Ungdungdaoham ppt 1

1. © Mark E. Damon - All Rights Reserved
Welcome to
Who Wants to be a Millionaire

2. © Mark E. Damon - All Rights Reserved
15
14
13
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11
10
9
8
7
6
5
4
3
2
1
$1 Million
$500,000
$250,000
$125,000
$64,000
$32,000
$16,000
$8,000
$4,000
$2,000
$1,000
$500
$300
$200
$100
Câu hỏi ôn tập
ứng dụng của
đạo hàm
50:50
Người soạn: Nguyễn Anh Tuấn
Trường THPT Nguyễn Trãi- Hải Phòng

3. © Mark E. Damon - All Rights Reserved
15
14
13
12
11
10
9
8
7
6
5
4
3
2
1
$1 Million
$500,000
$250,000
$125,000
$64,000
$32,000
$16,000
$8,000
$4,000
$2,000
$1,000
$500
$300
$200
$100

4. © Mark E. Damon - All Rights Reserved
A: y’=0 trên (a;b)
C: y’<0 trên (a;b)
B: y’>0 trên (a;b)
D: y’ không xác
định trên (a;b)
50:50
15
14
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11
10
9
8
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6
5
4
3
2
1
$1 Million
$500,000
$250,000
$125,000
$64,000
$32,000
$16,000
$8,000
$4,000
$2,000
$1,000
$500
$300
$200
$100
Hàm số đồng biến
trên (a;b) nếu
1
2
3
y x= −

5. © Mark E. Damon - All Rights Reserved
15
14
13
12
11
10
9
8
7
6
5
4
3
2
1
$1 Million
$500,000
$250,000
$125,000
$64,000
$32,000
$16,000
$8,000
$4,000
$2,000
$1,000
$500
$300
$200
$100

6. © Mark E. Damon - All Rights Reserved
A: y’=0 trên (a;b)
C: y’<0 trên (a;b)
B: y’>0 trên (a;b)
D: y’’<0 trên (a;b)
50:50
15
14
13
12
11
10
9
8
7
6
5
4
3
2
1
$1 Million
$500,000
$250,000
$125,000
$64,000
$32,000
$16,000
$8,000
$4,000
$2,000
$1,000
$500
$300
$200
$100
Hàm số nghịch biến
trên (a;b) nếu

7. © Mark E. Damon - All Rights Reserved
15
14
13
12
11
10
9
8
7
6
5
4
3
2
1
$1 Million
$500,000
$250,000
$125,000
$64,000
$32,000
$16,000
$8,000
$4,000
$2,000
$1,000
$500
$300
$200
$100

8. © Mark E. Damon - All Rights Reserved
A: y’(a)=0
C: y’(a) không xác
định
B: y’(a)=0 hoặc
không xác định
D: y’’(a)=0
50:50
15
14
13
12
11
10
9
8
7
6
5
4
3
2
1
$1 Million
$500,000
$250,000
$125,000
$64,000
$32,000
$16,000
$8,000
$4,000
$2,000
$1,000
$500
$300
$200
$100
x=a là điểm tới hạn
của hàm số nếu

9. © Mark E. Damon - All Rights Reserved
15
14
13
12
11
10
9
8
7
6
5
4
3
2
1
$1 Million
$500,000
$250,000
$125,000
$64,000
$32,000
$16,000
$8,000
$4,000
$2,000
$1,000
$500
$300
$200
$100

10. © Mark E. Damon - All Rights Reserved
A:
C:
B:
D:
50:50
15
14
13
12
11
10
9
8
7
6
5
4
3
2
1
$1 Million
$500,000
$250,000
$125,000
$64,000
$32,000
$16,000
$8,000
$4,000
$2,000
$1,000
$500
$300
$200
$100
Tìm cực trị của hàm số
3 2
y 2x 3x 36x 10= + − −
CD CTy 71; y 54= = − CD CTy 71; y 54= − = −
CD CTy 71; y 54= = CD CTy 71; y 54= − =

11. © Mark E. Damon - All Rights Reserved
15
14
13
12
11
10
9
8
7
6
5
4
3
2
1
$1 Million
$500,000
$250,000
$125,000
$64,000
$32,000
$16,000
$8,000
$4,000
$2,000
$1,000
$500
$300
$200
$100

12. © Mark E. Damon - All Rights Reserved
A:
C:
B:
D:
50:50
15
14
13
12
11
10
9
8
7
6
5
4
3
2
1
$1 Million
$500,000
$250,000
$125,000
$64,000
$32,000
$16,000
$8,000
$4,000
$2,000
$1,000
$500
$300
$200
$100
Tìm các điểm cực trị
của hàm số sau
2
x 4x 5
y
x 2
+ +
=
+
CD CTx 3; x 1= − = −
CD CTx 3; x 1= = − CD CTx 3; x 1= − =
CD CTx 3; x 1= =

13. © Mark E. Damon - All Rights Reserved
Congratulations!
You’ve Reached
the $1,000
Milestone!
Congratulations!Congratulations!

