What could be the arguments of a production functionA Cost and La.pdf

•

0 likes•2 views

What could be the arguments of a production function? A Cost and Labor B Profit and Prices C Output and Profit D Capital and Labor E Any of the above Solution Option D The production function relates the combination of output represented at various combinations of labor and inputs. It tells on at what levels of capital and labor does maximise the ouput using capital and labor as the inputs..

Education

More from deepaksatrker

What are electromagnetic waves? Solution We are encompassed by waves we can see and listen, from sea waves to sound waves. A wave demonstrates the exchange of vitality, from the wind that begins a sea wave to the sound that travels through the air to your ear drum. Waves that go through a physical protest or medium are called mechanical waves. Dissimilar to mechanical waves, electromagnetic waves needn\'t bother with a medium to travel or spread. Electric and attractive fields both deliver vibrations and, together, the two sorts of vitality make electromagnetic waves. Waves take distinctive shapes, yet electromagnetic waves all have a snake-like shape, which makes them transverse waves. Transverse waves are measured by their tallness, or sufficiency, and by their wavelength, or the separation between the most astounding purpose of one wave, the peak, to the peak of the following wave. The most reduced purpose of a wave is known as a trough. Trough to trough can be measured, as well. While dissecting an electromagnetic wave, both the plentifulness and separation between waves is measured. One entire wave, from peak to peak, or trough to trough, is known as a cycle. The quantity of cycles that happen every second is the wave\'s recurrence. Out of appreciation for Heinrich Hertz, we measure recurrence in hertz or Hz. Electromagnetic waves will be waves which can go through the vacuum of space. Mechanical waves, not at all like electromagnetic waves, require the nearness of a material medium keeping in mind the end goal to transport their vitality starting with one area then onto the next. Sound waves are cases of mechanical waves while light waves are cases of electromagnetic waves. Electromagnetic waves are made by the vibration of an electric charge. This vibration makes a wave which has both an electric and an attractive segment. An electromagnetic wave transports its vitality through a vacuum at a speed of 3.00 x 108 m/s (a speed esteem ordinarily spoke to by the image c). The proliferation of an electromagnetic wave through a material medium happens at a net speed which is under 3.00 x 108 m/s. This is portrayed in the liveliness underneath. The instrument of vitality transport through a medium includes the assimilation and reemission of the wave vitality by the molecules of the material. At the point when an electromagnetic wave encroaches upon the molecules of a material, the vitality of that wave is retained. The retention of vitality causes the electrons inside the iotas to experience vibrations. After a brief time of vibrational movement, the vibrating electrons make another electromagnetic wave with an indistinguishable recurrence from the main electromagnetic wave. While these vibrations happen for just a brief timeframe, they defer the movement of the wave through the medium. Once the vitality of the electromagnetic wave is reemitted by a molecule, it goes through a little locale of space between particles. When it achieves the foll.

