This document discusses solving quadratic equations by factorization. It begins by defining quadratic equations as equations where the highest power of the variable is 2. It then explains that the factorization method involves factorizing the quadratic equation into two linear factors and setting each factor equal to zero to solve for the roots. Several examples of solving quadratic equations using factorization are shown step-by-step. The document concludes by assigning practice problems to solve using factorization.
2. SUBJECT : MATHEMATICS
CLASS : MATRIC
CHAPTER ( 2/4 ) : EQUATIONS
LESSON NO : 01 OF 09
TOPIC : SOLUTION OF
QUADRATIC EQUATION
BY FACTORIZATION
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3. Q. What is meant by the solution of an equation?
A. By the solution of an equation we mean to find the
value of variable which satisfies the equation.
Q. What is meant by the degree of an equation?
A. Maximum power of the variable in the equation is
called degree of equation.
Q. What is meant by the quadratic equation?
A. An equation in which maximum power of the
variable is two is called quadratic equation.
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4. Q. How can we solve a quadratic equation?
A. We can solve a quadratic equation by these
methods.
(i) Factorization method
(ii) Completing square method
(iii) Quadratic formula
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5. ο Quadratic Equation
ο Factorization Method
ο Related Examples
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6. Quadratic Equation
ο An equation in one variable
ο Maximum power of variable is two
Examples
2x2 β 5x + 3 =0
9x2 β 13x + 7 =0
SOLUTION OF QUADRATIC EQUATION
BY FACTORIZATION
s k y h a w k s 2 f l y / 0 3 3 3 9 3 0 2 2 5 6 s k y h a w k s
7. General form of quadratic equation is
ax2 + bx + c = 0 ; (a οΉ o)
Where a & b are the coefficients of the second and the
first degree terms respectively, and βcβ is constant.
Quadratic Equation
SOLUTION OF QUADRATIC EQUATION
BY FACTORIZATION
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8. Factorization Method
In this method, we factorize the given equation
and get two factors which on equating to zero, give the
required two values for unknown.
SOLUTION OF QUADRATIC EQUATION
BY FACTORIZATION
s k y h a w k s 2 f l y / 0 3 3 3 9 3 0 2 2 5 6 s k y h a w k s
9. Solve by factorising: x2 + 7x + 12=0
1 x 12 = 12
2 x 6 = 12
3 x 4 = 12
Write down all
the factor pairs
of 12.
From this list,
choose the pair that
adds up to 7
3 + 4 = 7
Put these numbers
into brackets
0 = (x + 3)(x + 4)
x = β 3 and β 4
Multiply constant
termβ12β and the term
βx2β
What will be the
answer?
Ans. β12 x2β
Note: Now make
such factors of β7xβ
so that their sum
should be equal to
β7xβ and product
equal to β12 x2β.
(x +....)(x+β¦.)
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10. s k y h a w k s 2 f l y / 0 3 3 3 9 3 0 2 2 5 6 s k y h a w k s
11. Solve by factorising: 0 = x2 + x - 6
1 x -6 = -6
2 x -3 = -6
3 x -2 = -6
6 x -1 = -6
Write down all the
factor pairs of β 6
From this list,
choose the pair
that adds up to 1
(3) + (-2) = 1
3 β 2 = 1
Put these numbers
into brackets
0 = (x + 3)(x - 2)
x = β 3 and 2
Multiply constant
termβ-6β and the term
βx2β.
What would be the
answer ?
Ans:- β-6x2 β
Note: Now make
such factors of βxβ
so that their sum
should be equal to
βxβ and product
equal to β-6x2β.
