SlideShare a Scribd company logo
1 of 10
Download to read offline
‫ﭘﺎرﺳﺎ‬ ‫ﭘﻮرﻳﺎ‬
‫سازی‬ ‫شبيه‬ ‫کدھای‬ ‫و‬ ‫تحليل‬
‫اول‬ ‫سری‬ ‫تمرين‬
‫ﺳﺎزي‬ ‫ﺷﺒﻴﻪ‬ ‫ﻛﻤﻚ‬ ‫ﺑﺎ‬ ‫اول‬ ‫ﺗﻤﺮﻳﻦ‬ ‫ﺣﻞ‬ ‫ﺗﺤﻠﻴﻞ‬matlab
1-‫در‬‫ﻣﺪل‬DMC‫ﻣﺪل‬ ‫از‬‫ﭘﺎﺳﺦ‬‫ﭘﻠﻪ‬‫ﺳﻴﺴﺘﻢ‬‫اﺳﺘﻔﺎده‬‫ﻣﻴﻜﻨﻴﻢ‬.
2-‫ﻓﺮض‬ ‫ﺑﺎ‬‫ﺑﻪ‬‫ﺗﺎﺑﻊ‬‫ﺗﺒﺪﻳﻞ‬‫ﺳﻴﺴﺘﻢ‬‫ﺳﻮال‬‫ﻛﻤﻚ‬ ‫ﺑﺎ‬ ‫و‬‫از‬‫ﻫﺎي‬ ‫ﻛﺪ‬‫ﺳﺎزي‬ ‫ﺷﺒﻴﻪ‬ ‫اول‬ ‫ﻗﺴﻤﺖ‬‫ﺑﻪ‬‫ﻧﺘﺎﻳﺠﻲ‬
‫ﺧﻮاﻫﻴﻢ‬‫رﺳﻴ‬‫ﺪ‬.
3-‫ﭘﻠﻪ‬ ‫ﭘﺎﺳﺦ‬ ‫ﺳﭙﺲ‬‫زﻣﺎن‬ ‫ﮔﺬﺷﺖ‬ ‫از‬ ‫ﺑﻌﺪ‬ ‫ﺳﻴﺴﺘﻢ‬ ‫دﻫﺪ‬ ‫ﻣﻲ‬ ‫ﻧﺸﺎن‬ ‫ﻛﻪ‬ ‫ﻛﻨﻴﻢ‬ ‫ﻣﻲ‬ ‫راﺑﺮرﺳﻲ‬26‫ﺑﻪ‬ ‫ﺛﺎﻧﻴﻪ‬
‫رﺳﺪ‬ ‫ﻣﻲ‬ ‫ﺧﻮد‬ ‫ﻧﻬﺎﻳﻲ‬ ‫ﻣﻘﺪار‬.
4-‫آورﻳﻢ‬ ‫ﻣﻲ‬ ‫ﺑﺪﺳﺖ‬ ‫را‬ ‫ﺷﺪه‬ ‫ﺧﻮاﺳﺘﻪ‬ ‫ﻫﺎي‬ ‫ﻟﺤﻈﻪ‬ ‫در‬ ‫ﻣﻘﺪار‬ ‫ﻣﺮﺑﻮﻃﻪ‬ ‫ﻫﺎي‬ ‫ﻓﺮﻣﻮل‬ ‫و‬ ‫رواﺑﻂ‬ ‫ﺑﻪ‬ ‫ﺗﻮﺟﻪ‬ ‫ﺑﺎ‬
)‫ﻟﺤﻈﻪ‬t‫و‬k(
5- ŷ(t+k⊥t)=Σgiki=1Δu(t+k+i)+ym(t)+Σ(gi+kNi=1−gi)Δu(t−i)
6-‫ﻣﺮ‬ ‫ﺳﻮال‬ ‫اول‬ ‫ﻗﺴﻤﺖ‬‫ﺣﺎل‬ ‫ورودي‬ ‫ﺑﻪ‬ ‫ﺑﻮط‬‫و‬ ‫زﻣﺎن‬ ‫ﻫﻤﺎن‬ ‫در‬ ‫ﺳﻴﺴﺘﻢ‬ ‫ﺧﺮوﺟﻲ‬ ‫ﺑﻪ‬ ‫ﻣﺮﺑﻮط‬ ‫دوم‬ ‫ﻗﺴﻤﺖ‬ ‫و‬
‫ﺑﺎﺷﺪ‬ ‫ﻣﻲ‬ ‫ﺧﺎرج‬ ‫ﻣﺎ‬ ‫ﻛﻨﺘﺮل‬ ‫از‬ ‫ﭼﻮن‬ ‫ﺑﺎﺷﺪ‬ ‫ﻧﻤﻲ‬ ‫ﺑﺎزﻧﻮﻳﺴﻲ‬ ‫ﻗﺎﺑﻞ‬ ‫ﻛﻪ‬ ‫ﺑﺎﺷﺪ‬ ‫ﻣﻲ‬ ‫ﻗﺒﻞ‬ ‫ﻫﺎي‬ ‫زﻣﺎن‬.
7-‫ﻣﻴﮕﻴﺮﻳﻢ‬ ‫ﻛﻤﻚ‬ ‫ﻣﺎﺗﺮﻳﺲ‬ ‫از‬ ‫ﺑﺎﻻ‬ ‫ﺗﻮﺿﻴﺢ‬ ‫ﺑﻴﺸﺘﺮ‬ ‫درك‬ ‫ﺑﺮاي‬
8-‫ﻛﻪ‬ ‫ﻣﺴﺌﻠﻪ‬ ‫ﻓﺮض‬ ‫ﺑﻪ‬ ‫ﺗﻮﺟﻪ‬ ‫ﺑﺎ‬N , p ,m‫ﺗﺮﺗﻴﺐ‬ ‫ﺑﻪ‬5‫و‬10‫و‬30‫ﺑﺎﺷﺪ‬ ‫ﻣﻲ‬.‫ﺑﻴﻦ‬ ‫ﭘﻴﺶ‬ ‫ﻛﻨﺘﺮل‬ ‫در‬
‫ﻟﺤﻈﻪ‬t‫ﻛﻨﻴﻢ‬ ‫ﻣﻲ‬ ‫ﻣﺤﺎﺳﺒﻪ‬ ‫را‬
9-‫ﻣﺎﺗﺮﻳﺲ‬ ‫ﭘﻠﻪ‬ ‫ﭘﺎﺳﺦ‬ ‫ﻃﺒﻖ‬ ‫ﺑﺮ‬ ‫ﺑﻴﻦ‬ ‫ﭘﻴﺶ‬ ‫ﻛﻨﺘﺮل‬ ‫در‬ ‫ﺳﭙﺲ‬G‫دﻫﻴﻢ‬ ‫ﻣﻲ‬ ‫ﺗﺸﻜﻴﻞ‬ ‫را‬.
10-‫ﻣﺎﺗﺮﻳﺲ‬ ‫ﻛﺪ‬G‫ﻣﺎﺗﺮﻳﺲ‬ ‫ﻫﻢ‬ ‫ﻣﺮﺑﻌﻲ‬ ‫ﻣﺎﺗﺮﻳﺲ‬ ‫از‬ ‫ﺗﻮاﻧﻴﻢ‬ ‫ﻣﻲ‬ ‫ﻫﻤﭽﻨﻴﻦ‬ ‫ﻧﻮﻳﺴﻴﻢ‬ ‫ﻣﻲ‬ ‫را‬G‫ﺑﺪﺳﺖ‬ ‫را‬
‫آورﻳﻢ‬.
11-‫ﻛﻨﻴﻢ‬ ‫ﻣﻲ‬ ‫ﺣﺴﺎب‬ ‫را‬ ‫آﻳﻨﺪه‬ ‫ﻫﺎي‬ ‫ورودي‬
12-‫آورﻳﻢ‬ ‫ﻣﻲ‬ ‫ﺑﺪﺳﺖ‬ ‫را‬ ‫ﺧﺮوﺟﻲ‬ ‫و‬ ‫را‬ ‫ﺟﺪﻳﺪ‬ ‫ﻫﺎي‬ ‫ورودي‬ ‫ﻣﻴﻜﻨﻴﻢ‬ ‫وارد‬ ‫ﺳﻴﺴﺘﻢ‬ ‫ﺑﻪ‬.
13-‫ﻣﺎﺗﺮﻳﺲ‬ ‫ﺳﭙﺲ‬Gn‫دﻫﻴﻢ‬ ‫ﻣﻲ‬ ‫ﺗﺸﻜﻴﻞ‬ ‫را‬.
14-‫ﻟﺤﻈﻪ‬ ‫در‬t‫ﺑﺮدار‬ ‫ﻣﺎﺗﺮﻳﺲ‬ ‫اﻳﻦ‬ ‫ﻛﻤﻚ‬ ‫ﺑﺎ‬f‫ﺷﻮد‬ ‫ﻣﻲ‬ ‫ﻣﺤﺎﺳﺒﻪ‬.
15-‫ﺑﺮاي‬‫ﺗﺤﻠﻴﻞ‬‫ﺟﻮاب‬‫در‬‫اﺑﺘﺪا‬‫اﻓﻖ‬‫ﭘﻴﺶ‬‫ﺑﻴﻨﻲ‬10‫ﺗﻌﺪاد‬‫ﻧﻤﻮﻧﻪ‬‫ﻫﺎ‬30‫و‬‫اﻓﻖ‬‫ﻛﻨﺘﺮل‬‫را‬5‫ﮔﺮﻓﺘﻪ‬‫و‬
