4.2Why is there waiting in an infinite-source queuing systemmul.pdf

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4.2 Why is there waiting in an infinite-source queuing system? multiple-phase processing slow service variability in arrival and service rates low utilization poor scheduling of servers Solution The population or source in a queuing theory is divided into two parts including finite and infinite population. In infinite source queuing system, the number of customers in the system has no effect on the arrival pattern of customers. Besides it also experiences huge variability in the arrival rate of customers as well as the service rates. Due to this reason there is waiting in infinite-source queuing system. Hence, the correct option is variability in arrival and service rates..

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Sharks are able to maintain their fluids hypertonic to the ocean environment by accumulating: (Choose One) A. fluids in the rectal gland B. fluid in the organ of Lorenzini C. Calcium and phosphate D. urea and TMAO Solution Ans D urea and TMAO sharks store urea and TMAO ( trimethyl amine oxide). Urea is responsible for the metabolism of different compounds in their body and help to excrete nitrogen out from their body..

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Quantum Bank Inc. is a regional bank with branches throughout the southeast. In early 2011 the bank launched an app for mobile devices that provided its customers with the ability to check account balances, obtain information about the bank’s various services, obtain contact information and email questions, and link to a variety of other useful sources of information. Given the app’s tremendous success, competition from both traditional and nontradi- tional organizations, and the desire to expand its presence beyond its current geographical area, Quantum decided to significantly enhance its app. More specifically, Quantum would like to enhance its app to include a mo payment service, allow customers to apply for credit cards and loans, open accounts, and manage their investment portfolios. Vice-President of Information Systems, Stacey Thomas, has been charged with overseeing the project. One of her first tasks was to select the project manager. Because of the strategic importance of the project, she had a strong preference for staffing the project internally as opposed to employing the services of one of the many consulting firms available that specialize in these types of projects. After developing a list of ten or so possible candidates to serve as project manager, she was finally able to pare the list down to the two finalists described below. Bill Fence Bill joined Quantum in 2005 after gradu- ating from a well-respected small private school with a degree in computer science. His first assignment as a member of the bank’s help desk provided him with expo- sure to a variety of areas in the bank. He quickly gained a reputation for being able to solve difficult technical problems. In addition, users of the bank’s various computer systems were often heard commenting on how service oriented Bill was and on his ability to describe concepts in nontechnical terms. Because of both his technical knowledge related to hardware and his ability to program, Bill was selected to develop the bank’s first mobile app in 2010. Bill worked alone on this project and had frequent meetings with one of the bank’s directors of Information Systems, who supervised the project. Initially, the director did most of the design work and Bill did the programming. Bill often proposed alternative ways for incorporating key features into the app, and the director would choose among the options Bill identified. Toward the end of the development project, Bill began to take a more active role in pro- posing features to include in the app. The development project was largely completed on time and on budget considering the changes in the scope of the project that were made as the project progressed. Several suggestions that would have extended the app’s functionality were tabled to be considered as updates after the app was officially launched. In his current position as Webmaster, Bill is in charge of maintaining the bank’s Web site. Although Bill’s staff now includes a pr.

Quantum Bank Inc. is a regional bank with branches throughout the so.pdf

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Neeb Corporation manufactures and sells a single product. The company uses units as the measure of activity in its budgets 2 9 and performance reports, During January, the company budgeted for 7,000 units, but its actual level The company has provided the following data concerning the formulas used in its budgeting and its actual results for January of activity was 7040 units Fixed Variable element element per unit $27.20 per month Revenue Direct labor Direct materials Manufacturing overhead Selling and administrative expenses Total expenses s$ 3.20 9.70 1.10 27,000 0.46 $71,300 $%14.4 44,300 Solution.

