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University of Engineering and technology Peshawar, Pakistan Prepared by: Muhammad Bilal
Design for Flexure and Shear
For any cross-sectional shape, flexure and shear are given in the following formulas:
Flexure formula 𝑓𝑏=
𝑀𝑐
𝐼
and shear formula is 𝑓𝑣=
𝑉𝑄
𝐼𝑏
Where:
𝑓𝑏 = flexure/bending stress
𝑓𝑣 = shearing stress
M = maximum moment applied to the beam
V = maximum shear applied to the beam
I = moment of inertia about the neutral axis
Q = moment of area above or below neutral axis
b = breadth
h= height/depth
c= outermost fiber distance from neutral axis
Now consider a rectangular section
in such case we know the value of β€˜c’ i.e. h/2 outermost distance from neutral axis and also we know
the value of β€˜I’ moment of inertia of rectangle is
π‘β„Ž3
12
the bending stress becomes
𝑓𝑏=
𝑀𝑐
𝐼
Putting these values in formula
= 𝑀
β„Ž
2
x
12
π‘β„Ž3
=
6𝑀
π‘β„Ž2
So for rectangle bending stress becomes this, incase of
square as b=h so the denominator term will be β„Ž3
for shearing stress
𝑓𝑣=
𝑉𝑄
𝐼𝑏
the value of β€˜I’ remains same while Q is (
β„Ž
2
Γ— 𝑏)(
β„Ž
4
) =
π‘β„Ž2
8
Putting values in the formula
=
π‘‰π‘β„Ž2
8
Γ—
12
𝑏2
Γ—1
β„Ž3
=
3𝑉
2π‘β„Ž
for rectangular section the shearing stresses becomes this, for square it will be
3𝑉
2β„Ž2

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Design for flexure and shear (rectangular & square section)

  • 1. University of Engineering and technology Peshawar, Pakistan Prepared by: Muhammad Bilal Design for Flexure and Shear For any cross-sectional shape, flexure and shear are given in the following formulas: Flexure formula 𝑓𝑏= 𝑀𝑐 𝐼 and shear formula is 𝑓𝑣= 𝑉𝑄 𝐼𝑏 Where: 𝑓𝑏 = flexure/bending stress 𝑓𝑣 = shearing stress M = maximum moment applied to the beam V = maximum shear applied to the beam I = moment of inertia about the neutral axis Q = moment of area above or below neutral axis b = breadth h= height/depth c= outermost fiber distance from neutral axis Now consider a rectangular section in such case we know the value of β€˜c’ i.e. h/2 outermost distance from neutral axis and also we know the value of β€˜I’ moment of inertia of rectangle is π‘β„Ž3 12 the bending stress becomes 𝑓𝑏= 𝑀𝑐 𝐼 Putting these values in formula = 𝑀 β„Ž 2 x 12 π‘β„Ž3 = 6𝑀 π‘β„Ž2 So for rectangle bending stress becomes this, incase of square as b=h so the denominator term will be β„Ž3 for shearing stress 𝑓𝑣= 𝑉𝑄 𝐼𝑏 the value of β€˜I’ remains same while Q is ( β„Ž 2 Γ— 𝑏)( β„Ž 4 ) = π‘β„Ž2 8 Putting values in the formula = π‘‰π‘β„Ž2 8 Γ— 12 𝑏2 Γ—1 β„Ž3 = 3𝑉 2π‘β„Ž for rectangular section the shearing stresses becomes this, for square it will be 3𝑉 2β„Ž2