‫ﻣﻴﻜﻨﻴﻢ‬ ‫ﻧﮕﺎه‬ ‫را‬ ‫ﻧﺘﻴﺠﻪ‬.
16-‫در‬‫اﺑﺘﺪا‬‫ﺗﻌﺪاد‬‫ﻧﻤﻮﻧﻪ‬‫ﻫﺎي‬‫ﭘﺎﺳﺦ‬‫ﭘﻠﻪ‬‫را‬‫از‬30‫ﺑﻪ‬40‫اﻓﺰاﻳﺶ‬‫ﻣﻴﺪﻫﻴﻢ‬‫ﺗﻔﺎوت‬‫زﻳﺎدي‬‫ﺣﺎﺻﻞ‬‫ﻧﻤﻴﺸﻮد‬
‫ﻧﻤﻮﻧﻪ‬ ‫از‬ ‫ﺑﻌﺪ‬ ‫ﭼﻮن‬30‫اﺧﺘﻼف‬‫ﺑﻴﻦ‬‫ﺟﻮاﺑﻬﺎي‬‫ﭘﺎﺳﺦ‬‫ﭘﻠﻪ‬‫ﻛﻤﺘﺮ‬‫از‬0,003‫ﻣﻴﺒﺎﺷﺪ‬.‫ﻓﻘﻂ‬‫در‬‫ﺣﺎﻟﺖ‬‫ﻛﻠﻲ‬
‫ﺑﺎ‬‫اﻓﺰاﻳﺶ‬‫ﺗﻌﺪاد‬‫ﻫﺎﺣﺠﻢ‬ ‫ﻧﻤﻮﻧﻪ‬‫ﻣﺤﺎﺳﺒﺎت‬‫ﺑﺎﻻ‬‫ﻣﻴﺮود‬‫وﻟﻲ‬‫از‬‫اورﺷﻮت‬‫زدن‬‫ﺳﻴﺴﺘﻢ‬‫ﺟﻠﻮﮔﻴﺮي‬‫ﻣﻴﻜﻨﺪ‬.
17-‫اﻓﻖ‬‫ﭘﻴﺶ‬‫ﺑﻴﻨﻲ‬‫را‬‫اﻓﺰاﻳﺶ‬‫داده‬‫و‬‫ﻣﺸﺎﻫﺪه‬‫ﻣﻴﺸﻮد‬‫ﻛﻪ‬‫ﺑﺎ‬‫اﻓﺰاﻳﺶ‬‫اﻓﻖ‬‫ﭘﻴﺶ‬‫ﺑﻴﻨﻲ‬‫ﭼﻮن‬‫در‬‫ﻫﺮ‬
‫ﺧﺮوﺟﻴﻬﺎي‬ ‫ﻣﺮﺣﻠﻪ‬‫ﺑﻴﺸﺘﺮي‬‫را‬‫ﺗﺨﻤﻴﻦ‬‫زدﻫﺎﻳﻢ‬‫ﻛﻪ‬‫ﺷﺎﻳﺪ‬‫داراي‬‫اﻃﻼﻋﺎت‬‫ﻧﺎدرﺳﺘﻲ‬‫ﺑﺎﺷﻨﺪ‬‫ورودي‬‫اﻳﻦ‬‫ﻟﺤﻈﻪ‬
‫ﺑﺮاي‬‫ﺟﻮاب‬ ‫داﺷﺘﻦ‬‫ﻣﻄﻠﻮب‬‫ﺑﺮاي‬‫داﺷﺘﻦ‬‫ﻋﻜﺲ‬‫اﻟﻌﻤﻞ‬‫ﻣﻨﺎﺳﺐ‬‫در‬‫ﺧﺮوﺟﻲ‬‫ﻫﺎي‬‫آﻳﻨﺪه‬‫ﻣﻴﺒﺎﺷﺪ‬‫در‬‫ﻧﺘﻴﺠﻪ‬‫ﻣﻘﺪار‬
‫ﺳﻴﮕﻨﺎل‬‫اﻓﺰاﻳﺶ‬ ‫ﻛﻨﺘﺮﻟﻲ‬‫ﻳﺎﻓﺘﻪ‬‫و‬‫اﮔﺮ‬‫اﻳﻦ‬‫اﻓﻖ‬‫ﺑﻴﺸﺘﺮ‬‫اﻓﺰاﻳﺶ‬‫ﻳﺎﺑﺪ‬‫ﻣﻨﺠﺮ‬‫ﺑﻪ‬‫ﻧﺎﭘﺎﻳﺪاري‬‫ﺳﻴﺴﺘﻢ‬‫ﻧﻴﺰ‬‫ﻣﻴﺸﻮد‬.
18-‫ورﻳﻢ‬Ĥ‫ﻣﻴ‬ ‫ﺑﺪﺳﺖ‬ ‫را‬ ‫ﺳﻴﺴﺘﻢ‬ ‫اﻏﺘﺸﺎش‬.
19-‫ﻗﺴﻤﺖ‬ ‫ﺧﺮوﺟﻲ‬MAC‫راﺑﻄﻪ‬ ‫ﻛﻤﻚ‬ ‫ﺑﺎ‬ ‫آورﻳﻢ‬ ‫ﻣﻲ‬ ‫ﺑﺪﺳﺖ‬ ‫را‬‫ݕ‬ = ‫ܪ‬1ܷ+ + ‫ܪ‬2ܷ− + ݊
20-U+‫ﻛﻨﻴﻢ‬ ‫ﻣﻲ‬ ‫ﻣﺤﺎﺳﺒﻪ‬ ‫ﺳﺎزي‬ ‫ﺑﻬﻴﻨﻪ‬ ‫ﻃﺮﻳﻖ‬ ‫از‬ ‫را‬
21-‫ﻫﺎي‬ ‫ﻣﺎﺗﺮﻳﺲ‬H1 H2‫را‬‫از‬ ‫اﻃﻼع‬ ‫ﺑﺎ‬p=3 , m=5‫ﻣﻴﻜﻨﻴﻢ‬ ‫درﺳﺖ‬.
22-‫ﺗﺎ‬ ‫را‬ ‫ﻛﻨﺘﺮل‬ ‫اﻓﻖ‬m=10‫ﻛﻨﻴﻢ‬ ‫ﻣﻲ‬ ‫زﻳﺎد‬.
23-‫ﻫﺰﻳﻨﻪ‬ ‫ﺗﺎﺑﻊ‬ ‫در‬ ‫را‬ ‫ورودي‬ ‫وزن‬10‫ﻛﻨﻴﻢ‬ ‫ﻣﻲ‬ ‫ﺑﺮاﺑﺮ‬.
24-‫دﻫﻴﻢ‬ ‫ﻣﻲ‬ ‫اﻓﺰاﻳﺶ‬ ‫را‬ ‫ﭘﻴﺶ‬ ‫اﻓﻖ‬.
‫ﺳﺎزي‬ ‫ﺷﺒﻴﻪ‬ ‫ﺗﺤﻠﻴﻞ‬ ‫ﻧﻬﺎﻳﻲ‬ ‫ﻧﺘﻴﺠﻪ‬
‫ﺑﺮاي‬‫اﻳﻨﻜﻪ‬‫ﺗﺤﻠﻴﻞ‬‫درﺟﻪ‬‫ﺗﻮاﺑﻊ‬‫ﭘﺎﻳﻪ‬‫را‬‫ﺑﻔﻬﻤﻴﻢ‬‫ورودي‬‫ﺳﻴﺴﺘﻢ‬‫را‬‫ﺑﻪ‬‫ﺻﻮرت‬‫ﻫﺎي‬ ‫ﭘﻠﻪ‬‫ﻣﺨﺘﻠﻒ‬‫اﻳﺠﺎد‬‫ﻣﻴﻜﻨﻴﻢ‬
‫ﻣﺸﺎﻫﺪه‬‫ﻣﻴﺸﻮد‬‫ﻫﺮﭼﻪ‬‫درﺟﻪ‬‫ﺗﻮاﺑﻊ‬‫ﭘﺎﻳﻪ‬‫را‬‫اﻓﺰاﻳﺶ‬‫دﻫﻴﻢ‬‫ﺟﻮاب‬‫ﻧﻪ‬‫ﺗﻨﻬﺎ‬‫ﺑﻬﺘﺮ‬‫ﻧﻤﻴﺸﻮد‬‫ﺑﺪﺗﺮ‬‫ﻧﻴﺰ‬‫ﻣﻴﺸﻮد‬.‫دﻟﻴﻞ‬
‫اﻳﻦ‬‫ﻣﻮﺿﻮع‬‫اﻳﻦ‬‫اﺳﺖ‬‫ﻛﻪ‬‫اﻧﺘﺨﺎب‬‫ﺗﻮاﺑﻊ‬‫ﭘﺎﻳﻪ‬‫ﺑﻪ‬‫ﻧﻮع‬‫رﻓﺮﻧﺲ‬‫ﻣﺎ‬‫واﺑﺴﺘﻪ‬‫ﻣﻴﺒﺎﺷﺪ‬‫و‬‫در‬‫اﻳﻨﺠﺎ‬‫ﭼﻮن‬‫ازﻧﻮع‬‫ﭘﻠﻪ‬‫اﺳﺖ‬
‫اﺳﺖ‬ ‫ﺑﻬﺘﺮ‬‫از‬‫ﺗﻮاﺑﻊ‬‫ﭘﺎﻳﻪ‬‫ﭘﻠﻪ‬‫ﻳﺎ‬‫درﺟﻪ‬‫ﻳﻚ‬‫اﻧﺘﺨﺎب‬‫ﻛﻨﻴﻢ‬.‫ﻣﺎﻧﻨﺪ‬‫روﺷﻬﺎي‬‫ﻗﺒﻠﻲ‬‫ﺣﺎل‬‫درﺟﻪ‬‫ﺗﻮاﺑﻊ‬‫ﭘﺎﻳﻪ‬‫را‬0‫درﻧﻈﺮ‬