Neeb Corporation manufactures and sells a single product. The com.pdf

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Describe the primary, secondary, and tertiary structure of DNA Solution Answer: 1. Primary structure: DNA is made of nucleotides. Nucleotides are arranged in linear fashion by the phosphodiester bonds. Linear structure of DNA is called primary structure. 2. Secondary structure: Helical tructure is called secondary structure. In this structure, two linear polynucleotides are held together by hydrogen bonds and formrs double helical structure. The DNA appears in different helices, hence the DNA is called as A-DNA, B-DNA and Z-DNA. 3. Tertiary structure: It is specific three dimensional shape of DNA that is formed by repeating folding of DNA. This foldings are formed by the histone proteins. Several beads like structures are formed in the tertiary structure called nucleosomes. Hence, the tertiary structure of DNA appears like beads on string..

Describe the primary, secondary, and tertiary structure of DNASo.pdf

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I need help with this program for java. The program you are given to start with: Lab4.java The input file of ints:10,000ints.txt The input file of words:172,822words.txt Execute your program like this: C:\\> java Lab4 10000ints.txt 172822words.txt Be sure to put the ints filename before the words filename. The starter file will be expecting them in that order. Lab#4\'s main method is completely written. Do not modify main. Just fill in the methods. Main will load a large arrays of int, and then load a large array of Strings. As usual the read loops for each file will be calling a resize method as needed. Once the arrays are loaded, each array will be tested for the presence of duplicates via calls to indexOfFirstDuplicate(). Do not do any trim operation. Here are the rules: In your methods that look for the first occurrence of a duplicate in each array, you must sort the arrays before looking for the dupe. Do not search the array for the dupe until it is sorted. We require this because an unsorted array would require a quadratic algorithm (N squared via nested loops). If you sort you array first you will only incur an O(n*Log2n) cost for the sort with an additional O(n) for the search. This is the best that can be done without using a technology such as hashing which you will use for your next lab. Inside your method to find the dupe you must sort the array first. Do not define/use any new type or data structure that we have not covered yet. Your traversal of the array looking for the dupe should require no more than one pass. Be as efficient as you can without breaking rule #2. Assuming the array below, the 1st occurrence of a duplicate is at index 4, not 3, since the element at [4] is the first index position where that value was seen for a second time. Be sure you understand this. Do not report the index of the first occurrence of a value as being the index where the duplicate occurred. Your job will be to fill in the definitions of these methods below main static int[] upSizeArr( int[] fullArray ); // incoming array is FULL. It needs it\'s capacity doubled static String[] upSizeArr( String[] fullArray ); // incoming array is FULL. It needs it\'s capacity doubled static int indexOfFirstDupe( int[] arr, int count ); // returns ind of 1st occurrence of duplicate value static int indexOfFirstDupe( String[] arr, int count ); // returns ind of 1st occurrence of duplicate value Here is the starting file! Solution HI, Please find my implementation of all required methods. Please let me know in case of any issue. /* Lab4.java Reads two files into two arrays then checks both arrays for dupes */ import java.io.*; import java.util.*; public class Lab4 { static final int INITIAL_CAPACITY = 10; static final int NOT_FOUND = -1; // indexOfFirstDupe returns this value if no dupes found public static void main (String[] args) throws Exception { // ALWAYS TEST FIRST TO VERIFY USER PUT REQUIRED INPUT FILE NAME ON THE COMMAND LINE if (args.length < 1 ) { Syst.

I need help with this program for java.The program you are given t.pdf

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Harrison works in a cubicle at a window next to Karen Ravenwood\'s cubicle at Tabernacle Insurers. One day, Harrison overhears Karen\'s supervisor make a comment that she\'d be more successful if she spent as much time on shaping her list of prospective customers as she does on shaping her body. Karen files a complaint of sex/gender discrimination with the EEOC and Harrison is called to testify during the gation. The EEOC decides not to pursue the matter. A month and a half after the investigation is closed, Tabernacle management moves Harrison from his cubicle to a cubicle on a vacant floor. All other aspects of his job remain the same. Harrison files a complaint of retaliation. 0 a. Harrison cannot pursue a case of retaliation because the relocation of his work area between cubicles did not materially affect the terms, conditions, or privileges of his employment at Tabernacle Ob. Harrison cannot prove a case of retaliation because he is not in the same protected group as Karen Harrison cannot prove a case of retaliation because the investigation uncovered no wrongdoing d. Harrison can prove a case of retaliation Solution Answer d. Harrison can prove this as a case of retaliation, even if the investigation of Karen\'s case didn\'t prove anything. To prove this Harrison need to show that i) moving him to the vacant floor wasn\'t a strategic decision. ii) If he\'d be in the same position as earlier, there wouldn\'t be any change in the performance of the organization or the organization needn\'t change his position to get better output from him. iii) He needs to show that he is the only one who has been moved to that floor and nobody else was moved..