What are electromagnetic wavesSolutionWe are encompassed by w.pdf

deepaksatrker

Using Rust Because postfix expressions are simpler and faster to evaluate, compilers transform infix expressions in source programs to postfix expressions in executable programs. You will implement this transformation. ## Infix expressions An infix expression contains one or more of the following tokens: * Operands: integers, such as `1`, `-23`. * Operators: arithmetic operators `+`, `-`, `*`, and `/` with their normal association and precedence. * Left and right parentheses. A valid infix expression must satisfy all the following rules: * An operand or left parenthesis cannot be preceded by an operand or right parenthesis. * An operator or right parenthesis cannot * be the first token in the expression, or * be preceded by an operator or left parenthesis. * An operator or left parenthesis cannot be the last token in the expression. * Each left parenthesis must match a unique right parenthesis, and vice versa. ## Transform infix to postfix expression 1. Create a stack. 2. Scan the tokens in the infix expression. * If the token is an operand, output it. * If the token is a left parenthesis, push it onto the stack. * If the token is a right parenthesis, pop and output all the operators from the stack until encountering a left parenthesis. Pop and discard the left parenthesis. * If the token is an operator * If the stack is empty, push the token onto the stack. * Otherwise, if the top of the stack is an operator and its precedence is greater than or equal to the precedence of the token, pop and output the operator from the stack, and repeat this process. Finally, push the token in the infix expression onto the stack. 3. Pop and output all the remaining tokens on the stack. ## Public API Your program must provide the following public API. ``` #[derive(Clone, Copy, Debug, PartialEq)] pub enum Operator { // `+` Add, // `-` Sub, // `*` Mul, // `/` Div, } #[derive(Debug, PartialEq)] pub enum InfixToken { Operator(Operator), Operand(isize), LeftParen, RightParen, } #[derive(Debug, PartialEq)] pub enum PostfixToken { Operator(Operator), Operand(isize), } /// Transforms an infix expression to a postfix expression. /// /// If the infix expression is valid, outputs `Some(_)`; /// otherwise, outputs `None`. pub fn infix_to_postfix(tokens: &[InfixToken]) -> Option> { unimplemented!(); } Solution #[derive(Clone, Copy, Debug, PartialEq)] pub enum Operator { // `+` Add, // `-` Sub, // `*` Mul, // `/` Div, } #[derive(Debug, PartialEq)] pub enum InfixToken { Operator(Operator), Operand(isize), LeftParen, RightParen, } #[derive(Debug, PartialEq)] pub enum PostfixToken { Operator(Operator), Operand(isize), } /// Transforms an infix expression to a postfix expression. /// /// If the infix expression is valid, outputs `Some(_)`; /// otherwise, outputs `None`. pub fn infix_to_postfix(tokens: &[InfixToken]) -> Option> { let mut stack: Vec = vec![]; let mut output: Vec = vec![]; ////////////////////////////////// VALIDATION /////////////////////////////////////////////.

Using RustBecause postfix expressions are simpler and faster to ev.pdf

deepaksatrker

tnt en Assignment Nickele Company reoorts net income of sae,4n0 in 2014 However ending inventory was understuted be .30 What is the correctinet income for 20 14 2z e correct net income What offuct. it any will this error have on total asets as reourted in the balance shest at December 31, 20n 014 IRNil in the balance sheet will be by the amount that ending inventory is Solution 1. Net Income for 2014 = $86,440 + $7,220 = $93,660 2. Total Assets in the balance sheet will be Understated by the amount that ending inventory is Understated, $7,220 *Note - Image is not clearly visible so I took understated amount as 7,220, if it is 7,320 then please drop a comment..

