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• A. J. Clark School of Engineering •Department of Civil and Environmental Engineering• A. J. Clark School of Engineering •Department of Civil and Environmental Engineering• A. J. Clark School of Engineering •Department of Civil and Environmental Engineering• A. J. Clark School of Engineering •Department of Civil and Environmental Engineering• A. J. Clark School of Engineering •Department of Civil and Environmental Engineering
Third Edition
LECTURE
15
6.6 – 6.7
Chapter
BEAMS: SHEAR FLOW, THIN
WALLED MEMBERS
by
Dr. Ibrahim A. Assakkaf
SPRING 2003
ENES 220 – Mechanics of Materials
Department of Civil and Environmental Engineering
University of Maryland, College Park
LECTURE 15. BEAMS: SHEAR FLOW, THIN-WALLED MEMBERS (6.6 – 6.7) Slide No. 1
ENES 220 ©Assakkaf
Shear on the Horizontal Face of a Beam Element
• Consider prismatic beam
• For equilibrium of beam element
( )
∫
−
=∆
∑ ∫ −+∆==
A
CD
A
DDx
dAy
I
MM
H
dAHF σσ0
xVx
dx
dM
MM
dAyQ
CD
A
∆=∆=−
∫=
• Note,
flowshear
I
VQ
x
H
q
x
I
VQ
H
==
∆
∆
=
∆=∆
• Substituting,
2
LECTURE 15. BEAMS: SHEAR FLOW, THIN-WALLED MEMBERS (6.6 – 6.7) Slide No. 2
ENES 220 ©Assakkaf
Shear on the Horizontal Face of a Beam Element
flowshear
I
VQ
x
H
q ==
∆
∆
=
• Shear flow,
• where
sectioncrossfullofmomentsecond
aboveareaofmomentfirst
'
2
1
=
∫=
=
∫=
+AA
A
dAyI
y
dAyQ
• Same result found for lower area
HH
QQ
q
I
QV
x
H
q
∆−=′∆
=
=′+
′−=
′
=
∆
′∆
=′
axisneutralto
respecthmoment witfirst
0
LECTURE 15. BEAMS: SHEAR FLOW, THIN-WALLED MEMBERS (6.6 – 6.7) Slide No. 3
ENES 220 ©Assakkaf
Shearing Stress in Beams
Example 16
The transverse shear V at a certain
section of a timber beam is 600 lb. If
the beam has the cross section
shown in the figure, determine (a) the
vertical shearing stress 3 in. below
the top of the beam, and (b) the
maximum vertical stress on the cross
section.
3
LECTURE 15. BEAMS: SHEAR FLOW, THIN-WALLED MEMBERS (6.6 – 6.7) Slide No. 4
ENES 220 ©Assakkaf
Shearing Stress in Beams
Example 16 (cont’d)
12 in.
8 in.
4 in.
8 in.
LECTURE 15. BEAMS: SHEAR FLOW, THIN-WALLED MEMBERS (6.6 – 6.7) Slide No. 5
ENES 220 ©Assakkaf
Shearing Stress in Beams
Example 16 (cont’d)
From symmetry, the neutral axis is located
6 in. from either the top or bottom edge.
( ) ( )
( )( ) ( )( )[ ]
( )( ) ( )( )[ ] 3
3
3
4
33
in0.1124222528
in0.945.3212528
in3.981
12
84
12
128
=+=
=+=
=−=
′′
NAQ
Q
I
8 in.
4 in.
8 in.
12 in.
8 in.
4 in.
8 in.
N.A.
3 in.
( )
( )
( )
( )
psi2.171
43.981
1126000
)b(
psi7.143
43.981
946000
)a(
max
max
3
3
===
=== ′′
′′
It
VQ
It
VQ
Q
τ
τ
· ·· ·
··
4
LECTURE 15. BEAMS: SHEAR FLOW, THIN-WALLED MEMBERS (6.6 – 6.7) Slide No. 6
ENES 220 ©Assakkaf
Longitudinal Shear on a Beam
Element of Arbitrary Shape
Consider a box beam obtained by
nailing together four planks as shown in
Fig. 1.
