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Minimización de
funciones Booleanas
• Manipulación Algebraica
• Mapas de Karnaugh
Manipulación Algebraica
• Factorización
• Duplicando un termino ya existente
• Teorema del consenso
• Propiedad distributiva
• Identidades
• Teorema de Dmorgan
Mapas de Karnaugh
Factorización
Manipulación Algebraica
Factor común B
m
A B F
0
0 0 0
1
0 1 1
2
1 0 0
3
1 1 1
Factorización
m
A B F
0
0 0 0
1
0 1 1
2
1 0 0
3
1 1 1
F(A,B)=AB+AB = B
la Factorización se efectúa cuando solo
cambia una variable entre dos términos
y esta variable se elimina
m S P E CS CP CE
0 0 0 0 0 0 0
1 0 0 1 0 0 1
2 0 1 0 0 1 0
3 0 1 1 0 1 0
4 1 0 0 1 0 0
5 1 0 1 1 0 0
6 1 1 0 1 0 0
7 1 1 1 1 0 0
CS (S, P, E ) =
m S P E CS CP CE
0 0 0 0 0 0 0
1 0 0 1 0 0 1
2 0 1 0 0 1 0
3 0 1 1 0 1 0
4 1 0 0 1 0 0
5 1 0 1 1 0 0
6 1 1 0 1 0 0
7 1 1 1 1 0 0
CS (S, P, E ) = S P’ E’
m S P E CS CP CE
0 0 0 0 0 0 0
1 0 0 1 0 0 1
2 0 1 0 0 1 0
3 0 1 1 0 1 0
4 1 0 0 1 0 0
5 1 0 1 1 0 0
6 1 1 0 1 0 0
7 1 1 1 1 0 0
CS (S, P, E ) = S P’ E’ + S P’ E
m S P E CS CP CE
0 0 0 0 0 0 0
1 0 0 1 0 0 1
2 0 1 0 0 1 0
3 0 1 1 0 1 0
4 1 0 0 1 0 0
5 1 0 1 1 0 0
6 1 1 0 1 0 0
7 1 1 1 1 0 0
CS (S, P, E ) = S P’ E’ + S P’ E + S P E’
m S P E CS CP CE
0 0 0 0 0 0 0
1 0 0 1 0 0 1
2 0 1 0 0 1 0
3 0 1 1 0 1 0
4 1 0 0 1 0 0
5 1 0 1 1 0 0
6 1 1 0 1 0 0
7 1 1 1 1 0 0
CS (S, P, E ) = S P’ E’ + S P’ E + S P E’ + S P E
CS (S, P, E ) = S P’ E’ + S P’ E + S P E’ + S P E
CS (S, P, E ) = S P’ (E’+E)+ S P (E’+E)
CS (S, P, E ) = S P’ + S P
CS (S, P, E ) = S (P’+P)
CS (S, P, E ) = S
m S P E CS CP CE
0 0 0 0 0 0 0
1 0 0 1 0 0 1
2 0 1 0 0 1 0
3 0 1 1 0 1 0
4 1 0 0 1 0 0
5 1 0 1 1 0 0
6 1 1 0 1 0 0
7 1 1 1 1 0 0
CS (S, P, E ) = S P’ E’ + S P’ E + S P E’ + S P E
CS (S,) = S
m S P E CS CP CE
0 0 0 0 0 0 0
1 0 0 1 0 0 1
2 0 1 0 0 1 0
3 0 1 1 0 1 0
4 1 0 0 1 0 0
5 1 0 1 1 0 0
6 1 1 0 1 0 0
7 1 1 1 1 0 0
CS (S, P, E ) = S P’ E’ + S P’ E + S P E’ + S P E = S
CS (S,) = S
m S P E CS CP CE
0 0 0 0 0 0 0
1 0 0 1 0 0 1
2 0 1 0 0 1 0
3 0 1 1 0 1 0
4 1 0 0 1 0 0
5 1 0 1 1 0 0
6 1 1 0 1 0 0
7 1 1 1 1 0 0
CP (S, P, E ) = S’ P E’ + S’ P E
CP (S, P, E ) = S’ P (E’+E)
