ty ty +x +X Solution Let, mass of each rod , m = M length of each rod , L = 7.5 m Case(a): ( with all four rods ) Total mass, m1 = 4 M X-coordinate of center of mass , X1 =0 Y-coordinate of center of mass , Y1 =0 Case (b) : ( for the removed rod ) mass, m2 = M X-coordinate of center of mass , X2 =L / 2 = 7.5 /2 = 3.75 m Y-coordinate of center of mass , Y2 =0 Center of mass of the remaining part: X-coordinate of center of mass , Xcm = (m1 X1 - m2 X2 ) / ( m1- m2 )= ( 4 M * 0 - M * 4.0 ) / ( 4 M - M ) = -1.33 m Y-coordinate of center of mass , Ycm = (m1 Y1 - m2 Y2 ) / ( m1- m2 )= ( 4 M * 0 - M * 0 ) / ( 4 M - M ) = 0 m .