The shear per unit length (Shear flow) q
on a horizontal surfaces along which the
planks are joined is given by
flowshear
I
VQ
q == (1)
LECTURE 15. BEAMS: SHEAR FLOW, THIN-WALLED MEMBERS (6.6 – 6.7) Slide No. 7
ENES 220 ©Assakkaf
Longitudinal Shear on a Beam
Element of Arbitrary Shape
Figure 1
5
LECTURE 15. BEAMS: SHEAR FLOW, THIN-WALLED MEMBERS (6.6 – 6.7) Slide No. 8
ENES 220 ©Assakkaf
Longitudinal Shear on a Beam
Element of Arbitrary Shape
But couldBut could qq be determined if the planksbe determined if the planks
had been joined alonghad been joined along vertical surfacesvertical surfaces,,
as shown in Fig. 1b?as shown in Fig. 1b?
Previously, we had examined the
distribution of the vertical components
τxy of the stresses on a transverse
section of a W-beam or an S-beam as
shown in the following viewgraph.
LECTURE 15. BEAMS: SHEAR FLOW, THIN-WALLED MEMBERS (6.6 – 6.7) Slide No. 9
ENES 220 ©Assakkaf
Shearing Stresses τxy in Common
Types of Beams
• For a narrow rectangular beam,
A
V
c
y
A
V
Ib
VQ
xy
2
3
1
2
3
max
2
2
=








−==
τ
τ
• For American Standard (S-beam)
and wide-flange (W-beam) beams
web
ave
A
V
It
VQ
=
=
maxτ
τ
6
LECTURE 15. BEAMS: SHEAR FLOW, THIN-WALLED MEMBERS (6.6 – 6.7) Slide No. 10
ENES 220 ©Assakkaf
Longitudinal Shear on A Beam
Element of Arbitrary Shape
But what about theBut what about the horizontalhorizontal
componentcomponent ττxzxz of the stresses in theof the stresses in the
flanges?flanges?
To answer these questions, the
procedure developed earlier must be
extended for the determination of the
shear per unit length q so that it will
apply to the cases just described.
LECTURE 15. BEAMS: SHEAR FLOW, THIN-WALLED MEMBERS (6.6 – 6.7) Slide No. 11
ENES 220 ©Assakkaf
Longitudinal Shear on a Beam Element
of Arbitrary Shape
• We have examined the distribution of
the vertical components τxy on a
transverse section of a beam. We
now wish to consider the horizontal
components τxz of the stresses.
• Consider prismatic beam with an
element defined by the curved surface
CDD’C’.
( )∑ ∫ −+∆==
a
dAHF CDx σσ0
• Except for the differences in
integration areas, this is the same
result obtained before which led to
I
VQ
x
H
qx
I
VQ
H =
∆
∆
=∆=∆
7
LECTURE 15. BEAMS: SHEAR FLOW, THIN-WALLED MEMBERS (6.6 – 6.7) Slide No. 12
ENES 220 ©Assakkaf
Shearing Stress in Beams
Example 17
A square box beam is constructed from
four planks as shown. Knowing that the
spacing between nails is 1.75 in. and the
beam is subjected to a vertical shear of
magnitude V = 600 lb, determine the
shearing force in each nail.
SOLUTION:
• Determine the shear force per unit
length along each edge of the upper
plank.
• Based on the spacing between nails,
determine the shear force in each
nail.
LECTURE 15. BEAMS: SHEAR FLOW, THIN-WALLED MEMBERS (6.6 – 6.7) Slide No. 13
ENES 220 ©Assakkaf
Example 17 (cont’d)
For the upper plank,
( )( )( )
3
in22.4
.in875.1.in3in.75.0
=
=′= yAQ
For the overall beam cross-section,
( ) ( )
4
3
12
13
12
1
in42.27
in3in5.4
=
−=I
SOLUTION:
• Determine the shear force per unit
length along each edge of the upper
plank.