tnt en Assignment Nickele Company reoorts net income of sae,4n0 in .pdf

deepaksatrker

This file contains a complete array-based MultiSet, but not the code needed to support its Iterator. Complete the Iterator\'s next() and hasNext() methods. Solution Hi, I have implemented both required methods. Please let me know in case of any issue. import java.util.Collection; import java.util.Iterator; public class ArrayMultiSet implements Collection { /** Array in which the elements in this multiset are stored. */ private E[] _store; /** * Array indices below this amount contain the active elements in this collection. */ private int _size; /** * Modification counter used to preserve the fail-fast nature of its iterators. */ private long _modCount; /** * Create a new empty multiset. */ public ArrayMultiSet() { _modCount = 0; clear(); } /** * Remove all of the elements within the instance and invalidate any current iterators. */ @SuppressWarnings(\"unchecked\") @Override public void clear() { _store = (E[]) (new Object[16]); _size = 0; // maintains the class invariant } /** * Update the multiset so that it includes all of the elements from before the call AND the given element. * * @param e Item to be added to this collection. */ @SuppressWarnings(\"unchecked\") @Override public boolean add(E e) { // Check if we do not have enough space in the underlying array to store the // new element if (_size == _store.length) { // We do not have space, so create a new larger space (doubling the size // is the most time efficient) E[] newStore = (E[]) new Object[_store.length * 2]; // Copy all of the references into the new array for (int i = 0; i < _store.length; i++ ) { newStore[i] = _store[i]; } _store = newStore; // An easier, more efficient way of coding this (but less useful for // teaching) would instead be: // _store = Arrays.copyOf(_store, _store.length * 2); } // Add the element to the store _store[_size] = e; // Finally, we can increase _size, since this change will no longer violate // any class invariants. _size += 1; return true; } /** * Return true if at least one element in the multiset is equal to the given object. When {@code obj} is null, it must * use the {@code ==} operator to perform these checks, but when {@code obj} is not null, the {@link Object#equals} * method is used. * * @param obj Object (or null) for which we will search * @return {@code true} if {@code obj} was found; {@code false} if a match could not be found. */ @Override public boolean contains(Object obj) { // Only scan through _size, since those are the only \"real\" entries for the // multiset. for (int i = 0; i < _size; i++ ) { // When obj is null, we need to use == if ((obj == null) && (_store[i] == null)) { return true; } // Otherwise, we use .equals() to find a match else if ((obj != null) && obj.equals(_store[i])) { return true; } // No else clause, since the match could be at a higher index! } // Checked all VALID indices, so the result must be: return false; } @Override public int size() { return _size; } /** * Remove the element found at the given index. .

This file contains a complete array-based MultiSet, but not the code.pdf

deepaksatrker

The structure of a high temperature superconductor containing barium.pdf

deepaksatrker

The present value of $5,000 per year for three y FVA of $1 (Use appropriate factor(s) from the to True or False True Folse Solution True ,Present value = $5000 * PVAF (12%,3 years) = $5000 * 2.4018 = $5000 * 2.4018 = $12009 Note:- PVAF(12%,3 years) = [1 - (1+0.12)-3*1] / [0.12] =[1 - (1.12)-3] / 0.12 =[1 - 1/(1.12)3] / 0.12 =[1 - 1/1.404928] / 0.12 =0.288220/ 0.12 = 2.4018 So , PVAF(12%,3 years) = 2.4018.

The present value o.pdf

deepaksatrker

The Associated Handles section in Resource Monitor can be used to sh.pdf

deepaksatrker

T 5. A contract should be held enforceable even if a party is mistaken about the F value or quality of an item purchased. T F 6. A contract may be determined unenforceable if both parties were mistaken about an important fact, but not if only one party was mistaken. TF7. The contract defense of fraud requires some false statement of a factual nature. TF 8. A statement that no reasonable person would believe is probably not fraudulent. T F 9. Duress involves a statement by a person who has special influence over TF 10. Some contracts must be in writing to be enforceable. T F 11. Real estate contracts typically must be in writing to be enforceable. TF 12. A contract covered by the Statute of Frauds must be signed by both parties. T F 13. A party may be able to transfer their rights and duties under a contract to another, such as a trusted friend or advisor. another party T F 14. An award of punitive damages is very common for contract breach. T F 15. A party may be entitled to foreseeable damages beyond the contract itself but which result from a breach of the contract, such as lost profits. F 16. The party breaching a contract has a duty to mitigate the damages which will T result from his/her breach. T F 17. Liquidated damages are an agreed amount to be paid for a future breach. Solution 5. False: This is the case of unilateral mistake in a contract. Unilateral mistake occurs when one party is mistaken as to the subject matter or the terms contained in the contract. One party is mistaken and the other is not. Since only one party is mistaken it may lead to the unfair advantage of to the other party. Therefore when a contract was entered on the basis of unilateral mistake the contract may be liable to recession or reformation. Unilateral mistake commonly occurs in prices, quantities and description of goods and services. 6. False. If both the parties to an agreement are mistaken about the subject matter of the contract, such contract is void. 7. True: Fraud means concealment of a material fact or misrepresentation of a material fact. A fraud in contract occurred when one party of the contract presents information to another which is incorrect, deceitful or intend to confuse the other party. 8. True. Misrepresentation is a statement that no reasonable person would believe it to be true. 10. True. Contracts may be written or oral and both are enforceable. Oral contracts are very difficult to enforce because there is not clear record on the offer, consideration and acceptance. Therefore the law requires some agreement must be in writing in order to bind both the parties. Such agreements are agreement to pay debts, contract that takes longer than one year to complete, real estate lease for more than one year, contracts for above certain amount of money, contract which has duration over the life time of the party and transfer of property at the death of the party performing the contract. 11. True. The law requires some agreement must be in writing .

