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DESIGN PROJECT
DESIGN OF HALF – SHAFT AND REAR
 WHEEL HUB ASSEMBLY OF A RACE CAR
Faculty co-ordinator:   Prof. Gokul Kumar

Design project guide: Prof. B . K Jha



                               Manvendra Singh Inaniya(08BME126)
                                                       9047288146
                                         Ravi Shekhar (08BME181)
                                                       9566810725
INTRODUCTION
Project Objective
• It was required to design a hub assembly and
  half–shafts for the Formula 1 car of mass about
  640 kg, maximum speed of 300 km/hr and
  average speed of 150km/hr.

• The assembly must give stability during rotation
  of the wheels. The weight and the dimension of
  the hub must be as small as possible because of
  the unsprung weight which further reduces the
  rotational mass. The half-shafts should not fail
  under stress.
Red Bull RB7 Formula 1 Car




RB7 F1 is the official car from World Champions Red Bull for the 2011 season of
Formula 1. We have considered this vehicle as a reference for this Design Project
as it is one of the fastest and most technologically matured vehicle in the racing
scenario.
Half - Shafts

• A half - shaft is an axle on a front wheel
  drive vehicle connecting the transmission to
  the driven wheels.

• The rear wheel driven Formula 1 vehicle
  being observed for the project uses half shafts
  in rear, as the differential is rigidly mounted
  and an independent rear suspension is used.
Design Consideration
Half shafts are designed as
 – a hollow metal tube to reduce weight.
 – CV joint at either end, allowing the driven wheels
   to maintain constant velocity .
 – Splines to transmit power between differential, CV
   joints, shaft and wheel hub.
 – the suspension travels during driving.
 – fatigues due to high speed rotation.
Wheel-Hub
• A hub assembly contains the wheel bearing,
  and the hub to mount the wheel to vehicle.
• It is located between the brake rotors and axle.
Design Consideration
• The bolt pattern is determined by the number
  of bolts on the wheel hub.
• Selection of material strong enough to take the
  weight of the car.
• Wheel bearings in the hub depending on ID
  and OD of spindle coming out of hub.
• Type of lug nuts or bolts.
LITERATURE
  REVIEW
DESIGN CRITERIA AND DURABILITY
    APPROVAL OF WHEEL HUB
SAE international,USA        11-16-1998       technical paper
      authors : Gerhard fischer , Vatroslov V. grubisic
 The author says that the design of wheel hub must be based on
 stress generated under customer usage through operational
 loads acting on wheels. Wheel hub are highly steered safety
 components which must not fail under the applied loading
 conditions.
                The main parameters for design of wheel hub
 assembly are loading conditions , manufacturing process and
 material behavior. The influence of these parameters are
 interactive so material fatigue behaviour will be changed
 depending upon the wheel hub design and loading conditions.
FRACTURE ANALYSIS OF WHEEL HUB
   FABRICATED FROM PRESSURE DIE
       ALUMINIUM ASSEMBLY
theoretical and applied fracture mechanics ,vol 9 feb 1988
                     authors : S . Dhar
 The author says that a catastrophic failure of wheel hub occurred
 during service. The nature of crack was a corner crack. An
 analytical investigation was carried out using tool of linear elastic
 fracture mechanics to establish the cause of failure. The non – linear
 behavior is due to the presence of material inhomogeneties and
 discontinuities.
                 An analytical estimation was carried out in order to
 calculate the minimum no. of cycles carried by wheel hub in service.
 The initiation of crack growth is complex because the heterogeneity
 and morphology of fracture surface. Fractographic and
 metallographic studies are carried out to assist the understanding of
 corner cracking problem.
Finite element modeling of dynamic impact and
 cornering fatigue of cast aluminum and forged
            magnesium road wheels.
           Proquest dissertation and thesis              2006
                authors : Shang, Shixian (Robert)
The author says that numerical investigation of wheel dynamics impact and
 cornering fatigue performance is essential to shorten design time , enhance
 mechanism performance and lower development costs. The desertion
 focused on two objectives:
   i) Finite element models of a dynamic impact test on wheel and tire
 assembly were developed which considered the material in homogeneity
 of wheels. Comparison of numerical predictions with experimental
 measurements of wheel impact indicated 20% reduction of initial striker
 kinetic energy provide an effective method for simplifying modeling.
ii) numerical prediction of wheel cornering fatigue testing was considered.
It proceeded in two methods, first was static stress analysis with bending
 direction applied to the hub. Second was dynamic stress analysis with
 application of a rotating bending moment applied to hub.
PRELIMINARY
PRODUCT DESIGN
Prototype CAD Model
     Half - Shaft