‫ﮔﺮﻓﺘﻪ‬‫و‬‫اﻓﻖ‬‫ﭘﻴﺶ‬‫ﺑﻴﻦ‬‫را‬‫اﻓﺰاﻳﺶ‬30	‫و‬‫ﻛﺎﻫﺶ‬(3)‫ﻣﻴﺪﻫﻴﻢ‬.‫ﻣﺸﺎﻫﺪه‬‫ﻣﻴﺸﻮد‬‫ﻛﻪ‬‫ﺟﻮاب‬‫ﺑﺪﺗﺮ‬‫ﻣﻴﺸﻮد‬‫ﭼﻮن‬‫در‬
‫ﻫﺮ‬‫ﮔﺎم‬‫ﻣﺎ‬‫ﺗﻌﺪاد‬‫زﻳﺎدي‬)‫ﺗﻌﺪاد‬‫ﻛﻤﻲ‬(‫از‬‫ﺧﺮوﺟﻲ‬‫ﭘﻴﺸﺒﻴﻨﻲ‬ ‫را‬‫ﻛﺮدﻫﺎﻳﻢ‬‫و‬‫ﺑﺮاﺳﺎس‬‫آن‬‫ورودي‬‫را‬‫ﺑﺪﺳﺖ‬
‫آوردﻫﺎﻳﻢ‬‫ﻛﻪ‬‫داراي‬‫اﻃﻼﻋﺎت‬‫ﻧﺎدرﺳﺖ‬‫و‬‫ﻳﺎ‬‫ﻧﺎﻗﺼﻲ‬‫ﻣﻴﺒﺎﺷﺪ‬‫و‬‫اﻧﺘﺨﺎب‬ ‫ﺧﻮﺑﻲ‬ ‫و‬ ‫ﻣﺸﺨﺼﻲ‬ ‫ي‬ ‫ﻣﺤﺪوده‬ ‫ﻳﻚ‬ ‫در‬ ‫ﺑﺎﻳﺪ‬
‫ﺷﻮد‬.
‫ﻣﺘﻠﺐ‬ ‫ﻛﺪ‬
1,7)
g(1)=0;
g(2)=0;
g(3)=0.271;
for j=4:120
g(j)=.8351*g(j-1)+0.2713;
end
8,13)
for i=1:p
for j=1:i
Gp(i,j)=g(i-j+1);
end
end
G=Gp(:,1:m);
14)
for i=1:30
for j=1:p
Gn(j,i)=g(j+i)-g(i) ;
end
end
w(1)=ym;
for k=1:10
f(k,:)=ym+Gn(k,:)*Un
if(t<period) alfa=0;
elseif (t>period && t<2*period) alfa=0.7;
elseif(t>2*period && t<3*period) alfa=0;
else alfa=0.7;
end
if t<61
landa=1
else landa=0.1
end
w(k+1,1)=alfa*w(k,1)+(1-alfa)*r(t+k,1);
end
delta_U=inv(G'*G+landa*eye(5,5))*G'*(w(2:11)-f);
U=delta_U(1,1)+u(1,1);
u(2:121,1)=u(1:120,1);
u(1,1)=U;
up(t)=U;
Un=[u(1,:)-u(2,:);Un(1:29,:)]
clc
clear all
close all
p=10;
m=5;
Nsim=120;
period = 30;
r=[ones(1,period),zeros(1,period),ones(1,period),zeros(
1,period),ones(1,10)]';
%%%Step Response
g(1)=0;
g(2)=0;
g(3)=0.271;
for j=4:120
g(j)=.8351*g(j-1)+0.2713;
end
figure(1)
plot (g)
title ('step response of system')
grid
for i=1:p
for j=1:i
Gp(i,j)=g(i-j+1);
end
end
G=Gp(:,1:m)
Gn=zeros (p,30);
for i=1:30
for j=1:p
Gn(j,i)=g(j+i)-g(i) ;
end
end
%%% Product F
u(1,1)=0;
u(2,1)=0;
u=zeros(120,1);
Un=zeros(30,1);
y_m0=0;
for t=1:120
ym=.8351*y_m0+0.2713*u(3,1);
w(1)=ym;
for k=1:10
f(k,:)=ym+Gn(k,:)*Un
if(t<period) alfa=0;
elseif (t>period && t<2*period) alfa=0.7;
elseif(t>2*period && t<3*period) alfa=0;
else alfa=0.7;
end
if t<61
landa=1
else landa=0.1
end
w(k+1,1)=alfa*w(k,1)+(1-alfa)*r(t+k,1);
end
delta_U=inv(G'*G+landa*eye(5,5))*G'*(w(2:11)-f);