( )( )
lengthunitperforceedge
in
lb
15.46
2
in
lb
3.92
in27.42
in22.4lb600
4
3
=
==
===
q
f
I
VQ
q
• Based on the spacing between nails,
determine the shear force in each
nail.
( )in75.1
in
lb
15.46 





== lfF
lb8.80=F
8
LECTURE 15. BEAMS: SHEAR FLOW, THIN-WALLED MEMBERS (6.6 – 6.7) Slide No. 14
ENES 220 ©Assakkaf
Shearing Stress in Thin-Walled
Members
It was noted earlier that Eq. 1 can be
used to determine the shear flow in an
arbitrary shape of a beam cross section.
This equation will be used in this section
to calculate both the shear flow and the
average shearing stress in thin-walled
members such as flanges of wide-
flange beams (Fig. 2) and box beams or
the walls of structural tubes.
LECTURE 15. BEAMS: SHEAR FLOW, THIN-WALLED MEMBERS (6.6 – 6.7) Slide No. 15
ENES 220 ©Assakkaf
Shearing Stress in Thin-Walled
Members
Figure 2
Wide-Flange Beams
9
LECTURE 15. BEAMS: SHEAR FLOW, THIN-WALLED MEMBERS (6.6 – 6.7) Slide No. 16
ENES 220 ©Assakkaf
Shearing Stress in Thin-Walled
Members
Consider a segment of a wide-flange
beam subjected to the vertical shear V.
The longitudinal shear force on the
element is
x
I
VQ
H ∆=∆ (2)
LECTURE 15. BEAMS: SHEAR FLOW, THIN-WALLED MEMBERS (6.6 – 6.7) Slide No. 17
ENES 220 ©Assakkaf
Shearing Stress in Thin-Walled
Members
Figure 3
10
LECTURE 15. BEAMS: SHEAR FLOW, THIN-WALLED MEMBERS (6.6 – 6.7) Slide No. 18
ENES 220 ©Assakkaf
Shearing Stress in Thin-Walled
Members
The corresponding shear stress is
Previously found a similar expression
for the shearing stress in the web
It
VQ
xt
H
xzzx =
∆
∆
≈=ττ (3)
It
VQ
xy =τ (4)
LECTURE 15. BEAMS: SHEAR FLOW, THIN-WALLED MEMBERS (6.6 – 6.7) Slide No. 19
ENES 220 ©Assakkaf
Shearing Stress in Thin-Walled
Members
• The variation of shear flow across the
section depends only on the variation of
the first moment.
I
VQ
tq ==τ
• For a box beam, q grows smoothly from
zero at A to a maximum at C and C’ and
then decreases back to zero at E.
• The sense of q in the horizontal portions
of the section may be deduced from the
sense in the vertical portions or the
sense of the shear V.
11
LECTURE 15. BEAMS: SHEAR FLOW, THIN-WALLED MEMBERS (6.6 – 6.7) Slide No. 20
ENES 220 ©Assakkaf
Shearing Stress in Thin-Walled
Members
• For a wide-flange beam, the shear flow
increases symmetrically from zero at A
and A’, reaches a maximum at C and the
decreases to zero at E and E’.
• The continuity of the variation in q and
the merging of q from section branches
suggests an analogy to fluid flow.
LECTURE 15. BEAMS: SHEAR FLOW, THIN-WALLED MEMBERS (6.6 – 6.7) Slide No. 21
ENES 220 ©Assakkaf
Shearing Stress in Thin-Walled
Members
Example 18
Knowing that the
vertical shear is 50
kips in a W10 × 68
rolled-steel beam,
determine the
horizontal shearing
stress in the top
flange at the point a.
