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H2SO4 + 2 NaOH = Na2SO4 + 2 H2O moles of NaOH = 2.6 * .45 = 1.17 So
moles of Na2So4 formed = 1.17/2 weight = 1.17/2 * 142 = 83.07 g
Solution
H2SO4 + 2 NaOH = Na2SO4 + 2 H2O moles of NaOH = 2.6 * .45 = 1.17 So
moles of Na2So4 formed = 1.17/2 weight = 1.17/2 * 142 = 83.07 g

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  • 1. H2SO4 + 2 NaOH = Na2SO4 + 2 H2O moles of NaOH = 2.6 * .45 = 1.17 So moles of Na2So4 formed = 1.17/2 weight = 1.17/2 * 142 = 83.07 g Solution H2SO4 + 2 NaOH = Na2SO4 + 2 H2O moles of NaOH = 2.6 * .45 = 1.17 So moles of Na2So4 formed = 1.17/2 weight = 1.17/2 * 142 = 83.07 g