T 5. A contract should be held enforceable even if a party is mistake.pdf

deepaksatrker

Subject :- Project Management Describe what the WBS is and why you think it\'s important to create one. You have the option to research the web, textbook etc Solution Ans:- A work breakdown structure (WBS), inproject management and systems engineering, is a deliverable-oriented decomposition of a project into smaller components. A work breakdown structure is a key project deliverable that organizes the team\'s work into manageable sections. The Project Management Body of Knowledge (PMBOK) defines the work breakdown structure as a \"deliverable oriented hierarchical decomposition of the work to be executed by the project team.\" A work breakdown structure element may be aproduct, data, service, or any combination thereof. A WBS also provides the necessary framework for detailed cost estimating and control along with providing guidance for schedule development and control. A work breakdown structure lets project managers plan their work more efficiently. A project is characterized by time-limited activities and is assigned fixed time frames and costs. When it is finished, a project must fulfill the stakeholder needs it was designed to address. The project management has to plan for the schedule, the fixed costs and the functional completeness of the project and assign responsibilities. The WBS helps make this planning consistent and provides for effective project execution. Importance;- Tasks The main purpose of a WBS is to reduce complicated activities to a collection of tasks. This is important for the project manager because she can oversee the tasks more effectively than the complex activities. Tasks must be measurable and independent, with clearly defined limits. All the project work must be included in one of the tasks and the tasks must not include any non- project work. Costs Because the WBS tasks are measurable, the project management can assign specific costs to each task. The WBS lets project managers distribute the project budget into defined packages linked to the tasks and check to make sure that the task costs in total don\'t exceed the total project cost. Schedule The WBS is important for tracking progress in the project schedule. Because the WBS tasks have clearly defined limits, the project management can determine how advanced the project is by checking which of the tasks are finished. Even within each task, the project management can check for percent completion because each task is measurable..

Subject - Project ManagementDescribe what the WBS is and why you .pdf

deepaksatrker

Significant mass extinctions occurred during which of the following epochs? A.Pleistocene, Ordovician, and Triassic B.Ordovician, Triassic, and Jurassic C.Triassic, Permian, and Cretaceous D.Triassic, Permian, Cretaceous, Pleistocene, Ordovician, and Devonian E.Ordovician, Triassic, Jurassic, Silurian, Eocene, and Oligocene Solution Ans d triassic, permian, cretaceous pleistocene, ordovician, and devonian These are the largest mass extinctions in the earth history. Many species got extincted in short period of time..

Significant mass extinctions occurred during which of the following .pdf

deepaksatrker

SOLUTIONNotice thatt2becomes simpler when differentiated (wherease5tis mostly unchanged when differentiated or integrated), so we choose Thendu=u=dv=dtThendu=dtv= Find t^2e^5tdt. SOLUTION Notice that t^2becomes simpler when differentiated (whereas e^5t is mostly unchanged when differentiated or integrated), so we choose Integration by parts gives The integral that we obtained, te^5t dt, is simpler than the original integral but is still not obvious. Therefore, we use integration by parts a second time, this time withu=tanddv=e^5tdt. Thendu= Putting this in Equation 3, we get Solution t*T e^(5t)/5 - (2/5)[ te^(5t)/5 - e^(5t)/25 ] t*t e^(5t)/5 - (2/25) te^(5t) + 2/125 e^(5t) ].

