension • (2) Confining reinforcement placed perpendicular to the bar • Two or more ties or stirrups perpendicular to ℓdh enclosing the hooks • Evenly distributed with a center-to-center spacing ≤ 8db Fig. R25.4.3.3b
  • 36. Development Length of Std. Hooks in Tension Modification factor Condition Value of factor 318-14 Cover ψc For No. 11 bar and smaller hooks with side cover (normal to plane of hook) ≥ 2-1/2 in. and for 90-degree hook with cover on bar extension beyond hook ≥ 2 in. 0.7 Other 1.0 318-19 Location, ψo For No.11 and smaller diameter hooked bars (1) Terminating inside column core w/ side cover normal to plane of hook ≥ 2.5 in., or (2) with side cover normal to plane of hook ≥ 6db 1.0 Other 1.25 Table 25.4.3.2: Modification factors for development of hooked bars in tension
  • 37. Development Length of Std. Hooks in Tension Modification factor Condition Value of factor Concrete strength, ψc For f’c < 6000 psi f’c/15,000 +0.6 For f’c ≥ 6000 psi 1.0
  • 38. Changes to the Concrete Design Standard ACI 318-19 Deflection Equations
  • 39. Concerns about deflection calculations • Service level deflections based on Branson’s equation underpredicted deflections for ρ below ≈ 0.8% • Reports of excessive slab deflections (Kopczynski, Stivaros) • High-strength reinforcement may result in lower reinforcement ratios 𝑰𝑰𝒆𝒆 = 𝑴𝑴𝒄𝒄𝒄𝒄 𝑴𝑴𝒂𝒂 𝟑𝟑 𝑰𝑰𝒈𝒈 + 𝟏𝟏 − 𝑴𝑴𝒄𝒄𝒄𝒄 𝑴𝑴𝒂𝒂 𝟑𝟑 𝑰𝑰𝒄𝒄𝒄𝒄
  • 40. Ie should be the average of flexibilities
  • 41. • Branson • Bischoff Branson combines stiffnesses. Bischoff combines flexibilities. Comparison of Branson’s and Bischoff’s Ie 𝐼𝐼𝑒𝑒 = 𝑀𝑀𝑐𝑐𝑐𝑐 𝑀𝑀𝑎𝑎 3 𝐼𝐼𝑔𝑔 + 1 − 𝑀𝑀𝑐𝑐𝑐𝑐 𝑀𝑀𝑎𝑎 3 𝐼𝐼𝑐𝑐𝑐𝑐 ≤ 𝐼𝐼𝑔𝑔 1 𝐼𝐼𝑒𝑒 = 𝑀𝑀𝑐𝑐𝑐𝑐 𝑀𝑀𝑎𝑎 2 1 𝐼𝐼𝑔𝑔 + 1 − 𝑀𝑀𝑐𝑐𝑐𝑐 𝑀𝑀𝑎𝑎 2 1 𝐼𝐼𝑐𝑐𝑐𝑐 ≤ 1 𝐼𝐼𝑔𝑔 𝐼𝐼𝑒𝑒 = 𝑀𝑀𝑐𝑐𝑐𝑐 𝑀𝑀𝑎𝑎 3 𝐼𝐼𝑔𝑔 + 1 − 𝑀𝑀𝑐𝑐𝑐𝑐 𝑀𝑀𝑎𝑎 3 𝐼𝐼𝑐𝑐𝑐𝑐 ≤ 𝐼𝐼𝑔𝑔 𝐼𝐼𝑒𝑒 = 𝑀𝑀𝑐𝑐𝑐𝑐 𝑀𝑀𝑎𝑎 3 𝐼𝐼𝑔𝑔 + 1 − 𝑀𝑀𝑐𝑐𝑐𝑐 𝑀𝑀𝑎𝑎 3 𝐼𝐼𝑐𝑐𝑐𝑐 ≤ 𝐼𝐼𝑔𝑔 1 𝐼𝐼𝑒𝑒 = 𝑀𝑀𝑐𝑐𝑐𝑐 𝑀𝑀𝑎𝑎 2 1 𝐼𝐼𝑔𝑔 + 1 − 𝑀𝑀𝑐𝑐𝑐𝑐 𝑀𝑀𝑎𝑎 2 1 𝐼𝐼𝑐𝑐𝑐𝑐 ≤ 1 𝐼𝐼𝑔𝑔
  • 43. • Table 24.2.3.5 ~ Inverse of Bischoff Eqn. • 2/3 factor added to account for: • restraint that reduces effective cracking moment • reduced concrete tensile strength during construction • Prestressed concrete maintains use of Branson’s Eq. and 1.0 Ma. Effective Moment of Inertia 𝑀𝑀𝑎𝑎 > ⁄ 2 3 𝑀𝑀𝑐𝑐𝑐𝑐, 𝐼𝐼𝑒𝑒 = 𝐼𝐼𝑐𝑐𝑐𝑐 1 − ⁄ 2 3 𝑀𝑀𝑐𝑐𝑐𝑐 𝑀𝑀𝑎𝑎 2 1 − 𝐼𝐼𝑐𝑐𝑐𝑐 𝐼𝐼𝑔𝑔 𝑀𝑀𝑎𝑎 ≤ ⁄ 2 3 𝑀𝑀𝑐𝑐𝑐𝑐, 𝐼𝐼𝑒𝑒 = 𝐼𝐼𝑔𝑔 𝑀𝑀𝑎𝑎 > ⁄ 2 3 𝑀𝑀𝑐𝑐𝑐𝑐, 𝐼𝐼𝑒𝑒 = 𝐼𝐼𝑐𝑐𝑐𝑐 1 − ⁄ 2 3 𝑀𝑀𝑐𝑐𝑐𝑐 𝑀𝑀𝑎𝑎 2 1 − 𝐼𝐼𝑐𝑐𝑐𝑐 𝐼𝐼𝑔𝑔 𝑀𝑀𝑎𝑎 ≤ ⁄ 2 3 𝑀𝑀𝑐𝑐𝑐𝑐, 𝐼𝐼𝑒𝑒 = 𝐼𝐼𝑔𝑔
  • 44. Changes to the Concrete Design Standard ACI 318-19 Special Structural Walls
  • 45. 18.10.2.4—Longitudinal reinforcement ratio at ends of walls hw/ℓw ≥ 2.0 • Failures in Chile and New Zealand • 1 or 2 large cracks • Minor secondary cracks
  • 46. 18.10.2.4—Longitudinal reinforcement ratio at ends of walls New edge reinforcement ratio • Well distributed cracks • Flexure yielding over longer length ' 6 c y f f ρ =
  • 48. 18.10.6.4(f)—Special Boundary Elements Longitudinal bars supported by a seismic hook or corner of a hoop 0.025 w b c ≥ 
  • 49. Changes to the Concrete Design Standard ACI 318-19 Strut-and-Tie Method
  • 50. 23.10 Curved-bar Nodes Nodal zones are generally too small to allow development Dapped-end T-beam
  • 51. 23.10 Curved-bar Nodes Two issues that need to be addressed: 1. Slipping of bar 2. Concrete crushing Circumferential stress Radial stress T1 T2
  • 52. 23.10 Curved-bar Nodes ≥ ts y b ' s c A f r b f 2 C-T-T T T C C but not less than half bend diameter of Table 25.3 θ < 180 degree bend
  • 53. 23.10 Curved-bar Nodes 23.10.6 The curved bar must have sufficient to develop difference in force ℓcb > ℓd(1 – tan θc) In terms of rb 2 (1 tan ) 2 d c b b d r − θ > − π 