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Implicit & Explicit Forms
Implicit Form

xy = 1

Explicit Form

1
−1
y= =x
x

Explicit: y in terms of x
Implicit: y and x together

Differentiating: want to be able to use either

Derivative

dy
1
−2
= −x = − 2
dx
x
Differentiating with respect to x

Derivative →

d
dx

Deriving when denominator agrees → use properties
Deriving when denominator disagrees → use chain rule & properties

( )

8x

( )

dy
6y
dx

d
4x 2 =
dx
d
3y 2 =
dx

Denominator agrees properties

Denominator disagrees –
chain rule
Implicit Differentiation
Trying to find

dy
dx
Derive Explicitly
x 2 + y2 = 5
y = ± 5 − x2
dy
1
=
× −2x )
(
2
dx ±2 5 − x
dy
−x
=
dx ± 5 − x 2
sin ce y = ± 5 − x 2
dy −x
=
dx
y

Derive Implicitly

x 2 + y2 = 5
dy
2x + 2y = 0
dx
dy
2y = −2x
dx
dy
y = −x
dx
dy − x
=
dx y
Derive implicitly:

y = 3xy 4
dy
4
3 dy
= 3×y + 4y
3x
dx
dx
dy
3 dy
− 4y
×3x = 3×y 4
dx
dx
dy
1− 4y3 3x ) = 3×y 4
(
dx
dy
1− 12xy3 = 3×y 4
dx

(

)

4

dy
3×y
=
dx ( 1− 12xy3 )
Example: Find the derivative

x 3 − 2 x 2 y + 3 xy 2 = 38

dy 2   2
dy 
2
3x −  4xy + 2x ÷+  3y + 2y 3x ÷= 0

 
dx
dx 
dy 2
dy
2
2
3x − 4xy − 2x + 3y + 2y 3x = 0
dx
dx
dy
2 dy
−6xy + 2x
= 3x 2 − 4xy + 3y 2
dy dx
2dx
2
2
−6xy + 2x = 3x − 4xy + 3y
dx

(

)

dy 3x − 4xy + 3y
=
dx
−6xy + 2x 2 )
(
2

2
Example: Determine the slope at the point (1,1)

x + y = 2 xy
3

3

dy
dy
3x + 3y
= 2y + 2x
dx
dx
dy
2 dy
3y
− 2x
= 2y − 3x 2
dx
dx
2

2

dy
3y 2 − 2x ) = 2y − 3x 2
(
dx
dy
2y − 3x
=
dx ( 3y 2 − 2x )
2

dy
dx

x=1
y=1

dy
dx

x=1
y=1

2 × 3× 2
1− 1
=
3× 2 − 2 × )
( 1 1
=

−1
= −1
1

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4.2 derivatives of logarithmic functions

  • 1.
  • 2. Implicit & Explicit Forms Implicit Form xy = 1 Explicit Form 1 −1 y= =x x Explicit: y in terms of x Implicit: y and x together Differentiating: want to be able to use either Derivative dy 1 −2 = −x = − 2 dx x
  • 3. Differentiating with respect to x Derivative → d dx Deriving when denominator agrees → use properties Deriving when denominator disagrees → use chain rule & properties ( ) 8x ( ) dy 6y dx d 4x 2 = dx d 3y 2 = dx Denominator agrees properties Denominator disagrees – chain rule
  • 5. Derive Explicitly x 2 + y2 = 5 y = ± 5 − x2 dy 1 = × −2x ) ( 2 dx ±2 5 − x dy −x = dx ± 5 − x 2 sin ce y = ± 5 − x 2 dy −x = dx y Derive Implicitly x 2 + y2 = 5 dy 2x + 2y = 0 dx dy 2y = −2x dx dy y = −x dx dy − x = dx y
  • 6. Derive implicitly: y = 3xy 4 dy 4 3 dy = 3×y + 4y 3x dx dx dy 3 dy − 4y ×3x = 3×y 4 dx dx dy 1− 4y3 3x ) = 3×y 4 ( dx dy 1− 12xy3 = 3×y 4 dx ( ) 4 dy 3×y = dx ( 1− 12xy3 )
  • 7. Example: Find the derivative x 3 − 2 x 2 y + 3 xy 2 = 38  dy 2   2 dy  2 3x −  4xy + 2x ÷+  3y + 2y 3x ÷= 0    dx dx  dy 2 dy 2 2 3x − 4xy − 2x + 3y + 2y 3x = 0 dx dx dy 2 dy −6xy + 2x = 3x 2 − 4xy + 3y 2 dy dx 2dx 2 2 −6xy + 2x = 3x − 4xy + 3y dx ( ) dy 3x − 4xy + 3y = dx −6xy + 2x 2 ) ( 2 2
  • 8. Example: Determine the slope at the point (1,1) x + y = 2 xy 3 3 dy dy 3x + 3y = 2y + 2x dx dx dy 2 dy 3y − 2x = 2y − 3x 2 dx dx 2 2 dy 3y 2 − 2x ) = 2y − 3x 2 ( dx dy 2y − 3x = dx ( 3y 2 − 2x ) 2 dy dx x=1 y=1 dy dx x=1 y=1 2 × 3× 2 1− 1 = 3× 2 − 2 × ) ( 1 1 = −1 = −1 1
  • 9. x + y = 2 xy 3 3 dy 2y − 3x = 2 dx ( 3y − 2x ) 2 dy dx x=1 y=1 −1 = = −1 1
  • 10. x + y = 2 xy 3 3 dy 2y − 3x = 2 dx ( 3y − 2x ) 2 dy dx x=1 y=1 −1 = = −1 1