CP (S, P, E ) = S’ P
CP (S, P ) = S’ P
Duplicando un termino ya existente
F= A + B
m A B C X
0 0 0 0 1
1 0 0 1 1
2 0 1 0 1
3 0 1 1 0
4 1 0 0 0
5 1 0 1 0
6 1 1 0 0
7 1 1 1 0
FX (A,B,C) = A’ B’ C’ + A’ B’ C + A’ B C’
FX (A,B,C) = A’ B’ C’ + A’ B’ C
+ A’ B C’ + A’ B’ C’
FX (A,B,C) = A’ B’ + A’ C’
FX (A,B,C) = A’ (B’ + C’)
S(A,B,C,D)= A’B’C'+ A’B’CS(A,B,C,D)= A’B’CS(A,B,C,D)= A’B’C'+ A’B’C + AB’C' +’BC'D'S(A,B,C,D)= A’B’C'+ A’B’C + AB’C'
M A B C D S
0 0 0 0 0 1
1 0 0 0 1 1
2 0 0 1 0 1
3 0 0 1 1 1
4 0 1 0 0 1
5 0 1 0 1 0
6 0 1 1 0 0
7 0 1 1 1 0
8 1 0 0 0 1
9 1 0 0 1 1
10 1 0 1 0 0
11 1 0 1 1 0
12 1 1 0 0 1
13 1 1 0 1 0
14 1 1 1 0 0
15 1 1 1 1 0
S(A,B,C,D)= A'B' + B'C' + C'D'
S(A,B,C,D)= A’B’C'D'+ A’B’C'D + A’B’CD'+A’B’CD
+A’BC'D' + AB’C'D' + AB’C'D + ABC'D'
0 1 2 3
4 8 9 12
0-1 2-3 8-9 4-12
S(A,B,C,D)= B’C'+ A’B’ + +’BC'D'
0-1, 8-9 0-1, 2,3
Teorema del consenso
m. Acuerdo producido por consentimiento entre todos
los miembros de un grupo o entre varios grupos.
Teorema del consenso
Teorema del consenso
1
1
1
1
1
Teorema del consenso
Propiedad Distributiva
Propiedad Distributiva
F= A’ B + A B’ + A B + A’ C’
F= B + A + A’ C’
F= B + (A+ A’)(A+ C’)
F= B + A+ C’ F= A+B+C’
Actividad
Usando como recursos
• Factorización
• Duplicando un termino ya existente
• Teorema del consenso
• Propiedad distributiva
• Identidades
• Teorema de Dmorgan
Resuelva las siguientes funciones
1.-Identidades
2.- Factorización
AB’ + AB = A(B’+B)= A
3.- Propiedad Distributiva
X+YZ = (X+Y) (X+Z)
X (Y+Z) = XY +XZ
4.-Teorema del consenso
AB+A’C+BC = AB+A’C
5.-Teorema de Dmorgan
(AB)’=A’+ B’ (A+B)’=A’ B’
A+B =(A’ B’)’ AB =(A’+B’)’
AND OR
A A=A A + A=A
A 0 =0 A + 0 = A
A 1 =A A + 1 =1
A A’ =0 A+A’ =1 1
1+ B’+ C
2
DC’(0)
3
A’+B+A
4
A+ A’ BC
5
A’BC+A’BC’
F1 (B,C)= 1+B’+C
F1 (B,C)= 1
1.-Identidades
2.- Factorización
AB’ + AB = A(B’+B)= A
3.- Propiedad Distributiva
X+YZ = (X+Y) (X+Z)
X (Y+Z) = XY +XZ
4.-Teorema del consenso
AB+A’C+BC = AB+A’C
5.-Teorema de Dmorgan
(AB)’=A’+ B’ (A+B)’=A’ B’
A+B =(A’ B’)’ AB =(A’+B’)’
AND OR
A A=A A + A=A
A 0 =0 A + 0 = A
A 1 =A A + 1 =1
A A’ =0 A+A’ =1
F2 (D,C)= DC’(0)
F2 (D,C)= 0
1.-Identidades
2.- Factorización