U=delta_U(1,1)+u(1,1);
u(2:121,1)=u(1:120,1);
u(1,1)=U;
up(t)=U;
Un=[u(1,:)-u(2,:);Un(1:29,:)]
y_m0=ym;
y(t)=ym;
w=zeros(10,1);
end
15,18)
d(1)=0;d(2)=0;d(3)=0.05;
for j=4:129
d(j)=0.9*d(j-1)+0.05;
end
clc
clear all
close all
p=10;
m=5;
Nsim=120;
period = 30;
r=[ones(1,period),zeros(1,period),ones(1,period),zeros(
1,period),ones(1,10)]'
r=[ones(1,130)]';
dis=[zeros(1,20), 2*ones(1,40), zeros(1,60)]';
diss=[zeros(1,20),2,zeros(1,38),-2,zeros(1,70)]';
%%%Step Response
g(1)=0;
g(2)=0;
g(3)=0.271;
for j=4:120
g(j)=.8351*g(j-1)+0.2713;
end
figure(1)
plot (g)
title ('step response of system')
grid
for i=1:p
for j=1:i
Gp(i,j)=g(i-j+1);
end
end
G=Gp(:,1:m)
Gn=zeros (p,30);
for i=1:30
for j=1:p
Gn(j,i)=g(j+i)-g(i) ;
end
end
diss=.02*diss;d(1)=0;d(2)=0;d(3)=0.05;
for j=4:129
d(j)=0.9*d(j-1)+0.05;
end
%%% Product F
u(1,1)=0;
u(2,1)=0;
u=zeros(120,1);
Un=zeros(30,1);
y_m0=0;
y_dis0=0;
for t=4:120
ym=.8351*y_m0+0.2713*u(3,1);
y_dis=0.9*y_dis0+0.05*diss(t);
ym=ym+y_dis;
w(1)=ym;
% for i=1:10
% D(i,1)=dis(t+i)
% end
DD=zeros(p,1);
for k=1:10
DD(k,:)=0;
for i=1:30
if t+k>i
DD(k,:)=DD(k,:)+d(i)* diss(t+k-i)
else
DD(k,:)=DD(k,:);
end
end
f(k,:)=ym+Gn(k,:)*Un+DD(k,:);
if(t<period) alfa=0;
elseif (t>period && t<2*period) alfa=0;
elseif(t>2*period && t<3*period) alfa=0;
else alfa=0;
end
if t<61
landa=1;
else landa=0.1;
end
landa=1;
w(k+1,1)=alfa*w(k,1)+(1-alfa)*r(t+k,1);
end
delta_U=inv(G'*G+landa*eye(5,5))*G'*(w(2:11)-f);
U=delta_U(1,1)+u(1,1);
u(2:121,1)=u(1:120,1);
u(1,1)=U;
up(t)=U;
Un=[u(1,:)-u(2,:);Un(1:29,:)];
y_m0=ym;
y_dis0=y_dis;
y(t)=ym;
w=zeros(10,1);
end
19)
for i=1:30
h(i)=g(i+1)-g(i);
end
for i=1:P
for j=1:i
h1(i,j)=h(i-j+1);
end
end
for i=1:M
for j=i:N-1
h2(i,j)=h(N-(j-i))
end
end