         Isometric View
Parameters for Half-shaft
•   L    –     Length of shaft
•   Do   –     Outer diameter of shaft
•   Di   –     Internal diameter of shaft
•   T    –     Maximum Torque applied by
               differential on shaft
•   σ    –     Maximum Normal Stress on shaft
•   τ    –     Maximum Sheer Stress on shaft
•   J    –     Polar Moment of Inertia of shaft
•   G    –     Modulus of Rigidity
Wheel Hub
Parameters of Wheel Hub
• n     -   Number of Bolts
• b     -   Bolt Circle Diameter or
            Pitch Circle Diameter
• d     -   Flange diameter is measured
            between opposite holes
• S     -   Spoke hole diameter
• W     -   Width centre to flange
• P     -   Load capacity is the amount of
            weight a wheel will carry
THEORETICAL
  DESIGN
Half - Shaft
GIVEN :
•   Maximum Torque of engine at 14000 rpm =              280 N-m
•   Gear ratio for 1st gear                              =       1.833
•   Final Drive ratio                                    =       2.15

Material selection:
•   The material chosen for the design of Half – shaft is ion nitrided titanium
    alloy.
•   The titanium and titanium alloys have unique corrosion, nonmagnetic         and
    strength – to-weight ratio properties.
•    Mechanical properties of nitride titanium alloys are as follows:
    Yield stress                                 =      1.24105631 × 109 Pascal
    Maximum Sheer Stress                         =      0.62052815 × 109 Pascal
Calculation of Torque at half-shafts:
Shock torque = factor of safety x first gear ratio x final drive x maximum engine torque
                         = 2.5 x 1.833 x 2.15 x 280
                         = 2758.665 N-m.

   Internal to external diameter ratio, k = 5

As T = 6246.765 N-m , τ = 0.62052815 × 109 Pascal , k = 5

The Axial Force acting upon the half-shafts has been countered by adding plunge to the
C.V. joints at the end of the half-shafts

The Gyroscopic couple acting due to rotational masses likes tyres, camshafts and
crankshafts is negligible as the rims, camshafts and crankshafts are made of light weight
titanium alloys which contribute insignificantly to gyroscopic couple.

No bending moment is observed as no additional weight, except self-weight of half-
shafts, is loaded on the half-shafts. Thus our calculations would be based upon the
strength required from shaft under torsional loading only.
T     = (π/16) x τ x (do)3 x [ 1 – (di / do)4]

                    We have, k = di / do = 5

         So, 2758.665 = (3.14/16) x 0.62x 109 x (do)3 [ 1 – (1/5)4]

                  do3    = 22882.115

                 do = 28.39 mm
             Or, do = 29 mm.
       Therefore, di = 29/5
                   di = 5.66 mm.

From the design calculation we find that the required external and internal
diameter of the half – shaft as per the specified engine parameters and given
conditions is 29 mm and 5.6 mm.
Wheel-Hub Assembly
Tires and rims selection:

The tires selected were of 13” diameter. The diameter was selected as
such that floor of the formula car does not touch the ground. At the same
time a low ride height would give an aerodynamic as well as low Center-
of-gravity advantage.

Number of bolts is taken 4 as it is a standard for 13” wheels.

Pitch Circle Diameter(P.C.D.) is fixed at 100 mm as it is a standard for
13” wheels.

Spoke Hole Diameter(S) is taken as M12 as it is a standard for 13”
wheels.

