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Hi, I have updated the code. Highlighted the code changes below. we can end the loop by break statement. #include using namespace std; int main() { int x = 10; int y =20; int z = x + y; while(z == z){ if(y ==z){ do{ for(int i=0; i<2; i++){ cout<<\"This is the answer \"< Solution Hi, I have updated the code. Highlighted the code changes below. we can end the loop by break statement. #include using namespace std; int main() { int x = 10; int y =20; int z = x + y; while(z == z){ if(y ==z){ do{ for(int i=0; i<2; i++){ cout<<\"This is the answer \"<.
System is a set of interacting or interdependent entities forming an.pdf
System is a set of interacting or interdependent entities forming an.pdf
proloyankur01
Given F1 = -5i+3j-4k F2 = 5i-5j-2k The position vectors of the forces F1 and F2 are r1 and r2 respectively From figure we can write r1 = 4 i -0.15 j + 0.25 k r2 = 4 i +0.15 j + 0.25 k Now the equivalent force at O is FR = F1 + F2 = -5i+3j-4k+ 5i-5j-2k FR = -2 j -6 k Therefore FRx, FRy,FRz = (0, -2, -6) Now the resultant moment about O is MR,O = r1XF1 + r2X F2 MR,O =(4 i -0.15 j + 0.25 k)X(-5i+3j-4k)+(4 i +0.15 j + 0.25 k)X( 5i-5j-2k) MR,O =12 k +16 j -0.75 k+0.6 i -1.25 j -0.75 i -20 k+8 j -0.75 k -0.3 i +1.25 j + 1.25 i MR,O = 0.8 i + 24 j -9.5 k so (MR,Ox,MR,Oy, MR,Oz) = (0.8, 24, -9.5) Solution Given F1 = -5i+3j-4k F2 = 5i-5j-2k The position vectors of the forces F1 and F2 are r1 and r2 respectively From figure we can write r1 = 4 i -0.15 j + 0.25 k r2 = 4 i +0.15 j + 0.25 k Now the equivalent force at O is FR = F1 + F2 = -5i+3j-4k+ 5i-5j-2k FR = -2 j -6 k Therefore FRx, FRy,FRz = (0, -2, -6) Now the resultant moment about O is MR,O = r1XF1 + r2X F2 MR,O =(4 i -0.15 j + 0.25 k)X(-5i+3j-4k)+(4 i +0.15 j + 0.25 k)X( 5i-5j-2k) MR,O =12 k +16 j -0.75 k+0.6 i -1.25 j -0.75 i -20 k+8 j -0.75 k -0.3 i +1.25 j + 1.25 i MR,O = 0.8 i + 24 j -9.5 k so (MR,Ox,MR,Oy, MR,Oz) = (0.8, 24, -9.5).
Solution Given thatBy definition of logarithm, we getSolution.pdf
Solution Given thatBy definition of logarithm, we getSolution.pdf
proloyankur01
EAR = (1 + .127/365)^365 - 1, or 13.2% Solution EAR = (1 + .127/365)^365 - 1, or 13.2%.
Percent error actual - experimental actual x 100.AMU, atomic.pdf
Percent error actual - experimental actual x 100.AMU, atomic.pdf
proloyankur01
Erythrocyte Protoporphyrin Erythrocyte Protoporphyrin ( hemoglobin precursor) begin to accumulate as hemoglobin as hematocrit declineduring the 3rd stage of iron deficiency occurs when their is lack of iron limits hemoglobin production. World wide,how many people are estimated to have iron deficiency anemia Ans; 2.0 to 2.5billion ( over 30% 0f world population according to WHO) Solution Erythrocyte Protoporphyrin Erythrocyte Protoporphyrin ( hemoglobin precursor) begin to accumulate as hemoglobin as hematocrit declineduring the 3rd stage of iron deficiency occurs when their is lack of iron limits hemoglobin production. World wide,how many people are estimated to have iron deficiency anemia Ans; 2.0 to 2.5billion ( over 30% 0f world population according to WHO).
Please follow the code and comments for description and outputs C.pdf
Please follow the code and comments for description and outputs C.pdf
proloyankur01
Dear, The answer is 25. Solution Dear, The answer is 25..
organization acted as the IdPThe fundamental concept introduced b.pdf
organization acted as the IdPThe fundamental concept introduced b.pdf
proloyankur01
Average concentration of atrazine in the inflow water = 8.0 mg/L Volume of reservoir = 3.0 x 105 m3 Total annual flow = 1.5 x 105 m3 Annual outflow due to evaporation =1.2 x 105 m3 Average concentration of atrazine in the outflow = 6.2 mg/L Total quantity of atrazine added into the reservoir = 8.0 x 1.5 x 105 x 1000 mg = 1200 kg As,the volume of the reservoir is steady, i.e. it is constant, Outflow = Inflow – Evaporation loss = (1.5 x 105 m3) - (1.2 x 105 m3) = 0.3 x 105 m3 Total quantity of atrazine leaving the system = 6.2 mg/L x 0.3 x 105 m3 x 1000L/m3 = 186 kg Total loss of atrazine by mass in the reservoir in the whole year = 1200 = 1014 kg Internal Sink rate = 1014 kg/(3 x105 m3 x 365) = 9.26 mg/m3-day Please provide feedback. Solution Average concentration of atrazine in the inflow water = 8.0 mg/L Volume of reservoir = 3.0 x 105 m3 Total annual flow = 1.5 x 105 m3 Annual outflow due to evaporation =1.2 x 105 m3 Average concentration of atrazine in the outflow = 6.2 mg/L Total quantity of atrazine added into the reservoir = 8.0 x 1.5 x 105 x 1000 mg = 1200 kg As,the volume of the reservoir is steady, i.e. it is constant, Outflow = Inflow – Evaporation loss = (1.5 x 105 m3) - (1.2 x 105 m3) = 0.3 x 105 m3 Total quantity of atrazine leaving the system = 6.2 mg/L x 0.3 x 105 m3 x 1000L/m3 = 186 kg Total loss of atrazine by mass in the reservoir in the whole year = 1200 = 1014 kg Internal Sink rate = 1014 kg/(3 x105 m3 x 365) = 9.26 mg/m3-day Please provide feedback..
Let X = JohnSolutionLet X = John.pdf
Let X = JohnSolutionLet X = John.pdf
proloyankur01
Answer: Muscle temparature. Proprioreceptor involves in the detection of changes in tension in muscles and tendons and fibrous capsules in the joints. But temperature is sensed by specific receptors. Solution Answer: Muscle temparature. Proprioreceptor involves in the detection of changes in tension in muscles and tendons and fibrous capsules in the joints. But temperature is sensed by specific receptors..
In the United States, policy makers, health professionals, and patie.pdf
In the United States, policy makers, health professionals, and patie.pdf
proloyankur01
Ac- + H2O ~~> OH + AcH Kb = [OH-][AcH]/[Ac-] Kb=10^-14/Ka = 5.556x10^-10 [OH-]______[AcH]________[Ac-] initial_____0_______0_________1M change___+x______+x_________-x final______x_______x__________0.052-x Kb = x2/(0.052-x) = 5.556x10-10 Solve for x: x=5-log(0.535) = [OH-] pOH = -log[OH] = 5.27 pH=14-pOH=8.73 Solution Ac- + H2O ~~> OH + AcH Kb = [OH-][AcH]/[Ac-] Kb=10^-14/Ka = 5.556x10^-10 [OH-]______[AcH]________[Ac-] initial_____0_______0_________1M change___+x______+x_________-x final______x_______x__________0.052-x Kb = x2/(0.052-x) = 5.556x10-10 Solve for x: x=5-log(0.535) = [OH-] pOH = -log[OH] = 5.27 pH=14-pOH=8.73.
holding period return = (2D1P1Po)Solutionholding period retur.pdf
holding period return = (2D1P1Po)Solutionholding period retur.pdf
proloyankur01
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Hi, I have updated the code. Highlighted the code changes below. we can end the loop by break statement. #include using namespace std; int main() { int x = 10; int y =20; int z = x + y; while(z == z){ if(y ==z){ do{ for(int i=0; i<2; i++){ cout<<\"This is the answer \"< Solution Hi, I have updated the code. Highlighted the code changes below. we can end the loop by break statement. #include using namespace std; int main() { int x = 10; int y =20; int z = x + y; while(z == z){ if(y ==z){ do{ for(int i=0; i<2; i++){ cout<<\"This is the answer \"<.