14. © Mark E. Damon - All Rights Reserved
Welcome to
Who Wants to be a Millionaire

15. © Mark E. Damon - All Rights Reserved
15
14
13
12
11
10
9
8
7
6
5
4
3
2
1
$1 Million
$500,000
$250,000
$125,000
$64,000
$32,000
$16,000
$8,000
$4,000
$2,000
$1,000
$500
$300
$200
$100

16. © Mark E. Damon - All Rights Reserved
A: 1 cực đại và 2
cực tiểu
C: 1 cực đại và
không có cực tiểu
B: 1 cực tiểu và 2
cực đại
D:1 cực tiểu và 1
cực đại
50:50
15
14
13
12
11
10
9
8
7
6
5
4
3
2
1
$1 Million
$500,000
$250,000
$125,000
$64,000
$32,000
$16,000
$8,000
$4,000
$2,000
$1,000
$500
$300
$200
$100
Cho hàm số 4 21
y x 2x 1
4
= − +
Hàm số có:

17. © Mark E. Damon - All Rights Reserved
15
14
13
12
11
10
9
8
7
6
5
4
3
2
1
$1 Million
$500,000
$250,000
$125,000
$64,000
$32,000
$16,000
$8,000
$4,000
$2,000
$1,000
$500
$300
$200
$100

18. © Mark E. Damon - All Rights Reserved
A:
C:
B:
D:
50:50
15
14
13
12
11
10
9
8
7
6
5
4
3
2
1
$1 Million
$500,000
$250,000
$125,000
$64,000
$32,000
$16,000
$8,000
$4,000
$2,000
$1,000
$500
$300
$200
$100
hàm số
2
x
y
1 x
=
−
Đồng biến trên các khoảng
( ;1) và (1; )−∞ +∞(0;1) và (1;2)
( ;1) và (2; )−∞ +∞( ;1) và (1;2)−∞

19. © Mark E. Damon - All Rights Reserved
15
14
13
12
11
10
9
8
7
6
5
4
3
2
1
$1 Million
$500,000
$250,000
$125,000
$64,000
$32,000
$16,000
$8,000
$4,000
$2,000
$1,000
$500
$300
$200
$100

20. © Mark E. Damon - All Rights Reserved
A:-6
C: 0
B: -3
D: 3
50:50
15
14
13
12
11
10
9
8
7
6
5
4
3
2
1
$1 Million
$500,000
$250,000
$125,000
$64,000
$32,000
$16,000
$8,000
$4,000
$2,000
$1,000
$500
$300
$200
$100
Cho hàm số
3 2
y x 3x 1= − +
Tích các giá trị cực đại và
cực tiểu của hàm số bằng

21. © Mark E. Damon - All Rights Reserved
15
14
13
12
11
10
9
8
7
6
5
4
3
2
1
$1 Million
$500,000
$250,000
$125,000
$64,000
$32,000
$16,000
$8,000
$4,000
$2,000
$1,000
$500
$300
$200
$100

22. © Mark E. Damon - All Rights Reserved
toạ độ của
Các điểm cực trị của hàm số y=sin2x-x là
CD CTD: x k ; x k
6 3
π π
= + π = − + π
CD CTB: x k ; x k
6 3
π π
= − + π = − + π
CD CTA: x k ; x k
6 6
π π
= + π = − + π
CD CTC: x k ; x k
3 6
π π
= + π = − + π

23. © Mark E. Damon - All Rights Reserved
toạ độ của
Các điểm cực trị của hàm số y=sin2x-x là
CD CTD : x k ; x k
6 3
π π
= + π =− + π
CD CTB: x k ; x k
6 3
π π
= − + π = − + π
CD CTA : x k ; x k
6 6
π π
= + π = − + π
CD CTC: x k ; x k
3 6
π π
= + π = − + π

24. © Mark E. Damon - All Rights Reserved
15
14
13
12
11
10
9
8
7
6
5
4
3
2
1
$1 Million
$500,000
$250,000
$125,000
$64,000
$32,000
$16,000
$8,000
$4,000
$2,000
$1,000
$500
$300
$200
$100