Material : Ti6Al4V - titanium alloy is the most widely used .
Brake Force Calculation
• Brake force is required to estimate the load on the
  wheel hub.

• As almost all the design parameters of a wheel
  hub are fixed by the size of wheel, the thickness
  of the wheel hub is the defining parameter.

• The thickness of wheel hub is determined by
  maximum force acting on a wheel.
Brake Calculation             :-


Velocity of Vehicle                           =         vo
Frictional force will be acting on it         =         F
Stopping distance                             =         d

Friction force of the road must do enough work on the car to reduce its kinetic
energy to zero .

To reduce the kinetic energy to zero
Workfriction = µmgd = 0.5mv02

             d= vo2/2µg

Velocity of our vehicle                       =         150 km/hr
Friction of road                              =         0.90
       d                                      =         98.31 m
Acceleration of the vehicle:-

vo2      = u2 + 2ad

Where a is the acceleration of the vehicle

a       = vo2/2d
a       = 8.8m/s
Total force acting on the vehicle
Ftotal = mv* a
Where mv is the mass of the vehicle = 640kg
Ftotal = 640 * 8.8 = 5632N

Force on each wheel:-
F1     = Ftotal/4 = 3953.43/4 =1408 N
F1     = 1408 N
Torque on the tire:-

Tr        =         F1 * rtire
Rim is taken to be 13”
rtire     =         20.43 * 0.0254/2       =        0.2595 m
Tr        =         1408 * 0.2595          =        365.35 N-m

Torque on disc:-

Tdisc       =       Ffriction*reffective

disc is assumed to be 200mm , therefore reffective should be 9cm
we know that Tdisc = Ttire

Ffriction   =       25647.012 / 9
Ffriction   =       2849.67N

Force on the clamp:-

Fclamp      =       Ffriction/µ            = 2849.67/0.5 = 5699.34 N
SOFTWARE
ANALYSIS
Wheel Hub Assembly
• In design stage, we estimated all the forces acting on hub and disc

• The wheel hub was modeled in CAD with given parameters

• The forces were applied on model using Finite Element Analysis in
..COSMOS

• The thickness of hub was varied in increments of 2 mm till a Factor
..of Safety value of 2 was attained

• Thus the final design of wheel hub is complete
Finite Element Analysis
No external force              External force applied




        Factor of Safety = 2
Safe Design
DETAILED PRODUCT
     DESIGN
Half - Shaft
Material = ion nitride titanium alloy
                Yield stress          = 1.241 x 109 Pascal
                Max. Shear stress     = 0.62 x 109 Pascal
 Engine characteristics
                N = 1400 rpm
                T = 280 N-m.
       First gear ratio            = 2.833
       Final drive ratio           = 2.15
       Shock torque                = 2758.665 N-m.
                 K, d0/di          =5
             External dia.         = 29 mm.
            Internal dia.          = 5.6 mm
Wheel hub
Tyre dia.                 = 13”
No. of bolts              =4
Pitch circle dia.         = 100mm.
Spoke hole dia .          = M12
Material                  = Ti6Al4V – titanium alloy
Stopping distance          = 98.31 m.
Velocity of vehicle         = 150 Km/hr.
Acceleration of vehicle    = 8.8 m/s2.
Force on each wheel        = 1408 N.
Torque on tyre (R-13)       = 388.75 N-m.
Diameter of disc            = 200 mm.
Effective radius             = 90 mm.
Clamping force              = 8638.86 N.
Width of flange           = 10 mm.
conclusion
• Wheel Hub has been designed for a formula 1 car of mass about 640 kg,
  maximum speed of 300 km/hr and average speed of 150 km/hr.

•   The designed assembly gives stability during rotation of the wheels.

• The weight and dimension of the hub is such that it reduces the rotational
  mass.

• The design project enabled us to understand the various forces that act on a
  half – shaft and wheel hub, while the Formula 1 race car is in running
  condition.

•    The calculated parameters help us to design half - shaft and wheel hub
    such.