System is a set of interacting or interdependent entities forming an.pdf
System is a set of interacting or interdependent entities forming an.pdf
proloyankur01
Given F1 = -5i+3j-4k F2 = 5i-5j-2k The position vectors of the forces F1 and F2 are r1 and r2 respectively From figure we can write r1 = 4 i -0.15 j + 0.25 k r2 = 4 i +0.15 j + 0.25 k Now the equivalent force at O is FR = F1 + F2 = -5i+3j-4k+ 5i-5j-2k FR = -2 j -6 k Therefore FRx, FRy,FRz = (0, -2, -6) Now the resultant moment about O is MR,O = r1XF1 + r2X F2 MR,O =(4 i -0.15 j + 0.25 k)X(-5i+3j-4k)+(4 i +0.15 j + 0.25 k)X( 5i-5j-2k) MR,O =12 k +16 j -0.75 k+0.6 i -1.25 j -0.75 i -20 k+8 j -0.75 k -0.3 i +1.25 j + 1.25 i MR,O = 0.8 i + 24 j -9.5 k so (MR,Ox,MR,Oy, MR,Oz) = (0.8, 24, -9.5) Solution Given F1 = -5i+3j-4k F2 = 5i-5j-2k The position vectors of the forces F1 and F2 are r1 and r2 respectively From figure we can write r1 = 4 i -0.15 j + 0.25 k r2 = 4 i +0.15 j + 0.25 k Now the equivalent force at O is FR = F1 + F2 = -5i+3j-4k+ 5i-5j-2k FR = -2 j -6 k Therefore FRx, FRy,FRz = (0, -2, -6) Now the resultant moment about O is MR,O = r1XF1 + r2X F2 MR,O =(4 i -0.15 j + 0.25 k)X(-5i+3j-4k)+(4 i +0.15 j + 0.25 k)X( 5i-5j-2k) MR,O =12 k +16 j -0.75 k+0.6 i -1.25 j -0.75 i -20 k+8 j -0.75 k -0.3 i +1.25 j + 1.25 i MR,O = 0.8 i + 24 j -9.5 k so (MR,Ox,MR,Oy, MR,Oz) = (0.8, 24, -9.5).
Solution Given thatBy definition of logarithm, we getSolution.pdf
Solution Given thatBy definition of logarithm, we getSolution.pdf
proloyankur01
EAR = (1 + .127/365)^365 - 1, or 13.2% Solution EAR = (1 + .127/365)^365 - 1, or 13.2%.
Percent error actual - experimental actual x 100.AMU, atomic.pdf
Percent error actual - experimental actual x 100.AMU, atomic.pdf
proloyankur01
Erythrocyte Protoporphyrin Erythrocyte Protoporphyrin ( hemoglobin precursor) begin to accumulate as hemoglobin as hematocrit declineduring the 3rd stage of iron deficiency occurs when their is lack of iron limits hemoglobin production. World wide,how many people are estimated to have iron deficiency anemia Ans; 2.0 to 2.5billion ( over 30% 0f world population according to WHO) Solution Erythrocyte Protoporphyrin Erythrocyte Protoporphyrin ( hemoglobin precursor) begin to accumulate as hemoglobin as hematocrit declineduring the 3rd stage of iron deficiency occurs when their is lack of iron limits hemoglobin production. World wide,how many people are estimated to have iron deficiency anemia Ans; 2.0 to 2.5billion ( over 30% 0f world population according to WHO).
Please follow the code and comments for description and outputs C.pdf
Please follow the code and comments for description and outputs C.pdf
proloyankur01
Dear, The answer is 25. Solution Dear, The answer is 25..
organization acted as the IdPThe fundamental concept introduced b.pdf
organization acted as the IdPThe fundamental concept introduced b.pdf
proloyankur01
Average concentration of atrazine in the inflow water = 8.0 mg/L Volume of reservoir = 3.0 x 105 m3 Total annual flow = 1.5 x 105 m3 Annual outflow due to evaporation =1.2 x 105 m3 Average concentration of atrazine in the outflow = 6.2 mg/L Total quantity of atrazine added into the reservoir = 8.0 x 1.5 x 105 x 1000 mg = 1200 kg As,the volume of the reservoir is steady, i.e. it is constant, Outflow = Inflow – Evaporation loss = (1.5 x 105 m3) - (1.2 x 105 m3) = 0.3 x 105 m3 Total quantity of atrazine leaving the system = 6.2 mg/L x 0.3 x 105 m3 x 1000L/m3 = 186 kg Total loss of atrazine by mass in the reservoir in the whole year = 1200 = 1014 kg Internal Sink rate = 1014 kg/(3 x105 m3 x 365) = 9.26 mg/m3-day Please provide feedback. Solution Average concentration of atrazine in the inflow water = 8.0 mg/L Volume of reservoir = 3.0 x 105 m3 Total annual flow = 1.5 x 105 m3 Annual outflow due to evaporation =1.2 x 105 m3 Average concentration of atrazine in the outflow = 6.2 mg/L Total quantity of atrazine added into the reservoir = 8.0 x 1.5 x 105 x 1000 mg = 1200 kg As,the volume of the reservoir is steady, i.e. it is constant, Outflow = Inflow – Evaporation loss = (1.5 x 105 m3) - (1.2 x 105 m3) = 0.3 x 105 m3 Total quantity of atrazine leaving the system = 6.2 mg/L x 0.3 x 105 m3 x 1000L/m3 = 186 kg Total loss of atrazine by mass in the reservoir in the whole year = 1200 = 1014 kg Internal Sink rate = 1014 kg/(3 x105 m3 x 365) = 9.26 mg/m3-day Please provide feedback..
Let X = JohnSolutionLet X = John.pdf
Let X = JohnSolutionLet X = John.pdf
proloyankur01
Answer: Muscle temparature. Proprioreceptor involves in the detection of changes in tension in muscles and tendons and fibrous capsules in the joints. But temperature is sensed by specific receptors. Solution Answer: Muscle temparature. Proprioreceptor involves in the detection of changes in tension in muscles and tendons and fibrous capsules in the joints. But temperature is sensed by specific receptors..
In the United States, policy makers, health professionals, and patie.pdf
In the United States, policy makers, health professionals, and patie.pdf
proloyankur01
Ac- + H2O ~~> OH + AcH Kb = [OH-][AcH]/[Ac-] Kb=10^-14/Ka = 5.556x10^-10 [OH-]______[AcH]________[Ac-] initial_____0_______0_________1M change___+x______+x_________-x final______x_______x__________0.052-x Kb = x2/(0.052-x) = 5.556x10-10 Solve for x: x=5-log(0.535) = [OH-] pOH = -log[OH] = 5.27 pH=14-pOH=8.73 Solution Ac- + H2O ~~> OH + AcH Kb = [OH-][AcH]/[Ac-] Kb=10^-14/Ka = 5.556x10^-10 [OH-]______[AcH]________[Ac-] initial_____0_______0_________1M change___+x______+x_________-x final______x_______x__________0.052-x Kb = x2/(0.052-x) = 5.556x10-10 Solve for x: x=5-log(0.535) = [OH-] pOH = -log[OH] = 5.27 pH=14-pOH=8.73.
holding period return = (2D1P1Po)Solutionholding period retur.pdf
holding period return = (2D1P1Po)Solutionholding period retur.pdf
proloyankur01
100 DIM C(50) (50 is max number of servers) 110 INPUT S,NSTOP (S,NSTOP = number of servers, customers to be simulated) 120 FOR D=1 TO NSTOP 130 IA= (IA = interarrival time) 140 A=A+IA (A = arrival time) 150 J=0 160 J=J+1 (J = index of server being probed) 170 IF J=S+1 THEN K=K+1 (K = number of customers that are blocked) 180 IF J=S+1 THEN 270 190 IF AA THEN AB=AB+M- A (AB = cumulative time during which all servers busy) 270 NEXT D 280 PRINT K/NSTOP,AB/A (fraction of customers blocked, fraction of time all servers are simultaneously busy) Solution 100 DIM C(50) (50 is max number of servers) 110 INPUT S,NSTOP (S,NSTOP = number of servers, customers to be simulated) 120 FOR D=1 TO NSTOP 130 IA= (IA = interarrival time) 140 A=A+IA (A = arrival time) 150 J=0 160 J=J+1 (J = index of server being probed) 170 IF J=S+1 THEN K=K+1 (K = number of customers that are blocked) 180 IF J=S+1 THEN 270 190 IF AA THEN AB=AB+M- A (AB = cumulative time during which all servers busy) 270 NEXT D 280 PRINT K/NSTOP,AB/A (fraction of customers blocked, fraction of time all servers are simultaneously busy).