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Hi there I am having difficulty in finalizing my Tetris game , below I posted the codes for the classes and I need the rest six pieces to be done. Can anybody help me here. It is a java code and must use the code I posted bellow. Thanks, Completing Tetris [Description: shapes] Overview You will be completing the game Tetris. The features needed are 1. Adding the other 6 pieces 2. Adding the ability to rotate the pieces Concepts The purpose of this assignment is to gain experience with the following new concepts: inheritance/class hierarchy dynamic dispatch algorithms If you were not able to complete homework 1, please come see me to get a working solution. Implementation Requirements OTHER PIECES: The first step in the assignment is to add the other six pieces. Lets think a little about the planning though; we don\'t want the Game class to have to know about all 7 different piece types (we wouldn\'t want Game to have 7 different instance variables, 1 for each type. How would it keep track of which one was current?) Instead, Game should know about 1 type (a super type) and let dynamic dispatch do the work for us. So to start, we need to redesign (or refactor) the current code. To do this, we want a super class that contains everything common to all pieces; then sub classes for the individual pieces and their individual needs. So what is the same about all the pieces? the state currently handled by LPiece is common to all pieces all the behaviors currently in LPiece are common to all pieces (except the constructor of course) What is different about each piece: How each individual playing piece is constructed The implementation of how each rotates (the second feature for this assignment) 1) Therefore, start by breaking up the LPiece.java class into a super class and sub class. At this point, test your program. It should run as it did before. 2) Now its time to add the other game pieces. You will need to figure out how to initialize the pieces. This will be similar to how the L-shaped piece was done, and, in fact, you may find it helpful to start each new class by copying the code from a previous shape and modifying it. The pieces should be initialized in the following orientations: [Description: shapes] In the Game class, the piece instance variable must have a new type. What do you think it should be? You\'ll need to modify the Game class so that it doesn\'t always instantiate an LPiece piece, but randomly chooses which shape to instantiate. (I strongly recommend creating 1 new shape at a time and testing.) ROTATION: The current tetris piece needs to be able to rotate in quarter turns clockwise each time the \'r\' key is pressed. As an example see the figure below illustrating how the L-shaped piece rotates: [Description: Lrotate] Here is where dynamic dispatch will come in handy since each shape class must have its own rotate implementation. Update the existing classes (super and sub classes) to enable dynamic dispatch to work properly. Modify.

