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Design for flexure and shear (rectangular & square section)
1. University of Engineering and technology Peshawar, Pakistan Prepared by: Muhammad Bilal
Design for Flexure and Shear
For any cross-sectional shape, flexure and shear are given in the following formulas:
Flexure formula ππ=
ππ
πΌ
and shear formula is ππ£=
ππ
πΌπ
Where:
ππ = flexure/bending stress
ππ£ = shearing stress
M = maximum moment applied to the beam
V = maximum shear applied to the beam
I = moment of inertia about the neutral axis
Q = moment of area above or below neutral axis
b = breadth
h= height/depth
c= outermost fiber distance from neutral axis
Now consider a rectangular section
in such case we know the value of βcβ i.e. h/2 outermost distance from neutral axis and also we know
the value of βIβ moment of inertia of rectangle is
πβ3
12
the bending stress becomes
ππ=
ππ
πΌ
Putting these values in formula
= π
β
2
x
12
πβ3
=
6π
πβ2
So for rectangle bending stress becomes this, incase of
square as b=h so the denominator term will be β3
for shearing stress
ππ£=
ππ
πΌπ
the value of βIβ remains same while Q is (
β
2
Γ π)(
β
4
) =
πβ2
8
Putting values in the formula
=
ππβ2
8
Γ
12
π2
Γ1
β3
=
3π
2πβ
for rectangular section the shearing stresses becomes this, for square it will be
3π
2β2