create file name as board.javawrite below codeimport java.aw.pdf
create file name as board.javawrite below codeimport java.aw.pdf
proloyankur01
1 Suppose, annualized growth in inflation rate is I 4.5 = 1.2*(1+I) ^3 (1+I)^3 = 4.5/1.2 = 3.75= 1.553^ (1/3) I = 55.3% In an economy, when GDP is growing consistently and unemployment rate is also falling. Though, growth rate in inflation rate is very high and it is approx. 55.3%. It means that demand is increasing and it is more than the supply. It is also causing overheating of the economy. Here, more money is chasing few goods. It leads to further increase in price. And it drives inflation on the higher side. Data given the problem confirms the economic scenario mentioned. It propels the inflation further and it is very high as a proof. 2 Inflation is growing with annualized rate of 55.3%. In this case, Federal Reserve should use contraction policy. As a part of it, Federal Reserve should deploy right money policy. It will discourage people to borrow and demand will come down. Thus, inflation will be controlled. 3. Federal Reserve can increase reserve requirements. Further, Federal Reserve can also sell government securities in open market. It will suck cash out of the system and contractionary policy will be implemented. Reduced government expending will also help. It will help curbing the inflation. 4 If recession happens and due to this reason, layoff takes place as well as demand decreases then contractionary economic policy will be ineffective. In those circumstances, Federal Reserve has to reverse the strategy. Technological change can also make a reduction in demand of products. In that industry, contractionary policy will be discouraging. Also, for those product categories where demand is inelastic in nature. Contractionary policy will not work. Note: Already answered similar question on Chegg Q&A board. Thus, above answer is the modified version as per the requirements mentioned in the question. Solution 1 Suppose, annualized growth in inflation rate is I 4.5 = 1.2*(1+I) ^3 (1+I)^3 = 4.5/1.2 = 3.75= 1.553^ (1/3) I = 55.3% In an economy, when GDP is growing consistently and unemployment rate is also falling. Though, growth rate in inflation rate is very high and it is approx. 55.3%. It means that demand is increasing and it is more than the supply. It is also causing overheating of the economy. Here, more money is chasing few goods. It leads to further increase in price. And it drives inflation on the higher side. Data given the problem confirms the economic scenario mentioned. It propels the inflation further and it is very high as a proof. 2 Inflation is growing with annualized rate of 55.3%. In this case, Federal Reserve should use contraction policy. As a part of it, Federal Reserve should deploy right money policy. It will discourage people to borrow and demand will come down. Thus, inflation will be controlled. 3. Federal Reserve can increase reserve requirements. Further, Federal Reserve can also sell government securities in open market. It will suck cash out of the system and contractionary policy will be implemented. Red.
Dear,The answer is 25.SolutionDear,The answer is 25..pdf
Dear,The answer is 25.SolutionDear,The answer is 25..pdf
proloyankur01
11. SAMPLING FREQUENCY REQUIRED IS 3998 HZ 12. to provide equivalent digital binary output 13.half of maximum frequency content of analog input 14. MOSFET gate current is equivalent to ZERO 15. DC series motor IS STARTED WITHOUT NO LOAD Solution 11. SAMPLING FREQUENCY REQUIRED IS 3998 HZ 12. to provide equivalent digital binary output 13.half of maximum frequency content of analog input 14. MOSFET gate current is equivalent to ZERO 15. DC series motor IS STARTED WITHOUT NO LOAD.
Cybrcoin or commonly known as Bitcoin is gaining ground from the las.pdf
Cybrcoin or commonly known as Bitcoin is gaining ground from the las.pdf
proloyankur01
1. Corporations, limited liability companies (LLCs), general and limited partnerships, and sole proprietorships are the more common legal entities used for operating a business. 2.Corporations and LLCs offer owners limited liability. General partners and sole proprietors may be held personally responsible for the debts of the general partnership and sole proprietorship. However,limited partners are not responsible for the partnership’s liabilities. 3.A business entity may be legally classified as a corporation, limited liability company (LLC), a general partnership (GP), a limited partnership (LP), or a sole proprietorship under state law. However, for tax purposes a business entity can be classified as either a separate taxpaying entity or as a flow-through entity. Separate taxpaying entities pay tax on their own income. In contrast, flow-through entities generally don’t pay taxes because income from these entities flows through to their business owners who are responsible for paying tax on the income. C corporations are separate taxpaying entities and if elected some flow-through entities may be treated as separate taxpaying entities. Flow-through entities are usually taxed as either partnerships, sole proprietorships, or disregarded entities. 4.A taxation principle referring to income taxes that are paid twice on the same source of earned income. Double taxation occurs because corporations are considered separate legal entities from their shareholders. As such, corporations pay taxes on their annual earnings, just as individuals do. When corporations pay out dividends to shareholders, those dividend payments incur income-tax liabilities for the shareholders who receive them, even though the earnings that provided the cash to pay the dividends were already taxed at the corporate level. 5. Double tax is actually more favorable if you, 1. Pay reasonable salaries to shareholders. 2. Lease property from shareholders. 3. Defer or eliminate dividend payments. 4. Defer capital gains taxes on shares by making lifetime gifts of appreciated stock Solution 1. Corporations, limited liability companies (LLCs), general and limited partnerships, and sole proprietorships are the more common legal entities used for operating a business. 2.Corporations and LLCs offer owners limited liability. General partners and sole proprietors may be held personally responsible for the debts of the general partnership and sole proprietorship. However,limited partners are not responsible for the partnership’s liabilities. 3.A business entity may be legally classified as a corporation, limited liability company (LLC), a general partnership (GP), a limited partnership (LP), or a sole proprietorship under state law. However, for tax purposes a business entity can be classified as either a separate taxpaying entity or as a flow-through entity. Separate taxpaying entities pay tax on their own income. In contrast, flow-through entities generally don’t pay taxes because income fr.
Cant see the questionSolutionCant see the question.pdf
Cant see the questionSolutionCant see the question.pdf
proloyankur01
1) D because he earns 25 dollars plus 80*h (h being the number of overtime hours) 2) Each side is x+6 (Not like what you drew 2 sides with X and the other 2 side with 6) b) G. because 4(x+6) = 2(x+4)+2(x+8) 3) F b)yes he can buy the item Solution 1) D because he earns 25 dollars plus 80*h (h being the number of overtime hours) 2) Each side is x+6 (Not like what you drew 2 sides with X and the other 2 side with 6) b) G. because 4(x+6) = 2(x+4)+2(x+8) 3) F b)yes he can buy the item.