12
LECTURE 15. BEAMS: SHEAR FLOW, THIN-WALLED MEMBERS (6.6 – 6.7) Slide No. 22
ENES 220 ©Assakkaf
Shearing Stress in Thin-Walled
Members
Example 18 (cont’d)
SOLUTION:
• For the shaded area,
( )( )( )
3
in98.15
in815.4in770.0in31.4
=
=Q
• The shear stress at a,
( )( )
( )( )in770.0in394
in98.15kips50
4
3
==
It
VQ
τ
ksi63.2=τ

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Lecture15

  • 1. 1 • A. J. Clark School of Engineering •Department of Civil and Environmental Engineering• A. J. Clark School of Engineering •Department of Civil and Environmental Engineering• A. J. Clark School of Engineering •Department of Civil and Environmental Engineering• A. J. Clark School of Engineering •Department of Civil and Environmental Engineering• A. J. Clark School of Engineering •Department of Civil and Environmental Engineering Third Edition LECTURE 15 6.6 – 6.7 Chapter BEAMS: SHEAR FLOW, THIN WALLED MEMBERS by Dr. Ibrahim A. Assakkaf SPRING 2003 ENES 220 – Mechanics of Materials Department of Civil and Environmental Engineering University of Maryland, College Park LECTURE 15. BEAMS: SHEAR FLOW, THIN-WALLED MEMBERS (6.6 – 6.7) Slide No. 1 ENES 220 ©Assakkaf Shear on the Horizontal Face of a Beam Element • Consider prismatic beam • For equilibrium of beam element ( ) ∫ − =∆ ∑ ∫ −+∆== A CD A DDx dAy I MM H dAHF σσ0 xVx dx dM MM dAyQ CD A ∆=∆=− ∫= • Note, flowshear I VQ x H q x I VQ H == ∆ ∆ = ∆=∆ • Substituting,
  • 2. 2 LECTURE 15. BEAMS: SHEAR FLOW, THIN-WALLED MEMBERS (6.6 – 6.7) Slide No. 2 ENES 220 ©Assakkaf Shear on the Horizontal Face of a Beam Element flowshear I VQ x H q == ∆ ∆ = • Shear flow, • where sectioncrossfullofmomentsecond aboveareaofmomentfirst ' 2 1 = ∫= = ∫= +AA A dAyI y dAyQ • Same result found for lower area HH QQ q I QV x H q ∆−=′∆ = =′+ ′−= ′ = ∆ ′∆ =′ axisneutralto respecthmoment witfirst 0 LECTURE 15. BEAMS: SHEAR FLOW, THIN-WALLED MEMBERS (6.6 – 6.7) Slide No. 3 ENES 220 ©Assakkaf Shearing Stress in Beams Example 16 The transverse shear V at a certain section of a timber beam is 600 lb. If the beam has the cross section shown in the figure, determine (a) the vertical shearing stress 3 in. below the top of the beam, and (b) the maximum vertical stress on the cross section.
  • 3. 3 LECTURE 15. BEAMS: SHEAR FLOW, THIN-WALLED MEMBERS (6.6 – 6.7) Slide No. 4 ENES 220 ©Assakkaf Shearing Stress in Beams Example 16 (cont’d) 12 in. 8 in. 4 in. 8 in. LECTURE 15. BEAMS: SHEAR FLOW, THIN-WALLED MEMBERS (6.6 – 6.7) Slide No. 5 ENES 220 ©Assakkaf Shearing Stress in Beams Example 16 (cont’d) From symmetry, the neutral axis is located 6 in. from either the top or bottom edge. ( ) ( ) ( )( ) ( )( )[ ] ( )( ) ( )( )[ ] 3 3 3 4 33 in0.1124222528 in0.945.3212528 in3.981 12 84 12 128 =+= =+= =−= ′′ NAQ Q I 8 in. 4 in. 8 in. 12 in. 8 in. 4 in. 8 in. N.A. 3 in. ( ) ( ) ( ) ( ) psi2.171 43.981 1126000 )b( psi7.143 43.981 946000 )a( max max 3 3 === === ′′ ′′ It VQ It VQ Q τ τ · ·· · ··