•    The design project helped to better under the uses of software in real
    scenario.
GANTT CHART(Design Project)

                  "DESIGN OF HALF - SHAFT OF A PROTOTYPE RACE CAR"
Sl                                                Time in Weeks
No.        CATEGORY            1     2  3     4   5     6    7  8 9                   10   11   12
    Topic and guide selection
 A for project

B Literature review
  Develop preliminary
C product design

D Theoretical Design

E CAD modelling

F Software analysis

G Optimization of design
  Develop detailed product
H design
  Final Presentation
I Compilation
           ***Please note that the weeks mentioned above doesnot contain the CAT weeks.
THANK YOU

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Design of half shaft and wheel hub assembly for racing car

  • 2. DESIGN OF HALF – SHAFT AND REAR WHEEL HUB ASSEMBLY OF A RACE CAR Faculty co-ordinator: Prof. Gokul Kumar Design project guide: Prof. B . K Jha Manvendra Singh Inaniya(08BME126) 9047288146 Ravi Shekhar (08BME181) 9566810725
  • 4. Project Objective • It was required to design a hub assembly and half–shafts for the Formula 1 car of mass about 640 kg, maximum speed of 300 km/hr and average speed of 150km/hr. • The assembly must give stability during rotation of the wheels. The weight and the dimension of the hub must be as small as possible because of the unsprung weight which further reduces the rotational mass. The half-shafts should not fail under stress.
  • 5. Red Bull RB7 Formula 1 Car RB7 F1 is the official car from World Champions Red Bull for the 2011 season of Formula 1. We have considered this vehicle as a reference for this Design Project as it is one of the fastest and most technologically matured vehicle in the racing scenario.
  • 6. Half - Shafts • A half - shaft is an axle on a front wheel drive vehicle connecting the transmission to the driven wheels. • The rear wheel driven Formula 1 vehicle being observed for the project uses half shafts in rear, as the differential is rigidly mounted and an independent rear suspension is used.
  • 7. Design Consideration Half shafts are designed as – a hollow metal tube to reduce weight. – CV joint at either end, allowing the driven wheels to maintain constant velocity . – Splines to transmit power between differential, CV joints, shaft and wheel hub. – the suspension travels during driving. – fatigues due to high speed rotation.
  • 8. Wheel-Hub • A hub assembly contains the wheel bearing, and the hub to mount the wheel to vehicle. • It is located between the brake rotors and axle.
  • 9. Design Consideration • The bolt pattern is determined by the number of bolts on the wheel hub. • Selection of material strong enough to take the weight of the car. • Wheel bearings in the hub depending on ID and OD of spindle coming out of hub. • Type of lug nuts or bolts.
  • 11. DESIGN CRITERIA AND DURABILITY APPROVAL OF WHEEL HUB SAE international,USA 11-16-1998 technical paper authors : Gerhard fischer , Vatroslov V. grubisic The author says that the design of wheel hub must be based on stress generated under customer usage through operational loads acting on wheels. Wheel hub are highly steered safety components which must not fail under the applied loading conditions. The main parameters for design of wheel hub assembly are loading conditions , manufacturing process and material behavior. The influence of these parameters are interactive so material fatigue behaviour will be changed depending upon the wheel hub design and loading conditions.
  • 12. FRACTURE ANALYSIS OF WHEEL HUB FABRICATED FROM PRESSURE DIE ALUMINIUM ASSEMBLY theoretical and applied fracture mechanics ,vol 9 feb 1988 authors : S . Dhar The author says that a catastrophic failure of wheel hub occurred during service. The nature of crack was a corner crack. An analytical investigation was carried out using tool of linear elastic fracture mechanics to establish the cause of failure. The non – linear behavior is due to the presence of material inhomogeneties and discontinuities. An analytical estimation was carried out in order to calculate the minimum no. of cycles carried by wheel hub in service. The initiation of crack growth is complex because the heterogeneity and morphology of fracture surface. Fractographic and metallographic studies are carried out to assist the understanding of corner cracking problem.