Baud rate states that the symbol of frequency in a communication cha.pdf
Baud rate states that the symbol of frequency in a communication cha.pdf
proloyankur01
1) (-3xy^-3)^-4/(xy^-1)^-2 = (xy^-1)^2/(-3xy^-3)^4 ( revesring the num and denom.) Now , (x^2*y^-2)/(81x^4*y^-12) = x^2-4*y^(-2+12)/81 = x^-2*y^10/81 2) x^2 +4x+3 by (x+3) x^2 +4x +3 = x^2 +3x+x +3 ( Factorising) x(x+3) +1(x+3) = (x+1)(x+3) So, we have (x+1)(x+3)/(x+3) = (x+1) 3) 4b^2 -4b -3 by 2b-1 4b^ -6b+2b -3 = 2b(2b-3) +1(2b-3) ( factorising) = (2b+1)(2b-3) (2b+1)(2b-3)/(2b-1) = 2b-3 (cancelling out common term ) 4) (7x^2 +x^3)/(x^2 +5x -14) We have to look for points where denominator is zero and function is undefined x^2 +5x -14 = x^2 +7x -2x -14 = x(x+7)-2(x+7) = (x-2)(x+7) Denominator is zero at x =2 , -7 Domain : All real except x = 2 and x =-7 Solution 1) (-3xy^-3)^-4/(xy^-1)^-2 = (xy^-1)^2/(-3xy^-3)^4 ( revesring the num and denom.) Now , (x^2*y^-2)/(81x^4*y^-12) = x^2-4*y^(-2+12)/81 = x^-2*y^10/81 2) x^2 +4x+3 by (x+3) x^2 +4x +3 = x^2 +3x+x +3 ( Factorising) x(x+3) +1(x+3) = (x+1)(x+3) So, we have (x+1)(x+3)/(x+3) = (x+1) 3) 4b^2 -4b -3 by 2b-1 4b^ -6b+2b -3 = 2b(2b-3) +1(2b-3) ( factorising) = (2b+1)(2b-3) (2b+1)(2b-3)/(2b-1) = 2b-3 (cancelling out common term ) 4) (7x^2 +x^3)/(x^2 +5x -14) We have to look for points where denominator is zero and function is undefined x^2 +5x -14 = x^2 +7x -2x -14 = x(x+7)-2(x+7) = (x-2)(x+7) Denominator is zero at x =2 , -7 Domain : All real except x = 2 and x =-7.
b.) varies only in name from a one way analysis of varianceSolut.pdf
b.) varies only in name from a one way analysis of varianceSolut.pdf
proloyankur01
(a) Ka for C6H5NH3+ = Kw/Kb for C6H5NH2 = 10-14/4.27 x 10-10 = 2.342 x 10-5 Henderson-Hasselbalch equation: pH = pKa + log([C6H5NH2]/[C6H5NH3+]) = -log Ka + log([C6H5NH2]/[C6H5NH3+]) 4.20 = -log(2.342 x 10-5) + log(0.50/[C6H5NH3+]) log(0.50/[C6H5NH3+]) = -0.4304 0.50/[C6H5NH3+] = 10-0.4304 = 0.3712 [C6H5NH3+] = 1.347 1.35 M (b) Initial moles of C6H5NH2 = volume x concentration = 1.00 x 0.50 = 0.50 mol Initial moles of C6H5NH3+ = volume x concentration = 1.00 x 1.35 = 1.35 mol C6H5NH3+ + NaOH => C6H5NH2 + H2O + Na+ Moles of NaOH added = mass/molar mass = 4.00/40.00 = 0.100 mol Moles of C6H5NH2 = initial moles of C6H5NH2 + moles of NaOH added = 0.50 + 0.100 = 0.600 mol Moles of C6H5NH3+ = initial moles of C6H5NH3+ - moles of NaOH added = 1.35 - 0.100 = 1.25 mol Henderson-Hasselbalch equation: pH = pKa + log([C6H5NH2]/[C6H5NH3+]) = -log Ka + log(moles of C6H5NH2/moles of C6H5NH3+) since volume = 1.00 L for both = -log(2.342 x 10-5) + log(0.600/1.25) = 4.31 Solution (a) Ka for C6H5NH3+ = Kw/Kb for C6H5NH2 = 10-14/4.27 x 10-10 = 2.342 x 10-5 Henderson-Hasselbalch equation: pH = pKa + log([C6H5NH2]/[C6H5NH3+]) = -log Ka + log([C6H5NH2]/[C6H5NH3+]) 4.20 = -log(2.342 x 10-5) + log(0.50/[C6H5NH3+]) log(0.50/[C6H5NH3+]) = -0.4304 0.50/[C6H5NH3+] = 10-0.4304 = 0.3712 [C6H5NH3+] = 1.347 1.35 M (b) Initial moles of C6H5NH2 = volume x concentration = 1.00 x 0.50 = 0.50 mol Initial moles of C6H5NH3+ = volume x concentration = 1.00 x 1.35 = 1.35 mol C6H5NH3+ + NaOH => C6H5NH2 + H2O + Na+ Moles of NaOH added = mass/molar mass = 4.00/40.00 = 0.100 mol Moles of C6H5NH2 = initial moles of C6H5NH2 + moles of NaOH added = 0.50 + 0.100 = 0.600 mol Moles of C6H5NH3+ = initial moles of C6H5NH3+ - moles of NaOH added = 1.35 - 0.100 = 1.25 mol Henderson-Hasselbalch equation: pH = pKa + log([C6H5NH2]/[C6H5NH3+]) = -log Ka + log(moles of C6H5NH2/moles of C6H5NH3+) since volume = 1.00 L for both = -log(2.342 x 10-5) + log(0.600/1.25) = 4.31.
AnswerThe evolutionary history of humans since the most recent co.pdf
AnswerThe evolutionary history of humans since the most recent co.pdf
proloyankur01
(1) Q = 50 - 6.25P When demand increases by 20%, the new demand Q2 = 1.2 x Q So: 1.2 x Q = 1.2 x (50 - 6.25P) or, Q1 = 60 - 7.5P (2) Original Qd = 50 - 6.25P Qs = - 10 + 12.5P In equilibrium, Qd = Qs 50 - 6.25P = - 10 + 12.5P 18.75P = 60 P = 3.20 Q = - 10 + (12.5 x 3.2) = 30 (3) New Qd = 60 - 7.5P Equating with Qs: 60 - 7.5P = - 10 + 12.5P 20P = 70 P = 3.50, Q = - 10 + (12.5 x 3.5) = 33.75 (4) (a) elasticity of demand = Change in quantity demanded / change in price = 0.20 / [(3.5 - 3.2) / 3.2] ** = 2.13 ** change in quantity demanded = 20% (0.20) given (b) Elasticity of supply = change in quantity supplied / change in price = [(33.75 - 30) / 30] / [(3.5 - 3.2) / 3.2] = 0.125 / 0.0938 = 1.33 Solution (1) Q = 50 - 6.25P When demand increases by 20%, the new demand Q2 = 1.2 x Q So: 1.2 x Q = 1.2 x (50 - 6.25P) or, Q1 = 60 - 7.5P (2) Original Qd = 50 - 6.25P Qs = - 10 + 12.5P In equilibrium, Qd = Qs 50 - 6.25P = - 10 + 12.5P 18.75P = 60 P = 3.20 Q = - 10 + (12.5 x 3.2) = 30 (3) New Qd = 60 - 7.5P Equating with Qs: 60 - 7.5P = - 10 + 12.5P 20P = 70 P = 3.50, Q = - 10 + (12.5 x 3.5) = 33.75 (4) (a) elasticity of demand = Change in quantity demanded / change in price = 0.20 / [(3.5 - 3.2) / 3.2] ** = 2.13 ** change in quantity demanded = 20% (0.20) given (b) Elasticity of supply = change in quantity supplied / change in price = [(33.75 - 30) / 30] / [(3.5 - 3.2) / 3.2] = 0.125 / 0.0938 = 1.33.
Answer-Cultural relativism is a complex concept that has its inte.pdf
Answer-Cultural relativism is a complex concept that has its inte.pdf
proloyankur01
#include using namespace std; int main() { int n; cout<<\"enter n between 1 and 10 : \"; cin>>n; cout<<\"\ Roman numeral is : \"; switch(n) { case 1: cout<<\"I\"; break; case 2: cout<<\"II\"; break; case 3: cout<<\"III\"; break; case 4: cout<<\"IV\"; break; case 5: cout<<\"V\"; break; case 6: cout<<\"VI\"; break; case 7: cout<<\"VII\"; break; case 8: cout<<\"VIII\"; break; case 9: cout<<\"IX\"; break; case 10: cout<<\"X\"; break; } return 0; } Solution #include using namespace std; int main() { int n; cout<<\"enter n between 1 and 10 : \"; cin>>n; cout<<\"\ Roman numeral is : \"; switch(n) { case 1: cout<<\"I\"; break; case 2: cout<<\"II\"; break; case 3: cout<<\"III\"; break; case 4: cout<<\"IV\"; break; case 5: cout<<\"V\"; break; case 6: cout<<\"VI\"; break; case 7: cout<<\"VII\"; break; case 8: cout<<\"VIII\"; break; case 9: cout<<\"IX\"; break; case 10: cout<<\"X\"; break; } return 0; }.
