The document provides an overview of the Engineering Equation Solver (EES) software, including installation information, usage examples, and exercises related to thermodynamic problems. It covers solving linear equations, performing unit conversions, and calculating properties of steam and water in various scenarios. Additionally, it includes examples on the Rankine cycle and details on built-in functions for thermodynamic calculations.

1. EES FOR
THERMODYNAMICS
A hands-on training.
Naveed ur Rehman
http://www.naveedurrehman.com/

2. EES – A software
• EES (pronounced ’ease’): “Engineering Equation Solver”
• Licensed and distributed by F-Chart software
(http://fchart.com)
• Demo version can be acquired free from
http://fchart.com/ees/demo.php
• Licensing and ordering information can obtained from
http://fchart.com/ees/ and http://fchart.com/ees/order.php
• Single user license fee: $600-$1200
• Download software and presentation from
https://goo.gl/U9s8Ud (Disconnect internet while using EES)
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3. Environment
“Equations window”
“Menu”
“Toolbar”
Remember, EES is case-insensitive
i.e. ABC = abc = AbC = Abc…
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4. Solving linear equation
X + 3 = 5
Example:
To obtain solution:
[Menu] Calculate > Solve
or
Press “F2” key
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5. Solving linear equation
X + 3 = 5
Example:
Solution Window:
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6. Solving polynomial
3*H^2 - 4*H - 5 = 0
Example:
Solution Window:
6
3𝐻2
− 4𝐻 − 5 = 0
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7. Solving system of equations
Example:
X + Y = 10
X - 2*Y = 5
7
X + Z = 10 - Y
X - 2*Y = 5
X = 4 - Z
X + Y + Z = 10
X + Y = 0
What about this?
Remember, number of variables = number of equations!
ERROR!
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8. Solving system of equations
Example:
V = pi * (R^2) * H
R = 10
H = 12
8
Calculate volume of cylinder where radius is 10 m and
height = 12 m (using 𝑉 = 𝜋𝑅2 𝐻)
Calculate radius of cylinder where height is 10 m and
volume = 3000 m3 (using 𝑉 = 𝜋𝑅2 𝐻)
V = pi * (R^2) * H
H = 10
V = 3000
𝑅 = Τ𝑉 𝜋𝐻
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9. Exercise
9
A piston cylinder device initially contains 0.4m3 of air at
100kPa and 80°C. The air is now compressed to 0.1m3 in
such a way that the temperature inside the cylinder
remains constant. Determine the work done during this
process.
𝑊𝑖𝑠𝑜𝑡ℎ𝑒𝑟𝑚𝑎𝑙 = 𝑃1 𝑉1 ln
𝑉2
𝑉1
V1 = 0.4
P1 = 100
T1 = 80
V2 = 0.1
Wb = (P1*V1)*ln(V2/V1)
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10. Units and conversion
Try:
A = 30*Convert(ft,m)
B = 10*Convert(MJ, kJ)
C = 100*Convert(kJ/kg,BTU/lbm)
10
Solution:
Note: Unit to each variable is automatically assigned.
Convert statement is used to do unit conversion:
Convert ( from-unit , to-unit )
Right-click and
select “Units list”
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11. Exercise
a = 3*convert(bar/kW,kPa/J)
11
Convert 3 bar/kW to kPa/J
Convert 3 bar/kW to kPa.s/J
a = 3*convert(bar/kW,kPa*s/J)
ERROR!
Remember, always convert into consistent units.
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12. Units and conversion: Temperature
Try:
TheF = ConvertTEMP(C,F,30) "Convert 30 deg. C to deg. F"
TheC = ConvertTEMP(F,C,100) "Convert 100 deg. F to deg. C"
12
Solution:
ConvertTemp statement is used to do unit conversion
between degree centigrade (°C) and Fahrenheit (°F):
ConvertTEMP ( from-unit , to-unit, value)
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13. Built-in Functions
13
To access built-in functions:
[Menu] Options > Function Info
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14. Exercise
14
What is the
temperature of
water/steam at
11 MPa and
internal energy
of 2920 kJ/kg?
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15. Exercise
15
What is the enthalpy of water/steam at 100 ⁰C and 50 kPa?
Solution:
ℎ 𝑤𝑎𝑡𝑒𝑟 = ℎ 𝑇=100℃,𝑃=50𝑘𝑃𝑎
Tw = 100
Pw = 50
hw = enthalpy(Steam,T=Tw,P=Pw)
hw = enthalpy(Steam,T=100,P=50)
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16. Exercise
16
What is the specific volume of water/steam at 100 ⁰C and 50
kPa?
Solution:
𝑣 𝑤𝑎𝑡𝑒𝑟 = 𝑣 𝑇=100℃,𝑃=50𝑘𝑃𝑎
v = volume(Steam,T=100,P=50)
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17. Exercise
17
A rigid tank contains 50 kg of saturated liquid water at 90
⁰C. Determine pressure in the tank and volume of tank.
Pw=Pressure(Steam,T=90,x=0)
Vw = 50*Volume(Steam, T=90,x=0)
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18. Exercise
18
A mass of 200 gm of saturated liquid water is completely
vaporized at a constant pressure of 100 kPa. Determine
the volume change and the amount of energy added to
water.
m = 200/1000
x1 = 0
x2 = 1
Pw = 100
V1 = volume(Steam, P=Pw, x=x1)
V2 = volume(Steam, P=Pw, x=x2)
V = m*(V2-V1)
h1 = enthalpy(Steam, P=Pw, x=x1)
h2 = enthalpy(Steam, P=Pw, x=x2)
H = m*(h2-h1)
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19. Exercise: Rankine Cycle
19
Consider a steam power plant operating on a simple ideal
Rankine cycle. Steam enters the turbine at 3 MPa and
350⁰C and is condensed in a condenser at a pressure of
75kPa. Determine the thermal efficiency of this cycle.
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20. Exercise: Rankine Cycle
20
P1 = 75
T1 =TEMPERATURE(Steam,P=P1,x=0)
h1 = ENTHALPY(Steam,T=T1,P=P1)
v1 = VOLUME(Steam,P=P1,x=0)
P2 = 3*convert(MPa,kPa)
Wp = v1*(P2-P1)
h2 = h1 + Wp
P3 = P2
T3 = 350
h3 = ENTHALPY(Steam,T=T3,P=P3)
s3 = ENTROPY(Steam,T=T3,P=P3)
P4 = P1
s4 = s3
h4 = ENTHALPY(Steam,s=s4,P=P4)
qin = h3 - h2
qout = h4 - h1
eta = 1-qout/qin
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21. THANK YOU!
Naveed ur Rehman
http://www.naveedurrehman.com/
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