Hi there I am having difficulty in finalizing my Tetris game , below.pdf

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I need help creating a parametized JUnit test case for the following class. import java.util.Arrays; import java.util.Collections; import java.util.LinkedList; import java.util.List; import static java.lang.Integer.valueOf; public class IntegerSet { /** * The only instance variable in the class. No other variables allowed. */ private List list; public int size() { return list.size(); } public boolean isEmpty() { return list.isEmpty(); } /** * Initializes the empty set. */ public IntegerSet() { list = new LinkedList(); } /** * Initializes a set with the numbers in the argument. */ public IntegerSet(Integer[] integers) { this(); if (integers == null) { throw new NullPointerException(\"The argument cannot be null\"); } else { for (Integer i : integers) { if (!exists(i)) { this.insertElement(i); } } } Collections.sort(list); } /** * Inserts an integer to the set if the integer does not exist in the set */ public void insertElement(int i) { if (!list.contains(i)) { list.add(i); } } /** * Inserts to the set all the integers in the argument which do not exist in * the set. */ public void insertAll(Integer[] data) { if (data == null) { throw new NullPointerException(\"The argument cannot be null\"); // throw new // IllegalArgumentException(\"The argument cannot be null\"); } else { Arrays.sort(data); for (Integer num : data) { if (!exists(num)) { insertElement(num); } } } } /** * Deletes an integer from the set if it exists in the set. */ public void deleteElement(int i) { list.remove(i); } /** * Deletes all the elements in the set. */ public void deleteAll() { list.clear(); } /** * Returns true if the argument exists in the set, false otherwise. */ public boolean exists(int i) { return list.contains(i); } public String toString() { char delimiter = \' \'; String str = \"[\"; for (Integer i : list) { str += i; str += delimiter; } return str + \"]\"; } /** * Finds the union of two sets. A null pointer is considered an empty set. * * Return \"new IntegerSet()\" when the result is an empty set. */ public static IntegerSet union(IntegerSet set1, IntegerSet set2) { IntegerSet union = new IntegerSet(); if (set1.isEmpty() && set2.isEmpty()) { return union; } if (!set1.list.isEmpty()) { for (Integer num : set1.list) { if (!union.list.contains(num)) { union.list.add(num); } } } if (!set2.isEmpty()) { for (Integer num : set2.list) { if (!union.list.contains(num)) { union.list.add(num); } } } return union; } /** * Finds the intersection of two sets. A null pointer is considered an empty * set. * * Return \"new IntegerSet()\" when the result is an empty set. */ public static IntegerSet intersection(IntegerSet set1, IntegerSet set2) { IntegerSet intersection = new IntegerSet(); // check for null pointers if (set1.list.isEmpty() || set2.list.isEmpty()) { return intersection; } for (Integer num : set1.list) { if ((!intersection.list.contains(num)) && set2.list.contains(num)) { intersection.list.add(num); } } return intersection; } /** * Builds an array with the ele.

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How do the genomes of Archaea and Bacteria compare? Drag and drop the phrases on the left to complete the sentences on the right. Part D Genome size of Archaea versus Bacteria How do the genomes of Archaea and Bacteria compare? Drag and drop the phrases on the left to complete the sentences on the right. Reset Help is/are larger than 1. Just by knowing that the Thaumarchaeota are Archaea, it isare smaller than those of s possible to predict that their genomes islare less complex than may contain a lower most Bacteria. proportion of coenzyme genes than 2. Just by knowing that N. equitans is a parasite, it is may contain more than those of unidentified genes than possible to predict that its genome most other hyperthermophiles. 3. Just by knowing that a bacterium is a autotroph, it is than those of possible to predict that its genome average heterotrophs. Hints My Answers Give Up Review Part Submit Genomic analyses can be extremely useful in learning a great deal about microbes and may eventually lead to more definite conclusions about differences between Archaea and Bacteria. These analyses can also be used at a larger scale. Metagenomics involves studying all of the genetic material in an environment, not just that in individual species. Solution (1) Archaea contain more unidentified genes than bacteria. Therefore, Just by knowing that the Thaumarchaeota are Archaea, it is possible to predict that their genomes (may contain more unidentified genes than) those of most Bacteria. (2) Parasites are smaller in size than hyperthermophiles. Therefore, Just by knowing tha N. equitans is a parasite, it is possible to predict that its genome (is/are smaller than) those of most other hyperthermophiles. (3) Genome of an autotroph is larger than a heterotroph. Therefore, Just by knowing that a bacterium is an autotroph, it is possible to predict that its genome ( is/are larger than) those of average heterotrophs..