AB’ + AB = A(B’+B)= A
3.- Propiedad Distributiva
X+YZ = (X+Y) (X+Z)
X (Y+Z) = XY +XZ
4.-Teorema del consenso
AB+A’C+BC = AB+A’C
5.-Teorema de Dmorgan
(AB)’=A’+ B’ (A+B)’=A’ B’
A+B =(A’ B’)’ AB =(A’+B’)’
AND OR
A A=A A + A=A
A 0 =0 A + 0 = A
A 1 =A A + 1 =1
A A’ =0 A+A’ =1
F3 (A, B) = A’+B+A
F3 (A, B) = 1
1.-Identidades
2.- Factorización
AB’ + AB = A(B’+B)= A
3.- Propiedad Distributiva
X+YZ = (X+Y) (X+Z)
X (Y+Z) = XY +XZ
4.-Teorema del consenso
AB+A’C+BC = AB+A’C
5.-Teorema de Dmorgan
(AB)’=A’+ B’ (A+B)’=A’ B’
A+B =(A’ B’)’ AB =(A’+B’)’
AND OR
A A=A A + A=A
A 0 =0 A + 0 = A
A 1 =A A + 1 =1
A A’ =0 A+A’ =1
F4 (A,,B,C) = A+A’BC
F4 (A,,B,C)=(A+A’)(A+BC)
F4 (A,,B,C)=A+BC
1.-Identidades
2.- Factorización
AB’ + AB = A(B’+B)= A
3.- Propiedad Distributiva
X+YZ = (X+Y) (X+Z)
X (Y+Z) = XY +XZ
4.-Teorema del consenso
AB+A’C+BC = AB+A’C
5.-Teorema de Dmorgan
(AB)’=A’+ B’ (A+B)’=A’ B’
A+B =(A’ B’)’ AB =(A’+B’)’
AND OR
A A=A A + A=A
A 0 =0 A + 0 = A
A 1 =A A + 1 =1
A A’ =0 A+A’ =1

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Simplificación funciones Booleanas

  • 1. Minimización de funciones Booleanas • Manipulación Algebraica • Mapas de Karnaugh
  • 2. Manipulación Algebraica • Factorización • Duplicando un termino ya existente • Teorema del consenso • Propiedad distributiva • Identidades • Teorema de Dmorgan
  • 4. Factorización Manipulación Algebraica Factor común B m A B F 0 0 0 0 1 0 1 1 2 1 0 0 3 1 1 1
  • 5. Factorización m A B F 0 0 0 0 1 0 1 1 2 1 0 0 3 1 1 1 F(A,B)=AB+AB = B
  • 6. la Factorización se efectúa cuando solo cambia una variable entre dos términos y esta variable se elimina
  • 7.
  • 8.
  • 9. m S P E CS CP CE 0 0 0 0 0 0 0 1 0 0 1 0 0 1 2 0 1 0 0 1 0 3 0 1 1 0 1 0 4 1 0 0 1 0 0 5 1 0 1 1 0 0 6 1 1 0 1 0 0 7 1 1 1 1 0 0 CS (S, P, E ) =
  • 10. m S P E CS CP CE 0 0 0 0 0 0 0 1 0 0 1 0 0 1 2 0 1 0 0 1 0 3 0 1 1 0 1 0 4 1 0 0 1 0 0 5 1 0 1 1 0 0 6 1 1 0 1 0 0 7 1 1 1 1 0 0 CS (S, P, E ) = S P’ E’
  • 11. m S P E CS CP CE 0 0 0 0 0 0 0 1 0 0 1 0 0 1 2 0 1 0 0 1 0 3 0 1 1 0 1 0 4 1 0 0 1 0 0 5 1 0 1 1 0 0 6 1 1 0 1 0 0 7 1 1 1 1 0 0 CS (S, P, E ) = S P’ E’ + S P’ E