More Related Content

More from Pourya Parsa

Matlab code for An overview of solar photovoltaic panel modeling based on ana...
Matlab code for An overview of solar photovoltaic panel modeling based on ana...Matlab code for An overview of solar photovoltaic panel modeling based on ana...
Matlab code for An overview of solar photovoltaic panel modeling based on ana...Pourya Parsa
 
digital control system Final exam
digital control system Final exam digital control system Final exam
digital control system Final exam Pourya Parsa
 
Non linear final solution1 94
Non linear final solution1 94Non linear final solution1 94
Non linear final solution1 94Pourya Parsa
 
Least squares based iterative identification for a class of multirate systems
Least squares based iterative identification for a class of multirate systemsLeast squares based iterative identification for a class of multirate systems
Least squares based iterative identification for a class of multirate systemsPourya Parsa
 
Identification of linear dynamic systems operating in a networked environment
Identification of linear dynamic systems operating in a networked environment Identification of linear dynamic systems operating in a networked environment
Identification of linear dynamic systems operating in a networked environment Pourya Parsa
 
جزوه کنترل پیش بین دکتر رمضانی
جزوه کنترل پیش بین دکتر رمضانیجزوه کنترل پیش بین دکتر رمضانی
جزوه کنترل پیش بین دکتر رمضانیPourya Parsa
 
نمونه سوالات و پاسخ کنترل مدرن
نمونه سوالات و پاسخ کنترل مدرننمونه سوالات و پاسخ کنترل مدرن
نمونه سوالات و پاسخ کنترل مدرنPourya Parsa
 
Hybrid Adaptive Control for Aerial Manipulation
Hybrid Adaptive Control for Aerial ManipulationHybrid Adaptive Control for Aerial Manipulation
Hybrid Adaptive Control for Aerial ManipulationPourya Parsa
 
Modern control system
Modern control systemModern control system
Modern control systemPourya Parsa
 

More from Pourya Parsa (12)

Matlab code for An overview of solar photovoltaic panel modeling based on ana...
Matlab code for An overview of solar photovoltaic panel modeling based on ana...Matlab code for An overview of solar photovoltaic panel modeling based on ana...
Matlab code for An overview of solar photovoltaic panel modeling based on ana...
 
digital control system Final exam
digital control system Final exam digital control system Final exam
digital control system Final exam
 
Non linear final solution1 94
Non linear final solution1 94Non linear final solution1 94
Non linear final solution1 94
 
Least squares based iterative identification for a class of multirate systems
Least squares based iterative identification for a class of multirate systemsLeast squares based iterative identification for a class of multirate systems
Least squares based iterative identification for a class of multirate systems
 
Identification of linear dynamic systems operating in a networked environment
Identification of linear dynamic systems operating in a networked environment Identification of linear dynamic systems operating in a networked environment
Identification of linear dynamic systems operating in a networked environment
 
جزوه کنترل پیش بین دکتر رمضانی
جزوه کنترل پیش بین دکتر رمضانیجزوه کنترل پیش بین دکتر رمضانی
جزوه کنترل پیش بین دکتر رمضانی
 
Solution modern
Solution modernSolution modern
Solution modern
 
نمونه سوالات و پاسخ کنترل مدرن
نمونه سوالات و پاسخ کنترل مدرننمونه سوالات و پاسخ کنترل مدرن
نمونه سوالات و پاسخ کنترل مدرن
 
Hybrid Adaptive Control for Aerial Manipulation
Hybrid Adaptive Control for Aerial ManipulationHybrid Adaptive Control for Aerial Manipulation
Hybrid Adaptive Control for Aerial Manipulation
 
انرژی
انرژیانرژی
انرژی
 
Modern control system
Modern control systemModern control system
Modern control system
 