Answer The answer is (C)DoubleSolutionAnswer The a.pdf
Answer The answer is (C)DoubleSolutionAnswer The a.pdf
proloyankur01
a. The results are inconclusive because the king size cigarettes are different sizes than the filtered cigarettes. b. No, the filters do not appear to make a difference because there is insufficient evidence to warrant the rejection of the claim. c. No, the filters do not appear to make difference because there is sufficient evidence to warrant the rejection of the claim. d. Given the king size cigarettes have the largest mean, it appears that the filters do make a difference(although this conclusion is not justified by the results from analysis of variance) Solution a. The results are inconclusive because the king size cigarettes are different sizes than the filtered cigarettes. b. No, the filters do not appear to make a difference because there is insufficient evidence to warrant the rejection of the claim. c. No, the filters do not appear to make difference because there is sufficient evidence to warrant the rejection of the claim. d. Given the king size cigarettes have the largest mean, it appears that the filters do make a difference(although this conclusion is not justified by the results from analysis of variance).
Advantages1.Easy to share data over a network2.Better communica.pdf
Advantages1.Easy to share data over a network2.Better communica.pdf
proloyankur01
let be A=x1i+y1j B=x2i+y2j A+B=(x1+x2)i+(y1+y2)j lA+Bl^2=(x1+x2)^2+(y1+y2)^2 now lAl^2=x1^2+y1^2 lBl^2=x2^2+y2^2 and AB=x1x2+y1y2 now lAl^2+2AB+lBl^2=x1^2+x2^2+2x1x2+2y1y2+y1^2+y2^2=(x1+x2)^2+(y1+y2)^2=lA+Bl^2 there fore lA+Bl^2=lAl^2+2AB+lBl^2 or lA+Bl^2=lAl^2+lBl^2+2lAllBl=lAl^2+2AB+lBl^2 Solution let be A=x1i+y1j B=x2i+y2j A+B=(x1+x2)i+(y1+y2)j lA+Bl^2=(x1+x2)^2+(y1+y2)^2 now lAl^2=x1^2+y1^2 lBl^2=x2^2+y2^2 and AB=x1x2+y1y2 now lAl^2+2AB+lBl^2=x1^2+x2^2+2x1x2+2y1y2+y1^2+y2^2=(x1+x2)^2+(y1+y2)^2=lA+Bl^2 there fore lA+Bl^2=lAl^2+2AB+lBl^2 or lA+Bl^2=lAl^2+lBl^2+2lAllBl=lAl^2+2AB+lBl^2.
An S corporation is formed by filing an Articles of Incorporation wi.pdf
An S corporation is formed by filing an Articles of Incorporation wi.pdf
proloyankur01
Income statement Net Sales / Income from Operations Rs m 8,741 Other Operating Income Rs m 58 Total Income Rs m 8,799 Expenditure (Increase) / Decrease in Finished / Trading Goods Rs m (74) Consumption of Raw Materials and Movement in Work-in-Progress Rs m 5,686 Purchase of Trading Goods Rs m 223 Employees Cost Rs m 532 Depreciation Rs m 207 Other Expenditure Rs m 1,370 Total Rs m 7,944 Profit / (Loss) from Operations Before Other Income, Financial Expenses and Exceptional Item Rs m 855 Other Income Rs m - Profit Before Financial Expenses and Exceptional Item Rs m 855 Interest Rs m 147 Profit / (Loss) After Financial Expenses But Before Exceptional Item Rs m 708 Exceptional Items Rs m - Profit from Ordinary Activities Before Tax Rs m 708 Tax Expense - Income Tax Rs m 241 Net Profit for the Period Rs m 468 Balance Sheet ( Rs m) Sources of Funds Shareholders\' Fund Share Capital 383 Equity Share Warrants - Reserves and Surplus 5,956 Total 6,340 Minority - Loan Fund Secured Loans 3,810 Unsecured Loans 3,690 Total 7,500 Deferred Tax Liability Net 1,052 Total 14,892 Application of Funds Fixed Assets Gross Block 13,106 Less: Depreciation 4,699 Net Block 8,407 Capital Work-in-Progress 779 Share in Joint Venture - Goodwill on Consolidation - Investments 4 Current Assets, Loans and Advances Inventories 4,194 Sundry Debtors 1,752 Cash and Bank Balances 2,315 Other Current Assets 2 Loans and Advances 1,844 Total Current Assets, Loans and Advances 10,106 Less: Current Liabilities and Provisions Current Liabilities 3,886 Provisions 520 Total Current Liabilities and Provisions 4,407 Net Current Assets 5,699 Deferred Revenue Expenditure 3 Total 14,892 Change in Retained earning Opening Balance Rs m 1,844 Add Transfer from Profit and Loss Account Rs m 500 Less Transfer to Profit & Loss Account Rs m (436) Common Stock Repurchased and Cancelled Rs m - Closing Balance Rs m 1,908 Solution Income statement Net Sales / Income from Operations Rs m 8,741 Other Operating Income Rs m 58 Total Income Rs m 8,799 Expenditure (Increase) / Decrease in Finished / Trading Goods Rs m (74) Consumption of Raw Materials and Movement in Work-in-Progress Rs m 5,686 Purchase of Trading Goods Rs m 223 Employees Cost Rs m 532 Depreciation Rs m 207 Other Expenditure Rs m 1,370 Total Rs m 7,944 Profit / (Loss) from Operations Before Other Income, Financial Expenses and Exceptional Item Rs m 855 Other Income Rs m - Profit Before Financial Expenses and Exceptional Item Rs m 855 Interest Rs m 147 Profit / (Loss) After Financial Expenses But Before Exceptional Item Rs m 708 Exceptional Items Rs m - Profit from Ordinary Activities Before Tax Rs m 708 Tax Expense - Income Tax Rs m 241 Net Profit for the Period Rs m 468 Balance Sheet ( Rs m) Sources of Funds Shareholders\' Fund Share Capital 383 Equity Share Warrants - Reserves and Surplus 5,956 Total 6,340 Minority - Loan Fund Secured Loans 3,810 Unsecured Loans 3,690 Total 7,500 Deferred Tax Liability Net 1,052 Total 14,892 Application of F.
A)depository institutionsB) contractual savings institutionsC)in.pdf
A)depository institutionsB) contractual savings institutionsC)in.pdf
proloyankur01
whats the right answer ?? Solution whats the right answer ??.
A is correct. History holds ten commands in the buffer by default..pdf
A is correct. History holds ten commands in the buffer by default..pdf
proloyankur01
4P + 5O2 = 2P2O5 the molar ratio of P to O2 is 4:5. moles of O2 = (0.221 mol/4) x 5 = 0.276 mol Solution 4P + 5O2 = 2P2O5 the molar ratio of P to O2 is 4:5. moles of O2 = (0.221 mol/4) x 5 = 0.276 mol.
4P + 5O2 = 2P2O5 the molar ratio of P to O2 is 4.pdf
4P + 5O2 = 2P2O5 the molar ratio of P to O2 is 4.pdf
proloyankur01
resulting solution is acidic as CH3NH3Cl is weak acid. Solution resulting solution is acidic as CH3NH3Cl is weak acid..
1. Corporations, limited liability companies (LLCs), general and lim.pdf
1. Corporations, limited liability companies (LLCs), general and lim.pdf
proloyankur01
Co has +3 ionic charge Solution Co has +3 ionic charge.
Using the dilution formula M1V1 = M2V2 12 20 = .pdf
Using the dilution formula M1V1 = M2V2 12 20 = .pdf
proloyankur01
...
VAMOS CUIDAR DO NOSSO PLANETA! .
VAMOS CUIDAR DO NOSSO PLANETA! .
Colégio Santa Teresinha
Open Tools for Research, Learning, Sharing in Agriculture and Society as a whole. Remote lecture by Marc Dusseiller and Fernando "nano" Castro on open science hardware for agriculture and edication, held for students of microbiology at UGM, Yogyakarta (remote - online )
dusjagr & nano talk on open tools for agriculture research and learning
dusjagr & nano talk on open tools for agriculture research and learning
Marc Dusseiller Dusjagr
Setting up a development environment for odoo using pycharm is highly preferred by odoo developers to develop and debug odoo modules and other related functionalities .