How do the genomes of Archaea and Bacteria compare Drag and drop th.pdf

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General question: How would the technology affect who lives and who dies? Solution due to the technology there will be both good and bad also who lives ..? technology became the man\'s sophisticated tool ,with out technology man will lag , how man will get benifited from the technology.? (iam giving some of the example how man is living with the help of technologies) some of the major area\'s are 1)Medical --there is lot improvement in the medical sciencs which help the human to restore his health 2)transport--the travelling time of the man decreases due to the technology improvement in transportation 3)chemical -- due to the improvement in the technology of the chemical industries like creating more sophistictaed material which will help man 4)computer science-- man is getting benifited in most possible ways by the computer technologies who dies..? due to the increasing of the technology there is an effect on the both human and wild life ,sea creatures also 1)as technology increases the pollution also increases due to the pollution many sea ccreature are dying as well as wild life also 2)there is an effect onn human also because as the days going on the life span of the human being is decreases and getting new diseases due to the pollution 3)man is gettig obesity due to the increasing of comforts.

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Describe how partial diploids can be produced in E. coli. Solution Patial diploids can be produced by the transfer of genetic material of Hfr cell to an F- cell through conjugation.When Hfr mates with F- cell through conjugation the chromosome acts as a rolling circle transferring part of its genetic material across a conjugation bridge.Very rarely whole portion of DNA is transferred,resulting very low chance of passing of F factor to the F- cell.After that F- cell will contain part of Hfr,the exogene and its own genomic material the endogene,at this stage the cell is called partial diploid..

Describe how partial diploids can be produced in E. coli.Solutio.pdf

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A single layer of gold atoms lies on a table. The radius of each gold atom is about 1.5×1010 m, and the radius of each gold nucleus is about 7.0×1015 m. A particle much smaller than the nucleus is shot at the layer of gold atoms. Roughly, what is its chance (probability p) of hitting a nucleus and being scattered? (The electrons around the atom have no effect.) Solution So we can estimate the probability neglecting the detailed crystal structure of the gold layer but only from consideration of a single atom. The probability will be proportional to area of the obstacle, so assuming circularity p=area of nucleus/area of the atom=(radius of the nucleus)^2/(that of the atom)^2=2.2*10^(-9).

A single layer of gold atoms lies on a table. The radius of each gol.pdf

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An erect object is 25 cm from a concave mirror of radius 30 cm. The .pdf

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Answer the following 3 questions.... What is the difference between Generation 1 and Generation 2 VMs? What are some potential problems you might encounter when attempting to install a non-Microsoft operating system into a Hyper-V virtual machine? Based on your answer for question 6, can you identify any reasons why the specific distribution and version of Linux used in the lab was selected? Solution The new features in system enter machine manager 2012 R2 was the addition of generation-1 and generation-2 virtual machines. Differences between gen-1,gen-2: ->Generation 2 virtual machines has faster boot time,fewer devices and boot from SCSI virtual driver. In Generation -1 hast slower boot time comared to Generation-2 virtual machine and and it canot boot from SCSI virtual driver. ->Generation-1 supports legacy drivers and uses Hyper-V Bios based architecture. Generation-2 supports UEFI based architecture,in which a subset of integration service components has been included to allow SCSI controller to initialize before. The operating system starts loading. ->Generation-2 virtual machine no oger loads the legacy drivers Generation-1 virtual mechine supprots legacy drivers. ->A Generation-2 virtual machine provides the functionalities over a Generation-1 virtual machines. ->In Generation -1 of Hyper -V was not possible to boot from a SCSI virtual drive. But,in windows server 2012 R2 supports to boot from SCSI virtual hard drive. ->In Generation-1 virtual machines,if you wanted to install operating system using network boot,you were required to install the legacy network adapter after the installing the operating system. But, in Generation-2 virtual mechines is now possible to install guest operating system by connecting to remote installation service using the PXE boot option. ->In Generation-2 virtual machines by default enabled secure boot.this feature prevent unauthorized firm ware(or)UEFI drivers from running at boot time. ->Gen-1 virtual machines can only load legacy IDE drivers for initilizing file system. But Gen-2 virtual mecgines provides suport for VMBUS driver at the boot. ->In Gen-1 virtual machine created will always use device emulation unless integration service components have been installed. But,in Gen-2 the operating system is provided with the synthetic drivers which enables operating system to use SCSI drivers at the boot. ->There are fewer devices running inGeneration-2 virtual machine compared to Generation-1 virtual machine.This is because supprot for emulate drivers such as IDE and legacy network adaptors have been removed and replaced with VMBUS drivers. ->Generation-2 virtual machines as comapare to Generation-1 virtual machine.There are no options to add/configure IDE conrollers. ->Generation-2 virtual machines are more efficient than Generation-1 virtual machines..

