moles of Al = 12/27 Since chlorine is in excess , Moles of Alcl3 = 12/27 * 1 = 4/9
Solution
moles of Al = 12/27 Since chlorine is in excess , Moles of Alcl3 = 12/27 * 1 = 4/9.
moles of Al = 1227 Since chlorine is in excess ,.pdf
1. moles of Al = 12/27 Since chlorine is in excess , Moles of Alcl3 = 12/27 * 1 = 4/9
Solution
moles of Al = 12/27 Since chlorine is in excess , Moles of Alcl3 = 12/27 * 1 = 4/9