  • 12. m S P E CS CP CE 0 0 0 0 0 0 0 1 0 0 1 0 0 1 2 0 1 0 0 1 0 3 0 1 1 0 1 0 4 1 0 0 1 0 0 5 1 0 1 1 0 0 6 1 1 0 1 0 0 7 1 1 1 1 0 0 CS (S, P, E ) = S P’ E’ + S P’ E + S P E’
  • 13. m S P E CS CP CE 0 0 0 0 0 0 0 1 0 0 1 0 0 1 2 0 1 0 0 1 0 3 0 1 1 0 1 0 4 1 0 0 1 0 0 5 1 0 1 1 0 0 6 1 1 0 1 0 0 7 1 1 1 1 0 0 CS (S, P, E ) = S P’ E’ + S P’ E + S P E’ + S P E
  • 14. CS (S, P, E ) = S P’ E’ + S P’ E + S P E’ + S P E CS (S, P, E ) = S P’ (E’+E)+ S P (E’+E) CS (S, P, E ) = S P’ + S P CS (S, P, E ) = S (P’+P) CS (S, P, E ) = S
  • 15. m S P E CS CP CE 0 0 0 0 0 0 0 1 0 0 1 0 0 1 2 0 1 0 0 1 0 3 0 1 1 0 1 0 4 1 0 0 1 0 0 5 1 0 1 1 0 0 6 1 1 0 1 0 0 7 1 1 1 1 0 0 CS (S, P, E ) = S P’ E’ + S P’ E + S P E’ + S P E CS (S,) = S
  • 16. m S P E CS CP CE 0 0 0 0 0 0 0 1 0 0 1 0 0 1 2 0 1 0 0 1 0 3 0 1 1 0 1 0 4 1 0 0 1 0 0 5 1 0 1 1 0 0 6 1 1 0 1 0 0 7 1 1 1 1 0 0 CS (S, P, E ) = S P’ E’ + S P’ E + S P E’ + S P E = S CS (S,) = S
  • 17. m S P E CS CP CE 0 0 0 0 0 0 0 1 0 0 1 0 0 1 2 0 1 0 0 1 0 3 0 1 1 0 1 0 4 1 0 0 1 0 0 5 1 0 1 1 0 0 6 1 1 0 1 0 0 7 1 1 1 1 0 0 CP (S, P, E ) = S’ P E’ + S’ P E CP (S, P, E ) = S’ P (E’+E) CP (S, P, E ) = S’ P CP (S, P ) = S’ P
  • 18. Duplicando un termino ya existente F= A + B
  • 19. m A B C X 0 0 0 0 1 1 0 0 1 1 2 0 1 0 1 3 0 1 1 0 4 1 0 0 0 5 1 0 1 0 6 1 1 0 0 7 1 1 1 0 FX (A,B,C) = A’ B’ C’ + A’ B’ C + A’ B C’ FX (A,B,C) = A’ B’ C’ + A’ B’ C + A’ B C’ + A’ B’ C’ FX (A,B,C) = A’ B’ + A’ C’ FX (A,B,C) = A’ (B’ + C’)
  • 20. S(A,B,C,D)= A’B’C'+ A’B’CS(A,B,C,D)= A’B’CS(A,B,C,D)= A’B’C'+ A’B’C + AB’C' +’BC'D'S(A,B,C,D)= A’B’C'+ A’B’C + AB’C' M A B C D S 0 0 0 0 0 1 1 0 0 0 1 1 2 0 0 1 0 1 3 0 0 1 1 1 4 0 1 0 0 1 5 0 1 0 1 0 6 0 1 1 0 0 7 0 1 1 1 0 8 1 0 0 0 1 9 1 0 0 1 1 10 1 0 1 0 0 11 1 0 1 1 0 12 1 1 0 0 1 13 1 1 0 1 0 14 1 1 1 0 0 15 1 1 1 1 0 S(A,B,C,D)= A'B' + B'C' + C'D' S(A,B,C,D)= A’B’C'D'+ A’B’C'D + A’B’CD'+A’B’CD +A’BC'D' + AB’C'D' + AB’C'D + ABC'D' 0 1 2 3 4 8 9 12 0-1 2-3 8-9 4-12 S(A,B,C,D)= B’C'+ A’B’ + +’BC'D' 0-1, 8-9 0-1, 2,3
  • 21. Teorema del consenso m. Acuerdo producido por consentimiento entre todos los miembros de un grupo o entre varios grupos.