  • 4. 4 LECTURE 15. BEAMS: SHEAR FLOW, THIN-WALLED MEMBERS (6.6 – 6.7) Slide No. 6 ENES 220 ©Assakkaf Longitudinal Shear on a Beam Element of Arbitrary Shape Consider a box beam obtained by nailing together four planks as shown in Fig. 1. The shear per unit length (Shear flow) q on a horizontal surfaces along which the planks are joined is given by flowshear I VQ q == (1) LECTURE 15. BEAMS: SHEAR FLOW, THIN-WALLED MEMBERS (6.6 – 6.7) Slide No. 7 ENES 220 ©Assakkaf Longitudinal Shear on a Beam Element of Arbitrary Shape Figure 1
  • 5. 5 LECTURE 15. BEAMS: SHEAR FLOW, THIN-WALLED MEMBERS (6.6 – 6.7) Slide No. 8 ENES 220 ©Assakkaf Longitudinal Shear on a Beam Element of Arbitrary Shape But couldBut could qq be determined if the planksbe determined if the planks had been joined alonghad been joined along vertical surfacesvertical surfaces,, as shown in Fig. 1b?as shown in Fig. 1b? Previously, we had examined the distribution of the vertical components τxy of the stresses on a transverse section of a W-beam or an S-beam as shown in the following viewgraph. LECTURE 15. BEAMS: SHEAR FLOW, THIN-WALLED MEMBERS (6.6 – 6.7) Slide No. 9 ENES 220 ©Assakkaf Shearing Stresses τxy in Common Types of Beams • For a narrow rectangular beam, A V c y A V Ib VQ xy 2 3 1 2 3 max 2 2 =         −== τ τ • For American Standard (S-beam) and wide-flange (W-beam) beams web ave A V It VQ = = maxτ τ
  • 6. 6 LECTURE 15. BEAMS: SHEAR FLOW, THIN-WALLED MEMBERS (6.6 – 6.7) Slide No. 10 ENES 220 ©Assakkaf Longitudinal Shear on A Beam Element of Arbitrary Shape But what about theBut what about the horizontalhorizontal componentcomponent ττxzxz of the stresses in theof the stresses in the flanges?flanges? To answer these questions, the procedure developed earlier must be extended for the determination of the shear per unit length q so that it will apply to the cases just described. LECTURE 15. BEAMS: SHEAR FLOW, THIN-WALLED MEMBERS (6.6 – 6.7) Slide No. 11 ENES 220 ©Assakkaf Longitudinal Shear on a Beam Element of Arbitrary Shape • We have examined the distribution of the vertical components τxy on a transverse section of a beam. We now wish to consider the horizontal components τxz of the stresses. • Consider prismatic beam with an element defined by the curved surface CDD’C’. ( )∑ ∫ −+∆== a dAHF CDx σσ0 • Except for the differences in integration areas, this is the same result obtained before which led to I VQ x H qx I VQ H = ∆ ∆ =∆=∆
  • 7. 7 LECTURE 15. BEAMS: SHEAR FLOW, THIN-WALLED MEMBERS (6.6 – 6.7) Slide No. 12 ENES 220 ©Assakkaf Shearing Stress in Beams Example 17 A square box beam is constructed from four planks as shown. Knowing that the spacing between nails is 1.75 in. and the beam is subjected to a vertical shear of magnitude V = 600 lb, determine the shearing force in each nail. SOLUTION: • Determine the shear force per unit length along each edge of the upper plank. • Based on the spacing between nails, determine the shear force in each nail. LECTURE 15. BEAMS: SHEAR FLOW, THIN-WALLED MEMBERS (6.6 – 6.7) Slide No. 13 ENES 220 ©Assakkaf Example 17 (cont’d) For the upper plank, ( )( )( ) 3 in22.4 .in875.1.in3in.75.0 = =′= yAQ For the overall beam cross-section, ( ) ( ) 4 3 12 13 12 1 in42.27 in3in5.4 = −=I SOLUTION: • Determine the shear force per unit length along each edge of the upper plank. ( )( ) lengthunitperforceedge in lb 15.46 2 in lb 3.92 in27.42 in22.4lb600 4 3 = == === q f I VQ q • Based on the spacing between nails, determine the shear force in each nail. ( )in75.1 in lb 15.46       == lfF lb8.80=F