Chaos control
Chaos controlChaos control
Chaos control
 

شبيه سازي کنترل پيش بين

  • 1. ‫ﭘﺎرﺳﺎ‬ ‫ﭘﻮرﻳﺎ‬ ‫سازی‬ ‫شبيه‬ ‫کدھای‬ ‫و‬ ‫تحليل‬ ‫اول‬ ‫سری‬ ‫تمرين‬ ‫ﺳﺎزي‬ ‫ﺷﺒﻴﻪ‬ ‫ﻛﻤﻚ‬ ‫ﺑﺎ‬ ‫اول‬ ‫ﺗﻤﺮﻳﻦ‬ ‫ﺣﻞ‬ ‫ﺗﺤﻠﻴﻞ‬matlab 1-‫در‬‫ﻣﺪل‬DMC‫ﻣﺪل‬ ‫از‬‫ﭘﺎﺳﺦ‬‫ﭘﻠﻪ‬‫ﺳﻴﺴﺘﻢ‬‫اﺳﺘﻔﺎده‬‫ﻣﻴﻜﻨﻴﻢ‬. 2-‫ﻓﺮض‬ ‫ﺑﺎ‬‫ﺑﻪ‬‫ﺗﺎﺑﻊ‬‫ﺗﺒﺪﻳﻞ‬‫ﺳﻴﺴﺘﻢ‬‫ﺳﻮال‬‫ﻛﻤﻚ‬ ‫ﺑﺎ‬ ‫و‬‫از‬‫ﻫﺎي‬ ‫ﻛﺪ‬‫ﺳﺎزي‬ ‫ﺷﺒﻴﻪ‬ ‫اول‬ ‫ﻗﺴﻤﺖ‬‫ﺑﻪ‬‫ﻧﺘﺎﻳﺠﻲ‬ ‫ﺧﻮاﻫﻴﻢ‬‫رﺳﻴ‬‫ﺪ‬. 3-‫ﭘﻠﻪ‬ ‫ﭘﺎﺳﺦ‬ ‫ﺳﭙﺲ‬‫زﻣﺎن‬ ‫ﮔﺬﺷﺖ‬ ‫از‬ ‫ﺑﻌﺪ‬ ‫ﺳﻴﺴﺘﻢ‬ ‫دﻫﺪ‬ ‫ﻣﻲ‬ ‫ﻧﺸﺎن‬ ‫ﻛﻪ‬ ‫ﻛﻨﻴﻢ‬ ‫ﻣﻲ‬ ‫راﺑﺮرﺳﻲ‬26‫ﺑﻪ‬ ‫ﺛﺎﻧﻴﻪ‬ ‫رﺳﺪ‬ ‫ﻣﻲ‬ ‫ﺧﻮد‬ ‫ﻧﻬﺎﻳﻲ‬ ‫ﻣﻘﺪار‬. 4-‫آورﻳﻢ‬ ‫ﻣﻲ‬ ‫ﺑﺪﺳﺖ‬ ‫را‬ ‫ﺷﺪه‬ ‫ﺧﻮاﺳﺘﻪ‬ ‫ﻫﺎي‬ ‫ﻟﺤﻈﻪ‬ ‫در‬ ‫ﻣﻘﺪار‬ ‫ﻣﺮﺑﻮﻃﻪ‬ ‫ﻫﺎي‬ ‫ﻓﺮﻣﻮل‬ ‫و‬ ‫رواﺑﻂ‬ ‫ﺑﻪ‬ ‫ﺗﻮﺟﻪ‬ ‫ﺑﺎ‬ )‫ﻟﺤﻈﻪ‬t‫و‬k( 5- ŷ(t+k⊥t)=Σgiki=1Δu(t+k+i)+ym(t)+Σ(gi+kNi=1−gi)Δu(t−i) 6-‫ﻣﺮ‬ ‫ﺳﻮال‬ ‫اول‬ ‫ﻗﺴﻤﺖ‬‫ﺣﺎل‬ ‫ورودي‬ ‫ﺑﻪ‬ ‫ﺑﻮط‬‫و‬ ‫زﻣﺎن‬ ‫ﻫﻤﺎن‬ ‫در‬ ‫ﺳﻴﺴﺘﻢ‬ ‫ﺧﺮوﺟﻲ‬ ‫ﺑﻪ‬ ‫ﻣﺮﺑﻮط‬ ‫دوم‬ ‫ﻗﺴﻤﺖ‬ ‫و‬ ‫ﺑﺎﺷﺪ‬ ‫ﻣﻲ‬ ‫ﺧﺎرج‬ ‫ﻣﺎ‬ ‫ﻛﻨﺘﺮل‬ ‫از‬ ‫ﭼﻮن‬ ‫ﺑﺎﺷﺪ‬ ‫ﻧﻤﻲ‬ ‫ﺑﺎزﻧﻮﻳﺴﻲ‬ ‫ﻗﺎﺑﻞ‬ ‫ﻛﻪ‬ ‫ﺑﺎﺷﺪ‬ ‫ﻣﻲ‬ ‫ﻗﺒﻞ‬ ‫ﻫﺎي‬ ‫زﻣﺎن‬. 7-‫ﻣﻴﮕﻴﺮﻳﻢ‬ ‫ﻛﻤﻚ‬ ‫ﻣﺎﺗﺮﻳﺲ‬ ‫از‬ ‫ﺑﺎﻻ‬ ‫ﺗﻮﺿﻴﺢ‬ ‫ﺑﻴﺸﺘﺮ‬ ‫درك‬ ‫ﺑﺮاي‬ 8-‫ﻛﻪ‬ ‫ﻣﺴﺌﻠﻪ‬ ‫ﻓﺮض‬ ‫ﺑﻪ‬ ‫ﺗﻮﺟﻪ‬ ‫ﺑﺎ‬N , p ,m‫ﺗﺮﺗﻴﺐ‬ ‫ﺑﻪ‬5‫و‬10‫و‬30‫ﺑﺎﺷﺪ‬ ‫ﻣﻲ‬.‫ﺑﻴﻦ‬ ‫ﭘﻴﺶ‬ ‫ﻛﻨﺘﺮل‬ ‫در‬ ‫ﻟﺤﻈﻪ‬t‫ﻛﻨﻴﻢ‬ ‫ﻣﻲ‬ ‫ﻣﺤﺎﺳﺒﻪ‬ ‫را‬ 9-‫ﻣﺎﺗﺮﻳﺲ‬ ‫ﭘﻠﻪ‬ ‫ﭘﺎﺳﺦ‬ ‫ﻃﺒﻖ‬ ‫ﺑﺮ‬ ‫ﺑﻴﻦ‬ ‫ﭘﻴﺶ‬ ‫ﻛﻨﺘﺮل‬ ‫در‬ ‫ﺳﭙﺲ‬G‫دﻫﻴﻢ‬ ‫ﻣﻲ‬ ‫ﺗﺸﻜﻴﻞ‬ ‫را‬. 10-‫ﻣﺎﺗﺮﻳﺲ‬ ‫ﻛﺪ‬G‫ﻣﺎﺗﺮﻳﺲ‬ ‫ﻫﻢ‬ ‫ﻣﺮﺑﻌﻲ‬ ‫ﻣﺎﺗﺮﻳﺲ‬ ‫از‬ ‫ﺗﻮاﻧﻴﻢ‬ ‫ﻣﻲ‬ ‫ﻫﻤﭽﻨﻴﻦ‬ ‫ﻧﻮﻳﺴﻴﻢ‬ ‫ﻣﻲ‬ ‫را‬G‫ﺑﺪﺳﺖ‬ ‫را‬ ‫آورﻳﻢ‬. 11-‫ﻛﻨﻴﻢ‬ ‫ﻣﻲ‬ ‫ﺣﺴﺎب‬ ‫را‬ ‫آﻳﻨﺪه‬ ‫ﻫﺎي‬ ‫ورودي‬ 12-‫آورﻳﻢ‬ ‫ﻣﻲ‬ ‫ﺑﺪﺳﺖ‬ ‫را‬ ‫ﺧﺮوﺟﻲ‬ ‫و‬ ‫را‬ ‫ﺟﺪﻳﺪ‬ ‫ﻫﺎي‬ ‫ورودي‬ ‫ﻣﻴﻜﻨﻴﻢ‬ ‫وارد‬ ‫ﺳﻴﺴﺘﻢ‬ ‫ﺑﻪ‬. 13-‫ﻣﺎﺗﺮﻳﺲ‬ ‫ﺳﭙﺲ‬Gn‫دﻫﻴﻢ‬ ‫ﻣﻲ‬ ‫ﺗﺸﻜﻴﻞ‬ ‫را‬. 14-‫ﻟﺤﻈﻪ‬ ‫در‬t‫ﺑﺮدار‬ ‫ﻣﺎﺗﺮﻳﺲ‬ ‫اﻳﻦ‬ ‫ﻛﻤﻚ‬ ‫ﺑﺎ‬f‫ﺷﻮد‬ ‫ﻣﻲ‬ ‫ﻣﺤﺎﺳﺒﻪ‬. 15-‫ﺑﺮاي‬‫ﺗﺤﻠﻴﻞ‬‫ﺟﻮاب‬‫در‬‫اﺑﺘﺪا‬‫اﻓﻖ‬‫ﭘﻴﺶ‬‫ﺑﻴﻨﻲ‬10‫ﺗﻌﺪاد‬‫ﻧﻤﻮﻧﻪ‬‫ﻫﺎ‬30‫و‬‫اﻓﻖ‬‫ﻛﻨﺘﺮل‬‫را‬5‫ﮔﺮﻓﺘﻪ‬‫و‬ ‫ﻣﻴﻜﻨﻴﻢ‬ ‫ﻧﮕﺎه‬ ‫را‬ ‫ﻧﺘﻴﺠﻪ‬. 16-‫در‬‫اﺑﺘﺪا‬‫ﺗﻌﺪاد‬‫ﻧﻤﻮﻧﻪ‬‫ﻫﺎي‬‫ﭘﺎﺳﺦ‬‫ﭘﻠﻪ‬‫را‬‫از‬30‫ﺑﻪ‬40‫اﻓﺰاﻳﺶ‬‫ﻣﻴﺪﻫﻴﻢ‬‫ﺗﻔﺎوت‬‫زﻳﺎدي‬‫ﺣﺎﺻﻞ‬‫ﻧﻤﻴﺸﻮد‬