SOLUTIONNotice thatt2becomes simpler when differentiated (wherease5t.pdf

deepaksatrker

Please help with the English test !!! Thank you very much! Identify the term that best describes the italic bold word 1.The teacher asked the class to stay put while she went to the office. a) transitive verb b) intransitive verb c) auxiliary verb d) linking verb 2. The ancient Greeks believed that the more people learn, the less they know. a) correlative conjunctions b) coordinating conjunctions 3. The committee decided that Pedro’s logo was the most appropriate representation of the organization’s mission. a)predicate nominative b)predicate adjective c)objective compliment d)direct object 4.Maintaining a perfect GPAbecome more important to him than athletics. a) appositive phrase b) infinitive phrase c) prepositional phrase d) gerund phrase 5. Developed by government scientists, the Internet is now part of everyday life. a) appositive phrase b) participle phrase c) gerund phrase d) infinitive phrase Identify the sentence structure. 6. Without her cat in her lap, she felt alone during the long ride. a)simple sentence b)compound sentence c)complex sentence d)compound-complex sentence 7. Today he is frail, but he still commands respect. a)simple sentence b)compound sentence c) complex sentence d)compound-complex sentence Solution 1) In the first question you forgot to mention Italic Bold letter, but I think STAY is the verb you meant to ask. In the first question the answer is Intransitive verb. let me explain it why. Definition: An intransitive verb has two properties. one, it is an action verb, expressing an activity which is doable e.g.:Come, go, eat, drink, sneeze, stand etc. Second, unlike a transitive verb, it won\'t have a direct object who is receiving the action. Example: Because of liver problems, Sameer always eats before leaving for office. 2) It\'s a correlative conjunction. Because correlative conjunctions are always in pairs and one will be related to another. Other examples are neither/or, Both/and, not only/but also, whether/or, neither/nor and sooner/than. 3) Direct object is the answer Because a direct object is followed by transitive verb, it can be nouns, pronouns, phrases, or clauses. 4) It is an Infinitive phrase. 5) It\'s a Participle phrase. other examples: The water drained slowly in the pipe clogged with dog hair. 6) It is clearly a Complex sentence, since complex sentences have one independent clause and at least one dependent clause. Without her cat in her lap is independent clause and she felt alone during the long ride. is a dependent clause. 7) This one is a Simple sentence..

Please help with the English test !!! Thank you very much!Identify.pdf

deepaksatrker

Name the process used to arrange fluorescent colored DNA segments in gel according to size. Solution Gel Elecrophoresis Electrophoresis enables you to distinguish DNA fragments of different lengths DNA is negatively charged, therefore, when an electric current is applied to the gel, DNA will migrate towards the positively charged electrode.The use of dyes, fluorescent tags or radioactive labels enables the DNA on the gel to be seen after they have been separated..

Name the process used to arrange fluorescent colored DNA segments in.pdf

deepaksatrker

1) the micronutrient calcium is often applied in the form of calcium.pdf

deepaksatrker

1) Which of the following can Spyware (1 poin and viruses not do to your computer? O Keep track of websites you visit O Erase or corrupt files O Record keystrokes O Install an alternate operating system Next Question Solution Answer- (d) Install an alternate operating system. Spyware can keep track of websites you visit and can also record keystrokes. A virus in computer may erase or corrupt files. Both spyware and viruses can not install an alternate operating system..