  • 8. 8 LECTURE 15. BEAMS: SHEAR FLOW, THIN-WALLED MEMBERS (6.6 – 6.7) Slide No. 14 ENES 220 ©Assakkaf Shearing Stress in Thin-Walled Members It was noted earlier that Eq. 1 can be used to determine the shear flow in an arbitrary shape of a beam cross section. This equation will be used in this section to calculate both the shear flow and the average shearing stress in thin-walled members such as flanges of wide- flange beams (Fig. 2) and box beams or the walls of structural tubes. LECTURE 15. BEAMS: SHEAR FLOW, THIN-WALLED MEMBERS (6.6 – 6.7) Slide No. 15 ENES 220 ©Assakkaf Shearing Stress in Thin-Walled Members Figure 2 Wide-Flange Beams
  • 9. 9 LECTURE 15. BEAMS: SHEAR FLOW, THIN-WALLED MEMBERS (6.6 – 6.7) Slide No. 16 ENES 220 ©Assakkaf Shearing Stress in Thin-Walled Members Consider a segment of a wide-flange beam subjected to the vertical shear V. The longitudinal shear force on the element is x I VQ H ∆=∆ (2) LECTURE 15. BEAMS: SHEAR FLOW, THIN-WALLED MEMBERS (6.6 – 6.7) Slide No. 17 ENES 220 ©Assakkaf Shearing Stress in Thin-Walled Members Figure 3
  • 10. 10 LECTURE 15. BEAMS: SHEAR FLOW, THIN-WALLED MEMBERS (6.6 – 6.7) Slide No. 18 ENES 220 ©Assakkaf Shearing Stress in Thin-Walled Members The corresponding shear stress is Previously found a similar expression for the shearing stress in the web It VQ xt H xzzx = ∆ ∆ ≈=ττ (3) It VQ xy =τ (4) LECTURE 15. BEAMS: SHEAR FLOW, THIN-WALLED MEMBERS (6.6 – 6.7) Slide No. 19 ENES 220 ©Assakkaf Shearing Stress in Thin-Walled Members • The variation of shear flow across the section depends only on the variation of the first moment. I VQ tq ==τ • For a box beam, q grows smoothly from zero at A to a maximum at C and C’ and then decreases back to zero at E. • The sense of q in the horizontal portions of the section may be deduced from the sense in the vertical portions or the sense of the shear V.
  • 11. 11 LECTURE 15. BEAMS: SHEAR FLOW, THIN-WALLED MEMBERS (6.6 – 6.7) Slide No. 20 ENES 220 ©Assakkaf Shearing Stress in Thin-Walled Members • For a wide-flange beam, the shear flow increases symmetrically from zero at A and A’, reaches a maximum at C and the decreases to zero at E and E’. • The continuity of the variation in q and the merging of q from section branches suggests an analogy to fluid flow. LECTURE 15. BEAMS: SHEAR FLOW, THIN-WALLED MEMBERS (6.6 – 6.7) Slide No. 21 ENES 220 ©Assakkaf Shearing Stress in Thin-Walled Members Example 18 Knowing that the vertical shear is 50 kips in a W10 × 68 rolled-steel beam, determine the horizontal shearing stress in the top flange at the point a.
  • 12. 12 LECTURE 15. BEAMS: SHEAR FLOW, THIN-WALLED MEMBERS (6.6 – 6.7) Slide No. 22 ENES 220 ©Assakkaf Shearing Stress in Thin-Walled Members Example 18 (cont’d) SOLUTION: • For the shaded area, ( )( )( ) 3 in98.15 in815.4in770.0in31.4 = =Q • The shear stress at a, ( )( ) ( )( )in770.0in394 in98.15kips50 4 3 == It VQ τ ksi63.2=τ