  • 27.
  • 28. F= A’ B + A B’ + A B + A’ C’ F= B + A + A’ C’ F= B + (A+ A’)(A+ C’) F= B + A+ C’ F= A+B+C’
  • 29. Actividad Usando como recursos • Factorización • Duplicando un termino ya existente • Teorema del consenso • Propiedad distributiva • Identidades • Teorema de Dmorgan Resuelva las siguientes funciones
  • 30. 1.-Identidades 2.- Factorización AB’ + AB = A(B’+B)= A 3.- Propiedad Distributiva X+YZ = (X+Y) (X+Z) X (Y+Z) = XY +XZ 4.-Teorema del consenso AB+A’C+BC = AB+A’C 5.-Teorema de Dmorgan (AB)’=A’+ B’ (A+B)’=A’ B’ A+B =(A’ B’)’ AB =(A’+B’)’ AND OR A A=A A + A=A A 0 =0 A + 0 = A A 1 =A A + 1 =1 A A’ =0 A+A’ =1 1 1+ B’+ C 2 DC’(0) 3 A’+B+A 4 A+ A’ BC 5 A’BC+A’BC’
  • 31. F1 (B,C)= 1+B’+C F1 (B,C)= 1 1.-Identidades 2.- Factorización AB’ + AB = A(B’+B)= A 3.- Propiedad Distributiva X+YZ = (X+Y) (X+Z) X (Y+Z) = XY +XZ 4.-Teorema del consenso AB+A’C+BC = AB+A’C 5.-Teorema de Dmorgan (AB)’=A’+ B’ (A+B)’=A’ B’ A+B =(A’ B’)’ AB =(A’+B’)’ AND OR A A=A A + A=A A 0 =0 A + 0 = A A 1 =A A + 1 =1 A A’ =0 A+A’ =1
  • 32. F2 (D,C)= DC’(0) F2 (D,C)= 0 1.-Identidades 2.- Factorización AB’ + AB = A(B’+B)= A 3.- Propiedad Distributiva X+YZ = (X+Y) (X+Z) X (Y+Z) = XY +XZ 4.-Teorema del consenso AB+A’C+BC = AB+A’C 5.-Teorema de Dmorgan (AB)’=A’+ B’ (A+B)’=A’ B’ A+B =(A’ B’)’ AB =(A’+B’)’ AND OR A A=A A + A=A A 0 =0 A + 0 = A A 1 =A A + 1 =1 A A’ =0 A+A’ =1
  • 33. F3 (A, B) = A’+B+A F3 (A, B) = 1 1.-Identidades 2.- Factorización AB’ + AB = A(B’+B)= A 3.- Propiedad Distributiva X+YZ = (X+Y) (X+Z) X (Y+Z) = XY +XZ 4.-Teorema del consenso AB+A’C+BC = AB+A’C 5.-Teorema de Dmorgan (AB)’=A’+ B’ (A+B)’=A’ B’ A+B =(A’ B’)’ AB =(A’+B’)’ AND OR A A=A A + A=A A 0 =0 A + 0 = A A 1 =A A + 1 =1 A A’ =0 A+A’ =1
  • 34. F4 (A,,B,C) = A+A’BC F4 (A,,B,C)=(A+A’)(A+BC) F4 (A,,B,C)=A+BC 1.-Identidades 2.- Factorización AB’ + AB = A(B’+B)= A 3.- Propiedad Distributiva X+YZ = (X+Y) (X+Z) X (Y+Z) = XY +XZ 4.-Teorema del consenso AB+A’C+BC = AB+A’C 5.-Teorema de Dmorgan (AB)’=A’+ B’ (A+B)’=A’ B’ A+B =(A’ B’)’ AB =(A’+B’)’ AND OR A A=A A + A=A A 0 =0 A + 0 = A A 1 =A A + 1 =1 A A’ =0 A+A’ =1