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12. Copy and fill in the missing
values when you factorise
x2 + 8x + 12 = 0
Find all the factor pairs of 12
1 x 12 = 12
2 x _ = 12
3 x 4 = 12
From these choose the pair
that add up to 8
_ + 6 = 8
Put these values into the
brackets (x + _)(x + _) = 0
x = -2 and - 6
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13. Example 1
Solve x2 - 3x = 2x β 6
SOLUTION OF QUADRATIC EQUATION
BY FACTORIZATION
Solution
x2 - 3x = 2x β 6
x2-5x+6 = 0
x2-3x-2x+6 = 0
x(x-3)-2(x-3) = 0
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14. (x-2) (x-3) = 0
x-2 = 0 or x-3 = 0
x = 2 or x = 3
Solution set = { 2 , 3 }
SOLUTION OF QUADRATIC EQUATION
BY FACTORIZATION
s k y h a w k s 2 f l y / 0 3 3 3 9 3 0 2 2 5 6 s k y h a w k s
15. SOLUTION OF QUADRATIC EQUATION
BY FACTORIZATION
Solution
3x2 +4x-4=0
3 x2+6x-2x-4 = 0
3x(x+2)-2(x+2) = 0
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16. (x+2) (3x-2) = 0
x+2 = 0 or 3x-2 = 0
x=-2 or x = 2/3
Solution set = { -2 , 2 / 3 }
SOLUTION OF QUADRATIC EQUATION
BY FACTORIZATION
s k y h a w k s 2 f l y / 0 3 3 3 9 3 0 2 2 5 6 s k y h a w k s
17. 1. x2 + 5x + 6 = 0
2. x2 - x β 6 = 0
3. x2 + 8x + 12 = 0
4. x2 + x β 12 = 0
5. x2 - 8x + 15 = 0
6. x2 + 3x β 21 = 0
7. x2 - 3x β 18 = 0
8. x2 - 10x β 24 = 0
9. x2 + 8x + 16 = 0
10. x2 - 4x β 60 = 0
(x+β¦)(x+β¦)
(xββ¦)(x+β¦)
-3 and -2
3 and -2
(x+β¦)(x+β¦) -2 and -6
(xββ¦)(x+β¦)
(xββ¦)(xββ¦)
(x+β¦)(xββ¦)
(xββ¦)(x+β¦)
(x-β¦)(x+β¦)
(x+β¦)(x+β¦)
(x-β¦)(x+β¦)
3 and -4
3 and 5
-7 and 4
6 and -3
12 and -2
-4 and -4
10 and -4
(x+3)(x+2)
(xβ3)(x+2)
(x+2)(x+6)
(xβ3)(x+4)
(xβ3)(xβ5)
(x+7)(xβ4)
(xβ6)(x+3)
(x-12)(x+2)
(x+4)(x+4)
(x-10)(x+4)
GOOD JOB GUYS!
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18. ο Quadratic Equation
ο Factorization Method
ο Related Examples
SOLUTION OF QUADRATIC EQUATION BY
FACTORIZATION
s k y h a w k s 2 f l y / 0 3 3 3 9 3 0 2 2 5 6 s k y h a w k s
19. s k y h a w k s 2 f l y / 0 3 3 3 9 3 0 2 2 5 6 s k y h a w k s
20. Q. What is the definition of quadratic equation?
A. An equation in one variable and the maximum
power of variable is two is called Quadratic
Equation.
Q. What is the general form of quadratic equation?
A. General form of quadratic equation is
ax2 + bx + c = 0 ; (a οΉ o)
SOLUTION OF QUADRATIC EQUATION
BY FACTORIZATION
s k y h a w k s 2 f l y / 0 3 3 3 9 3 0 2 2 5 6 s k y h a w k s
21. Assignment
Solve the following for βxβ by factorization method.
(i) 9x2 β12x β 5 = 0
(ii) x (x+7) = (2x-1) (x+4)
(iii) x 2βx = 2
SOLUTION OF QUADRATIC EQUATION BY
FACTORIZATION
s k y h a w k s 2 f l y / 0 3 3 3 9 3 0 2 2 5 6 s k y h a w k s
22. SOLUTION OF QUADRATIC EQUATION
BY
COMPLETING SQUARE METHOD
s k y h a w k s 2 f l y / 0 3 3 3 9 3 0 2 2 5 6 s k y h a w k s