How to setup Pycharm environment for Odoo 17.pptx
How to setup Pycharm environment for Odoo 17.pptx
Celine George
https://app.box.com/s/x7vf0j7xaxl2hlczxm3ny497y4yto33i
80 ĐỀ THI THỬ TUYỂN SINH TIẾNG ANH VÀO 10 SỞ GD – ĐT THÀNH PHỐ HỒ CHÍ MINH NĂ...
80 ĐỀ THI THỬ TUYỂN SINH TIẾNG ANH VÀO 10 SỞ GD – ĐT THÀNH PHỐ HỒ CHÍ MINH NĂ...
Nguyen Thanh Tu Collection
Brief pharmacology of Remifentanil
REMIFENTANIL: An Ultra short acting opioid.pptx
REMIFENTANIL: An Ultra short acting opioid.pptx
Dr. Ravikiran H M Gowda
People are more triggered by positive news than negative news. Audience does not want to hear, read or receive any kind of bad news. So these slides show how to convey negative news to someone without affecting their emotions.
COMMUNICATING NEGATIVE NEWS - APPROACHES .pptx
COMMUNICATING NEGATIVE NEWS - APPROACHES .pptx
annathomasp01
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100 DIM C(50) (50 is max number of servers) 110 INPUT S,NSTOP (S,NSTOP = number of servers, customers to be simulated) 120 FOR D=1 TO NSTOP 130 IA= (IA = interarrival time) 140 A=A+IA (A = arrival time) 150 J=0 160 J=J+1 (J = index of server being probed) 170 IF J=S+1 THEN K=K+1 (K = number of customers that are blocked) 180 IF J=S+1 THEN 270 190 IF AA THEN AB=AB+M- A (AB = cumulative time during which all servers busy) 270 NEXT D 280 PRINT K/NSTOP,AB/A (fraction of customers blocked, fraction of time all servers are simultaneously busy) Solution 100 DIM C(50) (50 is max number of servers) 110 INPUT S,NSTOP (S,NSTOP = number of servers, customers to be simulated) 120 FOR D=1 TO NSTOP 130 IA= (IA = interarrival time) 140 A=A+IA (A = arrival time) 150 J=0 160 J=J+1 (J = index of server being probed) 170 IF J=S+1 THEN K=K+1 (K = number of customers that are blocked) 180 IF J=S+1 THEN 270 190 IF AA THEN AB=AB+M- A (AB = cumulative time during which all servers busy) 270 NEXT D 280 PRINT K/NSTOP,AB/A (fraction of customers blocked, fraction of time all servers are simultaneously busy).
create file name as board.javawrite below codeimport java.aw.pdf
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proloyankur01
1 Suppose, annualized growth in inflation rate is I 4.5 = 1.2*(1+I) ^3 (1+I)^3 = 4.5/1.2 = 3.75= 1.553^ (1/3) I = 55.3% In an economy, when GDP is growing consistently and unemployment rate is also falling. Though, growth rate in inflation rate is very high and it is approx. 55.3%. It means that demand is increasing and it is more than the supply. It is also causing overheating of the economy. Here, more money is chasing few goods. It leads to further increase in price. And it drives inflation on the higher side. Data given the problem confirms the economic scenario mentioned. It propels the inflation further and it is very high as a proof. 2 Inflation is growing with annualized rate of 55.3%. In this case, Federal Reserve should use contraction policy. As a part of it, Federal Reserve should deploy right money policy. It will discourage people to borrow and demand will come down. Thus, inflation will be controlled. 3. Federal Reserve can increase reserve requirements. Further, Federal Reserve can also sell government securities in open market. It will suck cash out of the system and contractionary policy will be implemented. Reduced government expending will also help. It will help curbing the inflation. 4 If recession happens and due to this reason, layoff takes place as well as demand decreases then contractionary economic policy will be ineffective. In those circumstances, Federal Reserve has to reverse the strategy. Technological change can also make a reduction in demand of products. In that industry, contractionary policy will be discouraging. Also, for those product categories where demand is inelastic in nature. Contractionary policy will not work. Note: Already answered similar question on Chegg Q&A board. Thus, above answer is the modified version as per the requirements mentioned in the question. Solution 1 Suppose, annualized growth in inflation rate is I 4.5 = 1.2*(1+I) ^3 (1+I)^3 = 4.5/1.2 = 3.75= 1.553^ (1/3) I = 55.3% In an economy, when GDP is growing consistently and unemployment rate is also falling. Though, growth rate in inflation rate is very high and it is approx. 55.3%. It means that demand is increasing and it is more than the supply. It is also causing overheating of the economy. Here, more money is chasing few goods. It leads to further increase in price. And it drives inflation on the higher side. Data given the problem confirms the economic scenario mentioned. It propels the inflation further and it is very high as a proof. 2 Inflation is growing with annualized rate of 55.3%. In this case, Federal Reserve should use contraction policy. As a part of it, Federal Reserve should deploy right money policy. It will discourage people to borrow and demand will come down. Thus, inflation will be controlled. 3. Federal Reserve can increase reserve requirements. Further, Federal Reserve can also sell government securities in open market. It will suck cash out of the system and contractionary policy will be implemented. Red.
Dear,The answer is 25.SolutionDear,The answer is 25..pdf
Dear,The answer is 25.SolutionDear,The answer is 25..pdf
proloyankur01
11. SAMPLING FREQUENCY REQUIRED IS 3998 HZ 12. to provide equivalent digital binary output 13.half of maximum frequency content of analog input 14. MOSFET gate current is equivalent to ZERO 15. DC series motor IS STARTED WITHOUT NO LOAD Solution 11. SAMPLING FREQUENCY REQUIRED IS 3998 HZ 12. to provide equivalent digital binary output 13.half of maximum frequency content of analog input 14. MOSFET gate current is equivalent to ZERO 15. DC series motor IS STARTED WITHOUT NO LOAD.
Cybrcoin or commonly known as Bitcoin is gaining ground from the las.pdf
Cybrcoin or commonly known as Bitcoin is gaining ground from the las.pdf
proloyankur01
1. Corporations, limited liability companies (LLCs), general and limited partnerships, and sole proprietorships are the more common legal entities used for operating a business. 2.Corporations and LLCs offer owners limited liability. General partners and sole proprietors may be held personally responsible for the debts of the general partnership and sole proprietorship. However,limited partners are not responsible for the partnership’s liabilities. 3.A business entity may be legally classified as a corporation, limited liability company (LLC), a general partnership (GP), a limited partnership (LP), or a sole proprietorship under state law. However, for tax purposes a business entity can be classified as either a separate taxpaying entity or as a flow-through entity. Separate taxpaying entities pay tax on their own income. In contrast, flow-through entities generally don’t pay taxes because income from these entities flows through to their business owners who are responsible for paying tax on the income. C corporations are separate taxpaying entities and if elected some flow-through entities may be treated as separate taxpaying entities. Flow-through entities are usually taxed as either partnerships, sole proprietorships, or disregarded entities. 4.A taxation principle referring to income taxes that are paid twice on the same source of earned income. Double taxation occurs because corporations are considered separate legal entities from their shareholders. As such, corporations pay taxes on their annual earnings, just as individuals do. When corporations pay out dividends to shareholders, those dividend payments incur income-tax liabilities for the shareholders who receive them, even though the earnings that provided the cash to pay the dividends were already taxed at the corporate level. 5. Double tax is actually more favorable if you, 1. Pay reasonable salaries to shareholders. 2. Lease property from shareholders. 3. Defer or eliminate dividend payments. 4. Defer capital gains taxes on shares by making lifetime gifts of appreciated stock Solution 1. Corporations, limited liability companies (LLCs), general and limited partnerships, and sole proprietorships are the more common legal entities used for operating a business. 2.Corporations and LLCs offer owners limited liability. General partners and sole proprietors may be held personally responsible for the debts of the general partnership and sole proprietorship. However,limited partners are not responsible for the partnership’s liabilities. 3.A business entity may be legally classified as a corporation, limited liability company (LLC), a general partnership (GP), a limited partnership (LP), or a sole proprietorship under state law. However, for tax purposes a business entity can be classified as either a separate taxpaying entity or as a flow-through entity. Separate taxpaying entities pay tax on their own income. In contrast, flow-through entities generally don’t pay taxes because income fr.
