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A=P(1+(rn))ntA = total amountP = principal or amount of money .pdf

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A=P(1+(r/n))n*t A = total amount P = principal or amount of money deposited, r = annual interest rate n = number of times compounded per year t = time in years 13000=P(1+(6.5/100*12))12*3 13000=P(1.00542)36 13000=P(1.214817) P=$ 10701.2 Solution A=P(1+(r/n))n*t A = total amount P = principal or amount of money deposited, r = annual interest rate n = number of times compounded per year t = time in years 13000=P(1+(6.5/100*12))12*3 13000=P(1.00542)36 13000=P(1.214817) P=$ 10701.2.

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A=P(1+(r/n))n*t A = total amount P = principal or amount of money deposited, r = annual interest rate n = number of times compounded per year t = time in years 13000=P(1+(6.5/100*12))12*3 13000=P(1.00542)36 13000=P(1.214817) P=$ 10701.2 Solution A=P(1+(r/n))n*t A = total amount P = principal or amount of money deposited, r = annual interest rate n = number of times compounded per year t = time in years 13000=P(1+(6.5/100*12))12*3 13000=P(1.00542)36 13000=P(1.214817) P=$ 10701.2

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A=P(1+(rn))ntA = total amountP = principal or amount of money .pdf

  • 1. A=P(1+(r/n))n*t A = total amount P = principal or amount of money deposited, r = annual interest rate n = number of times compounded per year t = time in years 13000=P(1+(6.5/100*12))12*3 13000=P(1.00542)36 13000=P(1.214817) P=$ 10701.2 Solution A=P(1+(r/n))n*t A = total amount P = principal or amount of money deposited, r = annual interest rate n = number of times compounded per year t = time in years 13000=P(1+(6.5/100*12))12*3 13000=P(1.00542)36 13000=P(1.214817) P=$ 10701.2