6. A solution of an acid, with a general formula HA, contains 0.400 moles of H\"\'. The acid solution is neutralized by 43.4 mL of sodium hydroxide. What is the molarity of the sodium hydroxide solution? 7. Write the balanced chemical equations for the removal of water from the following hydrated crystals. a) Copper(Il) sulfate pentahydrate b) Tin(II) chloride dehydrate c) Cobalt(II) chloride hexahydrate d) Magnesium sulfate heptahydrate oint of solution made hy dissolving 6.000 q of urea Solution 6) HA + NaOH ------------------> NaA + H2O moles of HA = moles of NaOH = 0.400 moles = 0.400 volume = 43.4 mL = 0.0434 L molarity of NaOH = moles / volume = 0.400 / 0.0434 = 9.21 M 7) a) CuSO4 .5H2O ------------------> CuSO4 + 5 H2O b) SnCl2 H2O ----------------------> SnCl2 + H2O c) CoCl2.6H2O --------------------> CoCl2 + 6H2O d) MgSO4 7H2O -------------------> MgSO4 + 7H2O .

1. 6. A solution of an acid, with a general formula HA, contains 0.400 moles of H"'. The acid
solution is neutralized by 43.4 mL of sodium hydroxide. What is the molarity of the sodium
hydroxide solution? 7. Write the balanced chemical equations for the removal of water from the
following hydrated crystals. a) Copper(Il) sulfate pentahydrate b) Tin(II) chloride dehydrate c)
Cobalt(II) chloride hexahydrate d) Magnesium sulfate heptahydrate oint of solution made hy
dissolving 6.000 q of urea
Solution
6) HA + NaOH ------------------> NaA + H2O
moles of HA = moles of NaOH = 0.400
moles = 0.400
volume = 43.4 mL = 0.0434 L
molarity of NaOH = moles / volume
= 0.400 / 0.0434
= 9.21 M
7)
a) CuSO4 .5H2O ------------------> CuSO4 + 5 H2O
b) SnCl2 H2O ----------------------> SnCl2 + H2O
c) CoCl2.6H2O --------------------> CoCl2 + 6H2O
d) MgSO4 7H2O -------------------> MgSO4 + 7H2O