Cant see the questionSolutionCant see the question.pdf
Cant see the questionSolutionCant see the question.pdf
proloyankur01
1) D because he earns 25 dollars plus 80*h (h being the number of overtime hours) 2) Each side is x+6 (Not like what you drew 2 sides with X and the other 2 side with 6) b) G. because 4(x+6) = 2(x+4)+2(x+8) 3) F b)yes he can buy the item Solution 1) D because he earns 25 dollars plus 80*h (h being the number of overtime hours) 2) Each side is x+6 (Not like what you drew 2 sides with X and the other 2 side with 6) b) G. because 4(x+6) = 2(x+4)+2(x+8) 3) F b)yes he can buy the item.
Baud rate states that the symbol of frequency in a communication cha.pdf
Baud rate states that the symbol of frequency in a communication cha.pdf
proloyankur01
1) (-3xy^-3)^-4/(xy^-1)^-2 = (xy^-1)^2/(-3xy^-3)^4 ( revesring the num and denom.) Now , (x^2*y^-2)/(81x^4*y^-12) = x^2-4*y^(-2+12)/81 = x^-2*y^10/81 2) x^2 +4x+3 by (x+3) x^2 +4x +3 = x^2 +3x+x +3 ( Factorising) x(x+3) +1(x+3) = (x+1)(x+3) So, we have (x+1)(x+3)/(x+3) = (x+1) 3) 4b^2 -4b -3 by 2b-1 4b^ -6b+2b -3 = 2b(2b-3) +1(2b-3) ( factorising) = (2b+1)(2b-3) (2b+1)(2b-3)/(2b-1) = 2b-3 (cancelling out common term ) 4) (7x^2 +x^3)/(x^2 +5x -14) We have to look for points where denominator is zero and function is undefined x^2 +5x -14 = x^2 +7x -2x -14 = x(x+7)-2(x+7) = (x-2)(x+7) Denominator is zero at x =2 , -7 Domain : All real except x = 2 and x =-7 Solution 1) (-3xy^-3)^-4/(xy^-1)^-2 = (xy^-1)^2/(-3xy^-3)^4 ( revesring the num and denom.) Now , (x^2*y^-2)/(81x^4*y^-12) = x^2-4*y^(-2+12)/81 = x^-2*y^10/81 2) x^2 +4x+3 by (x+3) x^2 +4x +3 = x^2 +3x+x +3 ( Factorising) x(x+3) +1(x+3) = (x+1)(x+3) So, we have (x+1)(x+3)/(x+3) = (x+1) 3) 4b^2 -4b -3 by 2b-1 4b^ -6b+2b -3 = 2b(2b-3) +1(2b-3) ( factorising) = (2b+1)(2b-3) (2b+1)(2b-3)/(2b-1) = 2b-3 (cancelling out common term ) 4) (7x^2 +x^3)/(x^2 +5x -14) We have to look for points where denominator is zero and function is undefined x^2 +5x -14 = x^2 +7x -2x -14 = x(x+7)-2(x+7) = (x-2)(x+7) Denominator is zero at x =2 , -7 Domain : All real except x = 2 and x =-7.
b.) varies only in name from a one way analysis of varianceSolut.pdf
b.) varies only in name from a one way analysis of varianceSolut.pdf
proloyankur01
(a) Ka for C6H5NH3+ = Kw/Kb for C6H5NH2 = 10-14/4.27 x 10-10 = 2.342 x 10-5 Henderson-Hasselbalch equation: pH = pKa + log([C6H5NH2]/[C6H5NH3+]) = -log Ka + log([C6H5NH2]/[C6H5NH3+]) 4.20 = -log(2.342 x 10-5) + log(0.50/[C6H5NH3+]) log(0.50/[C6H5NH3+]) = -0.4304 0.50/[C6H5NH3+] = 10-0.4304 = 0.3712 [C6H5NH3+] = 1.347 1.35 M (b) Initial moles of C6H5NH2 = volume x concentration = 1.00 x 0.50 = 0.50 mol Initial moles of C6H5NH3+ = volume x concentration = 1.00 x 1.35 = 1.35 mol C6H5NH3+ + NaOH => C6H5NH2 + H2O + Na+ Moles of NaOH added = mass/molar mass = 4.00/40.00 = 0.100 mol Moles of C6H5NH2 = initial moles of C6H5NH2 + moles of NaOH added = 0.50 + 0.100 = 0.600 mol Moles of C6H5NH3+ = initial moles of C6H5NH3+ - moles of NaOH added = 1.35 - 0.100 = 1.25 mol Henderson-Hasselbalch equation: pH = pKa + log([C6H5NH2]/[C6H5NH3+]) = -log Ka + log(moles of C6H5NH2/moles of C6H5NH3+) since volume = 1.00 L for both = -log(2.342 x 10-5) + log(0.600/1.25) = 4.31 Solution (a) Ka for C6H5NH3+ = Kw/Kb for C6H5NH2 = 10-14/4.27 x 10-10 = 2.342 x 10-5 Henderson-Hasselbalch equation: pH = pKa + log([C6H5NH2]/[C6H5NH3+]) = -log Ka + log([C6H5NH2]/[C6H5NH3+]) 4.20 = -log(2.342 x 10-5) + log(0.50/[C6H5NH3+]) log(0.50/[C6H5NH3+]) = -0.4304 0.50/[C6H5NH3+] = 10-0.4304 = 0.3712 [C6H5NH3+] = 1.347 1.35 M (b) Initial moles of C6H5NH2 = volume x concentration = 1.00 x 0.50 = 0.50 mol Initial moles of C6H5NH3+ = volume x concentration = 1.00 x 1.35 = 1.35 mol C6H5NH3+ + NaOH => C6H5NH2 + H2O + Na+ Moles of NaOH added = mass/molar mass = 4.00/40.00 = 0.100 mol Moles of C6H5NH2 = initial moles of C6H5NH2 + moles of NaOH added = 0.50 + 0.100 = 0.600 mol Moles of C6H5NH3+ = initial moles of C6H5NH3+ - moles of NaOH added = 1.35 - 0.100 = 1.25 mol Henderson-Hasselbalch equation: pH = pKa + log([C6H5NH2]/[C6H5NH3+]) = -log Ka + log(moles of C6H5NH2/moles of C6H5NH3+) since volume = 1.00 L for both = -log(2.342 x 10-5) + log(0.600/1.25) = 4.31.
AnswerThe evolutionary history of humans since the most recent co.pdf
AnswerThe evolutionary history of humans since the most recent co.pdf
proloyankur01
(1) Q = 50 - 6.25P When demand increases by 20%, the new demand Q2 = 1.2 x Q So: 1.2 x Q = 1.2 x (50 - 6.25P) or, Q1 = 60 - 7.5P (2) Original Qd = 50 - 6.25P Qs = - 10 + 12.5P In equilibrium, Qd = Qs 50 - 6.25P = - 10 + 12.5P 18.75P = 60 P = 3.20 Q = - 10 + (12.5 x 3.2) = 30 (3) New Qd = 60 - 7.5P Equating with Qs: 60 - 7.5P = - 10 + 12.5P 20P = 70 P = 3.50, Q = - 10 + (12.5 x 3.5) = 33.75 (4) (a) elasticity of demand = Change in quantity demanded / change in price = 0.20 / [(3.5 - 3.2) / 3.2] ** = 2.13 ** change in quantity demanded = 20% (0.20) given (b) Elasticity of supply = change in quantity supplied / change in price = [(33.75 - 30) / 30] / [(3.5 - 3.2) / 3.2] = 0.125 / 0.0938 = 1.33 Solution (1) Q = 50 - 6.25P When demand increases by 20%, the new demand Q2 = 1.2 x Q So: 1.2 x Q = 1.2 x (50 - 6.25P) or, Q1 = 60 - 7.5P (2) Original Qd = 50 - 6.25P Qs = - 10 + 12.5P In equilibrium, Qd = Qs 50 - 6.25P = - 10 + 12.5P 18.75P = 60 P = 3.20 Q = - 10 + (12.5 x 3.2) = 30 (3) New Qd = 60 - 7.5P Equating with Qs: 60 - 7.5P = - 10 + 12.5P 20P = 70 P = 3.50, Q = - 10 + (12.5 x 3.5) = 33.75 (4) (a) elasticity of demand = Change in quantity demanded / change in price = 0.20 / [(3.5 - 3.2) / 3.2] ** = 2.13 ** change in quantity demanded = 20% (0.20) given (b) Elasticity of supply = change in quantity supplied / change in price = [(33.75 - 30) / 30] / [(3.5 - 3.2) / 3.2] = 0.125 / 0.0938 = 1.33.