Answer the following 3 questions.... What is the difference between .pdf

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1 pts D Question 12 In the decision making process, top level managem.pdf

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Classify each of the following as a Lewis acid or a Lewis base. Lewis acids Lewis bases Solution All cations are lewis acids A molecules central atom contains in complete octet are lewis acids multiple bonds between atoms of dissimilar electronegativities are lewis acids All anions are lewis bases A molecules central atom contains lone pair of electrons are lewis bases Lewis acids Lewis bases AlCl3, Fe^2+,CO2 OH^- , NH3, Br^- , CO.

Classify each of the following as a Lewis acid or a Lewis base. Lewi.pdf

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1.1. Find the Binary representation for the name Biniam from ASCII t.pdf

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(c) Is Mass Marketing still relevant? Consider the continuum from mass marketing (one message to all consumers, as in a television advertising) to targeted marketing (with identified segments receiving tailored marketing messages), to one-to-one marketing (with each consumer receiving a personalized message). With the changes in communication technology in recent years, do you think that mass marketing is still relevant? Can it be effective in a world of computers, cell phones, and tablets? Solution Mass marketing is still relevant. The reason is that vast no. Of people still prefer watching television and that too for news and entertainment. Also for some people TV ads by outstanding channels may be more reliable than some Facebook or Web page with which they are not much familiar and which they trust less. This is particularly true considering the vast amount of fake advertisements on Internet which are nothing more than spam and other instruments which try to steal personal information of people. Further if company is reliable people will flock to it through any medium. Also people do not always check their email etc. The need of the hour is combination of two rather than depending on only one..

(c) Is Mass Marketing still relevantConsider the continuum from m.pdf

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1)what are the relevant facts? 2)what are the ethical issues? 3)who are the primary stakeholders? 4)what are the possible alternatives? 5) what are the ethics of the alternatives? 6)what are the practical constraints? 7) what actions should be taken? Case 3: Victoria, a recent college graduate, recently started a new job as an analyst at a boutique investment bank. The office is a small, all- male environment, known as \"The Bullpen.\" After her first two months at work, the company is set to hold its annual summer outing. As the outing is some distance from her house, Victoria is pleased when one of the executives, Luke, offers to drive her home. During the drive, Luke invites Victoria for \"a casual dinner.\" She feels pressured to accept. Since they are currently working together on a deal, she hopes that the dinner will be a great opportunity to collaborate on business. Instead, she is ill at ease when Luke continuously brings up personal matters. Back in the car, Luke is even more insistent that Victoria comes to his house. She is extremely uncomfortable, but sees no way out of the situation, feeling as if she cannot decline. At his house, Luke makes a direct advance toward Victoria. By this point she has had enough and is visibly upset. Immediately, she confronts Luke as to why he is placing her in such an inappropriate situation. Victoria then calls a cab and departs, mulling over her options. Victoria is unsure what action to take. Her first two months on the job were going so well and she wonders what impact this incident will have on her work environment. She does not feel comfortable approaching her firm\'s HR department, a one-man operation who seems to exhibit and condone the firm\'s \"bullpen\" attitude. Victoria fears that if she does not speak up the advances will continue, but considering that she has to work with Luke on their current deal, she wonders if forgetting the incident will make it go away faster. What should Victoria do? Solution 1)what are the relevant facts? 2)what are the ethical issues? 3)who are the primary stakeholders? The organization - HR, Victoria, and, Luke 4)what are the possible alternatives? 5) what are the ethics of the alternatives?.

1)what are the relevant facts2)what are the ethical issues3)wh.pdf

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