  • 2. ‫ﻧﻤﻮﻧﻪ‬ ‫از‬ ‫ﺑﻌﺪ‬ ‫ﭼﻮن‬30‫اﺧﺘﻼف‬‫ﺑﻴﻦ‬‫ﺟﻮاﺑﻬﺎي‬‫ﭘﺎﺳﺦ‬‫ﭘﻠﻪ‬‫ﻛﻤﺘﺮ‬‫از‬0,003‫ﻣﻴﺒﺎﺷﺪ‬.‫ﻓﻘﻂ‬‫در‬‫ﺣﺎﻟﺖ‬‫ﻛﻠﻲ‬ ‫ﺑﺎ‬‫اﻓﺰاﻳﺶ‬‫ﺗﻌﺪاد‬‫ﻫﺎﺣﺠﻢ‬ ‫ﻧﻤﻮﻧﻪ‬‫ﻣﺤﺎﺳﺒﺎت‬‫ﺑﺎﻻ‬‫ﻣﻴﺮود‬‫وﻟﻲ‬‫از‬‫اورﺷﻮت‬‫زدن‬‫ﺳﻴﺴﺘﻢ‬‫ﺟﻠﻮﮔﻴﺮي‬‫ﻣﻴﻜﻨﺪ‬. 17-‫اﻓﻖ‬‫ﭘﻴﺶ‬‫ﺑﻴﻨﻲ‬‫را‬‫اﻓﺰاﻳﺶ‬‫داده‬‫و‬‫ﻣﺸﺎﻫﺪه‬‫ﻣﻴﺸﻮد‬‫ﻛﻪ‬‫ﺑﺎ‬‫اﻓﺰاﻳﺶ‬‫اﻓﻖ‬‫ﭘﻴﺶ‬‫ﺑﻴﻨﻲ‬‫ﭼﻮن‬‫در‬‫ﻫﺮ‬ ‫ﺧﺮوﺟﻴﻬﺎي‬ ‫ﻣﺮﺣﻠﻪ‬‫ﺑﻴﺸﺘﺮي‬‫را‬‫ﺗﺨﻤﻴﻦ‬‫زدﻫﺎﻳﻢ‬‫ﻛﻪ‬‫ﺷﺎﻳﺪ‬‫داراي‬‫اﻃﻼﻋﺎت‬‫ﻧﺎدرﺳﺘﻲ‬‫ﺑﺎﺷﻨﺪ‬‫ورودي‬‫اﻳﻦ‬‫ﻟﺤﻈﻪ‬ ‫ﺑﺮاي‬‫ﺟﻮاب‬ ‫داﺷﺘﻦ‬‫ﻣﻄﻠﻮب‬‫ﺑﺮاي‬‫داﺷﺘﻦ‬‫ﻋﻜﺲ‬‫اﻟﻌﻤﻞ‬‫ﻣﻨﺎﺳﺐ‬‫در‬‫ﺧﺮوﺟﻲ‬‫ﻫﺎي‬‫آﻳﻨﺪه‬‫ﻣﻴﺒﺎﺷﺪ‬‫در‬‫ﻧﺘﻴﺠﻪ‬‫ﻣﻘﺪار‬ ‫ﺳﻴﮕﻨﺎل‬‫اﻓﺰاﻳﺶ‬ ‫ﻛﻨﺘﺮﻟﻲ‬‫ﻳﺎﻓﺘﻪ‬‫و‬‫اﮔﺮ‬‫اﻳﻦ‬‫اﻓﻖ‬‫ﺑﻴﺸﺘﺮ‬‫اﻓﺰاﻳﺶ‬‫ﻳﺎﺑﺪ‬‫ﻣﻨﺠﺮ‬‫ﺑﻪ‬‫ﻧﺎﭘﺎﻳﺪاري‬‫ﺳﻴﺴﺘﻢ‬‫ﻧﻴﺰ‬‫ﻣﻴﺸﻮد‬. 18-‫ورﻳﻢ‬Ĥ‫ﻣﻴ‬ ‫ﺑﺪﺳﺖ‬ ‫را‬ ‫ﺳﻴﺴﺘﻢ‬ ‫اﻏﺘﺸﺎش‬. 19-‫ﻗﺴﻤﺖ‬ ‫ﺧﺮوﺟﻲ‬MAC‫راﺑﻄﻪ‬ ‫ﻛﻤﻚ‬ ‫ﺑﺎ‬ ‫آورﻳﻢ‬ ‫ﻣﻲ‬ ‫ﺑﺪﺳﺖ‬ ‫را‬‫ݕ‬ = ‫ܪ‬1ܷ+ + ‫ܪ‬2ܷ− + ݊ 20-U+‫ﻛﻨﻴﻢ‬ ‫ﻣﻲ‬ ‫ﻣﺤﺎﺳﺒﻪ‬ ‫ﺳﺎزي‬ ‫ﺑﻬﻴﻨﻪ‬ ‫ﻃﺮﻳﻖ‬ ‫از‬ ‫را‬ 21-‫ﻫﺎي‬ ‫ﻣﺎﺗﺮﻳﺲ‬H1 H2‫را‬‫از‬ ‫اﻃﻼع‬ ‫ﺑﺎ‬p=3 , m=5‫ﻣﻴﻜﻨﻴﻢ‬ ‫درﺳﺖ‬. 22-‫ﺗﺎ‬ ‫را‬ ‫ﻛﻨﺘﺮل‬ ‫اﻓﻖ‬m=10‫ﻛﻨﻴﻢ‬ ‫ﻣﻲ‬ ‫زﻳﺎد‬. 23-‫ﻫﺰﻳﻨﻪ‬ ‫ﺗﺎﺑﻊ‬ ‫در‬ ‫را‬ ‫ورودي‬ ‫وزن‬10‫ﻛﻨﻴﻢ‬ ‫ﻣﻲ‬ ‫ﺑﺮاﺑﺮ‬. 24-‫دﻫﻴﻢ‬ ‫ﻣﻲ‬ ‫اﻓﺰاﻳﺶ‬ ‫را‬ ‫ﭘﻴﺶ‬ ‫اﻓﻖ‬. ‫ﺳﺎزي‬ ‫ﺷﺒﻴﻪ‬ ‫ﺗﺤﻠﻴﻞ‬ ‫ﻧﻬﺎﻳﻲ‬ ‫ﻧﺘﻴﺠﻪ‬ ‫ﺑﺮاي‬‫اﻳﻨﻜﻪ‬‫ﺗﺤﻠﻴﻞ‬‫درﺟﻪ‬‫ﺗﻮاﺑﻊ‬‫ﭘﺎﻳﻪ‬‫را‬‫ﺑﻔﻬﻤﻴﻢ‬‫ورودي‬‫ﺳﻴﺴﺘﻢ‬‫را‬‫ﺑﻪ‬‫ﺻﻮرت‬‫ﻫﺎي‬ ‫ﭘﻠﻪ‬‫ﻣﺨﺘﻠﻒ‬‫اﻳﺠﺎد‬‫ﻣﻴﻜﻨﻴﻢ‬ ‫ﻣﺸﺎﻫﺪه‬‫ﻣﻴﺸﻮد‬‫ﻫﺮﭼﻪ‬‫درﺟﻪ‬‫ﺗﻮاﺑﻊ‬‫ﭘﺎﻳﻪ‬‫را‬‫اﻓﺰاﻳﺶ‬‫دﻫﻴﻢ‬‫ﺟﻮاب‬‫ﻧﻪ‬‫ﺗﻨﻬﺎ‬‫ﺑﻬﺘﺮ‬‫ﻧﻤﻴﺸﻮد‬‫ﺑﺪﺗﺮ‬‫ﻧﻴﺰ‬‫ﻣﻴﺸﻮد‬.‫دﻟﻴﻞ‬ ‫اﻳﻦ‬‫ﻣﻮﺿﻮع‬‫اﻳﻦ‬‫اﺳﺖ‬‫ﻛﻪ‬‫اﻧﺘﺨﺎب‬‫ﺗﻮاﺑﻊ‬‫ﭘﺎﻳﻪ‬‫ﺑﻪ‬‫ﻧﻮع‬‫رﻓﺮﻧﺲ‬‫ﻣﺎ‬‫واﺑﺴﺘﻪ‬‫ﻣﻴﺒﺎﺷﺪ‬‫و‬‫در‬‫اﻳﻨﺠﺎ‬‫ﭼﻮن‬‫ازﻧﻮع‬‫ﭘﻠﻪ‬‫اﺳﺖ‬ ‫اﺳﺖ‬ ‫ﺑﻬﺘﺮ‬‫از‬‫ﺗﻮاﺑﻊ‬‫ﭘﺎﻳﻪ‬‫ﭘﻠﻪ‬‫ﻳﺎ‬‫درﺟﻪ‬‫ﻳﻚ‬‫اﻧﺘﺨﺎب‬‫ﻛﻨﻴﻢ‬.‫ﻣﺎﻧﻨﺪ‬‫روﺷﻬﺎي‬‫ﻗﺒﻠﻲ‬‫ﺣﺎل‬‫درﺟﻪ‬‫ﺗﻮاﺑﻊ‬‫ﭘﺎﻳﻪ‬‫را‬0‫درﻧﻈﺮ‬ ‫ﮔﺮﻓﺘﻪ‬‫و‬‫اﻓﻖ‬‫ﭘﻴﺶ‬‫ﺑﻴﻦ‬‫را‬‫اﻓﺰاﻳﺶ‬30 ‫و‬‫ﻛﺎﻫﺶ‬(3)‫ﻣﻴﺪﻫﻴﻢ‬.‫ﻣﺸﺎﻫﺪه‬‫ﻣﻴﺸﻮد‬‫ﻛﻪ‬‫ﺟﻮاب‬‫ﺑﺪﺗﺮ‬‫ﻣﻴﺸﻮد‬‫ﭼﻮن‬‫در‬ ‫ﻫﺮ‬‫ﮔﺎم‬‫ﻣﺎ‬‫ﺗﻌﺪاد‬‫زﻳﺎدي‬)‫ﺗﻌﺪاد‬‫ﻛﻤﻲ‬(‫از‬‫ﺧﺮوﺟﻲ‬‫ﭘﻴﺸﺒﻴﻨﻲ‬ ‫را‬‫ﻛﺮدﻫﺎﻳﻢ‬‫و‬‫ﺑﺮاﺳﺎس‬‫آن‬‫ورودي‬‫را‬‫ﺑﺪﺳﺖ‬ ‫آوردﻫﺎﻳﻢ‬‫ﻛﻪ‬‫داراي‬‫اﻃﻼﻋﺎت‬‫ﻧﺎدرﺳﺖ‬‫و‬‫ﻳﺎ‬‫ﻧﺎﻗﺼﻲ‬‫ﻣﻴﺒﺎﺷﺪ‬‫و‬‫اﻧﺘﺨﺎب‬ ‫ﺧﻮﺑﻲ‬ ‫و‬ ‫ﻣﺸﺨﺼﻲ‬ ‫ي‬ ‫ﻣﺤﺪوده‬ ‫ﻳﻚ‬ ‫در‬ ‫ﺑﺎﻳﺪ‬ ‫ﺷﻮد‬. ‫ﻣﺘﻠﺐ‬ ‫ﻛﺪ‬ 1,7) g(1)=0; g(2)=0; g(3)=0.271; for j=4:120 g(j)=.8351*g(j-1)+0.2713;