1) Which of the following can Spyware (1 poin and viruses not do to y.pdf

deepaksatrker

IV Answer the following uestions. 2 points each) Definition or Question Term or Answer Ribulose bisphosphate carboxylase (ie, Rubisco) refers to an gized state of a membrane usually formed ener through the action of electron transport chain Nicotinamide adenine dinucieotide (NAD) ews con term refers to a non-protein, highly hydrophobic electron transport carrier molecule that accepts and donates 2 electrons and protons Mixotrophy Flovoproleurs. term refers to proteins that assist in protein folding in cells RNA Polymerase II NA refers to inclusions widely found in phototrophs where they perform photoprotective roles Chaperones Fold ins are term refers to the membrane-enelosed compartments used in the anaerobic/anoxic oxidation of ammonia Solution Anammox is a microbial process of ammonium oxidation for nitrogen cycle which is a membrane enclosed compartments used in the anaerobic/anoxic oxidation of ammonia. Anoxygenic photosynthetic bacteria carry photons to perform photosynthesis. Cytochrome is a non protein which is highly hydrophobic electron transport carrier molecule. The energized state of a membrane formed by the result of charged molecules in electron transport chain is the Protein Motive Force..

IV Answer the following uestions. 2 points each) Definition or Questi.pdf

deepaksatrker

Interpret the following graph Your answer must include discussion of A) The principal (= most important) patterns depicted in the graph B) Some physiological and anatomical explanations for the (these) principal pattern(s) C) Evolutionary (fitness) implications of the pattern(s). That is why does the pattern exist? D) Is there evidence in the data to support the idea that the pattern(s) evolved for the purpose you suggested in your answer to question C. Metabolic rate (arbitary units) Polar bear cub Ground squirrel i i, Snow bunting Lemming Weasel Jungle rat Marmoset Human Monkey Raccoon Sloth Solution The metabolic rate of various organisms found in two different geographical location was studied with relation to the variation of temperature.The organisms choose for this study were from different groups like some were rodents while some were mammals .Birds were also studies A) As shown in the graph it is vary clear that the temperature exerts effect on metabolic rate. As the temperature increase the metabolic rate decrease and vice versa. B) Metabolic rate also affected due to body size, the small organisms have a higher metabolic rate as compare to larger animals. C) Organisms of Arctic area require the much lower temperature to attain a particular metabolic rate as compare to the tropical one which requires a higher temperature to attain the same metabolic rate.It can be explained as that the tropical organisms has adapted at a lower temperature while the tropical one adapted higher temperature as compare to Arctic one.After a particular temperature, the variation in metabolic rate become negilable.After this temprature, metabolic rate increase vary slowly and constantly with a sharp rise in temprature . Adaptation is the main reason for such type of pattern. D) For example, to attain 2 unit of metabolic rate jungle rat(Tropical mammal) requires approximately 18 oC while snow bunting can survive at -10o C with same metabolic rate due to their respective adaptation with their environment. o.

Interpret the following graphYour answer must include discussion o.pdf

deepaksatrker

In 1925, David Keilin used a simple spectroscope to observe the characteristic absorption bands of the cytochromes that participate in the electron-transport chain in mitochondria. A spectroscope passes a very bright light through the sample of interest and then through a prism to display the spectrum from red to blue. If molecules in the sample absorb light of particular wavelengths, dark bands will interrupt the colors of the rainbow. His key discovery was that the absorption bands disappeared when oxygen was introduced and then reappeared when the samples became anoxic. Subsequent findings demonstrated that different cytochromes absorb light of different frequencies. When light of a characteristic wavelength shines on a mitochondrial sample, the amount of light absorbed is proportional to the amount of a particular cytochrome present in its reduced form. Thus, spectrophotometric methods can be used to measure how the amounts of reduced cytochromes change over time in response to various treatments. If isolated mitochondria are incubated with a source of electrons such as succinate, but without oxygen, electrons enter the respiratory chain, reducing each of the electron carriers almost completely. When oxygen is then introduced, the carriers oxidize at different rates, as can be seen from the decline in the amount of reduced cytochrome (see Figure Q14-67). Note that cytochromes a1 and a3 cannot be distinguished and thus are listed as cytochrome (a1 + a3). How does this result allow you to order the electron carriers in the respiratory chain? What is their order? 100T add so succinate (a1 + a) H-a time b nuaouad) auaapoouO panpai Solution The order of the individual electron carriers in the chain was determined by sophisticated spectroscopic measurements. Many of the electron carriers in the respiratory chain absorb visible light and change color when they are oxidized or reduced. In general, each has an absorption spectrum and reactivity that are distinct enough to allow its behavior to be traced spectroscopically, even in crude mixtures. It was therefore possible to purify these components long before their exact functions were known. The sudden addition of oxygen shows the waves of increasing oxidation of the carriers are seen. In this result ,the cytochrome b has the highest degree of oxidation so that it comes first in order. From the result the order of of electron carrier is b,c1,c,(a1+a3)..