25. © Mark E. Damon - All Rights Reserved
A:
C:
B:
D:
50:50
15
14
13
12
11
10
9
8
7
6
5
4
3
2
1
$1 Million
$500,000
$250,000
$125,000
$64,000
$32,000
$16,000
$8,000
$4,000
$2,000
$1,000
$500
$300
$200
$100
Phương trình đường thẳng
đi qua hai điểm cực trị của
hàm số trên là
Cho hàm số:
3 2
y x 3x 9x m= − − +
y 8x m 3= − − +y 8x m 3= − +
y 8x m 3= + −y 8x m 3= − + −

26. © Mark E. Damon - All Rights Reserved
A:
C:
B:
D:
50:50
15
14
13
12
11
10
9
8
7
6
5
4
3
2
1
$1 Million
$500,000
$250,000
$125,000
$64,000
$32,000
$16,000
$8,000
$4,000
$2,000
$1,000
$500
$300
$200
$100
Phương trình đường thẳng
đi qua hai điểm cực trị của
hàm số trên là
Cho hàm số:
3 2
y x 3x 9x m= − − +
y 8x m 3= − − +
y 8x m 3= − +
y 8x m 3= + −
y 8x m 3= − + −

27. © Mark E. Damon - All Rights Reserved
Congratulations!
You’ve Reached
the $32,000
Milestone!
Congratulations!Congratulations!

28. © Mark E. Damon - All Rights Reserved
Welcome to
Who Wants to be a Millionaire

29. © Mark E. Damon - All Rights Reserved
15
14
13
12
11
10
9
8
7
6
5
4
3
2
1
$1 Million
$500,000
$250,000
$125,000
$64,000
$32,000
$16,000
$8,000
$4,000
$2,000
$1,000
$500
$300
$200
$100

30. © Mark E. Damon - All Rights Reserved
50:50
15
14
13
12
11
10
9
8
7
6
5
4
3
2
1
$1 Million
$500,000
$250,000
$125,000
$64,000
$32,000
$16,000
$8,000
$4,000
$2,000
$1,000
$500
$300
$200
$100
Cho hàm số
Chọn đáp án đúng trong
4 đáp án sau
2 1
y sinx cos x
2
= + +
7
C. max y ;
4
=
3
D. min y ;
2
=
1
B. min y ;
2
=
3
A. max y ;
2
=

31. © Mark E. Damon - All Rights Reserved
50:50
15
14
13
12
11
10
9
8
7
6
5
4
3
2
1
$1 Million
$500,000
$250,000
$125,000
$64,000
$32,000
$16,000
$8,000
$4,000
$2,000
$1,000
$500
$300
$200
$100
Cho hàm số
Chọn đáp án đúng trong
4 đáp án sau
2 1
y sinx cos x
2
= + +
7
C. max y ;
4
=
3
D. min y ;
2
=
1
B. min y ;
2
=
3
A. max y ;
2
=

32. © Mark E. Damon - All Rights Reserved
15
14
13
12
11
10
9
8
7
6
5
4
3
2
1
$1 Million
$500,000
$250,000
$125,000
$64,000
$32,000
$16,000
$8,000
$4,000
$2,000
$1,000
$500
$300
$200
$100

33. © Mark E. Damon - All Rights Reserved
50:50
15
14
13
12
11
10
9
8
7
6
5
4
3
2
1
$1 Million
$500,000
$250,000
$125,000
$64,000
$32,000
$16,000
$8,000
$4,000
$2,000
$1,000
$500
$300
$200
$100
Tìm giá trị lớn nhất
của hàm số
4 2
y cos x sin x cosxsin x= + +
5
C.max y
4
=
5
D.max y
4
= −
9
B.max y
4
=1
A.max y
4
=

34. © Mark E. Damon - All Rights Reserved
50:50
15
14
13
12
11
10
9
8
7
6
5
4
3
2
1
$1 Million
$500,000
$250,000
$125,000
$64,000
$32,000
$16,000
$8,000
$4,000
$2,000
$1,000
$500
$300
$200
$100
Tìm giá trị lớn nhất
của hàm số
4 2
y cos x sin x cosxsin x= + +
5
C.max y
4
=
5
D.max y
4
= −
9
B.max y
4
=1
A.max y
4
=

35. © Mark E. Damon - All Rights Reserved
15
14
13
12
11
10
9
8
7
6
5
4
3
2
1
$1 Million
$500,000
$250,000
$125,000
$64,000
$32,000
$16,000
$8,000
$4,000
$2,000
$1,000
$500
$300
$200
$100

