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Chain Rule
Chain Rule
This rule is used to differentiate composite functions.
4
For example y=(3x+2)
Chain Rule method
n
If y=u , where u is
expressed in terms x.
Then
dy dy du
=
dx du dx
4
y=(3x+2) , then u=3x+2 and 3
du
dx
=
4
3 3
y=u
=4u 4(3 2)
dy
x
du
= +
3 3dy
= =4(3x+2) 3=12(3x+2)
dx
dy du
du dx
4
Differentiate y=(3x+2)
2
Find the derivative of x +1
1
2 2
y=(x +1)
2
Let u=x +1
du
=2x
dx
1
2
1
-
2
2
1 1
2 2 1
y u
dy
u
du x
=
= =
+
2 2
dy dy du 1 x
= = .2x=
dx du dx 2 x +1 x +1
5
2
2
Differentiate y= , 1.
1
x
with respect to x when x
x
 
= ÷
+ 
2
2x
Let u=
x +1 2 2 2 2
2 2 2 2 2 2
du (x +1)(2)-2x(2x) 2x +2-4x 2 2
= =
dx (x +1) (x +1) ( 1)
x
x
−
=
+
5
4
4
2
y=u
dy 2x
=5u =5
du x +1
 
 ÷
 
4 2
2 2 2
dy dy du 2x 2 -2x
= =5
dx du dx x +1 (x +1)
  
 ÷ ÷
   
dy 2
When x=1,then =5 (0)=0
dx 2
 
 ÷
 
Differentiate the following exercises
with respect to x:
3
4 5
4
2
1. (1+7x) Leaving CertificateHigher paper1 2005 no6(a)(i)
2. (x 1) Leaving CertificateHigher paper1 2002 no6(a)(i)
3. If y= 3 5, what is ?
2 5
4. If y= , hat is ?
1
5. If y= , hat is
2 5
dy
x
dx
x dy
w
x dx
dy
w
x
+
+
+ 
 ÷
 
 
 ÷
+ 
?
dx

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P9 chainrule

  • 2. Chain Rule This rule is used to differentiate composite functions. 4 For example y=(3x+2)
  • 3. Chain Rule method n If y=u , where u is expressed in terms x. Then dy dy du = dx du dx
  • 4. 4 y=(3x+2) , then u=3x+2 and 3 du dx = 4 3 3 y=u =4u 4(3 2) dy x du = + 3 3dy = =4(3x+2) 3=12(3x+2) dx dy du du dx 4 Differentiate y=(3x+2)
  • 5. 2 Find the derivative of x +1 1 2 2 y=(x +1) 2 Let u=x +1 du =2x dx 1 2 1 - 2 2 1 1 2 2 1 y u dy u du x = = = + 2 2 dy dy du 1 x = = .2x= dx du dx 2 x +1 x +1
  • 6. 5 2 2 Differentiate y= , 1. 1 x with respect to x when x x   = ÷ +  2 2x Let u= x +1 2 2 2 2 2 2 2 2 2 2 du (x +1)(2)-2x(2x) 2x +2-4x 2 2 = = dx (x +1) (x +1) ( 1) x x − = + 5 4 4 2 y=u dy 2x =5u =5 du x +1    ÷   4 2 2 2 2 dy dy du 2x 2 -2x = =5 dx du dx x +1 (x +1)     ÷ ÷     dy 2 When x=1,then =5 (0)=0 dx 2    ÷  
  • 7. Differentiate the following exercises with respect to x: 3 4 5 4 2 1. (1+7x) Leaving CertificateHigher paper1 2005 no6(a)(i) 2. (x 1) Leaving CertificateHigher paper1 2002 no6(a)(i) 3. If y= 3 5, what is ? 2 5 4. If y= , hat is ? 1 5. If y= , hat is 2 5 dy x dx x dy w x dx dy w x + + +   ÷      ÷ +  ? dx