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# EES for Thermodynamics

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A hands-on short training on using Engineering Equation Solver (EES) for solving thermodynamics problems.

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### EES for Thermodynamics

1. 1. EES FOR THERMODYNAMICS A hands-on training. Naveed ur Rehman http://www.naveedurrehman.com/
2. 2. EES – A software • EES (pronounced ’ease’): “Engineering Equation Solver” • Licensed and distributed by F-Chart software (http://fchart.com) • Demo version can be acquired free from http://fchart.com/ees/demo.php • Licensing and ordering information can obtained from http://fchart.com/ees/ and http://fchart.com/ees/order.php • Single user license fee: \$600-\$1200 • Download software and presentation from https://goo.gl/U9s8Ud (Disconnect internet while using EES) 2naveedurrehman.com
3. 3. Environment “Equations window” “Menu” “Toolbar” Remember, EES is case-insensitive i.e. ABC = abc = AbC = Abc… 3naveedurrehman.com
4. 4. Solving linear equation X + 3 = 5 Example: To obtain solution: [Menu] Calculate > Solve or Press “F2” key 4naveedurrehman.com
5. 5. Solving linear equation X + 3 = 5 Example: Solution Window: 5naveedurrehman.com
6. 6. Solving polynomial 3*H^2 - 4*H - 5 = 0 Example: Solution Window: 6 3𝐻2 − 4𝐻 − 5 = 0 naveedurrehman.com
7. 7. Solving system of equations Example: X + Y = 10 X - 2*Y = 5 7 X + Z = 10 - Y X - 2*Y = 5 X = 4 - Z X + Y + Z = 10 X + Y = 0 What about this? Remember, number of variables = number of equations! ERROR! naveedurrehman.com
8. 8. Solving system of equations Example: V = pi * (R^2) * H R = 10 H = 12 8 Calculate volume of cylinder where radius is 10 m and height = 12 m (using 𝑉 = 𝜋𝑅2 𝐻) Calculate radius of cylinder where height is 10 m and volume = 3000 m3 (using 𝑉 = 𝜋𝑅2 𝐻) V = pi * (R^2) * H H = 10 V = 3000 𝑅 = Τ𝑉 𝜋𝐻 naveedurrehman.com
9. 9. Exercise 9 A piston cylinder device initially contains 0.4m3 of air at 100kPa and 80°C. The air is now compressed to 0.1m3 in such a way that the temperature inside the cylinder remains constant. Determine the work done during this process. 𝑊𝑖𝑠𝑜𝑡ℎ𝑒𝑟𝑚𝑎𝑙 = 𝑃1 𝑉1 ln 𝑉2 𝑉1 V1 = 0.4 P1 = 100 T1 = 80 V2 = 0.1 Wb = (P1*V1)*ln(V2/V1) naveedurrehman.com
10. 10. Units and conversion Try: A = 30*Convert(ft,m) B = 10*Convert(MJ, kJ) C = 100*Convert(kJ/kg,BTU/lbm) 10 Solution: Note: Unit to each variable is automatically assigned. Convert statement is used to do unit conversion: Convert ( from-unit , to-unit ) Right-click and select “Units list” naveedurrehman.com
11. 11. Exercise a = 3*convert(bar/kW,kPa/J) 11 Convert 3 bar/kW to kPa/J Convert 3 bar/kW to kPa.s/J a = 3*convert(bar/kW,kPa*s/J) ERROR! Remember, always convert into consistent units. naveedurrehman.com
12. 12. Units and conversion: Temperature Try: TheF = ConvertTEMP(C,F,30) "Convert 30 deg. C to deg. F" TheC = ConvertTEMP(F,C,100) "Convert 100 deg. F to deg. C" 12 Solution: ConvertTemp statement is used to do unit conversion between degree centigrade (°C) and Fahrenheit (°F): ConvertTEMP ( from-unit , to-unit, value) naveedurrehman.com
13. 13. Built-in Functions 13 To access built-in functions: [Menu] Options > Function Info naveedurrehman.com
14. 14. Exercise 14 What is the temperature of water/steam at 11 MPa and internal energy of 2920 kJ/kg? naveedurrehman.com
15. 15. Exercise 15 What is the enthalpy of water/steam at 100 ⁰C and 50 kPa? Solution: ℎ 𝑤𝑎𝑡𝑒𝑟 = ℎ 𝑇=100℃,𝑃=50𝑘𝑃𝑎 Tw = 100 Pw = 50 hw = enthalpy(Steam,T=Tw,P=Pw) hw = enthalpy(Steam,T=100,P=50) naveedurrehman.com
16. 16. Exercise 16 What is the specific volume of water/steam at 100 ⁰C and 50 kPa? Solution: 𝑣 𝑤𝑎𝑡𝑒𝑟 = 𝑣 𝑇=100℃,𝑃=50𝑘𝑃𝑎 v = volume(Steam,T=100,P=50) naveedurrehman.com
17. 17. Exercise 17 A rigid tank contains 50 kg of saturated liquid water at 90 ⁰C. Determine pressure in the tank and volume of tank. Pw=Pressure(Steam,T=90,x=0) Vw = 50*Volume(Steam, T=90,x=0) naveedurrehman.com
18. 18. Exercise 18 A mass of 200 gm of saturated liquid water is completely vaporized at a constant pressure of 100 kPa. Determine the volume change and the amount of energy added to water. m = 200/1000 x1 = 0 x2 = 1 Pw = 100 V1 = volume(Steam, P=Pw, x=x1) V2 = volume(Steam, P=Pw, x=x2) V = m*(V2-V1) h1 = enthalpy(Steam, P=Pw, x=x1) h2 = enthalpy(Steam, P=Pw, x=x2) H = m*(h2-h1) naveedurrehman.com
19. 19. Exercise: Rankine Cycle 19 Consider a steam power plant operating on a simple ideal Rankine cycle. Steam enters the turbine at 3 MPa and 350⁰C and is condensed in a condenser at a pressure of 75kPa. Determine the thermal efficiency of this cycle. naveedurrehman.com
20. 20. Exercise: Rankine Cycle 20 P1 = 75 T1 =TEMPERATURE(Steam,P=P1,x=0) h1 = ENTHALPY(Steam,T=T1,P=P1) v1 = VOLUME(Steam,P=P1,x=0) P2 = 3*convert(MPa,kPa) Wp = v1*(P2-P1) h2 = h1 + Wp P3 = P2 T3 = 350 h3 = ENTHALPY(Steam,T=T3,P=P3) s3 = ENTROPY(Steam,T=T3,P=P3) P4 = P1 s4 = s3 h4 = ENTHALPY(Steam,s=s4,P=P4) qin = h3 - h2 qout = h4 - h1 eta = 1-qout/qin naveedurrehman.com
21. 21. THANK YOU! Naveed ur Rehman http://www.naveedurrehman.com/ 21naveedurrehman.com