  • 13. Finite element modeling of dynamic impact and cornering fatigue of cast aluminum and forged magnesium road wheels. Proquest dissertation and thesis 2006 authors : Shang, Shixian (Robert) The author says that numerical investigation of wheel dynamics impact and cornering fatigue performance is essential to shorten design time , enhance mechanism performance and lower development costs. The desertion focused on two objectives: i) Finite element models of a dynamic impact test on wheel and tire assembly were developed which considered the material in homogeneity of wheels. Comparison of numerical predictions with experimental measurements of wheel impact indicated 20% reduction of initial striker kinetic energy provide an effective method for simplifying modeling. ii) numerical prediction of wheel cornering fatigue testing was considered. It proceeded in two methods, first was static stress analysis with bending direction applied to the hub. Second was dynamic stress analysis with application of a rotating bending moment applied to hub.
  • 15. Prototype CAD Model Half - Shaft Isometric View
  • 16. Parameters for Half-shaft • L – Length of shaft • Do – Outer diameter of shaft • Di – Internal diameter of shaft • T – Maximum Torque applied by differential on shaft • σ – Maximum Normal Stress on shaft • τ – Maximum Sheer Stress on shaft • J – Polar Moment of Inertia of shaft • G – Modulus of Rigidity
  • 18. Parameters of Wheel Hub • n - Number of Bolts • b - Bolt Circle Diameter or Pitch Circle Diameter • d - Flange diameter is measured between opposite holes • S - Spoke hole diameter • W - Width centre to flange • P - Load capacity is the amount of weight a wheel will carry
  • 20. Half - Shaft GIVEN : • Maximum Torque of engine at 14000 rpm = 280 N-m • Gear ratio for 1st gear = 1.833 • Final Drive ratio = 2.15 Material selection: • The material chosen for the design of Half – shaft is ion nitrided titanium alloy. • The titanium and titanium alloys have unique corrosion, nonmagnetic and strength – to-weight ratio properties. • Mechanical properties of nitride titanium alloys are as follows: Yield stress = 1.24105631 × 109 Pascal Maximum Sheer Stress = 0.62052815 × 109 Pascal
  • 21. Calculation of Torque at half-shafts: Shock torque = factor of safety x first gear ratio x final drive x maximum engine torque = 2.5 x 1.833 x 2.15 x 280 = 2758.665 N-m. Internal to external diameter ratio, k = 5 As T = 6246.765 N-m , τ = 0.62052815 × 109 Pascal , k = 5 The Axial Force acting upon the half-shafts has been countered by adding plunge to the C.V. joints at the end of the half-shafts The Gyroscopic couple acting due to rotational masses likes tyres, camshafts and crankshafts is negligible as the rims, camshafts and crankshafts are made of light weight titanium alloys which contribute insignificantly to gyroscopic couple. No bending moment is observed as no additional weight, except self-weight of half- shafts, is loaded on the half-shafts. Thus our calculations would be based upon the strength required from shaft under torsional loading only.
  • 22. T = (π/16) x τ x (do)3 x [ 1 – (di / do)4] We have, k = di / do = 5 So, 2758.665 = (3.14/16) x 0.62x 109 x (do)3 [ 1 – (1/5)4] do3 = 22882.115 do = 28.39 mm Or, do = 29 mm. Therefore, di = 29/5 di = 5.66 mm. From the design calculation we find that the required external and internal diameter of the half – shaft as per the specified engine parameters and given conditions is 29 mm and 5.6 mm.
