turn x+2y-4=0 into y=mx+b form also 6x-5y+20=0 x+3 = 0 and 2x-7=0 Solution to put your equation to y = mx + b, it means to solve for y in every equation. 1) x + 2y - 4 = 0 x+ 2y = 4 ( add 4 to both sides) 2y = -x + 4 ( move x over) y = (-x + 4) / 2 (divide both sides by 2) y = -x/2 + 4/2 y = -x/2 + 2 (break your right handside into 2 fractions and simplify) m= -1/2, b = 2 2)6x - 5y + 20 = 0 6x + 20 = 5y (move 5y over by adding 5y to both sides) 5y = 6x + 20 ( swtich right and left, nothing change) y = ( 6x + 20)/5 (divide both sides by 5) y = 6x/5 + 4 m = 6/5, b = 4 3) x+ 3 = 0 is already is in the form because there is no \"y\" x + 3 = 0y x = -3 when you graph this one, it\'s a verticle line, it\'s a special case for a function. 4) 2x - 7 = 0 x - 7/2 = 0 (divide by 2) same part c, already in the form. just y is missing, but it\'s ok .

1. turn x+2y-4=0 into y=mx+b form
also 6x-5y+20=0
x+3 = 0
and
2x-7=0
Solution
to put your equation to y = mx + b, it means to solve for y in every equation. 1) x + 2y - 4 = 0 x+
2y = 4 ( add 4 to both sides) 2y = -x + 4 ( move x over) y = (-x + 4) / 2 (divide both sides by 2) y
= -x/2 + 4/2 y = -x/2 + 2 (break your right handside into 2 fractions and simplify) m= -1/2, b = 2
2)6x - 5y + 20 = 0 6x + 20 = 5y (move 5y over by adding 5y to both sides) 5y = 6x + 20 ( swtich
right and left, nothing change) y = ( 6x + 20)/5 (divide both sides by 5) y = 6x/5 + 4 m = 6/5, b =
4 3) x+ 3 = 0 is already is in the form because there is no "y" x + 3 = 0y x = -3 when you graph
this one, it's a verticle line, it's a special case for a function. 4) 2x - 7 = 0 x - 7/2 = 0 (divide by
2) same part c, already in the form. just y is missing, but it's ok