36. © Mark E. Damon - All Rights Reserved
50:50
15
14
13
12
11
10
9
8
7
6
5
4
3
2
1
$1 Million
$500,000
$250,000
$125,000
$64,000
$32,000
$16,000
$8,000
$4,000
$2,000
$1,000
$500
$300
$200
$100
Có nghiệm khi và chỉ khi
PT x 1 x 1 5 x 18 3x 2m 1+ + − − − − − = +
2 3 15 1 6 3
B. m
2 2
− − + −
≤ ≤
2 3 1 6
A. m
2 2
− +
≤ ≤
2 3 15 1 6 3
D. m
2 2
− − − + −
≤ ≤
3 15 6 3
C. m
2 2
− − −
≤ ≤

37. © Mark E. Damon - All Rights Reserved
50:50
15
14
13
12
11
10
9
8
7
6
5
4
3
2
1
$1 Million
$500,000
$250,000
$125,000
$64,000
$32,000
$16,000
$8,000
$4,000
$2,000
$1,000
$500
$300
$200
$100
Có nghiệm khi và chỉ khi
PT x 1 x 1 5 x 18 3x 2m 1+ + − − − − − = +
2 3 15 1 6 3
B. m
2 2
− − + −
≤ ≤
2 3 1 6
A. m
2 2
− +
≤ ≤
2 3 15 1 6 3
D. m
2 2
− − − + −
≤ ≤
3 15 6 3
C. m
2 2
− − −
≤ ≤

38. © Mark E. Damon - All Rights Reserved
15
14
13
12
11
10
9
8
7
6
5
4
3
2
1
$1 Million
$500,000
$250,000
$125,000
$64,000
$32,000
$16,000
$8,000
$4,000
$2,000
$1,000
$500
$300
$200
$100

39. © Mark E. Damon - All Rights Reserved
50:50
15
14
13
12
11
10
9
8
7
6
5
4
3
2
1
$1 Million
$500,000
$250,000
$125,000
$64,000
$32,000
$16,000
$8,000
$4,000
$2,000
$1,000
$500
$300
$200
$100
PT x 3 6 x (x 3)(6 x) m+ + − − + − =
Có nghiệm khi và chỉ khi
6 2 9
A. m 3
2
−
≤ ≤
6 2 9
B. m 3
2
− −
≤ ≤
6 2 9
D. m 3
2
−
≤ ≤
6 2 11
C. m 3
2
−
≤ ≤

40. © Mark E. Damon - All Rights Reserved
50:50
15
14
13
12
11
10
9
8
7
6
5
4
3
2
1
$1 Million
$500,000
$250,000
$125,000
$64,000
$32,000
$16,000
$8,000
$4,000
$2,000
$1,000
$500
$300
$200
$100
PT x 3 6 x (x 3)(6 x) m+ + − − + − =
Có nghiệm khi và chỉ khi
6 2 9
A. m 3
2
−
≤ ≤
6 2 9
B. m 3
2
− −
≤ ≤
6 2 9
D. m 3
2
− −
≤ ≤ −
6 2 11
C. m 3
2
−
≤ ≤

41. © Mark E. Damon - All Rights Reserved
15
14
13
12
11
10
9
8
7
6
5
4
3
2
1
$1 Million
$500,000
$250,000
$125,000
$64,000
$32,000
$16,000
$8,000
$4,000
$2,000
$1,000
$500
$300
$200
$100

42. © Mark E. Damon - All Rights Reserved
50:50
15
14
13
12
11
10
9
8
7
6
5
4
3
2
1
$1 Million
$500,000
$250,000
$125,000
$64,000
$32,000
$16,000
$8,000
$4,000
$2,000
$1,000
$500
$300
$200
$100
Tìm m để hệ phương
trình sau có nghiệm
2x 3 y m
2y 3 x m
 + − =

+ − =
D. 3 m 3≤ ≤C. 3 m 6≤ ≤
B. 6 m 3≤ ≤A. 3 m 3− ≤ ≤

43. © Mark E. Damon - All Rights Reserved
50:50
15
14
13
12
11
10
9
8
7
6
5
4
3
2
1
$1 Million
$500,000
$250,000
$125,000
$64,000
$32,000
$16,000
$8,000
$4,000
$2,000
$1,000
$500
$300
$200
$100
Tìm m để hệ phương
trình sau có nghiệm
2x 3 y m
2y 3 x m
 + − =

+ − =
D. 3 m 3≤ ≤C. 3 m 6≤ ≤
B. 6 m 3≤ ≤A. 3 m 3− ≤ ≤

44. © Mark E. Damon - All Rights Reserved
YOU WIN $1
MILLION DOLLARS!