  • 23. Wheel-Hub Assembly Tires and rims selection: The tires selected were of 13” diameter. The diameter was selected as such that floor of the formula car does not touch the ground. At the same time a low ride height would give an aerodynamic as well as low Center- of-gravity advantage. Number of bolts is taken 4 as it is a standard for 13” wheels. Pitch Circle Diameter(P.C.D.) is fixed at 100 mm as it is a standard for 13” wheels. Spoke Hole Diameter(S) is taken as M12 as it is a standard for 13” wheels. Material : Ti6Al4V - titanium alloy is the most widely used .
  • 24. Brake Force Calculation • Brake force is required to estimate the load on the wheel hub. • As almost all the design parameters of a wheel hub are fixed by the size of wheel, the thickness of the wheel hub is the defining parameter. • The thickness of wheel hub is determined by maximum force acting on a wheel.
  • 25. Brake Calculation :- Velocity of Vehicle = vo Frictional force will be acting on it = F Stopping distance = d Friction force of the road must do enough work on the car to reduce its kinetic energy to zero . To reduce the kinetic energy to zero Workfriction = µmgd = 0.5mv02 d= vo2/2µg Velocity of our vehicle = 150 km/hr Friction of road = 0.90 d = 98.31 m
  • 26. Acceleration of the vehicle:- vo2 = u2 + 2ad Where a is the acceleration of the vehicle a = vo2/2d a = 8.8m/s Total force acting on the vehicle Ftotal = mv* a Where mv is the mass of the vehicle = 640kg Ftotal = 640 * 8.8 = 5632N Force on each wheel:- F1 = Ftotal/4 = 3953.43/4 =1408 N F1 = 1408 N
  • 27. Torque on the tire:- Tr = F1 * rtire Rim is taken to be 13” rtire = 20.43 * 0.0254/2 = 0.2595 m Tr = 1408 * 0.2595 = 365.35 N-m Torque on disc:- Tdisc = Ffriction*reffective disc is assumed to be 200mm , therefore reffective should be 9cm we know that Tdisc = Ttire Ffriction = 25647.012 / 9 Ffriction = 2849.67N Force on the clamp:- Fclamp = Ffriction/µ = 2849.67/0.5 = 5699.34 N
  • 29. Wheel Hub Assembly • In design stage, we estimated all the forces acting on hub and disc • The wheel hub was modeled in CAD with given parameters • The forces were applied on model using Finite Element Analysis in ..COSMOS • The thickness of hub was varied in increments of 2 mm till a Factor ..of Safety value of 2 was attained • Thus the final design of wheel hub is complete
  • 30. Finite Element Analysis No external force External force applied Factor of Safety = 2
  • 33. Half - Shaft Material = ion nitride titanium alloy Yield stress = 1.241 x 109 Pascal Max. Shear stress = 0.62 x 109 Pascal Engine characteristics N = 1400 rpm T = 280 N-m. First gear ratio = 2.833 Final drive ratio = 2.15 Shock torque = 2758.665 N-m. K, d0/di =5 External dia. = 29 mm. Internal dia. = 5.6 mm
  • 34. Wheel hub Tyre dia. = 13” No. of bolts =4 Pitch circle dia. = 100mm. Spoke hole dia . = M12 Material = Ti6Al4V – titanium alloy Stopping distance = 98.31 m. Velocity of vehicle = 150 Km/hr. Acceleration of vehicle = 8.8 m/s2. Force on each wheel = 1408 N. Torque on tyre (R-13) = 388.75 N-m. Diameter of disc = 200 mm. Effective radius = 90 mm. Clamping force = 8638.86 N. Width of flange = 10 mm.
  • 35. conclusion • Wheel Hub has been designed for a formula 1 car of mass about 640 kg, maximum speed of 300 km/hr and average speed of 150 km/hr. • The designed assembly gives stability during rotation of the wheels. • The weight and dimension of the hub is such that it reduces the rotational mass. • The design project enabled us to understand the various forces that act on a half – shaft and wheel hub, while the Formula 1 race car is in running condition. • The calculated parameters help us to design half - shaft and wheel hub such. • The design project helped to better under the uses of software in real scenario.
  • 36. GANTT CHART(Design Project) "DESIGN OF HALF - SHAFT OF A PROTOTYPE RACE CAR" Sl Time in Weeks No. CATEGORY 1 2 3 4 5 6 7 8 9 10 11 12 Topic and guide selection A for project B Literature review Develop preliminary C product design D Theoretical Design E CAD modelling F Software analysis G Optimization of design Develop detailed product H design Final Presentation I Compilation ***Please note that the weeks mentioned above doesnot contain the CAT weeks.