  • 3. end 8,13) for i=1:p for j=1:i Gp(i,j)=g(i-j+1); end end G=Gp(:,1:m); 14) for i=1:30 for j=1:p Gn(j,i)=g(j+i)-g(i) ; end end w(1)=ym; for k=1:10 f(k,:)=ym+Gn(k,:)*Un if(t<period) alfa=0; elseif (t>period && t<2*period) alfa=0.7; elseif(t>2*period && t<3*period) alfa=0; else alfa=0.7; end if t<61 landa=1 else landa=0.1 end w(k+1,1)=alfa*w(k,1)+(1-alfa)*r(t+k,1);
  • 4. end delta_U=inv(G'*G+landa*eye(5,5))*G'*(w(2:11)-f); U=delta_U(1,1)+u(1,1); u(2:121,1)=u(1:120,1); u(1,1)=U; up(t)=U; Un=[u(1,:)-u(2,:);Un(1:29,:)] clc clear all close all p=10; m=5; Nsim=120; period = 30; r=[ones(1,period),zeros(1,period),ones(1,period),zeros( 1,period),ones(1,10)]'; %%%Step Response g(1)=0; g(2)=0; g(3)=0.271; for j=4:120 g(j)=.8351*g(j-1)+0.2713; end figure(1) plot (g) title ('step response of system') grid for i=1:p
  • 5. for j=1:i Gp(i,j)=g(i-j+1); end end G=Gp(:,1:m) Gn=zeros (p,30); for i=1:30 for j=1:p Gn(j,i)=g(j+i)-g(i) ; end end %%% Product F u(1,1)=0; u(2,1)=0; u=zeros(120,1); Un=zeros(30,1); y_m0=0; for t=1:120 ym=.8351*y_m0+0.2713*u(3,1); w(1)=ym; for k=1:10 f(k,:)=ym+Gn(k,:)*Un if(t<period) alfa=0; elseif (t>period && t<2*period) alfa=0.7; elseif(t>2*period && t<3*period) alfa=0; else alfa=0.7; end if t<61 landa=1 else landa=0.1
  • 7. diss=[zeros(1,20),2,zeros(1,38),-2,zeros(1,70)]'; %%%Step Response g(1)=0; g(2)=0; g(3)=0.271; for j=4:120 g(j)=.8351*g(j-1)+0.2713; end figure(1) plot (g) title ('step response of system') grid for i=1:p for j=1:i Gp(i,j)=g(i-j+1); end end G=Gp(:,1:m) Gn=zeros (p,30); for i=1:30 for j=1:p Gn(j,i)=g(j+i)-g(i) ; end end diss=.02*diss;d(1)=0;d(2)=0;d(3)=0.05; for j=4:129 d(j)=0.9*d(j-1)+0.05; end %%% Product F u(1,1)=0;
  • 8. u(2,1)=0; u=zeros(120,1); Un=zeros(30,1); y_m0=0; y_dis0=0; for t=4:120 ym=.8351*y_m0+0.2713*u(3,1); y_dis=0.9*y_dis0+0.05*diss(t); ym=ym+y_dis; w(1)=ym; % for i=1:10 % D(i,1)=dis(t+i) % end DD=zeros(p,1); for k=1:10 DD(k,:)=0; for i=1:30 if t+k>i DD(k,:)=DD(k,:)+d(i)* diss(t+k-i) else DD(k,:)=DD(k,:); end end f(k,:)=ym+Gn(k,:)*Un+DD(k,:); if(t<period) alfa=0; elseif (t>period && t<2*period) alfa=0; elseif(t>2*period && t<3*period) alfa=0; else alfa=0; end if t<61
  • 10. end