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proloyankur01
#include using namespace std; int main() { int n; cout<<\"enter n between 1 and 10 : \"; cin>>n; cout<<\"\ Roman numeral is : \"; switch(n) { case 1: cout<<\"I\"; break; case 2: cout<<\"II\"; break; case 3: cout<<\"III\"; break; case 4: cout<<\"IV\"; break; case 5: cout<<\"V\"; break; case 6: cout<<\"VI\"; break; case 7: cout<<\"VII\"; break; case 8: cout<<\"VIII\"; break; case 9: cout<<\"IX\"; break; case 10: cout<<\"X\"; break; } return 0; } Solution #include using namespace std; int main() { int n; cout<<\"enter n between 1 and 10 : \"; cin>>n; cout<<\"\ Roman numeral is : \"; switch(n) { case 1: cout<<\"I\"; break; case 2: cout<<\"II\"; break; case 3: cout<<\"III\"; break; case 4: cout<<\"IV\"; break; case 5: cout<<\"V\"; break; case 6: cout<<\"VI\"; break; case 7: cout<<\"VII\"; break; case 8: cout<<\"VIII\"; break; case 9: cout<<\"IX\"; break; case 10: cout<<\"X\"; break; } return 0; }.
Answer The answer is (C)DoubleSolutionAnswer The a.pdf
Answer The answer is (C)DoubleSolutionAnswer The a.pdf
proloyankur01
a. The results are inconclusive because the king size cigarettes are different sizes than the filtered cigarettes. b. No, the filters do not appear to make a difference because there is insufficient evidence to warrant the rejection of the claim. c. No, the filters do not appear to make difference because there is sufficient evidence to warrant the rejection of the claim. d. Given the king size cigarettes have the largest mean, it appears that the filters do make a difference(although this conclusion is not justified by the results from analysis of variance) Solution a. The results are inconclusive because the king size cigarettes are different sizes than the filtered cigarettes. b. No, the filters do not appear to make a difference because there is insufficient evidence to warrant the rejection of the claim. c. No, the filters do not appear to make difference because there is sufficient evidence to warrant the rejection of the claim. d. Given the king size cigarettes have the largest mean, it appears that the filters do make a difference(although this conclusion is not justified by the results from analysis of variance).
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proloyankur01
let be A=x1i+y1j B=x2i+y2j A+B=(x1+x2)i+(y1+y2)j lA+Bl^2=(x1+x2)^2+(y1+y2)^2 now lAl^2=x1^2+y1^2 lBl^2=x2^2+y2^2 and AB=x1x2+y1y2 now lAl^2+2AB+lBl^2=x1^2+x2^2+2x1x2+2y1y2+y1^2+y2^2=(x1+x2)^2+(y1+y2)^2=lA+Bl^2 there fore lA+Bl^2=lAl^2+2AB+lBl^2 or lA+Bl^2=lAl^2+lBl^2+2lAllBl=lAl^2+2AB+lBl^2 Solution let be A=x1i+y1j B=x2i+y2j A+B=(x1+x2)i+(y1+y2)j lA+Bl^2=(x1+x2)^2+(y1+y2)^2 now lAl^2=x1^2+y1^2 lBl^2=x2^2+y2^2 and AB=x1x2+y1y2 now lAl^2+2AB+lBl^2=x1^2+x2^2+2x1x2+2y1y2+y1^2+y2^2=(x1+x2)^2+(y1+y2)^2=lA+Bl^2 there fore lA+Bl^2=lAl^2+2AB+lBl^2 or lA+Bl^2=lAl^2+lBl^2+2lAllBl=lAl^2+2AB+lBl^2.
An S corporation is formed by filing an Articles of Incorporation wi.pdf
An S corporation is formed by filing an Articles of Incorporation wi.pdf
proloyankur01
Income statement Net Sales / Income from Operations Rs m 8,741 Other Operating Income Rs m 58 Total Income Rs m 8,799 Expenditure (Increase) / Decrease in Finished / Trading Goods Rs m (74) Consumption of Raw Materials and Movement in Work-in-Progress Rs m 5,686 Purchase of Trading Goods Rs m 223 Employees Cost Rs m 532 Depreciation Rs m 207 Other Expenditure Rs m 1,370 Total Rs m 7,944 Profit / (Loss) from Operations Before Other Income, Financial Expenses and Exceptional Item Rs m 855 Other Income Rs m - Profit Before Financial Expenses and Exceptional Item Rs m 855 Interest Rs m 147 Profit / (Loss) After Financial Expenses But Before Exceptional Item Rs m 708 Exceptional Items Rs m - Profit from Ordinary Activities Before Tax Rs m 708 Tax Expense - Income Tax Rs m 241 Net Profit for the Period Rs m 468 Balance Sheet ( Rs m) Sources of Funds Shareholders\' Fund Share Capital 383 Equity Share Warrants - Reserves and Surplus 5,956 Total 6,340 Minority - Loan Fund Secured Loans 3,810 Unsecured Loans 3,690 Total 7,500 Deferred Tax Liability Net 1,052 Total 14,892 Application of Funds Fixed Assets Gross Block 13,106 Less: Depreciation 4,699 Net Block 8,407 Capital Work-in-Progress 779 Share in Joint Venture - Goodwill on Consolidation - Investments 4 Current Assets, Loans and Advances Inventories 4,194 Sundry Debtors 1,752 Cash and Bank Balances 2,315 Other Current Assets 2 Loans and Advances 1,844 Total Current Assets, Loans and Advances 10,106 Less: Current Liabilities and Provisions Current Liabilities 3,886 Provisions 520 Total Current Liabilities and Provisions 4,407 Net Current Assets 5,699 Deferred Revenue Expenditure 3 Total 14,892 Change in Retained earning Opening Balance Rs m 1,844 Add Transfer from Profit and Loss Account Rs m 500 Less Transfer to Profit & Loss Account Rs m (436) Common Stock Repurchased and Cancelled Rs m - Closing Balance Rs m 1,908 Solution Income statement Net Sales / Income from Operations Rs m 8,741 Other Operating Income Rs m 58 Total Income Rs m 8,799 Expenditure (Increase) / Decrease in Finished / Trading Goods Rs m (74) Consumption of Raw Materials and Movement in Work-in-Progress Rs m 5,686 Purchase of Trading Goods Rs m 223 Employees Cost Rs m 532 Depreciation Rs m 207 Other Expenditure Rs m 1,370 Total Rs m 7,944 Profit / (Loss) from Operations Before Other Income, Financial Expenses and Exceptional Item Rs m 855 Other Income Rs m - Profit Before Financial Expenses and Exceptional Item Rs m 855 Interest Rs m 147 Profit / (Loss) After Financial Expenses But Before Exceptional Item Rs m 708 Exceptional Items Rs m - Profit from Ordinary Activities Before Tax Rs m 708 Tax Expense - Income Tax Rs m 241 Net Profit for the Period Rs m 468 Balance Sheet ( Rs m) Sources of Funds Shareholders\' Fund Share Capital 383 Equity Share Warrants - Reserves and Surplus 5,956 Total 6,340 Minority - Loan Fund Secured Loans 3,810 Unsecured Loans 3,690 Total 7,500 Deferred Tax Liability Net 1,052 Total 14,892 Application of F.
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proloyankur01
whats the right answer ?? Solution whats the right answer ??.
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proloyankur01
4P + 5O2 = 2P2O5 the molar ratio of P to O2 is 4:5. moles of O2 = (0.221 mol/4) x 5 = 0.276 mol Solution 4P + 5O2 = 2P2O5 the molar ratio of P to O2 is 4:5. moles of O2 = (0.221 mol/4) x 5 = 0.276 mol.
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proloyankur01
resulting solution is acidic as CH3NH3Cl is weak acid. Solution resulting solution is acidic as CH3NH3Cl is weak acid..
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Co has +3 ionic charge Solution Co has +3 ionic charge.
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