In 1925, David Keilin used a simple spectroscope to observe the char.pdf

deepaksatrker

i am finishing a project for my cs 0401 java course. I have completed everything for the project that requires us to sort and then using a binary search display a txt file read through the command prompt. For some reason when the program treads through the file the first element isnt sorted and just ends up being printed in front of all the other sorted elements. my code is: import java.util.*; import java.io.*; public class Project4 { static final int INITIAL_CAPACITY = 5; public static void main( String args[] ) throws Exception { // ALWAYS TEST FIRST TO VERIFY USER PUT REQUIRED INPUT FILE NAME ON THE COMMAND LINE if (args.length < 1 ) { System.out.println(\"\ usage: C:\\\\> java Project4 \ \ \"); // i.e. C:\\> java Project4 P4input.txt System.exit(0); } // LOAD FILE INTO ARR USING INSERINORDER Scanner infile = new Scanner( new File( args[0] ) ); int[] arr = new int[INITIAL_CAPACITY]; int count= 0; while (infile.hasNextInt()) { if ( count==arr.length ) arr = upSizeArr(arr); insertInOrder( arr, count++, infile.nextInt() ); } infile.close(); arr=trimArr(arr,count); // Now count == .length System.out.println( \"Sorted array of \" + arr.length + \" ints from \" + args[0] + \" after insertInOrder:\" ); printArray( arr ); // we trimmed it thus count == length so we don\'t bother to pass in count } // END MAIN // ############################################################################# ############################### // USE AS IS - DO NOT MODIFY static void printArray( int[] arr ) { for( int i=0 ; i= index + 1; i--) { arr[i] = arr[i - 1]; } arr[index]=key; // LEAVE THIS HERE } } static int bSearch(int[] a, int count, int key) { int hi = count-1; int lo = 0; int mid = (hi +lo)/2; if(hi == -1) { return mid; } else { mid = (hi+lo)/2; } while (lo <= hi) { if (key==a[mid]) { return (mid+1); } else if (key < a[mid]) { hi = mid-1; mid = (hi+lo)/2; } else { lo = mid +1; mid = (hi+lo)/2; } } return (mid +1); } } and the .txt file has the elements: Solution HI, I have fixed the issue. import java.util.*; import java.io.*; public class Project4 { static final int INITIAL_CAPACITY = 5; public static void main( String args[] ) throws Exception { // ALWAYS TEST FIRST TO VERIFY USER PUT REQUIRED INPUT FILE NAME ON THE COMMAND LINE if (args.length < 1 ) { System.out.println(\"\ usage: C:\\\\> java Project4 \ \ \"); // i.e. C:\\> java Project4 P4input.txt System.exit(0); } // LOAD FILE INTO ARR USING INSERINORDER Scanner infile = new Scanner( new File( args[0] ) ); int[] arr = new int[INITIAL_CAPACITY]; int count= 0; while (infile.hasNextInt()) { if ( count==arr.length ) arr = upSizeArr(arr); insertInOrder( arr, count++, infile.nextInt() ); } infile.close(); arr=trimArr(arr,count); // Now count == .length System.out.println( \"Sorted array of \" + arr.length + \" ints from \" + args[0] + \" after insertInOrder:\" ); printArray( arr ); // we trimmed it thus count == length so we don\'t bother to pass in count } // END MAIN // ###################################.

i am finishing a project for my cs 0401 java course. I have complete.pdf

deepaksatrker

More from deepaksatrker (19)